1. As air in Earth's atmosphere is heated by
the Sun, the warmer air expands and
becomes less dense than the cooler air. As a
result, the warmer air rises and the cooler
air sinks. What is the cycle of warm air
rising and cool air sinking called?

tidal current

surface current

deep current

convection current

Answer: [tex]3000\ W,\ 78,000\ J[/tex]

Explanation:

Given

The voltage of the battery is [tex]V=12\ V[/tex]

Current through the battery is [tex]I=250\ A[/tex]

(a) Power is the product of voltage and current

Power dissipates is given by

[tex]P=VI\\P=12\times 250\\P=3000\ W[/tex]

(b) Energy delivered

[tex]E=P\times t[/tex]

[tex]E=3000\times 26\\E=78,000\ J[/tex]

Answer: Negative punishment includes taking away a certain reinforcing item after the undesired behavior happens in order to decrease future responses. Positive punishment involves adding an aversive consequence after an undesired behavior is emitted to decrease future responses.

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SUKHMANJOT

Answer:

the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.

Explanation:

Answer:

the emission or transmission of energy in the form of waves or particles through space or through a material medium

Explanation:

this includes electromagnetic radiation, such as radio waves, microwaves, infrared, visible light, ultraviolet, x-rays, and gamma radiation

Answer:

medication error thats easy

Answer: it always opposes the directions of motion is the right answer

Explanation:

Answer:

Explanation:

Volume of inner core = 4/3 π R₁³

where R₁ is radius of inner core so R₁ = 1220 km

Volume of inner core = 4/3 π (1220 km )³

= 1764.4 x 10¹⁷ m³ - 4/3 π (1220 km )³

= 76.02 x 10⁸ x 10⁹ m³

= 76.02 x 10¹⁷ m³

Density = 13000 kg / m³

mass = volume x density

= 76.02 x 10¹⁷ x 13000

= 988.26 x 10²⁰ kg

Volume of outer  core = 4/3 π (3480 km )³ -  4/3 π (1220 km )³

= 1764.4 x 10⁸ km³ - 4/3 π (1220 km )³

= 1764.4 x 10⁸ x 10⁹m³ - 4/3 π (1220 km )³

= 1764.4 x 10¹⁷ m³ - 4/3 π (1220 km )³

= 1764.4 x 10¹⁷ m³ - 76.02 x 10¹⁷ m³

= 1688.38 x 10¹⁷ m³

density = 11100 kg /m³

mass of outer  core= 1688.38 m³ x10¹⁷ x  11100 kg /m³

= 18741 x 10²⁰ kg

Volume of outer mantle  =  4/3 π (6371  km )³ - 4/3 π (3480 km )³

= 10826 x 10¹⁷ m³- 1764.4 x 10¹⁷ m³

= 9062 x 10¹⁷ m³

density = 4400 kg /m³

mass of outer  core= 9062 x 10¹⁷ m³ x  4400 kg /m³

= 39872.8 x 10²⁰ kg

Total mass of the earth = 988.26 x 10²⁰ kg + 18741 x 10²⁰ kg +39872.8 x 10²⁰ kg

= 59602.06 x 10²⁰ kg .

Total volume = 4/3 π (6371  km )³

= 10826 x 10¹⁷ m³

Density = mass / volume

= 59602.06 x 10²⁰ kg /  10826 x 10¹⁷ m³

= 5505.45 kg / m³

B )

Mass = 5.974 x 10²⁴ kg

volume = Total volume = 4/3 π (6371  km )³

= 10826 x 10¹⁷ m³

density = 5.974 x 10²⁴ kg / 10826 x 10¹⁷ m³

= 5518.2 kg / m³

The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.

Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.

There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.

1 mmHg = 0.0013133 atm

hence, 760 mmHg = 1 atm

On the surface of Venus, the pressure is 9200 kilopascal.

1 mmHg = 0.133 KPa

then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.

Therefore, height of mercuric column will be 69017 mm in Venus surface.

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The following which is not a safety tip for outdoor activities is to go alone for a sense of oneness with nature and is therefore denoted as option A.

This is referred to as the condition of being protected from harm or other danger and it involves the use of various methods and activities and an example is to ensure that a  basic first aid kit is available so as to help in the incident of an injury.

However going alone for a sense of oneness with nature is not a safety tip as should in case any issue arises there will be no one to support and rescue such individual.

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The full question is:

Which of the following is not a safety tip for outdoor activities

a. go alone for a sense of oneness with nature

b. bring a basic first aid kit

c. bring a flashlight or headlamp

d. pack plenty of water and energy-dense food

Answer:

C po ang sa got pa braenlest

Answer:

C. Uranium-235

Explanation:

I just took the test.

The evaluation of the capacitor (in series) network is as follows;

Part A

Q = 3.2 μC

Part B

Q₁ = 3.2 μC

Part C

Q₂ = 3.2 μC

Part D

U = 76.8 μJ

Part E

U₁ = 34 2/15 μJ

Part F

U₂ = 53 1/3 μJ

Part G

V₁ = 21 1/3 V

Part H

V₂ = 26 2/3 V

A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.

The specified parameters are;

The voltage across ab = 48 V

The capacitance of the first capacitor, C₁ = 150 nF

Capacitance of the second capacitor, C₂ = 120 nF

Part A

The total charge in a capacitor network can be found as follows;

[tex]C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF[/tex]

[tex]C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF[/tex]

[tex]Q_{eq} = C_{eq}\times V_{ab}[/tex]

Therefore;

[tex]Q_{eq}[/tex] = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC

Part B

The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;

Q = C₁V₁ = C₂V₂

The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC

The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC

Part C

The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.

Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC

Q₂ = 3.2 μF

Part D

The total energy stored in the network can be obtained using the formula;

U = (1/2)·C·V²

Where;

U = The energy in the capacitor

C = The equivalent capacitance of the network = 66 2/3 nF

V = The voltage

Therefore;

[tex]U = \dfrac{1}{2} \times C_{eq}\times V^2[/tex]

[tex]U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8[/tex]

Part E

The energy stored in the 150 nF capacitor is found as follows;

[tex]Q_{eq}[/tex] = Q₁ = C₁ × V₁

V₁ = [tex]Q_{eq}[/tex] ÷ C₁

Therefore;

V₁ = 3.2 μC ÷ 150 nF = [tex]21\frac{1}{3}[/tex] V

U₁ = 0.5×C₁×V₁²

Part F

The energy stored in the 120 nF capacitor, U₂, can be found as follows;

V₂ = 3.2 μC ÷ 120 nF = [tex]26\frac{2}{3}[/tex] V

U₂ = 0.5 × 150 nF × [tex]\left(26\frac{2}{3} \, V\right)^2[/tex] = [tex]53\frac{1}{3}\, \mathrm{ \mu J}[/tex]

Part G;

The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V

Part H

The potential difference across the 120 nF, obtained in part F, is 26 2/3 V

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Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].

Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.

We are given that:

Number of point charges = 3

Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so

E4 = E1 + E2 + E3

E4 = kQ/a² + kQ/√(2a²) + kQ/a²

E4 = kQ [1/a² + 1/√(2a²) + 1/a²]

Thus the electric field at the fourth corner is  E4 = kQ [2/a² + 1/a√2].

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Answer:

the answer is c

Explanation:

melting = become liquefied by heat

solubility = a new bond formation

conductivity = electric transmitter

flammability = burnable

Doing contracting work for government agencies of private businesses

The mission control center is a facility that is responsible for controlling and coordinating the operations of a spacecraft during a mission. It is typically run by NASA or another space agency and is used to monitor and communicate with spacecraft, as well as to plan and execute mission objectives. The mission control center is not typically involved in contracting work for government agencies or private businesses.

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To solve this we must be knowing each and every concept related to interval. Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as below.

An interval is any set of numbers that fall between two distinct integers. This range includes all real values that fall between those two. All real numbers that lie in any 2 of a set's numbers are collectively referred to as an interval within mathematics.

For instance, the set of integers x fulfilling 0 x 1 is the interval consisting of 0, 1, and all numbers in between. a snapshot graph of wave on a string moving toward one another at 1 m/s at time t = 0 s.

At time t = 0,Y₀= 0 cm

At At time t =1, Y₁= 0 cm

At time t = 2, Y₂= 0 cm

At time t =3, Y₃= 0 cm

At time t =4, Y₄= 0 cm

At time t = 5 ,Y₅=0 cm

At time t = 6, Y₆= 0 cm

Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as above.

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This might help as well:

https://www.mathsisfun.com/physics/light.html

Answer:

Energy consumed by the electric kettle in 9.5 min =Pt=(2.5×10

3

)×(9.5×60)=14.25×10

5

J

Energy usefully consumed =msΔT=3×(4.2×10

3

)×(100−15)=10.71×10

5

where s=4.2J/g

o

C= specific heat of water and boiling point temp=100

o

C

Heat lost =14.25×10

5

−10.71×10

5

=3.54×10

5

The shape of the coastlines and the slope of the ocean floor, as well as the gravitational pull of the Sun and Moon, all have an impact on the tides of the ocean.

Tides are extremely long-period waves that travel across the water as a result of the moon's and the sun's gravitational pull. The rise and fall of the sea's surface on a regular basis is what tides, which originate in the ocean, appear as as they move toward the coastlines.

High tide is when the wave's highest portion, or crest, reaches a specific area; low tide is when the wave's lowest portion, or trough, reaches that location. The term "tidal range" refers to the height difference between high tide and low tide.

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In the given image A. load, B. fulcrum, C. effort. 1st class. The correct option is B.

The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.

The fulcrum of first-class levers is in the centre. Levers of the second class have the load in the centre.

This indicates that a heavy load can be moved with only moderate effort. - Levers of the third class exert middle-of-the-road force.

The illustration shows a class 1 lever with a fulcrum in the middle and load and effort located at the other two ends.

Thus, the correct option is B.

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Answer:

pls give me brainliest

Explanation:

Answer:

vf = 0

Explanation:

Since the initial height hi = 0, we can rewrite the energy equation as

vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0

Therefore, his final velocity vf is

vf = 0

Answer:

a) capacitance is doubled., b)  Q = cte, c) oltage doubling the distance doubles, d)    ΔE =0, e)  U = Q² / 2C, f) W>0

Explanation:

he capacitance of a condensate is

          C =[tex]\frac{ Q}{ \Delta V} =\epsilon_o \frac{A}{d}[/tex]

let's use this expression to answer the question

a) Capacitance.

Without distance, the capacitance is doubled.

Answer: Half

b) The charge.

As the battery is disconnected, no more electrons reach the capacitor, so the charge remains the same

           Q = cte

c) the voltage

          ΔV = E d = ([tex](\frac{Q}{\epsilon_o A}) \ d[/tex]

so the voltage doubling the distance doubles

d) The electric field between parallel plates is constant

           E = Q / A eo

           E =0

e) The stored energy is described by the expression

          U = Q² / 2C

as capacitance decreases and discant increases, stored energy increases

f) The work to separate the positive charge, that the force must be in the same direction as the electric force

g) when the battery is disconnected the energy in the capacitor remains constant

1 N*m = 1 Joule

40 N*m = 40 joules

Answer:

-0.0069 rad/s

Explanation:

The change in angular velocity of the rod can be determined by using the conservation of angular momentum equation: Lf = Li.

The initial angular momentum of the rod is Li = Iwo and the final angular momentum of the rod is Lf = Iwf.

Plugging in the given values, we get:

(1.05 x 10^-3 kg•m^2)(0.606 rad/s) + (5 x 10^-3 kg)(0.609 m)^2(wf) = (1.05 x 10^-3 kg•m^2)(wo).

Solving for wf, we get wf = -0.0069 rad/s.

Therefore, the change in angular velocity of the rod is -0.0069 rad/s.

Answer:

A. and D.

Explanation:

Statements A and D best correctly describe transmutation. The parent and daughter elements are different, and the number of nucleons is conserved.​

Transmutation is the process of converting one chemical element to another. Transmutation is any process that alters the number of protons or neutrons in an atom's nucleus.

The  statements correctly describe transmutation are;

A. The parent and daughter elements are different

D. The number of nucleons is conserved.​

Hence, statements A and D best correctly describe transmutation.

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Answer:

d= -2

Explanation:

t=5s

S=100 meters

V= 10 m/ s

d=?

deceleration = (final velocity - initial velocity) / time. d = (vf - vi)/t.

The formula for acceleration can be used, recognizing that the final result must have a negative signe.

d= (0-10)/5

d= -2

Answer:

the answer is

Mahatma Gandhi

Answer:

Mahatma Gandhi

Answer:

Lami's Theorem states:

“When three forces acting at a point are in equilibrium, then each force is proportional to the sine of the angle between the other two forces”.

Explanation:

Answer:

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Explanation:

sbnwtauajababcahajanavgzuz

Answer:

4.05 000 the about id

Explanation:

Answer:

. an increase in the mass on the spring

Explanation:

Period of oscillation is inversely proportional to amplitude. Since amplitude is displacement and displacement is, the answer of objective b is ignored

My answer is a