6. How fast is each train traveling (km/h)? Round to the nearest whole number. a) Train A travels 520.4 km in 4.8 h b) Train B travels 72.1 km in 0.8 h​

Answer:

The given line of best fit is: T = 6.5d + 11.8

We can use this equation to estimate the total burn time for a candle with a diameter of 0.5 inches:

T = 6.5(0.5) + 11.8

T = 3.25 + 11.8

T = 15.05

So, according to the line of best fit, the total burn time of a candle with a diameter of 0.5 inch would be approximately 15.05 hours.

Therefore, the answer is D. 15 hours.

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A real-world situation that might involve three linear equations in three variables is trying to determine the ages of three siblings.

Let's call them A, B, and C. We know that the sum of all three ages is a certain value, let's say it's 60. We also know the sum of the first two ages is either twice the third age or the third age squared. For example, if the sum of the first two ages is twice the third age, we could write it as A + B = 2C.

Alternatively, if the sum of the first two ages is the third age squared, we could write it as A + B = C^2. Similarly, we know the sum of the first and third ages is either twice the second age or the square root of the second age. So, we could write it as A + C = 2B or A + C = sqrt(B).

We now have three linear equations in three variables that we can use to solve for the ages of the three siblings. By solving the system of equations, we can find out how old each sibling is.

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The length of side AB is 6.3 units.

The length of side AB is solved using the distance formula below

AB = √((x₂ - x₁)² + (y₂ - y₁)²

where

(x₁, y₁) = (-9, 0) and

(x₂, y₂) = (-3, 2).

AB = √((-3 - (-9))² + (2 - 0)²)

AB = √(6² + 2²)

AB = √(40)

AB = 2√(10)

AB = 6.3245

AB = 6.3 to the nearest tenth

Therefore, the length of side AB is 6.3 units.

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Answer:

o MDC de 6 e 9 é 3.

O produto de dois números é 54 e o seu MMC é 18. Precisamos encontrar o MDC desses dois números.

Primeiro, encontramos os dois números cujo produto é 54: 6 e 9.

Então, fatoramos cada número em seus fatores primos: 6 = 2 x 3 e 9 = 3 x 3.

O MDC de 6 e 9 é o produto dos fatores primos comuns, elevados à menor potência. Neste caso, o único fator primo comum é 3, elevado à primeira potência.

Portanto, o MDC de 6 e 9 é 3.

Event A' has a probability of 50% (25% for freshmen + 25% for seniors).

To determine Event A', we need to first identify what Event A represents. Event A is the probability that a student is a sophomore or junior. Since students have equal probabilities of being freshmen, sophomores, juniors, or seniors, the probability of Event A is 50% (25% for sophomores + 25% for juniors).
Event A' is the complement of Event A, which means it includes the other two grade levels not included in Event A, in this case, freshmen and seniors. Therefore, Event A' is the probability that a student is a freshman or a senior. Since students have equal probabilities of being in each grade level, Event A' also has a probability of 50% (25% for freshmen + 25% for seniors).

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Answer:

Perry would need to place his ladder 6.63 ft away from the base of the basketball hoop in order to reach the hoop.

Hope this helps!

Step-by-step explanation:

The Pythagorean theorem is [tex]a^{2} +b^{2} =c^{2}[/tex].

It is given that c is 12 and b is 10, so that would be:

[tex]c^{2} -b^{2} =a^{2}[/tex]

[tex]12^{2} -10^{2} =a^{2}[/tex]

144 - 100 = [tex]a^{2}[/tex]

44 = [tex]a^{2}[/tex]

a = [tex]\sqrt{44}[/tex]

a = 6.6332...

( c is the length of the ladder, b is the height of the hoop, and a is the distance between the ladder and the basketball hoop )

The inequality that can be used to determine the number of outfits Jason can purchase while staying within his budget is 68.54 o ≤ 274.16.

Solving the inequality gives:

o ≤ 4

The total cost of items that Jason spends on :

= 217. 34 + 36. 32 + 12. 18

= $ 265. 85

The amount that Jason has left from the $ 540 is:

= 540 - 265. 85

= $ 274. 16

If each outfit costs $ 68. 54 then the inequality that would help stay in budget is:

68.54 o ≤ 274.16

Solving this, gives:

o ≤ 274. 16 / 68.54

o ≤ 4

In conclusion, Jason can purchase up to 4 biking outfits while staying within his budget.

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The best-fitting model for the data and its corresponding R2 value need to be calculated.

To find the model that best fits the data and its corresponding R2 value, we would need to perform linear regression analysis on the data. However, since the data table is not provided, we cannot provide an answer to this question.

Linear regression analysis is a statistical method used to model the relationship between two variables. In this case, the variables are the year and the number of insect species encountered on each trip. By analyzing the data, we can determine the equation of the line that best fits the data and the R2 value, which represents the proportion of the variance in the data that is accounted for by the model. A higher R2 value indicates a better fit between the model and the data.

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The value of x that makes line A and B parallel is 13.

Two Angles are Supplementary when they add up to 180 degrees.

From the diagram:

Angle 1 = 9x + 24

Angle 2 = 3x

Angle 1 and angle 2 are supplementary as their sum equals 180 degrees making line A and B parallel.

Hence:

Angle 1 + Angle 2 = 180°

Plug in the values

9x + 24 + 3x = 180

Solve for x

Collect like terms

9x + 3x = 180 - 24

12x = 156

Divide both sides by 12

12x/12 = 156/12

x = 56/12

x = 13

Therefore, the value of x is 13.

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The value of x that maximizes revenue is x 28.99 and maximum revenue is $1680 (thousand).

The revenue function for a company that sells x (thousand) items is R(x) = x² + 840. To find the value of x that maximizes revenue, we need to differentiate the revenue function, set it equal to zero and solve for x. The maximum revenue can then be calculated by substituting the value of x into the revenue function.

Revenue function: R(x) = x² + 840

To find the value of x that maximizes revenue, we differentiate the revenue function with respect to x:

dR/dx = 2x

Setting this equal to zero, we get:

2x = 0

x = 0

However, this value does not make sense in the context of the problem, as the company cannot sell 0 items. Therefore, we need to consider the critical points of the function, which occur when dR/dx = 0 or is undefined.

dR/dx = 0 when 2x = 0, so x = 0 is a critical point.

dR/dx is undefined when x = ±√840, so these are also critical points.

We can use the second derivative test to determine which critical point corresponds to a maximum. The second derivative of the revenue function is:

d²R/dx² = 2

At x = 0, d²R/dx² = 2 > 0, so this critical point corresponds to a minimum.

At x = ±√840, d²R/dx² = 2 > 0, so these critical points correspond to a minimum.

Therefore, the value of x that maximizes revenue is x = √840 ≈ 28.99 (thousand items).

To find the maximum revenue, we substitute x = √840 into the revenue function:

R(√840) = (√840)² + 840 = 1680

So the maximum revenue is $1680 (thousand).

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Answer:

--------------------------

Let the equal sides be both marked as ?

Use the perimeter formula to determine one of the equal sides.

Substitute the expression for the perimeter and find the value of ?

Hence the length of each of equal sides is 4x² - x + 2.

The velocity of the truck after the collision would be 24 m/s east.

The law of conservation of momentum states that the momentum of a closed system remains constant if no external forces act on it. In this case, we can assume that the car and the truck form a closed system.

The momentum of an object is given by its mass multiplied by its velocity, p = mv. Initially, the momentum of the system is:

p_initial = m_car * v_car + m_truck * v_truck

where m_car and v_car are the mass and velocity of the car, and m_truck and v_truck are the mass and velocity of the truck.

After the collision, the car is stopped, so its velocity is 0. The momentum of the system after the collision is:

p_final = m_car * 0 + m_truck * v'_truck

where v'_truck is the velocity of the truck after the collision.

Since momentum is conserved, we can set p_initial equal to p_final:

m_car * v_car + m_truck * v_truck = m_truck * v'_truck

Solving for v'_truck, we get:

v'_truck = (m_car * v_car + m_truck * v_truck) / m_truck

Substituting the given values, we have:

v'_truck = (1200 kg * 40 m/s + 2000 kg * 0 m/s) / 2000 kg

v'_truck = 24 m/s east

Therefore, the velocity of the truck after the collision would be 24 m/s east.

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Ornamental Insulation Corporation would report a net income of $1,022,000 and comprehensive income of $1,010,000 resulting from these investments in its 2021 financial statements.

Ornamental Insulation Corporation would report the following amounts in its 2021 income statement, statement of comprehensive income, and balance sheet as a result of the investment activities:

Interest Income from American Instruments Bonds: $93,600 ($1,170,000 × 8%)

Gain on Sale of Distribution Transformers Bonds: $43,000 ($623,000 - $580,000)

Total Net Income: $136,600 ($93,600 + $43,000)

Gain on Investments: $55,000 (This represents the gain on the sale of the distribution transformers bonds and is included in the comprehensive income section.)

Balance Sheet (as of December 31, 2021):

American Instruments Bonds: $1,102,000 (market value)

M&D Corporation Bonds: $1,670,000 (face value)

Accumulated Other Comprehensive Income: $55,000 (This represents the gain on investments and is included in the comprehensive income section.)

Retained Earnings: Increase of $136,600 (This represents the net income from the income statement.)

In summary, Ornamental Insulation Corporation would report a net income of $136,600, a comprehensive income of $55,000, and an increase in retained earnings of $136,600 as a result of these investments for the fiscal year 2021.

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The corresponding measure of the parameters are;

i. 1ml = 0. 001 liter a.

ii. 1000ml = 1 liter b.

iii. 1 cl = 0. 01 liter c.

iv. 10dcl = 1 liter d.

v. 1cl = 100ml e.

v. 0. 01 cl = 1ml f.

To convert the factors, we need to know the following conversion rates.

We have;

1 milliliter = 0. 001 liter

1 centiliter = 0. 01 liter

1 deciliter = 0. 1 liter

1 cubic centimeter = 1 millimeter

Hence, the sizes are determined by the corresponding factor.

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Complete question:

Convert the following to their equivalent measurement for each letter

i. 1 ml = a liters

ii) b ml = 1 liters

iii) 1 cl = c liters

iv)d cl = 1 liters

v) 1 cl = e ml

vi) f cl = 1 ml

Answer:

m= month 12k - 3500= 950 she needs to save for 2 in a half months to get her car

Step-by-step explanation:

z - 9 = 10(x - 5) - 8(y - 4) this is the equation of the tangent plane at the point (5, 4, 9). (x - 5)/10 = (y - 4)/(-8) = (z - 9)/(-1). These are the symmetric equations for the normal line to the surface at the given point.

(a) To find the equation of the tangent plane to the surface z = x^2 - y^2 at the point (5, 4, 9), we first need to find the partial derivatives with respect to x and y:

∂z/∂x = 2x
∂z/∂y = -2y
Now, we evaluate these at the given points (5, 4, 9):
∂z/∂x(5, 4) = 2(5) = 10
∂z/∂y(5, 4) = -2(4) = -8
Using the tangent plane equation:
z - z₀ = ∂z/∂x (x - x₀) + ∂z/∂y (y - y₀)
Plugging in the values:
z - 9 = 10(x - 5) - 8(y - 4)
This is the equation of the tangent plane at the point (5, 4, 9).

(b) The normal vector to the surface at the given point is given by the gradient vector (∂z/∂x, ∂z/∂y, -1) = (10, -8, -1). To find the symmetric equations for the normal line, we use the point-normal form:
(x - x₀)/a = (y - y₀)/b = (z - z₀)/c
Plugging in the point (5, 4, 9) and the normal vector components (10, -8, -1):
(x - 5)/10 = (y - 4)/(-8) = (z - 9)/(-1)
These are the symmetric equations for the normal line to the surface at the given point.

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The average number of books bought per year by customers in the survey is approximately 4.85 books.

To find the average number of books bought per year, we need to calculate the mean of the data set. We can do this by using the formula:

Average = (Sum of all data points) / (Number of data points)

However, we do not have the actual number of data points. Instead, we have percentages. Therefore, we need to convert the percentages into actual numbers.

Out of 100 customers surveyed:

30% bought 3 books, which is equal to 30/100 x 100 = 30 customers

25% bought 5 books, which is equal to 25/100 x 100 = 25 customers

45% bought 6 books, which is equal to 45/100 x 100 = 45 customers

Now, we can calculate the average number of books bought per year using the formula mentioned earlier:

Average = (30 x 3) + (25 x 5) + (45 x 6) / (30 + 25 + 45)

Simplifying the above equation, we get:

Average = (90 + 125 + 270) / 100

Therefore, the average number of books bought per year is:

Average = 485/100

Average = 4.85 books per year (rounded to two decimal places)

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Answer:

12

Step-by-step explanation:

The numbers increase by 4 on each row.

The numbers preceding a variable

The coefficients are the number before the variable.

Finding Coefficients

All variables are multiplied by some coefficient. Sometimes those coefficients are one or another number. Take the variable 5x. The coefficient is 5. Since 5 is the number that comes before the variable, it is the coefficient. Additionally, the variable x has a coefficient of 1 because x is multiplied by 1.

Polynomial Example

Every variable within a polynomial can have a unique variable. For example, 3x⁶+5x³+2x². The first coefficient is 3, then 5, then 2. Coefficients are simply the constants that a variable is multiplied by. It does not matter what the variable is or the exponent.

The distance from the gazebo to the dock is approximately 120.45 meters.

The given problem can be solved using the concept of trigonometry.

let the distance from the gazebo to the dock be "d".

According to the question it is known that the bearing from the gazebo to the dock is S 41° W which means that the angle between the line from the gazebo to the dock and due south is 41°.

Hence the angle between the line from the gazebo to the tree and due south is =(74°-41°) =33°

Similarly, the angle between the line from the dock to the tree and due south is = 28°-x =28°-41°= -13°(As it is to the west of south).

Using the trigonometry law of sines we can write,

d/ sin(41°) = 100/ sin(33°)

d=(100/sin(33°))*sin(41°)

d= 120.45 meters

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The directional derivative of f(x, y, z) = z³ – x²y at the point (3,-1, -2) in the direction of the vector v=(-1,-4,-4) is -234/√33.

The function is f(x, y, z) = z³ – x²y

We have to find directional derivative at the point (3, -1, -2)

In the direction vector v = (-1, -4, -4)

The gradient of the function is

∇f(x, y, z) = ∂f/∂x [tex]\hat{i}[/tex] + ∂f/∂y [tex]\hat{j}[/tex] + ∂f/∂z [tex]\hat{k}[/tex]

∇f(x, y, z) = ∂/∂x(z³ – x²y) [tex]\hat{i}[/tex] + ∂/∂y(z³ – x²y) [tex]\hat{j}[/tex] + ∂/∂z(z³ – x²y) [tex]\hat{k}[/tex]

∇f(x, y, z) = -2xy[tex]\hat{i}[/tex] - x²y[tex]\hat{j}[/tex] + 3z²[tex]\hat{k}[/tex]

At the point (3, -1, 4).

∇f(3, -1, 4) = -2(3)(-1)[tex]\hat{i}[/tex] - (3)²(-1)[tex]\hat{j}[/tex] + 3(4)²[tex]\hat{k}[/tex]

∇f(3, -1, 4) = 6[tex]\hat{i}[/tex] + 9[tex]\hat{j}[/tex] + 48[tex]\hat{k}[/tex]

The length of the vector is

|v| = √[(-1)² + (-4)² + (-4)²]

|v| = √[1 + 16 + 16]

|v| = √33

To normalize the vector we have

n = (-√33/33, -4√33/33, -4√33/33)

The directional derivative is

∇f(x, y, z) · n = (6, 9, 48) · (-√33/33, -4√33/33, -4√33/33)

∇f(x, y, z) · n = -6√33/33 - 36√33/33 - 192√33/33

∇f(x, y, z) · n = (-6 - 36 - 192)√33/33

∇f(x, y, z) · n = -234√33/33

∇f(x, y, z) · n = -234/√33

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damePor lo tanto, la edad que tienes es de aproximante 14.67 años.

Si al triple de la edad que tengo, se quita mi edad aumentada en 8 años, tendría 36 años. ¿

Podemos plantear este problema como una ecuación algebraica. Si llamamos "x" a la edad que tienes, la ecuación sería:

3x - 8 = 36

Ahora, despejamos la variable "x" para encontrar su valor:

3x = 36 + 8

3x = 44

x = 44/3

.Este resultado nos indica que nuestra edad actual es de aproximadamente 14.67 años. Es importante tener en cuenta que la solución no es un número entero, lo cual puede parecer inusual para una edad, pero es una respuesta matemáticamente correcta según la ecuación planteada en el problema.

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Answer:

y = 2.25

Step-by-step explanation:

The solutions are the points of intersection of the 2 graphs.

Answer:

48 calories per (each) minute.

Step-by- Step

=

. 0.587 in scientific notation is 5.87 x 10^-1.

Scientific notation is a way of writing numbers that are very large or very small in a compact and standardized way. In scientific notation, a number is expressed as a coefficient multiplied by 10 raised to some power.

For example, the number 0.587 can be written in scientific notation as 5.87 x 10^-1. The coefficient 5.87 is obtained by moving the decimal point one place to the right, while the negative exponent -1 indicates that the decimal point has been moved one place to the left, to the tenth place.

Scientific notation is commonly used in scientific and engineering fields where very large or very small numbers are often encountered, and it allows for easier calculation and comparison of these values.

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The number 71.38 can be written in word form as "seventy-one and thirty-eight hundredths." The correct answer is option D.

In decimal notation, the number 71.38 can be broken down into its whole number and decimal parts. The whole number part is 71, and the decimal part is 0.38.

In a decimal number, the digits to the right of the decimal point represent fractions of a whole. Each digit to the right of the decimal point has a place value that is a power of 10.

In word form, the decimal part 0.38 is read as "thirty-eight hundredths." Therefore, when combined with the whole number 71, the correct word form is "Seventy-one and thirty-eight hundredths."

Therefore option D is the correct answer.

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Answer:

P = (5.4, -2.6)

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{5 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]

As the given circle has a radius of 6 units and is centred at the origin, the equation of the circle is:

[tex]x^2+y^2=36[/tex]

The formula for the equation of the tangent line to a circle with the equation x² +  y² = a² is:

[tex]\boxed{y = mx \pm a \sqrt{1+ m^2}}[/tex]

where:

To find the slope of the equation of the tangent line to the circle that passes through the point (0, -14), substitute a = 6, x = 0 and y = -14 into the formula and solve for m:

[tex]\implies -14 = m(0) \pm 6 \sqrt{1+ m^2}[/tex]

[tex]\implies -14 = \pm 6 \sqrt{1+ m^2}[/tex]

[tex]\implies \pm\dfrac{14}{6} =\sqrt{1+ m^2}[/tex]

[tex]\implies \left(\pm\dfrac{14}{6}\right)^2 =1+m^2[/tex]

[tex]\implies m^2= \left(\pm\dfrac{14}{6}\right)^2-1[/tex]

[tex]\implies m^2=\dfrac{40}{9}[/tex]

[tex]\implies \sqrt{m^2}= \sqrt{\dfrac{40}{9}}[/tex]

[tex]\implies m=\pm\sqrt{\dfrac{40}{9}}[/tex]

[tex]\implies m=\pm\dfrac{2\sqrt{10}}{3}[/tex]

The slope-intercept form of a straight line is y = mx + b, where m is the slope and b is the y-intercept.

As the slope of the given tangent line is positive, and the y-intercept is (0, -14), the equation of the tangent line is:

[tex]\boxed{y=\dfrac{2\sqrt{10}}{3}x-14}[/tex]

As point P is the point of intersection of the circle and the tangent line, substitute the tangent line into the equation of the circle and solve for x:

[tex]x^2+\left(\dfrac{2\sqrt{10}}{3}x-14\right)^2=36[/tex]

Expand the brackets:

[tex]x^2 +\dfrac{40}{9}x^2-\dfrac{56\sqrt{10}}{3}x+196=36[/tex]

Subtract 36 from both sides of the equation:

[tex]\dfrac{49}{9}x^2-\dfrac{56\sqrt{10}}{3}x+160=0[/tex]

Multiply both sides of the equation by 9:

[tex]49x^2-168\sqrt{10}x+1440=0[/tex]

Rewrite the equation in the form a² - 2ab + b²:

[tex](7x)^2-2 \cdot 7 \cdot 12\sqrt{10}x+(12\sqrt{10})^2=0[/tex]

Apply the Perfect Square formula: a² - 2ab + b² = (a - b)²

[tex](7x-12\sqrt{10})^2=0[/tex]

Solve for x:

[tex]7x-12\sqrt{10}=0[/tex]

[tex]7x=12\sqrt{10}[/tex]

[tex]x=\dfrac{12\sqrt{10}}{7}[/tex]

To find the y-coordinate of point P, substitute the found value of x into the equation of the tangent line:

[tex]y=\dfrac{2\sqrt{10}}{3}\left(\dfrac{12\sqrt{10}}{7}\right)-14[/tex]

[tex]y=\dfrac{2\sqrt{10}\cdot 12\sqrt{10}}{3\cdot 7}\right)-14[/tex]

[tex]y=\dfrac{240}{21}-14[/tex]

[tex]y=\dfrac{80}{7}-\dfrac{98}{7}[/tex]

[tex]y=-\dfrac{18}{7}[/tex]

Therefore, the exact coordinates of point P are:

[tex]\left(\dfrac{12\sqrt{10}}{7}, -\dfrac{18}{7}\right)[/tex]

The coordinates of point P to 1 decimal place are:

[tex](5.4, -2.6)[/tex]

In a rectangle, the diagonals are equal in length. So we can write the equation: AC = BD or 16 = 2x + 4. Solving for x, we get x = 6.

After leveling the sand box, the height of the sand box is 1.57 in

Volume is defined as the space occupied within the boundaries of an object in three-dimensional space.

The volume of a cuboid is expressed as;

V = l × w × h

V = 30 × 20 × 5

V = 3000 in³

After leveling, the volume decreases by 1680 in³, therefore the new volume of the sand box is

3000-1680 = 1320

Therefore the new height of the sand is calculated as;

1320 = 30 × 28 × h

1320 = 840h

divide both sides by 840

h = 1320/840

h = 1.57 in

therefore the height of the remaining sand is 1.57

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In Year 6 at Woodland Junior School, there are 90 children split into three classes of 14, 24, and 12 on the basis of there selection of sports. In 6M, 14 not chose hockey, and the rest of the class was split equally between football and netball. In 6P, 24 not chose netball, 16 chose football, and 8 choose hockey  In 6T, the ratio of football to netball to hockey was 1:2:3. The completed table is shown.

To complete the table, we need to distribute the remaining children who did not choose their sport in each class. Here's how we can calculate it

In 6M, the number of children who did not choose hockey is 27 - 13 = 14.

Since the rest of the class was split equally between football and netball, each of these two sports will have 14/2 = 7 children.

In 6P, the number of children who did not choose netball is 33 - 9 = 24.

Since twice as many children chose football as chose hockey, we can write the number of footballers as 2x, and the number of hockey players as x. Then we have 2x + x + 9 = 33, which gives x = 8. Therefore, we have 16 children who chose football, and 8 children who chose hockey. The number of children who did not choose any of these two sports is 33 - 16 - 8 - 9 = 0.

In 6T, the ratio of children who chose football to netball to hockey was 1:2:3. Let's call the number of children who chose netball as 2x, and the number of children who chose hockey as 3x. Then we have x + 2x + 3x = 30, which gives x = 6. Therefore, we have 6 children who chose football, 12 children who chose netball, and 18 children who chose hockey.

Thus, the completed table is shown.

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