The magnitude and direction of resultant force is 4.12N and direction is 75.96degree
The combined force that affects a body in a different way is known as the resultant force. Typically, it uses a vector calculation to calculate.
F net = / (square root of F1 resultant + F2 resultant + F1F2 cos tita)/........(1)
For instance, if two forces are acting in the same direction, we add them together; if they are acting in opposition, we subtract them from one another.
When two forces are exerting pressure on a body at an angle of, the combined net force is 4N in the direction of North. In this case, the two forces are 10N and 6N, which are operating in opposing directions. Additionally, 5N and 4N are moving in the other direction, resulting in a net force of 1N moving westward from these two forces.
by substituting we get F net =4.12N
direction is = 4 / tan tita = 75.96 degree
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How much work is done to lift a 5.36kg box off the ground 2.2m?
Answer:
Explanation:
Given:
m = 5.36 kg
h = 2.2 m
___________
A -?
Work:
A =m·g·h
A = 5.36·9.8·2.2 ≈ 116 J
Please help!Giving Brainliest
I need to turn this in by midnight
u = initial speed = 10 m/s
v = final speed = 14 m/s
Impulse is 2000 N/s
Given,
Mass of car = 500 kg
Force = 200 N
Acceleration = F/M
Acceleration = 0.4 m/s^2
Calculating the final speed,
u = initial speed = 10
v = final speed = ?
t = time of acceleration
v = u + at
v = 10 + (0.4 x 10)
v = 14m/s
Impulse = Ft = mv - uv
(200 x 10) = (500 x 14) - (500 x 10)
2000 = 7000 - 5000
2000 = 2000
Hence our answer is correct and the impulse is 2000 N/s.
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A horizontal net force F is exerted on an object at rest. The object starts at x = 0 m and has a speed of 4.0 m/s after moving 4.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.
What is the mass of the object?
Answer: 15 kg
THIS IS THE QUESTION AND THE ANSWER! SEE ATTACHED.
A horizontal net force F is exerted on an object at rest and with a speed of 4.0 m/s. The object will be 5 kg in weight.
What is Force?An influence with the capacity to change the motion of an object is called a force. A force acting on an object with mass can cause it to accelerate or modify its velocity. Pushing or pulling is a simple way to explain the force.
According to the question, the given values are :
Initial Velocity, u = 0 at x = 0
Final Velocity, v = 4 m/s at x = 4 m
Work done=Area on graph
1/2 m(v²-u²) = 1/2 × base × height
m (4²-0²) = 4 × 20
m = 5 kg
Hence, the mass of the object will be 5 kg.
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Ignore air drag. Drop two balls, one big and one small. The big ball drops ___ the small ball.
A- the same speed as
B- slower than
C- faster than
D- sooner than
Direction of the vector A
The direction of vector A which is parallel but opposite to the vector I is is 305°
Direction of vector I = 125°
Vector I makes a parallel line with vector A. Consider vector A and I to be collinear. Collinear lines makes up an angle of 180°
[tex]Angle_{A}[/tex] + [tex]Angle_{I}[/tex] = 180°
[tex]Angle_{A}[/tex] + 125° = 180°
[tex]Angle_{A}[/tex] = 55°
Direction of vector A = 360° - 55° = 305°
The direction of a vector is the angle, the vector creates with positive x-axis in counter clockwise direction.
Therefore, the direction of vector A is 305°
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As the coaster starts rolling down the hill, it has a height of 10 m and a velocity of 42 m/s. What is the total energy of the coaster at this point? (It has a mass of 1300 kg.)
The total energy of the coaster at that point is 1274000 J.
What is energy?Energy can be defined as the ability or the capacity for a body to perform work.
From the question, to calculate the total energy of the coaster at that point, we use the formula below.
Formula:
E = mgh+mv²/2........... Equation 1Where:
E = Total energy of the coaster at that point.m = Mass of the coasterh = Height of the coaster at that pointv = Velocity of the coaster at that pointg = acceleration due to gravity.From the question,
Given:
m = 1300 kgh = 10 mv = 42 m/sg = 9.8 m/s²Substitute the values above into equation 1
E = (1300×10×9.8)+(1300×42²/2)E = 127400+1146600E = 1274000 JHence, the total energy of the coaster at that point is 1274000 J.
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A car driver traveling 40 m/s slows down to a speed of 20 m/s in 10 seconds. What is the car’s acceleration?
The equation we use is to determine the acceleration of the car, it is a Uniformly Varied Rectilinear Motion (MRUV) is:
[tex]\boxed{\sf{a=\dfrac{V_{f}-V_{o}}{t}}} \ \ \ \ \ \sf{\longmapsto \ \ \ \ \ Where \ \ \ \ \begin{cases}\sf{V_{f} = Final \ velocity} \\ \sf{V_{o}=Initial \ velocity} \\ \sf{a=Acceleration} \\ \sf{t=Time} \end{cases}}[/tex]
We extract the data of the problem:
[tex]\sf{V_{f}=20 \ m/s}[/tex][tex]\sf{V_{o}=40 \ m/s}[/tex][tex]\sf{t=10 \ s}[/tex]We plug these values into the scalar equation above.
[tex]\sf{a=\dfrac{V_{f}-V_{o}}{t}}[/tex]
[tex]\sf{a=\dfrac{20 \ m/s-40m/s}{10 \ s} }[/tex]
[tex]\sf{a=\dfrac{-20 \ m/s}{10 \ s} }[/tex]
[tex]\boxed{\boxed{\boldsymbol{\sf{a=-2 \ m/s^{2} }}}}[/tex]
Rpta: The acceleration of the car was -2 m/s^2.
Mary needs to row her boat across a 140 m-wide
river that is flowing to the east at a speed of
1.5 m/s. Mary can row with a speed of 4.0 m/s.
Answer:
2.5
Explanation:
you just subtract basic math
What is the volume of a rock with a density of 45 g/mL and a mass of 855 grams?
Your answer must have units
The volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml
We know that,
ρ = m / V
where,
ρ = Density
m = Mass
V = Volume
Given that,
ρ = 45 g / ml
m = 855 g
V = 855 / 45
V = 19 ml
Density is the measure of amount of molecules present in substance. It is denoted by ρ. Its unit is usually g / ml.
Therefore, the volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml
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The snell's law is also known as ________?
First law of reflection
Second law of accoutic
Second law of reflection
Second law of refraction
The Snell's law is also known as second law of refraction.
According to the Snell's law , the ratio of the sine of angle of incidence to the sine angle of refraction is equal to a constant of a light ray for two media . And it is given as,
[tex]\frac{sini}{sinr} = constant[/tex]
Where, [tex]sin i[/tex] is the angle of incidence light ray, [tex]sinr[/tex] is the angle of refracted light ray. Refractive index, also known as this constant and referred to as the second medium with respect to the first medium i.e. (₁μ₂) ,therefore the equation can be written as,
μ₁/μ₂ = ₁μ₂= [tex]\frac{sini}{sinr} = constant[/tex]
Refraction is a phenomena in which a light ray bends as it travels through one medium through another .
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An atom of a _____________________ has two electrons in its outer level and will lose these when it combines with another atom.
a. alkali metal
b. noble gas
c. alkaline earth metal
d. halogen
Answer:
A alkali metals hope this helps
Answer: c. alkaline earth metal
Explanation: group II elements in the periodic table are generally found as 2+ ions. This is because they have lost two electrons to ionic bonding.
What subatomic particle is responsible for the observed properties of an atom?
Electrons are responsible for the properties of atoms.
What is an atom?The atom is the smallest particle of a substance that can take part in chemical reaction. We know that an atom is composed of smaller particles that are called subatomic particles. The basic subatomic particles are; electrons proton and neutrons.
The protons and the neutrons are bond up in the nucleus and do not contribute to the properties of the atom. The properties of the atom are due to loss or gain of electrons.
Thus electrons are responsible for the properties of atoms.
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How is simple machine are more applicable than complex machine.
Answer:
Explanation:
A simple machine is the simplest device that performs work. A simple machine applies a single force to a single load and generally acts as a building block in developing more complex, compound machines. Simple machines usually fall into one of six categories, including: lever, wheel and axle, pulley, inclined plane, wedge and the screw.
I hope this helps you ")
Pleaseee help me with this question?!!!!!!!!!!
In a road with speed limit of 30 miles per hour, how much time (in minutes) will you gain by driving at an average speed of 5 miles per hour over the speed limit if it would take 30 minutes to reach your destination driving at the posted speed limit?
You will gain 150 minutes by driving at an average speed of 5 miles per hour
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
How to determine the distance travelledWe'll begin by calculating the distance travelled. This can be obtained as follow:
Speed = 30 miles per hourTime = 30 minutes = 30 / 60 = 0.5 hourDistance =?Speed = Distance / time
Cross multiply
Distance = speed × time
Distance = 30 × 0.5
Distance = 15 miles
How to determine the time taken to travel at 5 miles per hourSpeed = 5 miles per hourDistance = 15 milesTime = ?Speed = distance / time
5 = 15 / time
Cross multiply
5 × time = 15
Divide both side by 5
Time = 15 / 5
Time = 3 hours
How to determine the time gainedTime for 30 miles per hour = 30 minutesTime for 5 miles per hour = 3 hours = 3 × 60 = 180 minutesTime gained =?Time gained = 180 - 30
Time gained = 150 minutes
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ighth grade F.1 Identify reactants and products MGX
This passage describes a chemical reaction. Read the passage. Then, answer the question
below.
The cheesemaking process sometimes includes a step called lactic acid fermentation.
This step occurs when a certain type of bacteria is added to milk. The bacteria form
lactic acid (C3H603) by combining water (H₂O) and lactose (C12H22011) in the milk.
When lactic acid forms, the milk's proteins clump into curds that can later be used to
make many types of cheese.
In the chemical reaction described in the passage, which of the following are reactants?
Select all that apply.
water (H₂O)
lactose (C12H22011)
Submit
lactic acid (C3H603)
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True or false-Consider an object that starts from rest and moves with constant acceleration. The plot of displacement versus time for such motion is a curved line while the plot of displacement versus time squared is a straight line.
Question 21 options:
True
False
A football is punted to its maximum height. As soon as it starts to fall to the ground it starts to gain kinetic energy. What happens to the potential energy of the football as it starts to gain kinetic energy?
From conservation of energy, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.
What is Conservation of Energy ?Conservation of energy state that energy can not be created nor destroyed but can only be transformed from one form to another.
Given that a football is punted to its maximum height. At this maximum height, the kinetic energy is zero while the potential energy is maximum.
As soon as it starts to fall to the ground it starts to gain kinetic energy. And what will happen to the potential energy of the football as it starts to gain kinetic energy is the reduction of the potential energy.
Therefore, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.
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What Happens When Two Objects Are Charged By Rubbing Or Peeling?
a. One object has only one type of charge. The other object has only the other type of charge.
b. Both objects have the same type of charge.
c. Both objects have both types of charge, but there are different amounts of each type on each object. (One object has more negative charges than positive and the other object has more positive charges than negative charges.)
When Two Objects Are Charged By Rubbing Or Peeling, both objects have both types of charge, but there are different amounts of each type on each object. (One object has more negative charges than positive chrages and the other object has more positive charges than negative charges); option C.
What happens when two objects are charged by rubbing or peeling?Charges are the inherent properties of the particles of matter which determines how the atoms will react when placed in an electric filed.
There are two types of charges in an atom:
positive charges which are present on the protonsnegative charges that which are present on the electrosThe electrons in an atom can be easily transferred from one atom to another, hence objects can be charged by rubbing or peeling one against the other.
When when two objects are rubbed or peeled against each other, electrons move from one object to the other.
The object that acquires the electrons become negatively charged whereas the object that loses the electrons become positively charged. However, both objects have both electrons and protons present in them.
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A charge of 10 coulomb passes through a cross-section of a conductor in 20 seconds. What is the magnitude of current flowing through it?
The magnitude of current flowing through the conductor is 0.5A.
The charge flowing through the cross-section of the conductor is q = 10C.The time taken by the charge to flow is t = 20s.A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.The equation for the current flowing in the circuit is I = q/t. Where I is the current in the circuit.Substitute the values of q and t,I = 10C/20sI = 1/2AI = 0.5AThus, the current flowing through the conductor is 0.5 A.To learn more about current, visit :
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NEED HELP ASAP PLS
If a basketball player jumps and lands on the ground after 3.2 seconds with a final velocity of −5.5 m/s, what is the player’s initial velocity? Assume (a=−9.8 m/s2) (NOTE: Only 1 point if no work is shown)
The player’s initial velocity, given the data from the question is 15.68 m/s
How to determine the time to reach the maximum heightWe'll begin by obtaining the time taken for the player to reach the maximum height. This can be obtannnned as follow:
Time for the entire trip (T) = 3.2 sTime to reach maximum height (t) = ?T = 2t
3.2 = 2t
Divide both sides by 2
t = 3.2 / 2
t = 1.6 s
How to determine the initial velocity of the playerTime to reach maximum height (t) = 1.6 sAcceleration due to gravity (g) = -9.8 m/s²Final velocity (v) = 0 (at maximum height)Initial velocity (u) = ?v = u + gt
0 = u + (-9.8 × 1.6)
0 = u - 15.68
Collect like terms
u = 0 + 15.68
u = 15.68 m/s
Thus, the initial velocity of the player is 15.68 m/s
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a sailboat moves faster as the wind pick up this is an example Of?
It is an example of acceleration due to the wind.
Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration of all other motions.
Acceleration is a vector quantity since it has both a magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration.
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If there is 100 ml of liquid mercury in a graduated cylinder that weighs 25 grams. What must be the density of the liquid mercury, if the combined mass of the liquid mercury and the graduated cylinder is 1,385.0 grams?
The density of 100 ml of liquid mercury in the graduated cylinder that weighs 25 grams is 13.6 g / ml
ρ = m / V
ρ = Density
m = Mass
V = Volume
V = 100 ml
Mass of cylinder = 25 g
Combined mass of cylinder and mercury = 1385 g
Mass of mercury = 1385 - 25 = 1360 g
ρ = 1360 / 100
ρ = 13.6 g / ml
Density is the amount of molecules present in a given volume of the substance. It is denoted by ρ.
Therefore, the density of 100 ml of liquid mercury in the graduated cylinder that weighs 25 grams is 13.6 g / ml
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An object is dropped from an airplane and takes 72 seconds to hit the ground what is the magnitude of its Vfy
The magnitude of its Vfy i.e Vertical componet is mathematically given as
V=705.6 m/s
This is further explained below.
What is the magnitude of its Vfy?Generally, At this point, we need to do an analysis of the vertical motion of the item, which may be thought of as a free fall motion with a constant acceleration.
g = 9.8
As a result, we are able to employ the suvat equation that is as follows:
v = u +at
As a result, the following expression may be used to determine the magnitude of the object's vertical velocity after t = 72 seconds:
v = 0 + (9.8) (72)
V=705.6 m/s
In conclusion, the magnitude
V=705.6 m/s
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What effect generates lift on a Flettner rotor?
Magnus effect generates lift on a Flettner rotor. It is named as Magnus effect, as it was first experimentally investigated by H G Magnus.
A Flettner rotor is a smooth cylinder with a disc plate at the end of it. The disc at the end is called as Thom disc. It optimses aerodynamic efficiency at the end of rotor. The rotor is rotated along its axis by the ship's engines. It is used in ships and airplanes. In ships it is mounted upright whereas in airplanes it is mounted sideways in place of wings.
As air strikes the rotating rotor at right angles to the axis of rotor, the ship moves in the direction perpendicular to both the rotation axis and air flow direction due to aerodynamic force created by Magnus effect.
Therefore, Magnus effect generates lift on a Flettner rotor.
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1. A radiographic technique calls for a 2000 ms (time) exposure, What is
this time in s?
Answer:
2 s
Explanation:
2000 ms / 1000 ms/s = 2 s
Trenton is a middle-aged man with Down syndrome. Compared to unaffected adults his age, Trenton is at greater risk of developing ______.
Answer:
because
Explanation:
ok just because
The hammer is the closest of the three bones in the middle ear to the cochlea true or false
False. The hammer is not the closest of the three bones in the middle ear to the cochlea.
The three bones in the middle ear are Malleus, Incus and Stapes. Malleus is commonly known as Hammer, Incus as anvil and stapes as stirrup. Hammer is attached to the ear drum, Anvil is the chain of the bones and Stirrup is attached to the oval window.
Cochlea is a hollow, spiral shaped bone present in the inner ear. So the order of bones from outside to cochlea is Hammer first, followed by Anvil in the middle and Stirrup near the inner ear where cochlea is present.
Therefore, the hammer is not the closest of the three bones in the middle ear to the cochlea
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An airplane acceleration is 3m/s^2. The minimum take-off speed is 102 m/s. The minimum runway length is ____ meter.
The airplane starts form rest, then accelerates by rate of [tex]3m/s^2[/tex] until it reaches 102m/s at the end of the runway. so we have:
[tex]Vo=0m/s\\Vf=102m/s\\a=3m/s^2\\\\[/tex]
From the equations of uniformly accelerated motion (since the airplane's acceleration is uniform) [tex]'Vf^2=Vo^2+2aS' \\[/tex] is compatible to find the minimum runway length (S).
[tex]Vf^2=Vo^2+2aS\\Vf^2-Vo^2=2aS\\S=Vf^2-Vo^2/2a\\[/tex]
[tex]S=((102m/s)^2-(0m/s)^2)/2m/s^2\\S=(10404m^2/s^2-0m^2/s^2)/2m/s^2\\S=(10404m^2/s^2)/2m/s^2\\S=5202m[/tex]
An object’s weight is equal to the force of gravity on it. The Moon has a gravity of 1/6 that of earth’s, while Jupiter has a gravity of 2.64 times that of the earth how much more would a 5.00 kg turtle weigh on Jupiter than the moon?
Answer:
See below
Explanation:
On Earth , turtle weight = 5 * 9.81 =49 N
Moon = 490.5 * 1/6 = 8.18 N
Jupiter 490.5 * 2.64 = 129.4 N
129.4 - 8.18 N = 121.2 N more on Jupiter than moon
A rock is thrown vertically upwards at a velocity of 11 meters per second from an initial height of 1.5 meters.
Considering “up” to be the positive y direction, answer the following questions:
How high above the ground does the rock go?
How long does it take to get to the top of its travel?
What is the velocity of the rock half of a second after it is released?
What is the velocity of the rock 1.5 seconds after release?
The height above the ground reached by the rock is 7.7 m.
The time taken for the rock to travel half of a second after it is released is 1.12 seconds.
The velocity of the rock half of a second after it is released is 15.9 m/s.
The velocity of the rock 1.5 seconds after release is 25.7 m/s.
Height travelled by the rock
The vertical height traveled by the rock is calculated as follows;
h = u²/2g
h = (11²)/(2 x 9.8)
h = 6.2 m
Height above the ground reached by the rock = 1.5 m + 6.2 m = 7.7 m
Time of motion of the rockt = √2h/g
t = √(2 x 6.2/9.8)
t = 1.12 seconds
Velocity of the rock half a second after it was releasedv = u + gt
v = 11 m/s + (9.5 x 0.5)
v = 15.9 m/s
Velocity of the rock 1.5 seconds laterv = u + gt
v = 11 m/s + (9.5 x 1.5)
v = 25.7 m/s
Thus, the height above the ground reached by the rock is 7.7 m.
The time taken for the rock to travel half of a second after it is released is 1.12 seconds.
The velocity of the rock half of a second after it is released is 15.9 m/s.
The velocity of the rock 1.5 seconds after release is 25.7 m/s.
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