A) How much gravitational potential energy must a 3120-kg satellite acquire in order to attain a geosynchronous orbit?
B) How much kinetic energy must it gain? Note that because of the rotation of the Earth on its axis, the satellite had a velocity of 456 m/s relative to the center of the Earth just before launch.

Answers

Answer 1

The kinetic energy required for the satellite to attain a geosynchronous orbit is approximately 3.00 × 108 J.

When answering questions on Brainly, a question-answering bot should always be factually accurate, professional, and friendly, be concise and not provide extraneous amounts of detail, and use the following terms provided in the student question while also ignoring any typos or irrelevant parts of the question.

In response to the student question, we will calculate the gravitational potential energy and kinetic energy required for a 3120-kg satellite to attain a geosynchronous orbit.

Gravitational potential energyTo calculate the gravitational potential energy required to attain a geosynchronous orbit, we use the formula:U = -G (Mm/r)where U is the gravitational potential energy, G is the universal gravitational constant (6.67 × 10-11 N m2/kg2), M is the mass of the Earth (5.98 × 1024 kg),

m is the mass of the satellite (3120 kg), and r is the radius of the geosynchronous orbit (42,164 km).Substituting these values into the equation:U = -6.67 × 10-11 × 5.98 × 1024 × 3120 / 42,164 × 103U = -9.84 × 1010 JSo the gravitational potential energy required for the satellite to attain a geosynchronous orbit is approximately 9.84 × 1010 J.

Kinetic energyTo calculate the kinetic energy required to attain a geosynchronous orbit, we use the formula:KE = (1/2)mv2where KE is the kinetic energy,

m is the mass of the satellite (3120 kg), and v is the velocity of the satellite just before launch (456 m/s).Substituting these values into the equation:KE = (1/2) × 3120 × (456)2KE = 3.00 × 108 J

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Related Questions

Two concrete spans of a 370 m long bridge are
placed end to end so that no room is allowed
for expansion. 370 mT T + 20◦Cy
If the temperature increases by 20◦C, what
is the height to which the spans rise when
they buckle? Assume the thermal coefficient
of expansion is 1.2 × 10−5(◦C)−1

Answer in units of m.

Answers

The height to which the spans rise when they buckle is 0.0222 m.

A high thermal coefficient: what does that imply?

A material will expand more as a result of being heated if its coefficient of thermal expansion is larger.

What does the thermal expansion law mean?

The phenomena known as thermal expansion can be seen in solids, liquids, and gases. In this procedure, the application of heat causes an object or body to expand (temperature). The term "thermal expansion" refers to an object's propensity to change its dimensions as a result of heat, including length, density, area, and volume.

The following formula can be used to determine the height to which the spans rise when they buckle:

ΔL = LαΔT

where ΔL = change in length,

L = original length,

α = coefficient of thermal expansion,

ΔT = change in temperature

the length of the bridge = 370 m,

the coefficient of thermal expansion = 1.2 × 10^-5 (°C)^-1,

the change in temperature = 20°C.

The change in length of each span is,

ΔL = LαΔT = (370/2)(1.2 × 10^-5)(20)

    = 0.0444 m

Since there are two spans, the total change in length is 0.0888 m.

h = ΔL/2 = 0.0444/2

   = 0.0222 m

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on the bench, a vertical wire is attached to a power supply and a switch. the wire runs through the center of a plastic stand. when the switch is closed, what direction will the current flow (up or down) in the wire?

Answers

As a result, electric current flows from top to bottom i.e. downwards in the vertical wire.

When the switch is closed, the current will flow downwards in the vertical wire attached to a power supply and a switch. The wire runs through the center of a plastic stand. This is because the direction of electric current is from higher potential to lower potential.

When the switch is closed, it completes the circuit allowing electric current to flow through the wire. The power supply provides a higher potential at the top of the wire and a lower potential at the bottom of the wire.

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when soot lands on snow and ice, the absorption of thermal energy increases because there is a decrease in

Answers

Soot is a dark-colored substance made up of tiny particles of carbon. When soot lands on snow and ice, it darkens the surfaces and decreases the albedo, or reflectivity, of that surface.

This means that less sunlight is reflected back into the atmosphere, and more is absorbed by the snow and ice. This absorption of thermal energy causes the snow and ice to melt more quickly.

Additionally, the soot particles act like tiny heat absorbers and further increase the temperature of the snow and ice. This can further speed up the melting process and contribute to a decrease in global snow and ice cover. In turn, this can have serious environmental consequences, such as sea level rise and increased global temperatures.

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a roller coaster needs to complete a vertical loop that has radius 10 m what must its minimum speed be at top of loop ?

Answers

Answer:

9.90 m/s.

Explanation:

In order for the roller coaster to complete a vertical loop of radius 10 m, it must have enough speed at the top of the loop to overcome the force of gravity and maintain contact with the track. At the top of the loop, the roller coaster is momentarily at rest (i.e., its speed is zero), and the only force acting on it is gravity. Therefore, we can use the following equation to find the minimum speed required:

Centripetal force = Weight of the roller coaster
                  mv^2/r = mg

where m is the mass of the roller coaster, v is its speed at the top of the loop, r is the radius of the loop, and g is the acceleration due to gravity.

Solving for v, we get:

v = √(gr)

Substituting in the given values, we get:

v = √(9.81 m/s^2 * 10 m)v = 9.90 m/s

Therefore, the minimum speed that the roller coaster must have at the top of the loop is 9.90 m/s.

The roller coaster's minimum speed at the top of the loop should be approximately 9.90 m/s  that has radius 10 m.

To complete a vertical loop without falling off at the top, the roller coaster must have sufficient speed to counteract gravity.

At the top of the loop, the minimum speed required can be found using the concept of centripetal force.

At the top of the loop, the centripetal force (provided by the roller coaster's speed) must equal the force due to gravity. This can be expressed as:

[tex]mv^2[/tex]/ r = mg

Where m is the mass of the roller coaster, v is its speed, r is the radius of the loop, and g is the acceleration due to gravity

(approximately 9.81 [tex]m/s^{2}[/tex]).

Solving for v:

[tex]v^2 = rg[/tex]

v = [tex]\sqrt{(10 m * 9.81 m/s^{2} )[/tex] ≈ [tex]\sqrt{(98.1 m^{2} /s^{2} )[/tex] ≈ 9.90 m/s

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Can omeone help me with 1 and two

Answers

Answer: f =  0.6 per sec

54 cycles in 90 sec

Explanation:

Which energy type is missing in the windmill energy transformation? kinetic (wind) > ________ > electrical

Answers

Answer: mechanical?

Explanation:

When warm air rises in a convection current, what happens next?
Please I need help!

Answers

Answer:

cool air flows toward the ground

Explanation:

Answer:

it brings heat

Explanation:

or it can lead you to death when warm air rises

If we traveled at 50,000 km/hr, how long will it take us to get to Proxima Centauri in a space ship?

Answers

Therefore, it would take approximately 2.88 million seconds, or around 32.5 days, to travel to Proxima Centauri at a speed of 50,000 km/hr.

How much time would it take for a spacecraft to reach Alpha Centauri?

Nearly 40 trillion kilometers, or 4.4 light-years, separate us from Alpha Centauri. The NASA-Germany Helios probes, the fastest spacecraft to date to be propelled into orbit, travelled at a speed of 250,000 kilometres per hour.

We need to convert this speed to a more useful measure, such as kilometres per second (km/s), to find the time it would take a spacecraft travelling at 50,000 km/hr to reach Proxima Centauri.

1 hour = 60 minutes

1 minute = 60 seconds

Therefore, 1 hour = 60 x 60 = 3600 seconds

So, 50,000 km/hr = (50,000 km / 3600 sec) = 13.89 km/s

We must know the distance in kilometres in order to determine the estimated travel duration to Proxima Centauri. The distance to Proxima Centauri is calculated as follows given that 1 light-year is equal to roughly 9.46 trillion kilometres:

4.24 light-years x 9.46 trillion km/light-year = 40.003 trillion km

Using the formula

time = distance / speed

we can calculate the travel time:

time = 40.003 trillion km / 13.89 km/s = 2.88 million seconds

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astronomers have used observations from the hubble space telescope to measure the rate at which the universe is expanding, and have estimated the age of the universe from that measured rate. suppose the expansion turns out to be faster than current measurements indicate. in that case, our new estimate for the age of the universe would be group of answer choices younger (less time between now and the big bang). unaffected. older (more time between now and the big bang).

Answers

If the expansion of the universe turns out to be faster than current measurements indicate, it would mean that the universe is expanding at a greater rate than previously thought. This would imply that the universe has been expanding for a shorter period of time, as the same amount of expansion could be achieved in less time at a faster rate.

The new estimate for the age of the universe would be younger, with less time between now and the big bang. This would have significant implications for our understanding of the early universe, as a younger age would mean that there was less time for galaxies and structures to form.

It would also have implications for other cosmological models, as the age of the universe is a fundamental parameter in many theories of cosmology. However, it is important to note that this is still a hypothetical scenario, and further observations and measurements are needed to confirm or refute this possibility.

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An airplane flies at 120km/h relative to air. There is a wind blowing at 90km/h relative to the ground. Calculate the speed of the airplane relative to the ground if.
a) they have opposite direction
b) perpendicular.​

Answers

Explanation:

a) if theya re OPPOSITE then the wind speed subtracts from the airplane's speed ( a headwind) sooooo    120 - 90 = 30 km/hr

b) if the two speeds are perpendicular , you can use Pythagorean theorem:

      R^2 = 120^2 + 90^2

      R = 150 km/hr

a lighter block (5 kg) and a heavier block (20 kg) sit on a frictionless surface. both blocks are initially at rest. the same force of 10 n then pushes to the right on each block for a distance of 16 m. what are the changes in kinetic energy of the blocks?

Answers

The changes in kinetic energy of the two blocks are both 160 J.

The changes in kinetic energy of the two blocks can be calculated using the work-energy theorem. The force of 10 N applied to both blocks does the same amount of work on each block, since they both move the same distance of 16 m. The work done on each block can be calculated as:

[tex]W = Fd = (10 N)(16 m) = 160 J[/tex]

The change in kinetic energy of each block can then be calculated as:

Δ[tex]K = W = 160 J[/tex]

Since the initial kinetic energy of both blocks is zero, their final kinetic energies are equal to the work done on them:

[tex]K\ final (5 kg block) = 160 J\\K\ final (20 kg block) = 160 J[/tex]

Therefore, changes in kinetic energy of the two blocks are both 160 J.

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at 9:19 a.m., you pass a police car at 60 mph that is stopped on the freeway. you pass a second police car at 60 mph at 9:55 a.m., which is located 42 mi from the first police car. if the speed limit is 65 mph, can the police cite you for speeding?

Answers

No, the police cannot cite you for speeding since you were traveling at the speed limit of 60 mph.

Expecting you kept a steady speed of 60 mph, you went for 36 minutes (9:19 a.m. to 9:55 a.m.) prior to passing the second squad car. During this time, you voyaged a distance of 36 miles (60 miles/hour x 0.6 hours). According to the viewpoint of the primary squad car, you were going at a speed of 60 mph, which is beneath the speed furthest reaches of 65 mph. Thusly, the primary squad car can't refer to you for speeding.

At the point when you passed the second squad car, you had voyaged an all out distance of 42 miles (the distance between the two squad cars). You had been driving for 36 minutes (0.6 hours) and your speed was steady at 60 mph. In this way, your typical speed was 70 mph (42 miles ÷ 0.6 hours). This is over the speed furthest reaches of 65 mph, so the second squad car could refer to you for speeding.

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if a 4kg crate is being pulled to the right with a force of 20 n and it experiences a friction force of 5n what is its acceleration

Answers

If a 4kg crate is being pulled to the right with a force of 20 n and it experiences a friction force of 5n.  The acceleration of the crate is 3.75 m/s².

The net force acting on the 4kg crate can be calculated by subtracting the friction force from the applied force:

20N - 5N = 15N.

To find the acceleration, use Newton's second law, F = ma.

Rearranging  the equation to solve for acceleration:

a = F/m.

In this case,

a = 15N / 4kg

a = 3.75 m/s².

So, the acceleration of the crate is 3.75 m/s² to the right.

The rate at which an object's velocity varies over time is called accelaration. It is, in other words, the change in velocity per unit time. Acceleration occurs when an item accelerates, decelerates, or changes direction.

In the International System of Units, acceleration is typically measured in metres per second squared (m/s^2) (SI).

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when will a new moon appear

Answers

Answer:on april 20th at aproximately 12: 12 a.m

Why does 250 N not push an object when frictional force is 188 N while 251 N is pushing with fast acceleration.

Answers

Due to the difference in net force delivered to the item in each situation, 250 N cannot push an object while the frictional force is 188 N, whereas 251 N may push the identical thing with rapid acceleration.

When there is friction, what happens to acceleration?

When friction is present, an object may continue to travel at a steady speed despite the application of an external force. The friction force simply balances the applied force in this scenario. There is no acceleration since there is no net force.

Does friction increase as you go faster?

No, acceleration has no impact on the kinetic friction coefficient. The type of surfaces that make contact with one other and not the speed at which they are travelling determine the coefficient of kinetic friction, which is constant.

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a heat pump is used to heat a house. it have a desired output of heat at a rate of 10 kw, and it accepts 5 kw of work. determine the cop of the heat pump.

Answers

The COP of the heat pump is 2. The coefficient of performance (COP) is a measure of the efficiency of a heat pump, defined as the ratio of the desired output of heat to the input of work.

In this case, the desired output of heat is 10 kW and the input of work is 5 kW, so the COP of the heat pump is: COP = desired output / input of work COP = 10 kW / 5 kW COP = 2

which means that for every unit of work input, the heat pump produces two units of desired output heat. This is a measure of the efficiency of the heat pump, with higher COP values indicating better efficiency.

Heat pumps are a popular and efficient way to heat homes, as they can extract heat from the outside air or ground, and use it to heat the indoor air. The COP of a heat pump can vary depending on factors such as the temperature difference between the inside and outside, and the efficiency of the components used in the system.

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A runner covers the last straight stretch of a race in 4s During the time he speeds up from 5m/s to 9ms. What is the runners acceleration in this part of the race?

Answers

Answer: 1m/s^2

Explanation: The formula to find acceleration is:

a = (vf - vi) / t

where:

a= acceleration

vf= final velocity

vi= intial velocity

t= time

By substituting these values ​​in the acceleration equation, we obtain:

a = (9 m/s - 5 m/s) / 4 s

we get:

a = 1 m/s^2

go to the sources group and select the sine wave block and replace the step with this. this means vm is a sinusoid. set the amplitude to 5 and frequency to 2*pi*3 (3 hz). run the simulation and obtain the omega l(t) trace. does the output make sense and why?

Answers

In RLC circuit the output omega L(t) represents the instantaneous energy stored in the inductor. It will be a function of time.

If a sinusoidal voltage is applied to the circuit, the energy stored in the inductor start to oscillates. It will start oscillating at the same frequency as the voltage.

The amplitude of the energy oscillations depends on the parameters of circuit and amplitude of the voltage. These parameters includes resistance, inductance, and capacitance.

So we can say that the output omega L(t) shows sinusoidal oscillations at a frequency of 3 Hz and an amplitude of 5. Now it would make sense for the given circuit parameters and voltage amplitude.

The waveform shape and the amplitude will depend on the specific circuit parameters. Also depend on the initial conditions.

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what are the two correct answers to this question

Answers

Answer:

Most probably mass and volume

Explanation:

i dont think you can really measure it from its color i dont think measurements work that way lol. temperature cant be the option because all of them are likely to be in the same condition and time is just an absurd way to measure a object

For the solar cooker project, the two measurements that students should make to determine the dependent variable are: temperature and time.

What are the  measurement that student should make to determine the dependent variable?

Two measurements that students should make to determine the dependent variable are :

Temperature: The students should measure the temperature of the food being cooked at different times of day and under different conditions, such as with or without insulation, with or without reflective materials, and so on. The temperature would be dependent variable because it is directly related to the rate of cooking. The higher the temperature, then faster the food will cook.

Time: The students should measure the time it takes to cook the food under different conditions. The time would be a secondary dependent variable because it is also directly related to rate of cooking. The faster the food cooks, the shorter the cooking time will be.

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if two bodies contact one another without slipping, and the points in contact move along different paths, the tangential components of acceleration will be

Answers

When two bodies contact each other without slipping and the points in contact move along different paths, the tangential components of acceleration will be different. This means that the bodies will have different accelerations along the tangential direction.

Tangential acceleration refers to the component of an object's acceleration that is parallel to the object's velocity vector. As an object moves, its velocity vector changes in direction, and thus the direction of its acceleration vector also changes.

The tangential acceleration is the part of this vector that is parallel to the velocity vector. It is also referred to as the longitudinal acceleration.

When two bodies make non-slip contact and the points of contact travel along distinct routes, the tangential components of acceleration diverge. This indicates that the bodies' accelerations will differ along the tangential direction.

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two electromagnetic waves have different frequencies but equal amplitudes. the one with higher frequency has the group of answer choices longer wavelength. greater energy. none of these. greater speed. all of these.

Answers

Explanation:

The correct answer is: none of these.

The frequency of an electromagnetic wave is inversely proportional to its wavelength and directly proportional to its energy. Therefore, two electromagnetic waves with different frequencies will have different wavelengths and energies. The amplitude of an electromagnetic wave, on the other hand, refers to the maximum displacement of the wave from its equilibrium position and is not related to its frequency, wavelength, or energy.

Therefore, we cannot determine whether the electromagnetic wave with higher frequency has a longer wavelength, greater energy, greater speed, or any combination of these, based solely on the information given in the question.

When two electromagnetic waves have different frequencies but equal amplitudes, the one with a higher frequency has greater energy.

What are electromagnetic waves?

Electromagnetic waves are a type of wave that travels through space. They are a combination of electric and magnetic fields that move at right angles to each other and at right angles to the direction of wave propagation. The sun, light, radio waves, and microwaves are all examples of electromagnetic waves.

The formula that explains the relationship between energy and frequency of electromagnetic waves is E=hv where E is energy, v is frequency, and h is Planck's constant. The energy of electromagnetic radiation is proportional to its frequency.

Therefore, When two electromagnetic waves have different frequencies but equal amplitudes, the one with a higher frequency has greater energy.

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a resistor is connected to a 3.0 v battery; the power dissipated in the resistor is 1.0 w. the battery is now traded for a 6.0 v battery. the power dissipated by the resistor is now:

Answers

A resistor is connected to a 3.0 V battery and the power dissipated in the resistor is 1.0 W. If the battery is now traded for a 6.0 V battery, the power dissipated by the resistor is now 4.0 W.

The power dissipated by a resistor is given by the formula:

P = V²/R

Rearranging this formula we get:

R = V²/P

Power is directly proportional to the square of voltage.

Hence, if the voltage is doubled, the power will be quadrupled.

Therefore, the power dissipated by the resistor will be four times the original power when the battery is traded for a 6.0 V battery.

Thus, the power dissipated by the resistor is 4.0 W now.

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2. How far (in meters) will you travel in 220 seconds running at a rate of 5.4 m/s?

Answers

Answer:

Explanation: Given: Time=220 seconds

Speed=5.4m/s

To find: Distance covered

Solution:

->The distance covered will be rate of running×time taken

Distance covered=5.4×220

->1188 metres

->Therefore, the distance covered will be 1188 metres.

a simple point-and-shoot camera uses 35 mm film (actually 36 mm wide and 24 mm tall). what is the required focal length of the camera in order that it has a horizontal angle of view of 52o? use the fact that the maximum image size that the film can capture occurs when the image height is equal to half the width of the film.

Answers

The required focal length of the camera in order to have a horizontal angle of view of 52° is approximately 27.2 mm.

To find the required focal length of the camera, we need to use the given information and the formula for angle of view. Here's a step-by-step explanation:
1. The maximum image size on the film occurs when the image height is equal to half the width of the film. So, the image height is 36 mm / 2 = 18 mm.
2. Since the image dimensions are 36 mm wide and 18 mm tall, we will focus on the horizontal angle of view, which is 52°.
3. The formula for the angle of view (α) is given by:
α = 2 * arctan (d / (2 * f))
where α is the angle of view, d is the image width, and f is the focal length.
4. We want to find the focal length (f) using the given angle of view (α) and the image width (d).

Rearrange the formula:
f = d / (2 * tan(α/2))

5. Plug in the values: α = 52° and d = 36 mm:
f = 36 / (2 * tan(52°/2))
6. Calculate the result:
f ≈ 27.2 mm
The required focal length of the camera in order to have a horizontal angle of view of 52° is approximately 27.2 mm.

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suppose a 200-mm focal length telephoto lens is being used to photograph mountains 9.5 km away. show answer no attempt 50% part (a) what is image distance, in meters, for this lens?

Answers

Suppose a 200-mm focal length telephoto lens is being used to photograph mountains 9.5 km away, The image distance for this lens is approximately 0.200 m (200 mm).

To calculate the image distance for a 200-mm focal length telephoto lens photographing mountains 9.5 km away, we can use the lens formula:
1/f = 1/do + 1/di
where f is the focal length (200 mm), do is the object distance (9.5 km), and di is the image distance we want to find.
Step 1: Convert distances to the same units (meters).
Focal length: 200 mm = 0.2 m
Object distance: 9.5 km = 9500 m
Step 2: Plug the values into the lens formula.
1/0.2 = 1/9500 + 1/di
Step 3: Rearrange the formula to solve for di.
1/di = 1/0.2 - 1/9500
Step 4: Calculate the value of 1/di.
1/di = 5 - 0.00010526
1/di = 4.99989474
Step 5: Find the value of di by taking the reciprocal of the previous result.
di = 1/4.99989474
di ≈ 0.200021 m

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Model B was accepted as the structure of the Universe for over 1,000 years. However, it had a major flaw that couldn't be explained. What was that flaw?

Model B is the Heliocentric Theory which cannot explain retrograde.
Model B is the Geocentric Theory which cannot explain retrograde.
Model B is the Heliocentric Theory which cannot explain the Law of Universal Gravitation.
Model B is the Geocentric Theory which cannot explain the Law of Universal Gravitation.

Answers

The Geocentric Theory, which cannot explain backward, is Model B.

Why didn't the heliocentric paradigm gain traction?

Because its proponents were unable to explain why the relative positions of the stars appeared to stay the same despite the Earth's changing perspectives as it rotated around the Sun, The solar system's heliocentric, or Sun-centered, model was never generally accepted.

Why is the heliocentric paradigm more popular than the geocentric model?

Instead of Earth, as was previously thought to be the case according to the geocentric model, the heliocentric model puts the Sun at the core of the solar system. Our greater knowledge of astronomy was built on this advancement, which brought us closer to the true nature of the solar system and the universe.

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a bungee jumper jumps from a platform and is decelerated by an elastic bungee cord, as shown. at which part of the jump are all three types of energy non-zero?

Answers

At the part of the bungee jump where all three types of energy (potential energy, kinetic energy, and elastic potential energy) are non-zero is when the jumper is falling and the bungee cord starts to stretch but has not yet reached its maximum extension.



1. The jumper starts with potential energy (height) and zero kinetic energy (not moving) and zero elastic potential energy (cord not stretched).
2. As the jumper falls, the potential energy decreases, and kinetic energy increases (due to acceleration), while the elastic potential energy is still zero (cord not stretched yet).
3. When the bungee cord starts to stretch, all three types of energy are non-zero: potential energy (some height remains), kinetic energy (still moving), and elastic potential energy (cord stretching).
4. At the maximum extension of the cord, kinetic energy becomes zero (momentarily stopped), potential energy is still non-zero (height), and elastic potential energy is at its maximum (cord fully stretched).

Therefore, the three types of energy are potential energy, kinetic energy, and elastic potential energy.

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four 20 ohm resistors are connected in series and the combination is connected to a 20 v emf device. the potential difference across any one of the resistors is:

Answers

The potential difference across any one of the resistors in a circuit where four 20 ohm resistors are connected in series and the combination is connected to a 20 V emf device is 5 V.

What is a potential difference? A potential difference, also known as voltage, is the difference in electric potential energy between two points in an electric field. It is calculated as the work done per unit charge to move a charge from one point to another in the electric field. It is measured in volts (V).How is the potential difference in a circuit determined?The potential difference in a circuit can be calculated using Ohm's law. According to Ohm's law, the potential difference across a resistor is directly proportional to the current flowing through the resistor and the resistance of the resistor.V = IRwhereV is the potential difference (in volts),I is the current (in amperes), andR is the resistance (in ohms).In the given circuit, the total resistance of the four 20 ohm resistors in series is 80 ohms. The emf of the device is 20 V.Using Ohm's law,V = IR20 = I(80)I = 20/80I = 0.25 AThe current flowing through the circuit is 0.25 A. Since the resistors are connected in series, the current flowing through each resistor is the same.I = V/RI = 5/20I = 0.25 AThe potential difference across any one of the resistors is 5 V.

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work-energy theorem: a 4.00-kg mass is attached to a very light ideal spring hanging vertically and hangs at rest in the equilibrium position. the spring constant of the spring is 1.00 n/cm. the mass is pulled downward 2.00 cm and released. what is the speed of the mass when it is 1.00 cm above the point from which it was released?

Answers

The speed of the 4.00-kg mass when it is 1.00 cm above the point from which it was released is 0.866 m/s.

Using the work-energy theorem, the speed of the 4.00-kg mass when it is 1.00 cm above the point from which it was released can be calculated as follows: First, find the potential energy stored in the spring when the mass is pulled down 2.00 cm.

The potential energy (PE) can be calculated using the formula: PE = 0.5 * k * [tex]x^{2}[/tex], where k is the spring constant (1.00 N/cm) and x is the displacement (2.00 cm).

PE = 0.5 * 1.00 * (2.00[tex])^{2}[/tex] = 2.00 J (joules)

Now, find the potential energy when the mass is 1.00 cm above the release point. The new displacement is 1.00 cm (since it moved 1.00 cm upwards).

PE_new = 0.5 * 1.00 * (1.00[tex])^{2}[/tex] = 0.50 J

The difference in potential energy is the kinetic energy (KE) gained by the mass.

KE = PE - PE_new = 2.00 - 0.50 = 1.50 J

The kinetic energy can be calculated using the formula: KE = 0.5 * m * [tex]V^{2}[/tex], where m is the mass (4.00 kg) and v is the speed. We can rearrange the formula to solve for the speed: v = sqrt(2 * KE / m)

v = ([tex]\sqrt{2 * 1.50 / 4.00}[/tex]) = [tex]\sqrt{0.75}[/tex] = 0.866 m/s

So, the speed of the 4.00-kg mass when it is 1.00 cm above the point from which it was released is 0.866 m/s.

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Help please. If a comet were so large that its mass generated more gravity, then what would happen?


A. It wouldn’t orbit the Sun.

B. It would have become an asteroid.

C. It wouldn’t have a tail.

D. It would have become a meteor.

Answers

Answer:

it will become an asteroid because of the gravitational force

A comet would not become an asteroid, meteor, or lose its tail unless it were so massive that its bulk produced additional gravity.

What would occur if a sizable comet collided with the Sun?

When a comet is large and powerful enough to strike the sun directly, it explodes. The comet is crushed by the sun's atmosphere after accelerating to more than 370 miles per second, creating a magnificent explosion that emits cosmic tidal waves of x-rays and ultraviolet light.

What do you believe would occur if a big comet hit the earth?

A large comet's impact on Earth would be catastrophic. Large tidal waves, fires, and airborne dust and soot buildup could result, blocking out the majority of sunlight, causing vegetation to die and animals to go hungry.

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