A 2.5 kg block is initially at rest on a horizontal surface. A horizontal force of magnitude 6.0 N and a vertical force are then applied to the block (Fig. 6-17). The coefficients of friction for the block and surface are ms 0.40 and mk 0.25. Determine the magnitude of the frictional force acting on the block if the magnitude of is (a) 8.0 N, (b) 10 N, and (c) 12 N.

Answer:

here you go -

Explanation:

try using the paraphrasing tool website!  

The sun makes three unique sorts of electromagnetic radiation, which is considered hurtful to people. The light made incorporates X-beams, gamma beams, and bright light. These beams are unsafe as a result of their high energy esteems, which are brought about by their enormous frequencies. The gases of Earth's air assimilate the high energy radiation, making their atoms move quicker, yet none of the light radiation arrives at Earth's surface. Fortunately for us, the high recurrence of gamma beams and X-beams, also as most bright light, can't enter Earth's environment and doesn't arrive at Earth's surface. In the event that those hurtful beams arrived at Earth's surface it would make the planet plain to earth's

The  4.7 g/cm3 is  the density of the substance.

What is density ?

How tightly something is packed can be used to gauge a material's density. Formally, it is defined as the mass per unit of volume. Formula for Density or Density Symbol: D D = m/V, where m is mass and V is volume, stands for density.

What is mass ?

The most basic characteristic of matter, it is one of the fundamental quantities in physics. As a way to gauge how much matter is there in a body, we might use the term mass. Kilograms are the SI unit of mass (kg).

density = mass of sample/ volume of sample

mass = 1.5 kg = 1500 g

volume = W*L*H

Vol = 3.2*17.1*5.8 cm3 = 317.376 cm3

Now,

D = mass/V = 1500/317.376

D = 4.726255 g/cm3

=4.7 g/cm3

Therefore, 4.7 g/cm3 is  the density of the substance.

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According to the given statement  If suddenly a load is dumped into the cart so that the cart's mass is doubled The acceleration slows.

which speaks of the rate of change in time of the speed and direction of motion. Something is said to be accelerating when it starts to move faster or slower. Even if the speed slows down, motion on a circle accelerates because the direction is constantly changing.

Any process in which the velocity changes is referred to as acceleration. There are only two ways to speed up because velocity consists of both a speed and a direction.

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Answer:

The total amount of energy necessary to carry out this process is 22600 joules (J).

Explanation:

This is because the heat of vaporization (the energy required to change the state of water from liquid to gas) of water is 2260 J/g. Since 10.0 g of water is being heated, the total amount of energy needed is 10.0 g * 2260 J/g = 22600 J.

Since I0 is the lowest sound intensity that a person with normal hearing can detect, it is chosen as the reference point. Given that log10 1 = 0, the decibel level of a sound with an intensity of 10–12 W/m2 is = 0 dB. In other words, the human hearing threshold is zero decibels.

The reference value I0 is 10–12 W/m2, which corresponds to the threshold of hearing intensity at 1000 Hz. The Sound Intensity Level, or SIL for short, is the intensity decibel scale. The related sign, like in our text, is LI.

Much more frequently than sound intensities in watts per square meter, sound intensity levels are expressed in decibels (dB). Both the scientific literature and the public media use decibels as their preferred measurement unit. The rationale behind this decision of units has to do with how we hear. There is a reference intensity, I0 = 1012 W/m2. The lowest or threshold intensity of sound that a person with normal hearing can perceive at a frequency of 1000 Hz is specifically known as I0. The degree of sound intensity is not the same as the intensity. is a unitless quantity that informs you of the sound level in relation to a predefined standard (1012 W/m2, in this case), as it is defined in terms of a ratio.

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The speed of the satellite in terms of kilometers per second is 455.89 km/sec

The speed of the satellite = 17,000 miles/hour

The speed of the satellite can be converted into kilometers/second by converting the miles into kilometers and then the hour into seconds

               1 miles = 1.609 km

Thus, the speed of the satellite,

          = 17,000 x 1.609 km/hour

          = 27,353 km/hr

Then, the speed of the satellite in one second is

          1 hour = 60 seconds

Thus, the speed of the satellite,

            = 27,353 x 1/60 km/sec

            = 455.89 km/sec

Thus, the speed of the satellite is 455.89 km/sec

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Answer:

The coefficient of friction between the surface of the block is 1/4

The correct option is C ; Water vapor , Water vapour is water that is gaseous rather than liquid. It can be generated by either evaporation or sublimation.

Water vapour, unlike clouds, fog, or mist, which are just suspended particles of liquid water in the air, cannot be seen since it is in gaseous form.

Water vapor has the same chemical formula as regular water - H2O - but the water molecules in vapor interact with each other less and are not as organized as they are in water and ice. Pressure, temperature, and relative humidity all influence whether water is liquid or gas.

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Answer:

A

C

D

B

Explanation.

At point A The body is at rest so k.E is zero but the height is maximum so that p.E is max.

It is False that  Visual inspection of the brake drum friction surface is not required, only measure drum diameter.

No matter whether the vehicle is moving forward or backward, drum brakes produce uniform braking force. Drum brakes produce the same amount of braking force in both directions, which explains this. This kind is typically utilized for the passenger car's rear brakes.

Unusual brake pedal sensation is one of the first indications when drum brakes are damaged or failing. Excessive brake drum wear might result in vibrations that can be felt in the pedal. When you press the pedal, any trembling or pulsating brought on by worn drums will be audible.

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The Barbie would be moving with speed 27.69 ft/s at the bottom of the path.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Mass of the Barbie = 0.23 kg.

Initial height of the Barbie: h= 11 ft 11 inches = ( 11 + 11/12) feet = 11.92 feet.

Acceleration due to gravity: g = 32.17 ft/s²

Hence, the speed of the Barbie at the bottom of the path = √(2gh)

= √( 2 × 32.17 ×11.92) ft/s

= 27.69 ft/s.

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(1) The frequency of the oscillation is 0.32 Hz.

(2) The period of the oscillation is 3.13 seconds.

The period of the wheel's oscillation is the time taken for the wheel to make one complete oscillation.

The period of an oscillatory motion is the reciprocal of the frequency of the oscillation.

The frequency of the oscillation is the number of cycles completed by the oscillatory object in a given second.

The frequency of the wheel undergoing oscillatory motion is calculated by using the following formula.

f = ω / 2π

where;

f = ( 2 rad/s ) / 2π

f = 0.32 Hz

The period of the oscillation is calculated as follows;

T = 1 / f

T = 1 / 0.32 s

T = 3.13 seconds

Thus, the period of oscillation and frequency of the oscillation are inversely proportional.

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A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. Minimum coefficient of static friction is required 13.56.

To find the minimum coefficient of static friction required, we need to calculate the centrifugal force acting on the child and compare it to the force of friction.

The centrifugal force acting on the child is given by:

= Fc

= m * r * w^2

where

= m

= 50.0 kg (mass of child)

= r

= 2.70 m (radius of the merry-go-round)

= w

= 3.95 rad/s (angular velocity)

So, Fc = 50.0 kg * 2.70 m * (3.95 rad/s)^2

= 6629.775 N

The force of friction acting on the child is given by:

= Ff

= friction coefficient * normal force

where

friction coefficient = minimum coefficient of static friction required (unknown)

= normal force

= m * g

The normal force is equal to the weight of the child, which is

= m * g

= 50.0 kg * 9.8 m/s^2

= 490 N

So, Ff = friction coefficient * 490 N

To find the minimum coefficient of static friction, we need to set Ff equal to Fc and solve for the friction coefficient:

friction coefficient = Ff / N

friction coefficient = 6629.775 N / 490 N

= 13.56

So the minimum coefficient of static friction required is 13.56.

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The height of the hill can be calculated using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (9.8 m/s2), and h is the height of the hill. So, solving for h, we get h = PE/mg = 1000 J/ (60.0 kg*9.8 m/s2) = 10.2 m.

Therefore, the height of the hill is 10.2 m.  The potential energy of an object is the energy it possesses due to its position or state. As the object moves, its potential energy can be converted into kinetic energy, or the energy it has due to its motion. In this case, the rollerblader is on top of the hill, so it has potential energy due to the height of the hill.  

The formula for potential energy is PE = mgh, which means that the potential energy is equal to the mass multiplied by the acceleration due to gravity multiplied by the height. In this case, the mass is known to be 60.0 kg, and the potential energy is known to be 1000 J. By using the formula and substituting in the known values, the height of the hill can be calculated.

The height of the hill is determined to be 10.2 m, which is relatively small. This means that the hill is not too steep, and the rollerblader would not have to use a lot of energy to go down it.

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Explanation:

This intense stretching method uses bouncing movements to push your body beyond its normal range of motion. Whereas static stretches are performed slowly and gradually, the ballistic method stretches muscles much farther and faster. You can do many of the same stretches as ballistic or static stretches.

According to Newton's law of gravitation, the new gravitational force will be F/9

It states that, the force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. That is,

F = GMm/d²

Where

The magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d can be expresses as follow

f = GMm/(3d)²

f = GMm/9d²

f = GMm/d² × 1/9

Since GMm/d² = F

f = F × 1/9

f = F/9

Therefore, the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d is F/9 Newton

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According to given data the volume of the unknown sample is 52. 5 mL - 47. 0 mL = 5.5 ml.

One typical style of lab glassware is graduated cylinders. They are a long, cylindrical vase with graduations marking the volume of liquid they can hold. Spouts are frequently included to make pouring easier.

Your graduation will go down in history as a significant event; it will stand for development, change, and embarking on new experiences. Celebrate your accomplishments thus far and be grateful for the memories this phase of your schooling has provided you.

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The centripetal acceleration of the aorta in which the blood travels with the speed of 0.30 m/s is 2.2 m/s²

The diameter of the aorta = 4.1 cm

                                           = 4.1 x 10⁻² m

The speed of the blood through the aorta = 0.3 m/s

The centripetal acceleration of the blood passing through the aorta can be found using the formula,

                     a = v²/r

where a is the centripetal acceleration

           v is the speed of the blood passing through the aorta

           r is the diameter of the aorta

Let us substitute the known values in the above equation, we get

         a = 0.30² / (4.1 x 10⁻²)

            = 0.09 /  (4.1 x 10⁻²)

            = 0.022 x 10²

            = 2.2 m/s²

Therefore, the centripetal acceleration of the aorta is 2.2 m/s²

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Answer:

2.995 seconds

Explanation:

We can use this kinematics equation to evaluate time.

[tex]y=v_0t-\frac{1}{2}gt^2[/tex]

Lets solve for [tex]t.[/tex]

Combine [tex]\frac{1}{2}[/tex] and [tex]gt^2[/tex].

[tex]y=v_0t-\frac{gt^2}{2}[/tex]

Subtract [tex]y[/tex] from both sides.

[tex]0=v_0t-\frac{gt^2}{2}-y[/tex]

[tex]0=-\frac{gt^2}{2} -v_0t-y[/tex]

Multiply both sides of the equation by -1.

[tex]0=\frac{gt^2}{2} -v_0t+y[/tex]

Multiply both sides of the equation by 2.

[tex]0=gt^2 -2v_0t+2y[/tex]

Use the quadratic formula to solve for t.

[tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]

[tex]a=-g\\b=2v_0\\c=-2y[/tex]

Solution 1 Steps

[tex]t=\frac{-2v_0+\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -8gy} }{-2g}[/tex]

Solution 2 Steps

[tex]t=\frac{-2v_0-\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -8gy} }{-2g}[/tex]

One of these solution will most likely lead to a negative answer. The solution that gives a positive answer is correct. Lets enter our values into both equations to see which one is correct.

We can assume the initial velocity is 0.

We are given

[tex]v_0=0\\g=-9.81\\y=44[/tex]

Lets try the first solution.

[tex]t=\frac{-2*0+\sqrt{(4*0^2) -(8*-9.81*44)} }{-2*-9.81}[/tex]

[tex]t=\frac{0+\sqrt{0 -(8*-9.81*44)} }{-2*-9.81}[/tex]

[tex]t=\frac{0+\sqrt{0 --3453.12} }{-2*-9.81}[/tex]

[tex]t=\frac{\sqrt{3453.12} }{19.62}[/tex]

[tex]t=2.995[/tex]

Our first solution was positive so there is no need to check the second solution.

The pressure at position y to be 10.0, which is the air pressure when the piston is at position y.

If the original pressure in the cylinder was 1.0, and the piston is pulled out from position x to position y without changing the temperature of the enclosed air, the air pressure at position y will be increased. This is due to the change in volume of the cylinder as the piston is pulled out. As the volume increases, the number of air molecules inside the cylinder also increases, which causes an increase in the air pressure.

To calculate the air pressure when the piston is at position y, we can use the gas law known as Boyles' Law, which states that the pressure and volume of a gas are inversely proportional. Therefore, if the volume increases, the pressure will decrease, and if the volume decreases, the pressure will increase.

Where P₁ is the initial pressure, V₁ is the initial volume, P₂ is the final pressure, and V₂ is the final volume.

By substituting the given values, we have:

Where V is the change in volume due to the movement of the piston.

Solving for P₂:

As we know, the original pressure is 1.0, and if we multiply it by 10, we will get the final pressure at position y to be 10.0, which is the air pressure when the piston is at position y.

This question is not written in a proper manner. The corrections are:

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Answer:

1: As the substance’s thermal energy increases, the kinetic energy of its particles increases, and vice versa.

2: Its molecules move around more quickly, so there is more space between them, making it less dense than the air above it.

3: Warmer sauce at the bottom of the pot is less dense, so it rises, forcing cooler sauce down, where it is warmed.

4: Hot soup warms the bowl where it sits.

5: transfer of thermal energy through infrared waves

Explanation:

This is correct for the Thermal Energy Transfer Quick Check

A simmering pot of spaghetti sauce provides an excellent illustration of convection currents because the process of heating the sauce causes hot molecules to rise and cool molecules to sink. This creates a circular motion known as a convection current.

When the pot is placed on a hot stove, the heat from the burner is transferred to the bottom of the pot, which in turn heats the sauce. As the sauce heats up, the molecules nearest to the heat source become hotter and lighter. These hot, lighter molecules rise to the top of the pot, creating a convection current. As they reach the surface, they cool down, become heavier, and then sink back down to the bottom of the pot.

This process of hot molecules rising and cool molecules sinking creates a circular motion that evenly distributes the heat throughout the sauce, ensuring that it cooks evenly. The convection currents in the pot are also responsible for the bubbles that rise to the surface of the sauce, releasing trapped steam and preventing the pot from boiling over.

In conclusion, a simmering pot of spaghetti sauce illustrates convection currents because it shows how hot molecules rise and cool molecules sink, creating a circular motion that evenly distributes heat and ensures that the sauce cooks evenly.

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Answer:

True

Explanation:

In the definition of weight, W = mg, the mass m refers to an inertial mass.

Explanation:

When you brake all of a sudden, if you are not wearing a seat belt, your face is bound to hit against the windshield. The seat belt stops this inertia. If your car is going at 60 MPH, your face will be saved from the impact. ... There are many accidents where the driver is thrown out of the car and this can be deadly.

Answer:

The two resistors should be connected in series.

(I assume that the question is stating the electrical power consumed by the resistors)

Explanation:

Think about the formula P = V^2 / R

For the electrical power consumed to be a minimum, we must let V be as small as possible.

For small V, between a series and a parallel connection, series is the correct connection as the combined potential difference (pd) for the two resistors is equal to the electromotive force (emf) of the battery.

However, for parallel connections, the combined pd for the two resistors is equal to twice the emf of the battery. (Each resistor will have a pd equal to the emf of the battery)

With lower total V, with the same R, power P consumed will decrease.

Explanation:

[tex]kinetic \: energy = \frac{1}{2} m {v}^{2} \\ but \: {v}^{2} = {u}^{2} + 2gh \\ {v}^{2} = 0 + (2 \times 10 \times 2) \\ v = 6.32 \: m {s}^{ - 1} \\ k.e = \frac{1}{2} \times 2.5 \times 6.32 {}^{2} \\ = 50 \: joules[/tex]

[tex]potential \: energy = mgh \\ = 2.5 \times 2 \times 10 \\ = 50 \: joules[/tex]

Using Newton's 1st law of motion. In the absence of external force, the isolated object maintains its condition of uniform motion. Thus, the spaceship keeps its constant speed throughout all of time. Option D is correct.

According to Newton's first law, unless pushed to alter its condition by the operation of an external force, every object will continue to be at rest or even in uniform motion along a straight line. Inertia is the propensity to maintain balance in a condition of motion.

The word "inertia" is derived from the Latin word iners, which meaning idle or sluggish. Inertia is the name for any physical object's opposition to a velocity change. Changes in the item's motion's direction or speed fall under this category.

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The expression for drag force that is proportional to the speed of the object is known as linear drag, while the expression that is proportional to the square of the speed is known as quadratic drag.

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The radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.

The radius of the event horizon of a black hole is known as the Schwarzschild radius and it is a function of the mass of the black hole. The Schwarzschild radius is given by the formula:

r = 2GM/c^2

where

r = radius of the event horizon (in meters)

G = gravitational constant (6.674 x 10^-11 N*(m/kg)^2)

M = mass of the black hole (in kg)

c = speed of light in a vacuum (2.998 x 10^8 m/s)

For a 10-Solar-mass black hole, we can use the mass conversion factor 1 Solar mass = 1.989 x 10^30 kg.

M = 10 x 1.989 x 10^30 kg

Now, we can substitute the values into the formula

r = 2 x 6.674 x 10^-11 x M/ (2.998 x 10^8)^2

r = 2GM/c^2 = 2 x 6.674 x 10^-11 x (10 x 1.989 x 10^30) / (2.998 x 10^8)^2

r = 2.95 x 10^3 m = 2950 kilometers

So, the radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.

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