1. How long is a day on Venus?
2. How is Venus similar to Earth?
3. Describe Venus’ atmospheric composition.

Answers

Answer 1

Answer:

2:Venus is often named as Earth's twin because both worlds share a similar size, surface composition and have an atmosphere with a complex weather system. ... Both planets have almost the same size and density and Venus is only a 30% closer to the Sun than Earth 1:116d 18h 0m 3: The atmosphere of Venus is made up almost completely of carbon dioxide. It also includes small doses of nitrogen and clouds of sulfuric acid. ... This composition causes a runaway greenhouse effect that heats the planet even hotter than the surface of Mercury, although Venus lies farther from the sun.

Explanation:


Related Questions

The mass of an object is 84 kg. Find its weight on the Earth and the Moon.​

Answers

Answer:

We would take the mass given, 80 kg, and multiply it times the acceleration of Earth's downward pull on that mass, 9.8 m/s/s. So the weight on Earth is 784 newtons. So the weight of the same 80 kg mass on the moon is 133.28 N.

hi

mass is express  in Newtons.

On Earth gravity is  9.807   so  wieght would be :   9.807 * 84= 823.79

On the Moon garvity is  1.62  so weight would be  :  84 *1.62 = 136.08

Help plz for 25 points !! I only have an hour left !

Answers

See the pic for the work!

Would the following reaction be endothermic or exothermic? Why?
CH4 + 02 --> CO2 + H2O + Energy
A. Exothermic because energy is a reactant
B. Endothermic because energy is a reactant
C. Endothermic because energy is a product
D. Exothermic because energy is a product

Answers

Answer:

D. Exothermic because energy is a product

Explanation:

ENDOTHERMIC REACTION: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.

EXOTHERMIC REACTION: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.

Hence, the correct answer for this question will be:

D. Exothermic because energy is a product

PLS HELP
According to the theory of spontaneous generation, tadpoles were believed to arise form dead flesh. True or False.
A.
FALSE
B.
TRUE

Answers

B. True

"This was the idea that non-living objects can give rise to living organisms."

eeeee
help pls
pls
pls

Answers

Answer:

hey dream I m your big fan for u I have answered this question The third one is correct.

When the number of gas particles at a constant pressure decreases how will the volume of the gas change?

Answers

PV = nrT
Volume will decrease

2. When braking and turning, you use ___?
a. All four wheels of traction
b. Only the outside edge of your tires
c. Split traction
d. Additional traction

Answers

Answer:

split traction

Explanation:

https://forms.office.com/Pages/ResponsePage.aspx?..
Print Management S Show My Homework
worites
10
Calculate the power in resistor X when the voltage across X is 2.1 V and the current in resistor
X is 0.041 A
(2 Points)

Answers

Answer:

P = 0.0861 W = 86.1 mW

Explanation:

The electrical power in a resistor is defined as the product of the current passing through that resistor and the voltage across that resistor. Therefore, the formula can be written as follows:

[tex]P = VI[/tex]

where,

P = Power in Resistor X = ?

V = Voltage across resistor X =  2.1 V

I = Current passing through resistor X = 0.041 A

Therefore,

[tex]P = (2.1\ V)(0.041\ A)[/tex]

P = 0.0861 W = 86.1 mW

how does the input distance of a third-class lever compare to the output distance​

Answers

Answer:

A first-class lever: fulcrum is between input and output force; second-class lever: output force is between input force and fulcrum; third-class lever: input force is between fulcrum and output force

A music fan at a swimming pool is listening to a radio on a diving platform. The radio is playing a constant- frequency tone when this fellow, clutching his radio, jumps off. Describe the Doppler Effect heard by (a) a person left behind on the platform and (b) a person down below floating on a rubber raft. In each case, specify (1) whether the frequency is greater or smaller than the frequency produced by the radio, (2) whether the observed frequency is constant, and (3) how the observed frequency changes during the fall, if it does change. Give your reasoning.

Answers

Answer:

The Doppler Effect is given by the following relation;

[tex]f' = \left (\dfrac{v + v_0}{v - v_s} \right) \times f[/tex]

Where;

f' = The frequency the observer hears

f = Actual frequency of the wave

v = The velocity of the sound wave

[tex]v_o[/tex] = The velocity of the observer

[tex]v_s[/tex] = The velocity of the source

Where the observer is stationary, we have;

(i) When the source is moving in the direction of the observer

[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]

(ii) When the source is receding from the observer, we have;

[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]

Therefore;

(a) A person left behind on the platform

For a person left behind on the platform, we have that the radio source is receding, therefore, we have;

[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]

(1) Given that (v + [tex]v_s[/tex]) > v, therefore, v < (v + [tex]v_s[/tex]), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively smaller

(b) A person down below floating on a rubber raft

For the the person down below on the rubber raft, the radio source is advancing

Therefore, the radio source is moving towards the person at rest down on the rubber raft, therefore, we have;

[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]

(1) Given that (v - [tex]v_s[/tex]) < v, therefore, f' > f, the frequency heard by the person down below floating on the rubber raft, f', is greater (higher) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)

Explanation:

A house painter stands 3.00 m above the ground on a 5.00-m-long ladder that leans against the wall at a point 4.70 m above the ground. The painter weighs 676 N and the ladder weighs 107 N. Assuming no friction between the house and the upper end of the ladder, find the force of friction that the driveway exerts on the bottom of the ladder. If the force of friction is away from the wall, enter a negative value and if the force of friction is toward the wall, enter a positive value.

Answers

Answer:

The force of friction that the driveway exerts on the ladder ≈ -176.03 N

Please see attached force diagram created with MS Visio

Explanation:

The height of the house painter above the ground = 3.00 m

The length of the ladder = 5.00 m

The height above the ground at which the ladder leans on the wall = 4.70 m

The weight of the painter = 676 N

The weight of the ladder = 107 N

The angle of inclination of the ladder, arcsin(4.7/5) ≈ 70.05°

For equilibrium, the sum of moments at a point, ∑M = 0

Taking moment about point A gives;

4.7 × R = 107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5)))

R = (107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5))))/4.7 ≈ 176.03

The reaction force at the top of the ladder, R ≈ 176.03 N

For equilibrium, we have;

The sum of the horizontal forces, ∑Fₓ = 0

The reaction at the top of the ladder, R + The force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] = 0

R + [tex]F_R[/tex] = 0

∴ R = [tex]-F_R[/tex]

R ≈ 176.03 N = [tex]-F_R[/tex]

∴ [tex]F_R[/tex] = -176.03 N

Therefore, the force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] ≈ -176.03 N (acting away from the wall).

When a ball is being lifted work is being done to it, giving it ______ energy.

Answers

Kinetic or Potential energy?

Kinetic energy is energy expended
Potential energy of energy stored










***Potential***

Which of the following statements is true with
regards to Blackbody radiation?
a)
b)
c)
A blackbody emits more energy at longer
wavelengths as it heats up
A blackbody emits energy at all wavelengths
The shape of the blackbody spectrum
depends on what the source is made of
All of the above
None of the above
00)
e)​

Answers

I believe that it most likely would be C,

Electricity is the _____________ of electrons, because electrons _____________ from atom to atom.

Answers

electricity is the FLOW of electrons, because electrons PASS from atom to atom

Electricity is the [tex]\sf{\underline{flow}}[/tex] of electrons, because electrons [tex]\sf{\underline{passes}}[/tex]  from atom to atom.

A light bulb has a power output of 80 W and it has been left on for 90 seconds. How much work was done?

Answers

7200 joules of heat and light energy was dissipated into the air. But no work was done ... no force moved through no distance.

3. What does the difference in force depend on?

Answers

Answer:

it depends on the relative masses of the objects.

Explanation:

It depends on the mass of an object

In which of the following situations is there acceleration? (There may be more than one correct answer)

a. A car is sitting at a stoplight. The light turns green and the car begins moving.

b. A car maintains a speed of 10 mi/hr as it turns a corner.

c. When a truck approaches a stop light, it begins to slow down.

d. A car travels at 65 mi/hr.

Answers

A is the correct answer because “The light turns green and the car begins moving.”

Can some one please help me

Answers

Answer:

its "up, then down, then up"

Explanation:

what is the difference between storm spotter and storm chaser?

Answers

Answer:

this is just a guess

Explanation:

a storm spotter only spots the storm and a storm chaser looks for the storm????

The weight of a cuboid box is 288 N. Find its mass.​

Answers

Answer:

29.39 kg

Explanation:

From the question,

W = mg...................... Equation 1

Where W = weight of the cuboid box, m = mass of the cuboid box, g = acceleration due to gravity.

make m the subject of the equation

m = W/g.................. Equation 2

Given: W = 288 N

Constant: g = 9.8 m/s²

Substitute these values into equation 2

m = 288/9.8

m = 29.39 kg

An electric toy with a resistance of 2.50\,\Omega is operated by a 3.00\,\text{V} battery. (c) How much energy was delivered to the toy [over four hours]?

Answers

Answer:

Energy = 51840 J = 51.84 KJ

Explanation:

The electrical energy delivered to the toy can be found out by the following formula:

[tex]Energy = (Power)(time)\\Energy = (VI)(t)\\Enegry = VIt\\[/tex]

where,

V = Voltage = 3 V

R = Resistance = 2.5 Ω

I = Current = V/R (Ohm's Law) = 3 V/2.5 Ω = 1.2 A

t = time = (4 h)(3600 s/1 h) =  14400 s

Therefore,

[tex]Energy = (3\ V)(1.2\ A)(14400\ s)\\[/tex]

Energy = 51840 J = 51.84 KJ

Please solve this worksheet for me It’s very important please don’t write unnecessary things or else I’ll report please help me i request

Answers

Answer:

1. 231.25 mL

2. 218.75 kPa

3. 6.21 L

4. 427.5 mL

5. 83.01 mL

6. 307.6 mL

7. 1.15 L

8. 440.4 mL

Explanation:

This questions describes Boyle's law. Using Boyle's law equation to solve the questions as follows:

P1V1 = P2V2

Where;

P1 = initial pressure

P2 = final pressure

V1 = initial volume

V2 = final volume

Please find the answers to each question as an attachment.

What allows a metal to be pounded into a flat shape?

Answers

C im pretty sure?.........

Figure 1 shows the kinetic energy as a function of time for a 2kg object that is released from rest and falls toward Earth’s surface. Figure 2 shows the kinetic energy as a function of time for a 5kg object that is released from rest and falls toward Earth’s surface. Both objects are released simultaneously from the same height. How much does the gravitational potential energy of the object-object-Earth system change from 0s to 10s ?
a) 400J
b)600 J
c)1000 J
d) 1400J

Answers

Answer:

The answer is 1400 J, according to my Physics teacher.

Explanation:

You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)

IF SOMEONE CAN'T FIND THE ANSWER I WILL COMMIT ARSON PLEASE HELP MEE
Brainliest + random amount of points please help me It's a crossword

Answers

Answer:

Freefall

Explanation:

Hi the answer is freefall, hope this helps :)

Please help choose one
A B C or D
???

Answers

I believe the answer is B

This is because in combustion reactions the products are being burned meaning heat increases. Therefore energy is transferred from the fuel to the surroundings.
^^Correct!!!!!!!!!!!!

Helppppppl!!!!!!!!!!!​

Answers

Answer:

I think deposition of C is the oldest deposit

A 1400 kg car traveling at 17.0 m/s to the south collides with a 4700 kg truck that is at rest. The car and truck stick together and move together after collision. What is the final velocity of the two-vehicle mass? If Kinetic Energy = 0.5 * m * v^2, calculate the KE before the crash and the KE of the combined vehicles after the crash.

Answers

Answer:

Final velocity = 7.677 m/s

KE before crash = 202300 J

KE after crash = 182,702.62 J

Explanation:

We are given;

m1 = 1400 kg

m2 = 4700 kg

u1 = 17 m/s

u2 = 0 m/s

Using formula for inelastic collision, we have;

m1•u1 + m2•u2 = (m1 + m2)v

Where v is final velocity after collision.

Plugging in the relevant values;

(1400 × 17) + (4700 × 0) = (1400 + 1700)v

23800 = 3100v

v = 23800/3100

v = 7.677 m/s

Kinetic energy before crash = ½ × 1400 × 17² = 202300 J

Kinetic energy after crash = ½(1400 + 1700) × 7.677² = 182,702.62 J

What could be the average human density? Justify?

Answers

Answer:

985 kg/m3

Explanation:

The average density of the human body is 985 kg/m3 k g / m 3 , and the typical density of seawater is about 1020 kg/m3 k g / m 3 .

Explanation:

the worldwide human population density is around 7,500,000,000 ÷ 510,000,000 = 14.7 per km2 (38 per sq. mi.). If only the Earth's land area of 150,000,000 km2 (58,000,000 sq. mi.) is taken into account, then human population density is 50 per km2 (129 per sq.

please help its worth 10 points
no links please!

Answers

Answer:

which question

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