1. Weight is the gravitational pull with which the earth attracts the body towards the center of the earth. The S.I unit is Newton (N)
2. The weight of an object is related to its mass with the below equation.
W = mg
Where W = weight, m = mass and g = acceleration due to gravity
3. The mass m = 50 kg and g = 9.8 m/[tex]s^{2}[/tex]
Substitute the parameters in the equation above.
W = 50 x 9.8
W = 490 N
4. An object is accelerating when it speeds up. If the object slows down, it means it is decelerating. The correct answer is option A
5. Newton's second law of motion is:
F = ma
Where F = force applied, m = mass and a = acceleration
Therefore, Newton's second law of motion relates an object's acceleration to its net force acting on it. The correct answer is option C
6. According to Newton's second law of motion which relates an object's acceleration to its mass, doubling the net force acting on an object a doubles its acceleration. Because mass is always constant.
7. Since the weight of an object is related to its mass with the equation.
W = mg, If the mass of an object doubles, its weight will also doubles. Option A is the correct answer.
8. If you know the mass of an object, you can calculate its weight with the formula F = mX when X = 9.8m/[tex]s^{2}[/tex]
9. Force is expressed in unit as Newton (N)
10. The parameters given are :
mass m = 20kg
Force F = 40N
To calculate acceleration, use the formula F = ma
Substitute all the parameters into the equation.
40 = 20a
a = 40/20
a = 2m/[tex]s^{2}[/tex]
The correct option is D
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Two metal spheres are suspended on wires so that they hang next to each other, just touching. Sphere X is raised to a certain height and released. Without
friction or air resistance, describe what would happen to Sphere Y.
Answer:A
Explanation:
What is the initial velocity of a moose who
accelerates uniformly at 1.5 m/s/s for 5 seconds and
finishes with a velocity of 7 m/s?
Answer:
- 0.5 m/s
Explanation:
(1) Acceleration = change in velocity / time
(2) Change in velocity = (Final velocity - Initial velocity)
We know:
acceleration = 1.5 m/s/s
time = 5 seconds
final velocity = 7 m/s
x = initial velocity)
1.5 = ( 7 - x ) / 5
1.5 x 5 = ( 7 - x )
7.5 = 7 - x
x = -0.5 m/s
You can check the answer by plugging in the values to equation (1).
The answer is 84N, but what is the mass and weight calculation?
Answer:
weight= density ×volume× 9.8
mass=density×volume
Explanation:
[tex]weight = 0.12 \times 0.04 \times 0.04 \times 3.14 \times 13600 \\ \times 9.8 = 80.351 \: n \\ \\ mass = 0.12 \times 0.04 \times 0.4 \times 3.14 \times 13600 = \\ = 8.199 \: kg[/tex]
que influencia tienen los rayos x en la actualidad?
what is atmospheric pressure
Answer:
IN THE EXPLANATION!!
Explanation:
Atmospheric pressure, also known as barometric pressure (after the barometer), is the pressure within the atmosphere of Earth.
Answer:
atmospheric pressure is the pressure exerted on the Earth's surface due to weight of air above it.
What is mass? (7th grade definition) thanks!!
Answer:
→ Mass is the lightness or heaviness of a body that is free from any force field.
OR→ Mass is the volume of a body multiplied by its density.
[tex].[/tex]
Four different blocks are resting on the floor. They each have a different mass, and they are each made of a different material, so the coefficients of friction are not the same. Using the information in the table below, rank, from highest to lowest, the magnitude of the maximum horizontal force
To answer this question, it is necessary to apply the static condition from Newton´s Laws
The solution is:
Fd > Fc > Fa > Fb
From the body free diagram, and from the second Newton´s law of movement we get:
∑ Fx = 0 F - Fr = 0 F = Fr Fr = μ×N
∑ Fy = 0 N = m×g ⇒ Therefore Fr = μ×m×g
F = μ×m×g g is the same in all the cases, then we just compare the products μ×m
So when F is just greater than Fr, the body will start moving
we make a table, with values from the information table.
1.- μ×m = 0.5× 40 = 20
2.-μ×m = 0.4× 80 = 16
3.- μ×m = 0.7× 30 = 21
4.- μ×m = 0.9× 35 = 31.5
According to the table, from highest to lowest the magnitude of the horizontal force is:
Fd > Fc > Fa > Fb
RelatedLink: https://brainly.com/question/16799228
the apparent shift of a nearby object against the background of more distant stars is called:
Answer:
Astronomers estimate the distance of nearby objects in space by using a method called stellar parallax, or trigonometric parallax. Simply put, they measure a star's apparent movement against the background of more distant stars as Earth revolves around the sun.
what is the most dangerous chemical on the periodic table?
Answer:
Polonium Marked as Po with atomic number 84, is a highly radioactive heavy metal. It is arguably the most lethal known material.
Explanation:
A cat falls from a table of height 1.3 m. What is the impact speed of the cat?
O A. 7.5 m/s
O B. 2.5 m/s
O C. 5.0 m/s
O D. 25.5 m/s
SUBMIT
The impact speed will be
v^2 = 2*9.8*1.3
v^2 = 25.48
v= 5.04 m/s or O C. 5.0 m/s
for each pair of terms below, write a sentence that summarizes how they are different.
thermal conductor, thermal insulator
thermal expansion, thermal contraction
Answer:
Thermal expansion ,thermal contraction
Explanation:
They are different because it has different cause and chemical reactions
thermal contraction is a chemical reaction
Physics 2.4.3 lab, please help, i just need this so i could move on to the next unit. 75 points if you could please do this
Answer:
There are only 38 points.
Explanation:
why are you saying 75?
how to turn off check engine light to pass emissions
Answer:
you must connect a radar reader under the steering wheel and clear it
Explanation:
A top-fuel dragster accelerates from rest to a velocity of 100 m/s in 8 s. What is the acceleration?
Answer:
100 m/s ÷ 8 = 12.5 m/s
Explanation:
You must put multiply (÷)
Explain how energy is transferred in an impact situation such as a car crash.
I PROMISE TO MARK YOU BRAINLIEST I JUST NEED A THOROUGH ANSWER!!
THANKS IN ADVANCE BESTIES
You are driving up an inclined road. After 3.0 km you notice a roadside sign that indicates that your elevation has increased by 160 m. What is the angle of the road above the horizontal?
Answer:
~3°
Explanation:
x^2 + 0.16^2 = 3^2
x^2 + 0.0256 = 9
x^2 = 8.9744
x = sqrt(8.9744) = 2.99... = ~3
Which of the following is a vector?
mass
time
acceleration
speed
Answer:
acceleration is a vector quantity the explanation is below
Explanation:
Acceleration is a vector quantity. Acceleration has both magnitude and direction. For example, 9.8ms2 downward or −9.8ms2 vertically is an acceleration.
you push a block of 50kg with a force of 400 N over a distance of 8m. How much kinetic energy does the box gain?
Answer:
The box gains 3200 J of kinect energy.
Explanation:
What is kinect energy?Kinect energy is the energy of an object has because of its motion. Almost anything that has mass and it's in motion has kinect energy. Examples:
wind;throwing a footbal;driving a car;lauching a rocket;etc.What is the work energy theorem?Also known as the principle of work and kinect energy, it states that the work done by all forces acting upon an object equals the change of its kinect energy.
For example, if you pull a box, then you're exerting a force on it and it moves forward. Since the box has mass and it's in motion, you have changed its kinect energy.
Solution:
Write the data down:
[tex]\bullet \quad \mathsf{m=50\,kg}\\\\\bullet \quad \mathsf{F=400\,N}\\\\\bullet \quad \mathsf{d=8\,m}[/tex]
Apply work energy theorem:
[tex]\mathsf{W}= \Delta\mathsf{K}[/tex]
The amount work done equals the change of kinect energy:
[tex]\mathsf{W}=\mathsf{K-K_o}[/tex]
Since the block is at rest at the beginning, so it has zero initial kinect energy:
[tex]\mathsf{W}=\mathsf{K-0}\\\\\\\mathsf{W}=\mathsf{K}[/tex]
Now, apply the formula for work to the left hand side of the equation:
[tex]\mathsf{F\cdot d}=\mathsf{K}\\\\\\\mathsf{400\cdot 8}=\mathsf{K}\\\\\\\therefore \boxed{\mathsf{K=3200\,J}}[/tex]
Conclusion: the box has gained 3200 J of kinect energy.
Happy studying!
Brainly Team
New attempt is in progress. Some of the new entries may impact the last attempt grading. Incorrect. The hammer throw is a track-and-field event in which a 7.30-kg ball (the hammer) is whirled around in a circle several times and released. It then moves upward on the familiar curved path of projectile motion and eventually returns to the ground some distance away. The world record for the horizontal distance is 86.75 m, achieved in 1986 by Yuriy Sedykh. Ignore air resistance and the fact that the ball was released above the ground rather than at ground level. Furthermore, assume that the ball is whirled around a circle that has a radius of 2.22 m and that its velocity at the instant of release is directed 47.9° above the horizontal. Find the magnitude of the centripetal force acting on the ball just prior to the moment of release.
This question involves the concepts of centripetal force, range of projectile and projectile motion.
The magnitude of centripetal force is "2812.8 N".
First, we will find the velocity of the ball by using the formula of the range of the projectile.
[tex]R = \frac{v^2Sin2\theta}{g}[/tex]
where,
R = range of projectile = 86.75 m
v = speed = ?
θ = launch angle = 47.9°
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]86.75\ m = \frac{(v)^2Sin(2)(47.9^o)}{9.81\ m/s^2}\\\\v = \sqrt{\frac{(86.75\ m)(9.81\ m/s^2)}{Sin95.8^o}}[/tex]
v = 29.25 m/s
Now, we will use the formula to find out the centripetal force:
[tex]F_c = \frac{mv^2}{r}[/tex]
where,
[tex]F_c[/tex] = Centripetal Force = ?
m = mass of the ball = 7.3 kg
v = speed = 29.25 m/s
r = radius = 2.22 m
Therefore,
[tex]F_c = \frac{(7.3\ kg)(29.25\ m/s)^2}{2.22\ m}[/tex]
Fc = 2812.8 N = 2.812 KN
Learn more about centripetal force here:
https://brainly.com/question/11324711?referrer=searchResults
why do we need to know physical and chemical change?
It is important to understand the differences between physical and chemical changes. ... It helps to think of physical changes as those involving changes that don't change the make up of the substance, while chemical changes are those that create a new substance. Physical Changes involve energy.
Please help I'll mark brainliest
+50 POINTS!!
SOMEONE PLEASE HELP!!!! I CANT FIND ANYTHING ELSE TO HELP ME WITH THIS!!!
Measure a pencil, end to end. Draw a sketch of the pencil and show your measurements. If you were to balance the pencil horizontally on your finger, where do you think it would be balanced? Note this on your sketch, and write down your hypothesis (distance from each end) and your prediction.
Now test your hypothesis. Balance the pencil on your finger horizontally. When it is balanced, your finger is at the center of gravity. Note and make a mark where your finger is in relation to each end of the pencil.
Measure from one end of the pencil to where your finger balanced it. Show this on your sketch, and record the data it in your chart.
Repeat steps b-c a second time for the pencil.
Repeat steps a - d using a pen and crayon as well.
What are your results? Compare your results with your hypothesis and then write an explanation in a conclusion. Which item has a center of gravity closer to the actual center that you measure?
Answer:
my pencil is about and 1/2 inches
i think it would be in the middle about 1 inch away
my hypothesis was wrong he was like a 1/2 inch on one he right side and he left didn't
Explanation:
hope this helps
A dog has the mass of 4kg and runs at a velocity of 3m/s. What is its KE
Answer:
m=4kg
v=3m/s
KE=1/2mv^2
KE=1/2×4×3×3
KE=18Joules
Explanation:
PLS MARK BRAINLIEST
3. A block is pushed with 30N of force this changes the velocity from 20m/s to
30m/s, after 2 seconds. What is the mass?
let's find the acceleration first :
[tex] \boxed{a = \frac{v - u}{t} }[/tex][tex]a = \dfrac{30 - 20}{2} [/tex][tex]a = \dfrac{10}{2} [/tex][tex]a = 5 \: \: ms {}^{ - 2} [/tex]now, we know that :
[tex]f orce= mass \times acceleration[/tex][tex]30 = m \times 5[/tex][tex]m = \dfrac{30}{5} [/tex][tex]m = 6 \: \: kg[/tex]hence, mass = 6kg
In any sample of water, there are always some water molecules which have become ions. These ions are produced by transferring a ________ from one water molecule to another
Answer: Proton
Explanation:
How does the law of conservation of matter apply to atoms?
On a pirate map, “X” marks the spot. Does that “X” reference the position or the
displacement of the treasure?
Answer:
it References the position
Explanation:
Displacement is defined to be the change in position of an object.
And the treasure can't move by itself because its an object (and objects don't move).
03. A rocket and its payload have a total mass of 5.0 × 104 kg. How large is the force produced by the engine (the thrust) when
(a) the rocket is “hovering” over the launch pad just after ignition, and
(b) when the rocket is accelerating upward at 20 ms-2?
Answer:
hddhgdffghuhuuy680ji8fgddff dadeldhura 30x72x19 ra 30x72x19 ra samidhan 6I
C
B.
1A.
1
2
3
G.
C.
45 6 8 9 11 12 time(s)
D.
F.
E.
Which section(s) of the graph would indicate that the object is moving forward?
A A and G
B A, F, and G
C Band E
D
A, B, C and G
Answer:
b
Explanation:
a,f,,and g is correct because it is indicated that object moving forward
Si se impulsa un bloque con una velocidad de 15m/s sobre el piso sin rozamiento mostrado. Determinar la altura “h” que alcanzará, no existe rozamiento.
PORFAAA AYUDA URGENTE
La altura máxima alcanzada por el bloque es de 14.471 metros.
En esta pregunta asumimos que la altura inicial del bloque es igual a tres metros por encima del la altura de referencia y la altura final puede ser determinada mediante el principio de conservación de la energía, en cuyo caso, la suma de la energía cinética traslacional inicial ([tex]K[/tex]) y la energía potencial gravitacional inicial ([tex]U_{o}[/tex]), ambos en joules, es igual a la energía potencial gravitacional final ([tex]U_{f}[/tex]), en joules. Matemáticamente hablando, tenemos la siguiente expresión:
[tex]U_{o}+K = U_{f}[/tex]
[tex]m\cdot g\cdot z_{o} + \frac{1}{2}\cdot m\cdot v^{2} = m\cdot g \cdot z_{f}[/tex] (1)
Donde:
[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]z_{o}[/tex], [tex]z_{f}[/tex] - Alturas inicial y final, en metros.[tex]v[/tex] - Rapidez inicial del bloque, en metros por segundo.A continuación, despejamos la altura final del bloque:
[tex]z_{f} = z_{o}+\frac{1}{2}\cdot \frac{v^{2}}{g}[/tex] (2)
Si sabemos que [tex]z_{o} = 3\,m[/tex], [tex]v = 15\,\frac{m}{s}[/tex] y [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], entonces la altura máxima alcanzada por el bloque es:
[tex]z_{f} = 3\,m + \frac{1}{2}\cdot \left[\frac{\left(15\,\frac{m}{s} \right)^{2}}{9.807\,\frac{m}{s^{2}} } \right][/tex]
[tex]z_{f} = 14.471\,m[/tex]
La altura máxima alcanzada por el bloque es de 14.471 metros.
Invitamos cordialmente a ver esta pregunta sobre el principio de conservación de la energía: https://brainly.com/question/19561287