A mass of 15 kg is resting on a horizontal, frictionless surface. Force 1 of 206 N is applied to it at some angle above the horizontal, force 2 has a magnitude of 144 N and is applied vertically downward, force 3 has a magnitude of 5 N and is applied vertically upwards, and force 4 has a magnitude of 42 N and is applied in the -x direction to the object. When these forces are applied to the object, the object is moving at 20 m/s in the x direction in a time of 3 seconds. What is the normal force acting on the mass in Newtons
Answers
Answer:
N = 136.77 N
Explanation:
This is an exercise in Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis. In the attachment we can see the applied forces.
Let's use trigonometry to decompose the force F1
cos θ = F₁ₓ / F₁
sin θ = F_{1y} / F₁
F₁ₓ = F₁ cos θ
F_{1y} = F₁ sin θ
now let's apply Newton's second law to each axis
X axis
F₁ₓ - F4 = m a
Y axis
N + F3 + F_{1y} -F₂ -W = 0
the acceleration can be calculated with kinematics
v = v₀ + a t
since the object starts from rest, the initial velocity is zero v₀ = 0
a = v / t
a = 20/3
a = 6.667 m / s²
we substitute in the equation
F₁ₓ = F₄ + m a
F₁ₓ = 42 + 15 6,667
F₁ₓ = 142 N
F₁ cos θ = 142
cos θ = 142/206 = 0.6893
θ = cos⁻¹ 0.6893
θ = 46.42º
now let's work the y axis
N = W + F₂ - F₃ - F_{1y}
N = 15 9.8 + 144 -5 - 206 sin 46.42
N = 286 - 149.23
N = 136.77 N
Related Questions
David drove the first 6 hours of his journey at 65km/hr and the last 3 hours of his journey at 80km/hour. How far is the whole journey in km?
Answers
630 kilometers for the whole journey
12) If a man weighs 900 N-on the Earth, what would he weigh on Jupiter, where the acceleration due to gravity is 25.9 m/s?
Answers
Answer:
Force=Mass*acceleration
on earth, acceleration=9.81 m/s^2
900 N=Mass*9.81 m/s^2
Mass=91.74 Kg
F=Mass*acceleration(Jupiter)
F=91.74Kg*25.9m/s
F=2376.066 N on Jupiter
Plz mark me as brainliest if u found it helpful
What is the amount of thermal energy that can be stored in an object depends on?
Answers
Hope this helps
a spring scale is constructed so that each 0.10-n increment is separated by 0.50 cm. what spring constant is necessary for the scale to be accurate?
Answers
Answer:
5.00
Explanation:
1. A tourist accidentally drops a camera from a 40.0 m high bridge and it falls for 2.85 seconds. If g = 9.81 m/s2 and air resistance are disregarded, what is the speed of the camera as it hits the water?
Answers
Answer:
28 m/s
Explanation:
v(final)^2=v(initial)^2+2a(delta y)
=sqrt(2*-9.8 m/s^2*-40)
28 m/s
The speed of the camera with which it hits the water is 27.93 meters per second.
What is the speed?
The speed of an object is the rate of change of position of an object in any of the directions. Speed can be measured as the ratio of distance covered by the object to the total time taken in which the distance was covered by the object. Speed is a scalar quantity because it has only magnitude and no direction.
v = gt
where, v is the velocity,
g is the acceleration due to gravity,
and t is the time taken by the object
v = (9.8 m/s²) (2.85s)
v = 27.93 m/s
Therefore, the speed of the camera as it hits the water is 27.93 meters per second.
Learn more about Speed here:
https://brainly.com/question/28224010
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If a 3.5 kg object is accelerating at 0.80 /s^2, the net force F causing this motion is ____ N.
A) 2.2
B)2.8
C)3.4
D)4.0
Answers
Answer:
The answer is option BExplanation:
To find the force acting on an object we use the formula
force = mass × accelerationFrom the question
mass = 3.5 kg
acceleration = 0.80 m/s²
We have
Force = 3.5 × 0.8
We have the final answer as
2.8 NHope this helps you
The displacement of an object moving 330 km North for 2 hours and an additional 220 km North for 5 hours is?
Answers
Answer:
Usbe
Explanation:
classify the planets as inner planets of outer planets explain your answer
Answers
Answer: Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.
Explanation:
Planet C is composed if the gases hydrogen and helium. It has a high mass and is much farther from 1 AU from the sun. These properties are consistent with the outer planets. So, planet C is an outer (gas giant) planet.
Answer:
Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.
Explanation:
2. What is the normal force acting a 800-kg car if there are two 55-kg people sitting inside the car?
Answers
Normal force = 910 x 9.8 = ... Newton
A sound wave in a steel rail has a frequency of 620 hz and a wavelength of 10.5m. What is the speed of sound in steel?
Answers
speed = 620 x 10.5 = ..... m/s
6. What velocity vector will move you 200 miles east in 4 hours travelingat a constant speed?
Answers
Answer:
50 mph east
Explanation:
which theory says dreaming is an unimportant by-product of neural firing during sleep
Answers
Answer:activation-synthesis
Explanation:
A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. It has an electrical capacity of 3000.0 μF and is charged to a potential difference of 60.0 V. Calculate the amount of energy stored in the capacitor. Tries 0/20 Calculate the charge on this capacitor when the electrical energy stored in the capacitor is 6.53 J. Tries 0/20 If the two plates of the capacitor have their separation increased by a factor of 5 while the charge on the plates remains constant, by what factor is the energy stored in the capacitor increased?
Answers
Answer:
1 = 5.4 J
2 = 0.1979 C
3 = 5
Explanation:
Energy in a capacitor, E is
E = 1/2 * C * V²
E = 1/2 * 3000*10^-6 * 60²
E = 1/2 * 3000*10^-6 * 3600
E = 1/2 * 10.8
E = 5.4 J
E = Q²/2C = 6.53 J
E * 2C = Q²
Q² = 6.53 * 2 * 3000*10^-6
Q² = 13.06 * 3000*10^-6
Q² = 0.03918
Q = √0.03918
Q = 0.1979 C
The Capacitor, C is inversely proportional to the distance of separation, D. Thus, if D is increased by 5 to be 5D, then C would be C/5. And therefore, our energy stored in the capacitor is increased by a factor of 5.
Three sticks are arranged in such a way that they form a right triangle. The
lengths of the three sticks are 0.47 m, 0.62 m, and 0.78 m. What would the
three angles of this triangle? *
Answers
Answer:
one right angel = 90 degrees
and two acute angels?
Explanation:
Which of the following is true as a ball that was thrown straight up into the air is traveling up?
A. The acceleration is upward until it stops and the acceleration becomes downward. The object is also slowing down as it rises.
B. The acceleration is downward as the object moves up. This causes the object to slow down until it stops and then speed up as it falls down.
Answers
Answer:
b
Explanation:
when a ball falls from the sky, it falls down fast due to no friction.
This chart shows Dan's budget:
Did Dan stay on budget? Why or why not?
Amount budgeted
tem
nome
Food
Rent
Debonary spending
Income
$100
S500
$100
5750
Amount spent
55
S90
3500
5140
Yes, Dan spent as much as he earned.
No, Dan should move to a new apartment
O Yes, Dan uses his savings to cover extra expense
No, Dan should reduce his discretionary spending,
Answers
Answer
No dan should reduce his discretionary apendings.
Explanation:
• An evacuated long tube contains a coin and a feather. If both objects fall together starting from the top of the tube, it is expected that:
(a) the coin will reach the bottom first.
(b) the feather will reach the bottom first.
(c) both objects will reach the bottom at the same instant.
• If this experiment is repeated at a place 2000 kilometers above the sea-level, the acceleration due to gravity gexp is expected to :
(a) increase. (b) decrease. (c) remain constant.
Answers
Answer:
c-) both objects will reach the bottom at the same instant.
(b) decrease.
Explanation:
Although the feather is lighter than the coin, the tube where the experiment is performed is evacuated. Therefore there is no air that prevents the feather from falling freely with the same acceleration and speed as the coin.
In fact in the equations of kinematics proposed by Newton, the mass of the bodies is not taken into account, as we can see in the following equation:
[tex]v_{f}= v_{i} +g*t[/tex]
where:
Vf = final velocity [m/s]
Vi = initial velocity [m/s]
g = gravity acceleration [m/s^2]
t = time [s]
Therefore the answer is C.
Gravitational pull is a function of height, as the height of the body increases, the force of gravity decreases.
PLEASE PROVIDE EXPLANATION FOR D AND E
THANK YOU!
Answers
Answer:
d) 14.1 m
e) 8.57 m/s
Explanation:
(a) There are three forces on the ball:
Normal force Fn pushing up,
Weight force Fg pulling down,
Kinetic friction Fk pushing left (resisting motion).
FBD is the correct free body diagram.
(b) Sum of forces in the y direction:
∑F = ma
Fn − Fg = 0
Fn = Fg
Sum of forces in the x direction:
∑F = ma
-Fk = ma
-Fn μk = ma
-mg μk = ma
a = -g μk
a = -(10 m/s²) (0.25)
a = -2.5 m/s²
(c) Sum of torques about the ball's center:
∑τ = Iα
Fk r = ⅖ mr² α
mg μk r = ⅖ mr² α
g μk = ⅖ r α
α = 5g μk / (2r)
α = 5 (10 m/s²) (0.25) / (2 × 0.2 m)
α = 31.25 rad/s²
(d) The velocity and angular velocity at time t is:
v = at + v₀
v = -2.5t + 12.0
ω = αt + ω₀
ω = 31.25t + 0
When the ball begins to roll without slipping, v = ωr.
-2.5t + 12.0 = (31.25t) (0.2)
-2.5t + 12.0 = 6.25t
12.0 = 8.75t
t = 1.37
The distance the ball moves is:
Δx = v₀ t + ½ at²
Δx = (12) (1.37) + ½ (-2.5) (1.37)²
Δx = 14.1 m
(e) v = at + v₀
v = (-2.5 m/s²) (1.37 s) + 12.0 m/s
v = 8.57 m/s
Answer:
a
Explanation:
on egde 2020
What is the average speed of the whole trip?
Answers
Answer:
65 miles per hour.
Explanation:
Answer:
Average speed of entire trip is : 3.67 m/s
Explanation:
Speed is calculated as the distance covered divided by time
Average speed will be the :speed before stop add to speed after stopping then divide by 2
Speed before stop = 200/ 60 = 3.33 m/s
Speed after stop = 400/100= 4m/s
Average speed = (3.33+4)/2 = 7.33/2 = 3.67 m/s
Activity_Mass_Balance_Recycle
Sea water must be desalinated by reverse osmosis. For a feed rate of 1000 lb/h sea water containing 3.1% salt (by weight) is desalinated water with only 500 ppm salt and the brine tailings containing 5.25% salt. Part of the brine tailings is recycled and the inlet stream in the reverse osmosis cell contains 4.0% salt. Determine:
a) A brine removal taxon (ṁ3);
b) The production rate of desalinated water (ṁ2);
c) The rate of brine that is recycled (ṁR).
Answers:
ṁ1 = 1720 lb / h
ṁ2 = 409.37 lb / h
ṁ3 = 590.63 lb / h
ṁR = 720 lb / h
Answers
Answer:
m₁ = 1720
m₂ = 413.46
m₃ = 586.54
mr = 720
Explanation:
Draw a diagram. Sea water (1000 lb/h, 3.1% salt) is mixed with the recycled brine (mr, 5.25% salt) to create the inlet stream (m₁, 4.0% salt). This inlet stream is fed into the osmosis cell. The osmosis cell produces desalinated water (m₂, 500 ppm) and brine tailings. Part of the tailings is recycled (mr, 5.25% salt), and the rest is removed (m₃, 5.25%).
The mass of water is conserved, so:
1000 + mr = m₁
m₁ = mr + m₂ + m₃
The mass of salt is conserved, so:
0.031 (1000) + 0.0525 mr = 0.040 m₁
0.040 m₁ = 0.0525 mr + 0.0005 m₂ + 0.0525 m₃
Four unknown variables, and four equations. We can use the first and third to find mr and m₁.
0.031 (1000) + 0.0525 mr = 0.040 (1000 + mr)
31 + 0.0525 mr = 40 + 0.040 mr
0.0125 mr = 9
mr = 720
m₁ = 1720
Now we can use these values and the second and fourth equations to solve for the remaining variables.
1720 = 720 + m₂ + m₃
0.040 (1720) = 0.0525 (720) + 0.0005 m₂ + 0.0525 m₃
1000 = m₂ + m₃
68.8 = 37.8 + 0.0005 m₂ + 0.0525 m₃
68.8 = 37.8 + 0.0005 m₂ + 0.0525 (1000 − m₂)
68.8 = 37.8 + 0.0005 m₂ + 52.5 − 0.0525 m₂
0.052 m₂ = 21.5
m₂ = 413.46
m₃ = 586.54
An African Swallow can travel at an average velocity of 11 m/s. How far can an African Swallow carry a coconut in 120 seconds?
Answers
Answer:
The distance will be x = 1320 [m]
Explanation:
To solve this problem we must use the expression of physics that relates space to time, which is defined as speed.
v = Speed = 11 [m/s]
t = time = 120 [s]
x = distance [m]
v = x/t
x = v*t
x = 11*120
x = 1320 [m]
A car travels 45 km due north and 70 km west. What is the car's displacement?
6 points
24.7 km northeast
83.2 km northwest
76.5 km northwest
115 km north
Answers
Answer:
A
Explanation:
What is the speed of a car that travels 0.200 km in 95 seconds? State your answer in meters per second.
Answers
Answer:
2.10 meters per secondExplanation:
speed (velocity) = distance / time
= 0.2 km (1000 m/km)
95 secs.
= 2.10 meters per second
Your shopping cart has a mass of 65 kilograms.In order to accelerate the shopping cart down an aisle at 0.30 m/s^2, what Force would you need to use or apply to the cart assuming the coefficient of friction between the cart and the floor is 0.01?
Answers
Answer:
25.88 N
Explanation:
Mass of the shopping cart,[tex]m=65 kg[/tex]
The coefficient of friction between the cart and the floor, [tex]\mu= 0.01[/tex]
Let, F be the required force to accelerate the cart at [tex]a=0.30 m/s^2[/tex].
Gravitational force, mg, acts downward which is being balanced by the normal reaction, N, on the cart by the floor.
As the motion of the cart in the vertical direction is zero. So, using the static equilibrium condition will be zero.
From free body diagram (FBD):
[tex]N-mg=0[/tex]
[tex]\Rightarrow N=mg.[/tex]
the net force action in this direction The frictional force, f, acts in the direction to opposes the motion of the cart as shown.
[tex]f=\muN=\mu mg[/tex]
Now, apply the dynamic equilibrium condition in the horizontal direction, i.e. net force acting on the body equals the rate of change of momentum of the body. From the FBD of the cart, we have
[tex]F-f-ma=0[/tex]
[tex]\Rightarrow F=f+ma[/tex]
[tex]\Rightarrow F=\mu mg+ma[/tex]
[tex]\Rightarrow F=m(\mu g +a)[/tex]
[tex]\Rightarrow F=65(0.01\times 9.81 + 0.3)[/tex]
[tex]\Rightarrow F=25.88 N.[/tex]
Hence, 25.88 N force required to accelerate the body with 0.03 [tex]m/s^2[/tex] .
A force of 150. N is exerted 22° north of east. Find the northward and eastward components of this force.
PLEASE HELP ASAP
Answers
Answer: northward would be 139 N
Explanation:
Amass oscillates in simple harmonic motion with amplitude A , if the mas is halved , but the amplitude is not changed , what will happen to the total mechanical energy of the system
A- It will increase
B-it will decrease
c-It will stay at the same
D-None of these
Answers
How much work does an athlete do if she
raises a 5N kettle bell 2 m off the ground?
Answers
Answer:
The answer is 10 NExplanation:
To find the work done by an object given the distance covered by the object and it's force we use the formula
work done = force × distanceFrom the question
force = 5 N
distance = 2 m
We have
work done = 5 × 2
We have the final answer as
10 NHope this helps you
a satellite is revolving around the sun in a circular orbit with uniform velocity v. if the gravitational force suddenly disappears the velocity of the satellite will be?
Answers
Answer:
when gravitational force suddenly disappears, then only centrifugal force will be acting and velocity is tangential to the orbit and hence, the satellite will fly off tangentially with same velocity v.
This is the path which one body follows around another body in space.
Answers
Answer:
Pls ezplain your question more
Explanation:
Answer:
orbit is the answer
Light refracts when traveling from air into glass because light
O A Travels at the same speed in air and in glass
B Frequency is greater in air than in glass
OC Frequency is greater in glass than in air
D Travels slower in glass than in air
Answers
Answer:
the last one
Explanation:
ii took the quiz and it was right... i think