3.5 divided by 0.375 with solution.

Answer:

40 so C would be your answer.

The third quartile of the data set is 38.

Quartiles are statistical measures that divide a dataset into four equal parts, each representing 25% of the data. They are used to analyze the distribution and spread of data.

There are three quartiles: the first quartile (Q1), the second quartile (Q2), and the third quartile (Q3).

To find the third quartile of a data set, we need to arrange the data in ascending order and then locate the value that divides the upper 25% of the data from the lower 75%.

Arranging the data set in ascending order:

14, 18, 20, 21, 25, 32, 38, 42, 48

The data set has 9 values, so the third quartile will be the value at the

(9 0.75)th position

= 6.75th position.

Since we can't have a fractional position, we round up to the nearest whole number, which is 7.

The value at the 7th position is 38. Therefore, the third quartile of the data set is 38.

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Answer:

D

Step-by-step explanation:

It goes 2 down. The ' mark shows that it is the new one

Answer:

See below

Step-by-step explanation:

Inscribed angles encompass twice as many degrees of arc as their angle measure

 soo    2* {   6x-5   +  x+17 } = 360

             shows x = 24      then ROP = x+17 = 41 degrees

Answer:

Step-by-step explanation:

Total number of days

The number of days she bought a banana or orange

The probability of buying a banana or an orange is

Answer:

[tex]\sf \dfrac{7}{10}=0.7=70\%[/tex]

Step-by-step explanation:

Given information:

Total number of days = 30

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Probability of buying a banana:

[tex]\implies \sf P(Banana)=\dfrac{12}{30}[/tex]

Probability of buying an orange:

[tex]\implies \sf P(Orange)=\dfrac{9}{30}[/tex]

Therefore,

[tex]\implies \sf P(Banana) \: or \: P(Orange)=\sf \dfrac{12}{30}+\dfrac{9}{30}=\dfrac{21}{30}=\dfrac{7}{10}[/tex]

So the probability of buying either a banana or an orange is:

  [tex]\sf \dfrac{7}{10}=0.7=70\%[/tex]

Answer:

The answer is B.

Step-by-step explanation:

4x-7 = 2x+9

2x = 16

x = 8

And then we put x into the equations.

y = 32 - 7

y = 25

We then check it with the other equation just to make sure we are correct.

y = 16 +9

y = 25

Therefore, the answer is (8,25).

Answer:

x = 12.5

Step-by-step explanation:

17 = 2(x - 4)

17 = 2x - 8

17 + 8 = 2x - 8 + 8

25 = 2x

12.5 = x

Answer:

Circumference = 25.14 cm

Area = 50.28 cm²

Step-by-step explanation:

∴ Circumference = 2πr

⇒C = (2) (22/7) (4)

⇒C = 25.14 cm

∴ Area = πr²

⇒A = (22/7) (4)²

⇒A = 50.28 cm²

Hope that helps...

Answer:

(2x + y)(2x - y)

Step-by-step explanation:

1. Simplify the square 4x²:

(2x)² - y²

2. Apple the difference of two squares formula x² - y² = (x + y)(x - y):

(2x + y)(2x - y)

hope this helps!

Answer:

A = 120 cm^2

Step-by-step explanation:

The formula for surface area of a rectangular prism is:

A = 2(area of the top) + 2(area of the front) + 2(area of one side)

Substituting the values:

A = 2(20) + 2(16) + 2(24)

First, distributing:

A = 40 + 32 + 48

Then adding, giving your final answer

A = 120 cm^2

Hope this helps you :)

Answer:

3

Step-by-step explanation:

0.1 rounds to 0 and 0.04 also rounds to zero. Therefore, the answer is 3.

Newton's Law of Gravitation:

Statement: According to this law, when two mass bodies are separated at finite distance then there must be an attractive force experience by them which is directly proportional to the product of their masses and inversely proportional to the square of their separation.

Consider two mass bodies m1 & m2 be kept at distance d. Then the force of attraction F is given as

                            [tex]Fam_{1}.m_{2}[/tex]

                                 [tex]Fa1/d^2[/tex]

Now, from above equations, we have

                          [tex]Fa\frac{m_{1}m_{2}}{d^2}[/tex]

or,                           [tex]F=G\frac{m_{1}m_{2}}{d^2}[/tex]

Here         [tex]G=6.67*10^{-11}Mm^2kg^{-2}[/tex]   is the universal gravitational constant.

Answer:

It depends on how many students there are in Mr. Edwards class

Step-by-step explanation:

The number or amount of ounces of the 75% tangy mustard sauce must the chef have used is: 20 ounces .

First step

Since 5 ounce sauce containing 50% tangy

Hence:

5 oz×.50 tangy

=2.50 oz-tangy

Second step

(5+x)×0.7=3.5+0.7x

Third step

2.50+0.75x=3.5+0.7x

Collect like term

0.75x-0.7x=3.5-2.50

0.05x=1

Divide both side by 0.05

x=1/0.05

x=20 ounces

Therefore the number of ounces of the 75% tangy mustard sauce must the chef have used is: 20 ounces .

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Answer: C

Step-by-step explanation:

The 36 degree angle is inscribed in the unknown arc, so the arc measures 36(2)=72 degrees.

Answer: 3.6

Step-by-step explanation:

Answer:

Hello there! 10 square of 3

Answer:

3,000 numbers.

Step-by-step explanation:

First digit: 2, 3, 5, or 7 (primes)

Second digit: 0, 1, 2, 3, or 4 (less than 5)

Third digit: 0-9

Fourth digit: 0, 1, or 8 (cubic numbers)

Fifth digit: 1, 3, 5, 7, or 9 (odd numbers)

So we have 4 * 5 * 10 * 3 * 5 = 3,000 possible numbers.

Answer:

-125

Step-by-step explanation:

Twice a number is x*2

x*2 = 500 + x*6

=> x = -125

5m long ladder placed against 4.3m up the wall.

the angle between the ladder and the ground.

Based on the given conditions, formulate: 

sin⁡x=4.3÷5

Evaluate the equation/expression:

x= 1.03527 or 2.10632

x= 1.03527°

or x= 2.10632°

The length of the hypotenuse AB is equal to the sum of the square of other two sides AC and BC. The measure of the curve DE is 10.5 units

The theorem states that the length of the hypotenuse AB is equal to the sum of the square of other two sides AC and BC.

According to the theorem;

AB^2 = AC^2 + BC^2

AB^2 = 6^2 + 8^2

AB^2 = 36 + 64

AB = 10

If the curve DE is 5% longer than line segment АВ, the measure of curve DE is given as;

DE = 1.05 * 10
DE = 10.5

Hence the measure of the curve DE is 10.5 units

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Answer:

option D is a correct answer AA postulate

The two triangles are similar by the AA postulate

If two triangles' corresponding angles are congruent and their corresponding sides are proportional, they are said to be similar triangles. In other words, similar triangles have the same shape but may or may not be the same size. The triangles are congruent if their corresponding sides are also of identical length.

Corresponding sides of similar triangles are in the same ratio. The ratio of area of similar triangles is the same as the ratio of the square of any pair of their corresponding sides

Given data ,

Let the first triangle be ΔEFG

Let the second triangle be ΔHJK

Now , the corresponding angles are

∠E = 25° = ∠H

So , the two angles are similar

And , the triangles are similar by the AA postulate

Hence , they are similar triangles

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Answer:

Sum of diagonals = 20 units

Step-by-step explanation:

[tex]A(rectangle)=25\sqrt 3\: units^2\\w(rectangle) =5\: units[/tex]

To find: Sum of diagonals

[tex]A(rectangle)=l(rectangle)\times w(rectangle) [/tex]

[tex]\implies l(rectangle)=\frac{A(rectangle)}{w(rectangle)}[/tex]

[tex]\implies l(rectangle)=\frac{25\sqrt 3}{5}[/tex]

[tex]\implies l(rectangle)={5\sqrt 3}\: units[/tex]

Let the diagonals of the rectangle be [tex]d_1\:\&\:d_2\: units[/tex]

Diagonals of a rectangle are equal in measure.

[tex]\implies d_1=d_2=\sqrt{l(rectangle)^2+w(rectangle)^2}[/tex]

(By Pythagoras Theorem)

[tex]\implies d_1=d_2=\sqrt{(5\sqrt 3)^2+(5)^2}[/tex]

[tex]\implies d_1=d_2=\sqrt{75+25}[/tex]

[tex]\implies d_1=d_2=\sqrt{100}[/tex]

[tex]\implies d_1=d_2=10\: units[/tex]

[tex]Sum \:of \:diagonals = d_1+d_2[/tex]

[tex]\implies Sum \:of \:diagonals = 10+10[/tex]

[tex]\implies Sum \:of \:diagonals = 20\: units[/tex]

Answer:

Step-by-step explanation:

44/2 is 22

84/3 is 28

Patrick Mahomes can throw more yards/sec

Answer:

Step-by-step explanation:

Given:

Isolate the term of y from one side of the equation.

(3y+2)(y-1)

Use the foil method.

[tex]\underline{\text{FOIL METHOD:}}[/tex]

[tex]\Longrightarrow: \sf{\left(A+B\right)\left(C+D\right)=AC+AD+BC+BD}[/tex]

(3y+2)(y-1)=3yy+3y(-1)+2y+2(-1)

Solve.

[tex]\sf{3yy=3y^2}\\\\\\\sf{3y(-1)=-3y}\\\\\\\sf{2(-1)=-2}[/tex]

[tex]\sf{3y^2-3y+2y-2}[/tex]

Add or subtract the numbers from left to right.

Solutions:

[tex]\sf{-3y+2y=-y}[/tex]

[tex]\Longrightarrow: \boxed{\sf{3y^2-y-2}}[/tex]

I hope this helps. Let me know if you have any questions.

Answer:

3y^2-y-2

Step-by-step explanation:

(3y+2)(y–1)

Use the FOIL method

First 3y * y = 3y^2

outer  3y * -1 = -3y

inner  2 * y = 2y

last  2 * -1 = -2

Add them together

3y^2 -3y +2y -2

Combine like term

3y^2-y-2