5 lb 6 oz = __________ oz
Explain yourself

Answer:

90081???

Step-by-step explanation:

Step-by-step explanation:

1=56⁰

2=56⁰

3=68⁰

4=68⁰

5=56⁰

6=112⁰

7=180-124 Ans=56⁰

8=68+56 Ans=124⁰

9=68⁰

10=112⁰

11=124⁰

12=56⁰

Answer:

a

Step-by-step explanation:

Answer:

The correct answer is B, The elevation is a nonlinear function because it does not have a constant rate of change.

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

3.45x+2*1.65+5>=20

3.45x+8.3>=20

3.45x>=11.7

after rounding

x>=3

Answer:

800

Step-by-step explanation:

800+799=1599

Answer:

14.87

Step-by-step explanation:

Para conocer cual es la fuerza que necesita el cuerpo para aumentar su velocidad de 5 m/s a 12 m/s en 8 m

Necesitamos conocer la aceleración y para conocer la aceleración debemos saber cuanto tiempo tarda en recorrer los 8m

Vf = Vo +a(t)

12 = 5 +a(t) -------> Vamos a despejar el tiempo.

t = 7/a

X= Vo(t) +1/2a(t²)

X= 5(7/a)+1/2a( 7/a )²

8 = 35/a+49/2a

a = 7.43 m/s²  

Ahora que conocemos la aceleración podemos calcular la fuerza como:

F = m*a

F = 7.43 * 2 kg.

F = 14.87

Here according to angle sum property all angles sum u up 180°

So,

[tex]8x + 2 + 60 + 70 = 180 \\ 8x + 132 = 180 \\ 8x = 180 - 132 \\ 8x = 48 \\ x = \frac{48}{8} \\ x = 6[/tex]

- BRAINLIEST answerer

Answer:

4,0 is the right ok I am a professor

Answer:

6 candies

Step-by-step explanation:

(find unit rate, cost / quantity)

35/10 = 3.5

20/3.5 = = 5.7142857142857

candies cannot be in decimal so you must round to the nearest whole

Answer:

$53.30

Step-by-step explanation:

61.43-21.75=39.68 is the cell phone bill in July.

39.68+13.62= 53.30 is the phone bill in June.

Answer:

53.30

Step-by-step explanation:

August= 61.43

July= (61.43-21.75) or 39.68

June= (39.68+13.62) or 53.30

Hope this helps! :)

Answer:

1/4 to the 0 power is equal to 1. Therefore, it is not bigger than 1

Answer:

$1.33

Step-by-step explanation:

32-20 = 12

12/9 = $1.33

Answer:

5.72

Step-by-step explanation:

(-16.75 + 16.75) = 0

0 + 5.72= 5.72

Therefore, the answer is 5.72

In what context? Do you mean calculus If you are talking about graphing on a graph plane it would be the two accelerates on the x axis so (left or right) and then the 1.5 accelerates on the y axis so 1.5 on the y axis would be one and halfway to the 2 mark on the y axis so in the middle of 1 to 2 on the y axis the y axis goes (up and down)

Using a system of equations, the height of the tree would be 12.80 meters.

Equating the height and shadows of the tree and pole :

Height of pole / shadow of pole = height of tree / shadow of tree

Representing the equation thus :

Let the height of the tree = h

3/4 = h/17

Cross multiply

4h = 17 × 3

4h = 51

Divide both sides by 4

h = 51/4

h = 12.75.

Hence, the height of the tree to the nearest tenth of a meter is 12.80 meters.

Learn more : https://brainly.com/question/25562438

Step-by-step explanation:

To multiply fractions:

Multiply numerator to numerator and multiply denominator to denominator. Simplify the answer.

To multiply mixed numbers:

Change mixed numbers into improper fraction. Then multiply numerator and denominator just like how you multiply the fractions. Simplify.

Answer:

g = he - 10h

Step-by-step explanation:

Answer:

363/20,000

.................................................................................

Answer:

24

Step-by-step explanation:

Let the number be " x ".

11 % of x = 4

( 11 / 100 ) * x = 4

x = 4 * ( 100 / 11 )

x = 400 / 11

66 % of that number

= 66 % of x.

= 66 % of 400 / 11

= ( 66 / 100 ) x ( 400 / 11 )

= ( 66 x 400 ) / ( 100 x 11 )

= 6 x 4

= 24

Answer:

18 miles

Step-by-step explanation:

9 miles : 45 minutes

? miles : 90 minutes

45 x 2 = 90 minutes

9 x 2 = 18 miles

Check the picture below.

Using error concepts for hypothesis tests, it is found that there is a Type I error.

A Type I error happens when a true null hypothesis is rejected.

A Type II error happens when a false null hypothesis is not-rejected.

In this problem, the null hypothesis is:

[tex]H_0: \mu = 24[/tex]

The alternative hypothesis is:

[tex]H_1: \mu > 24[/tex]

He concludes that the mean age is over 24 when it is not, that is, a true null hypothesis is rejected, hence there is a Type I error.

A similar problem is given at https://brainly.com/question/25225353

==========================================

Explanation:

A) This is true because there are 4 cups of green and 2 cups of white. Each box represents 1 cup.

B) This is false. The ratio 4:2 reduces to 2:1 when describing the ratio of green to white. We have twice as many green compared to white. Choice B describes the other way around. The order is important.

C) This is true. We have 2 cups of white and 4 cups of green.

D) False. There are 6 cups total, but only 2 white (not 4).

E) True. This is a verbal way of describing the ratio 4:2, of green to white.

F) False. The ratio is the other way around. See choice E.

G) False. There are 4 cups of green, not 6. There are 6 cups total, not 4. The ratio of green to total is 4:6.

H) True. We have 2 cups of white and 2+4 = 6 cups total.

Answer:

Add 6 to both sides

Step-by-step explanation:

The (usual) first thing to do when solving any equation is to simplify both sides of the equation. However, since we have nothing to simplify, we move onto the next step that'll be the first step: isolating the variable, x. To do so, we must do the inverse of subtracting 6 (which is adding 6).

Answer:

(a) [tex]\log_72 \approx 0.3562[/tex]

(b) [tex]\log_7(\frac{147}{16} ) = 2[/tex]

Step-by-step explanation:

For the point a:

For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex]

16 can be re-write as [tex]2^4[/tex]. Then you have:

[tex]\log_72^4[/tex]

Using the power property of the logarithm we have:

[tex]\log_ba^c = c\log_ba[/tex]

[tex]\log_72^4 = 4\log_72[/tex]

And this expression is equal to:

[tex]4\log_72 \approx 1.4248\\\log_72\approx \frac{1.4248}{4} \approx 0.3562\\[/tex]

For the point b:

For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex] and [tex]\log_73 \approx 0.5646[/tex]

The first is use the quotient property in the given log.

[tex]\log_c\frac{a}{b} = \log_ca-\log_cb[/tex]

[tex]\log_7\frac{147}{16} = \log_7147 -\log_716[/tex]

We already know the value of [tex]\log_716[/tex] then we have to calculate the value of [tex]\log_7147[/tex].

So we factorize the number 147 in [tex]3 \cdot 7 \cdot 7[/tex] (for factorize the number start with the smaller prime and check if the remainder is 0, it is then is a primer factor of the number).

Now re-write [tex]\log_7147[/tex] as [tex]\log_73 \cdot 7^2[/tex] and by the product property get:

[tex]\log_bmn = \log_b m +\log_b n\\\log_73 \cdot 49 = \log_7 3 +\log_7 49 = 0.5646 + 2 = 2.5646[/tex]

Know replace each value in the subtraction and get the result:

[tex]\log_7147 -\log_716 = 2.5646 - 0.5646 = 2[/tex]

Answer:

[tex]\lim_{x \to 5}f(x)=-5\\\lim_{x \to 1^-} f(x)=3\\\lim_{x \to 1^+} f(x)=3\\\lim_{x \to 1} f(x)=4\\[/tex]

Step-by-step explanation:

[tex]\lim_{x \to 5}f(x)[/tex]

This means "the limit of f(x) as x approaches 5"

In this case, f(x) is a basic linear function while x > 1, so a limit is not necessary but it can still be used as it is here. For this one, you can just calculate f(5), and that is:

[tex]f(x)=5-2x[/tex]

[tex]f(5)=5-2(5)=5-10=-5[/tex]

[tex]\lim_{x \to 5}f(x)=-5[/tex]

===================

[tex]\lim_{x \to 1^-} f(x)[/tex]

This one is a little different. It means "the limit of f(x) as x approaches 1 from the negative (left) direction"

The negative direction of course means x will be less than 1, so we'll use this function:

[tex]f(x)=4-x[/tex]

It's easier if you graph it, but you can also do it like this:

[tex]f(0)=4+0=4\\f(0.5)=4-0.5=3.5\\f(0.75)=4-0.75=3.25\\f(0.9)=4-0.9=3.1\\f(0.99)=4-0.99=3.01[/tex]

There's a clear pattern there. You can see that f(1) should be 3, but this function only applies while x is less than 1 so it can never reach 3. It will get infinitely close, and that can be shown with the limit:

[tex]\lim_{x \to 1^-} f(x)=3[/tex]

===================

[tex]\lim_{x \to 1^+} f(x)[/tex]

This one works the same way, but from the positive (right) direction.

[tex]f(2)=5-4=1\\f(1.5)=5-3=2\\f(1.25)=5-2.5=2.5\\f(1.1)=5-2.2=2.8\\f(1.01)=5-2.02=2.98\\f(1.001)=5-2.002=2.998[/tex]

It will also get infinitely close to 3 when x = 1, but won't ever reach it because this function only applies when x is greater than 1.

[tex]\lim_{x \to 1^+} f(x)=3[/tex]

===================

[tex]\lim_{x \to 1} f(x)[/tex]

Here, the function for x=1 is just:

[tex]f(x)=4[/tex]

It's given already, so the limit is just:

[tex]\lim_{x \to 1} f(x)=4[/tex]

Answer:

Well I’m not sure what Answers do you want

Step-by-step explanation:

Answer:

Unsure but it might be -8/3

Step-by-step explanation:

HCF (2x, x) = x.

Factors of 2x = 2 × x × 1

Factors of x = x × 1

Common factors = x, 1

HCF = x × 1 = x

See the attachment too.

________

Hope it helps ⚜