A 250. cm3 sample of neon is collected at standard temperature and pressure. Assuming the volume remains constant, what would be the pressure of the neon at 44.0°C?
a) 118 b)87.2 c) 0.00 d)290

the element that was reduced in this redox reaction is Fe

A redox reaction, also known as an oxidation-reduction or redox reaction, involves the exchange of electrons between chemical entities (the atoms, ions, or molecules involved in the reaction). Redox reactions occur everywhere; they are involved in the burning of fuels, the rusting of metals, and even the processes of photosynthesis and cellular respiration.Some species experience oxidation, or the loss of electrons, while others experience reduction, or the gain of electrons, during a redox process. Take rust, which results from the interaction of iron and oxygen:The third selection from the options presented above is the right response. The element that was reduced in the described redox reaction was Fe, or iron. It now has a neutral charge after having its +3 charge lowered.

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A vitamin supplement is a dietary supplement containing one or more essential vitamins, typically in the form of a pill, capsule, or tablet.

What are Vitamins?

Vitamins are a group of organic compounds that are essential for normal cellular functioning. They are required for a wide range of bodily functions, such as metabolism, growth, development, and immunity. They can be found naturally in food sources or taken as dietary supplements. There are 13 essential vitamins, including vitamins A, C, D, E, K, and the B vitamins.

The mass of fluorine that can be recovered from the vitamin is 455.9 mg (50.51% of 900 mg). The mass of iron that can be recovered from the vitamin is 444.1 mg (the remaining amount of 900 mg).

To calculate this, we need to use the percent composition formula:

Mass of Element = (Percent Composition/100) x Total Mass

Mass of Fluorine = (50.51/100) x 900 mg = 455.9 mg

Mass of Iron = (100 - 50.51)/100 x 900 mg = 444.1 mg.

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B) Rubidium is a highly reactive element.

Rubidium is a highly reactive element due to its low ionization energy, which makes it easily lose electrons and form compounds. It is considered to be one of the most reactive alkali metals.

When it comes into contact with water or air making rubidium is highly flammable. It can ignite spontaneously in the air and reacts violently with water to produce rubidium hydroxide and hydrogen gas.

Being noticeably more reactive than potassium but less so than cesium, it is likely to react with substances that are dangerous with sodium or potassium more forcefully. When rubidium is exposed to air or dry oxygen, it ignites, mostly generating oxide.

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The process orcas uses the oxygen is from the blowholes. the blow holes are situated on the top of of the head and it uses oxygen from their.

The whales and the humans uses the lungs for the respiration or to get oxygen required for the breathing. the orcas uses the oxygen from the blow holes situated at the top of the head. The orcas lives under the water and when the orcas dive in the water they have ability to hold the breath for at the time . but this is not good for the health . it is be very stressful for the body.

Thus, the process do the orcas uses oxygen for the intake is the from the blow holes.

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Answer: The volume of 0.640 grams of [tex]O_{2}[/tex] gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of [tex]O_{2}[/tex] gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of [tex]O_{2}[/tex] (molar mass = 32.0 g/mol) is as follows.

[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol[/tex]

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L[/tex]

Thus, we can conclude that the volume of 0.640 grams of [tex]O_{2}[/tex] gas at Standard Temperature and Pressure (STP) is 0.449 L.

The attractive force (intermolecular force) between these two molecules has most likely been produced by dipole-dipole interactions.

The correct option is B.

Intermolecular forces are forces of attraction or repulsion that act between atoms and other kinds of nearby particles, such as atoms or ions, to mediate interactions between molecules.

Some intermolecular forces are:

Considering the given molecules in the diagram:

Each molecule is made up of two distinct components, and as a result, each molecule has a constant bond dipole.

The attractive forces are dipole-dipole attractions because the dipoles do not cancel. The dipole-dipole attractions are substantially stronger than the dipole-induced dipole and London dispersion forces.

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[Ar]4s23d6 the electron configuration of the metal ion in Fe(NO3)3.

The noble gas krypton, which is isoelectronic with As arsenic 3 ion (As3), is isoelectronic with [Ar]3d104s2sp6 because it has gained three electrons.

Transition-metal ions are frequently referred to as having dn configurations because their valence electrons are mostly found in d orbitals. For instance, it is claimed that the Co3+ and Fe2+ ions have a d6 configuration.

The number of protons in the atomic nuclei of arsenic, abbreviated As, is 33. 33 electrons would likewise be present in a neutral As atom.

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you need 3.00 mL of the 4.00 M sulfuric acid solution to make 12.0 mL of a 0.50 M solution.

Solution is a way to solve a problem or address an issue. It can involve finding an answer or coming up with a strategy to tackle a difficult situation. Solutions can be found through research, brainstorming, trial and error, or by using existing resources.

To solve this problem, we must use the equation:
V1C1 = V2C2
Where V1 is the volume of the concentrated solution, C1 is the concentration of the concentrated solution, V2 is the volume of the dilute solution, and C2 is the concentration of the dilute solution.
In this case, V1 is the volume of the 4.00 M solution that we need, C1 is 4.00 M, V2 is 12.0 mL, and C2 is 0.50 M.
Plugging these values into the equation, we can solve for V1:
V1 = (V2C2) / C1
V1 = (12.0 mL)(0.50 M) / (4.00 M)
V1 = 3.00 mL

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The two quantities in this module for which we will develop unit factors to do dimensional analysis with chemical substances are mass (usually measured in grams) and volume (usually measured in liters).

Unit factors are developed to convert between two different units of measurement, in this case, mass and volume. We can do this by multiplying the given value by the appropriate unit factor to convert the given value from one unit to the other. For example, if we are given a mass of 10 grams, we can convert this to liters using the unit factor 1 gram = 1 liter. Thus, 10 grams = 10 liters.

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the oxidation number of the oxygen atoms in h2o2 and the oxidation number of the oxygen atoms in o2 is -1 and 0

An atom's oxidation number (also known as oxidation state) in a chemical is an amount that represents the amount of electron density gained or lost by the atom during in the formation of the compound. In general, the oxidising number of an element in a compound can be determined using the following rules: n element's oxidising number is null whenever it is unrestricted (uncombined). The oxidation number of a polyatomic ion is equivalent towards the ion's charge. We can use these rules to calculate the oxidation number of the oxygen atoms in H2O2 and O2: In H2O2, the oxidation number of the oxygen atoms is -1. This is because the compound is neutral and the hydrogen atoms have an oxidation number of +1, so the oxygen atoms must have an oxidation number of -1 in order for the sum of all the oxidation numbers to be zero. In O2, the oxidation number of the oxygen atoms is 0. This is because the compound is a diatomic molecule and the oxidation number of the free element oxygen is 0.

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Answer:

The earth would absorb more sun and temperatures would be a lot higher.

Explanation:

The final concentration of the mixture depends on the value of x.

Value is the worth of something. It can refer to the monetary worth of an item or service, the usefulness of something, or the importance of an idea, belief, or experience. Value is a subjective concept and can vary from person to person. Generally, it is the positive attributes that an individual or group associates with something that determines its value. The economic concept of value is based on the idea that the value of a good or service is determined by its cost, supply, and demand.

The final concentration of the mixture is equal to:
(200 mL x 10%) + (x mL x 40%) / (200 mL + x mL)

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Answer:No of moles of potassium sulfide (K2S)=0.61671moles

Explanation:

No of moles is given as   Mass/ molar mass

Here Mass of potassium sulfide (K2S) =68 grams

Molar mass of potassium sulfide (K2S)  = 39.0983 x 2 + 32.065 =110.2616 g/mol

No of moles =68 grams /110.2616 g/mol

=0.61671moles

Answer:No,it’s not a heterogeneous

Explanation:

Answer:

2,7

Explanation:

Two in the first shell and 7 in the outer and last shell.

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The number of moles of MgCO3 that is present in the given mass of magnesium carbonate is 2.99 moles.

The number of moles can be defined as the ratio of given mass over molar mass. The chemical that is given is magnesium carbonate having molar mass of 84.314 g/mol and the given mass of the same is 252.939 grams.

The formula for number of moles that is 'n' can be given as follows:

n= m/M where m is the given mass and M is the molar mass.

Substituting the values,

n= 252.939 grams /84.314 grams/mol

n=2.99 moles

Therefore, the number of moles of MgCO3 is 2.99 moles.

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Answer:

I have for Decompostion

Explanation:

A decomposition reaction occurs when one reactant breaks down into two or more products. It can be represented by the general equation: AB → A + B. In this equation, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction

We need 0.127 L of 0.450 M Na3PO4 to precipitate all the lead(II) ions from 190.0 mL of 0.600 M Pb(NO3)2.

This is a precipitation reaction. To determine the amount of Na3PO4 needed to precipitate all the lead(II) ions, we need to find the number of moles of Pb(NO3)2 present in the solution.

First, we'll use the formula to convert the volume of the solution to liters:

190.0 mL * (1 L/1000 mL) = 0.19 L

Next, we'll use the molarity formula to find the number of moles of Pb(NO3)2 in the solution:

molarity (M) = moles of solute / liters of solution

moles of Pb(NO3)2 = 0.600 M * 0.19 L = 0.114 moles

Now we can use the balanced equation for the reaction to find how many moles of Na3PO4 are needed to react with all 0.114 moles of Pb(NO3)2

Pb(NO3)2 + 3Na3PO4 -> Pb3(PO4)2 + 6NaNO3

We can see that 2 moles of Pb(NO3)2 react with 3 moles of Na3PO4

So we need 0.114 moles/ 2 moles = 0.057 moles of Na3PO4

Finally we can use the molarity formula again to find the volume of 0.450 M Na3PO4 required

Molarity (M) = moles of solute / liters of solution

0.057 moles = 0.450 M * V

V = 0.057 moles / 0.450 M = 0.127 L

So we need 0.127 L of 0.450 M Na3PO4 to precipitate all the lead(II) ions from 190.0 mL of 0.600 M Pb(NO3)2

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Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 5.4 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

Neptune to be precise

Explanation:

cause it is the last planet in our solar system

The compound is Glucose.

C: 40 g divided by 12 g per mol equals 3.333 mol

H: 6.72 g/mol (1 g) = 6.72 mol

O: 53.28 g/mol (16 g) = 3.33 mol

Subtract the lesser amount of moles.

C: 3.333 / 3.33 = 1.00

H: 6.72 / 3.33 = 2.02 ≈ 2

O: 3.33/3.33 = 1.00

Statistical method

The empirical formula's molar mass is 12 g/mol + 2*1 g/mol + 16 g/mol = 30 g/,ol.

180 g/mol / 30 g/mol = 6 times the mass of the empirical formula is contained in the molar mass.

The empirical formula of compound is six times the molecular formula.

=>[tex]C_{6} H_{12} O_{6}[/tex]

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Phosphorus, which has the atomic number 15 and is located in period 3 and group 15 of the periodic table.

Answer:

Skeleton equation: H2S(g) + O2(g) → SO2(g) + H2O(l)

Explanation:

Corrosion is the process of chemical or electrochemical attack of materials by their external environment.

The tendency/resistance of different metals to corrosion largely depends on the composition of the metal. Iron and steel corrode in the presence of oxygen due to oxidation, while some metals such as chromium, nickel and molybdenum provide a protective layer of oxide film on the surface of the metal which is then resistant to corrosion. Other metals such as aluminum and zinc form sacrificial oxide layers which corrode and protect the metal from becoming completely damaged.

Answer:

The ion with the largest size is Cs+.

Explanation:

The size of an ion is determined by the number of electrons it contains and the arrangement of those electrons in its electron cloud. Ions with a larger number of electrons will generally have a larger size because their electron clouds will be more diffuse and occupy more space. Ions with a smaller number of electrons will have a smaller size because their electron clouds will be more compact.

In general, ions in the same group of the periodic table will have a similar number of valence electrons and will be similar in size. For example, the F- ion and the O-2 ion both belong to Group 17 and have 7 valence electrons, so they are expected to be similar in size. Similarly, the Cs+ and Al+3 ions both belong to Group 1 and have a single valence electron, so they are also expected to be similar in size.

However, the Cs+ ion is much larger than the Al+3 ion because it has a larger number of total electrons. Cs+ has 55 electrons, while Al+3 has only 13 electrons. The larger number of electrons in Cs+ results in a more diffuse electron cloud and a larger overall size. Therefore, among the ions listed, Cs+ has the largest size

The two portions on this module for which we can broaden unit elements to do dimensional analysis with chemical materials are volume and mass.

volume is a degree of the quantity of three-dimensional space occupied by using an object or substance. it's miles regularly measured in liters, cubic centimeters, or cubic meters. volume is used to measure the potential of a field, the dimensions of an object, or the quantity of liquid or gas in a given space. it's also used to determine the mass of an item, because the density (mass in line with unit quantity) is often acknowledged.

the 2 portions of volume and mass are critical for doing dimensional analysis with chemical substances because they help to measure the amount of a substance in distinct gadgets. extent is vital for measuring the quantity of liquid materials, and mass is critical for measuring the quantity of strong substances. each of these portions are vital for accurate and specific measurements of chemical substances, making them crucial for dimensional analysis.

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The appropriate explanation for the non-metal is that the higher effective nuclear charge less will be the atomic radius.

Atomic radius typically decreases during a period from left to right. There are a few little outliers, such how the oxygen radius is a tiny bit bigger than the nitrogen radius. Protons are gradually added to the nucleus at the same time that electrons are gradually added to the main energy level. The enhanced positive charge of the nucleus gradually attracts these electrons closer to it. The size of the atoms shrinks as the strength of attraction between nuclei and electrons grows. Due to electron-electron repulsions that would otherwise result in the atom's size expanding, the effect becomes less pronounced as one proceeds further to the right in a period.

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