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What should be done to x^2 - 12x to create a perfect square?

A) add 36

B)subtract 6

C)add 6

D)subtract 36

Answer:

1/4

Step-by-step explanation:

Amplitude is equal the A part of the function which is 1/4.

Answer:

366 cm^3

Step-by-step explanation:

V = lwh

1st rectangle (L) = 3 x 6 x 15 = 270 cm^3

2nd rectangle (R) = 6 x 4 x 4 = 96 cm^3

270 + 96 = 366 cm^3

Hope this helps

Answer:

165 km²

Step-by-step explanation:

First, let us find the area of the big rectangle.

Area = length × Width

Area = 15km × 13 km

Area = 195 km²

Now, let us find the area of the small rectangle.

Area = length × width

Area = 6 km × 5 km

Area = 30 km²

And now, let us find the area of the shaded region.

For that, we have to subtract the area of the small rectangle from the area of the big rectangle.

Area = 195 km² - 30 km²

Area = 165 km²

Answer:

The answer is 70

Step-by-step explanation:

This is an inscribed angle, and acording to the inscribed angle therom, the ? is 1/2 the measure of it ark.

So divide the ark measure (140 degrees) by 2

and you get 70 as your answer

Hope this helps!! (ɔ◔‿◔)ɔ ♥

Answer:

The area of the figure is 385.5 in²

Step-by-step explanation:

The area of the figure = area of hemisphere + area of rectangle

Radius of hemisphere = 10/2 = 5 in

=> 3πr² + length × breadth

=> { 3×(3.14) × 5 × 5} + { 15 × 10 }

=> { 9.42 × 25 } + { 150 }

=> 235.5 + 150

=> 385.5 in²

The factored form of the given quadratic equation is (3x+5)(3x+2).

The given quadratic equation is:

[tex]9x^{2} +21x+10[/tex]

Any equation of the form [tex]ax^{2} +bx+c=0[/tex] is called a quadratic equation where [tex]a\neq 0[/tex].

Splitting the middle term of the given quadratic equation:

[tex]9x^{2} +15x+6x+10[/tex]

[tex]3x(3x+5)+2(3x+5)[/tex]

[tex](3x+5)(3x+2)[/tex]

So this is the factored form of the given quadratic equation.

Hence, the factored form of the given quadratic equation is (3x+5)(3x+2).

To get more about quadratic equations visit:

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Answer:

picture of answer.

Step-by-step explanation:

Answer:

dont anwer it

Step-by-step explanation:

its realy harder than mine

Answer:

Negative 1 and three-fifths meters

Answer:

-2

Step-by-step explanation:

plug in -1

The estimated difference of the area of Colorado and Wyoming in scienfic notation is  2 x [tex]10^{-1}[/tex]m².

Scienfic notation is used in expressing large numbers in smaller numbers. In order to write a number in stscienfic notation, the number is written as a decimal number, between 1 and 10 and multiplied by a power of 10.

Area of Colorado = (6.12 x [tex]10^{5}[/tex]) x (4.5 x [tex]10^{5}[/tex]) = 27.54 x [tex]10^{10}[/tex]

= 2.8 x [tex]10^{11}[/tex]m²

Difference in the areas = 2.8 x [tex]10^{11}[/tex]m² - 2.6 x x [tex]10^{11}[/tex]m² = 0.2m²

= 2 x [tex]10^{-1}[/tex]m²

To learn more about scienfic notation, please check: https://brainly.com/question/25334755

Based on the fact that the distance driven is proportional to the gallons used, the missing figure is 8 gallons.

The question is incomplete so I will use a similar question to explain the concept.

If the number of miles driven is proportional to the number of gallons used then you can find the number of miles driven per gallon as:

= Number of miles driven / Number of gallons used

= 112 / 4

= 28 miles per gallon

You can also use other entries in the table to get the same answer:

= 280 / 10 gallons

= 28 miles per gallon

If 224 miles have been driven, the number of gallons used would therefore be:

= Number of miles driven / Miles per gallon

= 224 / 28

= 8 gallons

Find out more on proportionality rules at https://brainly.com/question/870035.

Answer:

39

Step-by-step explanation:

Let h: hit

Let n: not hit

1) We can create two equations and solve them simultaneously using the substitution method or elimination.

h + n = 100

12h - 4n = 224

2) Solve them. I will demonstrate using the substitution method.

n = 100 - h

-----------------------

12h - 4(100 - h) = 224

12h - 400 + 4h = 224

16h = 224 + 400

16h = 624

h = 624/16

h = 39

3) Substitute the result into one of the equations above.

n = 100 - 39

n = 61

Since the question wants you to write the number of times the dragon was hit, the answer is 39.

3/24 (actually you have 25 marbles but we took 24 marbles since 1 has already been taken and then replaced , which means that it's not put back in the bag)

3/24 = 1/8

hope it helps...!!!

Answer:

16.76 ft³

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Set up the system of equations for volume. We'll use V for volume, and h for height.

[tex]V = \pi r^2 \frac{h}{3}[/tex]

Now, turn the equations into a multiplication problem, use 2 for radius, and 4 for height.

[tex]\pi * 2 * \frac{4}{3}[/tex]

Next, calculate.

[tex]\pi *2^2 = 12.5663706144...\\\frac{4}{3} = 1.3333333...\\\\12.566 * 1.333 = 16.75048(rough~estimate)[/tex]

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Ask in comments.

Answer:

A frequency distribution is a table that shows “classes” or “intervals” of data entries with a count of the number of entries in each class.

Step-by-step explanation:

hope this helps you a little!

Answer:

f(x) = -5(x+1)(x-5)

Step-by-step explanation:

Because the x-axis of the arch is 1 and -5 and it couldn't be -1/5 because the y-axis doesn't show that.

Answer:

y=6x+4

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Inverse is opposite. So, domain becomes range and range becomes domain

x<2 of domain becomes y<2 for range

y>0 of range becomes x>0 of domain

Answer:

4(1+7x)

Step-by-step explanation:

There are 2 terms in this expression: Factorize them

4: 2 * 2

28x: 2 * 2 * 7 * [tex]x[/tex]

Which factors do both of the terms have in common?

2 and 2, which means that the GCF is 4.

Now to figure out whats inside the parentheses.

What number multiplied by 4 gives 4? 1

What number multiplied by 28x gives 4? 7x

So the final result is 4(1+7x)

The options have not been given but three correct alternatives have been presented as the solution.

We have given,

[tex]\frac{c^2-4}{c+3} /\frac{c+2}{3(c^2-9)}[/tex]

Applying the rule a^2-b^2 to the numerator of the first term and the denominator of the second term,

[tex](a^2-b^2)=(a-b)(a+b)[/tex]

By applying the above formula we have:

[tex]=\frac{c^2-2^2}{c+3} /\frac{c+2}{3((c+3)(c-3)}[/tex]

[tex]=\frac{(c-2)(c+2)}{c+3} /\frac{c+2}{3((c+3)(c-3)}[/tex]

Therefore the solution is,

[tex]=(c-2) \times 3(c-3)\\\\=3(c^2-5c+6)\\\\=3c^2-15c+18[/tex]

To learn more about the expression visit:

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Answer:

C.) StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction 3 (c squared minus 9) Over c + 2 EndFraction"/>

Step-by-step explanation:

Which expression is equivalent to StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction c + 2 Over 3 (c squared minus 9) EndFraction?

StartFraction c + 3 Over c squared minus 4 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction 3 (c squared minus 9) Over c + 2 EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction 3 (c squared minus 9) Over c + 2 EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction

Your answer is (3,1)

Yw and pls mark me brainiest

Answer:

D. 6(x+2y)-y

Step-by-step explanation:

Both expressions can be simplified into 6x + 11y

3(2x+4y)-y
6x + 12y - y
6x + 11y

6(x+2y)-y
6x + 12y - y
6x + 11y

Answer:

D. 6(x+2y)-y

Step-by-step explanation:

To solve for the equivilent expression, begin by simplifying the given expression. (1) To simplify 3(2x+4y)-y, you can first multiply 3 into the parentheses then combine like terms; (6x+12y)-y or 6x + 12y - y --> 6x + 11y. (2) Solve to find which expression listed will yield the same product, 6x + 11y, when simplified as well. This is quiet straightfoward to see and you wont be needing to solve each individual problem. 6(x+2y)-y will simplify to 6x + 12y - y which is then equal to --> 6x + 11y. Meaning, D. 6(x+2y)-y is equvillent to 3(2x+4y)-y.

Answer:

bracelets : necklaces

9 : 11  

Answer:

870.

Step-by-step explanation:

There are 30 choices of representatives. This leaves 29 choices for alternate representatives.

If one person gets elected for representative, there are 29 choices for an alternate representative.

This is the case if any of the 30 students get elected as representatives.

That means you can set it up as:

x*y where x is the choice of representatives and y is the choice of alternate representatives.

30 * 29, or 870.

Here is a visual example. Students a - dd are shown here.

a b c d e f g h i j k l m n o p q r s t u v w x y z aa bb cc dd

In this case, a has been chosen as class president. Any of the other 29 students could be a alternate, and then paired with a. This makes 29 total possible pairings. This is then repeated for the possibility of every student becoming a president, which creates 30*29.

Please tell me if this is wrong, I will try to make changes!

Answer:

Problem 4: Dog pens 2 and 3

Problem 5: Dog Pens 1 and 2

Problem 6: 6cm and 6cm

problem 7: A

Step-by-step explanation:

Answer:

14.3

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2   where a and b are the legs and c is the hypotenuse

14^2 + 3^2 = c^2

196 + 9 = c^2

205 = c^2

Take the square root of each side

sqrt(205) = sqrt(c^2)

14.31782106 = c

Rounding to the nearest tenth

14.3 = c

Answer :

⠀

Explanation :

⠀

Solution :

where,

We know that,

[tex]{\longrightarrow \pmb{\mathbb {\qquad (XZ) {}^{2} = (XY) {}^{2} +( YZ) {}^{2} }}} \\ \\ [/tex]

Now, we will substitute the given values in the formula :

[tex]{\longrightarrow \sf{\pmb {\qquad (XZ) {}^{2} = (3) {}^{2} +( 14) {}^{2} }}} \\ \\ [/tex]

We know that, (3)² = 9 and (14)² = 196. So,

[tex]{\longrightarrow \sf{\pmb {\qquad (XZ) {}^{2} = 9 +196 }}} \\ \\ [/tex]

Now, adding 9 and 196 we get :

[tex]{\longrightarrow \sf{\pmb {\qquad (XZ) {}^{2} = 205 }}} \\ \\ [/tex]

Now, we'll take the square root of both sides to remove the square from XZ :

[tex]{\longrightarrow \sf{\pmb {\qquad \sqrt{(XZ) {}^{2}} = \sqrt{205 }}}} \\ \\ [/tex]

When we take the square root of (XZ)² , it becomes XZ,

[tex]{\longrightarrow \sf{\pmb {\qquad XZ = \sqrt{205 }}}} \\ \\ [/tex]

We know that, square root of 205 is 14.317 (approx) .

[tex]{\longrightarrow { \mathbb{\pmb {\qquad XZ }}}} \approx \pmb{\mathfrak{14.317 } }\\ \\ [/tex]

So,