Answer:
[tex]\Large\boxed{\sf{x=2}}[/tex]Step-by-step explanation:
GIVEN:
In order to solve this, you need to isolate the term x on one side of the equation.
8x+21+16x=25x+19First, combine like terms.
[tex]\Longrightarrow: \sf{8x+16x+21=25x+19}[/tex]
Solve.
8x+16x=24x
[tex]\Longrightarrow: \sf{24x+21=25x+19}[/tex]
You have to subtract by 21 from both sides.
[tex]\Longrightarrow: \sf{24x+21-21=25x+19-21}[/tex]
Solve.
[tex]\Longrightarrow: \sf{24x=25x-2}[/tex]
Subtract by 25x from both sides.
[tex]\Longrightarrow: \sf{24x-25x=25x-2-25x}[/tex]
Solve.
-x=-2
Then, you divide by -1 from both sides.
[tex]\Longrightarrow: \sf{\dfrac{-x}{-1}=\dfrac{-2}{-1}}[/tex]
Solve.
Divide the numbers from left to right.
[tex]\sf{\dfrac{-2}{-1}=2 }[/tex]
SOLUTIONS:
[tex]\Longrightarrow: \boxed{\sf{x=2}}[/tex]
Therefore, the correct answer is x=2.I hope this helps. Let me know if you have any questions.
Answer:
[tex]x = 2[/tex]
Step-by-step explanation:Given equation:
[tex]8x + 21 + 16x = 25x + 19[/tex]Combine like terms on the L.H.S and simplify the expression as needed.
⇒ [tex]8x + 21 + 16x = 25x + 19[/tex]⇒ [tex]x(8 + 16) + 21 = 25x + 19[/tex]⇒ [tex]x(24) + 21 = 25x + 19[/tex]⇒ [tex]24x + 21 = 25x + 19[/tex]Now, rewrite 25x in such a way such that 24x can be repeated on both sides. Clearly, we can rewrite 25x as 24x + x. Then,
⇒ [tex]24x + 21 = \underline{25x} + 19[/tex]⇒ [tex]24x + 21 = \underline{24x + x} + 19[/tex]Since 24x is being repeated on both sides, we can cancel it.
⇒ [tex]\bold{24x} + 21 = \bold{24x} + x + 19[/tex]⇒ [tex]21 = x + 19[/tex]Finally, subtract 19 on both sides to isolate x.
⇒ [tex]21 - 19 = x + 19 - 19[/tex]⇒ [tex]\boxed{2 = x}[/tex]Therefore, the value of x is 2.
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A culture started with 5000 becteria. after 2 hours it grew to 6500 becteria. Predict how many bacteria will be present after 18 hours. Round your answer to the nearest whole number. p=ae^kt
Answer:
About 53022 bacteria present.
Step-by-step explanation:
We can use the continuous growth formula:
[tex]\displaystyle P = A e^{kt}[/tex]
Where k is some constant.
With an initial population of 5000, it grew to 6500 after two hours.
In other words, P = 6500 when A = 5000 and t = 2:
[tex]\displaystyle (6500) = (5000)e^{k(2)}[/tex]
Solve for k:
[tex]\displaystyle \begin{aligned} 6500 & = 5000e^{2k} \\ \\ e^{2k} & = \frac{6500}{5000} = \frac{13}{10} \\ \\ \ln\left(e^{2k}\right) & = \ln\left(\frac{13}{10}\right) \\ \\ 2k & = \ln\frac{13}{10} \\ \\ k & = \frac{1}{2}\ln\frac{13}{10}\end{aligned}[/tex]
Therefore, our equation is:
[tex]\displaystyle P = \bigg{5000e}^{\dfrac{1}{2}\ln\dfrac{13}{10}t[/tex]
After 18 hours, t = 18. Hence:
[tex]\displaystyle \begin{aligned} P(18) & = \bigg{5000e}^{\dfrac{1}{2}\ln\dfrac{13}{10}(18)} \\ \\ & \approx 53022\end{aligned}[/tex]
Therefore, after 18 hours, there will be about 53022 bacteria present.
The value of 30 is between which two integers
[tex]5 < \sqrt{30} < 6[/tex]
Step-by-step explanation:[tex]Locate\ \sqrt{30}\ between\ two\ integers:\\ \downarrow\\ 5 < \sqrt{30} < 6[/tex]
I hope this helps you
:)
What are the missing numbers in this series: 10,16,21,26,31,
Answer:
38
Step-by-step explanation:
16 - 10 = 6
21 - 16 = 5
26 - 21 = 4
31 - 26 = 5
31 + 6 = 38
The next missing number is 38.
From there, continue the pattern.
Find the area of the sector.
a. 11.16 in²
b. 44.66 in²
c. 50.24 in²
d. 2.8 in²
Hi!
Circle Area Formula[tex]A=\pi r^2[/tex]
We will start by solving for the area of the entire figure.
Plugin the values into the circle area formula. We will use 3.14 for pi:
[tex]A=3.14(4)^2[/tex]
Simplify:
[tex]A=50.24[/tex]
Now, this is the area of the entire circle, but we only want that certain shaded region.
We know that a circle has a total of 360 degrees, and the shaded sector is simply 80 degrees.
We can divide to see how much of the circle is shaded:
80 / 360 = 0.22...
Now, we can take this number and multiply it by 50.24 (our answer from above) to get the area of the shaded sector:
0.22 * 50.24 = 11.16
Therefore, your answer is A.For a similar problem, see:
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given function g, which is defined by g(x)=x^3-x, what is the value of g(3)
Answer:
g(3) = 24
Step-by-step explanation:
The question is essentially asking you, "With an input of 3, what is the output of the function?" To find g(3), plug "3" into the "x" variable. Then, simplify as much as you can.
g(x) = x³ - x
g(3) = (3)³ - (3)
g(3) = 27 - 3
g(3) = 24
shannon purchased a quilt at the farmers market. the area of the quilt 9 1/3 meters. the width is 2 4/5. what is the length of the rug in meters
length = 3 1/3 m
hope it helps...!!!
Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of 20 years. The salvage value is $4,000.00. The book value at the end of year 2 is
The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.
What is the book value at the end of year 2?Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.
Sum-of-the-year digits = (remaining useful life / sum of the years ) x (Cost of asset - Salvage value)
Depreciation expense in year 1:
Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210
Undepreciated life of the asset = 20
(20 / 210) x ($79,600 - 4,000) = 7200
Depreciation expense in year 2:
19 / 210 x ($79,600 - 4,000) = 6840
Book value = 79600 - 7200 - 6840 = $65,560
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Evaluate 5(a•4)+ b, 1 when a=-andb=12. 3 O A) 14 3 OB) 17 2 O C) 18 3 OD) 27
HELP ASAP
Evaluate 5(a•4)+ b, when a = 1/3 and b=12
The Answer is
C. 18 2/3hope it's help hshshs
Complete the equation of the line through (-10,-7)(-5,−9)
Pls Help Me
Pls show your work pls and thank you
Answer:
DWest I think
Step-by-step explanation:
Someone else asked this and this is what they think and it seems right
Find the area of this trapezoid. Be sure to include the correct unit in your answer.
Answer: [tex]92 \text{ yd}^2[/tex]
=======================================================
Work Shown:
[tex]A = \frac{h(b_1+b_2)}{2}\\\\A = \frac{8(19+4)}{2}\\\\A = \frac{8(23)}{2}\\\\A = \frac{184}{2}\\\\A = 92\\\\[/tex]
The [tex]b_1[/tex] and [tex]b_2[/tex] are the parallel bases, while h is the height perpendicular to each base.
The units are in square yards, abbreviated as [tex]\text{yd}^2[/tex]
Think of a 1 yard by 1 yard square that has an area of [tex](1 \text{ yd})*(1 \text{ yd}) = (1)^2(\text{yd})^2 = 1 \text{ yd}^2[/tex]
The side of 9 yards is never used and put in there as a distraction.
Sue has $500 in an account for 9 years at a compound rate of 7.5%. How much does she have?
Answer:
she has about $3750 in her acount.
Step-by-step explanation:
hope this helps you!
Which of the following functions is graphed below?
Answer:
b
Step-by-step explanation:
Does anyone know how to get free answers? I ran out, I have a lot of points I just need more free answers again
Answer: I believe that by helping or answering others you can get get questions, but I do know there is a limited amount of questions being able to ask before paying monthly. Hope this helps
Answer:
What you have to do is answer peoples question to gain more
Step-by-step explanation:
Magda and Nicholas each purchase almonds and cashews for their trail mix recipes as shown.
Almonds
(pounds)
Cashews
(pounds)
Total Cost
(dollars)
Magda 6 1 $73.60
Nicholas 4 3 $78.00
Click on each blank to enter the cost per pound of almonds and cashews.
Answer:
almonds: $10.20
cashews: $12.40
Step-by-step explanation:
what’s the answer to this
The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year.
8.40, 8.35, 8.50, 8.40, 8.90, 8.20, 8.50, 8.30, 8.50, 8.50, 8.75, 8.30, 8.10, 8.55
Which box plot best represents this data?
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and the interquartile ranges approximately between 8.3 and 8.5 and the median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.7 and interquartile ranges approximately between 8.3 and 8.6 and median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.2 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.6 and median is approximately at 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.5.
To create the dot plot you will list the data in order and use the given numbers to create the box plot.
8.10, 8.20, 8.30, 8.32, 8.34, 8.50, 8.50, 8.50, 8.55, 8.60, 8.60, 8.65, 8.65, 8.90
Lower extreme: 8.10
Upper extreme: 8.90
Median: 8.50
1st/lower quartile: 8.32
3rd/upper quartile: 8.60
Please see the attached picture for the boxplot.
The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 1000
years?
Answer:
258.65 mg will be remain after 1000 years
Step-by-step explanation:
This problem can be solved several ways, I prefer the natural log approach for reasons I won’t go into here:
Activity final = Activity initial e^-kt, where
k = the decay constant, = ln2/half life = 0.693/1590, = 0.000436/year
t = the decay time, in the same time base as k
The problem can be worked in units of activity, mass, or number of atoms.
400 x e^-0.000436 x 1000 = 400 x e^-.436 = 258.65 mg
you can check this by estimating. There is about 2/3 of a half life, so there should be more than 200 mg, which would be the value at one half life.
Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross the x-axis at the zero.
Answer: See below
Step-by-step explanation:
To find the factor,
f(x) = 0
[tex]\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}[/tex]
So,
x = 0 multiplicity 2
x = -6 multiplicity 1
x = 6 multiplicity 1
For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis
Therefore,
x = 0 multiplicty 2, Touch
x = -6 multiplicty 1, Cross
x = 6 multiplicty 1, Cross
Find the following in radians. You
should be able to do this without a
calculator.
cos-1 0
=
TT
?
By using the definition of the inverse cosine function, we will see that:
[tex]cos^{-1}(0) = pi/2[/tex]
How to complete the expression?
We have the expression:
[tex]cos^{-1}(0) = \frac{pi}{?}[/tex]
Remember that if:
[tex]cos(x) = y\\\\cos^{-1}(y) = x[/tex]
Then, in what do we need to evaluate the cosine function to get an output equal to zero?
[tex]cos( pi/2) = 0[/tex]
Then:
[tex]cos^{-1}(0) = pi/2[/tex]
Then we can replace the question sign with a 2.
If you want to learn more about the cosine function, you can read:
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Here is a right angled triangle work out the value of x using trigonometry
[tex]~~~~~\sin 30^{\circ} = \dfrac{\text{Perpendicular}}{\text{Hypotenuse} }\\\\\\\implies \dfrac 12 = \dfrac{8}x\\\\\\\implies x = 8\cdot2\\\\\\\implies x = 16 ~ \text{cm.}[/tex]
The measure of the side length is 16 cm after applying the sin ratio which is the side opposite to the angle/hypotenuse.
What is a right-angle triangle?It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.
It is given that:
A right-angle triangle is shown in the picture.
To find the side length of the hypotenuse apply the sin ratio
sin30 = side opposite to the angle/hypotenuse
1/2 = 8/x
x = 8(2)
x = 16 cm
Thus, the measure of the side length is 16 cm after applying the sin ratio which is the side opposite to the angle/hypotenuse.
Learn more about the right-angle triangle here:
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#SPJ2
MY SISTER NEEDS HELP IN MATH...
Answer:
[tex]b. \: 16[/tex]
Step-by-step explanation:
Divide the numbers ⬇
16 ÷ 4 = 4[tex](4 + 2) \times 2 + 4[/tex]
Add the numbers ⬇
4+2=6[tex]6 \times 2 + 4[/tex]
Multiply the numbers ⬇
6 x 2 = 12[tex]12 + 4[/tex]
Add the numbers ⬇
[tex]12 + 4 = 16[/tex]
OPTION B IS RIGHT :)
hope this helps!! Mark me brainliest please!
Answer: B. 16
Step-by-step explanation:
Hope this helps!
Which pairs of polygons are similar?
Select each correct answer.
Answer:
Two polygons are similar if their corresponding angles are congruent and the corresponding sides have a constant ratio (in other words, if they are proportional). Typically, problems with similar polygons ask for missing sides.
Step-by-step explanation:
this is the correct answer
Tori invests $1,500 into the stock market which earns 9% per year. In 20 years, how much will Tori's investment be worth if interest is compounded semiannually (twice a year)?
A model satellite has a scale of 1 cm : 3 m. If the real satellite is 18 m wide, then how wide is the model satellite?
A. 54 cm
B. 1 cm
C. 6 cm
D. 15 cm
What is the length of the diameter of a circle with a radius that is 13 centimeters? cm
Answer:
13 this is the ansewer to this
Solve the equation 25z2 + 140 = −29 by using square roots.
A. z = ±13/5
B. z = ±29/5
C. no real solutions
D. z = ±7/5
Answer:
Option C, no real solutions
Step-by-step explanation:
Step 1: Subtract 140 from both sides
[tex]25z^2 + 140 = -29[/tex]
[tex]25z^2 + 140 -140 = -29 -140[/tex]
[tex]25z^2 = -169[/tex]
Step 2: Divide both sides by 25
[tex]\frac{25z^2}{25} = \frac{-169}{25}[/tex]
[tex]z^2 = -6.76[/tex]
Step 3: Square root both sides
[tex]\sqrt{z^2} = \sqrt{-6.76}[/tex]
Since we are trying to square root a negative it would cause imaginary solutions so in conclusion we have no real solutions.
Answer: Option C, no real solutions
Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling via a chain. Find an expres- sion for the tension in the string and the chain.
a. The expression for the tension in the string is T = mg
b. The expression for the tension in the chain is T = 2mg
To solve the problem, we need to know what tension is.
What is tension?This is the opposing force in a stretched material.
a. Tension in the stringThe expression for the tension in the string is T = mg
Since the string supports the weight of the object, the tension in the string equals the weight of the particle.
Let
T = tension in sring and W = weight of particle = mg where m = mass of particle and g = acceleration due to gravitySo, T = W
T = mg
So, the expression for the tension in the string is T = mg
b. Tension in chainThe expression for the tension in the chain is T = 2mg
Since the chain supports both strings, the tension in the chain equals the tension in both strings.
Let
T' = tension in chain and T = tension in each stringSo, T' = T + T
T' = 2T
T' = 2W
T' = 2mg
So, the expression for the tension in the chain is T = 2mg
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four dice are thrown simultaneously. what will be the probability that all of them have the same face ?
Answer:
1/216
Step-by-step explanation:
A dice (assuming it is from 1-6) has 6 faces. There are 4 dices.
equation will be
6*6*6=answer
Multiply 6 three times by itself because there are 4 dices. That is because One die would be 1
Two would be 1/6
Three would be 1/36
And four would be the ...
Asnwer=216
Which function is represented by the graph below?
Answer:
[tex]f(x)=2^x[/tex]
Step-by-step explanation:
Exponential function:
[tex]f(x)=a(b^x)+c[/tex]
Step 1. Find a, y-intercept
Step 2. Find b, slope
Step 3. Find c, horizontal asymptote
a = 1
m = (y₂ - y₁)/(x₂ - x₁)
m = (3 - 1)/(1 - 0) = 2/1
b = 2
c = 0
[tex]f(x)=1(2^x)+0\\f(x)=2^x[/tex]