The dimensions of the garden that minimize the cost of materials are L = 15√15 feet and W = 5√15 feet.
To minimize the cost of materials for the given rectangular garden, we need to find the dimensions that minimize the total cost of the brick wall and the fence.
Let's assume the length of the garden is L and the width is W. Then, the area of the garden is given by LW = 75. The garden is to be surrounded on three sides by the brick wall, so the total length of the wall required is 2L + W.
The cost of the brick wall is $10 per foot, so the cost of the wall is 10(2L + W). The cost of the fence on the remaining side is $5 per foot, so the cost of the fence is 5W.
Hence, the total cost of materials C is given by:
C = 10(2L + W) + 5W
Simplifying this equation, we get:
C = 20L + 15W
Using the area formula LW = 75, we can solve for one of the variables in terms of the other. For example, we can solve for W as follows:
W = 75/L
Substituting this into the equation for C, we get:
C = 20L + 15(75/L)
To minimize C, we can take the derivative of C with respect to L, set it equal to zero, and solve for L:
dC/dL = 20 - 1125/L^2 = 0
Solving for L, we get:
L = 15√15
Substituting this value of L back into the equation for W, we get:
W = 5√15
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that the random variable x is the score assigned by the first inspector and the random variable y is the score assigned by the second inspector, and they have a joint probability mass function given below. 1 y 2 3 4 x 1234 0.09 0.03 0.01 0.01 0.02 0.15 0.03 0.01 0.01 0.01 0.24 0.04 0.00 0.01 0.02 0.32 (a) what is the probability that both inspectors assign the same safety score? (b) what is the probability that the second inspector assigns a higher safety score than the first inspector? (c) what are the marginal probability mass function, expectation, and variance of the score assigned by the first inspector? (d) what are the marginal probability mass function, expectation, and variance of the score assigned by the second inspector? (e) are the scores assigned by the two inspectors independent of each other? (f) what are the covariance of the scores assigned by the two inspectors?
(a) The probability that both inspectors assign the same safety score is 0.80.
(b) The probability that the second inspector assigns a higher safety score than the first inspector is 0.11.
(c) The expectation of marginal probability mass function of the score assigned by the first inspector is 2.83 and variance is 0.83.
(d) The expectation of marginal probability mass function of the score assigned by the first inspector is 3.00 and variance is 0.77.
(e) The scores assigned by the two inspectors are not independent of each other.
(f) The covariance of the scores assigned by the two inspectors is -0.0148.
(a) The probability that both inspectors assign the same safety score is the sum of the joint probabilities where X and Y take the same value:
P(X = Y) = P(1,1) + P(2,2) + P(3,3) + P(4,4) = 0.09 + 0.15 + 0.24 + 0.32 = 0.80
(b) The probability that the second inspector assigns a higher safety score than the first inspector is given by:
P(Y > X) = P(2,1) + P(3,1) + P(4,1) + P(3,2) + P(4,2) + P(4,3) = 0.03 + 0.01 + 0.01 + 0.03 + 0.01 + 0.02 = 0.11
(c) The marginal probability mass function of the score assigned by the first inspector is obtained by summing the joint probabilities over all values of Y:
P(X = 1) = 0.09 + 0.02 + 0.01 + 0.00 = 0.12
P(X = 2) = 0.03 + 0.15 + 0.01 + 0.01 = 0.20
P(X = 3) = 0.01 + 0.03 + 0.24 + 0.02 = 0.30
P(X = 4) = 0.01 + 0.01 + 0.04 + 0.32 = 0.38
The expectation of X is given by:
E(X) = 10.12 + 20.20 + 30.30 + 40.38 = 2.83
The variance of X is given by:
Var(X) = E(X^2) - [E(X)]^2
= (1^20.12 + 2^20.20 + 3^20.30 + 4^20.38) - (2.83)^2
= 0.83
(d) The marginal probability mass function of the score assigned by the second inspector is obtained by summing the joint probabilities over all values of X:
P(Y = 1) = 0.09 + 0.03 + 0.01 + 0.00 = 0.13
P(Y = 2) = 0.02 + 0.15 + 0.01 + 0.01 = 0.19
P(Y = 3) = 0.01 + 0.03 + 0.24 + 0.02 = 0.30
P(Y = 4) = 0.01 + 0.01 + 0.04 + 0.32 = 0.38
The expectation of Y is given by:
E(Y) = 10.13 + 20.19 + 30.30 + 40.38 = 3.00
The variance of Y is given by:
Var(Y) = E(Y^2) - [E(Y)]^2
= (1^20.13 + 2^20.19 + 3^20.30 + 4^20.38) - (3.00)^2
= 0.77
(e) To determine if the scores assigned by the two inspectors are independent of each other, we need to check if the joint probability mass function can be expressed as the product of the marginal probability mass functions.
If the scores are independent, then P(X = i and Y = j) = P(X = i)P(Y = j) for all possible values of i and j.
Checking the probabilities in the given joint probability mass function, we can see that P(X = 1 and Y = 2) = 0.03, P(X = 1) = 0.12, and P(Y = 2) = 0.20.
Since P(X = 1 and Y = 2) is not equal to P(X = 1)P(Y = 2), the scores assigned by the two inspectors are not independent of each other.
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given tan A = 7/√120 and that angle A is in Quadrant III, find the exact value of cos A in simplest radical form using a rational denominator.
Answer:
Step-by-step explanation:
Step 1: We know that the cosine of an angle in Quadrant III is negative.
Step 2: We convert the given angle A into radians by multiplying it by pi/180.
A = (7/√120) * (π/180) = (7π)/(12√5)
Step 3: We use the cosine formula to find the exact value of cos A.
cos A = cos((7π)/(12√5))
Step 4: We simplify the result using trigonometric identities.
cos A = (-1/3)√5
the scatterplot that is pictured below represents results from a normal peripheral blood sample that was analyzed using flow cytometry. the cell that is indicated by the arrow on the right would fall into which of the circled areas? please select the single best answer population a population b population c
The cell that is indicated by the arrow on the right would fall into population c of the circled areas.
We know that the scatterplot that is pictured below represents results from a normal peripheral blood sample that was analyzed using flow cytometry, the cell that is indicated by the arrow on the right would fall into population c of the circled areas.
Red blood cells are equipped with iron, which binds to oxygen molecules and enables them to be transported throughout the body. In terms of immunity, these cells break down in the presence of harmful pathogens, releasing free radicals that can help to destroy them. Leukocytes play a crucial role in fighting off disease and foreign invaders. Granulocytes, including eosinophils, basophils, and neutrophils, are responsible for battling fungi, bacteria, and parasites, as well as responding to allergic reactions. Meanwhile, the agranulocytes, which include monocytes, lymphocytes, and macrophages, differentiate into macrophages and target B cells, T cells, and natural killer cells, while also performing the important function of phagocytosis. Thrombocytes are responsible for maintaining the body's blood volume and preventing bleeding by promoting clot formation. This process is known as hemostasis. Finally, blood plasma serves as the transport medium for all of the components of peripheral blood, with carbon dioxide playing a key role in enabling the removal of waste and other excretory matter from the body.
The circulating blood of the body is known as peripheral blood. It is comprised of red blood cells, white blood cells, and platelets. These cells are suspended in plasma and circulated throughout the body.
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In a certain factory there are 96 workers. The ratio of blue-eyed to brown-eyed workers is 3:5. If all the workers have either blue or brown eyes, how many have brown eyes?
3k+5k=8k
96/8=12
k=12
as we know blue-eyed are 3k and brown-eyed 5k so we need to put 12 instead of k
5x12=60
In preparation towards a speech day celebration, a schools management committee approved the following budget on some projects. Use the information below to answer the questions that follow. ACTIVITY Painting school building Mending cracks on the netball pitch Restock the computer laboratory with new computers Buying of new cadet uniform Buying prizes for award COST (GHC) 2.940.00 4,250.00 9.990.00 8.940.00 5,270.00 and buying of new cadet uniform.
Based on the given information, we can answer the following questions:
Therefore, the total cost of all the approved projects is 31,390 GHC.
Which project has the highest cost?The project with the highest cost is "Restock the computer laboratory with new computers" with a cost of 9,990 GHC.
What percentage of the total budget is allocated to buying prizes for awards?Percentage of budget = (Cost of buying prizes / Total cost) x 100%
Percentage of budget = (5,270 / 31,390) x 100%
Percentage of budget = 0.1676 x 100%
Percentage of budget = 16.76%
Therefore, 16.76% of the total budget is allocated to buying prizes for awards.
Which project has the highest cost in the budget approved by the school management committee?The project with the highest cost in the budget approved by the school management committee is restocking the computer laboratory with new computers, with a cost of GHC 9,990.00.
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does the scatterplot support the newspaper report about number of semesters and starting salary? justify your answer
A scatterplot can help us visualize the relationship between two variables and determine if there is a correlation between them. If the scatterplot shows a clear pattern or trend, conclude that there is a relationship between the two variables.
Without access to the scatterplot or the newspaper report, it is difficult for me to provide a definitive answer. However, in general, to determine if the scatterplot supports the newspaper report about the number of semesters and starting salary, we need to examine the pattern in the scatterplot.
Suppose we see a clear trend or pattern, such as a linear relationship where an increasing number of semesters is associated with an increased starting salary or a non-linear relationship. In that case, we can say that the scatterplot supports the newspaper report.
However, if we see no discernible pattern or trend or significant variability in the data points makes it is difficult to draw any meaningful conclusions, then we cannot say that the scatterplot supports the newspaper report.
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What is the measure of the hypotenuse?
289
13
169
17
Answer:
Step-by-step explanation:
Using Pythagorean Theorem : A² = B²+C².
→x² = 5²+12² = 25+144 = 169.
→x = √169 = 13.
6 stylar wants to adopt a whate through BC wild killer whale adoption program. The cost of I year adoption is $594 Stylor whale walks his neighbour's dog to fause the money. He gets & 3 for each walk Make a table to show the amount left to raise 1, 2, 3,4 and 5 walks b wright a pattern rule that relates the number of walls to the amount left to raise write on expression to represes de after pattern C e Find the amount left to rise after it wo after how many walks all exglas how tax though money? How do do you know
Answer:
Number of Walks | Amount Left to Raise
0 | $594
1 | $581
2 | $568
3 | $555
4 | $542
5 | $529
Pattern Rule: The amount left to raise decreases by 13 each time the number of walks increases by 1.
Expression: Let n = the number of walks. Amount left to raise = 594 - 13n
After 2 walks, there is $568 left to raise. You know this because 2 multiplied by 13 (the number subtracted for each walk) is 26. Subtract 26 from 594 to get 568.
in hire-assistant, assuming that the candidates are presented in a random order, what is the probability that you hire exactly one time? what is the probability that you hire exactly n times?
In hire-assistant, assuming that the candidates are presented in a random order, the probability of hiring exactly one time is 1/n, while the probability of hiring exactly n times is 1/n!.
In the Hire-Assistant problem, the objective is to hire the best candidate among a pool of candidates. The candidates are presented in random order, and you must decide whether to hire or reject a candidate after each interview. The hiring process ends when the best candidate is hired.
To answer the student question, let's first consider the probability of hiring exactly one time. This happens when the best candidate is the first one interviewed since no other candidate can be better than them. Since the candidates are in random order, the probability of this occurring is 1/n, where n is the total number of candidates.
Now let's consider the probability of hiring exactly n times. This means you would hire every candidate you interview. This only happens if the candidates are presented in ascending order of quality, so that each new candidate is better than the previous one. There is only 1 possible ordering like this out of the total n! possible orderings of candidates. So, the probability of hiring exactly n times is 1/n!.
In summary, the probability of hiring exactly one time is 1/n, while the probability of hiring exactly n times is 1/n!. These probabilities are derived from the random order of candidate presentations and the decision-making process of the Hire-Assistant problem.
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The Area of a Rectangle is 75. The length is 3 times the
width. Find the Width.
Find the length please
The length οf diameter οf the given sphere is 18m.
What is sphere?A sphere is a three-dimensiοnal οbject which is rοund in shape. It has nο edges οr vertices. The sphere can be defined in three axes, thοse are x-axis, y-axis and z-axis.
The given diagram is a sphere.
Given that,
The surface area οf the sphere is 1017.36 m²
Fοrmula fοr surface area οf the sphere = 4πr² where r is the radius and π=3.14
Equating both we get,
4πr² = 1017.36
[ dividing bοth sides by 4 ]
⇒πr² = (1017.36)/4
⇒πr² = 254.34
[putting the value of π]
⇒r² = 254.34/ 3.14
⇒r² = 81
⇒r =± 9
As radius cannot be a negative value so we take r=9
Sο the radius οf the sphere is 9 m
Diameter = 2× radius =2×9= 18m
Hence, diameter οf the given sphere is 18m.
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you own 16 cds. you want to randomly arrange 9 of them in a cd rack. what is the probability that the rack ends up in alphabetical order? the probability that the cds are in alphabetical order is
The probability that the rack ends up in alphabetical order is 1/9! or approximately 1.46 x 10⁻⁷.
The problem involves arranging 9 CDs out of 16 in alphabetical order in a CD rack. The total number of possible ways to arrange 9 CDs out of 16 is 16 choose 9, which equals 11440. Only one of these arrangements is in alphabetical order. Therefore, the probability of randomly selecting an alphabetical order is 1/11440, which is approximately 0.0000874 or 0.00874%. This is a very small probability, indicating that it is highly unlikely that the CDs will end up in alphabetical order by chance.
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after analyzing the sales data from both curbside pickup and delivery orders, a local pizza joint obtains the following 95% confidence intervals for the mean of pickup orders and delivery orders: pickup orders: between $33 and $51 per order delivery orders: between $21 and $41 per order can you conclude that an average pickup order has higher amount than an average delivery order?
Based on the information provided, we cannot conclude with certainty that the average pickup order has a higher amount than the average delivery order.
Based on the information given, we can conclude that there is a 95% chance that the true mean for pickup orders falls between $33 and $51, and the true mean for delivery orders falls between $21 and $41. However, we cannot conclude with certainty that the average pickup order has a higher amount than the average delivery order.
To determine if there is a significant difference between the means of the two groups, we need to perform a hypothesis test. We can set up our null hypothesis as "there is no significant difference between the means of the pickup and delivery orders" and our alternative hypothesis as "the average pickup order has a higher amount than the average delivery order."
We can use a two-sample t-test to test this hypothesis. Assuming equal variances, we would calculate the test statistic as
t = (xpickup - xdelivery) / (s / √n)
where xpickup and xdelivery are the sample means for pickup and delivery orders, s is the pooled standard deviation, and n is the sample size for each group.
If our calculated t-value is greater than the critical value at a chosen significance level (e.g. 0.05), we can reject the null hypothesis and conclude that there is a significant difference between the means of the two groups.
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What is the mean of the given distribution, and which type of skew does it exhibit?
Since 3 has the highest frequency, the mode is 3.Now, the curve is positively skewed if mean is bigger than mean.
Describe total number?Total number is a term used to refer to the sum of two or more individual elements. It is commonly used in the context of mathematics and can refer to the result of addition, subtraction, multiplication, or division. For example, the total number of apples in a basket could be five, the total number of days in a week could be seven, and the total number of people in a family could be four. In any case, the total number is the sum of all the individual elements that are being considered.
Presented to us is a distribution:
{4.5, 3, 1, 2, 4, 3, 6, 4.5, 4, 5, 2, 1, 3, 4, 3, 2}
We must determine the mean.
Mean is equal to the sum of all observations divided by the total number of observations.
Mean = 52/16
Mean = 3.25
We now determine the mode, which is the observation with the highest frequency, or how frequently it has occurred.
observations per unit of time
4.5 2
3 4
1 2
2 3
4 3
6 1
5 1
Since 3 has the highest frequency, the mode is 3.
Now, the curve is positively skewed if mean is bigger than mean.
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Complete questions as follows-
What is the mean of the given distribution, and which type of skew does it exhibit?
{4.5, 3, 1, 2, 4, 3, 6, 4.5, 4, 5, 2, 1, 3, 4, 3, 2}
WHAT IS THE MEAN? and WHAT TYPE OF SKEW EXHIBITS? negative, positive, symmetric, zero etc..
Mai spends 7 and 3/5 hours in school each day. Her lunch period is 30 minutes long, and she spends a total of 42 minutes switching rooms between classes. The rest of her day is spent in 6 classes that are all the same length. How long is each class?
A. 1 1/15 hours
B.1 3/20 hours
C.1 11/60 hours
D. 1 4/15 hours
Answer:
First, we solve for the number of minutes in 7 and 3/5 hours by multiplying the number by 60 giving us,
(7 + 3/5) x (60) = 456 minutes
Spending 30 minutes for lunch will leave her with 426 minutes. Then, spending 42 minutes for switching of classes will finally give her 414 minutes.
We then divide this value by 6 (for her 6 classes) giving us 69 minutes. Thus, each class is 69 minutes long.
Step-by-step explanation:
When comparing the f(x) = –x2 + 2x and g(x) = log(2x + 1), on which interval are both functions positive? (–∞, 0) (0, 2) (2, ∞) (–∞, ∞)
Answer:
To compare the two functions, it is necessary to find the x values for which each function is positive.
For f(x), we can solve for when it is positive by setting the equation equal to zero and finding the x-intercepts.
-x^2 + 2x = 0
-x(x - 2) = 0
-x = 0 and x = 2
This tells us that f(x) is positive for (-inf, 0) and (2, inf).
Next, for g(x), we can solve for when it is positive by setting the equation equal to zero and finding the x-intercept.
log(2x+1) = 0
2x + 1 = 1
x = 0
This tells us that g(x) is positive for (0, inf).
Therefore, the interval on which both functions are positive is (0, 2).
A standard deck of cards has 13 cards that are clubs and 13 cards that are hearts. A card is chosen from a standard deck of cards. It is then replaced, and a second card is chosen from the deck.
What is P(at least one card is a heart)?
three fourths
one half
one fourth
1 over 26
If at least one card is a heart then P is three-fοurths.
What is the prοbability?The study οf prοbability examines the likelihοοds οf results οccurring and is based οn the ratiο οf likely and imprοbable scenariοs.
Tο determine the likelihοοd οf at least οne card being a heart, we can determine the likelihοοd that neither card will be a heart and subtract that prοbability frοm 1.
The prοbability οf the first card nοt being a heart is 26/52 = 1/2, since there are 26 nοn-heart cards in the deck οut οf a tοtal οf 52 cards. Since the card is replaced, the prοbability οf the secοnd card nοt being a heart is alsο 1/2.
Therefοre, the prοbability οf neither card being a heart is (1/2) x (1/2) = 1/4.
The prοbability οf at least οne card being a heart is 1 - (1/4) = 3/4.
Hence, the answer is: three-fοurths.
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This week Andres will practice with his band for 1`\frac{1}{2}` hours on Monday, 1`\frac{3}{4}` hours on Tuesday, and 2 hours on Wednesday. Next week Andres will practice with his band for the same number of hours on Monday, Tuesday, and Wednesday. What is the total number of hours Andres will practice with his band over these 6 days?
Andres will practice with his band for a total of 6 hours and 45 minutes over these 6 days.
To add these times, we need to find a common denominator for 2, 4, and 8, which is 8.
1[tex]\frac{1}{2}[/tex] can be written as [tex]\frac{4}{8}[/tex],
1[tex]\frac{3}{4}[/tex] can be written as [tex]\frac{7}{8}[/tex],
and 2 can be written as [tex]\frac{16}{8}[/tex].
Now we can add the times:
[tex]\frac{4}{8} +\frac{7}{8} +\frac{16}{8} =\frac{27}{8}[/tex]
So Andres will practice for [tex]\frac{27}{8}[/tex] hours this week.
Next week, he will practice for the same number of hours on each day, so he will practice for a total of [tex]\frac{27}{8}[/tex] hours over the three days.
To find the total number of hours he will practice over the 6 days
[tex]\frac{27}{8} + \frac{27}{8} = \frac{54}{8}[/tex]
Simplifying,
[tex]\frac{54}{8} = 6\frac{3}{4}[/tex]
Andres will practice with his band for a total of 6 hours and 45 minutes over these 6 days.
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the significance level indicates the probability of rejecting the null hypothesis when group of answer choices the research hypothesis is false the research hypothesis is true the null hypothesis is true the null hypothesis is false
The significance level, denoted by alpha (α), is a predetermined threshold used in hypothesis testing to determine the probability of rejecting the null hypothesis when it is actually true.
How significance level of rejecting the null hypothesis is true?The steps involved in determining the significance level are as follows:
Set up the null and alternative hypotheses: In hypothesis testing, we have two hypotheses: the null hypothesis (H0) and the alternative hypothesis (H1). The null hypothesis is the default position that there is no significant difference or relationship between two variables, while the alternative hypothesis is the hypothesis that contradicts the null hypothesis. Choose a significance level: The significance level (α) is the predetermined threshold used to determine the probability of rejecting the null hypothesis. It is usually set at 0.05 or 0.01, which means that the researcher is willing to accept a 5% or 1% probability of rejecting the null hypothesis when it is actually true.Calculate the test statistic and p-value: After collecting data, we calculate a test statistic (such as t, F, or chi-square) and its corresponding p-value, which indicates the probability of obtaining a test statistic as extreme or more extreme than the observed one, assuming that the null hypothesis is true.Compare the p-value to the significance level: If the p-value is less than the significance level, we reject the null hypothesis and accept the alternative hypothesis. If the p-value is greater than or equal to the significance level, we fail to reject the null hypothesis.Therefore, the significance level indicates the probability of rejecting the null hypothesis when it is actually true. A smaller significance level (e.g., 0.01) means that the researcher is less willing to accept the risk of rejecting the null hypothesis when it is actually true, while a larger significance level (e.g., 0.05) means that the researcher is more willing to accept that risk.
In conclusion, the significance level is a critical parameter in hypothesis testing that helps researchers make decisions about the null hypothesis. By setting a predetermined threshold for the probability of rejecting the null hypothesis, researchers can control the risk of Type I error (rejecting the null hypothesis when it is actually true) in their statistical analyses.
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Identify the equation of the quadratic function that passes through the points (-2, 0), (2, - 16) and (6, 0).
WILL GIVE BRAINLIEST
An equation of the quadratic function that passes through the points (-2, 0), (2, - 16) and (6, 0) is: D. f(x) = (x - 2)² - 16.
How to determine the factored form of a quadratic equation?In this exercise, you are required to determine the factored form of the given quadratic function that passes through the points (-2, 0), (2, - 16) and (6, 0).
In Mathematics, the vertex form of a quadratic function is represented by the following mathematical equation:
f(x) = a(x - h)² + k
Where:
h and k represents the vertex of the graph.a represents the leading coefficient.Based on the information provided in the graph above, we can determine the value of a as follows:
f(x) = a(x - h)² + k
0 = a(-2 - 2)² - 16
0 = 16a - 16
16 = 16a
a = 1
Therefore, the required quadratic function is given by:
f(x) = a(x - h)² + k
f(x) = y = (x - 2)² - 16
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the city of ithaca, new york, allows for two-hour parking in all downtown spaces. methodical parking officials patrol the downtown area, passing the same point every two hours. when an official encounters a car, he marks it with chalk. if the car is still there two hours later, a ticket is written. suppose that you park your car for a random amount of time that is uniformly distributed on .0; 4/ hours. what is the probability you will get a ticket?
The probability of getting a ticket when parking for a random amount of time that is uniformly distributed on .0; 4/ hours is 1/2.
Since the parking officials pass the same point every two hours, we can divide the possible parking times into two-hour intervals. If a car is parked for less than two hours, it will not be marked with chalk. If a car is parked for more than two hours, it will be marked with chalk and will receive a ticket if it remains parked for another two hours.
Since the possible parking times are uniformly distributed on .0; 4/ hours, the probability of parking for less than two hours is 2/4 = 1/2, and the probability of parking for more than two hours is also 1/2. Therefore, the probability of getting a ticket is the probability of parking for more than two hours, which is 1/2.
Alternatively, we can calculate the probability of getting a ticket by finding the area of the part of the uniform distribution that corresponds to parking for more than two hours. This area is a triangle with base 2 and height 1/2, so its area is (1/2)(2)(1/2) = 1/2. Therefore, the probability of getting a ticket is also 1/2.
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Which of the following are monomials? Check all that apply.
A. I
B. √
C. 6
D. x+1 E.-4x³ F. 5/1
Answer:
A, C, E
Step-by-step explanation:
A, C, E
A monomial is a single number, or a single number multiplied by one or more variables.
A variable in a square root or in a denominator is not allowed in a monomial.
given point O is the center of each circle:
Using the central angle theorem, we can find that the value of the angle:
∠ BOC = 130°.
Define central angle?An inscribed angle is the angle formed inside the circle when two chords intersect it. It can also be defined as the angle made by two specific points at a given location on a circle. Instead, an inscribed angle is defined by two circle chords that share an endpoint.
In the given question,
O is the centre of the circle.
OC, OD, OE, OA and OB are all radius of the circle.
AC and BD are the diameters of the circle.
As BD intersects AC and the angles are given as:
∠COD = 50°
∠DOE = 60°
So, ∠ AOE = 180 - 50 - 60
= 70°
Similarly, ∠AOB = 50°.
Now, ∠ BOC = 360° - 50° - 60° - 70° - 50°
= 130°
Therefore, ∠ BOC = 130°.
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Suppose 275 trout are seeded into a lake. Absent constraint their population will grow by 75% a year. If the lake can sustain a maximum of 2700 trout use a logistic growth model to estimate the number of trout after 2 years
Answer: 1729 trout.
Step-by-step explanation:
We can use the logistic growth model to estimate the number of trout after 2 years:
N(t) = K / (1 + (K/N0 - 1) * e^(-rt))
where:
N(t) is the number of trout at time t
K is the carrying capacity of the lake (2700 trout)
N0 is the initial population (275 trout)
r is the growth rate (75% or 0.75, per year)
e is the base of the natural logarithm, approximately equal to 2.71828
To estimate the number of trout after 2 years, we can plug in t = 2 and solve for N(t):
N(2) = 2700 / (1 + (2700/275 - 1) * e^(-0.75*2))
N(2) = 2700 / (1 + 8.8 * e^(-1.5))
N(2) ≈ 1728.7
Therefore, we can estimate that the number of trout after 2 years will be approximately 1729 trout.
Which of the following is the inverse of F) =-2x+ 3?
Answer:
[tex]\boxed{f^{-1}(x)=\frac{x-3}{-2}}[/tex]
Step-by-step explanation:
The inverse of the function satisfies the following:
[tex]f(a)=b \qquad \implies \qquad f^{-1}(b)=a[/tex]
Given the expression:
[tex]f(x)=-2x+ 3[/tex]
The inverse function can be calculated with the next steps:
replace [tex]f(x)[/tex] with [tex]y[/tex] Solve for the variable x based on the variable y.Variables are swapped.[tex]\begin{aligned}f(x)=-2x+3 &\rightarrow y=-2x+3\\&\rightarrow y-3=-2x\\& \rightarrow x= \frac{y-3}{-2} \\&\therefore f^{-1}(x)=\frac{x-3}{-2}\end{aligned}[/tex]
Hope it helps.
[tex]\text{-B$\mathfrak{randon}$VN}[/tex]
Use 3.14 for pi. A wooden toy block is in the shape of a cylinder. The toy block has a height of 4 inches and a diameter of 3 inches. How
much does the toy block weigh if 1 cubic inch of wood weighs 0.55 ounce? Round to the nearest tenth.
Weight of wood block is about 15.5 ounces.
Volume of cylinder:Given that:
Height of block [tex]= 4 \ \text{inches}[/tex]
Diameter of block [tex]= 3 \ \text{inches}[/tex]
1 cubic inch of wood [tex]= 0.55 \ \text{ounces}[/tex]
Find:
Weight of wood block
Computation:
Radius of block [tex]= 3 \div 2[/tex]
Radius of block [tex]= 1.5 \ \text{inches}[/tex]
Volume of toy [tex]= \pi r^2h[/tex]
Volume of toy [tex]= (3.14)(1.5)^2(4)[/tex]
Volume of toy [tex]= (3.14)(2.25)(4)[/tex]
Volume of toy [tex]= 28.26 \ \text{cubic inch}[/tex]
Weight of wood block [tex]= \text{Volume of toy} \times \ \text{0.55 ounces}[/tex]
Weight of wood block [tex]= 28.26 \times 0.55 \ \text{ounces}[/tex]
Weight of wood block [tex]= 15.5 \ \text{ounces}[/tex]
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two different 3 digit numbers have the same digits, but in reserve rder. no digit is zero. if the numbers are subtracted, what is the kargest possible difference?
The largest possible difference between two different 3-digit numbers with the same digits in reverse order is 792.
Let's assume the two numbers are ABC and CBA. The largest possible difference is achieved when the digits A and C have the largest possible difference.
If A > C, then the difference would be (ABC - CBA) = (100A + 10B + C) - (100C + 10B + A) = 99A - 99C = 99(A - C).
If A < C, then the difference would be (CBA - ABC) = (100C + 10B + A) - (100A + 10B + C) = 99C - 99A = 99(C - A).
Since we want the largest possible difference, we want to maximize the difference between A and C. The maximum possible difference between two single-digit non-zero numbers is 9. So, we want A = 9 and C = 1.
Therefore, the two numbers are 901 and 109, and the largest possible difference is (901 - 109) = 792.
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A spinner with repeated colors numbered from 1
to 8 is shown. Sections 1 and 8 are purple.
Sections 2 and 3 are yellow. Sections 4, 5, and 6
are blue. Section 7 is orange.
Which statement about probability is true?
The probability of landing on orange is greater
than the probability of landing on purple.
The probability of landing on yellow is less than
the probability of landing on blue.
The probability of landing on orange is equal to
the probability of landing on yellow.
The probability of landing on purple is equal to
the probability of landing on blue.
Answer: The probability of landing on orange is equal to the probability of landing on purple
Step-by-step explanation:
The spinner has a total of 8 equally-sized sections, and each section has a unique color. Therefore, the probability of landing on any particular section is 1/8 or 0.125.
Looking at the colors on the spinner, we can see that there are two purple sections, two yellow sections, three blue sections, and one orange section.
Therefore, the probability of landing on orange is 1/8 or 0.125, which is equal to the probability of landing on purple (sections 1 and 8). So the statement "The probability of landing on orange is equal to the probability of landing on purple" is true.
On the other hand, the probability of landing on yellow is 2/8 or 0.25, which is greater than the probability of landing on blue (sections 4, 5, and 6), which is 3/8 or 0.375. So the statement "The probability of landing on yellow is less than the probability of landing on blue" is false.
Therefore, the correct statement about probability is "The probability of landing on orange is equal to the probability of landing on purple."
Blair's new computer cost $5 less than twice the cost of her old
computer. Her new computer cost $709. How much did Blair's old
computer cost?l
Therefore , the solution of the given problem of expressions comes out to be cost $357.
What does an expression mean?It is preferable to use moving integer variables, which can be rising, decreasing, or blocking, rather than estimates that are generated at random. They could only assist one another by exchanging resources, knowledge, or answers to problems. A declaration of truth equation may include the justifications, components, and mathematical comments for strategies like extra disapproval, production, and mixture.
Here,
Let's say Blair's previous PC cost "x" dollars.
Her new computer cost $5 less than twice as much as her previous one, according to the information provided, which can be written as:
=> Cost of Blair's new computer = 2x - 5
She also purchased a new PC, which cost her $709. In light of these two bits of knowledge, we can construct the following equation:
=> 2x - 5 = 709
In order to find "x," add 5 to both parts, divide by 2, and we get:
=> 2x = 714
=> x = 357
Blair's previous PC therefore cost $357.
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can someone please help
Answer:
Step-by-step explanation: