1. A tourist accidentally drops a camera from a 40.0 m high bridge and it falls for 2.85 seconds. If g = 9.81 m/s2 and air resistance are disregarded, what is the speed of the camera as it hits the water?
I NEED HELP plsssss
Answer:
28 m/s
Explanation:
vf^2=vi^2+2a(delta y)
=sqrt(2* -9.8 m/s^2* -40 m)
=28 m/s
Which action will cause the induced current to decrease or remain constant?
A. Moving the magnet faster B. Increasing the strength of the magnet
C. Adding more turns to coil. D. Reversing polarity of the magnet.
Answer:
Its Reversing the polarity of the magnet :)
Explanation:
The action that cause the induced current for reduce or be same is when the polarity is reverse with respect to the magnet.
The following actions should not induced the current:
In the case when the magnet moved in the fastest way. When the magnet strength is increased. And, when the more turns to coil is added.Therefore we can conclude that the action that cause the induced current for reduce or be same is when the polarity is reverse with respect to the magnet.
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Experiments need to be repeated by the scientist and also replicated by other scientists.
true
false
Answer:
false
Explanation: because the other scientists could've missed something in there experiment
A cell contains 20% solute. If it is placed in a solution with 35% solute, what will happen to the cell?
PLEASE HELP!! Salmon often jump waterfalls to reach their
breeding grounds.
Starting downstream, 3.41 m away from a
waterfall 0.397 m in height, at what minimum
speed must a salmon jumping at an angle of
28.4° leave the water to continue upstream?
The acceleration due to gravity is 9.81 m/s2
Answer in units of m/s.
Answer:
7.13781 m/s
Explanation:
X-direction | Y-direction
[tex]x=v_{xo}t+\frac{1}{2}a_{x}t^2[/tex] | [tex]y=v_{yo}t+\frac{1}{2}a_{y}t^2[/tex]
[tex]3.41=v_{o}cos(28.4)t[/tex] | [tex]0.397=v_{yo}sin(28.4)t+\frac{1}{2} (-9.81)t^2[/tex]
[tex]3.41=v_{o}(0.87964)t[/tex] | [tex]0.397=v_{yo}sin(28.4)(\frac{3.87658}{v_{o} })+\frac{1}{2} (-9.81)(\frac{3.87658}{v_{o} })^2[/tex]
[tex]\frac{3.41}{0.87964}=v_{o}t[/tex] | [tex]0.397=1.84379-\frac{73.71171}{v^2}[/tex]
[tex]\frac{3.87658}{v_{o} } =t[/tex] | [tex]7.13781=v[/tex]
The speed of light is 300,000 kilometres per second. This number isn't easy to get a feel for but it's good it's so fast because it allows us to see things instantly on Earth without waiting for the light to arrive.
The Sun is far enough away that light takes an appreciable time to travel to us. Assuming the sun is 150,000,000 kilometres away, how long would it take us to realize if the sun suddenly stopped shining?
Answer:
499 seconds or a little over 8 minutes
Explanation:
~150 million km/ 300,000 km per second = 500 seconds
You are piloting a General Aviation aircraft (e.g. Cessna 172) over the Georgia Tech campus in level flight at 3000 ft altitude. Your airspeed indicator shows that the true airspeed is 100 knots. You have trimmed the aircraft to have no sideslip and pitch angle at a 3 degree angle of attack. Your magnetic compass (which is uncorrected for magnetic variation) indicates that you are flying in the direction of local magnetic East. A local weather forecast predicted the winds to be steady at 10 knots coming exactly from the northeast direction at the time you took off.
a. Using the information provided above and any additional information you may require (state what it is), determine your aircraft's north and east velocity components, Vn and ve, in knots. Starting from Tech Tower at t = 0, you continue in this direction and you are planning to fly directly over a local VOR beacon exactly 10 minutes later. However, you note that you don't pass directly over the beacon and after 10 minutes and 15 seconds have elapsed you are exactly 300 meters away from the VOR beacon in the Easterly direction.
b. Assuming the discrepancy is attributable only to wind speed, estimate the actual average wind speed components, Vwind-n and Vwind-e in knots. Use a flat Earth approximation.
c. Based on the instruments you are using, describe 3 common causes of measurement error that could affect the output of either sensor.
Answer:
a) vₓ = 100 + 7.07 = 107.07 knot (East) , v_{y} = 7.07 knot (North)
b) v_wind_ North = 0 , v_wind_West = 61.12 knot (West)
Explanation:
a) This is a vector velocity addition problem, they tell us that the plane goes East at 100 Knots and the wind goes North East at 10 Knots
the components ask the total speed of the plane.
For this we decompose the wind speed
cos 45 = v₂ₓ / V₂
sin 45 = [tex]v_{2y}[/tex] / v₂
v₂ₓ = v₂ cos 45
v_{2y} = v₂ sin 45
v₂ₓ = 10 cos 45 = 7.07 m / s
v_{2y} = 10 sin45 = 7.07 m / s
the speed of the plane is
vₓ = v_plane + v₂ₓ
v_{y} = v_{2y}
vₓ = 100 + 7.07 = 107.07 knot (East)
v_{y} = 7.07 knot (North)
speed is
v = (107.07 i ^ + 7.07 j ^) knot
b) Estimated time for Target VOR t = 10 min
for a time of t = 10 min and 15 s, it is at a distance of d = 300 m from the VOR in an easterly direction
find the average speed of time on the ride
in the North direction there is no deviation so the average wind speed is zero
v_wind_ North = 0
In the east direction
as the estimated time was 10 min and the real time for the distance is 10 min 15 s
the time difference is t = 15 s to travel d = 300 m
with these data we can calculate the speed of the plane
v = x / t
v = 300/15
v = 20 m / s
let's reduce this speed to knot
v_real = 20 m / s (1knot / 0.5144 m / s) = 38.88 knots
therefore the wind speed is
v_tral = v_plane + v_wind_Este
v_wind_Este = v_real - v_avión
v_wind_Este = 38.88 - 100
v_wind_Este = -61.12 knot
the negative sign indicates that the wind is going west
v_wind_West = 61.12 knot (West)
3)
* The compass is not calibrated, to correct the magnetic deviation, therefore it gives an appreciable error in the direction
* The wind speed is taken when leaving, but there is no constant monitoring, so a change in direction or wind speed in the trajectory can significantly affect the results.
* The aircraft may noir throughout the trajectory at level, due to pitch errors
Which of the following does not affect gas pressure
Answer:
I NEED OPTIONS
Explanation:
10. A boy runs 5 miles East then turns around and runs 7.5 miles West. What is
his displacement?
Answer:
2.5
Explanation:
The diagram below shows a simplified floor plan for a small house. As the day goes on and the sun begins to set the rooms on the west side of the house grow warmer than the rooms on the east side as shown by the temperatures in each room.
The doors between the rooms are open. Which of the following most likely describes the direction of heat flow through the house and the effect of the great flow on temperature?
The options are in the picture please help i’ll give brainliest!!!
Answer:
Your answer is C! :D
Explanation:
From Room 1 to Rooms 2 and 3 until all rooms are about 27°C. The correct option is C.
What is heat flow?The movement of heat (energy) from the interior of the Earth to the surface is referred to as heat flow.
The majority of the heat is generated by the cooling of the Earth's core and the generation of radioactive heat in the upper 20 to 40 km of the Earth's crust.
The direction of heat flow is determined by the temperature difference between the bodies. Heat is transferred from a hotter body to a colder one.
As the illustration depicts a simplified floor plan for a small house. As the day progresses and the sun sets, the rooms on the west side of the house become warmer than the rooms on the east, as evidenced by the temperatures in each room.
The direction of heat flow through the house, and the effect of the large flow on temperature, will be from Room 1 to Rooms 2 and 3, until all rooms are around 27°C.
Thus, the correct option is C.
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A cannon is fired straight up into the air. If the cannon ball comes back down to the launch point in 5 seconds, what was the maximum height reached by the ball?
Answer:
30.63 m
Explanation:
From the question given above, the following data were obtained:
Total time (T) spent by the ball in air = 5 s
Maximum height (h) =.?
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Total time (T) spent by the ball in air = 5 s
Time (t) taken to reach the maximum height =.?
T = 2t
5 = 2t
Divide both side by 2
t = 5/2
t = 2.5 s
Thus, the time (t) taken to reach the maximum height is 2.5 s
Finally, we shall determine the maximum height reached by the ball as follow:
Time (t) taken to reach the maximum height = 2.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
h = ½gt²
h = ½ × 9.8 × 2.5²
h = 4.9 × 6.25
h = 30.625 ≈ 30.63 m
Therefore, the maximum height reached by the cannon ball is 30.63 m
An object is moving at 2.50 m/s [E]. At a time 3.00 seconds later the object is traveling at 1.50 m/s
[E]. What was the displacement during this 3.00 second time interval?
Given parameters:
First velocity = 2.50m/s
Time of travel = 3s
Second velocity = 1.50m/s
Unknown:
The displacement during the first interval = ?
Velocity is the displacement of a body with time. Displacement is a distance move in a specific direction by a body.
Velocity = [tex]\frac{Displacement}{Time taken}[/tex]
So;
Displacement = Velocity x Time taken
Now input the parameter for the first velocity and time of travel;
Displacement = 2.5 x 3 = 7.5m
The displacement id 7.5m
according to newton’s first law a moving object acted on by a net force of zero....
Answer:
Newton's first law says that if the net force on an object is zero ( Σ F = 0 \Sigma F=0 ΣF=0\Sigma, F, equals, 0), then that object will have zero acceleration. That doesn't necessarily mean the object is at rest, but it means that the velocity is constant.
Explanation:
According to Newton’s first law of motion, a moving object acted on by a net force of zero will continue in motion.
Newton's first law of motion states that an object in state of rest or uniform motion in a straight line will continue in that state unless it is acted upon by an external force.
This first is also known as the law of inertia because it is the reluctance of an object in motion to stop moving or reluctance of an object at rest to start moving which depends on the mass of the object.
Thus, we can conclude that according to Newton’s first law of motion, a moving object acted on by a net force of zero will continue in motion.
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The suffix used to name a monatomic anion is
O A. ite
O B. ide
O C. anion
O D. ate
 explain why earths acceleration is usually very small compared to the acceleration of the object the earth interact with
Answer:
F-ma
Explanation:
If you are speaking of objects like satellites, etc. then their mass is much less than that of the Earth. A good approximation is Newton's first law of motion:
Force = Mass × Acceleration
often written:
F = m a
The gravitational force is the same between the Earth and the object - only the mass differs. So the acceleration is inversely proportional to the mass.
Three vectors, one of 74 km at 30°, the second of 54 km at 135°, and the final of 62 km due South. What is the sum of the three vectors?
- will give brainliest -
Answer:
The sum of the three vectors are 63.18 km.
Explanation:
Given that,
One vector = 74 km at 30°
Second vector = 54 km at 135°
Third vector = 62 km
We need to calculate the sum of the three vectors
Using given data
[tex]R=\vec{A}\sin\theta+\vec{B}\sin\theta+\vec{C}[/tex]
Put the value into the formula
[tex]R=-74\sin30+54\sin135+62[/tex]
[tex]R=63.18\ km[/tex]
Hence, The sum of the three vectors are 63.18 km.
The mass of proton is 1.67x10 kg. How many protons will make a mass of
1,00kg?
1011
Answer: 938
Explanation:
1.67x10^-27kg (938V/c2)
You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogrammeter3kilogrammeter3 and the density of silicon in other units: 2.332.33 gramcentimeter3gramcentimeter3. You decide to convert the density of silicon into units of kilogrammeter3kilogrammeter3 to perform the comparison. By which combination of conversion factors will you multiply 2.332.33 gramcentimeter3gramcentimeter3 to perform the unit conversion?
Answer:
The conversion factors you will use to multiply is 1/0.001 or simply 1000 to perform the unit conversion.
Explanation:
To convert from gram/centimeter³ to kilogram/meter³
First,
NOTE:
1 kilogram = 1000 gram, that is 1 gram = 0.001 kilogram; and
1 meter = 100 centimeter, that is 1 centimeter = 0.01 meter
then,
1 meter³ = 1000000 centimeter³, that is
1 centimeter³ = 0.000001 meter³
Now, we can write that
1 kilogram/meter³ = 1000 gram / 1000000 centimeter³
= 0.001 gram/centimeter³
If 1 kilogram/meter³ = 0.001 gram/centimeter³
Then, 1 gram/centimeter³ = 1/0.001 kilogram/meter³ = 1000 kilogram/meter³
Hence, 1 gram/centimeter³ = 1000 kilogram/meter³
∴The conversion factors you will use to multiply is 1/0.001 or simply 1000 to perform the unit conversion.
That is,
2.33 gram/centimeter³ will be 2.33 × 1000 kilogram/meter³
= 2330 kilogram/meter³
what will happen if a low massive main sequence star runs out of hydrogen fuel?
Answer:
Low mass stars are: hydrogen burning in the core while on the Main Sequence. As the hydrogen fuel runs out, extreme pressure raises the temperature to 100 million degrees, where helium burning becomes possible.
what is 100+10000000000000000000
Answer:
200000000000000000000000
Explanation:
Answer:
10000000000000000100
Explanation:
In the equation, y = A sin( wt - kx ), obtain the dimensional formula ' w ' and ' k.
Answer:
In the given equation y=Asin(ωt−kx)
Since, trigonometric function is a dimensionless quantity. So, (ωt−kx)is also dimensionless quantity.
So,
(ωt−kx)=1
ωt=1
[ω]= 1=[T] ^−1
[T]
kx=1
[k]= 1=[L]^ −1
[L]
A train travels 600 km in 4 hours. What is the speed of the train?
0.007 km/h
O 604 km/h
O 150 km/h
O 2,400 km/h
The speed of the train is 150 Km/h.
Speed can be defined as the distance travelled over a period of time. Mathematically, it can be expressed as:
Speed = Distance / Time
With the above formula, we can obtain the speed of the train as shown below:
Distance = 600 KmTime = 4 hours Speed =?Speed = Distance / Time
Speed = 600 / 4
Speed = 150 Km/h
Therefore, the speed of the train is 150 Km/h.
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If a car hits a tree, the tree pushes back on the car. Damage to the car and/or the tree depends on what factors?
Answer:
Acceleration and mass.
Explanation:
Depends on how heavy the car is and how fast it is going.
F=MA
Which statement describes the direction of the current and the magnetic field when the left hand rule is being used?
Answer:
They are perpendicular.
Explanation:
A 2.5 μF capacitor consists of 2 large, thin metal plates separated by a plexiglas sheet. The plexiglas sheet has a dielectric constant of 3.4. The capacitor is connected to a 60 V battery and fully charged. Then, whilst still connected to the battery, the plexiglas sheet is removed (assume that the spacing between the metal plates does not change). Calculate the amount of charge that flows to (or from) the capacitor plates when the sheet is removed. Additional charge flowing onto the plates is represented with a + sign and charge leaving the plates is represented with a - sign.
Answer:
Q / Q₀ = 3.4 , ΔQ = 31.14 10⁻⁶ C
Explanation:
For this exercise we will calculate the charge of the capacitor with and without dielectric
the capacitance is given by
C = Q /ΔV
we also use the ratio of capacitances
C = k C₀
Q /ΔV = kQ₀ /ΔV
Q = k Q₀
Q / Q₀ = k
Q / Q₀ = 3.4
If we want a numerical value
C = k Q / DV
Q = C ΔV / k
Q = 2.5 10⁻⁶ 60 / 3.4
Q = 44.12 10⁻⁶ C
whereby the charge without dielectric is
Q₀ = Q / 3.4
Q₀ = 44.12 / 3.4 10⁻⁶
Q₀ = 12.98 10⁻⁶ C
therefore the charge when removing the dielectric is reduced, the amount of charge that flows is
ΔQ = Q - Q₀
ΔQ = (44.12 - 12.98) 10⁻⁶
ΔQ = 31.14 10⁻⁶ C
The amount of charge should be Q / Q₀ = 3.4 , ΔQ = 31.14 10⁻⁶ C
Capacitor:For this given situation, we will determine the charge of the capacitor with and without dielectric
We know that
the capacitance is given by
C = Q /ΔV
Now here we can applied the ratio of capacitances
So,
C = k C₀
Q /ΔV = kQ₀ /ΔV
Q = k Q₀
Q / Q₀ = k
Q / Q₀ = 3.4
In case of numerical value
C = k Q / DV
Q = C ΔV / k
Q = 2.5 10⁻⁶ 60 / 3.4
Q = 44.12 10⁻⁶ C
whereby the charge without dielectric is
Q₀ = Q / 3.4
Q₀ = 44.12 / 3.4 10⁻⁶
Q₀ = 12.98 10⁻⁶ C
Thus the charge at the time when removing the dielectric is decreased , the amount of charge that flows is
ΔQ = Q - Q₀
ΔQ = (44.12 - 12.98) 10⁻⁶
ΔQ = 31.14 10⁻⁶ C
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in which of the following media does sound travel faster?
Answer:
Sound travel faster through the medium of solid.
Protons and ____ have electric charge?
Marie curie investigation method
Answer: To isolate the unknown substances, of which only tiny amounts were present, the Curies were the first to use a new method of chemical analysis. They employed various standard (but sometimes demanding) chemical procedures to separate the different substances in pitchblende.
Explanation:
2.389 x 10^5 mi . Convert this distance to standard form.
Answer:
238 900 miles
Explanation:
google said it.
A car travels 45 km due north and 70 km west. What is the car's displacement? 6 points 24.7 km northeast 83.2 km northwest 76.5 km northwest 115 km north
Answer:
3150
Explanation:
if if you were two times 45 times 70 it would give you that answer