12. What is the empirical formula for C10H30O5?

Answers

Answer 1

Answer:

Just use a text book.. So that you get the concept


Related Questions

Most energy resources used by humans are nonrenewable. Which of the following is NOT a nonrenewable energy resource?
A coal
B natural gas
C oil
D wind

Answers

Answer:D wind

Explanation:

Most energy resources used by humans are nonrenewable. Wind is not  a nonrenewable energy resource. Therefore, option D is correct.

What are nonrenewable energy resource ?

Energy derived from fossil fuels including coal, crude oil, natural gas, and uranium is referred to as non-renewable energy. Non-renewable energy requires human intervention to make it appropriate for use, in contrast to renewable energy.

Fossil fuels made of carbon are one instance. With the use of heat and pressure, the original biological substance transforms into a fuel like gas or oil.

A renewable energy source is wind power. Water does not pollute, it cannot run out, and it lessens the need for fossil fuels, which are where greenhouse gases that contribute to global warming are produced.

Thus, option D is correct.

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How many short columns are on the periodic table?

Answers

Answer:

They are 4 short column on the periodic table

5 lollipops = 6 gumballs

8 gumballs = 6 lemonheads

14 lemonheads = 11

Answers

Explanation:

5 lollipops = 6 gumballs

8 gumballs = 6 lemonheads

14 lemonheads = 11 lollipops

It is in chain rule form.

Answer:

야만적 인 사랑은 누군가가 천사처럼 보이지만 야만적 인 사랑은 당신의 마음을 부러 뜨리게했다너무 귀엽다

Explanation:

난 천사야 네가 무슨 뜻인지 말해줘나는 모든 것을 가지고 나는 그것을 다시 포기하지 않을 것이다

what is van't hoff factor?
state the formulas to calculate " i " during association or dissociation.

tysm! :)​

Answers

The relationship between the calculated concentration of a material and the actual concentration of particles is known as the Van't Hoff factor.

I is the difference between a typical or theoretical colligative quality and an observable one.

What does the connection van t Hoff factor mean?

The van 't Hoff factor is the difference between the concentration of a material determined by its mass and the concentration of particles actually formed when the substance is dissolved. The van 't Hoff factor is virtually 1 for the majority of non-electrolytes dissolved in water.

What does Van t Hoff factor mean in terms of connection and dissociation?

For dissociation, association, and the non-electrolyte solute, the Van't Hoff factor value is more than one, less than one, and equal to one respectively.

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What would the Kc value be from this reaction: H2 + I2 = 2HI.
(Because of the coefficient "2" in front of HI, you will have to square the concentration
of HI to find Kc. Kc = ?

Answers

Answer: The value of [tex]K_{c}[/tex] for the given reaction is  [tex]K_{c} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex] .

Explanation:

The ratio of concentration of products and reactants raised to the power of their concentration is called equilibrium constant.

It is denoted by the symbol [tex]'K_{c}'[/tex].

For example, [tex]H_{2} + I_{2} \rightarrow 2HI[/tex]

The expression for [tex]K_{c}[/tex] of this reaction is as follows.

[tex]K_{c} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex]

So, by putting the respective concentrations of the species involved in the reaction it is possible to determine the value of [tex]K_{c}[/tex] for the given reaction.

Thus, we can conclude that the value of [tex]K_{c}[/tex] for the given reaction is  [tex]K_{c} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex] .

As long as proper
safety precautions have been taken, why can explosives be transported long distances without exploding?

Answers

Explosives can be transported long distances without exploding as long as proper safety precautions have been taken because explosives are designed to be stable under normal conditions. They will only explode when subjected to a specific trigger, such as a spark, heat, shock, or friction. When explosives are being transported, they are usually handled and stored in a way that minimizes the risk of exposure to these triggers. For example, explosives may be stored in containers that are resistant to shock, heat, and friction, and they may be transported in vehicles that are designed to minimize the risk of accidents or incidents that could cause a spark or other ignition source. Additionally, explosives may be transported in accordance with strict safety regulations that specify how they should be handled, stored, and transported to minimize the risk of accidental detonation.

How much energy (in J) is lost when a sample of iron with a mass of 28.3 g cools from 66.0 degrees celsius to 24.0 degrees celsius.

Answers

Answer:

-533.68J

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat required (Joules)

m = mass of substance (g)

c = specific heat of substance (J/g°C)

∆T = change in temperature (°C)

According to the information provided in this question;

Q = ?

m = 28.3 g

c of iron = 0.449 J/g°C

∆T = 24°C - 66°C = -42°C

Using the formula, Q = m × c × ∆T

Q = 28.3 × 0.449 × (-42)

Q = -533.68

Q = -533.68J

This means that 533.68J is lost to the environment when iron of 28.3g cools from 66°C to 24°C.

What is an Alkanoate?​

Answers

Answer: Alkanoate (plural alkanoates) (organic chemistry) Any salt or ester formed from the reaction of an alkaloic acid and alkaloids

Explanation: I looked in my dictionary and found this. I hope this helped

Which type of molecule is shown below?
O A. Alkyne
O B. Alkane
C. Alkene
O D. Aromatic

Answers

C. Alkene..............

The type of molecule shown in the image has been an alkyne. Thus option A is correct.

The molecules formed by hydrogen and carbon are hydrocarbons, These are the organic compounds with the sharing of electrons in between the atoms.

The number of electrons shared results in the bond formed. The compound with only a single bond has been alkane. The presence of sharing of 2 atoms results in a double bond, and the compounds are alkene. The triple bond compounds are alkynes.

The given structure has the presence of a triple bond in the structure, thus the image has been of an alkyne. Thus, option A is correct.

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The half-life of carbon-14 is 5715 years. How long would it take for 100 grams to decay to
12.5 grams

Answers

We are given:

half-life of carbon = 5715 years

Initial mass = 100 grams

Final mass = 12.5 grams

Finding the time taken:

Number of half-lives:

We know that in the relation:

[tex]\frac{Final\_mass}{Initial\_mass} = \frac{1}{2^{n}}[/tex], n is the number of half-lives taken

replacing the given values:

12.5 / 100 = 1/2ⁿ

1/8 = 1/2ⁿ

2ⁿ = 8

2ⁿ = 2³

n = 3

Hence, it took 3 half-lives to reduce the mass to 12.5 grams

Number of years:

Time taken = 3 half-lives

we know that one half-life is 5715 years, replacing that value:

Time taken = 3*(5715) years

Time taken = 17145 years

Therefore, after 17145 years, a 100 gram sample of carbon will decay and only 12.5 grams will remain

If a dog has a mass of 17.3 kg, what is its mass in the following units? Use scientific notation in all of your answers.

Answers

Answer:

what are the following units????

Explanation:

MY DOG WAS FAT BUT HE GOES TO GYM NOW, CAN BENCH LIFT 100 LBS :D

JK

What are greenhouse gases?

Answers

Carbon dioxide nitrous oxide methane and ozone

A student is studying the rate of the following reaction: C2H4O NaOH --> H20 NaC2H3O Knowing that this is an exothermic reaction, he is measuring the rate of the reaction by timing how quickly the reaction vessel heats up. He notices that if he adds HCl to this reaction, the rate increases dramatically. He also determines that the HCl is being used up during the reaction. Is the HCl a catalyst for this reaction.

Answers

Answer:

HCl is not a catalyst because these are not used up during the chemical reactions.

Explanation:

Hello there!

In this case, according to the performed experiments, it is possible for us to realize that HCl cannot be a catalyst for this reaction because it is used up during the reaction. This is explained by the fact that catalyst are able to return to the original form once the reaction has gone to completion; this is the example of palladium in the hydrogenation or dehydrogenation of hydrocarbons depending on the case. Moreover, we know that the catalysts increase the reaction rate because they decrease the activation energy of the reaction and therefore the student observed such increase.

Best regards!

EXPLAIN Before medical images are taken, radioisotopes are often injected into a vein in a patient’s arm, or the patient drinks a solution containing the radioisotopes. Why do
you think atoms in the body usually do not emit radiation?

Answers

Answer: adioisotopes, are species of chemical elements that are produced through the natural decay of atoms. Exposure to radiation generally is considered harmful to the human body, but radioisotopes are highly valuable in medicine, particularly in the diagnosis and treatment of disease.

Explanation:

A sample of AgCl is treated with 5mL of 2M Na2CO3 solution to produce Ag2CO3. The remaining solution contained 0.003gm of Cl per litre. Calculate solubility product of AgCl.(Ksp of Ag2CO3=8.2×10^-12)​

Answers

Answer: The solubility product of AgCl is [tex]10.73 \times 10^{-9}[/tex].

Explanation:

The reaction equation is as follows.

[tex]Ag_{2}CO_{3} \rightleftharpoons 2Ag^{+} + CO^{2-}_{3}[/tex]

Let us assume the concentration of [tex]2Ag^{+}[/tex] is 2S and concentration of [tex]CO^{2-}_{3}[/tex] is S. Hence, the expression for [tex]K_{sp}[/tex] of this reaction is as follows.

[tex]K_{sp} = [Ag^{+}]^{2}[CO^{2-}_{3}]\\8.2 \times 10^{-12} = (2S)^{2}(S)\\8.2 \times 10^{-2} = 4S^{3}\\S = 1.27 \times 10^{-4}[/tex]

This means that [tex][Ag^{+}][/tex] is [tex]1.27 \times 10^{-4}[/tex]. Now, the concentration of [tex]Cl^{-}[/tex] is calculated as follows.

[tex][Cl^{-}] = \frac{mass}{molar mass}\\= \frac{0.003 g}{35.5 g/mol}\\= 8.45 \times 10^{-5} M[/tex]

Hence,  [tex]K_{sp}[/tex] for AgCl is calculated as follows.

[tex]K_{sp} = [Ag^{+}] \times [Cl^{-}]\\= 1.27 \times 10^{-4} \times 8.45 \times 10^{-5}\\= 10.73 \times 10^{-9}[/tex]

Thus, we can conclude that solubility product of AgCl is [tex]10.73 \times 10^{-9}[/tex].

If sugar was broken back down into CO2 and H2O what kind of change would that be?

A. Chemical change
B. Radical change
or
C. Physical change

Answers

Answer: chemical change

HELP!!! Please

A Probability Swim in Lake S Orbital

1. How did you determine where the lake was most likely to be?


2. Why was it important to take ten obse
swimmers were located?


3. Explain why the statement "electrons are always located close to the nucleus of an atom" is not really accurate,

Answers

We determine where the lake was mostly likely to be by first look if it clean or if containes fish or another thing by it geographic please if it help us or healthy to swim or it make a risk for our lives if we swim in it

Why don’t different varieties of corn plants grow to the same size under similar growing conditions?

Answers

Because they were planted at different times in different conditions

A reservoir is filled with 4 billion cubic feet of polluted water that initially contains 0.4% pollutant. Every day 400 million cubic feet of pure water enters the reservoir and the well-mixed solution flows out at the same rate. When will the pollutant concentration in the lake be reduced to 0.2%

Answers

Answer:

Thus, the pollutant concentration in lake will be reduced to 0.2% after 6.931471 days

Explanation:

From the information given:

A(t) = amount of pollutant for time (t)

A 4 billion cubic ft is the same as 4000 million cubic ft:

The Initial amount of pollutant is [tex]A_o = (\dfrac{0.4}{100})\times 4000[/tex]

[tex]A_o = 16 \ million \ cubic \ feet[/tex]

However;

the pollutant rate (input) = 400 × 0 = 0

the pollutant rate (output) = [tex]400( \dfrac{A(t)} {4000})[/tex]

[tex]= 1( \dfrac{A(t)} {10})[/tex]

The net rate = [tex]A'(t) = 0 - 1( \dfrac{A(t)} {10})[/tex]

[tex]\implies A'(t) = - 1( \dfrac{A(t)} {10})[/tex]

[tex]\implies \dfrac{1}{A(t)}A'(t) = -(\dfrac{1}{10})[/tex]

[tex]\implies \int (\dfrac{1}{A(t)}A'(t) ) dt = \int -(\dfrac{1}{10}) dt[/tex]

[tex]\implies In (A(t)) = -(\dfrac{1}{10})t + c[/tex]

[tex]\implies A(t) = e^{-(\dfrac{1}{10})t+c}[/tex]

[tex]\implies A(t) = Ce^{-\dfrac{1}{10}^t}[/tex]

A(0) =  16

[tex]\implies Ce^{ -(1/20)^0} = 16 \\ \\ C = 16[/tex]

[tex]\implies A(t) = 16e^{(-1/10)t}[/tex]

[tex]0.2\% \ pollutant = (\dfrac{0.2}{100})*4000 =8 \ million \ cubic \ feet[/tex]

A(t) = 8

[tex]\implies 16e^{(-1/10)t}= 8 \\ \\ \implies e^{1/10)t} = 2 \\ \\ (\dfrac{1}{10} )^t = In(2) \\ \\ t = 10\ In(2) \\ \\ \mathbf{ t = 6.931471}[/tex]

Explain, in terms of subatomic particles in energy states, how the colors in a fireworks display are produced

Answers

Salts are heated to extremely high temperatures during a display of fireworks. The salts' ions pick up energy and get excited. Exciting hues are created as energy in the form of light is emitted from the ions. Each salt's metal ion can be identified by the hue of the light that is emitted.

What are subatomic particles?

Subatomic particles refer to the three fundamental particles that make up the atom.

The subatomic particles include:

electronsprotons, and neutrons

Electrons occupy several energy states. When electrons gain energy, they move to a higher energy state. The electrons on returning to a lower energy state emit radiation that is seen as several light color displays in fireworks.

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Separating mixtures into their components depends on the differences in the components'
A. phases
B. states of matter
C. physical properties
D. chemical properties

Answers

Answer:

D

Explanation:

chemical properties

I'm not sure abt it but hope that helps

I think the answer is D

Is this line real or imaginary?

Answers

Imaginary as there is no line

Answer:

What are you talking abt

Explanation:

If 14.7 g of NO2 are reacted, what mass of H2O is reacted with it?

Answers

Answer:

no se englesh

ajajajaja

5. 16.3 g of NaCl is dissolved in water to make 1.75 L of solution. What is the molarity of this solution? A 0.159 M B 0.278 M C 9.31 M D 33.4 M​

Answers

Answer: The molarity of this solution is 0.159 M.

Explanation:

Given: Mass of solute = 16.3 g

Volume = 1.75 L

Number of moles is defined as the mass of substance divided by its molar mass.

Hence, moles of NaCl (molar mass = 58.44 g/mol) ar calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{16.3 g}{58.44 g/mol}\\= 0.278 mol[/tex]

Molarity is the number of moles of a substance present in a liter of solution.

So, molarity of the given solution is calculated as follows.

[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.278 mol}{1.75}\\= 0.159 M[/tex]

Thus, we can conclude that the molarity of this solution is 0.159 M.

The bond that holds together positive and negative ions is
called a(n) bond.

Answers

Answer:

Ionic bond

Explanation:

An ionic bond holds positive and negative ions together.

No links!! Round two decimal places please

Answers

Answer:

255.46 grams NO3

Explanation:

The molar mass of NO3 is 62.0049 g/mol.

To get grams from moles, multiply the moles by the molar mass.

4.12*62.0049 = 255.4602 = 255.46 grams NO3

Give two ways a globe is like the earth and two ways a globe is not like the earth.
Its a homework question and I'm to lazy to think HELP PLEASE

Answers

Answer:

A glove is like the earth because...

A globe is like the earth in that it is a three-dimensional representation of the earth's features, such as countries, oceans, and landmasses.

A globe is also like the earth in that it can rotate on its axis, which allows the viewer to see different parts of the earth depending on the angle of rotation.

A globe is not like the earth because...

A globe is not like the earth in that it is typically much smaller than the earth.

A globe is also not like the earth in that it does not depict the earth's relief features, such as mountains and valleys, in their true proportion to the rest of the earth's surface.

Final answer:

A globe is like the earth in that it is a scaled-down, spherical model of the earth's surface, representing physical features accurately. However, a globe is not like the earth because it is much smaller and does not rotate or revolve.

Explanation:

The globe and the earth are similar in two main ways. First, a globe is a scaled-down model of the earth, showing an accurate representation of the earth's surface. This includes physical features such as continents, oceans, and countries, which are mapped out precisely. Second, a globe is spherical, just like the earth.

However, there are differences between a globe and the earth. One key difference is the scale: the earth is far larger than any globe. The most obvious point of difference is the size: while a globe is small enough to be held in your hands or placed on a desk, the earth has a diameter of approximately 7,917.5 miles. Also, the globe is a static object, it does not rotate on its axis or revolve around the sun like the earth does.

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How many grams of chromium are in 2.0 x 1024 atoms

Answers

Answer: 173 g ( 0.17 kg in right accuracy)

Explanation: Amount in moles is n = N/Na =  2.0·10^24 / 6.022·10^23 (1/mol).

n = 3.32116 mol. M(Cr) = 52.00 g/mol and  mass m = nM = 172.7 g

PROBLEM 1.22 Give the hybridization state of each carbon in the following

compounds:

(a) Carbon dioxide (0 = C = O)

(d) Propene (C*H_{3}*CH = C*H_{2})

(b) Formaldehyde (H_{2}*C = O)

(e) Acetone [(CH 3 ) 2 C = OI

(c) Ketene (H_{2}*C = C = O)

(f) Acrylonitrile ( C*H_{2} =CHC equiv N)

SAMPLE SOLUTION

(a) Carbon in C*O_{2} is directly bonded to two other atoms. It

is sp-hybridized.

Answers

To solve this we must be knowing each and every concept related to hybridisation. Therefore, the hybridisation of the given molecule can be given as below.

What is hybridisation?

Only during bond formation does hybridization occur, not in an individual gaseous atom. If the bonding of a molecule is known, the geometry of the molecule may be predicted.

compound                                                              hybridisation

Carbon dioxide (0 = C = O)                                       sp

Propene (CH[tex]_3[/tex]CH = CH[tex]_2[/tex])                                            sp³, sp²,sp²

Formaldehyde (H[tex]_2[/tex]C = O)                                             sp²

Acetone [(CH[tex]_3[/tex] )[tex]_2[/tex] C = O                                                 sp³, sp²,      sp³

Ketene (H[tex]_2[/tex]C = C = O)                                                  sp²,    sp

Therefore, the hybridisation of the given molecule can be given as above.

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bahobilat at dakobilat​

Answers

Answer:

sorry i didn't understand your question can you explain me your question have a good day hope its helps you ☺

LOLLL dako imong bilat-
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