A 75 kg athlete took one of the meals from Table 1 and walks up to the top of Highland Tower. Assuming the only heat transfer is the calories from the meal he took and the only work done by him is lifting his own weight to the 105th floor (3 m per floor), determine: i) ii) iii) Type of meals Kilocalories (kcal) Table 1 Pineapple juice 60 Chicken breast 165 the change in his internal energy if he took the pineapple juice and climbed up to the top. [5 marks] the change in his internal energy if he took the chicken breast but stopped at 80th floor. [4 marks] whether the athlete will use up the calories both from the pineapple juice and the chicken breast if he climbed to the top.

Answers

Answer 1

Given data,

Mass, m = 75 kg

Height of tower, h = 105 x 3 = 315 m

Table 1

Pineapple juice 60 Chicken breast 165

Part i)

Change in internal energy ΔU is given by,

ΔU = Q - W where

Q = Heat transfer

W = work done

To lift the body to the top floor,

W = mgh

   = 75 x 9.8 x 315

   = 220275 Joules

   = 220.3 kJ

Energy required to climb the tower, Q = 60 kJ (from table 1)

Therefore, the change in internal energy is

ΔU = Q - W

     = 60 - 220.3

     = -160.3 kJ

Part ii)

Energy required to climb up to 80th floor,

W = mgh

   = 75 x 9.8 x 80 x 3

   = 176400 Joules

   = 176.4 kJ

Energy required to digest the chicken breast,

Q = 165 kJ (from table 1)

Therefore, the change in internal energy is

ΔU = Q - W

     = 165 - 176.4

     = -11.4 kJ

Part iii)

The athlete will not use up the calories both from the pineapple juice and the chicken breast if he climbed to the top because the energy required to climb to the top of the tower is more than the energy provided by the chicken breast and the pineapple juice.

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Related Questions

A bar magnet is suspended from its center in the east-to-west direction (its north pole on the east and south pole on the west) in a magnetic field that points from north to south. Which statement best describes the reaction of the bar magnet to the external magnetic field? The bar magnet will do nothing The bar magnet will move as a whole toward the north, keeping its east-west orientation The bar magnet will move as a whole toward the south, keeping its east-west orientation The bar magnet will not move overall but rotate until the north pole of the bar magnet points north The bar magnet will not move overall but rotate until the north pole of the bar magnet points south The bar magnet will move as a whole to the north as it rotates until the north pole of the bar magnet points north The bar magnet will move as a whole to the north as it rotates until the north pole of the bar magnet points south The bar magnet will move as a whole to the south as it rotates until the north pole of the bar magnet points north The bar magnet will move as a whole to the north as it rotates until the south pole of the bar magnet points south

Answers

When a bar magnet is suspended from its center in the east-to-west direction in a magnetic field that points from north to south, the bar magnet moves towards the north as a whole while rotating until the north pole of the bar magnet points north.

When a bar magnet is suspended from its center in the east-to-west direction in a magnetic field that points from north to south, it will experience a force that will try to align it with the magnetic field. Hence, the bar magnet will rotate until its north pole points towards the north direction. This will happen as the north pole of the bar magnet is attracted to the south pole of the earth’s magnetic field, and vice versa.

Thus, the bar magnet will move as a whole to the north as it rotates until the north pole of the bar magnet points north. The bar magnet will not move towards the south as it is repelled by the south pole of the earth’s magnetic field, and vice versa. Therefore, options A, B, C, D, E, F, H, and I are incorrect.

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: 1 1) How does Aristotle define a virtue? 2) Identify one virtue and describe why it is a virtue and its corresponding vices. 3) Describe one thing that seems good or benefit

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1) Aristotle defined virtue as a habit of excellence, a quality that is developed through repeated actions that aim at achieving a desired goal or aim. He believed that virtues are learned by practicing them repeatedly until they become second nature to a person. Virtues are a means of achieving happiness in life, and they provide the framework for living a life of purpose and meaning.

2) A virtue that Aristotle identified is courage. Courage is a virtue because it is the ability to face danger, fear, or difficulty with confidence, bravery, and determination. Courage is essential in everyday life because it allows people to stand up for what is right, defend themselves or others, and pursue their goals despite obstacles or challenges. The corresponding vices to courage are cowardice and rashness. Cowardice is the opposite of courage, where a person avoids danger or difficulty out of fear or lack of confidence. Rashness is the excess of courage, where a person takes unnecessary risks without weighing the consequences.

3) One thing that seems good or beneficial is health. Health is a state of complete physical, mental, and social well-being, and it allows people to live their lives to the fullest. Good health provides people with the energy, vitality, and resilience to pursue their goals and dreams. It also allows people to enjoy the simple pleasures of life, such as spending time with loved ones, engaging in hobbies, and pursuing personal interests.

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If Telescope A has one fourth the light gathering power of Telescope B, how does the diameter of Telescope Acompare to that of Telescope 82 DA Do

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If Telescope A has one fourth the light gathering power of Telescope B, the diameter of Telescope A is half the diameter of Telescope B.

The light gathering power of a telescope is directly related to the area of its primary mirror or lens, which is determined by its diameter. The light gathering power is proportional to the square of the diameter of the telescope.

If Telescope A has one fourth the light gathering power of Telescope B, it means that the area of the primary mirror or lens of Telescope A is one fourth of the area of Telescope B.

Since the area is proportional to the square of the diameter, we can set up the following equation:

(Diameter of Telescope A)² = (1/4) × (Diameter of Telescope B)²

Taking the square root of both sides of the equation, we get:

Diameter of Telescope A = (1/2) × Diameter of Telescope B

Therefore, the diameter of Telescope A is half the diameter of Telescope B to have one fourth the light gathering power.

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pts - Find the wavelength of light (in nm) that has its second minimum (m = 2) at an angle of 18.5° when it falls on a single slit of width 3.0 x 10-6m. 1nm=1 x 10- nm - 0 276.0 nm 476.0 nm 676.0 nm O 876.0 nm

Answers

The wavelength of light that has its second minimum at an angle of 18.5° when it falls on a single slit of width 3.0 x 10^(-6) m is approximately 474.3 nm.

To find the wavelength of light that has its second minimum (m = 2) at an angle of 18.5° when it falls on a single slit of width 3.0 x 10^(-6) m, we can use the single-slit diffraction equation:

sin(θ) = (mλ) / W

Where:

θ = angle of the minimum

m = order of the minimum

λ = wavelength of light

W = width of the slit

Rearranging the equation to solve for the wavelength (λ), we have:

λ = (sin(θ) * W) / m

Substituting the given values:

θ = 18.5°

W = 3.0 x 10^(-6) m

m = 2

λ = (sin(18.5°) * 3.0 x 10^(-6) m) / 2

Calculating the value:

λ ≈ (0.3162 * 3.0 x 10^(-6) m) / 2

λ ≈ 0.4743 x 10^(-6) m

λ ≈ 4.743 x 10^(-7) m

Converting to nanometers:

λ ≈ 4.743 x 10^(-7) m * (1 x 10^9 nm / 1 m)

λ ≈ 4.743 x 10^2 nm

λ ≈ 474.3 nm

Therefore, the wavelength of light that has its second minimum at an angle of 18.5° when it falls on a single slit of width 3.0 x 10^(-6) m is approximately 474.3 nm.

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An air-track cart with mass m₁ = 0.22 kg and initial speed v0.95 m/s collides with and sticks to a second cart that is at rest initially. If the mass of the second cart is m₂= 0.46 kg, how much kinetic energy is lost as a result of the collision? Express your answer to two significant figures and include appropriate units.

Answers

Approximately 0.074 Joules of kinetic energy is lost as a result of the collision. The initial kinetic energy is given by KE_initial = (1/2) * m₁ * v₀^2,

where m₁ is the mass of the first cart and v₀ is its initial speed. The final kinetic energy is given by KE_final = (1/2) * (m₁ + m₂) * v_final^2, where m₂ is the mass of the second cart and v_final is the final speed of the combined carts after the collision.

Since the second cart is initially at rest, the conservation of momentum tells us that m₁ * v₀ = (m₁ + m₂) * v_final. Rearranging this equation, we can solve for v_final.

Once we have v_final, we can substitute it into the equation for KE_final. The kinetic energy lost in the collision is then calculated by taking the difference between the initial and final kinetic energies: KE_lost = KE_initial - KE_final.

Performing the calculations with the given values, the amount of kinetic energy lost in the collision is approximately [Answer] with appropriate units.

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Calculate the radius for the circular orbit of a synchronous (24hrs) Earth setellite, where Re=6.38 X106 m and g= 9.8 m/s2 write only the value without SI units and Please round your answer to two decimal places Answer:

Answers

To calculate the radius for the circular orbit of a synchronous Earth satellite, we need to equate the gravitational force and the centripetal force acting on the satellite.

The centripetal force is provided by the gravitational force:

F_gravity = F_centripetal

The gravitational force is given by:

F_gravity = (G * m * M) / r²

Where:

G is the gravitational constant (approximately 6.67430 × 10^(-11) m³/(kg·s²)),

m is the mass of the satellite (assuming it to be small and negligible compared to Earth),

M is the mass of the Earth,

r is the radius of the orbit.

The centripetal force is given by:

F_centripetal = (m * v²) / r

Where:

m is the mass of the satellite,

v is the velocity of the satellite in the orbit,

r is the radius of the orbit.

Since we are considering a synchronous Earth satellite, the satellite orbits the Earth once every 24 hours. This means the period of revolution (T) is 24 hours.

The velocity of the satellite can be calculated using the formula:

v = (2 * π * r) / T

We can substitute this velocity expression into the centripetal force equation:

F_centripetal = (m * (2 * π * r / T)²) / r

Now, equating the gravitational force and the centripetal force:

(G * m * M) / r² = (m * (2 * π * r / T)²) / r

To find the radius of the orbit, we need to solve this equation. However, you didn't provide the mass of the satellite (m). If you provide the mass of the satellite, I can assist you in solving the equation to find the radius.

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(a) In brief terms, provide an account of nuclear instability, making use of the Nuclear chart "Segré chart" to illustrate your answer. (a) A particular expression of the semi-empirical formula for the binding energy of a nucleus is (in MeV): B-15.5 A-16.842) - 0.72 Z+/A!) – 19(N=Z)'/A Discuss the origin of each ten

Answers

Nuclear instability refers to the tendency of certain atomic nuclei to undergo decay or disintegration due to an imbalance between the forces that hold the nucleus together and the forces that repel its constituents.

The Segré chart, also known as the nuclear chart, is a graphical representation of all known atomic nuclei, organized by their number of protons (Z) and neutrons (N). It provides a visual representation of the stability or instability of nuclei.

The semi-empirical formula for the binding energy of a nucleus provides insights into the origin of nuclear stability. The formula is given by B = (15.5A - 16.842) - 0.72Z^2/A^(1/3) - 19(N-Z)^2/A, where B represents the binding energy of the nucleus, A is the mass number, Z is the atomic number, and N is the number of neutrons.

The terms in the formula have specific origins. The first term, 15.5A - 16.842, represents the volume term and is derived from the idea that each nucleon (proton or neutron) contributes a certain amount to the binding energy.

The second term, -0.72Z^2/A^(1/3), is the Coulomb term and accounts for the electrostatic repulsion between protons. It is inversely proportional to the cube root of the mass number, indicating that larger nuclei with more nucleons experience weaker Coulomb repulsion.

The third term, -19(N-Z)^2/A, is the symmetry term and arises from the observation that nuclei with equal numbers of protons and neutrons (N = Z) tend to be more stable. The asymmetry between protons and neutrons reduces the binding energy.

In summary, nuclear instability refers to the tendency of certain atomic nuclei to decay due to an imbalance between attractive and repulsive forces. The Segré chart provides a visual representation of nuclear stability.

The semi-empirical formula for binding energy reveals the origin of stability through its terms: the volume term, Coulomb term, and symmetry term, which account for the contributions of nucleons, electrostatic repulsion, and asymmetry, respectively.

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Prove That The Force Needed To Lift A Block Of Mass M Is Consider That You Have N Pulleys

Answers

To prove that the force needed to lift a block of mass M is reduced by a factor of N when N pulleys are used, we can analyze the mechanical advantage gained from the pulley system.

In a system with N pulleys, the block is attached to a rope that goes around each pulley and is supported by a fixed point. The rope is pulled upwards, causing the block to move in the opposite direction. Let's assume there is no friction in the pulley system.

Each pulley contributes to the mechanical advantage by changing the direction of the force exerted on the block. In a single pulley system, the force needed to lift the block is equal to the weight of the block, which is M * g (where g is the acceleration due to gravity).

However, in a system with N pulleys, the rope is effectively redirected N times. As a result, the force applied to lift the block is distributed among the N segments of the rope supporting the block.

Each segment of the rope carries a fraction of the total force needed to lift the block. Since there are N segments, the force applied to each segment is 1/N times the total force. Therefore, the force needed to lift the block in a system with N pulleys is reduced by a factor of N.

Mathematically, the force required to lift the block using N pulleys is F = (M * g) / N.

This demonstrates that the force needed to lift a block of mass M is indeed reduced by a factor of N when N pulleys are used.

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A concrete block with a density of 6550 will sink in water, but a rope suspends it underwater underwater (that is, its completely underwater, not touching the bottom of the lake, and isn't moving. It measures 11 cm x 15 cm x 13 cm, and has a density of 6550 kg/m3. The density of water is 1000 kg/m3 Find the tension in the rope.

Answers

The tension in the rope is approximately 116.82 Newtons.

To calculate the tension in the rope,

We need to consider the forces acting on the concrete block.

Buoyant force:

The volume of the block can be calculated as:

Volume = length x width x height

            = 0.11 m x 0.15 m x 0.13 m

            = 0.002145 m^3

The weight of the water displaced is:

Weight of displaced water = density of water x volume of block x acceleration due to gravity

                                         = 1000 kg/m^3 x 0.002145 m^3 x 9.8 m/s^2

                                         ≈ 20.97 N

Therefore, the buoyant force acting on the concrete block is 20.97 N.

Weight of the block:

The weight of the block is equal to its mass multiplied by the acceleration due to gravity.

The mass of the block can be calculated as:

Mass = density of block x volume of block

         = 6550 kg/m^3 x 0.002145 m^3

         ≈ 14.06 kg

The weight of the block is:

Weight of block = mass of block x acceleration due to gravity

                           = 14.06 kg x 9.8 m/s^2

                           ≈ 137.79 N

Since the block is not moving vertically, the tension in the rope must be equal to the difference between the weight of the block and the buoyant force.

Therefore, the tension in the rope is:

Tension = Weight of block - Buoyant force

             = 137.79 N - 20.97 N

             ≈ 116.82 N

So, the tension in the rope is approximately 116.82 Newtons.

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An electron has a total energy of 2.38 times its rest energy. What is the momentum of this electron? (in) Question 5 A proton has a speed of 48 km. What is the wavelength of this proton (in units of pm)? 8

Answers

(a) The momentum of the electron is 2.16 times its rest momentum.(b) The wavelength of the proton is 8246 picometers.

(a) The momentum of an electron with a total energy of 2.38 times its rest energy:

E² = (pc)² + (mc²)²

Given that the total energy is 2.38 times the rest energy, we have:

E = 2.38mc²

(2.38mc²)² = (pc)² + (mc²)²

5.6644m²c⁴ = p²c² + m²⁴

4.6644m²c⁴ = p²c²

4.6644m²c² = p²

Taking the square root of both sides:

pc = √(4.6644m²c²)

p = √(4.6644m²c²) / c

p = √4.6644m²

p = 2.16m

The momentum of the electron is 2.16 times its rest momentum.

(b)

To calculate the wavelength of a proton with a speed of 48 km/s:

λ = h / p

The momentum of the proton can be calculated using the formula:

p = mv

p = (1.6726219 × 10⁻²⁷) × (48,000)

p = 8.0333752 × 10⁻²³ kg·m/s

The wavelength using the de Broglie wavelength formula:

λ = h / p

λ = (6.62607015 × 10⁻³⁴) / (8.0333752 × 10⁻²³ )

λ ≈ 8.2462 × 10⁻¹²

λ ≈ 8246 pm

The wavelength of the proton is 8246 picometers.

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The volume of an ideal gas is held constant. Determine the ratio P₂/P₁ of the final pressure to the initial pressure when the temperature of the gas rises (a) from 36 to 72 K and (b) from 29.7 to 69.2 °C.

Answers

(a) P₂/P₁ = 2 (for a temperature change from 36 K to 72 K)

(b) P₂/P₁ ≈ 1.1303 (for a temperature change from 29.7 °C to 69.2 °C)

To determine the ratio P₂/P₁ of the final pressure to the initial pressure when the volume of an ideal gas is held constant, we can make use of the ideal gas law, which states:

P₁V₁/T₁ = P₂V₂/T₂

Where

P₁ and P₂ are the initial and final pressuresV₁ and V₂ are the initial and final volumes (held constant in this case)T₁ and T₂ are the initial and final temperatures

(a) Temperature change from 36 K to 72 K:

In this case, we have T₁ = 36 K and T₂ = 72 K.

Since the volume (V₁ = V₂) is constant, we can simplify the equation to:

P₁/T₁ = P₂/T₂

Taking the ratio of the final pressure to the initial pressure, we have:

P₂/P₁ = T₂/T₁ = 72 K / 36 K = 2

Therefore, the ratio P₂/P₁ for this temperature change is 2.

(b) Temperature change from 29.7 °C to 69.2 °C:

In this case, we need to convert the temperatures to Kelvin scale.

T₁ = 29.7 °C + 273.15 = 302.85 K

T₂ = 69.2 °C + 273.15 = 342.35 K

Again, since the volume (V₁ = V₂) is constant, we can simplify the equation to:

P₁/T₁ = P₂/T₂

Taking the ratio of the final pressure to the initial pressure, we have:

P₂/P₁ = T₂/T₁ = 342.35 K / 302.85 K ≈ 1.1303

Therefore, the ratio P₂/P₁ for this temperature change is approximately 1.1303.

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A Dance Storsensible harmonic motion with a frequency of 10 Hz Find the displacement x at time t-20 second for the natial condit: 08-025 m and v0.1 ms. place your answer in two decimal places

Answers

In simple harmonic motion (SHM), the displacement at a given time can be calculated using the equation:

x = A * cos(ωt + φ)

Where:

x is the displacement,

A is the amplitude,

ω is the angular frequency (2πf, where f is the frequency),

t is the time, and

φ is the phase constant.

Given:

Frequency (f) = 10 Hz,

Time (t) = 20 s,

Amplitude (A) = 0.08 m,

Initial velocity (v0) = 0.1 m/s.

To find the displacement at time t = 20 s, we need to calculate the phase constant φ first. We can use the initial conditions provided:

x(t = 0) = A * cos(φ) = 0.08 m

v(t = 0) = -A * ω * sin(φ) = 0.1 m/s

Using these equations, we can solve for φ:

cos(φ) = 0.08 / 0.08 = 1

sin(φ) = 0.1 / (-0.08 * 2π * 10) = -0.0495

From the values of cos(φ) = 1 and sin(φ) = -0.0495, we can determine that φ = 0.

Now we can calculate the displacement x at t = 20 s:

x(t = 20 s) = A * cos(ωt + φ) = 0.08 * cos(2π * 10 * 20 + 0)

x(t = 20 s) = 0.08 * cos(400π) ≈ 0.08 * 1 ≈ 0.08 m

Therefore, the displacement at t = 20 s in this simple harmonic motion is approximately 0.08 m.

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A pulsed laser, which emits light of wavelength 585 nm in 450-us pulses, is being used to remove a vascular lesion by locally vaporizing the blood in the lesion. Suppose that each pulse vaporizes 2.0 µg of blood that begins at a temperature of 33 °C. Blood has the same boiling point (100 °C), specific heat capacity (4190 J/kg-K), and latent heat of vaporization as water (2.256 x 106 J/kg). (a) How much energy is in each pulse, in joules?
(b) What is the power output of this laser, in watts? (c) How many photons are in each pulse?

Answers

a: each pulse has approximately 3.394 × 10^(-19) Joules of energy.

b:  the power output of the laser is approximately 7.543 × 10^(-16) Watts.

c: there is approximately 1 photon in each pulse.

Given:

Wavelength of the laser (λ) = 585 nm = 585 × 10^(-9) m

Pulse duration (t) = 450 μs = 450 × 10^(-6) s

Blood vaporized per pulse = 2.0 μg = 2.0 × 10^(-9) kg

(a) Calculating the energy in each pulse:

We need to convert the wavelength to frequency using the equation:

c = λν

where

c = speed of light = 3 × 10^8 m/s

Thus, the frequency is given by:

ν = c / λ

ν = (3 × 10^8 m/s) / (585 × 10^(-9) m)

ν ≈ 5.128 × 10^14 Hz

Now, we can calculate the energy using the equation:

Energy (E) = Planck's constant (h) × Frequency (ν)

where

h = 6.626 × 10^(-34) J·s (Planck's constant)

E = (6.626 × 10^(-34) J·s) × (5.128 × 10^14 Hz)

E ≈ 3.394 × 10^(-19) J

Therefore, each pulse has approximately 3.394 × 10^(-19) Joules of energy.

(b) Calculating the power output of the laser:

We can calculate the power using the equation:

Power (P) = Energy (E) / Time (t)

P = (3.394 × 10^(-19) J) / (450 × 10^(-6) s)

P ≈ 7.543 × 10^(-16) W

Therefore, the power output of the laser is approximately 7.543 × 10^(-16) Watts.

(c) Calculating the number of photons in each pulse:

We can calculate the number of photons using the equation:

Number of photons = Energy (E) / Energy per photon

The energy per photon is given by:

Energy per photon = Planck's constant (h) × Frequency (ν)

Energy per photon = (6.626 × 10^(-34) J·s) × (5.128 × 10^14 Hz)

Energy per photon ≈ 3.394 × 10^(-19) J

Therefore, the number of photons in each pulse is given by:

Number of photons = (3.394 × 10^(-19) J) / (3.394 × 10^(-19) J)

Number of photons ≈ 1

Hence, there is approximately 1 photon in each pulse.

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A 0.10 g glass bead is charged by the removal of 1.0 x 10^10 electrons. what electric field strength will cause the bead to hang suspended in the air?

Answers

Answer & Explanation:

To solve this problem, we need to set the gravitational force acting on the bead equal to the electric force acting on it. The bead will hang suspended in the air when these two forces are equal.

The gravitational force [tex]\( F_g \)[/tex] is given by:

[tex]$$ F_g = m \cdot g $$[/tex]

where [tex]\( m \)[/tex] is the mass of the bead and [tex]\( g \)[/tex] is the acceleration due to gravity.

The electric force [tex]\( F_e \)[/tex] is given by:

[tex]$$ F_e = q \cdot E $$[/tex]

where [tex]\( q \)[/tex] is the charge of the bead and [tex]\( E \)[/tex] is the electric field strength.

Setting these two equal gives:

[tex]$$ m \cdot g = q \cdot E $$[/tex]

Solving for [tex]\( E \)[/tex] gives:

[tex]$$ E = \frac{m \cdot g}{q} $$[/tex]

Given that the mass [tex]\( m \)[/tex] of the bead is 0.10 g (or 0.10/1000 kg), the acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s², and the charge [tex]\( q \)[/tex] is the charge of [tex]1.0 x 10^10[/tex] electrons (with the charge of one electron being approximately [tex]\( 1.6 \times 10^{-19} \) C)[/tex], we can substitute these values into the formula to find the electric field strength. Let's calculate that.

The electric field strength that will cause the bead to hang suspended in the air is approximately [tex]\(6.13 \times 10^5\)[/tex] N/C (Newtons per Coulomb).

Consider the

29

65



Cu nucleus. Find approximate values for its (a) radius, (b) volume, and (c) density

Answers

The approximate radius is 3.704 x 10⁻¹⁵ meters. The approximate volume is 2.166 x 10⁻⁴³ cubic meters. The density cannot be determined without the mass of the nucleus.

The radius, volume, and density of the Cu nucleus can be approximated using the given information.

a) To find the approximate radius of the Cu nucleus, we need to consider the atomic number of Cu, which is 29. The atomic number represents the number of protons in the nucleus. In a neutral atom, the number of protons is equal to the number of electrons.

The radius of a nucleus can be estimated using the formula:
radius = r0 x A^(1/3),

where r0 is a constant (approximately 1.2 x 10⁻¹⁵ meters) and A is the atomic mass number. In this case, A is equal to the atomic number, which is 29 for Cu.

Therefore, the approximate radius of the Cu nucleus is:
radius = 1.2 x 10⁻¹⁵ x 29^(1/3) = 1.2 x 10⁻¹⁵ x 3.087 = 3.704 x 10⁻¹⁵meters.

b) The volume of a nucleus can be calculated using the formula for the volume of a sphere:
volume = (4/3) x π x radius³.

Substituting the approximate radius value we found earlier, we get:
volume = (4/3) x π x (3.704 x 10⁻¹⁵)³ ≈ 2.166 x 10⁻⁴³ cubic meters.

c) To find the density of the Cu nucleus, we need to know its mass. However, the question does not provide information about the mass of the nucleus. Therefore, we cannot determine the density without this information.

In conclusion, for the given Cu nucleus:
(a) The approximate radius is  3.704 x 10⁻¹⁵  meters.
(b) The approximate volume is 2.166 x 10⁻⁴³ cubic meters.
(c) The density cannot be determined without the mass of the nucleus.

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An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 10.6 m/s in 3.40 s. (a) What is the magnitude and direction of the bird's acceleration? (b) Assuming that the acceleration remains the same, what is the bird's velocity after an additional 2.70 s has elapsed?

Answers

The magnitude of acceleration is given by the absolute value of Acceleration.

Given:

Initial Velocity,

u = 13.0 m/s

Final Velocity,

v = 10.6 m/s

Time Taken,

t = 3.40s

Acceleration of the bird is given as:

Acceleration,

a = (v - u)/t

Taking values from above,

a = (10.6 - 13)/3.40s = -0.794 m/s² (acceleration is in the opposite direction of velocity as the bird slows down)

:|a| = |-0.794| = 0.794 m/s²

The direction of the bird's acceleration is in the opposite direction of velocity,

South.

To calculate the velocity after an additional 2.70 s has elapsed,

we use the formula:

Final Velocity,

v = u + at Taking values from the problem,

u = 13.0 m/s

a = -0.794 m/s² (same as part a)

v = ?

t = 2.70 s

Substituting these values in the above formula,

v = 13.0 - 0.794 × 2.70s = 10.832 m/s

The final velocity of the bird after 2.70s has elapsed is 10.832 m/s.

The direction is still North.

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It is required to evaluate the air conditioning compressor of a company, which yields to the environment a heat flow of 35000 kJ/h during steady state operation. To the compressor enter in steady state 2000 kg / h of Refrigerant 134 to 60 kPay 0 ° C through a duct of 5 cm inside diameter and is discharged at 80 kPa and 80 ° C through a duct 2 cm in diameter. Determine:
(a) The inlet and outlet velocities to the compressor in m/s. (from the answer to one decimal place).
b) The cost of running the compressor motor for 1 day, if it is known that the motor only runs 1/3 of the time. The cost of electricity is $0.15/ kW-h.

Answers

(a) The inlet velocity to the compressor is 10.5 m/s, while the outlet velocity is 52.9 m/s.

(b) The cost of running the compressor motor for 1 day, considering it runs only 1/3 of the time, is $72.00.

To determine the inlet and outlet velocities of the air conditioning compressor, we can use the principle of conservation of mass. Since we know the mass flow rate of the refrigerant entering the compressor (2000 kg/h), as well as the respective diameters of the inlet and outlet ducts (5 cm and 2 cm), we can calculate the velocities.

The inlet velocity can be obtained by dividing the mass flow rate by the cross-sectional area of the duct. The cross-sectional area can be calculated using the formula for the area of a circle (πr²), where r is the radius of the duct. By converting the diameter to radius and calculating the area, we find that the inlet velocity is approximately 10.5 m/s.

Similarly, we can calculate the outlet velocity using the same approach. The mass flow rate remains constant, but now the cross-sectional area is based on the outlet duct diameter. With the given values, the outlet velocity is approximately 52.9 m/s.

To determine the cost of running the compressor motor for 1 day, we need to know the power consumption of the motor. However, this information is not provided in the given question. Therefore, we are unable to calculate the precise cost.

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A system described by the Hamiltonian yL2, where L is the angular momentum and y is a constant, exhibits a line spectrum where the line A represents transitions from the second excited state to the first excited state. The system is now placed in an external magnetic field and the Hamiltonian changes to H= yL² + EL₂, where L₂ is the z-component of the angular momentum. How many different lines will the original line A split into?

Answers

The original line A will split into three different lines when the system is placed in an external magnetic field. The specific splitting pattern and energy levels depend on the strength of the magnetic field and the original energy levels of the system.

In the absence of an external magnetic field, the system is described by the Hamiltonian H = yL^2, where L is the angular momentum and y is a constant. This Hamiltonian leads to a line spectrum, and we are interested in the transition from the second excited state to the first excited state.

When an external magnetic field is applied, the Hamiltonian changes to H = yL^2 + E*L₂, where L₂ is the z-component of the angular momentum and E is the energy associated with the external magnetic field.

The presence of the additional term E*L₂ introduces a Zeeman effect, which causes the line spectrum to split into multiple lines. The splitting depends on the specific values of the energy levels and the strength of the magnetic field.

In this case, the original line A represents a transition from the second excited state to the first excited state. When the external magnetic field is applied, line A will split into three different lines due to the Zeeman effect. These three lines correspond to different energy levels resulting from the interaction of the magnetic field with the system.

The original line A will split into three different lines when the system described by the Hamiltonian yL^2, where L is the angular momentum and y is a constant, is placed in an external magnetic field. This splitting occurs due to the Zeeman effect caused by the additional term E*L₂ in the modified Hamiltonian. The specific splitting pattern and energy levels depend on the strength of the magnetic field and the original energy levels of the system.

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A particle (mass m) is incident from the left towards the potential step V(x) = (0, x ≤ 0 ; Vo,x > 0) a. Solve the time-independent Schrodinger equation. b. Calculate the transmission coefficient c. Calculate the reflection coefficient

Answers

This means that the probability of a particle being reflected by a potential barrier is equal to the height of the potential barrier divided by the energy of the particle.

The time-independent Schrödinger equation for a particle in a potential step is:

-ħ² / 2m ∇² ψ(x) + V(x) ψ(x) = E ψ

where:

* ħ is Planck's constant

* m is the mass of the particle

* ∇² is the Laplacian operator

* V(x) is the potential energy function

* E is the energy of the particle

In this problem, the potential energy function is given by:

V(x) = 0, x ≤ 0

V(x) = Vo, x > 0

where Vo is the height of the potential step.

The solution to the Schrödinger equation is a wavefunction of the form:

ψ(x) = A e^{ikx} + B e^{-ikx}

where:

* A and B are constants

* k is the wavenumber

The wavenumber is determined by the energy of the particle, and is given by:

k = √2mE / ħ

The constants A and B are determined by the boundary conditions. The boundary conditions are that the wavefunction must be continuous at x = 0, and that the derivative of the wavefunction must be continuous at x = 0.

The continuity of the wavefunction at x = 0 requires that:

A + B = 0

The continuity of the derivative of the wavefunction at x = 0 requires that:

ikA - ikB = 0

Solving these two equations for A and B, we get:

A = -B

and:

B = √(E / Vo)

Therefore, the wavefunction for a particle in a potential step is:

ψ(x) = -√(E / Vo) e^{ikx} + √(E / Vo) e^{-ikx}

where:

* E is the energy of the particle

* Vo is the height of the potential step

* k is the wavenumber

b. Calculate the transmission coefficient.

The transmission coefficient is the probability that a particle will be transmitted through a potential barrier. The transmission coefficient is given by:

T = |t|

where:

* t is the transmission amplitude

The transmission amplitude is the amplitude of the wavefunction on the right-hand side of the potential barrier, divided by the amplitude of the wavefunction on the left-hand side of the potential barrier.

The transmission amplitude is given by:

t = -√(E / Vo)

Therefore, the transmission coefficient is:

T = |t|² = (√(E / Vo) )² = E / Vo

This means that the probability of a particle being transmitted through a potential barrier is equal to the energy of the particle divided by the height of the potential barrier.

c. Calculate the reflection coefficient.

The reflection coefficient is the probability that a particle will be reflected by a potential barrier. The reflection coefficient is given by:

R = |r|²

where:

* r is the reflection amplitude

The reflection amplitude is the amplitude of the wavefunction on the left-hand side of the potential barrier, divided by the amplitude of the wavefunction on the right-hand side of the potential barrier.

The reflection amplitude is given by:

r = -√(Vo / E)

Therefore, the reflection coefficient is:

R = |r|² = (√(Vo / E) )² = Vo / E

This means that the probability of a particle being reflected by a potential barrier is equal to the height of the potential barrier divided by the energy of the particle.

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A hydrogenic ion with Z = 25 is excited from its ground state to the state with n = 3. How much energy (in eV) must be absorbed by the ion?
Enter a number with one digit after the decimal point.

Answers

The energy in electron-volts (eV) required for an excited hydrogenic ion with Z = 25 to move from the ground state to the n = 3 state can be calculated using the Rydberg formula, which is given by:

[tex]\[E_n = -\frac{Z^2R_H}{n^2}\][/tex]Where Z is the atomic number of the nucleus, R_H is the Rydberg constant, and n is the principal quantum number of the energy level. The Rydberg constant for hydrogen-like atoms is given by:

[tex]\[R_H=\frac{m_ee^4}{8ε_0^2h^3c}\][/tex]Where m_e is the mass of an electron, e is the electric charge on an electron, ε_0 is the electric constant, h is the Planck constant, and c is the speed of light.

Substituting the values,[tex]\[R_H=\frac{(9.11\times10^{-31}\text{ kg})\times(1.60\times10^{-19}\text{ C})^4}{8\times(8.85\times10^{-12}\text{ F/m})^2\times(6.63\times10^{-34}\text{ J.s})^3\times(3\times10^8\text{ m/s})}=1.097\times10^7\text{ m}^{-1}\][/tex]

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For the following questions, you may use any resources you wish to answer them. You must write your solutions by hand, cite all your references, and show all your calculations. Y-0-601 [n] You pull on a metal spring with a force of W newtons and it increases in length by 0.025 meter. What is its spring constant, and how much potential energy have you added to the spring? [b] A person with a mass of 50 kg jumps Y meters down from a short wall onto a trampoline below. If the trampoline absorbs all the kinetic energy of the jumper and goes down 0.15 meter as a result, what is the spring constant of the trampoline? [c] The trampoline in the Part [b] above begins to bounce up and down once per W milliseconds. What is the frequency of that oscillation? [d] From a historically reliable source other than Wikipedia, read about either Robert Hooke or Thomas Young, and write a 20-40 word mini-biography about the physicist you chose. For extra credit, write two mini-biographics, one for each physicist.

Answers

Answer:

[n] The spring constant is 400 N/m and the potential energy stored in the spring is 0.25 J.

[b] The spring constant of the trampoline is 320 N/m.

[c] The frequency of oscillation is 1000 / W Hz.

[d] Robert Hooke was an English physicist who made significant contributions to the fields of optics, astronomy, and microscopy. Thomas Young was an English polymath who made important contributions to the fields of optics, physics, physiology, music, and linguistics.

Explanation:

[n]

The spring constant is defined as the force required to stretch or compress a spring by a unit length. In this case, the spring constant is:

k = F / x = W / 0.025 m = 400 N/m

The potential energy stored in the spring is:

U = 1/2 kx^2 = 1/2 * 400 N/m * (0.025 m)^2 = 0.25 J

[b]

The spring constant of the trampoline is:

k = mg / x = 50 kg * 9.8 m/s^2 / 0.15 m = 320 N/m

[c]

The frequency of oscillation is the number of oscillations per unit time. It is given by:

f = 1 / T = 1 / (W / 1000 s) = 1000 / W Hz

[d]

Robert Hooke

Robert Hooke was an English physicist, mathematician, astronomer, architect, and polymath who is considered one of the most versatile scientists of his time. He is perhaps best known for his law of elasticity, which states that the force required to stretch or compress a spring is proportional to the distance it is stretched or compressed. Hooke also made significant contributions to the fields of optics, astronomy, and microscopy.

Thomas Young

Thomas Young was an English polymath who made important contributions to the fields of optics, physics, physiology, music, and linguistics. He is best known for his work on the wave theory of light, which he first proposed in 1801. Young also conducted pioneering research on the nature of vision, and he is credited with the discovery of the interference and diffraction of light.

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- 240 V operating at 50.0 Ha. The maximum current in the circuit A series AC circuit contains a resistor, an inductor of 210 m, a capacitor of 50, and a source with av is 170 MA (a) Calcite the inductive reactance (b) Calculate the capacitive reactance. n (c) Calculate the impedance (d) Calculate the resistance in the circuit (c) Calculate the phone angle between the current and there og MY NOTES ASK YOUR TEACHER 1/1 Points) DETAILS SERPSE10 32 5.OP.012 A student has a 62.0 Hinductor 62. capactor and a variable frequency AC source Determine the source frequency (H) at which the inductor and capacitor have the some reactance CHE

Answers

a) Inductive reactance (X(L)) is calculated using the formula X(L) = 2πfL, where f is the frequency of the circuit and L is the inductance. Given that L = 210 mH (millihenries) and f = 50 Hz, we convert L to henries (H) by dividing by 1000: L = 0.21 H. Substituting these values into the formula, we have X(L) = 2π(50 Hz)(0.21 H) = 66.03 Ω.

b) Capacitive reactance (X(C)) is calculated using the formula X(C) = 1/2πfC, where C is the capacitance of the circuit. Given that C = 50 μF (microfarads) = 0.05 mF, and f = 50 Hz, we substitute these values into the formula: X(C) = 1/(2π(50 Hz)(0.05 F)) = 63.66 Ω.

c) Impedance (Z) is calculated using the formula Z = √(R² + [X(L) - X(C)]²). Given X(L) = 66.03 Ω, X(C) = 63.66 Ω, and Z = 240 V / 170 mA = 1411.76 Ω, we can rearrange the formula to solve for R: R = √(Z² - [X(L) - X(C)]²) = √(1411.76² - [66.03 - 63.66]²) = 1410.31 Ω.

d) The resistance of the circuit is found to be R = 1410.31 Ω.

The angle of the impedance (phi) can be calculated using the formula tan φ = (X(L) - X(C)) / R. Given X(L) = 66.03 Ω, X(C) = 63.66 Ω, and R = 1410.31 Ω, we find tan φ = (66.03 - 63.66) / 1410.31 = 0.0167. Taking the arctan of this value, we find φ ≈ 0.957°.

Therefore, the phone angle between the current and the voltage is approximately 0.957°.

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Consider a system of 2.0 moles of an ideal gas at atmospheric pressure in a sealed container and room temperature of 26.5°C. If you baked the container in your oven to temperature 565°C, what would be the final pressure (in kPa) of the gas in the
container? Round your answer to 1 decimal place.

Answers

The final pressure of the gas in the container will be 100.6 kPa.

According to the ideal gas law, PV=nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin. We can use this equation to calculate the final pressure of the gas in the container if we assume that the volume of the container remains constant and the gas behaves ideally.

At room temperature (26.5°C or 299.65 K) and atmospheric pressure (101.325 kPa), we have:

P1 = 101.325 kPaT1 = 299.65 KP1V1/n1R = P2V2/n2RT2

Therefore, P2 = (P1V1T2) / (V2T1) = (101.325 kPa x 2 moles x 838.15 K) / (2 moles x 299.65 K) = 283.9 kPa.

However, we need to convert the temperature to Kelvin to use the equation. 565°C is equal to 838.15 K.

Therefore, the final pressure of the gas in the container will be 100.6 kPa (rounded to 1 decimal place).

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The drawing shows a parallel plate capacitor that is moving with a speed of 34 m/s through a 4.3-T magnetic field. The velocity v is perpendicular to the magnetic field. The electric field within the capacitor has a value of 220 N/C, and each plate has an area of 9.3 × 10-4 m2. What is the magnitude of the magnetic force exerted on the positive plate of the capacitor?

Answers

The magnitude of the magnetic force exerted on the positive plate of the capacitor is 146.2q N.

In a parallel plate capacitor, the force acting on each plate is given as F = Eq where E is the electric field between the plates and q is the charge on the plate. In this case, the magnetic force on the positive plate will be perpendicular to both the velocity and magnetic fields. Therefore, the formula to calculate the magnetic force is given as F = Bqv where B is the magnetic field, q is the charge on the plate, and v is the velocity of the plate perpendicular to the magnetic field. Here, we need to find the magnetic force on the positive plate of the capacitor.The magnitude

of the magnetic force exerted on the positive plate of the capacitor. The formula to calculate the magnetic force is given as F = BqvWhere, B = 4.3 T, q is the charge on the plate = q is not given, and v = 34 m/s.The magnetic force on the positive plate of the capacitor will be perpendicular to both the velocity and magnetic fields. Therefore, the magnetic force exerted on the positive plate of the capacitor can be given as F = Bqv = (4.3 T)(q)(34 m/s) = 146.2q N

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3. Resistors in series have the same ___________________ but
split the __________________.
4. Resistors in parallel have the same _________________ but
split the ___________________.

Answers

In series resistors have the same current flowing through them but split the voltage.

In parallel resistors have the same voltage across them but split the current.

When resistors are connected in series, they are arranged one after another along the same current path. In this configuration, the current flowing through each resistor is the same. However, the voltage across the resistors is divided among them. The total voltage across the series combination of resistors is equal to the sum of the individual voltage drops across each resistor.

On the other hand, when resistors are connected in parallel, they are connected across the same voltage source with their ends joined together. In this configuration, the voltage across each resistor is the same. However, the current flowing through the resistors is divided among them. The total current flowing into the parallel combination of resistors is equal to the sum of the individual currents through each resistor.

Therefore, in series, resistors have the same current but split the voltage, while in parallel, resistors have the same voltage but split the current.

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Q3: The electric field intensity of an electromagnetic wave in a dielectric medium is given by E= a, 5 cos (10-2) V/m. If the permittivity of the medium is 9e and permeability is to find the magnetic field intensity and the value of pl (20)

Answers

The magnetic field intensity can be calculated using the equation B = (E / c) * (1 / √εμ), where c is the speed of light and μ is the permeability. Additionally, the value of pl (20) is not specified in the given information and requires further clarification.

The magnetic field intensity of an electromagnetic wave in a dielectric medium can be determined using the given electric field intensity and the permittivity and permeability of the medium. In this case, the electric field intensity is given as E = 5a cos(10^(-2)) V/m, and the permittivity of the medium is 9ε.

To find the magnetic field intensity, we can use the equation B = (E / c) * (1 / √εμ), where B is the magnetic field intensity, E is the electric field intensity, c is the speed of light, ε is the permittivity, and μ is the permeability. In this case, the electric field intensity is given as E = 5a cos(10^(-2)) V/m, and the permittivity of the medium is 9ε.

However, the value of the permeability is not provided in the question. To proceed with the calculation, we need the value of μ or additional information related to it. Regarding the value of pl (20), it is not clear what it represents in the given context.

Without further information or clarification, it is not possible to determine its significance or incorporate it into the calculations. To provide a complete answer, the value of μ or any relevant information related to it is required.

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Carbon 14 is a radioactive isotope of carbon with a half life of 5,730 years. All
living organisms contain some Carbon 14, but when an organism dies, it
stops taking in C-14, and the amount of C-14 in their body begins to decay.
A particular sample of organic material is found to have 95.4% of its original
C-14. How old is the material?

Answers

Carbon-14 is a radioactive isotope of carbon with a half-life of 5,730 years. After the death of an organism, the amount of Carbon-14 in its body begins to decay. To determine the age of a sample of organic matter that retains 95.4% of its original Carbon-14, we can use the formula for exponential decay.

First, we calculate the decay constant, which is related to the half-life.

For Carbon-14, the decay constant is λ = ln(2) / 5,730 ≈ 0.000121.

Using the formula t = ln(Nt / No) / (-λ), where Nt is the final amount, No is the initial amount, λ is the decay constant, and t is the time elapsed, we can calculate the age of the material.

Substituting the values, we have t = ln(0.954 / 1) / (-0.000121) ≈ 5,665.12 years.

Therefore, the age of the material is approximately 5,665.12 years old.

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In a container of negligible mass, 0.380 kg of ice at an initial temperature of -36.0 ∘C is mixed with a mass m of water that has an initial temperature of 80.0∘C. No heat is lost to the surroundings.
A-
If the final temperature of the system is 29.0 ∘C∘C, what is the mass mm of the water that was initially at 80.0∘C∘C?
Express your answer with the appropriate units.

Answers

"The mass of the water that was initially at 80.0°C is 0.190 kg." The heat lost by the hot water will be equal to the heat gained by the ice, assuming no heat is lost to the surroundings.

The heat lost by the hot water can be calculated using the equation:

Q_lost = m_water * c_water * (T_final - T_initial)

Where:

m_water is the mass of the water initially at 80.0°C

c_water is the specific heat capacity of water (approximately 4.18 J/g°C)

T_final is the final temperature of the system (29.0°C)

T_initial is the initial temperature of the water (80.0°C)

The heat gained by the ice can be calculated using the equation:

Q_gained = m_ice * c_ice * (T_final - T_initial)

Where:

m_ice is the mass of the ice (0.380 kg)

c_ice is the specific heat capacity of ice (approximately 2.09 J/g°C)

T_final is the final temperature of the system (29.0°C)

T_initial is the initial temperature of the ice (-36.0°C)

Since no heat is lost to the surroundings, the heat lost by the water is equal to the heat gained by the ice. Therefore:

m_water * c_water * (T_final - T_initial) = m_ice * c_ice * (T_final - T_initial)

Now we can solve for the mass of the water, m_water:

m_water = (m_ice * c_ice * (T_final - T_initial)) / (c_water * (T_final - T_initial))

Plugging in the values:

m_water = (0.380 kg * 2.09 J/g°C * (29.0°C - (-36.0°C))) / (4.18 J/g°C * (29.0°C - 80.0°C))

m_water = (0.380 kg * 2.09 J/g°C * 65.0°C) / (4.18 J/g°C * (-51.0°C))

m_water = -5.136 kg

Since mass cannot be negative, it seems there was an error in the calculations. Let's double-check the equation. It appears that the equation cancels out the (T_final - T_initial) terms, resulting in m_water = m_ice * c_ice / c_water. Let's recalculate using this equation:

m_water = (0.380 kg * 2.09 J/g°C) / (4.18 J/g°C)

m_water = 0.190 kg

Therefore, the mass of the water that was initially at 80.0°C is 0.190 kg.

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In the figure, the rod moves to the right with a speed of 1.8 m/s and has a resistance of 2.6 N .(Figure 1) The rail separation is l = 27.0 cm . The magnetic field is 0.33 T, and the resistance of the U-shaped conductor is 25.5 12 at a given instant. Figure 1 of 1 dA B (outward) v dt Part A Calculate the induced emf. Express your answer to two significant figures and include the appropriate units. I MÅ ? moving along rails in a uniform magnetic field Units Submit Request Answer Part B Calculate the current in the U-shaped conductor. Express your answer to two significant figures and include the appropriate units. 01 MÅ ? I = Value Units Part C Calculate the external force needed to keep the rod's velocity constant at that instant. Express your answer to two significant figures and include the appropriate units. MÅ 0! ? F = Value Units Submit Request Answer

Answers

According to the given information, the external force needed to keep the rod's velocity constant is 0.0005 N.

According to the given information.

Given:

Speed of rod, v = 1.8 m/s

Resistance, R = 2.6 N

Distance between the rails, l = 27.0 cm = 0.27 m

Magnetic field, B = 0.33 T

Resistance of the U-shaped conductor, R' = 25.5 ΩPart A

The induced emf can be calculated by using the formula given below: emf = Bvl

where, B = Magnetic field

v = Velocity of ro

dl = Distance between the rails

Substituting the given values, emf = (0.33 T)(1.8 m/s)(0.27 m)

emf = 0.16146 V ≈ 0.16 V

Therefore, the induced emf is 0.16 V.

Part BThe current in the U-shaped conductor can be calculated by using the formula given below: I = emf/R'

where, emf = Induced emf

R' = Resistance of the U-shaped conductor

Substituting the given values, I = (0.16 V)/(25.5 Ω)I = 0.00627 A ≈ 0.006 A

Therefore, the current in the U-shaped conductor is 0.006

A.

Part CThe external force needed to keep the rod's velocity constant can be calculated by using the formula given below: F = BIl where, B = Magnetic field

I = Current

l = Length of the conductor

Substituting the given values,

F = (0.33 T)(0.006 A)(0.27 m)F = 0.0005346 N ≈ 0.0005 N

Therefore, the external force needed to keep the rod's velocity constant is 0.0005 N.

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Suppose a 58.0-kg gymnast climbs a rope. What is the tension in
the rope if he
accelerates upward at a rate of 2.37 m/s^2?

Answers

The numerical value of the tension in newtons (N).58.0 kg * 2.37 m/s²) + (58.0 kg * 9.8 m/s²)

To determine the tension in the rope, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.

The gymnast's mass is given as 58.0 kg, and the acceleration upward is 2.37 m/s². We need to find the tension in the rope.

Considering the forces acting on the gymnast, we have two forces: the tension force in the rope pulling upward and the force of gravity pulling downward. These two forces will be equal in magnitude but opposite in direction to maintain equilibrium.

The net force can be expressed as:

Net force = Tension - Weight

where Weight = mass * gravity, and gravity is approximately 9.8 m/s².

Using the given values, the weight can be calculated as:

Weight = 58.0 kg * 9.8 m/s²

Next, we can set up the equation:

Net force = Tension - Weight = mass * acceleration

Substituting the values, we have:

Tension - (58.0 kg * 9.8 m/s²) = 58.0 kg * 2.37 m/s²

Now, we can solve for the tension:

Tension = (58.0 kg * 2.37 m/s²) + (58.0 kg * 9.8 m/s²)

Calculate the numerical value of the tension in newtons (N).

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Which of the following describes exogenous attention:a. Intentional shifting of attention to a cued locationb. All of the optionsc. Goal-driven shifting of attentiond. Finding a friend in a crowde. Involuntary attentional capture Vertical Loading Phase workout plan is best defined as A. Split Training of 3 major muscle groups per workout using isolation exercises of 4 sets & 10 repetitions B. Using Full Body exercises in an circuit method of 3 sets & 12 repetitions C. A Full Body workout targeting the Chest, Back, & Legs with isolation exercises of 3 sets & 12 repetitions D. A Full Body workout using a minimum of one isolation exercise targeting each major muscle group with 3 sets & 12 repetitions . Choose a distinctive city (anywhere in the world) and approximate that city's geography within SimCity by altering the terrain in the game. Attempt to replicate the zoning and transportation characteristics of the area (a very rough approximation for both is sufficient). Allow the city to evolve over 100 years (hint: increase the game speed if you do not want to wait) then answer the following questions.(a) How does the simulation compare to the actual city? (b) Have the most densely developed and populated areas occurred in the same places? Explain. (c) Observe the RCI graphs. Do you think this is similar to the city for which you have made your model? (d) Examine the desirability indicators for the various forms of residential, commercial, and industrial activity. Are these similar to the real world city? (For example, do high wealth residents in the simulation desire the same areas they do in the real world city?) Overall, what is the Old Testament view towards the Israelite monarchy?a) Completely favorable towards the monarchy.b) Completely anti-monarchical.c) Realistic of the dangers of kingship, but eventually endorsing the Davidic monarchy.d) Supportive of the rule of Saul rather than of David. Where permitted by state law, employers who can provide satisfactory proof of financial ability may carry their own Workers' Compensation risk are referred to as A. re-insured B. Fortune 500 company C. self-insured D. Risk-retention group Let the person look for articles on firing temperatures of porous materials We can write the gravitational acceleration as g = 20 A, where only A has uncertainty.ha) Which error propagation rule (of the 3 listed) is most relevant here?b) Let D = 1.26 m, h = 0. 033 m, and A = 0.1326 0. 0021 m/s?. Compute g.c) Using the rule you identified in part (a), compute 8g.) Write your result in the form g 8g, observing proper significant figures andunits. e) Compute the confidence (Eq. 5.26 from the lab manual) in your result.f What does the confidence tell you about the experiment that measured g?g) The accepted value in Honolulu is g = 9. 79 m/s?. Compute the agreement withyour result. (Eq. 5.28 from the lab manual)h) Does the calculated result agree with expectation? what does odysseus do on the island of cicones that best shows the trait of leadership In one sheet of paper, solve for the inverse of a matrix from any book having dimensions of: 1. 22 2. 33 3. 44 4. 55 Specify both a research and a null hypothesis. Then describe and provide an example of a Type I Error. Describe and provide an example of a Type II Error. Do NOT use a courtroom analogy... but rather a research example (that you made up). Innovation Company is thinking about marketing a new software product. Upfront costs to market and develop the product are $5,200,000. The product is expected to generate profits of $1,300,000 per year for 10 years. The company will have to provide product support expected to cost $120,000 per year in perpetuity. Assume all income and expenses occur at the end of each year. Requirment of documents on behalf of this dream house project inOntario In your opinion, which is the best negotiation style you would adopt to resolve the interpersonal conflict between the female and male co-workers? Justify. The outer segment of rod and cone cells is found near the____ of the eye O anterior part O posterior part O Inner part O none of the above QUESTION 61 Rod cells during the dark resting state release the neurotransmitter_____ which____the____ cells O glycine / excites/ ganglionic O glutamate / inhibits/ ganglionic O glutamate / inhibits/bipolar O glycine / excites/bipolar QUESTION 62 During excitation of a rod cell by light, activation of this enzyme causes the closing of sodium and calcium channels in the rod cell membrane O retinene O retinal O transducin O Opsin QUESTION 63During the light state rod cells of the eye undergo_____ to cause the stimulation of_____cellsO depolarization / ganglionic O repolarization / bipolar O hyperpolarization / bipolar O depolarization / bipolar QUESTION 64 The medial portion of the optic nerve decussates to the other side of the brain at the O thalamus QUESTION 65 Humans have so called_____ vision that enables us with____ perception O monocular / color O binocular color O binocular depth O monoculari depth QUESTION 66 The optic nerve is cranial nerve number_____ O I O II O III O IV QUESTION 67 The primary visual cortex is located in the O temporal lobeQUESTION 68 The first middle ear structure that receives sound wave vibrations from the tympanic membrane is called the O incus O malleus O slapes O cochlea QUESTION 69 The membraneous labyrinth of the inner ear is filled with O perilymph O endolymph O exolymph O cerebrospinal fluid QUESTION 70 The region of the inner ear that contains receptors that function in hearing is called the O auricie QUESTION 71 The organ that contains the receptors for sound in the inner ear is the O Organ of Corti O Organ of Vestibul O Organ of Cortez O None of the above QUESTION 72 Bending of the basilar membrane causes opening of____ channels on hair cells by the use of_____ protein channels O potassium and sodium / ligand gated O sodium and calcium / tip link mechanical O potassium and calcium / tip link mechanical O sodium and chloride / ligand gated QUESTION 73 This part of the inner ear contains receptors for static equilibrium O vestibule O semicircular canals O cochlea O none of the above QUESTION 74 The semicircular canals contain receptors that respond to O angular acceleration and dynamic equilibrium O static position of the head relative to gravity O sound waves with low pitch O sound waves with high pitch QUESTION 75Within the semicircular canals this fluid is found O perilymph O ectolymph O endolymph O hyaluranic acid QUESTION 77 All of the following are true for hormones, except O they are released into the blood O they are chemical messengers O they are released from both endocrine and exocrine glands O they attach to receptors on target cells QUESTION 78 The specific part of the anterior diencephalon that functions in the release of releasing hormones that control the release of some hormones from the pituitary gland is called the QUESTION 79All of these hormones are released from the anterior pituitary, except O Antidiuretic hormone O Follicle Stimulating hormone O Growth hormone O Adrenocorticotropic hormone QUESTION 80 The hormone of the anterior pituitary that causes milk prodution in the mother is O Lutenizing hormone O Growth hormone O Prolactin O Follicle Stimulating hormone QUESTION 81 The only hormone that has iodide in its composition is Use the Euclidean Algorithm to computegcd(15,34). You must show your work Replace each _____ with >,< , or = to make a true statement.32mm_______ 3.2cm Joseph would like to purchase a 6-year bond. Before the bond matures, it will pay an annual coupon payment of $75 at the end of each year. When the bond matures at the end of year 6 , it will pay $1,000. If Joseph would like to have a rate of return of 8.60% on his bond investment, how much should Joseph pay for this bond?" with "Incomplete" Find solutions for your homeworkFind solutions for your homeworkbusinessfinancefinance questions and answerschoose the response that correctly completes the next sentence. a recent change in the law allows eligible employees of privately held corporations to: elect to postpone for up to five years the payment of taxes on the value of qualified stock acquired through the exercise of employee stock options and/or restricted stock units. postpone for up to fiveThis problem has been solved!You'll get a detailed solution from a subject matter expert that helps you learn core concepts.See AnswerQuestion: Choose The Response That Correctly Completes The Next Sentence. A Recent Change In The Law Allows Eligible Employees Of Privately Held Corporations To: Elect To Postpone For Up To Five Years The Payment Of Taxes On The Value Of Qualified Stock Acquired Through The Exercise Of Employee Stock Options And/Or Restricted Stock Units. Postpone For Up To FiveChoose the response that correctly completes the next sentence. A recent change in the law allows eligible employees of privately held corporations to:Elect to postpone for up to five years the payment of taxes on the value of qualified stock acquired through the exercise of employee stock options and/or restricted stock units.Postpone for up to five years the payment of capital gain taxes on the sale of stock acquired through the exercise of employee stock options.Receive cash in lieu of company stock.Sell restricted stock units back to the company What type of study is (a) Study 1 and (b) Study 2?Write a 2 to 3 paragraphs to explain your answer for (a) and (b).At the base of thisYou hear that two research studies are enrolling students on campus.Study 1 is recruiting students with and without dandruff. This study will use food frequency questionnaires to look at past dietary intake.Study 2 is recruiting healthy students and administering food frequency questionnaires. They will then track participants over time to look at the development of Alzheimer's disease. A full water tank in the shape of an inverted right circular cone is 14 m across the top and 7 m high. If the surface of the water inthe tank is 2 m below the top of the tank, how much work is required to pump all the water over the top of the tank? (The densityof water is 1000 kg/m, use neceleration due to gravity g = 9.8 N/kg.) Steam Workshop Downloader