A cubical surface surrounds a point charge q . Describe what happens to the total flux through the surface if (e) the charge is moved outside the surface.

The electric field at a distance of 7.00 cm is 8.60×10^−2C/m2

The charge per unit area of wall is

σ = (8.60×10^−6C/cm2)( 100cm /m)^2 = 8.60×10^−2C/m2

The electric field at a distance of 2.00 cm is then

E =  σ /7∈0  = (8.60×10^−2C/m^2) / 7(8.85×10−12C2/N⋅m2)

= 1.38×10^9N/C away from the wall.

Electric field, an electric property associated with each point in space when the charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.

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When thermal energy is removed from particles, then the particles' kinetic energy decreases (Option D).

The expression particles' kinetic energy makes reference to the amount of motion energy (i.e. energy in movement) that contain the particles of an object, which depends on the temperature of the material.

In conclusion, when thermal energy is removed from particles, then the particles' kinetic energy decreases (Option D).

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mass of one sheet of paper is 0.00504 kg or 5.04g.

First we will find the surface area of a single sheet of paper

surface area = length ×width

surface area =0.3×0.21

surface area =0.063m²

now 0.063m² is the surface area of a single sheet of paper .

so now we will find number of papers required to form 1m² of area

which will be given by dividing 1m² by surface area of a single sheet

i.e.

number of sheets required = 1/0.063m²

number of sheets required =15.87

mass of one sheet = mass of 1 m^2 of paper / number of times narrower

mass of one sheet = 0.080 kg / 15.873

mass of one sheet = 0.00504 kg

mass of one sheet of paper is 0.00504 kg or 5.04g.

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Explanation:

Endothermic reaction as heat from the environment is absorbed.

the transformation from solid to liquid is due to the latent heat of fusion/ enthalpy of fusion.

the heat energy absorbed from the environment is used to break the bonds of the solid structure therein converting it to a liquid. this is the reason why the temperature of the substance is constant at the state changes.

The force on the wire will be

F = 2.88 Newton

We have a current carrying wire in a uniform magnetic field.

We have to determine the magnitude of the magnetic force on this section of wire.

The force on the current carrying wire will be -

F = IBL sinθ

According to the question, we have -

Length (L) = 0.75 m (along +x - axis)

Current (I) = 2.4 A (along + x - axis)

Magnetic Field (B) = 0.39 k T (along +z axis)

Therefore, the angle between Magnetic field and Length = θ = 90°.

Therefore -

F = IBL sin(90)

F = 2.4 x 1.6 x 0.75 x sin(90)

F = 2.88 x sin(90)

F = 2.88 Newton

Hence, the force on the wire will be

F = 2.88 Newton

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The emf induced in the coil as a function of time is 2.2 mV.

The emf induced in the coil is calculated as follows;

emf = NAdB/dt

where;

A is area of the coil, A = πr² = π(2.7 x 10⁻³)² = 2.29 x 10⁻⁵ m².

dB/dt = 3.2cos(1046π) = 3.2

emf = (30 x 2.29 x 10⁻⁵ x 3.2) = 2.2 x 10⁻³ V

emf = 2.2 mV

Thus, the emf induced in the coil as a function of time is 2.2 mV.

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The average energy density of the solar component of electromagnetic radiation at this location is determined as 2.58 x 10⁻⁶ J.

The average energy density of the solar component of electromagnetic radiation at this location is calculated as follows;

U(avg) = (Brms)²/μ₀

U(avg) = (1.8 x 10⁻⁶)² / (4π x 10⁻⁷)

U(avg) = 2.58 x 10⁻⁶ J

Thus, the average energy density of the solar component of electromagnetic radiation at this location is determined as 2.58 x 10⁻⁶ J.

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The average normal strain in wires A, C and D is found to be 0.035, 0.035 and 0.059 respectively when there is a change in the angle by 2° clockwise.

A physical measurement called strain illustrates how much an object's dimensions vary while it is under stress. The ratio between the object's changed length and its initial length is known as the linear strain.

All wires are stretched when the stiff lever rotates 2° in a clockwise direction around pin B.

Elongation would be R x angle in radian

Elongation in the wire A = 200 mm x 3.142 x 2/180 = 6.982 mm

Elongation in the wire C = 300 x 3.142 x 2/180 = 10.473 mm

Elongation in the wire D = 500 x 3.142 x 2/180 = 17.455 mm

Therefore,

Average normal strain in the wire A = 6.982/200 = 0.03491

Average normal strain in the wire C = 10.473/300 = 0.03491

Average normal strain in the wire D = 17.455/300 = 0.05818

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The electric flux through the surface is 5.65×〖10〗^2 Nm^2/C ≈5.6×〖10〗^2  Nm^2/C

The electric flux through a surface describes the number of electric field lines that cross that surface. It is expressed as the surface integral of the electric field through that surface.

Gauss's law states that for a closed surface, the electric flux through that surface depends only on the total charge present inside that surface. Hence, for a closed surface, the electric flux can be computed without evaluating any integrals.

The charges are: q1=3.0nC, q2=−2.0nC, q3=−7.0nC, and q4=1.0nC

Gauss's Law provides that the net electric flux through a closed surface depends only on the net charge enclosed by the surface, by the equation:

ϕ=Qnet÷ϵ0

where,

Φ is the net electric flux through the closed surface.

Qnet is the net charge enclosed by the surface.

∈_0=8.85×〖10〗^(-12) C^2/Nm^2 is the permittivity of free space.

The net charge inside the box is:

Qnet = q1+q2+q3+q4

=3.0nC−2.0nC−7.0nC+1.0nC

= −5.0nC=−5.0×10−9C

The net electric flux through the box is:

Φ=Q_net/∈_0

Φ=(-5.0×〖10〗^(-9) C)/(8.85×〖10〗^(-12) C^2/Nm^2 )

Φ=5.65×〖10〗^2 Nm^2/C ≈5.6×〖10〗^2  Nm^2/C

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The car's acceleration would be for a mass of 4 kg is 3 m/s²

Given the information below:

12 Newtons of force.

Increasing speed Equals

By using Newton's Second Law of Motion, we can determine the mass of the car:

According to Newton's second law of motion, force is equal to the rate at which momentum changes. Force is defined as mass times acceleration for a constant mass.

force= mass* acceleration

This formula provides Newton's Second Law of Motion mathematically;

12= mass*3

mass=12/ 3

mass=4 kilogram

By changing the parameters in the formula, we obtain;

= 4 kilos of mass.

As a result, the vehicle with a mass of 4 kg would accelerate at 3 m/s².

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Answer:

net force= -50N +70N

=20N

Explanation:

The balls are moving in opposite directions as indicated and to the right is (-) while to left is (+). Therefore net force is equal to sum of the force

The cue ball travels to the left with a force of +70 N and collides with the four-ball moving towards the right with a force of -50 N.

A push or a pull that alters or tends to alter an object's uniform motion or state of rest, as well as altering an object's direction or shape, is referred to as force. It either accelerates items or increases the pressure they are under. The interaction between two items is, to put it simply, a push or a pull on the object. It is the fundamental driver of motion starting from stillness.

Given information according to the question,

The cue ball travels to the left with a force of +70 N and,

The force by four balls moving to the right is -50 N.

Net force, N = 70 N - 50 N

N = 20 N towards the left direction.

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Considering the definition of velocity, the magnitude of the helicopter's displacement is 700 meters.

Velocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction.

In other words, the velocity can be defined as the amount of space traveled per unit of time with which a body moves, considering the direction.

The velocity can be calculated using the expression:

velocity= displacement÷ time

In this case, you know:

Replacing in the definition of velocity:

70 m/s= displacement÷ 10 s

Solving:

70 m/s× 10 s= displacement

700 m= displacement

Finally, the magnitude of the helicopter's displacement is 700 meters.

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Answer:

he would tap on the "close tab "button and see old the apps he has used in that period

Explanation:

Dropped from a bridge and allowed to fall freely to the ground is an object. Modeling the object's height over time using h(t) = 144 - 16t2 is possible

An item that is falling only due to gravity is said to be in free fall. This means that any moving object that is simply being affected by gravity is said to be "in a condition of free fall." An item of this kind will accelerate downhill at a rate of 9.8 m/s/s. If an item is just moving in one direction—downward or upward toward its peak—and is only affected by gravity, then its acceleration value is 9.8 m/s/s.

The initial velocity of an object being dropped from a height is zero meters per second (m/s) as opposed to being hurled.

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The distance of a car that accelerates at 4 m/s² until it reaches 36 m/s is 162m.

The distance moved by a body can be calculated using the following formula:

S = ut + ½at²

Where;

However, the time taken must be calculated first as follows:

t = 36m/s ÷ 4m/s²

t = 9s

S = 0 × t + ½ × 4 × 9²

S = 0 + ½ × 81 × 2

S = 162m

Therefore, the distance of a car that accelerates at 4 m/s² until it reaches 36 m/s is 162m.

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Answer:

3.42 + 4 + 5.2 + 12= 24.62
So since we have 24.62 it will be 4 sig figs

Explanation:

The intensity delivered to the eardrum is [tex]3.0 \times {10^{ - 8}}\,W/{m^2}$[/tex].

The area is measured on a plane perpendicular to the direction of the energy's transmission, and the power transferred per unit area is known in physics as the intensity or flux of radiant radiation. The SI system's fundamental units are watts per square meter. The average power transmission across the course of a wave, such as sound waves or electromagnetic waves like light or radio waves, is referred to as the "intensity" of the wave. The term "intensity" can be used to characterize a wide range of energy exchange scenarios. For example, one may calculate the amount of kinetic energy that each drop of water from a sprinkler is carrying. It is possible to determine intensity using the energy density.

Calculations:

[tex]${\beta _1} = 10{\log _{10}}\left( {\dfrac{{{I_1}}}{{{I_0}}}} \right)$ and ${\beta _2} = 10{\log _{10}}\left( {\dfrac{{{I_2}}}{{{I_0}}}} \right)$$ = {\beta _2} - {\beta _1} = 10{\log _{10}}\left( {\dfrac{{{I_2}}}{{{I_0}}}} \right) - 10{\log _{10}}\left( {\dfrac{{{I_1}}}{{{I_0}}}} \right)$[/tex][tex]$ \ {\beta _2} - {\beta _1} = 10{\log _{10}}\left( {\dfrac{{{I_2}}}{{{I_0}}} \times \dfrac{{{I_0}}}{{{I_1}}}} \right)$ [Using $\log a - \log b = \log \left( {\dfrac{a}{b}} \right)$][/tex]

[tex]$ \arrow = {\beta _2} - {\beta _1} = 10{\log _{10}}\left( {\dfrac{{{I_2}}}{{{I_1}}}} \right)$\[ \arrow = \dfrac{{{\beta _2} - {\beta _1}}}{{10}} = {\log _{10}}\left( {\dfrac{{{I_2}}}{{{I_1}}}} \right)\][/tex]

[tex]\[ \arrow ={10^{\dfrac{{{\beta _2} - {\beta _1}}}{{10}}}} = \dfrac{{{I_2}}}{{{I_1}}}\]\[ \arrow ={I_2} = {I_1}{10^{\dfrac{{{\beta _2} - {\beta _1}}}{{10}}}}\]Thus, we have ${I_2} = 3.0 \times {10^{ - 11}}\,W/{m^2} \times {10^{\dfrac{{30.0}}{{10}}}}$$ \arrow= {I_2} = 3.0 \times {10^{ - 11}} \times {10^3}\,W/{m^2}$$ \arrow ={I_2} = 3.0 \times {10^{ - 8}}\,W/{m^2}$[/tex]

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The acceleration of the robot is 1.43 m/s2 in magnitude.

The acceleration of an object is defined as the variation of the velocity with respect to time. The acceleration is calculated by finding the ratio of the change in velocity to the change in time.

The acceleration is also calculated by using the force formula. The force is actually defined as the acceleration produced in the body by applying the force on an object of mass m.

On a non-stick surface, a toy robot and doll are standing side by side. The robot weighs 0. 30 kg, while the doll weighs 0. 20 kg. With a force of 0. 30 n, the robot pushes against the doll.

According to Newton's second law.

F = mass x acceleration

Given that

Force applied = 1N

Acceleration = Force/mass

Substitute the values and get acceleration.

Acceleration = 1/0.7

Acceleration = 1.43m/s²

Hence, the acceleration of the robot is 1.43 m/s2 in magnitude.

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Speed of light in terms of astronomical unit is 0.12AU/min.

The astronomical unit (symbol: au, or AU) is a measurement of length that is approximately 150 million kilometers (93 million miles) or 8.3 light minutes long, representing the distance between the Earth and the Sun. As Earth orbits the Sun, its actual distance from the Sun changes by roughly 3%, going from its greatest value (aphelion) to its smallest value (perihelion), and back again, once a year. Originally intended to represent the average of Earth's aphelion and perihelion, the astronomical unit has been precisely defined as 149597870700 m since 2012. The astronomical unit is mostly used to calculate distances within or around other stars and other solar systems. It is also a crucial element in the definition of the parsec, another astronomical measure of length.

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Given:

[tex]speed,\;v=449\;m/s[/tex]

We know that,

[tex]adiabatic index, \gamma = 1.667[/tex]

[tex]gas constant,\;R=8.314\;J[/tex]

The form speed of the sound in a monoatomic gas is,

[tex]v=\sqrt{\frac{\gamma\;R\;T}{M} }[/tex]

Substitute the known values in the above equation,

[tex]449=\sqrt{x} \frac{1.667 \times 8.314 \times 293}{M}[/tex]

[tex]M=\sqrt{x} \frac{1.667 \times 8.314 \times 293}{449}[/tex]

[tex]M=0.02014 \times (\frac{1000}{1})[/tex]

[tex]M=20.14\;g/mol[/tex]

Therefore, monoatomic gas is Neon gas (Ne)

Monatomic gas, which differs from diatomic, triatomic, or generally polyatomic gases in that it contains particles (molecules) made up of just one atom, includes gases like helium or sodium vapor. Because a monatomic gas lacks the rotational and vibrational energy components that characterize polyatomic gases, its thermodynamic behavior in the normal temperature range is incredibly straightforward. As a result, its heat capacity is independent of temperature and molecular weight (in this case, atomic weight), and its entropy (a measure of disorder) only depends on temperature and molecular weight.

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The speed of light u is equal to c.

Given,

The motion of a transparent medium influences the speed of light.

The water moves with speed v in a horizontal pipe.

Assume the light travels in the same direction as the water moves.

The speed of light with respect to the water is c /n.

The index of refraction of water, n = 1.33

Let us assume u' be the speed of light in water.

u' is related to the refractive index of water,as u' = c/n

where, c is the speed of light.

Let, u be the speed of light in water in the lab frame.

Now, u and u' are related as : u = ( u'+v) /(1+u'v/c^2)

Here, v is the speed of water in the horizontal pipe.

We know the value of u'. so by substituting the value, we will get ,

u = (c/n+v) /(1+cv/nc^2)

u = c/n (1+nv/c) /(1+v/nc)

u in the limit as the speed of the water approaches c.

Thus,

u = lim v-->c [c/n (1+nv/c) /(1+v/nc) ]

u= c/n (1+n) /(1+1/n)

u= c .

Hence, the speed of light u is equal to c.

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Disclaimer: incomplete question. here is the complete question.

Question:The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n = 1.33 is the index of refraction of water.

(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc).

(d) Evaluate u in the limit as the speed of the water approaches c .

While current is the same in series and parallel, voltage is not. Therefore, because these three resistors are connected in parallel, their voltage is the same, or 12 volts. Using the equation V=IR, 12V=I*10Ω gives you a current of 1.2A.

A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistors have a variety of purposes in electronic circuits, reducing current flow, modifying signal levels, dividing voltages, biassing active components, and terminating transmission lines are a few examples. High-power resistors that can generate many watts of heat instead of electrical energy can be utilised as test loads for generators, power distribution systems, and motor controls. Fixed resistors' resistances only sporadically vary as a result of changes in operating voltage, time, or temperature. Variable resistors can be utilised as force sensors, heat sensors, light sensors, volume controls, lamp dimmers, humidity sensors, and chemical activity sensors.

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By the charge density, The charge throughout te plastic is 0.059 nC.

We need to know about charge density to solve this problem. The charge density can be determined as

λ = Q / V

where λ is charge density, Q is charge and V is volume.

The parameter given is the charge density and the solid cylinder shape which are :

λ = 500nC/m³

r = 2.5 cm = 0.025 m

L = 6.0 cm = 0.06 m

Find the volume of solid cylinder

V = π .  r² . L

V = π .  0.025² . 0.06

V = 1.18 x 10¯⁴ m³

Find the charges

Q = λ x V

Q = 500 x  1.18 x 10¯⁴

Q = 0.059 nC

Hence, the charge throughout the plastic is 0.059 nC.

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Answer:

the energy of photon will be half.

Explanation:

If you need a deeper explanation please let me know. Hope I helped!

The distance should be 4m from the wire in order to get the magnetic field of 0.100μ .

It is given that magnetic field 40.0 cm away from a straight wire is  1.00μT having  current 2.00 A .

From equation (1)  magnetic field 40.0 cm = 0.4m away from a straight wire is 1.00μT which is given by    [tex]1.00=\frac{u_0I}{2\pi \times0.4}[/tex]      .....(2)

From equation (1)  magnetic field 'r' m away from a straight wire is 0.100μT which is given by    [tex]0.100=\frac{u_0I}{2\pi \times r}[/tex]       ...(3)

On dividing equation (2) by (3) , we get

             [tex]\frac{1}{0.1} =\frac{r}{0.4} \\\\r=4m[/tex]

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Answer:

Im not sure if this is correct but it might be 15.3

Explanation:

8.5kg multiplied by 1.8 m/s is 15.3

Answer:

KE = 13.77 J

Explanation:

KE=1/2 mv^2

For a constant volume, the pressure of a gas is directly proportional to the temperature in Kelvin is the conclusion which can be made from Gay-Lussac’s law and is denoted as option D.

This is referred to as the perpendicular force applied on a body per unit area and the unit is Pascal.

Gay-Lussac was a scientist who discovered through numerous experiments and observations that at a constant volume, the pressure of a gas is directly proportional to the temperature in Kelvin.

This is denoted as the following equation below:

P ∝ T

P = kT where p is pressure, k is constant and t is temperature.

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The options are:

Explanation:

E = hc / wavelength

Given that:

h = 6.626 × 10-34 Js

c = 2.998 x 10^8 m/s

wavelength = 263 x 10^-9 m

A boat travels 12. 0 m while reduces its velocity from 9. 5 m/s to 5. 5 m/s, while it travels the 12. 0 m, the acceleration of the boat is -2.5 m/s²

The rate at which an object's velocity with respect to the time changes is referred to as acceleration. It is a vector quantity to accelerate (in that they have magnitude and direction). The direction of the net force acting on an object determines the direction of its acceleration. According to Newton's Second Law, the amount of an object's acceleration is the combined result of two causes:

The given parameters;

distance traveled by boat, d = 12 m

initial velocity of boat, u = 9.5 m/s

final velocity of boat, v = 5.5 m/s

The acceleration of boat is calculated as;

[tex]v^{2}=u^{2}+2as\\ a=\frac{v^{2}-u^{2} }{2s}\\ a=\frac{5.5^{2}-9.5^{2} }{2*12}[/tex]

a=-2.5m/[tex]s^{2}[/tex]

Thus, the deceleration of boat is 2.5 m/s².

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