1.Number graph
2.Graph the line using the equation y=1/2x ​

Answer:

Step-by-step explanation:

To find the percentage of her total spending that she spent on Fun, we need to first find her total spending. We add up the amounts she spent in each category:

\begin{align*}

\text{Total spending} &= \text{Rent} + \text{Food} + \text{Fun} + \text{Other} \\

&= 1200 + 500 + 300 + 200 \\

&= 2200

\end{align*}

So Kara spent a total of $2200 this month.

To find the percentage of her spending that went towards Fun, we divide the amount spent on Fun by the total spending and then multiply by 100 to convert to a percentage:

300/2200 x 100 ≈ 13.6%

So Kara spent approximately 14% of her total spending on Fun.

Answer:

Step-by-step explanation:

To calculate the change in entropy, we need to consider each step of the process separately and then add up the individual entropy changes.

Step 1: Heating ice from -10.0°C to 0°C

The heat required for this step can be calculated using the formula:

q = m * Cp * ΔT

where m is the mass of ice, Cp is the molar constant-pressure heat capacity of ice, and ΔT is the change in temperature.

q = 10.0 g / 18.01528 g/mol * 37.6 J/K/mol * 10.0°C = 20.8 J

The entropy change for this step can be calculated using the formula:

ΔS = q / T

where T is the temperature in Kelvin.

ΔS = 20.8 J / 263.15 K = 0.079 J/K

Step 2: Melting ice at 0°C

The heat required for this step can be calculated using the formula:

q = n * ΔHfus

where n is the number of moles of ice and ΔHfus is the standard enthalpy of fusion of water.

n = 10.0 g / 18.01528 g/mol = 0.555 mol

q = 0.555 mol * 6.01 kJ/mol = 3.33 kJ = 3330 J

The entropy change for this step can be calculated using the formula:

ΔS = q / T

where T is the melting point of water in Kelvin (273.15 K).

ΔS = 3330 J / 273.15 K = 12.2 J/K

Step 3: Heating water from 0°C to 100°C

The heat required for this step can be calculated using the formula:

q = m * Cp * ΔT

where m is the mass of water (which is equal to the mass of ice that melted), Cp is the molar constant-pressure heat capacity of water, and ΔT is the change in temperature.

q = 10.0 g / 18.01528 g/mol * 75.3 J/K/mol * 100.0°C = 415.9 J

The entropy change for this step can be calculated using the formula:

ΔS = q / T

where T is the average temperature during the heating process (which is 50°C).

ΔS = 415.9 J / 323.15 K = 1.29 J/K

Step 4: Vaporizing water at 100°C

The heat required for this step can be calculated using the formula:

q = n * ΔHvap

where n is the number of moles of water and ΔHvap is the standard enthalpy of vaporization of water.

n = 10.0 g / 18.01528 g/mol = 0.555 mol

q = 0.555 mol * 40.7 kJ/mol = 22.6 kJ = 22600 J

The entropy change for this step can be calculated using the formula:

ΔS = q / T

where T is the boiling point of water in Kelvin (373.15 K).

ΔS = 22600 J / 373.15 K = 60.5 J/K

Step 5: Heating steam from 100°C to 115°C

The heat required for this step can be calculated using the formula:

q = m * Cp * ΔT

where m is the mass of steam (which is equal to the mass of ice that melted and the mass of water that vaporized), Cp is the molar constant-pressure heat

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Therefore, the volume of the cone is approximately 800π cubic centimeters, or approximately 2512.44 cubic centimeters when rounded to two decimal places.

Volume is a measure of the amount of space occupied by a three-dimensional object or a substance. The volume of a solid object can be determined by measuring its dimensions, such as its length, width, and height, and applying an appropriate mathematical formula depending on its shape.

Here,

The volume of a cone can be calculated using the formula:

V = (1/3)πr²h

where r is the radius of the base, h is the height of the cone, and π is a constant equal to approximately 3.14. In this case, we are given the radius of the cone as 10 cm and the slant height as 26 cm. We can use the Pythagorean theorem to find the height of the cone:

h² = (slant height)² - (radius)²

h² = 26² - 10²

h² = 576

h = √576

h = 24

Now that we have the height of the cone, we can use the formula for the volume of a cone:

V = (1/3)πr²h

V = (1/3)π(10²)(24)

V = (1/3)π(100)(24)

V = (1/3)(2400π)

V = 800π

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Answer:

Volumeof a cone=2,723.8095238095

Step-by-step explanation:

Slant height = 26cm

radius = 10cm

volume of a cone = ‽

The volume of cone =

[tex]v = \frac{1}{3} \pi {r}^{2} h[/tex]

[tex]v = \frac{1}{3} \times \frac{22}{7} \times 10 \times 10 \times 26 \\ \frac{1}{3} \times \frac{22}{7} \times 100 \times 26 \\ = \frac{22}{21} \times 2600 \\ = \frac{57200}{21} \\ = 2,723.8095238095cm[/tex]

The value of the expression is 2

Index forms are described as those forms that are used to represent numbers that are too large or small in more convenient forms.

They are also described as numbers that are raised to a variable or an exponents.

Other names for index forms are scientific notations and standard forms.

One of the rules of index forms is that the exponents are added when the have the same and are being multiplied.

From the information given, we have that;

(2^-1/2) / (2^1/2)

subtract the exponents

2^-1/2-1/2

subtract the values

2^ -1

Then, we have;

2

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The function that represents the profit p for selling b bracelets is p = 3.5b - 84

From the question, we have the following parameters that can be used in our computation:

This means that

Cost of b brackets = 3.5b

So, we have

Profit = Cost of b brackets - Cost price

substitute the known values in the above equation, so, we have the following representation

p = 3.5b - 84

Hence, the function that represents the profit p for selling b bracelets is p = 3.5b - 84

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Answer:

225 miles!!!!!!!!!!!!!!!!

The radius of the circle to the nearest 10th is 5.4

The formula for calculating the length of an arc of a circle is:

length of arc = radius x angle in radians

l = rθ

where

r = radius of the circle

l = length of arc

θ = angle in radians

From the question, we are given:

length of arc = 11.9

angle in radians (θ) = 2.2radians

The we can plug in the values

11.9 = r x 2.2

make r the subject of the formula

r = 11.9/2.2

r = 5.41 (to 2 decimal places)

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Comets could be visible from Earth when they are most likely to fall down into earth

The expected amount of time that the 5:30 appointment spends at the barber shop is,  E[W] = 45 + 45/e.

Given that, the barber has scheduled two appointments, one at

5 pm and the other at 5:30 pm.

Since the amount of time that appointments last are independent exponential random variables with mean 45 minutes.

Let W be the time the 2nd person has to wait in chamber Let X be the time the barber takes checking 1st person X-exp(45)

The distribution is,

W= X-45            if X >45

otherwise.

Expected time 2nd person spends in barber chamber

= E (W)+45

[ 45 is the mean time barber takes checking 2nd person]

[tex]E(W) = \int\limits^{\infinity }_0 {WP(X=45+W)} \, dw\\ \\\\=\int {W.1/45e^{\frac{-45+w}{45} } \, dw\\\\[/tex]

[tex]=e^{-1} \int\frac{W}{45} e^{\frac{-w}{45} } dw\\=\frac{45}{e}[/tex]

The expected amount of time that the 5:30 appointment spends at the barber's office is,

[tex]E[W]=45+\frac{45}{e}[/tex].

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The value of the tangent of J, tan J = 6.2/4

To determine the value, we need to find the opposite side of the angle J.

Using the Pythagorean theorem, we have that;

(√55)² = 4² + j²

Find the square of the values, we get;

55 = 16+ j²

collect the like terms, we have;

j² = 55 - 16

subtract the values

j² = 39

Find the square root of both sides

j = 6. 2

Then, using the tangent identity, we have;

tan J = opposite/adjacent

Opposite = 6. 2

Adjacent = 4

Substitute the values

tan J = 6.2/4

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The rate of change of cost when the number of magazines printed per day is 17 is 752 dollars per print. The correct option is C.

The function C(x) = 25x² - 98x represents the cost of printing magazines per day at a printing press. To find the rate of change of cost when 17 magazines are printed per day, we need to calculate the derivative of the function with respect to x (the number of magazines printed), which represents the rate of change at a given point.

The derivative of C(x) with respect to x can be found using the power rule for differentiation. For a function of the form f(x) = [tex]ax^n[/tex], its derivative is f'(x) = [tex]n*ax^{(n-1)[/tex].

Applying the power rule to our function, we get:
C'(x) = 2(25x) - 98 = 50x - 98.

Now, we need to evaluate C'(x) when x = 17 (the number of magazines printed per day):
C'(17) = 50(17) - 98 = 850 - 98 = 752.

Therefore, the rate of change of cost when the number of magazines printed per day is 17 is 752 dollars per print. So, the correct answer is: C. 752$/print.

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1. The next two term for the sequence using Geometric Progression is 8 and 16

2. The next two terms for the sequence using arithmetic progression is 7 and 11

A sequence is an ordered list of numbers (or other elements like geometric objects), that often follow a specific pattern or function.

Using Geometric Progression, the common ratio is 2/1 = 2

therefore the next two terms will be

4× 2 = 8 and 8× 2 = 16

Using Arithmetic progression , the common difference will be increasing by 1 per number of term, i.e r+1

for the fourth term ,common difference = 2+1 = 3

fourth term = 4+3 = 7

for the fifth term , common difference = 3+1 = 4

fifth term = 7+4 = 11

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There are 4 invariant points on the perimeter of the square when oabc is translated by the vector (1 3).

To find the invariant points on the perimeter of the square when oabc is translated by the vector (1 3), we need to apply this translation to each vertex of the square and see which ones remain on the square.

If we add the vector (1 3) to each vertex, we get:
o + (1 3) = (1 3)
a + (1 3) = (4 3)
b + (1 3) = (4 6)
c + (1 3) = (1 6)

Now we need to check which of these points are still on the square. We can see that points (1 3) and (4 3) are on two adjacent sides of the square, and points (1 6) and (4 6) are on the other two adjacent sides.

Therefore, there are 4 invariant points on the perimeter of the square when oabc is translated by the vector (1 3). These invariant points are the points where the sides of the original square intersect with the sides of the translated square.

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The point on the number line that represents the probability of rolling an even number and selecting a green marble is 3/8, which is between 0.3 and 0.4 on the number line.

Will she land on an even number and then selects agreen marble?

The probability of rolling an even number is 3/6, which can be simplified to 1/2, because there are three even numbers (2, 4, and 6) out of six possible outcomes.

The probability of selecting a green marble from the bag is 3/4, because there are three green marbles out of four total marbles in the bag.

To calculate the probability of both events happening together (rolling an even number and selecting a green marble), you multiply the probabilities of each event:

P(even number and green marble) = P(even number) x P(green marble)

P(even number and green marble) = (1/2) x (3/4)

P(even number and green marble) = 3/8

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the distance between the two planes is |x - 19|. Since we don't have any information about the value of x, we cannot compute the exact distance. We can only give the answer in terms of |x - 19|, rounded to three decimal places.

To verify that the two planes are parallel, we need to check if their normal vectors are parallel. The normal vector of the first plane is <2, 0, 0> and the normal vector of the second plane is <2, 0, -4>. We can see that these vectors are parallel because they have the same direction but different magnitudes. Therefore, the two planes are parallel.

To find the distance between the planes, we can use the formula:

distance = |ax + by + cz + d| / √(a² + b² + c²)

where a, b, and c are the coefficients of the variables x, y, and z in the equation of one of the planes, and d is the constant term.

Let's use the first plane: 2x - 42 = 4

We can rewrite this as 2x - 38 = 0, which means that a = 2, b = 0, c = 0, and d = -38.

Substituting these values into the formula, we get:

distance = |2x + 0y + 0z - 38| / √(2² + 0² + 0²)
distance = |2x - 38| / 2
distance = |x - 19|

Therefore, the distance between the two planes is |x - 19|. Since we don't have any information about the value of x, we cannot compute the exact distance. We can only give the answer in terms of |x - 19|, rounded to three decimal places.

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Answer:

y=9

Step-by-step explanation:

The opposite angles of 2 intersecting lines are equal.

11y-36⁰=63⁰

11y=63⁰+36⁰

11y=99⁰

y=9

Hope this helps!

The total area of the composite figure is 576 square meters

From the question, we have the following parameters that can be used in our computation:

The composite figure

The total area of the composite figure is the sum of the individual shapes

So, we have

Surface area = Rectangle + Trapezoid

Using the area formulas, we have

Surface area = 29 * 16 + 1/2 *(14 + 18) * (36 - 29)

Evaluate

Surface area = 576

Hence. the total area of the figure is 576 square meters

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Complete question

Find the area of the polygon.

See attachment

The area of the polygon is ____ square meters.

The calculated number of times you would expect to roll a three or a six is 32 times

From the question, we have the following parameters that can be used in our computation:

Cube = 96

In a cube, we have the following probability equation

P(3 or 6) = 1/6 + 1/6

When the sum is evaluated, we have

P(3 or 6) = 2/6

So, when the die is rolled 96 times, we have

Expected value = 2/6 * 96

Evaluate the products

Expected value = 32

Hence, the expected number of times is 32

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The probability that the drug lasts less than 220 minutes for a random sample of 10 people is 0.0571, or about 5.71%.

To solve this problem, we need to use the normal distribution formula and the central limit theorem. The formula for the standard normal distribution is:

z = (x - μ) / σ

where z is the z-score, x is the observed value, μ is the mean, and σ is the standard deviation.

In this case, we want to find the probability that the drug lasts less than 220 minutes (3 hours and 40 minutes) for a random sample of 10 people. To do this, we first need to calculate the sample mean and the sample standard deviation.

The sample mean is the same as the population mean, which is 240 minutes:

μ = 240 minutes

The sample standard deviation is given by the formula:

σ = population standard deviation / sqrt(sample size)

σ = 40 minutes / sqrt(10) = 12.65 minutes (rounded to the nearest hundredth)

Now, we can calculate the z-score for a drug duration of 220 minutes:

z = (220 - 240) / 12.65 = -1.58 (rounded to the nearest hundredth)

We can use a standard normal distribution table or a calculator to find the probability that the z-score is less than -1.58. The probability is approximately 0.0571 (rounded to the nearest ten-thousandth).

Therefore, the probability that the drug lasts less than 220 minutes for a random sample of 10 people is 0.0571, or 5.71%.

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To maximize the revenue, we need to find the maximum value of the revenue function.

The revenue function, R(x), is given by the product of the price per bolt (p) and the number of bolts sold (x thousand), which is R(x) = p * x.

Given the price function p = 82 - 26x,

we can substitute this into the revenue function:

R(x) = (82 - 26x) * x

Now, we need to find the maximum value of R(x). We'll do this by taking the derivative of R(x) with respect to x and setting it to zero:

R'(x) = d/dx[(82 - 26x) * x] R'(x) = 82 - 52x

Now, we set R'(x) = 0 and solve for x: 0 = 82 - 52x 52x = 82 x = 82 / 52 x ≈ 1.58

So, approximately 1.58 thousand (or 1580) bolts must be sold to maximize revenue in the hardware store.

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Answer:

---------------------------------

5) Use the combination formula:

In this case, n = 15 (total students) and r = 5 (students in a group).

Substitute and calculate:

The teacher can combine the students in 3003 ways for the first group.

6) After the first group of five is selected, there are 10 students remaining.

Again use the combination formula, with n = 10 and r = 5:

The teacher can combine the remaining students in 252 ways for the second group.

Kritim's percentage profit is 8.5%.

Milan bought the table for Rs 3600 and sold it to Kritim at a profit of Rs 205. Hence, Kritim paid Rs 3600 + Rs 205 = Rs 3805 for the table. Kritim then sold the table to Aayush for Rs 4968.

To find Kritim's profit percentage, we need to calculate the profit percentage on the cost price. The cost price for Kritim is Rs 3805, and the selling price is Rs 4968. Hence, the profit earned by Kritim is Rs 4968 - Rs 3805 = Rs 1163.

Profit percentage = (Profit / Cost price) x 100%

Profit percentage = (1163 / 3805) x 100%

Profit percentage = 0.3055 x 100%

Profit percentage = 30.55%

Therefore, Kritim's profit percentage is 8.5%.

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To answer this question, we need to compare the discounts offered by both stores for the Holy Stone drone with live video and adjustable wide-angle camera.

Best Buy is offering a discount of 20% on the drone for Black Friday, while PC Richard and Son is offering a discount of 10% plus an extra $20 off to the first 100 customers.

To calculate the price at Best Buy after the 20% discount, we need to multiply the original price of the drone by 0.8 (100% - 20%). Let's assume the original price of the drone is $200. So, the price at Best Buy after the discount will be:

Price at Best Buy = $200 x 0.8 = $160

To calculate the price at PC Richard and Son after the discount, we need to first calculate the 10% discount and then subtract the extra $20 off. Let's assume the original price of the drone is still $200. So, the price at PC Richard and Son after the 10% discount will be:

Price after 10% discount = $200 x 0.9 = $180

Then, we need to subtract the extra $20 off for the first 100 customers:

Price at PC Richard and Son = $180 - $20 = $160

So, both stores are offering the drone at the same price of $160 after the discounts. However, since you are one of the first 100 customers at PC Richard and Son, you can also get an extra $20 off, making it the cheaper option. Therefore, you should go to PC Richard and Son to get the cheaper price.

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The intermediate step in completing the square for x^2= -16x-37 is (x+8)^2=27.

To complete the square for the given equation, we need to add a constant value to both sides of the equation such that we can factor the left-hand side as a perfect square.

x^2 + 16x = -37

To determine the constant value we need to add to both sides, we take half the coefficient of x (which is 16/2 = 8) and square it to get 64. Then we add 64 to both sides of the equation:

x^2 + 16x + 64 = 27

Now we can factor the left-hand side as a perfect square:

(x + 8)^2 = 27

So the intermediate step in completing the square for x^2= -16x-37 is (x+8)^2=27.

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The range of the function f(x) is Range: [0, 125] In interval notation, this can be written as [0, 125] if the longest side length of the box can be no greater than 20 in.

The function f(x) = 1.25x^2 models the packaging costs, in cents, for a rectangular prism-shaped box with side lengths of 2x in., 2x in., and 0.5x in.

We need to determine the reasonable domain and range values for this function, given that the longest side length of the box can be no greater than 20 in.

Since the longest side length is 20 in., we know that:

2x ≤ 20

x ≤ 10

Therefore, the domain of the function f(x) is all real numbers less than or equal to 10, or: Domain: [-∞, 10]

To find the range of the function, we need to examine the behavior of the function as x varies. Since the coefficient of x^2 is positive, the function is quadratic with a minimum value at x = 0. Therefore, we know that the range of the function must start at its minimum value, which is f(0) = 0, and increase as x increases.

To determine the upper limit of the range, we can evaluate f(x) when x = 10 (the maximum value of x allowed):

f(10) = 1.25(10)^2 = 125

Therefore, the range of the function f(x) is:

Range: [0, 125]

In interval notation, this can be written as [0, 125].

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The area of the painted face of the brick is given as follows:

108 in².

The area of a rectangle of length l and width w is given by the multiplication of dimensions, as follows:

A = lw.

The dimensions for this problem are given as follows:

Hence the area of the painted face of the brick is given as follows:

A = 12 x 9 = 108 in².

(the area of a rectangle is given by the multiplication of the dimensions, which we did here).

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The simplified form of the given expression is (x-7)/3x.

The given expression is (2x²-8x-42)/6x² ÷ (x²-9)/(x²-3x)

Here, (x²-4x-21)/3x² ÷ (x-3)(x+3)/x(x-3)

= (x²-4x-21)/3x² ÷ (x+3)/x

= (x²-4x-21)/3x² × x/(x+3)

= (x²-4x-21)/3x × 1/(x+3)

= (x²-4x-21)/3x(x+3)

= (x²-7x+3x-21)/3x(x+3)

= [x(x-7)+3(x-7)]/3x(x+3)

= (x-7)(x+3)/3x(x+3)

= (x-7)/3x

Therefore, the simplified form of the given expression is (x-7)/3x.

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The total fraction of the wall that has been painted is 1/2. If a whole wall is split in half and we painted half of the wall 3 colors, each color occupies 1/6 of the painted area.

To answer your question, we need to first determine the total fraction of the wall that has been painted. Since the wall has been split in half, we can say that the painted area covers half of the wall. Therefore, the total fraction of the wall that has been painted is 1/2.

Now, we need to divide this 1/2 fraction among the three colors that were used. Let's say the three colors are red, blue, and green. We can represent the fraction of the wall occupied by each color as follows:

- Red: 1/3 x 1/2 = 1/6
- Blue: 1/3 x 1/2 = 1/6
- Green: 1/3 x 1/2 = 1/6

So each color occupies 1/6 of the painted area, which is equivalent to 1/12 of the whole wall. This means that if the wall was not split in half and we painted the entire wall with the same 3 colors, each color would occupy 1/12 of the total wall area.

In summary, if a whole wall is split in half and we painted half of the wall 3 colors, each color occupies 1/6 of the painted area, which is equivalent to 1/12 of the whole wall.

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If Sabina and the pole are proportional, then the pole’s shadow will be 35/4 feet tall.

Since Sabrina is 4 feet tall and casts a 3.5-foot shadow, we can set up a proportion comparing the heights and shadow lengths: Sabrina's height (4 feet) / her shadow (3.5 feet) = pole's height (10 feet) / pole's shadow (x).

This proportion can be represented as: 4/3.5 = 10/x. To solve for x (the length of the pole's shadow), we can cross-multiply:

4 * x = 3.5 * 10

4x = 35

Now, divide both sides by 4:

x = 35/4

So, the pole's shadow will be 35/4 feet long when both Sabrina and the pole are proportional. This fraction represents the pole's shadow length in relation to the given heights and shadow lengths.

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The minimum surface area of the box is 68 cm², which corresponds to option (d).

Let the side length of the square base be x and the height of the box be h. Then, we have:

Volume of the box = x²h = 32

h = 32/x²

The surface area of the box is given by:

S = x² + 4(xh) = x² + 4x(32/x²) = x² + 128/x

To find the minimum surface area, we can differentiate S with respect to x, set the derivative equal to zero, and solve for x:

dS/dx = 2x - 128/x² = 0

2x = 128/x²

x⁴ = 64

x = 2 cm

Note that we need to check that this critical point gives us a minimum surface area. We can do this by checking the second derivative:

d²S/dx² = 2 + 256/x³

d²S/dx² at x = 2 is positive,

indicating that this critical point gives us a minimum surface area.

Substituting x = 2 in the equation for S, we get:

S = 2² + 128/2 = 4 + 64 = 68

Therefore, the minimum surface area of the box is 68 cm², which corresponds to option (d).

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