a) Factorise x²-2x-3

If both confidence intervals were correctly calculated (6. 53, 7. 95) is the 90 percent level. Therefore, the correct option is A.

To determine which confidence interval corresponds to the 90 percent level and the 98 percent level, we can look at the width of the intervals. The interval with the larger width is the one with a higher confidence level because it accounts for more possible variation in the data.

The first interval (6.53, 7.95) has a width of 7.95 - 6.53 = 1.42.

The second interval (6.20, 8.28) has a width of 8.28 - 6.20 = 2.08.

Since the second interval has a larger width, it corresponds to the higher confidence level of 98 percent. Therefore, the first interval corresponds to the 90 percent confidence level. The correct answer is option A. (6.53, 7.95) is the 90 percent level.

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The equivalent expressions are p−3q=11 and 3p+q=3. Option A

It is important to note that equivalent equations are defined as equations that have the same solution but are different in the way with which the values are arranged.

From the information given, we have that;

3 times (p minus q) = 2 times p + 11

This equation is represented as;

3(p - q) = 2(p) + 11)

expand the bracket, we get;

3p - 3q = 2p + 11

collect the like terms

3p - 2p - 3q =11

Subtract the values

p - 3q = 11

Then,

4 times p + q = p + 3

4p + q = p + 3

collect like terms

4p - p + q = 3

3p = q = 3

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The P-value is less than the significance level of 0.01, we reject the null hypothesis.

Null Hypothesis: The proportion of adults who prefer window seats when they fly is 0.5 or less.

Alternative Hypothesis: The proportion of adults who prefer window seats when they fly is greater than 0.5.

Let p be the true proportion of adults who prefer window seats when they fly.

The sample proportion of adults who prefer window seats is:

= 520/813 = 0.639

The standard error of the sample proportion is:

SE = sqrt((1-)/n) = sqrt(0.639(1-0.639)/813) = 0.022

The test statistic is:

z = ( - 0.5)/SE = (0.639 - 0.5)/0.022 = 6.32

Using a normal distribution, the P-value is P(Z > 6.32) < 0.0001.

Since the P-value is less than the significance level of 0.01, we reject the null hypothesis.

Therefore, we conclude that there is sufficient evidence to support the claim that the majority of adults prefer window seats when they fly.

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The surface area of the rectangular prism with the given dimensions is 540yd².

To find the surface area (sa) of the rectangular prism with the given dimensions, we need to calculate the area of each face and add them together.

The formula for the area of a rectangle is length multiplied by width (A = l x w).

Face 1 has a length of 5yd and a width of 37yd, so its area is 5 x 37 = 185yd².
Face 2 has a length of 5yd and a width of 20yd, so its area is 5 x 20 = 100yd².
Face 3 has a length of 5yd and a width of 51yd, so its area is 5 x 51 = 255yd².

To find the total surface area, we add the areas of all three faces:

sa = area of face 1 + area of face 2 + area of face 3
sa = 185yd² + 100yd² + 255yd²
sa = 540yd²

Therefore, the numerical value of the surface area of the rectangular prism with the given dimensions is 540yd².

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The slope of the line that represents the proportional relationship between x and y in the given table is 1/6. To graph the line, we can plot the points from the table and connect them with a straight line passing through the origin (0,0).

The relationship between x and y is proportional, which means that there is a constant ratio between the two variables. We can find the slope of the line that represents this relationship by calculating the ratio of the change in y over the change in x between any two points on the line. Let's use the first and last points

slope = (y2 - y1) / (x2 - x1) = (2.0 - 0) / (12 - 0) = 2/12 = 1/6

So, the slope of the line that represents this proportional relationship is 1/6.

To graph the line, we can plot the points from the table and connect them with a straight line. The line will pass through the origin (0,0) and have a slope of 1/6. The graph will look like.

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Answer: 2

sqrt 41

Step-by-step explanation:

distance formula is just d=√((x2 – x1)² + (y2 – y1)²)

√(-2+8)^2+(-5-3)^2

√(-10)^2+(-8)^2

√100+64

2√41

In the given diagram, using the intersecting secant theorem, the length of c is 2 cm

From the question, we are to determine the length of segment c

From the intersecting secant theorem, we have that

If two secant segments intersect outside a circle, then the product of the secant segment with its external portion equals the product of the other secant segment with its external portion

Thus,

In the given circle, we can write that

a × b =  c × d

Substitute the values

3 × 12 = c × 18

36 = c × 18

Divide both sides by 18

36 / 18 = (c × 18) / 18

2 = c

Therefore,

c = 2

Hence, the length of c is 2 cm

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For the first question, to get the limit of the function lim (In V 4x2 + 6 - In x), we can use the property of logarithms that says ln(a) - ln(b) = ln(a/b). Applying this property to the given function, we get ln[(4x^2 + 6)/x]. Now we can simplify the expression by dividing both the numerator and the denominator by x. So we get ln(4x + 6/x), which can be rewritten as ln(4 + 6/x). Now we can take the limit as x approaches infinity. As x gets larger and larger, the 6/x term becomes smaller and smaller and approaches zero. So ln(4 + 6/x) approaches ln(4), and the final answer is A. In 2.

For the second question, to get the horizontal asymptote(s) of the function f(x) = 37€*, we can take the limit as x approaches infinity. As x gets larger and larger, the exponential term €* becomes larger and larger, approaching infinity. So the function approaches 37 times infinity, which is infinity. Therefore, there is no horizontal asymptote and the answer is D. none.
For the third question, the statement is false. The limit as x approaches infinity of 2^(ln(a)/ln(x)) is equal to infinity if a > 1 and is equal to zero if 0 < a < 1.

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The solution to the system of linear equations is (x, y) = (13, -4).

To solve the system of linear equations using Gaussian elimination, we need to eliminate one variable from one of the equations. Here, we can eliminate x from the second equation by subtracting twice the first equation from the second equation:

x + 2y = 5    (equation 1)

2x + 3y = 6    (equation 2)

--------------

  -2x - 4y = -10   (2 * equation 1)

        y = -4

Now, we can substitute the value of y into the first equation to solve for x:

x + 2(-4) = 5

x - 8 = 5

x = 13

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The fraction is equivalent to a whole number  are 9/3, -16/8, 7/0, 0/5

A fraction can simply be described as the part of a whole variable, a whole numbers, or a whole element.

In mathematics, there are different types of fractions. These fractions are listed thus;

From the information given, we have that;

Equivalent expressions or fractions are fractions with the same solutions

Then, we have;

9/3

Divide the values

3

-16/8

-2

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The total budget of the prom, using the percentage concept, is given by = $ 4000.

Hence the correct option is (D).

Let the total budget be $ 100x.

Spending on Entertainment is 25% of the Budget.

So the spending on Entertainment = 100x*(25/100) = $ 25x.

Spending on Refreshments is 30% of the Budget.

So the spending on Refreshments = 100x*(30/100) = $ 30x.

Spending on Decorations is 45% of the Budget.

So the spending on Decorations = 100x*(45/100) = $ 45x.

It is also given that the spending on refreshments in dollar is $ 1200.

According to information,

30x = 1200

x = 1200/30

x = 40

Hence the total budget is = $100x = $ 100*40 = $ 4000.

So the correct option is (D).

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The question is incomplete. The complete question will be -

"The student council is planning for the prom. They have broken down their expenses in the graph below. If they decide they will spend $1,200 on refreshments, then what is their total budget?

Prom Budget:

Entertainment: 25%

Refreshments: 30%

Decorations: 45%

Answer choices:

A. $3,600

B. $6,000

C. $7,200

D. $4,000"

Distribute

50+30(2x+10)

50+30×2x+30×10

50+60×+300

add the number

50+300+60×

350+60x

60x+350

common factors

10(6x+35)

The solution to this system of equations are x = -5 and y = 8.

In order to determine the solution to a system of two linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.

Given the following system of linear equations:

x + y = 3                .........equation 1.

x - 3y = -29                .........equation 2.

By subtracting equation 2 from equation 1, we have:

(x - x) + (y - (-3y) = 3 - (-29)

y + 3y = 3 + 29

4y = 32

y = 32/4 = 8

x = 3 - y

x = 3 - 8

x = -5

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The group of friends can consist of at most 9 people, given the budget constraint and pricing can go to the amusement park.

The inequality to determine the number of people who can go to the amusement park can be written as: 38.75p + 16.25 ≤ 365.

Where p represents the number of people and the left-hand side of the inequality represents the total cost of admission and parking for p people.

The inequality is set up such that the total cost cannot exceed the given budget of $365.

To solve this inequality, we can first subtract 16.25 from both sides: 38.75p ≤ 348.75. Then, divide both sides by 38.75: p ≤ 9

To determine the maximum number of people who can go to the amusement park with a given budget,

we can write and solve an inequality based on the cost of parking and admission per person.

In this case, the inequality is 38.75p + 16.25 ≤ 365, and the solution is p ≤ 9.

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Answer:

H

Step-by-step explanation:

You take each given side and multiply them all together

18.4 x 8.8 x 11 = approx 1782

Answer:

Step-by-step explanation:

A fair coin means that there is a 50% probability of heads and a 50% probability of tails.

Playing the game 300 times means that Mason will approach theoretical probability.

Therefore, playing 300 times, he should expect to win 50% of the time, so 50% x 300 = 150 times.

Mason should expect to win 150 times.

The surface area  of the given volume of the rectangular prism is equal to 13.86 square centimeters.

Volume of the rectangular prism is 6 cubic centimeters.

Let the dimensions of the rectangular prism be length (l), width (w), and height (h).

Volume of the rectangular prism = l x w x h

⇒ l x w x h = 6

Use the given volume to find one of the dimensions .

Then use that information to find the surface area.

To calculate the surface area at least two of the dimensions known.

Let us assume that the height (h) is 1 centimeter.

⇒l x w x 1 = 6

⇒ l x w = 6

Use this equation to solve for one of the dimensions.

⇒ l = 6/w

Substituting this value of l into the surface area formula, we get,

Surface area = 2lw + 2wh + 2lh

⇒Surface area = 2(6/w)w + 2w(1) + 2(6/w)(1)

⇒Surface area = 12/w + 2w + 12/w

⇒Surface area = 2w + 24/w

Value of w that gives the minimum surface area,

Take the derivative of the surface area formula with respect to w and set it equal to 0,

d/dw (2w + 24/w) = 0

⇒ 2 - 24/w^2 = 0

Solving for w, we get,

⇒w = √(12)

Substituting this value of w back into the surface area formula, we get,

⇒ Surface area = 2(√(12)) + 24/√(12)

⇒Surface area = 4√3 + 4√3

⇒Surface area = 8√3

⇒ Surface area = 13.86 square centimeters

Therefore, the surface area of the rectangular prism is approximately 13.86 square centimeters.

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When the diameter of the balloon is 50 cm, the radius of the balloon is increasing at a rate of approximately 0.0254 cm/s

We are given that the volume of a spherical balloon is increasing at a rate of 100 cm³/s. We need to find how fast the radius of the balloon is increasing when the diameter is 50 cm.

Let's first find the expression for the volume of the balloon in terms of its radius.

V = 4/3 πr³

Differentiating with respect to time (t), we get:

dV/dt = 4πr² (dr/dt)

We are given that dV/dt = 100 cm³/s. When the diameter of the balloon is 50 cm, the radius is 25 cm.

Substituting these values, we get:

100 = 4π(25)² (dr/dt)

Simplifying, we get:

dr/dt = 100 / (4π(25)²)

dr/dt ≈ 0.0254 cm/s

Therefore, when the diameter of the balloon is 50 cm, the radius of the balloon is increasing at a rate of approximately 0.0254 cm/s

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When approximating mixed fraction 5 6/13 to the nearest whole number, the rounded value is 5.

To round the mixed fraction 5 6/13 to the nearest whole number, we examine the fractional part, which is 6/13. The general rule for rounding mixed fractions is to consider the fractional part and round up if it is greater than or equal to 1/2, and round down if it is less than 1/2.

In this case, 6/13 is approximately 0.4615. Since it is less than 1/2, we need to round down to the nearest whole number. Therefore, when rounding 5 6/13 to the nearest whole number, the answer is 5.

A mixed fraction consists of a whole number part and a fractional part. When rounding a mixed fraction, we focus on the fractional part to determine the appropriate rounding direction. If the fractional part is exactly 1/2, it is typically rounded up to the next whole number.

However, in the case of 5 6/13, the fractional part is less than 1/2, so we round down. Rounding down gives us a more accurate approximation that is closer to the original value. In this instance, rounding 5 6/13 down to 5 provides a whole number estimate that is slightly smaller but still reasonably close to the initial mixed fraction.

Rounding serves as a useful tool in situations where precise values are not necessary and a simpler approximation is sufficient for practical purposes.

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ccabo de 25 años será la edad del padre tres veces mayor que la edad del hijo.El número es 36.Hay 8 hombres, 16 mujeres y 72 niños.Hay 27 cerdos y 8 pavos

Sea x el número de años transcurridos. La edad del padre será 35 + x y la edad del hijo será 5 + x. La ecuación que representa la situación es: 35 + x = 3(5 + x). Resolviendo la ecuación, tenemos:

35 + x = 15 + 3x

2x = 20

x = 10

Por lo tanto, después de 10 años, la edad del padre será tres veces mayor que la edad del hijo.

Sea x el número desconocido. La ecuación que representa la situación es: 2x - (1/2)x = 54. Resolviendo la ecuación, tenemos:

(4/2)x - (1/2)x = 54

(3/2)x = 54

x = 36

Por lo tanto, el número desconocido es 36.

Sea x el número de hombres. Según la información dada, el número de mujeres es el doble, es decir, 2x, y el número de niños es el triple, es decir, 3(x + 2x) = 9x. La ecuación que representa la situación es: x + 2x + 9x = 96. Resolviendo la ecuación, tenemos:

12x = 96

x = 8

Por lo tanto, hay 8 hombres, 16 mujeres y 72 niños en la reunión.

Sea x el número de cerdos y y el número de pavos. Según la información dada, tenemos las siguientes ecuaciones: x + y = 35 (por el total de cabezas) y 4x + 2y = 116 (por el total de patas). Resolviendo este sistema de ecuaciones, obtenemos:

x + y = 35

4x + 2y = 116

Multiplicamos la primera ecuación por 2:

2x + 2y = 70

Restamos la segunda ecuación de la primera:

2x + 2y - (4x + 2y) = 70 - 116

-2x = -46

x = 23

Sustituyendo el valor de x en la primera ecuación, tenemos:

23 + y = 35

y = 12

Por lo tanto, hay 23 cerdos y 12 pavos en la granja.

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Answer:

a_48000cm^3

b_48000000mm^3

Step-by-step explanation:

first of all, let's find the base area:

Ab=((b+B)h)/2=((10cm+30cm)20cm)/2=400cm^2

then, to find the volume, we need to multiplicate the base area to the height of the prism:

V=Ab*H=400cm^2*120cm=48000cm^3=48000000mm^3

Thus, approximately 33.33% of the data values are between 25 and 45.

A box-and-whisker plot, also known as a box plot, is a graphical representation of a set of data that shows the distribution of the data along a number line. The plot is composed of a box that represents the middle 50% of the data, along with two "whiskers" that represent the lowest and highest values in the data set. The box is drawn between the first and third quartiles of the data, with a line inside the box representing the median value. The distance between the first and third quartiles is known as the interquartile range (IQR), which can be used to identify outliers in the data. Box-and-whisker plots are useful for comparing the distribution of data between different groups or data sets.

Here,

To find the percentage of the data values that are between 25 and 45 on the given box-and-whisker plot, we need to find the area of the box that is between the lower quartile (Q1) and the median (Q2). From the plot, we can see that the lower quartile (Q1) is at 30, and the median (Q2) is at 40. The interquartile range (IQR), which is the distance between Q1 and Q3, is 20.

Therefore, the box extends from 30 to 40, which is a distance of 10. The total length of the plot is 30 (from 25 to 55), so the percentage of data values between 25 and 45 is:

10/30 * 100% = 33.33%

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Complete question:

The box-and-whisker plot below represents some data set. What percentage of the data values are between 25 and 45?

As an estimation of the exchange rates, 16 Euros is approximately equal to 12 Pounds.

To convert Euros to Pounds, we first need to determine the conversion rate between these two currencies. From the information provided, we know that 3 Pounds is approximately equal to 4 Euros. Using this information, we can establish a conversion factor by dividing 3 Pounds by 4 Euros:

Conversion factor = 3 Pounds / 4 Euros = 0.75 Pounds per Euro

Now that we have the conversion factor, we can use it to convert 16 Euros to Pounds. To do this, we simply multiply the amount in Euros (16) by the conversion factor (0.75 Pounds per Euro):

16 Euros * 0.75 Pounds per Euro = 12 Pounds

So, as an estimation, 16 Euros is approximately equal to 12 Pounds. Keep in mind that exchange rates between currencies can fluctuate over time, so it's always a good idea to double-check the current rate before making any financial transactions.

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Complete Question:

As an estimation we are told £3 is €4.

Convert €16 to pounds.

Answer:

B.

Resources, as in details of the problem and then you do check the answers and present the solution.

Answer:

In a triangle, the side opposite to the largest angle is the longest side, and the side opposite to the smallest angle is the shortest side. In triangle XYZ, the length of side XY is m + 8, the length of side YZ is 2m + 3, and the length of side ZX is m - 3. Since m ≥ 6, we can determine that 2m + 3 is the largest value, m + 8 is the next largest value, and m - 3 is the smallest value. Therefore, side YZ is the longest side and side ZX is the shortest side.

Since side YZ is the longest side, angle X must be the largest angle. Since side ZX is the shortest side, angle Y must be the smallest angle. Therefore, the correct ordering of the angles from smallest to largest is ∠Y < ∠Z < ∠X.

Step-by-step explanation:

Answer:80%

Step-by-step explanation:

Answer:

divide by 100

Step-by-step explanation:

hope it helps

Convert 1 Kilograms to Meters (kg to m) with our conversion calculator and conversion tables. To convert 1 kg to m use direct conversion formula below.

Convert 1 Kilograms to Meters (kg to m) with our conversion calculator and conversion tables. To convert 1 kg to m use direct conversion formula below.1 kg = 1 m.

Convert 1 Kilograms to Meters (kg to m) with our conversion calculator and conversion tables. To convert 1 kg to m use direct conversion formula below.1 kg = 1 m.You also can convert 1 Kilograms to other Weight (popular) units.

[tex]Direct \: \: conversion \: \: formula: 1 Kilograms * 1 = 1 Meters[/tex]

To prove that the right triangles are congruent, we need to show that they have three pairs of congruent parts (sides or angles).

Let's say that the given congruent parts are the hypotenuses and one leg of each triangle. To prove congruence, we can add one more pair of congruent parts, such as the other leg.

By the Side-Angle-Side (SAS) congruence theorem, if two triangles have two pairs of congruent sides and the included angle is also congruent, then the triangles are congruent. In this case, we have two pairs of congruent sides (the hypotenuses and one leg) and the included angle (the right angle) is congruent by definition.

Therefore, we can conclude that the two right triangles are congruent by SAS.

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a) The mean monthly rainfall amount for City A is 334.17 inches and for City B is 5.83 inches.

b) The MAD for City A is 464.28 inches and for City B is 0.46 inches.

c) The median for City A is 5 inches and for City B is 6 inches.

(a) To find the mean monthly rainfall amount for each city, we need to add up all the rainfall amounts and divide by the number of months:

For City A: (5 + 2.5 + 6 + 2008.5 + 5 + 3) / 6 = 334.17 inches

For City B: (7 + 6 + 5.5 + 6.5 + 5 + 6) / 6 = 5.83 inches

(b) To find the mean absolute deviation (MAD) for each city, we need to find the absolute deviations from the mean for each data point, then calculate the average of those absolute deviations:

For City A:

Mean = 334.17 inches

Absolute deviations from the mean: |5 - 334.17| = 329.17, |2.5 - 334.17| = 331.67, |6 - 334.17| = 328.17, |2008.5 - 334.17| = 1674.33, |5 - 334.17| = 328.17, |3 - 334.17| = 331.17

MAD = (329.17 + 331.67 + 328.17 + 1674.33 + 328.17 + 331.17) / 6 = 464.28 inches

For City B:

Mean = 5.83 inches

Absolute deviations from the mean: |7 - 5.83| = 1.17, |6 - 5.83| = 0.17, |5.5 - 5.83| = 0.33, |6.5 - 5.83| = 0.67, |5 - 5.83| = 0.83, |6 - 5.83| = 0.17

MAD = (1.17 + 0.17 + 0.33 + 0.67 + 0.83 + 0.17) / 6 = 0.46 inches

(c) To find the median for each city, we need to arrange the data points in order and find the middle value:

For City A: {2.5, 3, 5, 5, 6, 2008.5}

Median = 5 inches

For City B: {5, 5.5, 6, 6, 6.5, 7}

Median = 6 inches

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To evenly distribute 1425 stamps into 7 piles, you would divide 1425 by 7. This gives you a quotient of 203 with a remainder of 4. This means that each pile would contain 203 stamps and there would be 4 stamps left over.

To understand this better, you can visualize the process of dividing 1425 stamps into 7 equal piles. You could start by putting 203 stamps into the first pile. Then, you would add another 203 stamps to the second pile. You would continue this process until you had 7 piles, each containing 203 stamps. However, you would be left with 4 stamps that couldn't be evenly distributed.

This type of division is called integer division because it results in a whole number quotient and potentially a remainder. In this case, the quotient represents the number of stamps that can be evenly distributed among the piles, and the remainder represents the leftover stamps that cannot be evenly distributed.

Overall, to divide 1425 stamps into 7 piles, each pile would contain 203 stamps, with 4 stamps remaining.

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