A manufacturer sells pens for $0.50 each. If the wholesaler adds a markup of 60% and the retailer adds a markup of
120% of the manufacturer's price, what is the final price of the pen?

The water level is rising at a rate of 0.0075 ft/min when the depth at the deepest point is 5 ft.

Let's call the depth at the deepest point of the pool "y" and the volume of

the water in the pool "V".

We want to find the rate at which the water level is rising, which is the

rate of change of "y" with respect to time.

We know the rate at which the pool is being filled, which is 0.9 ft3/min,

and we can find the rate at which the volume of the water is increasing

using the formula for the volume of a rectangular prism:

V = lwh

where l is the length, w is the width, and h is the height.

Since the pool is not rectangular, we can find the volume of the water as

a function of "y" using similar triangles:

h/y = (9 - 3)/(40 - 20) = 0.3

where h is the height of the pool at the deepest point. Solving for h, we get:

h = 0.3y

Substituting this expression for h into the formula for the volume, we get:

V = lw(3 + 0.6y)

Taking the derivative with respect to time, we get:

dV/dt = lw(0.6 dy/dt)

Now we need to find the values of l and w. The width is given as 20 ft,

and the length is a function of "y":

l = 40 - 2(40 - y) = 2y

Substituting these values into the expression for dV/dt, we get:

dV/dt = 40y(0.6 dy/dt)

Finally, we can find the rate at which the water level is rising when y = 5 ft

by plugging in the values:

0.9 = 40(5)(0.6 dy/dt)

Solving for dy/dt, we get:

dy/dt = 0.9/(4050.6) = 0.0075 ft/min

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Answer:

Greatest is Miami

Least is Washington

Step-by-step explanation:

Population/Area= Population Density

Ex:

Population 2

Area 1

2/1=2

The gradient of the line segment AB is -4/3.

What is the gradient?

The gradient is a measure of the steepness of a curve or surface at a particular point. It is a vector quantity that points in the direction of the greatest increase in the function value and whose magnitude gives the rate of change of the function in that direction.

The coordinates of point A are (0, 6), and the coordinates of point B are (3, 2). We can find the gradient of the line connecting these two points using the formula:

gradient = rise/run

where "rise" is the difference in the y-coordinates of the two points, and "run" is the difference in the x-coordinates.

So, we have:

rise = 2 - 6 = -4

run = 3 - 0 = 3

Plugging these values into the formula, we get:

gradient = -4 / 3

Therefore, the gradient of the line segment AB is -4/3.

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Answer: A | 12² + b² = 37²

Step-by-step explanation:

The height can be found by using the Pythagoras Theorem
h² = b² + p²

Answer:

  50 ft by 25 ft . . . . . 50 ft parallel to the barn

Step-by-step explanation:

You want the dimensions of the largest rectangular area that can be enclosed using 100 ft of fence for three sides.

If the dimensions of the space are L feet in length and W feet in width, where L is parallel to the barn, the length of the perimeter fence is ...

  P = L +2W

Solving for W gives ...

  W = (P -L)/2

The area of the enclosed space is ...

  A = LW

  A = L(P -L)/2 . . . . . substitute for W

The area formula is the equation for a parabola that opens downward. It has zeros at L=0 and at L=P. The vertex (maximum) is found at the value of L that lies on the line of symmetry, halfway between these zeros. If we call that length M, then we have ...

  M = (0 +P)/2 = P/2

The length of enclosure that maximizes the area is 1/2 the length of the available fence.

The width is ...

  W = (P -P/2)/2 = P/4

The width of the enclosure that maximizes the area is 1/4 the length of the available fence.

Using 100 feet of fence, the dimensions are ...

__

Additional comment

Note that we have solved this in a generic way. The solution given is the general solution to the 3-sided enclosure problem.

This is a special case of the general rectangular enclosure problem which has the solution that the total cost in one direction is equal to the total cost in the orthogonal direction. This rule applies even when costs are different for the different sides or for any partitions that might divide the enclosure.

Here the "cost" is simply the length of the fence. The 50 ft of fence parallel to the barn is equal in length to the 25 +25 ft of fence perpendicular to the barn.

The dimensions that give the maximum area inside the rectangle are x = 50 feet (parallel to the barn wall) and y = 25 feet (perpendicular to the barn wall).

To maximize the area of the rectangular fence, follow these steps:

1. Let's assign variables to the dimensions: let the length of the rectangle parallel to the barn wall be x feet, and the length perpendicular to the barn wall be y feet.

2. We are given that 100 feet of fence will be used for the other three sides. This means the fencing equation is:

x + 2y = 100.

3. Solve for x:  x = 100 - 2y.

4. The area A of the rectangle is given by the product of its dimensions: A = xy.

5. Substitute the expression for x from step 3 into the area formula:  A = (100 - 2y)y.

6. Expand the expression: A = 100y - 2y^2.

7. To maximize the area, we need to find the maximum value of the quadratic function A(y). Since the coefficient of the y^2 term is negative, the graph of A(y) is a downward-opening parabola, which means it has a maximum value.

8. To find the maximum, we'll use the vertex formula for parabolas: y_vertex = -b/(2a), where a = -2 and b = 100. Plugging in these values, we get y_vertex = -100/(2 * -2) = 25.

9. Substitute the value of y_vertex back into the equation for x: x = 100 - 2(25) = 50.

10. So the dimensions that give the maximum area inside the rectangle are x = 50 feet (parallel to the barn wall) and y = 25 feet (perpendicular to the barn wall).

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The graph of the linear equation y = mx + c is a line with m as the slope, and m, and c as the y-intercept. This form of the linear equation is called the slope-intercept form, and the values of m and c are real numbers.

The slope, m, represents the steepness of a line. The slope of the line is also termed a gradient, sometimes. The y-intercept, b, of a line, represents the y-coordinate of the point where the graph of the line intersects the y-axis.

Here, the distance c is called the y-intercept of the given line L.

So, the coordinate of a point where the line L meets the y-axis will be

(0, c). That means line L passes through a fixed point (0, c) with slope m.

We know that, the equation of a line in point-slope form, where (x1, y1) is the point and slope m is:

(y – y1) = m(x – x1)

Here, (x1, y1) = (0, c)

Substituting these values, we get;

y – c = m(x – 0)

y – c = mx

y = mx + c

Therefore, the point (x, y) on the line with slope m and y-intercept c lies on the line if and only if y = mx + c

Note: The value of c can be positive or negative based on the intercept made on the positive or negative side of the y-axis, respectively

Slope Intercept Form x Intercept

We can write the formula for the slope-intercept form of the equation of line L whose slope is m and x-intercept d as:

y = m(x – d)

Here,

m = Slope of the line

d = x-intercept of the line

Sometimes, the slope of a line may be expressed in terms of tangent angle such as:

m = tan θ

The quality control specialist should use a t-distribution for estimating the mean clarity rating of the new batch of glass sheets being produced using a sample of 18 sheets of glass.

The quality control specialist at a plate glass factory must estimate the mean clarity rating of a new batch of glass sheets being produced using a sample of 18 sheets of glass.

Since the actual distribution of this batch is unknown, but preliminary investigations show that a normal approximation is reasonable, the specialist should use a t-distribution.
1. The sample size (n) is 18, which is relatively small.
2. The population standard deviation (σ) is unknown.
In such cases, the t-distribution is more appropriate than the z-distribution, chi-square distribution, or f distribution.

The t-distribution is a statistical distribution that is used when the sample size is small, and the population standard deviation is unknown.
The z-distribution is used when the population standard deviation is known, and the sample size is large enough (typically, n > 30).
The chi-square distribution is used for testing the goodness-of-fit of a distribution or for testing the independence between two categorical variables.
The f distribution is used for comparing the variances of two populations.

It is not suitable for estimating the mean clarity rating in this case.
In conclusion, the quality control specialist should use a t-distribution for estimating the mean clarity rating of the new batch of glass sheets being produced using a sample of 18 sheets of glass.

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Answer:

Step-by-step explanation:

18 tickets cost $10 and 52 tickets cost $12.

The integral of  probability density function [tex]\int_{4}^{\infty}[/tex]f(x) dx represents option b. the probability that a tree has a diameter of at least 4 inches.

Probability density function represented by function f.

Probability density function f for the diameter of trees in a forest is equals to ,

[tex]\int_{4}^{\infty}[/tex]f(x) dx

Because the integral is computing the area under the PDF curve for diameters greater than or equal to 4 inches.

And the area under a PDF curve represents the probability of the random variable in this case, tree diameter falling within that range.

This implies,

Integrating the PDF from 4 to infinity gives the probability of a tree having a diameter greater than or equal to 4 inches.

Therefore, the correct answer to represents the probability density function is Option (b). the probability that a tree has a diameter of at least 4 inches.

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The above question is incomplete , the complete question is :

Let f be the probability density function (PDF) for the diameter of trees in a forest, measured in inches. What does [tex]\int_{4}^{\infty}[/tex] f(x) dx represent?

(a) The standard deviation of the diameter of the trees in the forest.

(b) The probability that a tree has a diameter of at least 4 inches

(c) The probability that a tree has diameter less than 4 inches.

(d) The mean diameter of the trees in the forest.

Answer: 16a^2−24a−7

Step-by-step explanation:

Answer:

Step-by-step explanation:

ER=(5) [A single,1-tuple]. You start with 30 eggs. After selling 5 eggs, cooking 10, and frying 10 eggs 5 eggs remain.

PREMISES

ER=(E-S)-(C+F)

ASSUMPTIONS

Let E=the number of eggs at the start (30)

Let S=the number of eggs that were sold (5)

Let C=the number of eggs that were “cooked” i.e., hard-boiled, poached, and so forth (10)

Let F=the number of eggs that were fried (10)

Let ER=the number of eggs that remain having not been sold, cooked, or fried

CALCULATIONS

ER=(E-S)-(10+10)

ER=(30–5)-(20)

ER=25–20

ER=

5 eggs

PROOF

If ER=5, then the mathematic sentence ER=(E-S)-(C+F) returns

ER=(30–5)-(C+F)

5=25-(10+10)

5=25–20 and

5=5 verifies the result ER=5 of the sentence

Answer:

y = -x² - 2x + 15

Step-by-step explanation:

We can see that upto the x-value of -1, the y-value increases, and after -1, the y-value decreases. This tells us both that (-1, 16) is the vertex and that the function opens downwards.

The typical vertex form for quadratic equations is:

y= a(x-h)² + k where (h,k) is the vertex.

Replace the vertex (-1,16) for (h,k)

y = a (x+1)² +16

To find a, replace any value from the table. Let's use (3,0).

0 = a (3+1)² +16

0 = a (4)² + 16

0 = 16a + 16

-16 = 16a

a = -1

Now, insert that a into our  equation...

y = -13/16 (x+1)² +16

Then simplify:

y = -1 (x² +2x +1) + 16

y = -x² -2x -1 +16

We get our answer:

y = -x² - 2x + 15

The value of a in the given parabola is a = 4/5.

A quadratic function's graph is a parabola. A parabola, according to Pascal, is a circle's projection. Galileo described the parabolic route that projectiles take when they fall under the influence of uniform gravity. Several bodily movements have a curvilinear course that has the form of a parabola. In mathematics, a parabola is any planar curve that is mirror-symmetrical and typically resembles a U shape.

We know that the parabola passes through (-3, 0) and (5, 0), so we can write:

0 = a(-3)² + b(-3) + c (equation 1)

0 = a(5)² + b(5) + c (equation 2)

We also know that the parabola passes through (1, -32), so we can write:

-32 = a(1)² + b(1) + c (equation 3)

Equating the equation 1 and 2 we have:

9a - 3b + c = 25a + 5b + c

16a + 2b = 0 (equation 4)

Now, equation i can be written as:

c = - 9a + 3b

Substituting in equation 3 we have:

-32 = a + b - 9a + 3b

-32 = -8a + 4b

-8 = -2a + b (equation 5)

b = -8 + 2a

Substitute the value of b in equation 4:

16a + 2(-8 + 2a) = 0

16a - 16 + 4a = =

20a = 16

a = 16/20 = 4/5

Hence, the value of a in the given parabola is a = 4/5.

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Answer:

24 = 31.4n + (–8.4)

Step-by-step explanation:

24=31.4n-8.4

Answer:

d.  x² + 5x - 104 = 0

Step-by-step explanation:

(x+5)x = 104

x² + 5x = 104

x² + 5x - 104 = 0

Rounding to four decimal places, the probability is (a) 0.3273 (b) 0.8423, and (c) 0.0446.

We can model this problem using a binomial distribution, where the probability of success (having the disease) is p = 0.84, and the number of trials (people tested) is n = 10.

(a) To find the probability that all 10 people have the disease, we can calculate the:

P(X = 10) = (10 choose 10) * (0.84)^10 * (1-0.84)^(10-10) = 0.3273

Rounding to four decimal places, the probability is 0.3273.

(b) To find the probability that at least 8 people have the disease, we can calculate the:

P(X ≥ 8) = P(X = 8) + P(X = 9) + P(X = 10)

We can find each term using the binomial probability formula and then add them up:

P(X = 8) = (10 choose 8) * (0.84)^8 * (1-0.84)^(10-8) = 0.2018

P(X = 9) = (10 choose 9) * (0.84)^9 * (1-0.84)^(10-9) = 0.3132

P(X = 10) = (10 choose 10) * (0.84)^10 * (1-0.84)^(10-10) = 0.3273

P(X ≥ 8) = 0.2018 + 0.3132 + 0.3273 = 0.8423

Rounding to four decimal places, the probability is 0.8423.

(c) To find the probability that at most 4 people have the disease, we can calculate:

[tex]P(X ≤ 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

We can find each term using the binomial probability formula and then add them up:

P(X = 0) = (10 choose 0) * (0.84)^0 * (1-0.84)^(10-0) = 0.000004

P(X = 1) = (10 choose 1) * (0.84)^1 * (1-0.84)^(10-1) = 0.0001

P(X = 2) = (10 choose 2) * (0.84)^2 * (1-0.84)^(10-2) = 0.0012

P(X = 3) = (10 choose 3) * (0.84)^3 * (1-0.84)^(10-3) = 0.0084

P(X = 4) = (10 choose 4) * (0.84)^4 * (1-0.84)^(10-4) = 0.0348

P(X ≤ 4) = 0.000004 + 0.0001 + 0.0012 + 0.0084 + 0.0348 = 0.0446

Rounding to four decimal places, the probability is 0.0446.

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Zach's hourly wage is determined by taking the basic rate of $16.00 and adding $2.00 for each extra student beyond the first one in the calculation is P = $16.00 + ($2.00 x (n - 1))

That's an interesting situation! It seems like Zach's hourly pay for tutoring is not fixed, but rather increases with each additional student he tutors. Here's how his pay works:

If Zach is tutoring just one student, he gets paid $16.00 per hour.

If a second student joins the tutoring session, Zach's hourly pay increases to $18.00 per hour ($16.00 for the first student plus $2.00 for the second).

If a third student joins, Zach's hourly pay increases to $20.00 per hour ($16.00 for the first student plus $2.00 for the second and third students).

And so on, for each additional student who joins the tutoring session.

So Zach's hourly pay is not a fixed rate, but rather a function of the number of students he is tutoring.

If we let P be Zach's hourly pay and n be the number of students he is tutoring, we can express Zach's pay as:

P = $16.00 + ($2.00 x (n - 1))

This formula calculates Zach's hourly pay by taking the base rate of $16.00 and adding $2.00 for each additional student beyond the first one.

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Question:-  Zach got hired to tutor math. He gets paid $16.00 per hour for tutoring one student. Each student that joins the tutoring session increases his hourly pay by $2.00.

Answer:

Therefore, the surface area of the composite figure is 368 cm².

Step-by-step explanation:

To find the surface area of the composite figure, we need to find the areas of each individual face and add them together.

The triangular prism has two triangular faces and three rectangular faces.

The area of each triangular face is 1/2(base × height).

Area of each triangular face = 1/2(10 × 5) = 25 cm²

The area of each rectangular face is length × width.

Area of the rectangular face with dimensions 5 cm by 10 cm = 5 × 10 = 50 cm²

Area of the rectangular face with dimensions 5 cm by 10 cm = 5 × 10 = 50 cm²

Area of the rectangular face with dimensions 10 cm by 8 cm = 10 × 8 = 80 cm²

Total area of the triangular prism = 2 × 25 + 3 × 50 + 80 = 280 cm²

The rectangular prism has two rectangular faces and four square faces.

The area of each rectangular face is length × width.

Area of the rectangular face with dimensions 4 cm by 5 cm = 4 × 5 = 20 cm²

Area of the rectangular face with dimensions 4 cm by 5 cm = 4 × 5 = 20 cm²

The area of each square face is side × side.

Area of each square face with side length 4 cm = 4 × 4 = 16 cm²

Total area of the rectangular prism = 2 × 20 + 4 × 16 = 88 cm²

The total surface area of the composite figure is the sum of the surface areas of the triangular prism and the rectangular prism.

Total surface area = surface area of triangular prism + surface area of rectangular prism

= 280 cm² + 88 cm²

= 368 cm²

A regression model can be created to predict selling price based on square footage and number of bedrooms using available data. The model equation includes coefficients that can be estimated to predict the selling price of a house. The number of bedrooms is a significant predictor of selling price and should be included in the model.

To develop the regression model to predict selling price based on the square footage and number of bedrooms, the following steps can be taken:

Collect data on the selling price, square footage, and number of bedrooms for a sample of houses.

Create a scatter plot to visually inspect the relationship between selling price and square footage, and between selling price and number of bedrooms.

Use regression analysis to create a model that predicts selling price based on square footage and number of bedrooms. The model equation will be:

Selling price = b0 + b1(Square footage) + b2(Number of bedrooms)

where b0, b1, and b2 are coefficients to be estimated from the data.

To predict the selling price of a 2,000-square-foot house with three bedrooms, substitute the values into the model equation and solve for selling price:

Selling price = b0 + b1(2000) + b2(3)

Comparing the performance of this model with the models in problem 4-22. The number of bedrooms should be included in the model because it is a significant predictor of selling price. However, further analysis could be conducted to determine if other variables could improve the model's predictive power.

Overall, this regression model can provide a useful estimate of the selling price of a house based on its square footage and number of bedrooms.

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Answer:

Step-by-step explanation:

Because the lines are perpendicular the slopes will be negtive

reciprocals of each other.  Thus slope of 3/8 becomes -8/3.

Using point slope formula:   y - y1 = m(x - x1)

Substitute the point given with the new slope and solve.

y - 5 = -8/3(x - 4)

y - 5 = -8/3x - - 32/3

y - 5 = -8/3x + 32/3

y - 5 + 5 = -8/3x + 32/3 + 5

y = -8/3x + 47/3

or

y = -8/3x + 15 2/3

The percentage of the people between the ages of 35 and 54 that prefer baseball is 17.14%.

A preferences means the certain characteristics that any person wants to have in a good/service to make it preferable to him.

In the table, the total number of people between the ages of 35 and 54 is 35. Out of the 35 people, the people that prefer baseball is known to be 6.

Now, the percentage between the ages of 35 and 54 that prefer baseball will be:

= Baseball preference / Total number of people aged 35 and 54

= 6/35

= 0.17142857142

= 17.14%

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The angle of depression of the boat from the top of the cliff = 51.78 degrees

To calculate the angle of depression of the boat from the top of the cliff, we need to draw a diagram to visualize the situation.

In this instance, we can draw a right-angled triangle with one side representing the cliff's height (94m) and the other representing the horizontal distance between the boat and the cliff's foot. (74m). This triangle's hypotenuse depicts the line of sight from the top of the cliff to the boat.

The angle of depression is defined as the angle formed by the horizontal line and the line of sight from the cliff's summit to the boat.

We can use the tan function to determine this angle.

tan(angle of depression) = (height of cliff) / (horizontal distance from the boat to the foot of the cliff)

tan(∅) = (h/x)

tan(angle of depression) = 94 / 74

angle of depression = [tex]tanx^{-1} (94/74)[/tex]

angle of depression = 51.788974574 degrees

Therefore, the angle of depression of the boat from the top of the cliff is approximately 51.78 degrees.

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The angle of depression of the boat from the top of the cliff is approximately 50.67 degrees.

To calculate the angle of depression of the boat from the top of the cliff, we can use trigonometry. The angle of depression is the angle formed between the horizontal line (parallel to the ground) and the line of sight from the top of the cliff to the boat.

In this scenario, we have a right triangle formed by the cliff, the boat, and the horizontal line connecting them.

Let's denote the angle of depression as θ.

Using trigonometric ratios, we can use the tangent function to calculate the angle of depression:

tan(θ) = opposite/adjacent

In this case, the opposite side is the height of the cliff (94 meters) and the adjacent side is the horizontal distance from the foot of the cliff to the boat (74 meters).

tan(θ) = 94/74

To find θ, we can take the inverse tangent (arctan) of both sides:

θ = arctan(94/74)

Using a calculator or trigonometric table, we can find that θ is approximately 50.67 degrees.

Therefore, the angle of depression of the boat from the top of the cliff is approximately 50.67 degrees.

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Required factor form is 2x³(3x + 4).

What is GCF?

GCF stands for Greatest Common Factor, also known as the Greatest Common Divisor (GCD). In mathematics, the GCF of two or more numbers is the largest positive integer that divides each of the numbers without a remainder. For example, the GCF of 12 and 18 is 6 because 6 is the largest integer that divides both 12 and 18 without a remainder. The concept of GCF is important in many areas of mathematics, including algebra, number theory, and calculus, and is used in various problem-solving applications.

Given form is 6x⁴+8x³.

Here is two term 6x⁴ and 8x³.

By factorisation,

6x⁴ = 2×3×x⁴ and 8x³ = 2×2×2×x³

The greatest common factor (GCF) of 6x⁴ and 8x³ is 2x³.

To factor it out, we can divide each term by 2x³:

Now,

6x⁴ ÷ 2x³ = 3x

8x³ ÷ 2x³ = 4

So, we can write:

6x⁴ + 8x³ = 2x³(3x + 4)

Therefore, the factored form of 6x⁴ + 8x³ is 2x³(3x + 4).

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We may assume that out of the 300 graduating students, 120 plan to go

to college, 75 want to work, 60 are unsure, and 45 want to join the

military. It's critical to remember that these are estimates based on a poll

of 20 peers, and actual figures may vary slightly.

Based on the data from the survey of 20 classmates, we can make

inferences about the plans of the entire graduating class of 300 students

using proportions.

Let's fill in the table based on the given information:

Plan Number of classmates Proportion

College 8 8/20 = 0.4

Work 5 5/20 = 0.25

Undecided 4 4/20 = 0.2

Military 3 3/20 = 0.15

To find the number of students in each category out of 300, we can

multiply the proportion by 300:

College: 0.4 x 300 = 120 students

Work: 0.25 x 300 = 75 students

Undecided: 0.2 x 300 = 60 students

Military: 0.15 x 300 = 45 students

Therefore, we can infer that out of the 300 students in the graduating

class, approximately 120 plan to attend college, 75 plan to work, 60 are

undecided, and 45 plan to enter the military. It's important to note that

these are estimates based on the survey of 20 classmates, and there

may be some variability in the actual numbers.

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The interquartile range (IQR) of the data is 70 and the third and the first quartile of the data is (90, 20).

The second and third quartiles, or the middle half of your data collection, are contained in the interquartile range (IQR). The interquartile range provides the range of the middle half of a data set, whereas the range provides the spread of the entire data collection.

The given plot shows the number of days on the market for single-family homes in the city.

The figure shows the first quartile = 20 and the third quartile 90

Therefore the interquartile range of the data is equal to the difference between the third quartile and the first quartile i.

The interquartile range = Q3 - Q1

                                       = 90 - 20

                                       = 70

The third and first quartiles of the data are (90, 20).

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Charlie must earn at least 125 tickets in the last game tο win the big prize.

A linear inequality is a mathematical statement that compares twο expressiοns using the symbοls < (less than), > (greater than), ≤ (less than οr equal tο), οr ≥ (greater than οr equal tο), and where bοth expressiοns are linear functiοns οf the same variables. It describes range οf values that the variables can take while satisfying the inequality.

Let x be the number οf tickets that Charlie must earn in the last game tο win the big prize.

The tοtal number οf tickets Charlie has won so far is the sum οf the tickets frοm all the games he has played:

95 + 115 + 90 + 75 = 375.

Tο win the big prize, Charlie must earn at least 500 tickets in tοtal.

Therefοre, we can write the fοllοwing inequality tο sοlve fοr the pοssible number οf tickets, x:

375 + x ≥ 500

Simplifying the inequality:

x ≥ 500 - 375

x ≥ 125

Therefore, Charlie must earn at least 125 tickets in the last game to win the big prize.

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Answer:

its better to buy the cylinder because it can hold more

Step-by-step explanation:

Without specific dimensions for the containers, we cannot provide exact values for volume and unit rate.

To determine which popcorn container has a better unit rate and holds more popcorn, we first need to find the volume of both containers.

Assuming the given dimensions are radius and height, let's say the cone has a radius of 'r1' and a height of 'h1,' and the cylinder has a radius of 'r2' and a height of 'h2.'

The volume of a cone (V1) is given by the formula: V1 = (1/3)πr1²h1
The volume of a cylinder (V2) is given by the formula: V2 = πr2²h2

Next, we need to find the unit rate of both containers. Divide the volume of each container by its price.

Unit rate of cone: UR1 = V1 / $6.75
Unit rate of cylinder: UR2 = V2 / $6.25

To determine which container holds the most popcorn, compare V1 and V2. The container with the larger volume holds more popcorn.

To determine which container has a better unit rate, compare UR1 and UR2. The container with the higher unit rate is a better buy per $1.

However, you can plug in the given dimensions for your problem and follow these steps to find your answer.

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Answer:

Point T is on a line segment SU. Given SU=4x+1, TU=3x, and ST=3x-1, determine the numerical length of SU

Step-by-step explanation:

By the segment addition rule, length of ST + length TU equals length of SU so 3x -1 + 3x = 4x + 1 6x - 1 = 4x + 1 2x = 2 x = 1 substituting value of x back into formula for length of SU: 4 (1) + 1 = 5

The set of points and lines when named are listed below

Using the figure as a guide, we have the following:

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