A 9.00 kg object is dropped from rest near the surface of an unknown planet and begins to accelerate at 6.00 m/s2. What is the weight of the object on the unknown planet? (*Remember* F=ma)

Explanation:

See image for definitions....look at the units and fill the blanks appropriatly

The statement that best fits the graph is: D) Car B is faster than A because B's motion is accelerating and A is constant speed.

From the graph, we can see that the distance traveled by both cars increases over time. However, the slope of the distance-time graph for car B is steeper than that of car A. This means that car B covers more distance in the same amount of time as car A, indicating that car B is traveling faster than car A.

Furthermore, we can see that the speed-time graph for car B is a straight line with a positive slope, indicating that its speed is increasing over time. On the other hand, the speed-time graph for car A is a horizontal line, indicating that its speed is constant.

Therefore, we can conclude that car B is faster than car A because car B's motion is accelerating, while car A is moving at a constant speed.

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Explanation:

It ignores some basic laws of physics:

  You cannot get more work out of a machine than goes in

    You cannot ignore friction

(a) The final velocity of the blue ball is 5 m/s after the collision

(b)  The final velocity of the blue ball is 6 m/s after the collision.

To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy. The total momentum and total kinetic energy of the system before and after the collision must be the same.

a. When the green ball stops moving after the collision, its final velocity is 0 m/s. Let's call the final velocity of the blue ball v. The conservation of momentum equation is:

m_green x v_green + m_blue x v_blue = (m_green + m_blue)v

Substituting the values, we get:

10 kg x 10 m/s + 10 kg x 0 m/s = 20 kg x v

Simplifying, we get:

v = 5 m/s

b. When the green ball continues moving after the collision at 4 m/s in the same direction, its final velocity is 4 m/s. Let's call the final velocity of the blue ball v.

The conservation of momentum equation is the same as before:

m_green x v_green + m_blue x v_blue = (m_green + m_blue)v

Substituting the values, we get:

10 kg x 10 m/s + 10 kg x 0 m/s = 10 kg x 4 m/s + 10 kg x v

Simplifying, we get:

v = 6 m/s

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Answer:

A person who drives a car for themselves, generally taking themselves back and forth to work or errands, is generally referred to as a driver.

Assuming a circular orbit for the Sun, we can use the equation:

v^2 = GM/r

where v is the orbital velocity of the Sun, r is the distance from the center of the galaxy, G is the gravitational constant, and M is the mass of the galaxy.

We can solve for M:

M = v^2 * r / G

Using the given values of v = 240 km/s and r = 7.2 kpc = 7.2 * 3.086e+19 m, and G = 6.6743e-11 N m^2/kg^2, we get:

M = (240000 m/s)^2 * 7.2 * 3.086e+19 m / 6.6743e-11 N m^2/kg^2

M = 1.47e+42 kg

Therefore, the minimum mass of the galaxy, if the distance of the solar system from the center is actually 7.2 kpc, is approximately 1.47 x 10^42 kg.

Answer:52.972ft^3

Explanation:

It is unit conversion based and for a volume of a bin from cubic meter to cubic foot as we know 1 meter =3.281 foot.

where volume=1.5m^3

multiply 1.5*(3.281)^3 ft^3

v=52.972 ft^3

Answer:

true it is refraction of visible

The rate of heat flow through the window is approximately 84.38 W.

The rate of heat flow through the window can be calculated using the formula:

Q = (kA (T1 - T2))/d

Where

We first need to convert the temperatures to Kelvin, since temperature differences must be in Kelvin in this formula:

T1 = 15.0°C + 273.15 = 288.15 K

T2 = 14.0°C + 273.15 = 287.15 K

The thermal conductivity of glass can vary depending on the type of glass, but a typical value is around k = 0.9 W/(m·K) for plate glass.

Substituting the given values into the formula, we get:

Q = (0.9 W/(m·K) x 2.0 m x 1.5 m x (288.15 K - 287.15 K))/0.0032 m

Simplifying this expression, we get:

Q ≈ 84.38 W

Therefore, the rate of heat flow through the window is approximately 84.38 W.

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Explanation:

let at a distance x from the c

Basic values of mass in the existing program are c1/2 G-12 h1/2 if the speed of light (c), newtonian constant (G), and Planck's parameter (h) are taken as the fundamental units.

According to the Universal Gravitation Equation, G is equal to 6.673 x 10-11 N m2/kg2. Everything because of how a fruit falls from a tree to the reason the moon rotates around the earth may be explained by the Universal Gravitational Law.

This rule states that the distance is proportional to the product of the mass of the two objects. The Universal Law of Force of gravity is summed up by the following gravitational force equation: FG = (G.m1.

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Answer:

4 & 2

Explanation:

If you plug in experimental values into the formula for kinetic energy, you will see the relationship.

1.

[tex]\frac{1}{2}(2 kg)(2 m/s)^{2} = 4 kg * m^{2} /s^{2} \\\\\frac{1}{2}(8 kg)(2m/s)^{2} = 16 kg * m^{2} /s^{2}\\\\\frac{16}{4} = 4[/tex]

2.

[tex]\frac{1}{2}(6 kg)(2m/s)^{2} = 12 kg * m^{2} /s^{2} \\\\\frac{1}{2}(3 kg)(2 m/s)^{2} = 6 kg * m^{2}/s^{2}\\ \\\frac{12}{6} = 2[/tex]

Answer:

The answer is 8%

Explanation:

We know that the efficiency of the machine is given by,

E=(M.A)*100

=([tex]\frac{20}{50}[/tex])*[tex]\frac{1}{5}[/tex]*100

=8%

PLS MRK ME BRAINLIEST

Answer:

True

Explanation:

optical fibre consists of core and cladding. The signal is converted to light using transducers. The light travels across the cable undergoing multiple internal reflections. At the other end the light is converted back to Signal using transducers.

Answer: True

Explanation: Optical fiber uses the optical principle of "total internal reflection" to capture the light transmitted in an optical fiber and confine the light to the core of the fiber.

If I get this wrong im sorry

Answer:

The acceleration of an air cart, which is an object moving on a cushion of air, would not change when adding mass to it because the force of air resistance acting on the cart is negligible compared to the force applied by the air source that propels it. Therefore, the total force acting on the cart remains almost constant, regardless of the cart's mass, and according to Newton's second law of motion, the cart's acceleration would remain the same. This assumes that the air source provides a constant force and that the added mass does not significantly affect the friction between the cart and the surface on which it is moving.

Answer:

Quantum physics is the study of matter and energy at the most fundamental level. It aims to uncover the properties and behaviors of the very building blocks of nature.

The number of sources that we have to add at A so that the sound level intensity at M is doubled is 2.

(a) Let the distance of point A from one source be x. Then the distance from the other source is (OA - x), where OA is the distance between the two sources. The sound intensity at point A due to one source is proportional to 1/x^2. So, if the sound power of one source is P, then the sound intensity at A due to one source is given by I = P/(4πx^2), where 4πx^2 is the surface area of a sphere with radius x.

The sound level intensity is defined as L = 10log(I/I0), where I0 is a reference intensity (I0 = 10^-12 W/m^2). Since there are two sources, the total sound intensity at A is twice the sound intensity due to one source, i.e., I_total = 2I = 2P/(4πx^2). Therefore, the sound level intensity at A is L = 10log(2P/(4πx^2I0)) = 10log(2P/(4πI0)) - 20log(x).

(b) Let the distance of point M from one source be y. Then the distance from the other source is (OM - y), where OM is the distance between O and M. The sound intensity at M due to one source is proportional to 1/y^2. So, if the sound power of one source is P, then the sound intensity at M due to one source is given by I = P/(4πy^2), where 4πy^2 is the surface area of a sphere with radius y.

The sound level intensity at M due to one source is L_M = 10log(I/I0) = 10log(P/(4πy^2I0)).

Since the sound intensity is inversely proportional to the square of the distance, the sound intensity at A due to one source is four times the sound intensity at M due to one source. Therefore, I_A = 4I = 4P/(4πy^2), and the sound level intensity at A due to one source is L_A = 10log(I_A/I0) = 10log(P/(πy^2I0)).

We want the total sound level intensity at M due to all sources to be L_M = L_A + 10log2, where 10log2 is the sound level intensity increase due to adding a second source. Therefore, we have:

10log(P/(4πy^2I0)) + 10log2 = 10log(P/(πy^2I0))

10log2 = 10log(4/π)

log2 = log(4/π)

2 = 4/π

π = 2

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The electric field 0.40 m away from a source charge of 3.00 x 10^-5 C is 1.69 x 10^6 N/C, directed away from the source charge.

The electric field created by a point charge at a distance r from the charge is given by the equation:

E = kQ/r^2

where

E is the electric field in N/C,

k is Coulomb's constant (9.0 x 10^9 N m^2/C^2),

Q is the source charge in Coulombs, and

r is the distance from the source charge in meters.

Substituting the given values into the equation, we get:

E = (9.0 x 10^9 ) x (3.0 x 10^-5) / (0.40)^2

E = 1.69 x 10^6 N/C

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The relative density of kerosene is 0.006, or 6 kg/m³.

1 Response. Employ the Archimedes' Principle to your advantage: the buoyant force of a fluid is equal to the apparent loss of weight in water and is also equal to the weight of the displaced fluid. Weight of the displaced water equals 60 - 40 N, or the apparent loss in weight of the metal block. Water displacement mass is calculated as 20 / 9.8 = 2.04 kg.

Buoyant force = Weight of the displaced water = 20 N - 12 N = 8 N

Volume of water displaced = Buoyant force / Density of water = 8 N / 9.8 m/s² = 0.8163 kg

Density of metal = Weight of metal in air / Volume of metal = 20 N / (density of air x volume of metal)

Density of metal = 20 N / 0.8163 kg = 24.5 kg/m³

Buoyant force = Weight of the displaced kerosene = 20 N - 14 N = 6 N

Volume of kerosene displaced = Buoyant force / Density of kerosene = 6 N / 9.8 m/s² = 0.6122 kg

Density of kerosene = Mass of kerosene / Volume of kerosene displaced = 14 N / 0.6122 kg = 22.86 kg/m³

Relative density of kerosene = Density of kerosene / Density of water = 22.86 kg/m³ / 1000 kg/m³ = 0.006, or 6 kg/m³.

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the magnitude of the electric field in the region between the plates is 1.44 × [tex]10^6[/tex]V/m.

The electric field between the plates of the CRT can be calculated using the formula:

E = V/d

where E is the electric field, V is the potential difference across the plates, and d is the distance between the plates.

Substituting the given values, we get:

E = 24.5 kV / 0.017 m

Converting kV to V and simplifying, we get:

E = 24.5 × [tex]10^3[/tex]V / 0.017 m

E = 1.44 × [tex]10^6[/tex] V/m

An electric field is a force field created by a charged object or collection of charged objects that exerts a force on other charged objects within its vicinity. The electric field is a vector quantity and is measured in units of volts per meter (V/m).

The electric field at a point in space is defined as the force per unit charge acting on a positive test charge placed at that point. The direction of the electric field is given by the direction of the force that would be experienced by a positive test charge placed at that point.

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It takes 0.3 seconds for a force of 1000 N to halt a 10,000 kg goods car moving at 3.00 m/s along a track.

We must first establish the car's starting kinetic energy in order to calculate the time required to stop the vehicle:

Kinetic Energy (KE) is equal to half of mass times speed, or 10,000 kg times 3.00 m/s.

KE = 45,000 J

Then, we may use the designed with the intent, which asserts that an object's change in kinetic energy equals the jobs performed by an external force: Work equals Force x Distance x Change in KE.

The gain in kinetic energy is equal to the starting kinetic energy because the car is coming to a stop: KE Change = -45,000 J

As a result, the external force's work is: Work equals force times distance, or -45,000 J.

When we solve for distance, we obtain: Work / Force = -45,000 J / 1000 N Distance

Location = -45 m

Because the force is against the direction of the car's motion, you'll see that the range is negative.

Finally, we can calculate the travel time using the kine model for uniformly accelerated motion: Distance is equal to 1/2*acceleration*time2. Time is calculated as sqrt(2 * Distance / Acceleration) as well as sqrt(2 * 45 m / (1000 N / 10,000 kg)).

time equals sqrt(0.09 s2/kg).

time = 0.3 s

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The object's distance from the lens is 11.4 cm.

The thin lens equation can be used to determine how a converging lens's object distance (p), image distance (q), and focal length (f) relate to one another:

1/p + 1/q = 1/f

where p denotes the distance to the object, q is the distance to the picture, and f is the focal length.

Let's solve for the object distance using the thin lens equation:

1/p + 1/59.6 = 1/9.56

Combining both sides with p59.69.56 results in:

59.69.56 + p9.56 = p*59.6

Adding and subtracting:

570.176 + 9.56p = 59.6p

50.04p = 570.176

p = 11.4 cm

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Answer:

the magnitude of the frictional force acting between the box and the floor is 5 N.

Explanation:

The acceleration of the car was 6.88 [tex]m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.

To find the acceleration of the car, we can use the following formula:

acceleration = (final velocity - initial velocity) / time

However, we are not given the time it took for the car to undergo the displacement. To find the time, we can use the following formula:

displacement = (final velocity + initial velocity) / 2 * time

Solving for time, we get:

time = displacement / ((final velocity + initial velocity) / 2)

Plugging in the given values, we get:

time = [tex]-105 / ((-10.9 - 27.7) / 2) = 2.29 s[/tex]

Now that we have the time, we can use the first formula to find the acceleration:

acceleration = [tex](-10.9 - (-27.7)) / 2.29 = 6.88 m/s^2[/tex]

Therefore, the acceleration of the car was [tex]6.88 m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.

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Answer: just say no and never talk to that person again.

Explanation:

because that is what i would do to prevent drugs and/or nicotine to enter my body.

it's only beyond the surface of the sun! There is a barycenter throughout our entire solar system. All of the planets in the solar system, including the sun, center of mass.

The sun is significantly more massive than Earth and has a radius that is likewise much greater. The mass of the sun is more than 333,000 times more than the mass of the Earth and makes up nearly all of the solar system's mass (99.8%).

The Sun is 1000 times more than Jupiter, the solar system's most planet , but Jupiter is still 1000 times less than it.

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Answer:

To convert temperature from the new scale (X) to Celsius, we simply subtract 0 from the value in X and then multiply the resulting number by a factor of 100/70. This gives us the Celsius temperature.

For 35° X, we can use the formula as follows:

C = (35 - 0) * (100/70)

C = 35 * 1.4286

C = 50°C

Therefore, the correct answer is option A, which is 50.

the magnitude of the friction force on the disk is approximately 1.16 N.

We can use the conservation of energy to find the friction force on the disk. The initial kinetic energy of the wheel is equal to the work done by the friction force on the disk:

K_i = W_friction

The initial kinetic energy of the wheel can be found from its moment of inertia and angular velocity:

K_i = (1/2) I [tex]ω^2[/tex]

where I is the moment of inertia, ω is the angular velocity, and the factor of 1/2 comes from the rotational kinetic energy formula.

The final kinetic energy of the wheel is zero, since it comes to a stop. The work done by the friction force can be found from the distance over which it acts:

W_friction = F_friction d

where F_friction is the friction force and d is the distance over which the pads act on the disk. We can find the distance from the angular displacement of the wheel:

θ = ω t

where θ is the angle through which the wheel rotates, t is the time for the wheel to come to a stop, and the factor of 1/2π converts from rotations to radians. The distance over which the pads act is then:

d = r θ = 0.071 m × (5/2π) ≈ 0.562 m

Now we can put everything together:

K_i = W_friction

(1/2) I [tex]ω^2[/tex] = F_friction d

We can solve for the friction force:

F_friction = (1/2) I [tex]ω^2[/tex] / d

Plugging in the given values:

F_friction = (1/2) ×[tex]0.097 kg⋅m^2[/tex] × [tex](5/2.2π rad/s)^2[/tex] / 0.562 m ≈ 1.16 N

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Answer:

a = 3.02 m/s^2

h

Explanation:

we know that centripetal acceleration (a) is

[tex] \frac{v {}^{2} }{r} = a[/tex]

since v = rω, we can substitute it into the equation, which now gives us the centripetal acceleration in terms of angular velocity and radius (check image).

now we use the values given and find the answer