A probe orbiting Venus exerts a gravitational force of 2. 58 × 103 N on Venus. Venus has a mass of 4. 87 × 1024 kg. The mass of the probe is 655 kilograms. The gravitational constant is 6. 67 × 10-11 N*m2/kg2. To three significant digits, the probe is × 106 m from the center of Venus.

Answers

Answer 1

Answer:

9.08

Explanation:

To solve for the distance between the probe and  the center of Venus, use the formula:

[tex]\mathrm{F = \frac{G\: m1 \:m2}{r^2}}[/tex]

 

Plugin the values:

G =

[tex]6.67\times10^{-11} \mathrm{\frac{m3}{kg\: s2}}[/tex]

[tex]\mathrm{F} =2.58 \times 10^3\mathrm{N}[/tex]

[tex]\mathrm{m1 = 4.87 \times 10^{24}\:kg}[/tex]

[tex]\mathrm{m2 = 655\: kg}[/tex]

Hence:

[tex]\mathrm{F = \frac{G\: m1 \:m2}{r^2}}[/tex]

[tex]2.58 \times 10^{23} = 6.67 \times 10^{-11} (4.87 \times 10^{24})[/tex]

[tex]\frac{(655)}{r^2}[/tex]

[tex]\mathrm{r = 9.08 \times 10^6 \:km}[/tex]


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