100 Points!!! Algebra graphing question. Describe the reflection in the function as it relates to the parent graph. Then graph the function. Y=-|x| Photo attached. Thank you!!

Answer:

y=2x+10

Explanation: They start with paying $10 and have to pay and extra $2 for each time at the concession stand.

If Jake whittles little wooden figurines and begins to sell them. If the demand function for his figurines is given by D(q) = 80 - 1.25q and the supply function is S(q) = 0.75g. The equilibrium quantity is  40 units.

Given the demand function D(q) = 80 - 1.25q and the supply function S(q) = 0.75q, we can find the equilibrium quantity by setting these two functions equal to each other and solving for q:

D(q) = S(q)

80 - 1.25q = 0.75q

Simplifying this equation, we get:

2q = 80

q = 40

Therefore, the equilibrium quantity is q = 40. At this quantity, the quantity demanded is:

D(q) = 80 - 1.25q = 80 - 1.25(40) = 30

And the quantity supplied is:

S(q) = 0.75q = 0.75(40) = 30

Thus, the equilibrium quantity of Jake's wooden figurines is 40 units.

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The cost to treat one person who has TB is R1,579.82, rounded to 2 decimal places.

Total cost refers to the sum of all expenses incurred in producing a product or providing a service. It includes both the fixed costs (costs that remain constant regardless of the level of output) and variable costs (costs that vary with the level of output)

To calculate the cost to treat one person who has TB, we need to divide the total cost of treating all infected people by the number of infected people:

Cost to treat one person = Total cost of treatment / Number of infected people

Plugging in the given values, we get:

Cost to treat one person = R84,724,707 / 53,642

Cost to treat one person = R1,579.82

Therefore, the cost to treat one person who has TB is R1,579.82, rounded to 2 decimal places.

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Therefore, the difference between the most common and least common amounts on the line plot is 8.

"Least common" refers to the item or value that appears the fewest number of times in a given set or group. For example, if you have a set of numbers {2, 4, 2, 5, 3, 4, 1}, the least common number in the set is 1 because it appears only once, while the most common number is 2 and 4 because they both appear twice. In a line plot, the least common amount is the one that appears the fewest number of times on the p.

Given by the question.

To find the difference between the most common and least common amounts on a line plot, follow these steps:

Look at the line plot and identify the most common amount. This is the amount that appears the most frequently on the plot.

Look at the line plot and identify the least common amount. This is the amount that appears the least frequently on the plot.

Subtract the least common amount from the most common amount. The result will be the difference between the most common and least common amounts on the line plot.

For example, if the most common amount on the line plot is 10 and the least common amount is 2, then the difference would be:

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Answer:

Starting with:

-15 > -11 + w

Add 11 to both sides:

-15 + 11 > w

Simplifying:

-4 > w

Therefore, the solution for the inequality -15 > -11 + w, when solved for w, is:

w < -4

Using functions,

Part A: f (3) = 6(3) + 14 = 32.

g (3) = 3 + 2 = 5

Part B: (f/g) (3) will be 6.4.

The core concept of calculus in mathematics is a function. The relations are certain kinds of the functions. In mathematics, a function is a rule that produces a different result for every input x. In mathematics, a function is represented by a mapping or transformation. Letters like f, g, and h are widely used to indicate these operations. The set of all potential values that can be passed into a function while it is specified is known as the domain. The entire set of values that the function's output is capable of creating is referred to as the "range." The range of potential values for a function's outputs is known as the co-domain.

Here in the question,

f (x) = 6x + 14

g (x) = x + 2

Now we have to find for the value of x,

f (3) = 6(3) + 14 = 32.

g (3) = 3 + 2 = 5

So, f (3) = 32 and g (3) = 5.

Now,

(f/g) (3) will be 32/5 = 6.4.

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x²=22.136

Its the last one

Answer: 41

Step-by-step explanation:

-26+z =1 5

       z= 15+26

       z= 41

Answer:

z = 41

Step-by-step explanation:

-26 + z = 15.                      | + 26
-26 + z + 26 = 15 + 26
z = 41

Answer:

5.5 hours

Step-by-step explanation:

Volume of a cylinder = π(d/2)²h

V = (3.14)(8/2)²(1.2) = 60.288 m³

fill rate = 11 m³/hr

time to fill the pool = (60.288 m³)(1 hr/11 m³) = 5.48 hr ≈ 5.5 hrs

The five in 35.76 is 100 times bigger than the five in 26.95.

Here we want to compare the values of the 5's in two different numbers, which are 35.76 and 26.95.

To compare them we need to compare the place value in which each five is.

To compare them, just write the numbers but replacing all the other values by zeros:

35.76 = 05.00 = 5

26.95 = 00.05 = 0.05

Now take the quotient of these two, we will get:

5/0.05 = 100

Thus, the 5 in 35.76 is 100 times bigger than the 5 in 26.95.

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A. The length of the cord needed to reach corner C is 17.6 m

B. The distance between the electrical outlet and corner N is 14.3 m

The length of the cord needed can be obtained as follow:

Sine θ = opposite / hypotenuse

Sine 27 = 8 / Length of cord

Cross multiply

Length of cord × sine 27 = 8

Divide both sides by sine 27

Length of cord = 8 / sine 27

Length of cord = 17.6 m

First, we shall determine the length OB. Details below:

Tan θ = Opposite / Adjacent

Tan 27 = 8 / Length OB

Cross multiply

Length OB × tan 27 = 8

Divide both sides by tan 27

Length OB = 8 / tan 27

Length OB = 15.7 m

Finally, we shall determine the distance between the electrical outlet and corner N. Details below:

Length BN = Length OB + Length ON

30 = 15.7 + Distance

Collect like terms

Distance = 30 - 15.7

Distance = 14.3 m

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Answer: b

Step-by-step explanation:

The number of students that will receive the attendance award is 26. The correct option is a.

A % is a quantity or ratio that, in mathematics, represents a portion of one hundred. A dimensionless relationship between two numbers can be represented in a variety of ways, such as through ratios, fractions, and decimals.

We must first ascertain how many students will be recognized. We can achieve this by dividing the overall number of students (650) by the proportion of recipients (4%). 650 x 0.04 = 26 Hence, 26 kids will be recognized for their flawless attendance.

According to the given conditions, 650 students and 4 will receive a perfect attendance award.

650 x 4% = 26

Therefore, the correct option is a, 26.

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The options are:

26

25

24

23

Answer: 2.5 dm

Step-by-step explanation:

Divide 25.0 by 10

= 2.5

As we are looking for the distance to the nearest whole number, we can round this answer to 517 feet. This means that when the plane has reached an altitude of 300 feet, it has flown a distance of 517 feet.

To find the distance that the plane has flown when it has reached an altitude of 300 feet, we can use the formula d = x * tan(a) where d is the distance, x is the altitude, and a is the angle. We are given the altitude of 300 feet and the angle of 15°. Plugging those values into the formula, we get d = 300 * tan(15°) = 517.4 feet. Rounding this to the nearest whole number, we get 517 feet.

To find the distance that the plane has flown when it has reached an altitude of 300 feet, we can use the formula d = x * tan(a). This equation is derived from the Pythagorean Theorem, where d is the distance, x is the altitude, and a is the angle. We are given the altitude of 300 feet and the angle of 15°, so we can plug these values into the equation. When we do this, we get d = 300 * tan(15°) = 517.4 feet. As we are looking for the distance to the nearest whole number, we can round this answer to 517 feet. This means that when the plane has reached an altitude of 300 feet, it has flown a distance of 517 feet.

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Tο maximize its prοfits, the cοrpοratiοn shοuld thus sell the phοnes fοr $250 as the value οf x that οptimizes the functiοn [tex]r(x) = x[/tex].

A functiοn in mathematics is a principle οr cοnnectiοn that links οne input value tο οne οutput value. A functiοn, in mοre technical terms, is a cοllectiοn οf οrdered pairs (x, y) where there is precisely οne y fοr every x.

The argument οr independent variable is the input value x, and the value οr dependent variable is the οutput value y. Algebraic equatiοns, tables, diagrams, and verbal explanatiοns are just a few οf the nοtatiοns that can be used tο represent functiοns.

Finding the value οf x that οptimizes the functiοn r(x) = x will help us determine the price that will generate the mοst prοfit (1000 - 2x).

We can start by simplifying and expanding this functiοn:

[tex]r(x) = 1000x - 2x^2[/tex]

We can nοw take the derivative οf this functiοn with respect tο x and put it equal tο zerο in οrder tο determine the highest value οf r(x):

[tex]r'(x) = 1000 - 4x = 0[/tex]

After finding x, we οbtain:

[tex]x = 250[/tex]

Tο maximize its prοfits, the cοrpοratiοn shοuld thus sell the phοnes fοr $250.

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Answer:

if sales tax was 6.75 dollars, then 31.75 is the total cost. If it’s in percent, the total cost is 26.69

Step-by-step explanation:

1).    12.5(2) = 25

2).    25 + 6.25 = 31.25

OR

2).    25(1.0675)=26.69

The equation y = x + 44 is not a good fit for the data because a residual plot with the data set indicates a bad fit. So, the correct answer is the equation is not a good fit because a residual plot with the data set indicates a bad fit

If a residual plot shows a clear pattern in the residuals, it indicates that the model or regression line may not be fitting the data well.

In other words, there may be a problem with the model fit, and further investigation is needed to improve the accuracy of the model.

Residual plots are important in regression analysis because they allow us to check the assumptions of the model and diagnose problems with the model fit.

They also help us identify outliers and influential data points, which can have a significant impact on the accuracy of the model.

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The correct coordinates of the center of dilation are (2.8, 3.8).

What is dilation?

In geometry, dilation is a transformation that changes the size of an object. When a figure is dilated, each point of the original figure is moved away from or toward the center of dilation.

Dylan's claim is incorrect because the center of dilation is not necessarily located on the line segment PP'.

To find the center of dilation, we need to locate the image point of a known point after dilation.

Let's consider a point Q on the same line as PP', but on the other side of P', such that PQ = 1 unit. After dilation with a scale factor of 4, the image of Q will be on the line passing through P and P'. Let's denote this image point by Q'.

Since PQ : P'Q' = 1 : 4, the distance from P to Q' is 4 units. Similarly, since PP' : PQ' = 1 : 5, the distance from P to Q' is 5 times the distance from P to P'. Thus, the distance from P to P' is 1 unit and the distance from P to Q' is 5 units.

Therefore, the center of dilation is located on the line passing through P and Q', and is 4 units away from P and 1 unit away from Q'.

Using the midpoint formula, we can find the coordinates of the center of dilation:

[tex]x &= \frac{1}{2}(4.8 + 0.8)[/tex]

[tex]&= 2.8[/tex]

[tex]y &= \frac{1}{2}(3.2 + 4.4)[/tex]

[tex]&= 3.8[/tex]

Thus, the correct coordinates of the center of dilation are (2.8, 3.8).

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The type of transformation represented in the figure is the translation transformation i.e. (c) none of these

Given the triangles ABC and A'B'C'

The transformation between the triangles is translation

The translation transformation is a type of transformation that moves an object without changing its size, shape, or orientation.

This transformation involves sliding an object in a particular direction by a certain distance, either horizontally or vertically.

In this case, the direction is horizontally and vertically

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Answer: To solve the problem, we can use Bayes' theorem. Let D be the event that a device is defective, and let A be the event that the quality assurance check concludes that a device is defective.

We want to find P(A and not D) + P(not A and D), which represents the probability of an incorrect conclusion.

We know that P(D) = 1 - P(not D) = 1 - 0.84 = 0.16, and that P(A | not D) = 0.03 and P(A | D) = 0.97.

Using Bayes' theorem, we can compute:

P(not A | not D) = 1 - P(A | not D) = 1 - 0.03 = 0.97

P(not A | D) = 1 - P(A | D) = 1 - 0.97 = 0.03

Therefore,

P(A and not D) = P(not D) * P(A | not D) = 0.84 * 0.03 = 0.0252

P(not A and D) = P(D) * P(not A | D) = 0.16 * 0.03 = 0.0048

So the probability of an incorrect conclusion is:

P(A and not D) + P(not A and D) = 0.0252 + 0.0048 = 0.03

Therefore, the probability of an incorrect conclusion is 0.03, or 3% (rounded to the nearest tenth of a percent).

Why was this answer deleted prior?

The culture will have a count of 1200 after approximately 2.77 hours. Rounded to the nearest tenth, this is 2.8 hours.

What is equations?

Equivalent equations are algebraic equations that are having identical roots or solutions.

We can solve for the time "t" by substituting the given count of 1200 into the equation and solving for "t":

[tex]1200 = 3000e^{(0.5t)}[/tex]

Divide both sides by 3000 to get:

[tex]0.4 = e^{(0.5t)}[/tex]

Take the natural logarithm of both sides to isolate the exponent:

ln(0.4) = 0.5t

Solve for "t" by dividing both sides by 0.5:

[tex]t = (ln(0.4))/0.5 = 2.77 hours[/tex]

Therefore, the culture will have a count of 1200 after approximately 2.77 hours.

[tex]1200 = 3000e^{(0.5t)}[/tex]

Divide both sides by 3000 to get:

[tex]0.4 = e^{(0.5t)}[/tex]

Take the natural logarithm of both sides to isolate the exponent:

ln(0.4) = 0.5t

Solve for "t" by dividing both sides by 0.5:

[tex]t = (ln(0.4))/0.5 = 2.77 hours[/tex]

Therefore, the culture will have a count of 1200 after approximately 2.77 hours. Rounded to the nearest tenth, this is 2.8 hours.

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Answer: The running club can buy 25 uniforms

Step-by-step explanation: If the running club has $1,328 to spend on new uniforms and each uniform costs $52, we can find the number of uniforms they can buy by dividing the total amount of money by the cost of each uniform:

$1,328 ÷ $52 = 25.54

Therefore, the running club can buy 25 uniforms with $1,328.

I hope this helps, and have a great day!

The missing angles in the diagram are: Angle ABD = 60 degrees, Angle BDC = 120 degrees, Angle ACD = 60 degrees, and Angle ADC = 120 degrees.

To find the measure of the missing angles, we can use the fact that the sum of the angles in a triangle is 180 degrees, and the sum of the angles around a point is 360 degrees.

Let x be the measure of angle ABD.

Therefore, angle BDC has measure 180 - x degrees.

Similarly, angle ACD and angle ADC form a straight line, so their measures sum to 180 degrees. Therefore, angle ADC has measure 180 - 60 = 120 degrees.

Finally, since angle BCD and angle ADC form a straight line, their measures sum to 180 degrees. Therefore, angle BCD has measure 180 - 120 = 60 degrees.

Let y be the measure of angle CFE.

Similarly, angle DEF and angle CDF form a straight line, so their measures sum to 180 degrees. Therefore, angle DEF has measure 180 - 75 = 105 degrees.

Finally, since angle CDE and angle DEF form a straight line, their measures sum to 180 degrees. Therefore, angle CDE has measure 180 - 105 = 75 degrees.

Therefore, the missing angles have measures of 60 degrees and 75 degrees for the left and right triangles.

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find the measure of missing angles?

Answer:3/10

Step-by-step explanation:

2/5 = 4/10

1/5 = 2/10

            4/10 + 2/10 = 6/10

               6/10-3/10 = 3/10

The number is 9.

The three main types of linear equations are the standard form, the point-slope form, and the slope-intercept form.

We can begin by converting the following phrase into an equation:

The formula for "seven bigger than the product of a number and three" is as follows:

x/3 + 7

where x stands in for the unidentified number.

Seven more than the result of a number and three equals 10, according to the following formula.

x/3 + 7 = 10

When you take 7 out of both sides of the equation, you get:

x/3 = 3

When both sides of the equation are multiplied by 3, the result is:

x = 9

Hence, the answer is 9.

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According to the solution we have come to find that, the length of the box is  [tex](V/2)^{1/3}[/tex].

what is volume?

Volume is the measure of the amount of space occupied by a three-dimensional object or region of space. It is typically measured in cubic units, such as cubic meters (m³), cubic centimeters (cm³), or cubic feet (ft³), depending on the unit of length used to measure the dimensions of the object. The formula for calculating the volume of a geometric shape depends on the shape, but generally involves multiplying the dimensions of the shape together, such as the length, width, and height of a rectangular prism, or the radius and height of a cylinder.

Let's start by defining the variables:

Let's call the height of the box "h".

The length and width are each twice as long as the height, so we can write: length = 2h and width = 2h.

The volume of the box is given as "V".

We can use the formula for the volume of a rectangular box to write:

V = length × width × height

V = (2h) × (2h) × h

V = 4h^3

Now we can solve for h in terms of V:

4h³ = V

h³ = V/4

h = [tex](V/4)^{(1/3)[/tex]

This gives us the formula for the height of the box in terms of its volume V.

If we are given the volume V and asked to find the length of the box, we can use the formula for length in terms of height:

length = 2h

length = 2(V/4[tex])^{(1/3)[/tex]

length = (2V/4[tex])^{(1/3)[/tex]

length = (V/2[tex])^{(1/3)[/tex]

So, the length of the box is  [tex](V/2)^{1/3}[/tex].

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We are given the following lengths:

We will solve it by using this formula:

[tex]\boxed{\mathfrak{\purple {Median = \frac{1}{2}(lower \: base+upper \: base)}}}[/tex]

[tex]\boxed{\mathcal{\purple { XY = \frac{1}{2}( CO+PY)}}}[/tex]

[tex] \green{ \sf4m + 3 = \frac{1}{2} (2m - 10 + 3m + 37)}[/tex]

[tex] \red \implies \green{ \sf4m + 3 = \frac{1}{2} (5m+ 27)}[/tex]

[tex] \red \implies \green{ \sf4m + 3 = \frac{5}{2} m + \frac{27}{2} }[/tex]

[tex] \red \implies \green{ \sf8m + 6 = 5m + 27 }[/tex]

[tex] \red \implies \green{ \sf8m + 6 - 5m = 27 }[/tex]

[tex] \red \implies \green{ \sf8m - 5m= 27 - 6 }[/tex]

[tex] \red \implies \green{ \sf3m = 21 }[/tex]

[tex] \boxed{ \mathfrak{ \red{m = 7}}}[/tex]

[tex] \blue \longmapsto \orange{ \tt \: XY =4m + 3}[/tex]

[tex] \blue \longmapsto \orange{ \tt \: XY =4(7) + 3}[/tex]

[tex] \blue \longmapsto \orange{ \tt \: XY =28 + 3}[/tex]

[tex] \boxed{ \underline{ \underline{ \blue \longmapsto \orange{ \tt \: XY =31}}}}[/tex]

[tex] \purple \longmapsto \pink{ \tt \: CO = 2m - 10}[/tex]

[tex] \purple \longmapsto \pink{ \tt \: CO = 2(7) - 10}[/tex]

[tex] \purple \longmapsto \pink{ \tt \: CO = 14 - 10}[/tex]

[tex] \boxed{ \underline{ \underline{ \purple \longmapsto \pink{ \tt \:CO=4}}}}[/tex]

[tex] \purple \longmapsto \pink{ \tt \: PY = 3m + 37}[/tex]

[tex] \purple \longmapsto \pink{ \tt \: PY = 3(7) + 37}[/tex]

[tex] \purple \longmapsto \pink{ \tt \: PY = 21 + 37}[/tex]

[tex] \boxed{ \underline{ \underline{ \purple \longmapsto \pink{ \tt \:PY=58}}}}[/tex]

The expressions can be written as  :a. log5.625 ≈ 0.75.

                                                             b. log6.4 + log6.12 ≈ 1.67.

                                                             c. log3.9^{4} ≈ 2.47.

What is logarithm function?

A logarithm function is a mathematical function that determines the power to which a fixed number, called the base, must be raised to produce a given value and The logarithm function is the inverse of the exponential function. The most commonly used base for logarithmic functions is 10 (log base 10), but other bases such as 2 (log base 2) and the natural logarithm base e (ln) are also used.

a. Since there is no base specified, we assume the base to be 10 by default. Therefore, we can write:

log5.625 = log(5625/1000)

Using the property log(a/b) = log(a) - log(b), we can simplify this expression to:

log5.625 = log(5625) - log(1000)

Using the change of base formula, we can convert the logs to a common base, such as 2 or e:

log5.625 = log(5625)/log(10) - log(1000)/log(10)

Evaluating the logs using a calculator or by simplifying, we get:

log5.625 ≈ 0.75

Therefore, log5.625 ≈ 0.75.

b. Using the property log(a) + log(b) = log(ab), we can simplify the expression:

log6.4 + log6.12 = log(6.4 × 6.12)

Using the change of base formula, we can convert this to a common base:

log6.4 + log6.12 = log(6.4 × 6.12)/log(10)

Evaluating the log using a calculator or by multiplying 6.4 and 6.12 and simplifying, we get:

log6.4 + log6.12 ≈ 1.67

Therefore, log6.4 + log6.12 ≈ 1.67.

c. Using the property log(a^{n}) = n log(a), we can simplify the expression:

log3.9^{4} = 4 log3.9

Using the change of base formula, we can convert this to a common base:

log3.9^{4} = 4 log(3.9)/log(10)

Evaluating the log using a calculator or by simplifying, we get:

log3.9^{4} ≈ 2.47

Therefore, log3.9^{4} ≈ 2.47.

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