The Snickers bar released 1,077,280 joules of energy when burned.
To calculate the energy released by burning a Snickers bar, we can use the formula:
q = mcΔT
where q is the heat energy released, m is the mass of water, c is the specific heat of water, and ΔT is the temperature change.
We know the mass of water is 3500 g, and the temperature change is 72°C. The specific heat of water is 4.184 J/g°C.
Therefore:
q = (3500 g) x (4.184 J/g°C) x (72°C) = 1077280 J
So, the Snickers bar released 1,077,280 joules of energy when burned.
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A gas is confined in a cylinder fitted with a movable piston. At 27°C, the gas occupies a volume of 2. 0 L under a pressure of 3. 0 atm. The gas is heated to 47 °C and compressed to 5. 0 atm. What volume does the gas occupy in its final state?
a. 0. 48 L
b. 2. 1 L
c. 1. 3 L
d. 0. 78
The gas occupies a volume of 1.28 L in its final state, which is option (c).
We can solve this problem using the combined gas law:
(P1V1/T1) = (P2V2/T2)
where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.
Plugging in the given values, we have:
(3.0 atm)(2.0 L)/(300 K) = (5.0 atm)(V2)/(320 K)
Solving for V2, we get:
V2 = (3.0 atm)(2.0 L)(320 K)/(5.0 atm)(300 K) = 1.28 L
Therefore, the gas occupies a volume of 1.28 L in its final state, which is option (c).
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A solution is prepared by dissolving 8.50 g of c6h12o6 in 4.15 g of cyclohexane. what is the % mass of c6h12o6 in the new solution? round your answer to 1 decimal places.
The % mass of C6H12O6 in the new solution is approximately 67.2%.
We can calculate the mass percentage of C6H12O6 in the new solution using the following formula:
% mass = (mass of C6H12O6 / total mass of solution) x 100%
First, we need to calculate the total mass of the solution by adding the mass of C6H12O6 and the mass of cyclohexane:
total mass of solution = 8.50 g + 4.15 g = 12.65 g
Next, we can calculate the mass percentage of C6H12O6 in the solution:
% mass = (8.50 g / 12.65 g) x 100% ≈ 67.2%
Therefore, the % mass of C6H12O6 in the new solution is approximately 67.2%.
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At 15. 17 atm and 243. 41 K a certain gas has a volume of 641. 68 L. What will the volume of gas be at 561. 06 K and 70. 3 atm?
The volume of the gas at 561.06 K and 70.3 atm will be 168.08 L.
The initial conditions of the gas are given as P₁ = 15.17 atm, V₁ = 641.68 L, and T₁ = 243.41 K. To find the volume of the gas at the new conditions, we can use the combined gas law:
(P₁V₁)/T₁ = (P₂V₂)/T₂
where P₂, V₂, and T₂ are the new pressure, volume, and temperature, respectively.
We can rearrange the equation to solve for V₂:
V₂ = (P₂/P₁) x (T₁/T₂) x V₁
Substituting the given values:
V₂ = (70.3/15.17) x (243.41/561.06) x 641.68
V₂ = 168.08 L
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7. Calculate: Turn off Show most probable velocity and Show mean velocity. Select Hydrogen and set the Temperature to 100 K. You can calculate the most probable velocity (vp), mean velocity ( ), and root mean square velocity (vrms) using the following formulas: In each formula, R stands for the universal gas constant, or 8. 3144 J / K mol, T stands for Kelvin temperature, and M stands for the molar mass, in kg / mol. Hydrogen gas (H2) has a molar mass of 0. 002016 kg / mol. A. Calculate the most probable velocity (vp): ____________________ B. Check by turning on Show most probable velocity. Were you correct
The most probable velocity of hydrogen gas at 100 K is approximately 1809.46 m/s.
To calculate the most probable velocity (vp) of hydrogen gas [tex](H_2)[/tex] at 100 K, we can use the following formula:
[tex]vp = (2RT/\pi M)^{(1/2)}[/tex]
where R is the universal gas constant (8.3144 J/K*mol),
T is the temperature in Kelvin (100 K),
π is pi (3.14159),
and M is the molar mass of hydrogen gas (0.002016 kg/mol).
Putting in the values, we get:
[tex]vp = (2 * 8.3144 J/K*mol * 100 K / \pi * 0.002016 kg/mol)^{(1/2)}\\vp = 1809.46 m/s[/tex]
Therefore, the most probable velocity of hydrogen gas at 100 K is approximately 1809.46 m/s.
To check if the answer is correct, we can turn on Show most probable velocity. If the calculated value matches the displayed value, then we know we are correct.
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How a substance appears due to the wavelength of the light reflected off of its surface
The appearance of a substance is greatly influenced by the wavelength of light that is reflected off its surface.
This is because different substances absorb and reflect different wavelengths of light, resulting in the unique appearance of each material.
When light hits an object, it can either be absorbed, transmitted or reflected. The color of the object is determined by the wavelengths of light that are reflected back into our eyes. For example, a red apple appears red because it absorbs all colors of light except for red, which is reflected back to our eyes.
Similarly, a blue object appears blue because it reflects blue light while absorbing other colors.
The wavelength of light is also responsible for the phenomenon of iridescence, where objects appear to change color depending on the angle of light. This happens because the surface of the object reflects different wavelengths of light at different angles, creating a shimmering effect.
In summary, the wavelength of light that is reflected off an object greatly influences its appearance. By understanding how different substances interact with light, we can better understand the colors and textures of the world around us.
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The hydrolysis of acetyl phosphate has ΔG = −42 kJ mol−1 under typical biological conditions. If the phosphorylation of acetic acid were to be coupled to the hydrolysis of ATP, what is the minimum number of ATP molecules that would need to be involved?
The hydrolysis of one ATP molecule has ΔG = -30.5 kJ mol⁻¹. Therefore, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate, with ΔG = -42 kJ mol⁻¹, is 2 ATP molecules.
The phosphorylation of acetic acid involves the transfer of a phosphate group from ATP to acetic acid, forming acetyl phosphate and ADP. The reaction can be represented as follows:
Acetic acid + ATP → Acetyl phosphate + ADPThe hydrolysis of acetyl phosphate involves the addition of a water molecule, which breaks the phosphoanhydride bond and releases the energy stored in the phosphate bond. The reaction can be represented as follows:
Acetyl phosphate + H₂O → Acetic acid + PiThe ΔG value of the hydrolysis of acetyl phosphate is -42 kJ mol⁻¹. Since the phosphorylation of acetic acid requires one ATP molecule, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate is calculated as follows:
ΔG = ΔG1 + ΔG2-42 kJ mol⁻¹ = -30.5 kJ mol⁻¹ + ΔG2ΔG2 = -42 kJ mol⁻¹ + 30.5 kJ mol⁻¹ΔG2 = -11.5 kJ mol⁻¹Since the hydrolysis of one ATP molecule has ΔG = -30.5 kJ mol⁻¹, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate is 2.
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Calculate the molarity of the solutions described below. Round all answers to 2 decimal places. Hint: Use molar mass and dimensional analysis to convert grams into moles. A) 100.0 g of sodium chloride is dissolved in 3.0 L of solution. Answer: 0.57 M B) 72.5 g of sugar (C12H22O11) s dissolved in 1.5 L of solution. Answer: 0.13 M C) 125 g of aluminum sulfate is dissolved in 0.150 L of solution. Answer: M D) 1.75 g of caffeine (C8H10N4O2) is dissolved in 0.200 L of solution. Answer: M
Explanation:
A) To calculate the molarity of sodium chloride solution, we need to first convert the mass of sodium chloride into moles, using its molar mass of 58.44 g/mol:
100.0 g NaCl × (1 mol NaCl/58.44 g NaCl) = 1.71 mol NaCl
Then, we divide the number of moles by the volume of solution in liters to get the molarity:
Molarity = 1.71 mol NaCl ÷ 3.0 L = 0.57 M
Therefore, the molarity of the sodium chloride solution is 0.57 M.
B) To calculate the molarity of sugar (C12H22O11) solution, we need to first convert the mass of sugar into moles, using its molar mass of 342.3 g/mol:
72.5 g C12H22O11 × (1 mol C12H22O11/342.3 g C12H22O11) = 0.212 mol C12H22O11
Then, we divide the number of moles by the volume of solution in liters to get the molarity:
Molarity = 0.212 mol C12H22O11 ÷ 1.5 L = 0.13 M
Therefore, the molarity of the sugar solution is 0.13 M.
C) To calculate the molarity of aluminum sulfate solution, we need to first convert the mass of aluminum sulfate into moles, using its molar mass of 342.2 g/mol:
125 g Al2(SO4)3 × (1 mol Al2(SO4)3/342.2 g Al2(SO4)3) = 0.365 mol Al2(SO4)3
Then, we divide the number of moles by the volume of solution in liters to get the molarity:
Molarity = 0.365 mol Al2(SO4)3 ÷ 0.150 L = 2.43 M
Therefore, the molarity of the aluminum sulfate solution is 2.43 M.
D) To calculate the molarity of caffeine (C8H10N4O2) solution, we need to first convert the mass of caffeine into moles, using its molar mass of 194.2 g/mol:
1.75 g C8H10N4O2 × (1 mol C8H10N4O2/194.2 g C8H10N4O2) = 0.009 mol C8H10N4O2
Then, we divide the number of moles by the volume of solution in liters to get the molarity:
Molarity = 0.009 mol C8H10N4O2 ÷ 0.200 L = 0.045 M
Therefore, the molarity of the caffeine solution is 0.045 M
Answer:
Hi and sorry.
But what is the question in that?
There is already answers so i don't know how to help you.
Explanation:
6. How many moles are in 2. 65x10 22 atoms of carbon?
7. How many moles are in 1. 79x10 25 molecules of ammonia?
In problem 6, the number of atoms of carbon is 2.65 x 10²², which corresponds to 0.044 moles of carbon after dividing by Avogadro's number whereas In problem 7, the number of molecules of ammonia is 1.79 x 10²⁵, which is equivalent to 29.7 moles of ammonia after dividing by Avogadro's number.
In 6, the number of atoms of carbon given is 2.65 x 10²². To convert this to moles, we need to divide by Avogadro's number (6.02 x 10²³ atoms/mol).
Therefore, the number of moles of carbon is:
2.65 x 10²² atoms / 6.02 x 10²³ atoms/mol = 0.044 moles of carbon
In 7, the number of molecules of ammonia given is 1.79 x 10²⁵. To convert this to moles, we need to divide by Avogadro's number (6.02 x 10²³ molecules/mol).
Therefore, the number of moles of ammonia is:
1.79 x 10²⁵ molecules / 6.02 x 10²³ molecules/mol = 29.7 moles of ammonia.
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Use Boyle's, Charle's, or Gay-Lussac's law to calculate the missing value in each of the following. A. V1=2. 0 L, P1=0. 82 Atm, V2=1. 0 L, p2=?
After using Gay-Lussac's Law the missing value in this problem is P2, which is equal to 1.64 Atm
In this problem, we can use Gay-Lussac's law to calculate the missing value. Gay-Lussac's law states that at constant volume, the pressure of a gas is directly proportional to its temperature. In other words, if we increase the temperature of a gas, its pressure will increase as well, as long as the volume remains constant.
To use Gay-Lussac's law, we need to know the initial pressure and volume of the gas, as well as the final volume. We can then calculate the final pressure using the formula:
P2 = (P1 * V1 * T2) / (V2 * T1)
In this case, we know that V1 = 2.0 L, P1 = 0.82 Atm, V2 = 1.0 L, and we need to find P2. We don't know the temperature of the gas, but since the volume is decreasing and the pressure is likely to increase, we can assume that the temperature is staying the same.
Plugging in the values we have, we get:
P2 = (0.82 Atm * 2.0 L * T2) / (1.0 L * T1)
Simplifying this expression, we get:
P2 = 1.64 Atm
Therefore, the missing value in this problem is P2, which is equal to 1.64 Atm. We used Gay-Lussac's law to calculate this value based on the initial pressure, volume, and the final volume of the gas.
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Consider the following acid and bases HCO2H ka = 1. 8 x 10^-4
HOBr Ka = 2. 0 x 10^-9
(C2H5)2NH kb = 1. 3 x 10-3
HONH2 kb = 1. 1 x 10^-8
choose sobstances to create ph = 4 buffer solutions:
select all tha apply
HONH3NO3
HOBr
NaOBr
(C2H5)2NH2Cl
(C2H5)2NH
HCO2H
KHCO2
HONH2
The substances that can create a pH = 4 buffer solution are HCO₂H and KHCO₂.
When modest quantities of acid or base are added to a buffer solution, it resists changes in pH. In order to create a buffer solution, we need to have a weak acid and its conjugate base, or a weak base and its conjugate acid, in roughly equal amounts.
HCO₂H is a weak acid with a pKa of 3.74, and its conjugate base is HCO₂⁻. KHCO₂ is the potassium salt of HCO₂⁻, and it acts as a source of HCO₂⁻ ions, making it a good buffer component.
The other substances listed are not suitable for creating a pH = 4 buffer solution because they either do not have a pKa or pKb near 4, or they are neither a pair of a weak acid and its conjugate base, or a pair of a weak base and its conjugate acid..
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The pressure of 10 l of a gas is 1800 mmhg. how many l would this same gas occupy at a final pressure of 200 mmhg, if the amount of gas does not change?
The gas would occupy 90 L at a final pressure of 200 mmHg if the amount of gas does not change.
To determine how many liters this gas would occupy at a final pressure of 200 mmHg, we can use Boyle's Law. Boyle's Law states that the product of the initial pressure and volume of a gas is equal to the product of the final pressure and volume if the temperature and amount of gas remain constant. The formula for Boyle's Law is:
P₁ × V₁ = P₂ × V₂
Where P₁ is the initial pressure (1800 mmHg), V₁ is the initial volume (10 L), P₂ is the final pressure (200 mmHg), and V₂ is the final volume we need to find.
Rearranging the formula to find V₂:
V₂ = (P₁ × V₁) / P₂
Substituting the values:
V₂ = (1800 mmHg × 10 L) / 200 mmHg
V₂ = 18000 L·mmHg / 200 mmHg
V₂ = 90 L
So, this gas would occupy 90 L at a final pressure of 200 mmHg if the amount of gas does not change.
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(copied answer from the sheet)
The iron haematite contains 70% iron by mass. We can calculate the amount of iron obtained in 1 tonne (1000kg) of haematite by:
Mass of iron )kg)= 70/100 x1000=700kg
Calculate the amount of calcium and magnesium obtained from 500kg of dolomite, which is 22% calcium and 13% magnesium by mass. Show your working
1. The mass of calcium obtained from 500 Kg of dolomite is 110 kilograms
2. The mass of magnesium obtained from 500 Kg of dolomite is 65 kilograms
How do i determine the mass obtained?The mass of calcium and magnesium in the 500 Kg of dolomite can be obtained as shown below:
1. For calcium
Percentage of calcium = 22%Mass of dolomite = 500 kilogramsMass of calcium =?Mass of calcium = Percentage of calcium × Mass of dolomite
Mass of calcium = 22% × 500
Mass of calcium = (22/100) × 500
Mass of calcium = 110 kilograms
2. For magnesium
Percentage of magnesium = 13%Mass of dolomite = 500 kilogramsMass of magnesium =?Mass of magnesium = Percentage of magnesium × Mass of dolomite
Mass of magnesium = 13% × 500
Mass of magnesium = (13/100) × 500
Mass of magnesium = 65 kilograms
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you are separating anthracene from benzoic acid via an extraction between ethyl acetate and a basic aqueous solution in a separatory funnel. how would you recover the benzoic acid? group of answer choices collect the top layer, dry with na2so4, filter to remove the na2so4, and evaporate the solvent. collect the bottom layer, dry with na2so4, filter to remove the na2so4, and evaporate the solvent. collect the top layer and add hcl to precitipate the compound. collect the bottom layer and add hcl to precipitate the compound. collect the top layer and add naoh to precipitate the compound. collect the bottom layer and add naoh to precipitate the compound.
To recover the benzoic acid, collect the bottom layer, dry it with [tex]Na_{2} SO_{4}[/tex], filter to remove [tex]Na_{2} SO_{4}[/tex], and evaporate the solvent. The option 4 is correct.
This is because benzoic acid is a carboxylic acid and will react with the basic aqueous solution to form a water-soluble carboxylate salt. As a result, benzoic acid will be in the aqueous layer, which is the bottom layer. Ethyl acetate is the organic solvent and will form the top layer. By collecting the bottom aqueous layer, we can isolate the benzoic acid. Drying the solution with [tex]Na_{2} SO_{4}[/tex] removes any remaining water, and evaporating the solvent leaves behind the solid benzoic acid. Option 4 is correct answer.
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--The complete Question is, you are separating anthracene from benzoic acid via an extraction between ethyl acetate and a basic aqueous solution in a separatory funnel. how would you recover the benzoic acid? group of answer choices
1. collect the top layer, dry with na2so4,
2. filter to remove the na2so4, and evaporate the solvent.
3. collect the bottom layer, dry with na2so4,
4. collect the bottom layer and add hcl to precipitate the compound.
5. collect the top layer and add hcl to precitipate the compound. --
I need help with this question PLEASE
The oxidation number approach, commonly referred to as the oxidation states, keeps track of the electrons obtained during reduction and the electrons lost during oxidation.
Thus, Each atom in a charged or neutral molecule is given an oxidation number. Oxidation takes place whenever the oxidation number rises. Reduction happens when the oxidation number goes down. The total charge of a chemical is equal to the sum of all of its oxidation numbers.
The roles of oxidation and reduction is the only foolproof method for balancing a redox equation. Then you achieve equilibrium by bringing the electron gain and loss into balance.
The oxidation numbers of all atoms are determined using the oxidation number method. The altered atoms are then multiplied by small whole numbers.
Thus, The oxidation number approach, commonly referred to as the oxidation states, keeps track of the electrons obtained during reduction and the electrons lost during oxidation.
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Hazel used 45. 7grams of nickel II nitrate Ni(NO3)2 to make a 1. 25M solution. How much water is required to make this solution?
Solve for the GFM=
Hazel needs 0.6975 liters of water to make a 1.25M solution of Ni(NO₃)₂ using 45.7 grams of the solute.
To solve this problem, we need to use the formula:
Molarity (M) = moles of solute / liters of solution
First, we need to find the moles of nickel II nitrate:
moles = mass / molar mass
The molar mass of Ni(NO₃)₂ can be calculated by adding the molar masses of each element:
Ni: 58.69 g/mol
N: 14.01 g/mol
O (3 atoms): 3 x 16.00 g/mol = 48.00 g/mol
Total molar mass = 58.69 + 14.01 + 48.00 = 120.70 g/mol
So, the moles of Ni(NO₃)₂ used by Hazel is:
moles = 45.7 g / 120.70 g/mol = 0.3781 moles
Now, we can use the formula to find the volume of solution:
Molarity (M) = moles of solute / liters of solution
1.25 M = 0.3781 moles / liters of solution
Liters of solution = 0.3781 moles / 1.25 M = 0.3025 L
Therefore, the volume of water required to make the solution is:
Volume of water = Total volume - Volume of solute
Volume of water = 1 L - 0.3025 L = 0.6975 L
So, Hazel needs 0.6975 liters of water to make a 1.25M solution of Ni(NO₃)₂ using 45.7 grams of the solute.
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A solution contains 1.14×10^-2 M calcium acetate and 1.03×10^-2 M barium nitrate. Solid ammonium sulfate is added slowly to this mixture. A. What is the formula of the substance that precipitates first? formula =? B. What is the concentration of sulfate ion when this precipitation first begins? [SO42-] = M
the concentration of sulfate ion when the precipitation of barium sulfate begins is 1.07×10^-8 M.
To determine the formula of the substance that precipitates first, we need to determine which combination of ions will form an insoluble compound first. We can do this by considering the solubility rules for common ionic compounds.
Calcium acetate dissociates into Ca2+ and CH3COO- ions in solution, while barium nitrate dissociates into Ba2+ and NO3- ions. Ammonium sulfate, when added to the solution, will dissociate into NH4+ and SO42- ions.
The possible combinations of ions that can form insoluble compounds are:
- Ca2+ and SO42- form CaSO4, which is insoluble
- Ba2+ and SO42- form BaSO4, which is insoluble
According to the solubility rules, calcium sulfate (CaSO4) is slightly soluble in water, while barium sulfate (BaSO4) is insoluble. Therefore, the substance that precipitates first is barium sulfate (BaSO4).
To determine the concentration of sulfate ion when the precipitation first begins, we need to calculate the product of the concentrations of barium ion and sulfate ion, and compare it to the solubility product constant (Ksp) for barium sulfate.
The balanced chemical equation for the precipitation reaction is:
Ba(NO3)2 + (NH4)2SO4 → BaSO4↓ + 2NH4NO3
The Ksp expression for barium sulfate is:
Ksp = [Ba2+][SO42-]
At the point when precipitation begins, the barium and sulfate ion concentrations will be equal to each other, so we can use the concentration of barium ion to calculate the concentration of sulfate ion:
[Ba2+] = 1.03×10^-2 M
Ksp for barium sulfate is 1.1×10^-10 at 25°C.
Therefore, we can calculate the concentration of sulfate ion:
Ksp = [Ba2+][SO42-]
1.1×10^-10 = (1.03×10^-2 M)([SO42-])
[SO42-] = 1.07×10^-8 M
Therefore, the concentration of sulfate ion when the precipitation of barium sulfate begins is 1.07×10^-8 M.
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12. Lab Analysis: You forgot to label your chemicals and do not know whether your unknown solution is strontium nitrate or magnesium nitrate. You use the solutions potassium carbonate and potassium sulfate in order to determine your mistake. unknown + potassium carbonate & unknown + potassium sulfate . What do you observe when the unknown solution is mixed with potassium carbonate? (Can you see the shape underneath?)
1. Calculate the molarity of
6. 3x10-3 mol C2 N14 in 400 mL H₂O
The solution has a Molarity of approx 0.01575 M.
To calculate the molarity of a solution, we use the formula:
Molarity (M) = moles of solute ÷ volume of solution in liters
First, we need to convert the volume of the solution from milliliters to liters:
Volume of solution = 400 mL = 400/1000 L = 0.4 L
Next, we need to calculate the moles of solute:
moles of solute = 6.3 x [tex]10^{-3[/tex] mol
Substituting these values into the formula, we get:
Molarity (M) = 6.3 x[tex]10^{-3[/tex] mol ÷ 0.4 L = 0.01575 M
Therefore, the molarity of the solution is 0.01575 M.
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1. In a reaction, an excess of iron III oxide are reacted with carbon monoxide
to produce elemental iron and carbon dioxide. A total of 15. 88 grams of iron
are recovered with a percentage yield of 83. 25%.
Calculate the mass of carbon monoxide that has been used in the reaction.
Show ALL work. There will be MULTIPLE steps necessary.
The mass of carbon monoxide that has been used in the reaction is 5.296 g.
To solve this problem, we need to use stoichiometry which deals with the quantitative relationships between reactants and products in chemical reactions.
The balanced chemical equation for the reaction is:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
This equation tells us that for every 2 moles of Fe₂O₃ and 3 moles of CO that react, we get 2 moles of Fe and 3 moles of CO₂.
We are given the mass of iron that was recovered, and the percentage yield of the reaction. The percentage yield is a measure of how much product is actually obtained compared to the theoretical yield, which is the amount of product that would be obtained if the reaction proceeded to completion.
To calculate the theoretical yield of iron, we need to use stoichiometry and the given amount of carbon monoxide used in the reaction. We can use the following equation to calculate the amount of carbon monoxide used:
n = m/M
where n is the number of moles of carbon monoxide used, m is the mass of iron recovered, and M is the molar mass of iron.
Using the given values, we get:
n = 15.88 g / 55.845 g/mol = 0.2838 mol
This is the number of moles of iron that would be produced if the reaction proceeded to completion.
To calculate the theoretical yield of iron, we can use the stoichiometry of the balanced chemical equation. For every 3 moles of carbon monoxide used, 2 moles of iron are produced. So, the number of moles of carbon monoxide used is:
nCO = (2/3) × n = (2/3) × 0.2838 mol = 0.1892 mol
To calculate the mass of carbon monoxide used, we can use the following equation:
mCO = nCO × MCO
where mCO is the mass of carbon monoxide used, and MCO is the molar mass of carbon monoxide, which is 28.01 g/mol.
Using the given values, we get:
mCO = 0.1892 mol × 28.01 g/mol = 5.296 g
Therefore, the mass of carbon monoxide used in the reaction is 5.296 grams.
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1.85 l of a gas is collected over water at 98.0 kpa and 22.0 °c. what is the volume of the dry gas at stp?
In this problem, we are given the volume of a gas collected over water at a certain temperature and pressure. We need to determine the volume of the dry gas at STP (standard temperature and pressure).
First, we need to understand why the presence of water is important in this problem. When a gas is collected over water, some of the water vapor dissolves in the gas, which affects the volume of the gas we measure. In order to account for this, we need to use the concept of vapor pressure.
The vapor pressure of water at 22.0°C is 2.64 kPa. This means that at 22.0°C and 98.0 kPa, the total pressure is the sum of the pressure due to the gas and the pressure due to the water vapor. We can use Dalton's Law of Partial Pressures to calculate the pressure due to the gas alone:
P_gas = P_total - P_water vapor
P_gas = 98.0 kPa - 2.64 kPa
P_gas = 95.36 kPa
Now we can use the Ideal Gas Law to calculate the volume of the dry gas at STP:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. At STP, P = 101.3 kPa and T = 273.15 K.
We can rearrange the Ideal Gas Law to solve for the volume of the dry gas:
V_dry gas = (V_collected gas * P_gas * T_STP) / (P_STP * T_collected gas)
where V_collected gas is the volume of the gas collected over water, T_collected gas is the temperature of the gas collected over water, and T_STP is the temperature at STP.
Plugging in the numbers, we get:
V_dry gas = (1.85 L * 95.36 kPa * 273.15 K) / (101.3 kPa * 295.15 K)
V_dry gas = 1.60 L
Therefore, the volume of the dry gas at STP is 1.60 L. It's important to note that the volume of the dry gas is smaller than the volume of the gas collected over water, because some of the volume was occupied by water vapor.
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25) What occurs when an atom loses an electron?
A) The atom's radius decreases and the atom becomes a negative ion.
B) The atom's radius decreases and the atom becomes a positive ion.
C) The atom's radius increases and the atom becomes a negative ion.
D) The atom's radius increases and the atom becomes a positive ion.
Answer:
An electron has a negative charge therefore, losing the electron will cause the atom to be a positive ion. An ion is an atom where the number of protons does not equal the number of electrons.
Ammonia burns in oxygen according to the following equation:
4nh3 + 3o2 → 2n2 + 6h2o
how many moles of nitrogen gas are generated by the complete reaction of 8.56 moles of ammonia?
4.28 moles of nitrogen gas are generated by the complete reaction of 8.56 moles of ammonia.
To find out how many moles of nitrogen gas are generated by the complete reaction of 8.56 moles of ammonia, we can use the balanced chemical equation: 4NH3 + 3O2 → 2N2 + 6H2O.
Step 1: Identify the mole ratio between ammonia (NH3) and nitrogen gas (N2). From the balanced equation, we see that 4 moles of NH3 produce 2 moles of N2. This gives us a mole ratio of 4:2 or 2:1.
Step 2: Use the mole ratio to determine the moles of nitrogen gas produced. Since the mole ratio is 2:1, for every 2 moles of NH3 that react, 1 mole of N2 is produced.
Step 3: Calculate the moles of nitrogen gas generated from 8.56 moles of ammonia. Divide the given moles of ammonia by the mole ratio:
8.56 moles NH3 / 2 = 4.28 moles N2
Therefore, 4.28 moles of nitrogen gas are generated by the complete reaction of 8.56 moles of ammonia.
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1. a balloon
is filled with hydrogen at a temperature of 22.0°c and a pressure of
$12 mm hg. if the balloon's original volume was 1.25 liters, what will its new
volume be at a higher altitude, where the pressure is only 625 mm hg? assume
the temperature stays the same.
The new volume of the hydrogen-filled balloon at a higher altitude with a pressure of 625 mm Hg will be 6.25 L.
To solve this problem, we can use the gas law equation, which is P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given the initial pressure P1 = 112 mm Hg, the initial volume V1 = 1.25 L, and the final pressure P2 = 625 mm Hg, we can calculate the final volume V2 by rearranging the equation:
V2 = (P1V1) / P2
V2 = (112 mm Hg × 1.25 L) / 625 mm Hg
V2 = 6.25 L
So, the new volume of the balloon at a higher altitude will be 6.25 liters, assuming the temperature remains constant at 22.0°C.
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Please help!!!
1.00 L of gas is collected in a sealed elastic container in outer space where the pressure is 1.54 x 104 mm Hg and the temperature is 88 K. What will the volume be if the container is moved to sea level ( 101.3 kPa) and room temperature ( 23 C)?
The volume of the gas in the container at sea level and room temperature would be approximately 0.00676 L.
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
V = nRT / P
First, we need to calculate the number of moles of gas in the container:
n = PV / RT
Where:
P = 1.54 x[tex]10^{4}[/tex] mm Hg
V = 1.00 L
R = 8.31 J/mol*K (gas constant)
T = 88 K
Converting the pressure to kPa and the volume to m^3:
P = 1.54 x [tex]10^{4}[/tex] mm Hg * (101.3 kPa / 760 mm Hg) = 2054.59 Pa
V = 1.00 L * [tex]10^{-3}[/tex] [tex]m^{3}[/tex]/L) = 0.001 [tex]m^{3}[/tex]
n = (2054.59 Pa * 0.001 m^3) / (8.31 J/mol*K * 88 K) ≈ 0.000276 mol
P = 101.3 kPa
T = 23 + 273.15 K = 296.15 K
V = nRT / P
V = (0.000276 mol * 8.31 J/mol*K * 296.15 K) / 101.3 kPa
Converting the volume to liters:
V = 0.00676 L
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A 0. 50 L can of gas is at a pressure of 20. 0 kPa. If the can is run over by a garbage truck and flattened to a volume of 0. 010 L, what is the pressure in kPa?
The pressure inside the flattened can is 1000 kPₐ .
To solve this problem using the Ideal Gas Law formula and the given information. The terms involved in this question are pressure, volume, and the Ideal Gas Law (PV = nRT).
Here's the step-by-step explanation:
1. The initial state of the gas is given as: P₁ = 20.0 kPₐ and V₁ = 0.50 L.
2. The final state of the gas after being flattened is given as: V₂ = 0.010 L.
3. We need to find the final pressure, P₂.
4. Since the problem doesn't involve any changes in temperature or the amount of gas, we can use Boyle's Law, which is a simplified version of the Ideal Gas Law for constant temperature and amount of gas. Boyle's Law states that P₁V₁ = P₂V₂.
5. Plug in the given values: (20.0 kPₐ)(0.50 L) = P2(0.010 L).
6. Solve for P₂: P₂ = (20.0 kPₐ )(0.50 L) / 0.010 L = 1000 kPₐ .
The pressure inside the flattened can is 1000 kPₐ .
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What volume of oxygen gas at STP would be needed
to react completely with 1. 55 g of aluminum?
The volume of oxygen gas at STP that would be needed to react completely with 1.55 g of aluminum is 2.24 L.
The balanced chemical equation for the reaction of aluminum with oxygen gas is:
4Al + 3O₂ → 2Al₂O₃
From the equation, we can see that 4 moles of aluminum react with 3 moles of oxygen gas to produce 2 moles of aluminum oxide. We need to first calculate the number of moles of aluminum present in 1.55 g of aluminum:
moles of Al = mass/molar mass = 1.55 g/ 26.98 g/mol = 0.0574 mol
According to the balanced equation, 3 moles of oxygen gas react with 4 moles of aluminum. Therefore, the number of moles of oxygen gas required can be calculated as:
moles of O₂ = (3/4) * moles of Al = (3/4) * 0.0574 mol = 0.0431 mol
Finally, we can use the ideal gas law to calculate the volume of oxygen gas at STP (standard temperature and pressure, 0°C and 1 atm) that is required:
PV = nRT
where P = 1 atm, V = volume of gas, n = 0.0431 mol, R = 0.0821 L·atm/mol·K, and T = 273 K.
Solving for V, we get:
V = nRT/P = (0.0431 mol) * (0.0821 L·atm/mol·K) * (273 K) / (1 atm) = 2.24 L
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Environmental scientists can use a similar lab kit to test collected water samples from
bodies of water. In lakes and streams, calcium carbonate (CaCO3) causes alkalinity,
which allows it to function as a buffer, neutralizing any acid rain that may enter the
water supply. A buffer is a substance that serves to resist small changes in acidity or
alkalinity in a solution.
Environmental scientists monitoring pollution levels are measuring buffer levels in
two specific lakes. They found that Lake B had a greater ppm of calcium carbonate
than Lake A.
Which of the two lakes would be able to neutralize a greater amount of acid rain?
Explain your answer.
Lake B with a greater ppm of calcium carbonate would be able to neutralize a greater amount of acid rain.
Calcium carbonate (CaCO₃) acts as a buffer in lakes and streams by neutralizing any acid rain that may enter the water supply. A buffer is a substance that serves to resist small changes in acidity or alkalinity in a solution. Environmental scientists monitoring pollution levels are measuring buffer levels in two specific lakes. They found that Lake B had a greater ppm of calcium carbonate than Lake A.
Since calcium carbonate causes alkalinity, which allows it to function as a buffer, neutralizing any acid rain that may enter the water supply, Lake B would be able to neutralize a greater amount of acid rain than Lake A because it has a greater ppm of calcium carbonate.
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On your own: For further practice, click New sample. In this set, the contents of every tube is randomized. You may even find new substances you haven’t seen before. Record your observations and make hypotheses about the contents of each tube. Good luck!
You will need to observe each tube carefully and record your observations. Look at the color and consistency of the contents and note any unusual smells or other characteristics.
What is smells?Smells are the odors that people detect when certain molecules enter their noses. Smells can be pleasant, such as the aroma of a freshly baked pie, or unpleasant, such as the odor of garbage. Humans can detect millions of different smells and each smell has its own unique molecular composition. Smells can be used to identify a particular item or to trigger a memory. People can even use smells to detect potential danger, such as the smell of smoke indicating a fire. Some animals, such as dogs, have a much more acute sense of smell than humans, and can be trained to detect certain smells, such as explosives or drugs. Smells are a powerful and often overlooked sense that can be used to enhance experiences or warn of potential danger.
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Two solid chemical compounds are mixed together in a beaker. After one minute, ice crystals are observed on the outside of the beaker. What is the best description for the energy change occurring with the reaction inside the beaker?
Group of answer choices
exothermic because heat is being released to the surroundings
endothermic because heat is being released to the surroundings
exothermic because heat is being absorbed from the surroundings
endothermic because heat is being absorbed from the surroundings
The description that fits the reaction that was observed is endothermic because heat is being absorbed from the surroundings. Option D
What more should you know about endothermic reaction?Endothermic reaction stores energy. In the reaction that has occurred, heat energy was absorbed from the enviroment which makes the beaker to become cold.
Assuming it was an exothermic reaction, heat energy would have been released to the surrounding of the beaker. the beaker would have felt warm or hot to the touch,
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If re glazing do you cover what was forgotten(in the 2nd firing) or you fàreglaze everywhere
When reglazing, you cover the areas that were forgotten in the 2nd firing as well as reglaze everywhere for a uniform appearance.
Reglazing involves applying a new layer of glaze to a previously fired ceramic piece to improve its appearance, fix any issues from previous firings, or to achieve a specific effect.
In your case, if some areas were missed or improperly glazed during the 2nd firing, you would want to apply glaze to those forgotten areas to ensure a consistent finish.
However, it's important to reglaze the entire piece, not just the missed areas, to maintain a uniform appearance and avoid any inconsistencies in the final result. Before reglazing, make sure the ceramic piece is clean and free of dust or debris.
Apply the glaze evenly, using an appropriate technique such as brushing or dipping, and then fire the piece again according to the glaze's specific firing temperature and instructions. This should result in a well-glazed and visually appealing ceramic piece.
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