[tex]\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2\\\\~~~~~=\dfrac 12 \cdot 110 \times 10^{-3} \cdot 50^2\\\\~~~~~=137.5~ \text{J}[/tex]
Answer: 137.5 Joules
Explanation:
The SI units for kinetic energy is Joules, the SI units for mass is kilograms, and the SI units for velocity is meters per second. We are given the mass in grams, so we must convert it to kilograms. There are 1,000 grams in 1 kilogram:
[tex]110g*\frac{1kg}{1000g} =0.11kg[/tex]
Kinetic energy is the energy the system has due to its motion. It is defined to be:
[tex]KE=\frac{1}{2} mv^2[/tex]
Plug everything in:
[tex]KE=\frac{1}{2} (0.11kg)(50m/s)^2[/tex]
[tex]KE=137.5J[/tex]
PLEASE HELP
Which of the following is an example of a chemical reaction?
hydrogen peroxide and yeast are combined, producing lots of bubbles and heat
atoms of silver are bonded together to make a silver nugget
heat is applied to melt chocolate chips
red and blue paints are mixed to make purple paint
brainly an andean condor with a wingspan and a mass soars along a horizontal path. model its wings as a rectangle with a width. determine the difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces brainly
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.
Difference in pressure between the top and bottom of the wingspanThe difference in pressure between the top and bottom of the wingspan is calculated as follows;
ΔP = P(top) - P(bottom)
Area of the wingspanA = bh
A = 2.7 m x 0.27 m
A = 0.729 m²
Weight of the Andean condorW = mg
W = 9 x 9.8
W = 88.2 N
Pressure at the top surface of condor's wingsThe pressure at the top surface of condor's wings is due to atmospheric pressure
P(top) = 14.7 Psi = 101,325 Pa
Pressure at the bottom surface of condor's wingsThe pressure at the bottom surface is due to weight of andean condor.
P = W/A
P(bottom) = 88.2/0.729
P(bottom) = 120.99 Pa
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;
ΔP = P(top) - P(bottom)
ΔP = 101,325 Pa - 120.99 Pa
ΔP = 101,204 Pa
The complete question is below;
An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.
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PLEASE HELP
Which statement about matter is true?
Matter is anything that is made of atoms and that has mass (and volume).
Matter is anything that is made of organic substances and is found on the earth.
Matter is an element.
Matter is a compound
Answer: Matter is anything that is made of atoms and that has mass (A)
Explanation: All everyday objects that can be touched are ultimately composed of atoms. Even you are made of atoms. Anything that you can touch has moving particles unless the object is at absolute zero, which is not possible.
Hope this helps!
3. The property of sound called intensity is proportional
to the rate at which energy flows through
A.an area perpendicular to the direction of
propagation.
B.an area parallel to the direction of propagation.
C.a cylindrical tube.
D.a sound wave of a certain frequency.
Answer:
A. an area perpendicular to the direction of propagation.
Explanation:
The property of sound called intensity is proportional
to the rate at which energy flows through an area perpendicular to the direction of propagation.
The diagram shows a box being pulled along a horizontal surface with a force of 200.0 N.
Calculate the work done on the box to pull it a distance of 5.0 m.
Answer:
The formula for work is
W= fd
work= force X distance
so, this is
200 X 5 =1,000
and the unit for work is Joules
so.. 1,000 joules
Explanation:
hope that helps!
A negative charge of -6.0x10-6 C exerts an
attractive force of 65 N on a second charge that is
0.050 m away. What is the magnitude of the second
charge?
The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart How to determine the second charge Charge 1 (q₁) = –6×10¯⁶ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 0.05 mForce (F) = 65 NCharge 2 (q₂) =?F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Divide both side by Kq₁
q₂ = Fr² / Kq₁
q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)
q₂ = +3.0×10¯⁶ C (since the force is attractive)
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The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?
Answer:
Explanation:
This depends on the height.
Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.
Calculate the solar angle for the day at 10am and 2pm individually for the location of 21.23 south latitude on the 18th march 1993 (Assume it is non leap year)
Based on the latitude and time of the place, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
What is the solar hour angle?The solar hour angle of a point on the earth’s surface is the angle through which the earth would turn to bring the meridian of the point directly under the sun.
The rotation of the earth on its axis is 15° per hour where before noon is negative and after noon is positive. For example, at 10:00 a.m. local apparent time the hour angle is −30°.
Therefore, based on the latitude and time, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
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in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?
The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
Given the following data:
Charge = [tex]-2.35 \times 10^{-6}[/tex] C.
Distance = 0.100 m.
Scientific data:
Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]
How to calculate the net force.In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
Read more on charges here: brainly.com/question/14372859
Answer:
6.2
Explanation:
acellus
SOMEONE PLS HELP THANK YOU
Does magnitude effect the strength of attraction more than distance?
Or
Does distance effect the strength of attraction more than magnitude?
Explanation:
Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects.
What is the average velocity if the initial velocity of an object is 10 and the a final velocity is 28
Answer:
19
Explanation:
Avg. Vel = (28 + 10)/2
= 19
BTW, don't forget your units!
if every Galaxy have black hole in center than is that mean there used to humongous star that collapsed that formed galaxy and supermassive black hole?
Answer:
Yes, It does mean that there was a Red Giant in the middle of the galaxy.
Explanation:
The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns
The girl in the picture is using an oar to push the water backwards. At the same time the canoe iS moving forward with
the same amount of force. Which of Newton's Laws would explain why for every action there is an opposite and equal
reaction?
Newton's First Law of Motion
Newton's Second Law of Motion
C) Newton's Third Law of Motion
Newton's Thired Law of Motion
A 2.8 F capacitor and a 3,440
Ω
resistor are connected to a battery of voltage 5 V as shown in the circuit. After
closing the switch, how long will it take for the capacitor voltage to be 45 % of
the battery voltage?
Express your answer in seconds (s)
The time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
Discharge of the capacitor voltage
The rate at which the capacitor voltage discharges is given by the following formula;
[tex]V = V_0(1 - e^{-t/RC})[/tex]
Where;
V₀ is the initial voltageV is the final voltaget is the time of dischargeR is resistanceC is capacitanceThe final voltage = 0.45 x 5 V = 2.25 V
[tex]2.25 = 5(1 - e^{-t/RC})\\\\(1 - e^{-t/RC}) = \frac{2.25}{5} \\\\(1 - e^{-t/RC}) = 0.45\\\\e^{-t/RC} = 1- 0.45\\\\e^{-t/RC} = 0.55\\\\\frac{-t}{RC} = ln(0.55)\\\\\frac{-t}{RC} = -0.597\\\\t = 0.597 (RC)\\\\t = 0.597(3440 \times 2.8)\\\\t = 5,750.3 \ s[/tex]
Thus, the time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
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Which of the following is true about how pressure varies with depth in a fluid? a. Pressure decreases with depth because it must support the fluid weight above it. b. Pressure increases with depth because it must support the fluid weight above it. c. Pressure decreases with depth because it is supported by the fluid weight below it. d. Pressure increases with depth because it is supported by the fluid weight below it.
Answer:
b) pressure increases with depth because of the weight of the fluid above
P = ρ g H density * gravity * fluid depth
(Note - force from the fluid below is an example of Newton's Third Law - for every action there is an equal and opposite reaction)
When a potential difference of 2 volt is applied across the ends of a wire of 5 metre length a current of 1 ampere flows through it,calculate :-
(i) the resistance per unit length of the wire
(ii) the resistance of 2 metre length of the wire
(iii) the resistance across the ends of the wire if it is doubled on itself
[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} ⟿}[/tex]
(i) 0.4 Ω m^-1
(ii) 0.8 Ω
(iii) 0.5 Ω
Explanation:
(i) Given, V = 2 volt, I = 1 AResistance of 5 m length of wire :-
[tex] = > R = \frac{V}{I} = \frac{2}{1} = 2 \: Ω [/tex]
Resistance per unit length of the wire :-
[tex] = > \frac{R}{l} = \frac{2}{5} = 0.4 \: Ω \: {m}^{ - 1} [/tex]
(ii) Resistance of 2m length of the wire~
[tex] = \: 0.4 \: Ω \: {m}^{ - 1} \times 2 \: m = 0.8 \: Ω [/tex]
(iii) When the wire is doubled on itself, its area of cross section becomes twice and the length becomes half. Let a be the initial cross section and ρ be the specific resistance of the material of wire. Then,
[tex]from \ relation \: \: ➪ \: R = ρ \times \frac{1}{a}. \\ \\ we \: have, \\ \\ initial \: resistance \:➪ \: 2 = ρ\times \frac{5}{a}....eqn(i) \\ \\ new \: resistance \: ➪ \: R` = ρ\times \frac{2.5}{2a}....eqn(ii) \\ \\ on \: dividing \: eqn(ii) \: by \: eqn(i)... \\ \\ \frac{R`}{2} = \frac{2.5ρ}{2a} \div \frac{5ρ}{a} = \frac{1}{4} \\ \\ R` = \frac{2}{4} = 0.5 \: Ω[/tex]
Thus, on doubling the wire on itself, its resistance becomes one-fourth.
Hope it helps you!!What is the rate of acceleration if the object has a force of 857 N and a mass of 8000 kg
A 8.2 kg solid sphere, made of metal whose density is 2300 kg/m3, is suspended by a cord. When the sphere is immersed in a liquid of unknown density, the tension in the cord is 23 N. The density of the liquid is
The density of the liquid is 1470.43 kg/m³. Density is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
What is density?Density is defined as the mass per unit volume. The mass and density relation is given as;
mass = density × volume
The given data in the problem is as ;
m is the mass of a solid sphere=8.2 kg
[tex]\rm \rho_s[/tex] is the density of the metal= 2300 kg/m³
T is the tension in the cord = 23 N.
The volume of the liquid is found as;
[tex]\rm V_{sphere} = \frac{m}{\rho} \\\\ \rm V_{sphere} =\frac{8.2}{2300} \\\\ \rm V_{sphere} = 0.00356 \ m^3[/tex]
The volume of the sphere is equal to the volume displaced;
Volume displaced = 0.00356 m³
The buoyant force is found as;
[tex]\rm F_B = \rho g V \\\\[/tex]
From the given condition it is observed that the weight of the sphere is equal to the sum of buoyancy force and the tension in the cord.
[tex]\rm mg = \rho g V+T \\\\ 8.2 \times 9.81 = \rho \times 9.81 \times 0.00356+23 \\\\\ 80.442=\rho \times 0.0349 +23 \\\\ \rho = 1645.90 \ kg/m^3[/tex]
Hence the density of the liquid is 1645.90 kg/m³.
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please solve the given question
I know the answer but I need explanation also
PLEASE help
R² = F1² + F2² + 2 F1.F2 cos α ⇒cosinus
F1 and F2 perpendicular, α = 90°, cos 90° = 0
[tex]\tt R=\sqrt{3^3+4^2}=5[/tex]
the base is a polygon and its faces are triangles (cone, cube, cylinder, pyramid, rectangular prism
A 3.0-kg block moves up a 40° incline with constant speed under the action of a 26-N force acting up and parallel to the incline. What magnitude force must act up and parallel to the incline for the block to move down the incline at constant velocity?
Explanation:
Sooooo, first,
Constant Speed means that the body isn't accelerating.
a= 0
Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.
The force that pulls the body downwards is given by,
F = mgsin40°
F= 18.898N
P -(F+Fr) = ma, but, a= 0
P = F + Fr
Fr = 26-18.898
= 7.102N
If the block must move down the incline, Q and Fr will act in the same direction.
Q + Fr = F
Q = 11.796N
Question 4 (1 point) ✓ Saved
The term 'recruitment' refers to the process by which people decide on the kinds of
environments they will join.
True
False
A car starts moving from rest; If it gains avelocity of 72km/ht after to seconds what is the acceleration of the car.
Answer:
10 m/s²
Explanation:
Given
u = 0 (initial velocity as it is at rest)v = 72 km/h x 5/18 = 20 m/st = 2sSolving
v = u + at20 = 0 + 2a2a = 20a = 10 m/s²The correct answer is 10 m/s² .
4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
Question
4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
Hold on, our servers are swamped. Wait for your answer to fully load.
Answer:
Explanation:4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
T F
Organisms get energy from food
Answer:
It's true that organisms get energy from food.
Answer:
Explanation:
Organisms ingest large molecules, like carbohydrates, proteins, and fats, and convert them into smaller molecules like carbon dioxide and water. This process is called cellular respiration, a form of catabolism, and makes energy available for the cell to use
Oxygen is needed by all cells of most organisms for the release of
energy from what in photosynthesis?
Answer:
From the SUN
Explanation:
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Which definition refers to electrical power?
A. The rate at which an electric charge flows past a point in a circuit
B. The energy of an electric charge minus the resistance in a circuit
C. The energy of an electric charge due to its position in an electric
field
D. The rate at which electrical energy is transferred in a circuit
An 80.0 kg merry-go-round of radius 1.20 m is accelerating horizontally from rest by a constant force of 70.0 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 5.00 s. (Assume it is a solid cylinder.)
The kinetic energy of the merry-go-round after 5.00 s, when a constant force is applied tangentially to it, is determined as 3,069.5 J.
Conservation of angular momentumThe kinetic energy of the merry-go-round is determined by applying the principle of conservation of angular momentum as follows;
Iα = rF
where;
I is moment of inertia of the merry-go-round (solid cylinder)I = ¹/₂mr²
I = ¹/₂ x 80 x (1.2)²
I = 57.6 kgm²
α = (rF)/I
α = ( 1.2 x 70) / (57.6)
α = 1.46 rad/s²
Tangential acceleration of the merry-go-rounda = αR
a = 1.46 x 1.2
a = 1.752 m/s²
Velocity of the merry-go-roundThe velocity of the merry-go-round after 5 s is calculated as follows;
v = u + at
v = 0 + (1.752x 5)
v = 8.76 m/s
Kinetic energy of the merry-go-roundK.E = ¹/₂mv²
K.E = ¹/₂ x 80 x 8.76²
K.E = 3,069.5 J
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how do i turtle answer fast
Answer:
Take your TIme maaaaaan
Explanation:
Chillax
Here's a question for you Care to go bowling?
Answer:
By taking it Slow.
Don't go too fast
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
Answer:
Explanation:
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B