1. A race car accelerates uniformly from 19.5 m/s to 50.1 m/s in

2.47 seconds. Determine the acceleration of the car.

The acceleration of the car is 79.8.

Answer:

The crown is not made of solid gold.  

Explanation:

Density ρ = M/V.  M and V are given.

The density of the crown is (0.5 kg)/(185 cm3) * (106 cm3)/(1 m3) = 2.7*103 kg/m3.

Answer:

Chemical, mechanical, thermal i guess

Answer:

But once the core runs out of hydrogen, the star starts to contract again briefly, until a shell of hydrogen around the core becomes hot enough to fuse into helium. When this happens, the radiation pushes the outer layers of the star far out into space, turning the star into a red giant

Explanation:

Correct?

Answer:

   V = 12V,  V = 8V

Explanation:

a) In this series circuit the equivalent resistance is

          Req - R1 + R2

          Req = 30 + 20

          Eeq = 50 Ω

b) see attached

c) the circuit current is

          i = V / Req

          i = 20/50

          i = 0.4 A

voltages are>

         V = 0.4 30

          V = 12V

           V = 0.4 20

            V = 8V

Answer:

I can use a log and arock or something hard to make a pivot and place on it the log to build a jump

Answer:

1)    v = 2.5 m / s, 2)  v = -0.5 m / s

Explanation:

For this exercise we will use the kinematics relations

1) velocity is defined by

         v = [tex]\frac{dx}{dt}[/tex]dx / dt

this definition serves for the instantaneous and the average velocity if the displacements are linear in time

         v = 20/8

         v = 2.5 m / s

b) for this part we use

          v = [tex]\frac{\Delta x}{\Delta t}[/tex]

         Δx = x_f -x₀

we must place a reference system, where the direction to the right is positive

         x_f = -2 m

         x₀ = +3 m

         Δx = -2 -3

         Δx = -5 m

we calculate

         v = -5 / 10

         v = -0.5 m / s

this value is a scalar

Answer:

Gravity such as magnets

Explanation:

Hope this helped

The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body       Mass (gram)     Engine      Force (newtons)

1                   500                 1                     25

2                  1500                2                    20

3                  750                  3                    30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

 20    = 0.5 x acceleration

Acceleration [tex]$=\frac{20}{0.5}$[/tex]

                      [tex]$=\frac{200}{5}$[/tex]

                      [tex]$= 40 \ m/s^2$[/tex]

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of [tex]$ 40 \ m/s^2$[/tex] at the start of the launch.

Answer:

1.31×10⁻⁴ C or 131 μC

Explanation:

From the question,

Applying Coulomb's Law,

F = kqq'/r²..................... Equation 1

Where F = Force between the charges, q = first charge, q' = second charge, r = distance between the charges, k = coulomb's constant.

make q' the subject of the equation

q' = F×r²/(kq)

q' = Fr²/kq................ Equation 2

Given: F = 1240 N, r = 16.4 cm = 0.164 m, q = 28.4 μC = 2.84×10⁻⁵ C,

Constant: k = 8.98×10⁹ Nm/C²

Substitute these values into equation 2

q' = (1240×0.164²)/[(2.84×10⁻⁵)×(8.98×10⁹)

q' = (33.35104)/(25.5032×10⁴)

q' = 1.31×10⁻⁴ C

q' = 131 μC

Answer:

89 i would say

Explanation:

Answer:

its kainda blurry aploude another pic

Answer:

2

Explanation:

Answer:

Yeah of course

Explanation:

Its obvious because more people are attracted to men soccer

Answer:

5.59 m/s2

Explanation:

F = 1900 N

m = 340 kg

F = ma

Therefore, a = 1900/340 = 5.59

Answer: How much gravitational potential energy does the ball have at this point? At h = 20.4 m the gravitational potential energy of the ball reaches maximum.  

How much work did I do lifting up the ball?  As you are lifting the object you are doing work on the object. The work W done on an object by a constant force is defined as W = F·d. It is equal to the magnitude of the force, multiplied by the distance the object moves in the direction of the force.

Answer:

378

Explanation:

60 seconds in one minute

add the 24 seconds

multiply it by 4.5

60 + 24 = 84

4.5 x 84 = 378

Answer:D 125

Explanation:

Answer:

Suppose that the wave equation is:

f(x) = A*cos(k*x)

The wave is in phase for two points x₁ and x₂ if:

f(x₁) = f(x₂)

And if these points are consecutive (for example, two consecutive peaks) then the wavelength of the wave is:

wavelength = x₂ - x₁

In this case, we know that the wave is in phase for two points that are 2 m apart.

Then we can use the points:

x₁ and x₂ such that:

x₂ = x₁ + 2m

We also know that these are the nearest points such that this happens, then we can assume that the points are consecutive.

Then the wavelength will be:

wavelength = x₂ - x₁ = (x₁ + 2m) - (x₁) = 2m

Then the wavelength is 2m.

The correct option is C.

Answer:

D. Copper

Explanation:

Copper has the best electrical conductivity of any metal, except silver. A good electrical conductivity is the same as a small electrical resistance.

Helped By the ONE and ONLY #QUEEN aka #DRIPPQUEENMO!!

HOPE THIS HELPED!!

Answer:

C. Reflects only

Answer:

1m/s is the acceleration used. C

Explanation:

please mark brainliest

Answer:

a) 45 s , b)    vₐ = 90 m / s, v_b = 162 m / s, c)     x_b = 3.328 10⁴ m

Explanation:

We can solve this exercise using the kinematic relations

Vehicle A

              xₐ = v₀ₐ t + ½ aₐ t²

vehicle B

starts two seconds later

             x_b = v_{ob} (t-2) + ½  a_b (t-2) ²

as cars start from rest their initial velocities are zero

at the point where they meet, the position must be the same for both vehicles

             xa = 0 + ½ aₐ t²

             xb = 0 + ½ a_b (t-2) ²

             ½ aₐ t² = ½ a_b (t-2) ²

            [tex]\sqrt{ \frac{a_a}{a_b} }[/tex] t = (t-2)

              t (1 - \sqrt{  \frac{a_a}{a_b} }) = 2

             t (1 - ⅔, ) = 2

            t = 2 / 0.4444

             t = 45 s

b)

the speed of each car

                vₐ = voa + aa t

                vₐ = 0 + 2 45

                vₐ = 90 m / s

                v_b = 3.6 45

                v_b = 162 m / s

c) xb = 0 + ½ ab (t-2) ²

       x_b = ½ 3.6 (45-2) ²

       x_b = 3.328 10⁴ m

Answer:

Above

Explanation:

yes

Answer:

6 v

Explanation:

The formula for momentum is p = m*v

The conservation of momentum suggests:

m*vi = m*vf (initial mass times initial velocity = final mass times final velocity or initial momentum = final momentum)

(0.0010)(52.2) = (0.0010 + 3.3)vf

vf = (0.0010)(52.2)/(0.0010 + 3.3) = 0.0522/3.301 ≈ 0.01581 m/s

To the nearest thousandth  ≈ .016 m/s

5. All the resistors in this circuit, the 18 Ω resistor included, are in parallel. The voltage drop across each resistor is the same, which is the equivalent to the potential difference of the battery. That is, 36 V [choice K].

6. The ammeter is in series with the branch containing a 12 Ω resistor. Since the voltage drop across this resistor is 36 V, the current in this branch will be I = V/R = (36 V)/(12 Ω) = 3.0 A [choice D].

7. The equivalent resistance of the circuit can be calculated as follows:

1/R = 1/12 + 1/9 + 1/18 = 1/4; thus, R = 4.0 Ω [choice G].

8. Electrical power can be defined as electrical work/time, and electrical work can be given by W = qV. If P = qV/t and q/t = I (charge flowing per unit time is equal to current), then P = VI. From Ohm's law, V = IR, and I = V/R. Substituting V/R for I in the power equation, P = V²/R.

For this circuit, the V = 36 V and R (the equivalent resistance) = 4.0 Ω. So, the power loss in the circuit is P = (36 V)²/(4.0 Ω) = 324 W [choice J].

Answer:

The correct option is (c).

Explanation:

Given that,

The energy of a photon is, [tex]E=3.38\times 10^{-19}\ J[/tex]

We need to tell the color of this light. We know that, the energy of a photon is given by :

[tex]E=\dfrac{hc}{\lambda}[/tex]

Where

c is the speed of light

[tex]\lambda=\dfrac{hc}{E}\\\\\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3.38 \times 10^{-19}}\\\\\lambda=5.88\times 10^{-7}\ m\\\\\lambda=588\ nm[/tex]

The wavelength of yellow light is approx 580 nm. Hence, we can say that this photon corresponds to yellow light.

Answer:

B. Green

Explanation:

correct on EDGE2021

Answer:

vacuum-radiation

gas-convection

solid-conduction

Explanation: