50 points!!! Please help ASAP!!
The function y = f(x) is graphed below. What is the average rate of change of the
function f(x) on the interval -6

Answer:

2 dollars for 5 lb

Step-by-step explanation:

^

Answer:

Answer = B. Obtuse.

Step-by-step explanation:

Answer:

6+9=15

Step-by-step explanation:

hope this helps :D

Answer:   16%

step explanation:

100 m/hr is ONE S.D. (10) above 90

z - score = .8413    (Form Z-score chart)

      means    84 % of cars are travelling less than 100 m/hr

    ~ 16% are traveling 100 or more

Answer:

The value of the house increased $31,680.

The current value of the house is $427,680

Step-by-step explanation:

For $22.69 dollars I can ride the scooter for 179 minutes.

A quadratic equation is an algebraic expression in the form of variables and constants.

A quadratic equation has two roots as its degree is two.

Given, A scooter ride has a starting fee of $3 and then 11 cents per mile.

Assuming with $22.69 I can ride x no. of minutes.

∴ 0.11x + 3 = 22.69.

0.11x = 19.69.

x = 19.69/0.11.

x = 179 minutes.

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Answer:

36        ( or possibly  sqrt (2754)  )

Step-by-step explanation:

Use the Pythagorean Theorem to find the missing side   (you will have to try two different times because you do not know what is missing....a leg or the hypotenuse)

27^2 + 45^2 = x^2     x = sqrt2754=52.4786     although this is one true answer, I do not think it is what the question seeks

let's try

27^2 + x^2 = 45^2     x = 36    Check !  

Answer:

I would say the second one

Step-by-step explanation: Good luck! :)

Answer:

[tex]x=\pm1 \:\textsf{or}\:x=\pm3[/tex]

Step-by-step explanation:

[tex]x^4-10x^2+9=0[/tex]

[tex]\textsf{let}\:x^2=y[/tex]

[tex]\implies y^2-10y+9=0[/tex]

To factor a quadratic in the form [tex]ax^2+bx+c[/tex], find 2 two numbers that multiply to [tex]ac[/tex] and sum to [tex]b[/tex].

⇒ two numbers that multiply to 9 and sum to -10:  -9 and -1

Rewrite [tex]b[/tex] as the sum of these 2 numbers:

[tex]\implies y^2-y-9y+9=0[/tex]

Factorize the first two terms and the last two terms separately:

[tex]\implies y(y-1)-9(y-1)=0[/tex]

Factor out the common term [tex](y-1)[/tex]:

[tex]\implies (y-9)(y-1)=0[/tex]

[tex]\implies (y-9)=0 \implies y=9[/tex]

[tex]\implies (y-1)=0 \implies y=1[/tex]

Change [tex]y[/tex] back to [tex]x^2[/tex]:

[tex]\implies x^2=9\implies x=\pm3[/tex]

[tex]\implies x^2=1\implies x=\pm 1[/tex]

[tex]\textsf{So}\: x=\pm1 \:\textsf{or}\:x=\pm3[/tex]

Answer:

[tex]$x=\pm1\;\textrm{or}\;x=\pm3$[/tex]

Step-by-step explanation:

Substitute [tex]u = x^2[/tex] into the equation. This will make the quadratic formula easy to use.

[tex]\implies u^2 - 10u + 9 = 0[/tex]

Consider the form [tex]x^2 + bx + c = 0[/tex]. Find a pair of integers whose product is [tex]c[/tex] and whose sum is [tex]c[/tex]. In this case, whose product is [tex]9[/tex]and whose sum is [tex]10[/tex]. And write the factored form using the integers.

[tex]\implies (u - 9)(u - 1) = 0[/tex]

If any individual factor on the left side of the equation is equal to [tex]0[/tex], the entire expression will be equal to [tex]0[/tex].

[tex]\implies \begin{cases}u - 9 = 0 \\ \\ u - 1 = 0\end{cases}[/tex]

Set [tex]u - 9[/tex] equal to [tex]0[/tex] and solve for [tex]u[/tex]. Similarly, Set [tex]u - 1[/tex] equal to [tex]0[/tex] and solve for [tex]u[/tex].

[tex]\implies \begin{cases}u = 9 \\ \\ u = 1\end{cases}[/tex]

Substitute the real value of [tex]u = x^2[/tex] back into the solved equation.

[tex]\implies \begin{cases}x^2 = 9 \\ \\ x^2 = 1\end{cases}[/tex]

Take the square root of both sides of the equations to eliminate the exponent on the left side.

[tex]\implies \begin{cases}x = \sqrt{9} \\ \\ x = \sqrt{1}\end{cases}[/tex]

Solve both the equations for the value of [tex]x[/tex].

[tex]\implies \begin{cases}x = \pm3 \\ \\ x = \pm1\end{cases}[/tex]

Hence, this is our required solution for this question.

[tex]\rule{300}{1}[/tex]

Additional information:

There are three ways to solve a quadratic equation:

Factoring uses the logic that the product of any number and zero is zero. Complete the square method uses square root, and the quadratic formula is the simpler method of it.

Quadratic Formula [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Answer:

simply cut 5 and solve if no property needed but if needed use distributive

Step-by-step explanation:

The correct values for b is,

⇒ 0 < b < 1

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

The function is,

F (x) = [tex]log_{b} x[/tex]

Now, We know that;

As the logarithm of a negative number is undefined, b should be a positive number (b>0 ).

Therefore, the value of b must be in the range of 1 > b > 0 for the function to be a decreasing function.

Thus, The correct values for b is,

⇒ 0 < b < 1

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Answer:

[tex]t + \frac{1}{2} = 1 \frac{1}{4} [/tex]

Answer:

x=3,y=-3

Step-by-step explanation:

Isolate x for 4x +y=9: x=9-y/4

Substitute x = 9-y/4

[5 x 9-y/4+2y =9]

Isolate y for (45+3y/4)=9:

y=-3

For x= 9-y/4

Substitute y = -3

x= 9-(-3)/4

9-(-3)/4=3

X=3

The solutions to the system of equations are:

x=3 y= -3

Answer:

B and D

Why?

Well when looking for a function you have to look at the X Values. Why the X values? Well if they are different it is considered a function. If it is the same it will NOT be considered a function

Given -

To find -

Explanation -

Here as we are required to find the value of two different individuals hence first we will from 2 linear equations into two variables (taking each to be value as x and y or whatever you like, I will take them as a and b) will solve the equation by any method of your choice (explanation for them is in the link, below, it is given by the same me)

https://brainly.com/question/27161912?utm_source=android&utm_medium=share&utm_campaign=question

Solution -

Let the sum of money that was given to each boy be a and the number of boys be b. Hence, the total no. of money distributed to b no. of boys is ab.

According to the question,

Scenario 1 -

➡ (a + 2)(b - 10) = ab

Solving it further,

➡ a(b - 10) + 2(b - 10)= ab

➡ ab - 10a + 2b - 20= ab

Cancelling ab,

➡ 10a - 2b + 20 = 0

➡ 10a = 2b - 20

➡ a = 2(b - 10)/10

➡ a = (b - 10)/5

Scenario 2 -

➡ (a - 2)(b + 15) = ab

Solving it further,

➡ a(b + 15) - 2(b + 15)= ab

➡ ab + 15a - 2b - 30= ab

Cancelling ab,

➡ 15a - 2b - 30 = 0

Substituting the value of a in the equation,

➡ 15{(b - 10)/5} - 2b - 30 = 0

➡ 3(b - 10) - 2b - 30 = 0

➡ 3b - 30 - 2b - 30 = 0

➡ 3b - 2b -60 = 0

➡ b = 60

Substituting the value of b in a = (b - 10)/5,

➡ a = (60 - 10)/5

➡ a = 50/5

➡ a = 10

[Here we have used the substitution method]

Henceforth, the total number of boys is 60 and the sum received by each is Rs. 10 .

Answer: 52 ounces

multiply the mass value by 16

Answer:

The equation is 257/x = x/3.9

Step-by-step explanation:

Answer:

2500 pence (C = 2500)

Step-by-step explanation:

[tex]C = 10t + 20m[/tex]

From the given information, t is the number of texts so essentially you will plug in the number of texts provided (150) in the place of the variable t.

[tex]C = 10(150) + 20m[/tex]

Apply the same thing to minutes, plug in the number of minutes (50) in the place of the variable m.

[tex]C = 10(150) + 20(50)[/tex]

Now multiply the substitutes with the co-efficient.

[tex]C = 1500 + 1000[/tex] (10*150=1500 & 20*50=1000)

Add the addends

C = 2500

Answer:

The slope is 3

Step-by-step explanation:

The formula for slope is m = (y₂-y₁)/(x₂-x₁)

We assign

Note: You can choose any set of points as long as you assign y₂ and y₁ to y coordinates and x₂ and x₁ to x coordinates.

m = (-1+4)/(0+1) = 3/1 = 3

Answer:

D. 3 :)

Step-by-step explanation:

As the x value increases, so does the y value but in bigger jumps. It increases by 3 :)

Have an amazing day!!

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16.65... .... ..... ...

Answer: 16.65

Step-by-step explanation:

1/3 is equivalent to the decimal value .33

so, use the equation:

5x(3+.33) or 5x3.33, which equals 16.65

Answer:

A rhombus is both a rectangle and a rhombus. All the sides are equal and each angle measure 90 degrees. So yes it can be a rhombus.

Step-by-step explanation:

Answer:

No.

Step-by-step explanation:

A squares angles are all 90 degree, a rhombus however, has perpendicular angles crossing each other that are equal to 90 degress.

Graph D (last one)

Step-by-step explanation:

edge

Answer:

the last graph is d

Step-by-step explanation:

Answer:

y = x-3

Step-by-step explanation:

When the graph of this equation crosses the y - axis , the value of x is = 0.

 sub in zero to find this y value = -3

    so the point is (0, -3)

Now find the drivative of this equation....the derivative tells you the slope of the original graph at any given point

 derivative = 12x^2-10x+1        this , when x = 0 shows slope  = 1

    the equation then becomes   y = (1) x -3     or just  y = x-3

 See image below

Answer:

-3

Step-by-step explanation:

put x= 0

A mean is an arithmetic average of a set of observations. The average time taken by Shiho to complete the track is 3.7 seconds.

A mean is an arithmetic average of a set of observations. it is given by the formula,

[tex]\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}[/tex]

The reading of the 5 trials of Shiho is 3.3 seconds, 3.8 seconds, 4.1 seconds, 4.1 seconds, and 3.1 seconds. Therefore, the average or the meantime of Shiho can be written as,

[tex]\rm \text{Average Time} = \dfrac{\text{Sum of all observations}}{\text{Number of trials}}\\\\\text{Avrage Time} = \dfrac{3.3+3.8+4.1+4.1+3.1}{5}=\dfrac{18.4}{5}= 3.68\approx 3.7\ seconds[/tex]

Hence, the average time taken by Shiho to complete the track is 3.7 seconds.

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Answer:

3/10

Step-by-step explanation:

3/5 - 3/10 =          5×2 = 10 so 10 is the denominator

6/10 -3/10 =          rewrite with a denominator of 10

(6-3)/10 =              subtract numerators

3/10                      already in simplest form

Answer:

3/5

Step-by-step explanation:

You don’t need a common denominator when subtracting