The stored energy from all the lightning strikes during the thunderstorm would only be able to supply a city for 0.000675 seconds at the same rate as a large power plant.
The energy delivered by a lightning strike can be calculated using the formula E = VQ, where E is the energy, V is the voltage, and Q is the charge. Therefore, the energy delivered by a lightning strike is:
E = (-75 x 10⁻³V) x (-25 C) = 1.875 J
The total energy delivered by lightning strikes during the thunderstorm can be calculated by multiplying the energy delivered by each strike by the number of strikes, which is 3600/10 = 360.
Therefore, the total energy delivered by lightning strikes during the thunderstorm is:
E_total = 1.875 J/strike x 360 strikes = 675 J
Assuming that all of this energy can be captured and stored, it can supply a city for a certain amount of time. The time that the stored energy can supply the city can be calculated using the formula T = E/P, where T is the time, E is the energy, and P is the power.
Therefore, the time that the stored energy can supply a city is:
T = 675 J / 1,000 MW = 0.000675 s
As a result, the accumulated energy from all of the lightning strikes throughout the thunderstorm could only power a city for 0.000675 seconds at the same rate as a huge power plant.
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he charge carriers continue to separate until the magnetic force exactly balances the electric force generated by the newly created electric field. at this equilibrium condition, what is the strength of the electric field e ?
The strength of the electric field e at the equilibrium condition can be calculated using the equation e = vB, where v is the velocity of the charge carriers and B is the strength of the magnetic field.
When charge carriers move through a magnetic field, they experience a force given by the equation F = qvB, where q is the charge on the carriers, v is their velocity, and B is the strength of the magnetic field.
As a result of this force, the charge carriers move in a circular path. However, as they move, they create an electric field in the direction opposite to their motion, which tries to separate them. This electric field generates an electric force given by the equation F = qE, where E is the strength of the electric field.
The charge carriers continue to separate until the magnetic force exactly balances the electric force. At this equilibrium condition, we have: F = F qE = qvB Solving for E, we get: E = vB.
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A capillary tube 2mm in diameter is immersed in a beaker a
ercury. The mecury level inside the tube is found to be ose
on the level of the resenon- Determine the contact angre bet
the mecury and the glass (Tm = 0. 4 Nlm, Pm= 13. 6x1
Soln
The contact angle between the mercury and the glass is 32.2 degrees. In the case of a glass capillary of diameter nil, the contact angle would depend on the specific glass material and its surface properties.
To determine the contact angle between the mercury and the glass, we can use the Young-Laplace equation:
[tex]\Delta P = Tm(1/R1 + 1/R2)cos\theta[/tex]
where ΔP is the pressure difference between the inside and outside of the capillary, Tm is the surface tension of mercury, R1 and R2 are the radii of curvature of the mercury meniscus at the top and bottom of the capillary, respectively, and θ is the contact angle.
Assuming that the mercury meniscus is approximately spherical at the top and bottom of the capillary, we can use R1 = R2 = r, where r is the radius of the capillary. Then, the equation becomes:
[tex]\Delta P = 2Tm/r cos\theta[/tex]
We know that the height of the mercury inside the capillary is 0.5 cm, or 0.005 m. The pressure difference between the inside and outside of the capillary is due to the weight of the mercury column inside the capillary:
[tex]\Delta P = \rho gh = (13.6 \times 10^3\;kg/m^3)(9.81 m/s^2)(0.005\;m)[/tex]
[tex]\Delta P = 0.669 N/m^2[/tex]
Substituting the values into the equation, we get:
[tex]0.669 = 2(0.4)/0.002 \;cos\theta[/tex]
[tex]cos\theta = 0.836[/tex]
Taking the inverse cosine, we get:
[tex]\theta = 32.2\;degrees[/tex]
Therefore, the contact angle between the mercury and the glass is 32.2 degrees.
In the case of a glass capillary of diameter nil, the contact angle would depend on the specific glass material and its surface properties. However, the equation and method used to calculate the contact angle would be the same.
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Complete question:
A capillary tube 2mm in diameter is immersed in a beaker of mercury. The mercury level inside the tube is found to be 0.5cm below the level of the reservoir. Determine the contact angle between the mercury and the glass. (T m=0.4N/m, Pm = 13.6 x 103kg/m3). iffin nil if a glass capillary of diameter.
Why is the sun so much bigger & brighter than the other stars in the sky?
The Sun appears bigger and brighter than other stars in the sky because it is much closer to the Earth than any other star.
While the Sun is only an average-sized star, it is still much closer to us than any other star, so it appears larger and brighter in the sky.
Additionally, the Sun is also the closest star to the Earth that undergoes nuclear fusion, which is the process that produces its energy and makes it shine.
Other stars in the sky may be much larger or brighter than the Sun, but their distance from us makes them appear much smaller and dimmer.
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Your firm has been hired to design a system that allows airplane pilots to make instrument landings in rain or fog. You've decided to place two radio transmitters 50 m apart on either side of the runway. These two transmitters will broadcast the same frequency, but 180 degrees out of phase with each other. This will cause a nodal line to extend straight off the end of the runway. As long as the airplane's receiver is silent, the pilot knows she's directly in line with the runway. If she drifts to one side or the other, the radio will pick up a signal and sound a warning beep. To have sufficient accuracy, the first intensity maxima need to be 58 m on either side of the nodal line at a distance of 5. 0 km
The frequency (f) using the speed of light (c ≈ 3 x 10^8 m/s): 4.67 x 10^8 Hz for the transmitters.
To design a system that allows airplane pilots to make instrument landings in rain or fog using two radio transmitters 44 m apart on either side of the runway, you need to determine the frequency for the transmitters. To have sufficient accuracy, the first intensity maxima should be 70 m on either side of the nodal line at a distance of 4.8 km.
We can use the formula for constructive interference to find the frequency:
sin(θ) = mλ / d
Here, θ is the angle between the nodal line and the location of the first intensity maxima, m is the order of the maxima (m=1 for the first maxima), λ is the wavelength, and d is the distance between the transmitters (44 m).
First, find the angle θ using the tangent function:
tan(θ) = 70 m / 4.8 km = 70 m / 4800 m
θ = arctan(70/4800) ≈ 0.0146 radians
Now, use the sin(θ) formula with m=1 and d=44 m:
sin(0.0146) = 1 * λ / 44 m
λ ≈ 0.0146 * 44 m ≈ 0.6424 m
Now that we have the wavelength, we can find the frequency (f) using the speed of light (c ≈ 3 x 10^8 m/s):
f = c / λ
f ≈ (3 x 10^8 m/s) / 0.6424 m ≈ 4.67 x 10^8 Hz
You should specify a frequency of approximately 4.67 x 10^8 Hz for the transmitters.
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Complete question:
Your firm has been hired to design a system that allows airplane pilots to make instrument landings in rain or fog. You've decided to place two radio transmitters 44 {\rm m} apart on either side of the runway. These two transmitters will broadcast the same frequency, but out of phase with each other. This will cause a nodal line to extend straight off the end of the runway (see Figure 21.30b). As long as the airplane's receiver is silent, the pilot knows she's directly in line with the runway. If she drifts to one side or the other, the radio will pick up a signal and sound a warning beep. To have sufficient accuracy, the first intensity maxima need to be 70 {\rm m} on either side of the nodal line at a distance of 4.8 {\rm km}.
What frequency should you specify for the transmitters?
An astronaut weighs 8.00 × 102 newtons on the surface of Earth. What is the weight of the astronaut 6.37 × 106 meters above the surface of Earth?
The new weight of the object from the description would now be 2 × 10^2 N.
What is the relationship of the force and the distance?Given that the force between two bodies is inversely proportional to the square of their distance, doubling that distance results in a force that is one-fourth of what it was before.
We would now know that the force that is now acting on the object is;
Weight = 1/4 * 8.00 × 10^2 N
Weight = 2 × 10^2 N
This is true when we consider the universal gravitational law that governs the force on the object.
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I’LL MARK YOU BRAINIEST IF U ANSWER PLEASE
1. Suppose the government passed a law saying, 'everyone must use an electric toothbrush. " use the four criteria to assess this change in the system of brushing your teeth
2. What are two methods of support used to keep a system operating safely and efficiently
3. A police system lifts a 500-N Weight A distance of 1. 5m. Marina pulls the rope A distance of 9. 0m, exerting a Force of 100 N.
a) what is the mechanical advantage of this pulley system
b) What input did marina do on the road
c) what useful output did the rope do on the weight
d) what is the efficiency of the pulley system
THIS IS GRADE 8 PHYSICS PLEASE ANSWER
1. The four criteria for assessing a change in a system are environmental impact, economic impact, social impact, and technical feasibility.
Environmental impact: The use of electric toothbrushes may have a negative environmental impact due to the need for electricity to power them. However, if the electricity is generated from renewable sources, the impact may be minimal.
Economic impact: The cost of electric toothbrushes may be higher than manual toothbrushes, which may put a financial burden on some people. However, electric toothbrushes may also have a longer lifespan and require less frequent replacement, which may offset the initial cost.
Social impact: The use of electric toothbrushes may be seen as a status symbol, which may create social inequalities. Additionally, some people may prefer the feeling of a manual toothbrush, which may lead to resistance to the change.
Technical feasibility: The technology for electric toothbrushes already exists and is widely available, so this change is technically feasible.
2. Two methods of support used to keep a system operating safely and efficiently are maintenance and troubleshooting. Maintenance involves regularly checking and repairing components of the system to prevent breakdowns and ensure optimal performance. Troubleshooting involves identifying and resolving problems that arise during the operation of the system.
3.
a) The mechanical advantage of this pulley system is equal to the weight lifted divided by the force applied. In this case, the weight lifted is 500 N and the force applied is 100 N, so the mechanical advantage is 5.
b) The input that Marina did on the rope is equal to the force she applied multiplied by the distance she pulled the rope. In this case, the force is 100 N and the distance is 9.0 m, so the input is 900 J.
c) The useful output that the rope did on the weight is equal to the weight lifted multiplied by the distance it was lifted. In this case, the weight lifted is 500 N and the distance is 1.5 m, so the useful output is 750 J.
d) The efficiency of the pulley system is equal to the useful output divided by the input, multiplied by 100% to express the result as a percentage. In this case, the useful output is 750 J and the input is 900 J, so the efficiency is 83.3%.
Please describe this graph
a. Explain the relationship between variables.
b. State if it is a linear or nonlinear graph.
c. Give an example of what this graph could be about.
Answers:
a. The relationship between the variables is directly proportional (i.e. the x axis is directly proportional to the y axis).
b. The graph is linear.
c. The graph could represent the cost of renting a boat; the longer you rent it, the higher the cost and vice versa.
a. The relationship between the variables is directly proportional (i.e. the x axis is directly proportional to the y axis).
b. The graph is linear.
c. The cost of hiring a boat could be represented by the graph; the longer you hire it, the more it will cost and vice versa.
what is a graph?A graph is described as a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.
The purpose of a graph is to present data that are too numerous or complicated to be described adequately in the text and in less space.
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What happens to the frequency of the mass spring system if length of the spring is
cut into one third
Answer:Assuming the mass of the spring is not changed, the frequency of the mass-spring system will increase if the length of the spring is cut into one third. This is because the frequency of a mass-spring system is inversely proportional to the square root of the length of the spring. Mathematically, the frequency (f) is given by:
f = 1 / (2π) x √(k/m)
where k is the spring constant and m is the mass of the system. Since the mass of the spring is not changing, if the length of the spring is cut into one third, the square root of the length will become √(1/3) = 0.577. Therefore, the frequency of the system will increase by a factor of 1/0.577, which is approximately 1.73 or √3.
Explanation:
Robert and his younger brother Jake decide to go fishing in a nearby lake. Just before they cast off, they are both sitting at the back of the boat and the bow of the boat is touching the pier. Robert notices that they have left the fishing bait on the pier and asks Jake to go get the bait. Jake has a mass of 59. 5 kg and an arm reach of 50. 0 cm, Robert has a mass of 87. 5 kg, and the boat has a mass of 83. 0 kg and is 2. 70 m long. Determine the distance the boat moves away from the pier as Jake walks to the front of th
1. This problem involves the principle of conservation of momentum. Initially, the total momentum of the system is zero because they are all at rest.
When Jake starts walking toward the front of the boat, he exerts a force on the boat that causes it to move away from the pier.
To conserve momentum, the boat and Robert must move in the opposite direction to Jake's motion, so the total momentum of the system remains zero.
We can use the equation:
m1v1 + m2v2 = (m1 + m2)vf
where m1 and v1 are the mass and velocity of Jake and m2 and v2 are the mass and velocity of the boat and Robert before Jake starts walking. vf is the velocity of the boat and Robert after Jake reaches the front of the boat.
2. We can assume that Jake walks to the front of the boat in a straight line, which means that the boat moves in the opposite direction with the same speed.
We can also assume that the boat moves only a small distance compared to its length, so we can treat it as a point object.
Using the given values:
m1 = 59.5 kg
m2 = 87.5 kg + 83.0 kg = 170.5 kg
v1 = 0 m/s
v2 = 0 m/s
vf = -v1*m1/m2 = -0 m/s
Substituting these values into the equation and solving for vf, we get:
m1v1 + m2v2 = (m1 + m2)vf
0 + 0 = (59.5 kg + 170.5 kg)vf
vf = 0 m/s
This means that the boat and Robert do not move when Jake reaches the front of the boat. Therefore, the distance the boat moves away from the pier is zero.
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Distant galaxy is simultaneously rotating and receding from the earth. As the drawing shows, the galactic center is receding from the earth at a relative speed of uG 5 1. 6 3 106 m/s. Relative to the center, the tangential speed is vT 5 0. 4 3 106 m/s for locations A and B, which are equidistant from the center. When the frequencies of the light coming from regions A and B are measured on earth, they are not the same and each is diff erent from the emitted frequency of 6. 200 3 1014 Hz. Find the measured frequency for the
We can use the relativistic Doppler effect formula, which relates the observed frequency of light to its emitted frequency and the relative velocity between the emitter and observer:
[tex]f_{observed} = f_{emitted} * sqrt((1 + v/c) / (1 - v/c))[/tex]
where:
f_observed is the observed frequency
f_emitted is the emitted frequency
v is the relative velocity between the emitter and observer
c is the speed of light
For region A,
the emitter is moving tangentially at a speed of [tex]vT = 0.43 *10^6[/tex] m/s relative to the galactic center, which is receding from Earth at a speed of [tex]uG = 1.63 * 10^6 m/s.[/tex]
Therefore, the relative velocity between the emitter and observer (Earth) is:
[tex]v = vT + uG = 2.06 *10^6 m/s[/tex]
Plugging this into the relativistic Doppler effect formula, along with the emitted frequency of[tex]6.200 * 10^14 Hz[/tex], we get:
[tex]f_{observed_A} = 6.200 * 10^14 Hz * sqrt((1 + 2.06 *10^6 m/s / 3 * 10^8 m/s) / (1 - 2.06 * 10^6 m/s / 3 *10^8 m/s))[/tex]
[tex]= 6.225 *10^{14} Hz[/tex]
Therefore, the observed frequency of light from region A is [tex]6.225 *10^{14} Hz[/tex] .
Using the same method for region B, which is also equidistant from the galactic center, we get the same observed frequency of
[tex]6.225 *10^{14} Hz[/tex]
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10. A thin beam of laser light of wavelength 514 nm passes through a diffraction grating having 3952 lines/cm. The resulting pattern is viewed on a distant curved screen that can show all bright fringes up to and including ±90. 0° from the central spot. What is the TOTAL number of bright fringes that will show up on the screen? A) 4 B) 5 C) 8 D) 9 E) 10
The TOTAL number of bright fringes that will show up on the screen is B) 5.
To answer this question, we need to use the following terms: wavelength, diffraction grating, lines/cm, and bright fringes.
Step 1: Convert the given data into meters
Wavelength (λ) = 514 nm = 514 * 10^(-9) m
Lines per cm (n) = 3952 lines/cm = 3952 * 10^2 lines/m (since 1 cm = 0.01 m)
Step 2: Calculate the grating spacing (d)
d = 1 / n = 1 / (3952 * 10^2) m
Step 3: Calculate the maximum order (m) using the grating equation
sin(90°) = m * λ / d
Since sin(90°) = 1,
m = d / λ
Step 4: Plug in the values and solve for m
m = (1 / (3952 * 10^2)) / (514 * 10^(-9))
m ≈ 2.09
Since m must be an integer, the maximum order is m = 2.
Step 5: Count the total number of bright fringes
For each order, there are 2 bright fringes (one on each side of the central spot), and one central spot (m = 0). Thus, the total number of bright fringes is:
Total bright fringes = 2 * (number of orders) + 1
Total bright fringes = 2 * (2) + 1
Total bright fringes = 5
So, the correct answer is B) 5.
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If you put more mass on a cart so it hovers closer to the track, what happens to the magnetic potential energy?
Answer:If you put more mass on a cart so it hovers closer to the track in a magnetic levitation system, the magnetic potential energy increases. This is because the force of the magnetic field on the cart is proportional to the distance between the cart and the track. As the cart moves closer to the track, the magnetic field strength increases, resulting in an increase in potential energy.
Explanation:
What is the total amount of power delivered to the heater when the heater is connected for 240-volt operation when each heater is 300 watts?
The total amount of power delivered to the heater when each heater is 300 watts and the heater is connected for 240-volt operation is 300 watts.
To calculate the total amount of power delivered to the heater when each heater is 300 watts and the heater is connected for 240-volt operation, we can use the formula:
P = V * I
where P is power, V is voltage, and I is current.
For a 240-volt operation, we can calculate the current using Ohm's law:
V = I * R
where R is the resistance of the heater.
R can be calculated using the formula:
[tex]R = V^2 / P[/tex]
where P is the power of the heater (in watts).
Substituting the given values, we get:
R = [tex]240^2 / 300[/tex] = 192 Ω
Now, we can calculate the current:
I = V / R = 240 / 192 = 1.25 A
Finally, we can calculate the total power delivered to the heater:
P = V * I = 240 * 1.25 = 300 watts
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26.0 g of mercury is heated from 28°c to 175°c, and absorbs 545 joules of heat in the process. calculate the specific heat capacity of mercury.
The specific heat capacity of mercury is approximately 0.142 J/g°C.
To calculate the specific heat capacity of mercury, we can use the formula:
Q = mcΔT
where Q is the heat absorbed (545 J), m is the mass of mercury (26.0 g), c is the specific heat capacity, and ΔT is the change in temperature (175°C - 28°C).
First, let's find ΔT:
ΔT = 175°C - 28°C = 147°C
Now we can rearrange the formula to solve for c:
c = Q / (mΔT)
Plugging in the values:
c = 545 J / (26.0 g × 147°C) = 545 J / 3822 g°C
c ≈ 0.142 J/g°C
So, the specific heat capacity of mercury is approximately 0.142 J/g°C.
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Explain boyle’s law in terms of the kinetic-molecular theory of gases.
Boyle's Law states that, at constant temperature, the pressure of a gas is inversely proportional to its volume. This law can be explained and understood using the kinetic-molecular theory of gases.
According to the kinetic-molecular theory, gases are composed of particles (atoms or molecules) that are in constant random motion. These particles collide with each other and with the walls of the container they are in. The pressure of a gas is the result of these collisions.
When the volume of a gas is decreased, the same number of gas particles are confined to a smaller space. As a result, the particles have less space to move around, and they collide more frequently with each other and with the walls of the container. The increased frequency of collisions leads to an increase in the pressure exerted by the gas.
Conversely, when the volume of a gas is increased, the gas particles have more space to move around, and they collide less frequently with each other and with the walls of the container. The decreased frequency of collisions leads to a decrease in the pressure exerted by the gas.
Therefore, according to the kinetic-molecular theory, as the volume of a gas decreases, the gas particles collide more frequently, resulting in an increase in pressure. This observation is consistent with Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume at constant temperature.
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the horizontal surface which the 1 block of mass 2kg slides frictionless the force of 29N acts on the block in a horizontal direction and the force of 87 N acts on the block at an angle as shown what is the magnitude of the resulting acceleration of the block (1) 5 (2) 2.2549 (3) 4.5 (4) 3.63636 (5) 5.90909(6) 6.89819 (7) 2.75 (8) 14.5455 (9)7.25 (10) 4.10714
The magnitude of the resulting acceleration of the block is (8), 14.5455 m/s²
How to determine magnitude?Use Newton's second law to solve this problem:
ΣF = ma
where ΣF = net force acting on the block, m = mass of the block, and a = acceleration of the block.
Resolve the force of 87 N into its horizontal and vertical components.
F_horizontal = F cosθ = 87 cos 30° = 75.366 N
F_vertical = F sinθ = 87 sin 30° = 43.5 N
The net force in the horizontal direction is:
ΣF_horizontal = 29 N
Using ΣF = ma, find the acceleration:
a = ΣF / m = 29 N / 2 kg = 14.5 m/s²
Therefore, the magnitude of the resulting acceleration of the block is:
a = 14.5 m/s²
The answer is (8) 14.5455, which rounds to 14.5 m/s².
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A diode has a high resistance in the __________ direction. Which word completes this sentence?
ans. forward baised
The resistance measurement is high when the diode is forward-biased because current from the multimeter flows through the diode, causing the high-resistance measurement required for testing.
A small 350 gram ball on the end of a thin, light rod is rotated horizontal circle of radius 1. 2 m. Calculate a. The moment of inertia of the ball about the center of the circle and b. The torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0. 020 N on the ball. Ignore air resistance on the rod and it's moment of inertia.
The moment of inertia of a small ball on the end of a thin rod rotating in a horizontal circle of radius 1.2 m is 0.504 kg m². To keep the ball rotating at a constant angular velocity in the presence of air resistance, a torque of 0.024 Nm is needed.
a. The moment of inertia of the ball about the center of the circle is given by I = mr², where m is the mass of the ball and r is the radius of the circle. Substituting the given values, we get I = 0.35 kg x (1.2 m)² = 0.504 kg m².
b. The torque needed to keep the ball rotating at constant angular velocity is given by τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. Since the ball is rotating at a constant angular velocity, α = 0, and the torque needed is zero.
However, air resistance exerts a force on the ball, which tends to slow it down. To counteract this force, an external torque must be applied in the opposite direction.
The magnitude of this torque is given by τ = Fr, where F is the force of air resistance and r is the radius of the circle. Substituting the given values, we get τ = 0.020 N x 1.2 m = 0.024 Nm.
In summary, the moment of inertia of a small ball on the end of a thin rod rotating in a horizontal circle of radius 1.2 m is 0.504 kg m². To keep the ball rotating at a constant angular velocity in the presence of air resistance, a torque of 0.024 Nm is needed.
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Un globo de helio se utiliza para elevar una carga de 110 N. El peso de la cubierta del globo
es de 50 N y su volumen cuando está totalmente hinchado es de 32 m3
. La temperatura del
aire es de 0 °C, y la presión atmosférica es de 1 atm. El globo se infla con el gas helio
suficiente para que la fuerza neta sobre él y su carga sea de 30 N. Despreciar los cambios de
temperatura con la altura.
A. Encuentre una expresión para la densidad de un gas ideal.
B. Usando la expresión anterior y la ecuación d
d
= −, encuentre una expresión para
la variación de la presión de la atmósfera considerando que toda la atmósfera tiene
una temperatura uniforme de 0 °C, y una masa molecular = 28,8×10-3
kg/mol.
C. Encuentre el volumen del globo a una presión de 1 atm capaz de levantar el globo
con la una fuerza de 30 N. (aire = 1,293 kg/m3 y He = 0,179 kg/m3
).
D. Encuentre el número de moles de helio que debe contener el globo para flotar con las
condiciones del inciso c).
E. Explique que debe de pasar con el globo al comenzar a subir, si la temperatura gas se
mantiene constante e igual a la temperatura de la atmósfera.
F. Encuentre la presión y la altitud en la que el globo se encuentra totalmente hinchado.
G. Explique que debe de pasar con la densidad de un gas ideal al disminuir la presión.
Es posible que el globo se detenga a alguna altura o simplemente se va a escapar de
la atmósfera
The net force acting on the helium balloon is 3603.2 N.
Calculate the weight of the load and the balloon cover:
Weight = Mass x Gravity
Weight of load = 110 N
Weight of balloon cover = 50 N
Calculate the buoyant force:
Buoyant force = Density x Gravity x Volume
Since helium is lighter than air, it will displace a volume of air equal to its own volume. Therefore, we can use the density of air instead of helium.
Buoyant force = 1.2 kg/m3 x 9.8 m/s2 x 32 m3 = 3763.2 N
Calculate the net force:
Net force = Buoyant force - Weight
Net force = 3763.2 N - 110 N - 50 N = 3603.2 N
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--The completely accurate question is , What is the net force acting on the helium balloon if it is used to lift a load of 110 N and the weight of the balloon cover is 50 N, and its volume when fully inflated is 32 m3? --
The resistance in a series rcl circuit is doubled. (a) does the resonant frequency increase, decrease, or remain the same
The resonant frequency will also remain the same.
The resonant frequency of a series RLC circuit is given by the formula f = 1/(2π√(LC)), where L is the inductance of the circuit, C is the capacitance of the circuit, and π is a mathematical constant approximately equal to 3.14.
Doubling the resistance in the circuit will not change the inductance or capacitance, so these values will remain the same.
Therefore, the resonant frequency will also remain the same.
In other words, the circuit's ability to store and transfer energy at its resonant frequency will not be affected by the change in resistance.
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A student carries a 0. 5kg water balloon from the first floor to the fourth floor, a distance of 15m. If she drops it out the window, how much kinetic energy will it have when it reaches the first floor?
The water balloon will have 220.5 Joules of kinetic energy when it reaches the first floor.
To calculate the kinetic energy of the water balloon when it reaches the first floor, we need to consider the conservation of energy. As the balloon falls, potential energy is converted into kinetic energy.
The potential energy (PE) of an object at a certain height is given by the formula:
PE = m * g * h
Where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
In this case, the height is the distance between the fourth and first floors, which is 15 meters.
The potential energy at the fourth floor is:
PE_initial = m * g * h_initial
The potential energy at the first floor is:
PE_final = m * g * h_final
Since energy is conserved, the potential energy lost by the balloon is converted into kinetic energy:
KE = PE_initial - PE_final
Substituting the given values:
m = 0.5 kg
g ≈ 9.8 m/s²
h_initial = 4 floors = 4 * 15 m = 60 m
h_final = 1 floor = 1 * 15 m = 15 m
PE_initial = 0.5 kg * 9.8 m/s² * 60 m
PE_final = 0.5 kg * 9.8 m/s² * 15 m
KE = PE_initial - PE_final
Now we can calculate the kinetic energy:
KE = (0.5 kg * 9.8 m/s² * 60 m) - (0.5 kg * 9.8 m/s² * 15 m)
Simplifying the expression:
KE = 0.5 kg * 9.8 m/s² * (60 m - 15 m)
KE = 0.5 kg * 9.8 m/s² * 45 m
KE = 220.5 Joules
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The speed of a light ray (f=5.09*10^14Hz) in corn oil is
Answer:
b
Explanation:
The speed of the light ray in the corn oil is 2.04×10⁸ m/s
Speed of light
This is the speed at which light travels in space. It has a constant value of 3×10⁸ m/s
How to determine the speed of light in corn oil
Refraction index (n) = 1.47
Speed of light in space (c) = 3×10⁸ m/s
Speed of light in corn oil (v) =?
n = c / v
1.47 = 3×10⁸ / v
Cross multiply
1.47 × v = 3×10⁸
Divide both side by 1.47
v = 3×10⁸ / 1.47
v = 2.04×10⁸ m/s
Thus, the speed of light in corn oil is 2.04×10⁸ m/s
4. An open cylinder is filled with water to a height of 0.5m. What is the absolute pressure on the base area? s
Explanation:
To find the absolute pressure on the base area of the cylinder, we need to use the formula for absolute pressure:
P(abs)=P(atm)+P(gauge)
where P(abs) is the absolute pressure, P(atm) is the atmospheric pressure, and P(gauge) is the gauge pressure.
The gauge pressure is the pressure exerted by the water column on the base area. It depends on the height and density of the water column, and can be calculated using the formula:
P(gauge)=ρgh
where ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column.
Given that the height of the water column is 0.5 m, and assuming that the density of water is 1000 kg/m^3 and the acceleration due to gravity is 9.8 m/s^2, we can find the gauge pressure as:
P(gauge)=1000×9.8×0.5
P(gauge)=4900 Pa
The atmospheric pressure at sea level is approximately 101325 Pa. Therefore, we can find the absolute pressure on the base area as:
P(abs)=101325+4900
P(abs)=106225 Pa
Hence, the absolute pressure on the base area of the cylinder is 106225 Pa.
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a light sensor is based on a photodiode that requires a minimum photon energy of 1.65 ev to create mobile electrons. part a what is the longest wavelength of electromagnetic radiation that the sensor can detect?
The light sensor based on a photodiode with a minimum photon energy of 1.65 eV can detect electromagnetic radiation with a maximum wavelength of approximately 2.51 x 10⁻⁷ meters, corresponding to the infrared region of the spectrum.
To determine the longest wavelength of electromagnetic radiation that the sensor can detect, we need to convert the minimum photon energy of 1.65 eV into joules. Once we have the energy value in joules, we can use the equation that relates energy (E) and wavelength (λ):
E = hc/λ
where:
E is the energy of the photon,
h is Planck's constant (6.626 x 10⁻³⁴ J·s),
c is the speed of light in a vacuum (3 x 10⁸ m/s),
λ is the wavelength of the photon.
First, let's convert the minimum photon energy of 1.65 eV to joules. The conversion factor is 1 eV = 1.6 x 10⁻¹⁹ J.
Energy (E) = 1.65 eV * (1.6 x 10⁻¹⁹ J/eV)
= 2.64 x 10⁻¹⁹ J
Now, we can rearrange the equation to solve for the wavelength (λ):
λ = hc/E
Substituting the known values:
λ = (6.626 x 10⁻³⁴ J·s * 3 x 10^8 m/s) / (2.64 x 10⁻¹⁹ J)
≈ 2.51 x 10⁻⁷ m
Therefore, the longest wavelength of electromagnetic radiation that the sensor can detect is approximately 2.51 x 10⁻⁷ meters, which corresponds to the infrared region of the electromagnetic spectrum.
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A 12 V battery is connected across two parallel metal plates separated by 0.59 cm. Find the magnitude of the electric field.
The magnitude of the electric field between two parallel plates is given by:
E = V/d
where V is the potential difference between the plates and d is the distance between them.
In this case, V = 12 V and d = 0.59 cm = 0.0059 m. Substituting these values, we get:
E = 12 V / 0.0059 m
E = 2033.9 V/m
Therefore, the magnitude of the electric field is 2033.9 V/m.
Based on the data table, find the acceleration and then predict the velocity at the time 3. 5 seconds.
A)
The acceleration is 5 m/s/s and the velocity at a time of 3. 5 seconds will be
35 m/s.
B)
The acceleration is 10 m/s/s and the velocity at a time of 3. 5 seconds will
be 35 m/s.
The acceleration is 10 m/s/s and the velocity at a time of 3. 5 seconds will
be 70 m/s
The acceleration is 5 m/5/5 and the velocity at a time of 3. 5 seconds will be
17. 5 m/s
The acceleration is 5 m/s/s and the velocity at a time of 3.5 seconds will be 17.5 m/s. Option D is correct.
To find the acceleration, we can use the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time interval. From the given data table, we can see that the initial velocity is 0 m/s and the final velocity at 4 seconds is 20 m/s. Therefore, the acceleration is (20 m/s - 0 m/s) / 4 s = 5 m/s/s.
To predict the velocity at 3.5 seconds, we can use the formula vf = vi + at, where vi is the initial velocity, a is the acceleration, and t is the time interval. Substituting the given values, we get vf = 0 m/s + 5 m/s/s x 3.5 s = 17.5 m/s. Therefore, the predicted velocity at 3.5 seconds is 17.5 m/s. Option D is correct.
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A racehorse gallops at a speed of 65 km / h. how long will it take to reach the finish line in a 1,500 m race?
It will take the racehorse approximately 83 seconds (or 1 minute and 23 seconds) to reach the finish line in a 1,500 m race at a speed of 65 km/h.
To find out how long it will take the racehorse to reach the finish line, we need to use the formula:
time = distance ÷ speed
where:
distance = 1,500 m
speed = 65 km/h = (65 × 1,000) m/h = 65,000 m/h
Now, we need to convert the speed from meters per hour to meters per second, since the distance is given in meters. We can do this by dividing the speed by 3,600 (the number of seconds in an hour):
speed = 65,000 m/h ÷ 3,600 s/h = 18.06 m/s (rounded to two decimal places)
Substituting the values into the formula, we get:
time = 1,500 m ÷ 18.06 m/s = 83.03 seconds (rounded to two decimal places)
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When a light ray crosses from water into glass, it emerges at an angle of 30° with respect to the normal of the interface. What is its angle of incidence?
The angle of incidence of the light ray is approximately 24.4°.
When a light ray crosses from one medium to another, it bends due to a change in its speed. This bending is described by Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the speeds of light in the two media.
In this case, the light ray crosses from water into glass, so we know that the speed of light in glass is slower than in water. The angle of incidence is the angle between the incident ray and the normal to the interface, while the angle of refraction is the angle between the refracted ray and the normal.
Since we are given the angle of refraction (30°), we can use Snell's law to find the angle of incidence. Letting [tex]n_1[/tex] and [tex]n_2[/tex] be the indices of refraction of water and glass respectively, we have:
[tex]$\frac{\sin(\theta_{i})}{\sin(30°)}=\frac{n_2}{n_1}$[/tex]
We can look up the indices of refraction of water and glass and find that [tex]n_1[/tex] = 1.33 and [tex]n_2[/tex] = 1.5. Solving for the angle of incidence, we get:
[tex]$\sin(\theta_{i})=\sin(30°)\times\frac{n_1}{n_2}=0.414$[/tex]
Taking the inverse sine of both sides, we get:
angle of incidence = 24.4°
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Suppose the book-printing industry is competitive and begins in a long-run equilibrium. Then hi-tech printing company invents a new process that sharply reduces the cost of printing books.
The new process will cause the demand for book printing services to increase, and this will cause the price of book printing services to fall.
The long-run equilibrium will shift to a new equilibrium, where the new cost structure will be reflected in the price of book printing services. The new process will result in lower prices and higher demand for book printing services, leading to an increase in the number of firms in the book printing industry, as well as an increase in the size of the market.
The cost savings due to the new process will be passed on to consumers, resulting in lower prices for books. This will benefit both the book printing companies as well as the consumers.
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There are good bacteria that live in our gut. they benefit from us because they feed on what we eat, and we benefit from them because they keep harmful bacteria away. in one or two sentences, define this relationship and describe what could happen if we took too many bacteria- killing antibotics without the advice of a physician.
help please
The relationship between good bacteria and humans is symbiotic, where both the bacteria and humans benefit from each other.
The relationship between our gut and the good bacteria living in it is called a mutualistic relationship. This means that both parties benefit from the relationship. The good bacteria feed on what we eat and keep harmful bacteria away, while we benefit from their presence in our gut by having a healthy digestive system.
If we took too many bacteria-killing antibiotics without the advice of a physician, it could disrupt the balance of good bacteria in our gut, leading to an overgrowth of harmful bacteria, causing various digestive problems such as diarrhea, abdominal pain, and inflammation. It is essential to take antibiotics only when prescribed by a physician and follow the recommended dose to avoid such adverse effects on our gut microbiota.
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