4. A student has 500 identical, rectangular sheets of paper. The mass of 1.0m² of the paper is 0.080 kg. (2) Using a metre rule, she measures the length of one sheet of paper and its width. The length is 0.300 m and the width is 0.210m. (1) Calculate the mass of one sheet of paper.​

So long as the distance from the wall is small compared to the width and height of the wall, the distance does not affect the field.

Density, the mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre. For example, the density of water is 1 gram per cubic centimetre, and Earth’s density is 5.51 grams per cubic centimetre. Density can also be expressed as kilograms per cubic metre (in metre-kilogram-second or SI units).

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The magnitude of the acceleration of the robot is 1m/s^2 .

Given ,

A toy doll and a toy robot are standing on a frictionless surface facing each other .

The mass of the doll = 0.20kg

The mass of the robot = 0.30kg

Force applied by the robot on the doll = 0.30N

We know the force and mass of the robot , so from this we can calculate the acceleration by applying Newton's laws of motion ,

Thus , F= ma

a = F/m = 0.30N / 0.30k

a = 1 m/s^2

Hence , the magnitude of the acceleration of the robot is 1m/s^2 .

Acceleration is the rate of change in velocity.

Positive acceleration it occurs when an object speeds up. Negative acceleration it occurs when an object slows down.

Acceleration is a change of velocity over a period of time, expressed by the equation,

A=Δv/t

The unit of acceleration is m/s^2.

The dimensional formula of acceleration is [M^0 L^1 T^-2] .

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Answer:

0.9964

Explanation:

I think that's the right answer but here you go always!

The ball will leave the ground with the velocity of 4.5 m/s.

Velocity is the distance travelled in a specific direction per time taken. It is measured in m/s

Given that a tennis ball is dropped from 1.98 m above the ground. It rebounds to a height of 1.05 m. The acceleration of gravity is 9.8 m/s².

Using the formula

v² = u² - 2gH

0 = u² - 2 × 9.8 × 1.05

u² = 20.58

u = √20.58

u = 4.54 m/s

Therefore, the ball will leave the ground with the velocity of 4.5 m/s.

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If a cook puts 9.00g of water in a 2.00 -L pressure cooker that is then warmed to 500°C, the pressure inside the container is 15.8 atm.

From the ideal gas law;

PV = nRT

Where P is pressure, V is volume, n is amount of substance, T is temperature and R is the ideal gas constant (0.08206Latm/molK).

Given the data in the question;

First we determine the amount of water n.

We know that the molar mass of water is 18.01528 g/mol.

Hence

n = mass / molar mass

n = 9.00g / 18.01528 g/mol

n = 0.4995mol

Now, plug the values into the equation above and solve for P

PV = nRT

P = nRT / V

P = ( 0.4995mol × 0.08206Latm/molK × 773.15K ) / 2.00L

P = ( 31.6906Latm ) / 2.00L

P = 15.8 atm

If a cook puts 9.00g of water in a 2.00 -L pressure cooker that is then warmed to 500°C, the pressure inside the container is 15.8 atm.

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Gravity is the non contact force.

Gravity is a fundamental interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between things and governs the motion of planets, stars, galaxies, and even light.

On Earth, gravitational pull lends weight to tangible objects, and the moon's gravitational pull generates ocean tides. In addition, gravity plays a significant role in many biological processes, including gravitropism, which directs plant growth, and the movement of fluids in multicellular organisms. Gravity may affect how the immune system and cells differentiate in the human body, according to research on the effects of weightlessness.

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The period of motion is given as  ​π/2(√md³/KeqQ)

What is Coulombs law?

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.

The period of motion from the instance given  ​π/2(√md³/KeqQ).

w²= (2π/T)²

T=2π/w

where w is gotten as 16KeqQ/md³

T=  ​π/2(√md³/KeqQ).

m is the mass of the body with charge-Q

In conclusion, the Coulomb's law equation provides an accurate description of the force between two objects whenever the objects act as point charges.

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Electron and proton have rest energy which is option (a) and (c) .

According to Einstein's quantum theory light propagates in the form of packets i.e. quanta of energy, which is called photon.

The rest mass of photons is being zero. So photos do not have rest energy they are never at rest .

As electrons and protons posses mass , therefore they have rest energy which is given by [tex]E=mc^2[/tex] .

Hence , only electron and proton have rest energy not photon.

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Answer:

2.08 m  (2 d.p.)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

-------------------------------------------------------------------------------------

When a body is projected through the air with initial speed (u), at an angle of θ to the horizontal, it will move along a curved path.

Therefore, trigonometry can be used to resolve the body's initial velocity into its vertical and horizontal components:

Since the projectile is modeled as moving only under the influence of gravity, the only acceleration the projectile will experience will be acceleration due to gravity.

If the ball is kicked at an initial velocity of 20 m/s from flat ground at an angle of 45.9° then:

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

[tex]s=35 \quad u=20 \cos 45.9^{\circ} \quad v = 20 \cos 45.9^{\circ} \quad a=0[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=\left(\dfrac{u+v}{2}\right)t\\\\35&=\left(\dfrac{20 \cos 45.9^{\circ}+20 \cos 45.9^{\circ}}{2}\right)t\\35&=(20 \cos 45.9^{\circ})t\\t&=\dfrac{35}{20 \cos 45.9^{\circ}}\\\implies t&=2.51468288...\; \sf s\end{aligned}[/tex]

Therefore, the time is takes for the ball to reach the crossbar is 2.51 s.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↑ as positive:

[tex]u=20 \sin 45.9^{\circ} \quad a=-9.8 \quad t=2.51468288...[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(20 \sin 45.9^{\circ})(2.51468288...)+\dfrac{1}{2}(-9.8)(2.51468288...)^2\\s&=36.1171982...-30.9857870...\\\implies s&=5.131411132...\; \sf m\end{aligned}[/tex]

To find by how much the ball clears the crossbar, subtract the height of the crossbar (3.05 m) from found the vertical height of the ball at 2.51 s:

[tex]\implies 5.13141132...-3.05=2.08\; \sf m\;(2 \: d.p.)[/tex]

Therefore, the ball clears the crossbar by 2.08 m (2 d.p.).

The time spent in air by the tuna before it hits the ground is determined as 1.375 seconds.

The time spent in air by an object or a projectile is the total time of motion of the object or projectile.

The time spent in air by the tuna can be determined by finding equation of the final velocity of the tuna when it hits the ground as follows;

h = 16t² + ut

where;

Velocity of the tuna when it hits the ground,

v = dh/dt

dh/dt = 32t + u

when the tuna hits the ground, final velocity = 0

0 = 32t + u

0 = 32t + 44

t = -44/32

|t| = 1.375 seconds

Thus, the time spent in air by the tuna before it hits the ground is determined as 1.375 seconds.

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The height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

The time of motion of cat A is calculated as follows;

h = vt - ¹/₂gt

-23 = 7t - 4.9t²

4.9t² - 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = -7, c = - 23

t = 3.0 seconds

The time of motion of cat B is calculated as follows;

h = vt - ¹/₂gt

23 = 7t + 4.9t²

4.9t² + 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 7, c = -23

t = 1.57 seconds

h = u²/2g

h = (7²)/(2 x 9.8)

h = 2.5 m

v = u + gt

v = 7  + 3(9.8)

v = 36.4 m/s

v = u + gt

v = 7  + 1.57(9.8)

v = 22.39 m/s

Time difference = 3 s - 1.57 s = 1.43 seconds

Thus, the height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

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The velocity of a baseball thrown across a field is (V)= 10m/s

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled.

To calculate the velocity we are using the formula here,

V= S/t

Here we are given,

S= a distance of a baseball thrown= 40m

t= time to travel the distance = 4 seconds.

Now we put the values in the above equation, we get

V= S/t

Or, V = 40/4

Or, V= 10m/s

So, from the above calculation we can conclude that, the velocity of a baseball thrown across a field is (V)= 10m/s

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The acceleration of the bullet leaving the barrel is 2.25 x 10⁵ m/s².

Given,

Velocity of the bullet leaving the barrel, v = 600 m/s

Distance travelled by the bullet = Size of the rifle = s = 0.800 m

According the Third Equation of Motion which relates velocity with the distance and acceleration says that,

v² = u² + 2as ;

where 'v' and 'u' are final and initial velocity of the bullet respectively

'a' is the acceleration of the bullet

's' is the distance travelled by the bullet

here u = 0 m/s

(600)² = 0² + 2 * (0.800) * (a)

360000 = (1.6) * (a)

a = [tex]\frac{360000}{1.6}[/tex]

a = 225000 m/s²

a = 2.25 x 10⁵ m/s²

Therefore the rate at which bullet accelerated while being in the barrel is 2.25 x 10⁵ m/s².

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Answer:

*I think you meant seconds

45 min = 2,700 sec

Explanation:

Hope it helps!!!

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E. The magnitude of the average emf induced in the loop is 0.20 mV.

The magnitude of the average emf induced in the loop is calculated as follows;

emf = NA(B₁ - B₂)/t

where;

A = πr² = π(0.04)² = 5.027 x 10⁻³ m²

emf = (1)(5.027 x 10⁻³)(0.06 - 0.04)/0.5

emf = 2.01 x 10⁻⁴ V

emf = 0.201 mV

Thus, the magnitude of the average emf induced in the loop is 0.20 mV.

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Answer:

380 to 700 nanometers

Brainliest please

Explanation:

Excess charge on an isolated conductor must reside on its surface because excess charge moves away until they reach the surface of the body.

Charged conductors in electrostatic equilibrium exhibit a number of interesting properties. The electric field beneath the surface of a charged conductor is zero when it is in electrostatic equilibrium, which is one of its properties. The repulsive nature of force between similar charges and the liberty of motion of charges within a conductor allows for the establishment of equilibrium within charges present in the conductor. Due to this fact, excess charges carry like type of charge as contained within the conductor they are thus repelled away from the conductor till they reach the outer surface of the conductor.

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The entire battery should be charged, as a battery being tested has five cells testing normal and one cell showing very low, so option B is correct.

A battery is a component that turns chemical energy into electrical energy and stores it. This process is called electrochemistry, and the structure that supports a battery is referred to as an electrochemical cell. One or more electrochemical cells can be used to create a battery, as in Volta's original pile. Two electrodes and an electrolyte are the main components of an electrochemical cell.

Some popular batteries are only intended for one usage (known as primary or disposable batteries). The electrons only travel in one direction from the anode to the cathode. Either the buildup of reaction products on the electrodes prevents the reaction from continuing, or their electrodes get depleted as they release their positive or negative ions into the electrolyte, and it is finished. The battery is eventually disposed of (or, ideally, recycled; however, that is a whole different Nova topic).

Therefore, the entire battery should be charged, as a battery being tested has five cells testing normal and one cell showing very low.

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You wish to start a fire by reflecting sunlight from a mirror onto some paper under a pile of wood which means the best choice of the type of mirror for this operation is a concave one and is denoted as option B.

This type of mirror usually has a reflective surface that is curved inward and away from the light source. They also reflect light inward to one focal point which is done by reflecting all the rays parallel to its axis and converge them at a single point.

For fire to occur, then we need a large concentration of light rays which will help reflect all the sunlight from a mirror onto some paper under a pile of wood thereby causing the fire.

This is therefore the reason why concave mirror was chosen as the most appropriate choice.

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The player would continue in the same direction unless a force acts on the player.

The Newton's first law of motion states that an object will continue in its state of rest or uniform motion unless it is acted upon by an external force. This external force tries either make the object to move or to change its direction of motion accordingly.

Having said this, for a player that is running in the field with the ball, the player would continue in the same direction unless a force acts on the player such as when the player is pushed by another player.

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According to Gauss law,  the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.

Gauss law is defined mathematically in Equation 1

Φ=Q ϵo               (1)

Where;

Q is enclosed charge

ϵo is the permittivity of the free space

According to the above gaussian relation, If the charge is doubled, then flux will also be doubled. This is because there is a direct relationship between the total flux and charge present in the electric field. This means that the net electric flux is dependent on the charge moving through the surface of the cube.

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It makes sense for the valence electrons to stay the same within a group because these elements have same chemical properties.

We have a group from Periodic table.

We have to investigate the reason behind the fact that why elements with same number of valence electrons share the same group.

Periodic Table is a table of the chemical elements arranged in order of atomic number, usually in rows, so that elements with similar atomic structure (similar chemical properties) appear in vertical columns.

According to the question -

It is true that the number of valence electrons in the outermost shell of the elements of same group are equal. The number of valence electrons in the outermost orbit of the elements of the same group is same as the group number to which they belong. The elements in the same group have same number of valence electrons in their outermost shell. Due to this the elements have almost same Physical properties, Chemical properties and Reactivities of the elements.

Hence, it makes sense for the valence electrons to stay the same within a group because the elements in the same group have same properties.

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The forces acting on the baseball are air resistance, and force of gravity.

The forces which act on an object moving upward will either oppose the motion of the object or help to speed up the object.

The forces present during upward motion include;

The forces acting on a baseball thrown upwards which also travels rightward include the following;

Thus, the forces acting on the baseball are air resistance, and force of gravity.

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The complete question is below:

Consider this situation: A baseball travels upward and

rightward through the air. Of the forces listed, identify which

act upon the baseball. (force of air resistance, force of gravity, weight of the ball, frictional force).

The ratio of their time period is 1 : 2 : 2.

The momentum of a proton, a deuteron, and an alpha particle is the same in a uniform magnetic field.

The charge of a proton is q = e and the let m(p) be the mass of the proton.

Let m(d) = 2m(p) be the mass of the deuteron and the charge of a deuteron is q =e.

Now, an alpha particle is made up of 4 protons. Therefore the mass of an alpha particle is 4m(p) and the charge on an alpha particle is q = 2e.

The formula for the time period of a moving particle in a uniform magnetic field is given as:

[tex]T = \frac2 \pi m}{qB}[/tex] where B is the magnetic field, m is the mass and q is the charge of the particle.

So, the time period of a proton is:

[tex]T_{1} = \frac{2 \pi m(p)}{eB}[/tex]

The time period of a deuteron is:

[tex]T_{2} = \frac{2 \pi (2m(p))}{eB}[/tex]

And the time period of an alpha particle is:

[tex]T_{3} = \frac{2 \pi ( 4m(p) )}{2eB}[/tex]

Therefore, the ratio is:

[tex]T_{1}: T_{2} : T_{3} =\frac{2 \pi m(p)}{eB} : \frac{2 \pi 2m(p)}{eB} : \frac{2 \pi (4m(p))}{2eB}[/tex]

T₁ : T₂ : T₃ =  1 : 2 : 2

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Hi! Scientists use models for a lot of reasons. Primarily to study objects in detail that they wouldn't be able to normally. For example, to study something small like a cell, making a model could be easier. Also, things that are too dangerous to study in real life can be turned into models as well.

To put it shortly, scientists use models to observe things in better detail.

I can include a link to a website if that will help :)

https://study.com/academy/lesson/why-scientists-use-models-simulations.html

Good luck!

About 1.3 seconds the light takes to reach from the moon to the earth.

We know that the closest object to our earth is the Moon. Its distance from the earth is about 240,000 miles, so light from the Moon takes 1 and 1/3 seconds to get from the Moon to Earth while on the other hand, sun is  almost 400 times farther from earth as compared to the moon so the light reaches from sun is about 8 minutes 30 seconds.

So we can conclude that about 1.3 seconds the light takes to reach from the moon to the earth.

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The mobility of the light source depends on the interaction between the magnetic and electric forces.

Cathode ray refers to the electron beam that moves from the negatively charged cathode to the positively charged anode at the other end of the vacuum tube.

J. J. Thomson demonstrated that the identical beam deflections produced tubes with cathodes composed of varied materials and containing a range of gases prior to evacuation.

This discovery is significant because the interaction of the magnetic and electric forces determines the mobility of the light source.

Therefore, the interaction of the magnetic and electric forces determines how mobile the light source is.

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answer:

Use this equation (v=Δx/t); plug in velocity (0.500 m/s) and the time (2.4 s), then solve for displacement… (Δx=1.2 m)

If a coin is rolled in a straight line along a balcony edge at a steady speed of 0.46 m / s , then the distance traveled by this coin in 2.4 seconds would be 1.104 meters.

There are three equations of motion given by Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem If a coin is rolled in a straight line along a balcony edge at a steady speed of 0.46 m / s ,

The distance traveled by the coin = 0.46 × 2.4

                                                         =1.104 meters per second

For another coin , by using the first equation of motion ,

v = u + a × t

78.8 = 0 + a × 8.0

a = 78.8 / 8.0

a = 9.85 m / s²

Thus,  the distance traveled by this coin in 2.4 seconds would be 1.104 meters .

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When approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately 25 feet.

Tetraethyl lead, which is present in gasoline, deposits itself on the turbine blades. Because jet fuel has a higher viscosity than aviation gasoline, it may retain impurities with greater ease.

Once the gasoline charge has been cleared, start the engine manually or with an electric starter while cutting the ignition and using the maximum throttle.

On the final approach, the aeroplane needs to be re-trimmed to account for the altered aerodynamic forces. A substantial nose-down tendency results from the airflow producing less lift on the wings and less downward force on the horizontal stabiliser due to the reduced power and slower velocity.

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