A sample of gas occupies 200 L at 780 mm Hg and 280 K. What is the new volume, in liters, of the gas at 810 mm Hg and 300 K?

Answers

Answer 1

Given :

A sample of gas occupies 200 L at 780 mm Hg and 280 K.

To Find :

The new volume, in liters, of the gas at 810 mm Hg and 300 K.

Solution :

We know, by ideal gas equation :

[tex]PV = nRT[/tex]

Since, every thing is constant except [tex]nR[/tex] .

So,

[tex]\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}[/tex]

Putting all given values we get :

[tex]V_2 = \dfrac{T_2}{T_1}\times \dfrac{P_1}{P_2}\times V_1\\\\V_2 = \dfrac{300}{280}\times \dfrac{780}{810}\times 200\ L\\\\V_2 = 206.35 \ L[/tex]

Therefore, the new volume is 206.35 L.


Related Questions

WILL MARK BRAINLIEST!!
Which situation indicates a beta emission?


The atomic number increases by one, but the mass number does not change.


The atomic number decreases by two, and the mass number decreases by four.


The atomic number decreases by one, and the mass number decreases by one.

The atomic number and the mass number both decrease by two.

Answers

The answer is the first option

Answer:

A: The atomic number increases by one, but the mass number does not change.

All radioactive sources have a half-life.
Which statement about the half-life of a source is correct?

A. It is half the time it takes for an atom to decay

B. It is half the time for the radioactive source to become safe

C. It is the time it takes the actity of the source to decrease by half

D. It is half the time it takes the activity of the source to decrease to zero

Answers

Answer:

The answer is C

Explanation:

Duh its the name HALF LIFE!!

just a way to remember

The statement which is true about the half-life of a source is (D) It is half the time it takes the activity of the source to decrease to zero. Hence the correct option is (D)

What is Half Life Period of a source ?

Half-life is the length of time it takes for a radioactive element to decay to half of its initial value.

This suggests that a source's activity has a half-life when it takes time for it to decrease to half its initial value.

It is the amount of time needed for half of the atomic nuclei in a radioactive sample to spontaneously decay, which releases energy and particles into other nuclear species. Alternatively, it is the amount of time needed for the radioactive sample to disintegrate at a rate of one per second.

Therefore, The statement which is true about the half-life of a source is (D) It is half the time it takes the activity of the source to decrease to zero. Hence the correct option is (D)

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What is the molecular weight of MgCl2

Answers

The molecular weight of MgCl₂ is 94 g/mol.

What is molecular weight?

This refers to the total mass of a compound. It is equivalent to the sum of the individual atomic masses of each atom in the molecule.

Steps to determine the molecular formula of the molecule.

Determine the atomic mass of each element in the molecule.Multiply each element's atomic mass by the number of atoms of that element in the molecule. This number is represented by the subscript next to the element symbol in the molecular formula.Add these values together for each different atom in the molecule.The total will be the molecular mass of the compound.

Atomic number of Cl =17

Atomic number of Mg = 12

Mass number of Cl = 35

Mass number of Mg = 24

Calculating the molecular weight of MgCl₂

MgCl₂

=(12* 2) + (35*2)

= 24 + 70

= 94 g/mol.

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The Sun is located _____.

in the central core of the Milky Way galaxy
in the bar of the Milky Way
in an arm about 25% of the distance from the center of the Milky Way to its outer edge
in an arm about 75% of the distance from the center of the Milky Way to its outer edge

Answers

Answer:

I believe the answer is going to be A. in the central core of the Milky Way galaxy.

Explanation: lol sorry I put it in the question box instead of answering it, hope this helps!

Because the mass of the flask with water exceeds the amount that can be weighed on the digital balances, the triple-beam-balance is used, which only weighs to the nearest 0.01 g. Why doesn't using this balance affect the number of significant digits to which the experimental molecular weight of carbon dioxide can be reported

Answers

Answer:

The Less accuracy of this method is the reason for this balance affecting the number of significant digits to which the experimental molecular weight of carbon dioxide can be reported.

Explanation:

As we know the triple-beam-balance method is a less accurate method of measurement of mass.

An accurate molecular weight is not required in this case. So, this method is being used because much accuracy is not required.

That is why this balance affects the number of significant digits to which the experimental molecular weight of carbon dioxide can be reported.

A sample of N2 has a volume of 616 mL at 68 °C. What will be its volume at -17 °C?

Answers

Answer:

462.5ml

Explanation:

Using Charle's law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (ml)

V2 = final volume (ml)

T1 = initial temperature (K)

T2 = final temperature (K)

Based on the information provided in this question;

V1 = 616ml = 616/1000 = 0.616L

V2 = ?

T1 = 68°C = 68 + 273 = 341K

T2 = 17 °C = -17 + 273 = 256K

V1/T1 = V2/T2

0.616/341 = V2/256

Cross multiply

341 × V2 = 256 × 0.616

341V2 = 157.69

V2 = 157.69/341

V2 = 0.4625 L or 462.5ml

Please show all of your work, I need to understand all steps:
A student collected time (t) and concentration ([A]) data at
295 K for the reaction 2A→B. These time and concentration data are shown in the table to the right. The student then plotted graphs of [A] versus t (Figure 1) , ln[A] versus t (Figure 2) , and 1/[A] versus t (Figure 3) .
Figure 1:
t (s) (A)(M) ln(A) 1/ (A)
0.00 0.500 −0.693 2.00
20.0 0.389 −0.944 2.57
40.0 0.303 −1.19 3.30
60.0 0.236 −1.44 4.24
80.0 0.184 −1.69 5.43
i.) What is the rate of the reaction?
ii.) What is the value of the rate constant for this reaction?
iii.)
Next, the student ran the same reaction at a different temperature and measured a different reaction rate, with the following results:
T(K) k(s-1)
295 0.0125
325 0.0357
What is the activation energy of this reaction?
Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

a because the x and y value is the same

1. What is the process in which two daughter cells form called?
2. What are the five phases of mitosis?
3. What is the longest stage of mitosis?
4. What occurs during prophase?
5. What occurs during metaphase?
6. What occurs during anaphase?
7. What occurs during telophase?
8. Meiosis divides the cell into how many daughter cells?
9. Is Mitosis or Meiosis used in sexual reproduction?
10. What is the difference between asexual and sexual reproduction?

Answers

Answer:

1. Mitosis is a process of nuclear division in eukaryotic cells that occurs when a parent cell divides to produce two identical daughter cells. During cell division, mitosis refers specifically to the separation of the duplicated genetic material carried in the nucleus.

2. Today, mitosis is understood to involve five phases, based on the physical state of the chromosomes and spindle. These phases are prophase, prometaphase, metaphase, anaphase, and telophase.

3. Prophase. The first and longest phase of mitosis is prophase. During prophase, chromatin condenses into chromosomes, and the nuclear envelope (the membrane surrounding the nucleus) breaks down. In animal cells, the centrioles near the nucleus begin to separate and move to opposite poles of the cell.

4. During prophase, the complex of DNA and proteins contained in the nucleus, known as chromatin, condenses. The chromatin coils and becomes increasingly compact, resulting in the formation of visible chromosomes. The sister chromatids are pairs of identical copies of DNA joined at a point called the centromere.

5. During metaphase, the cell's chromosomes align themselves in the middle of the cell through a type of cellular "tug of war." The chromosomes, which have been replicated and remain joined at a central point called the centromere, are called sister chromatids.

6. During anaphase, each pair of chromosomes is separated into two identical, independent chromosomes. The chromosomes are separated by a structure called the mitotic spindle. The separated chromosomes are then pulled by the spindle to opposite poles of the cell.

7. Telophase is the fifth and final phase of mitosis, the process that separates the duplicated genetic material carried in the nucleus of a parent cell into two identical daughter cells. During telophase, a nuclear membrane forms around each set of chromosomes to separate the nuclear DNA from the cytoplasm.

8. Meiosis is a process where a single cell divides twice to produce four cells containing half the original amount of genetic information. These cells are our sex cells sperm in males, eggs in females. During meiosis one cell? divides twice to form four daughter cells.

9. Only sexually reproductive organisms utilize meiosis. Both sexual and asexual organisms go through the process of mitosis. It happens in the cells of the body known as the somatic cells and produces cells related to growth and repair.

10. Asexual reproduction involves one parent and produces offspring that are genetically identical to each other and to the parent. Sexual reproduction involves two parents and produces offspring that are genetically unique.

Explanation:

heart me pls

what is the energy of a photon of yellow light with a frequency of 5.2 x 10¹⁴ Hz?

Answers

Answer:

3.4x10⁻¹⁹J is the energy of the photon

Explanation:

To find the energy of a photon from its frequency we must use the equation:

E = hf

Where E is the energy of the photon in J, our incognite

h is Planck's constant = 6.6262x10⁻³⁴Js

And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹

Replacing:

E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹

E = 3.4x10⁻¹⁹J is the energy of the photon

Remember: all EM waves travel at the same __________. The equation for speed is __________ times the __________. So, for the answer to always be 300,000km/s, as one number goes __________, the other must go __________. All EM waves are __________. The higher the __________, the more __________ in the wave.

Answers

All the EM waves travel at the same speed. The equation for speed is frequency (v) times the wavelength (λ). Speed of light equals 300000 km/s. Hence one number goes to 3 × 10⁸ m and other number is 1 s⁻¹.

What is an electromagnetic wave ?

Electromagnetic waves are waves moving without a medium through vacuum. They are accompanied with an electric field and magnetic field. The speed of an electromagnetic wave is the product its wavelength and frequency.

c = νλ

Therefore, the given passage can be filled as follows:

All the EM waves travel at the same speed. The equation for speed is frequency (v) times the wavelength (λ). Speed of light equals 300000 km/s. Hence one number goes to 3 × 10⁸ m and other number is 1 s⁻¹.

All EM waves are energetic.  The higher the frequency the more energy in the wave.

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Which type of sedimentary rock forms from weathered sediment?

Answers

Answer:

Clastic or detrital sedimentary rocks are made from pieces of bedrock, sediment, derived primarily by mechanical weathering.

Explanation:

clastic or detrital sedimentary rocks

In today's experiment, Solutions A and B are prepared as follows.
Solution A: Solution B:
2.0 mL of 3.00 x 10-4 M bromcresol green 2.0 mL of 3.00 x 10-4 M bromcresol green
5.0 mL of 1.60 M acetic acid (HAc) 2.0 mL of 0.160 M sodium acetate (NaAc)
2.0 mL of 0.200 M KCl diluted to a total volume of 50 mL
diluted to a total volume of 50 mL
What is the molarity of HAc in Solution A?
A. 6.4x 10-3
B. 3.20 x 10-4
C. 8.0 x 10-3
D. 0.160
E. 1.60

Answers

Answer:

D. 0.160

Explanation:

The solution A is obtained adding 2.0mL of a solution of bromocresol green, 5.0mL of 1.60M HAc and 2.0mL of a solution of KCl. The solution is diluted to 50mL

That means the HAc is diluted from 5.0mL to 50.0mL, that is:

50.0mL / 5.0mL = 10 times.

And the final concentration of HAc must be:

1.60M / 10 times =

0.160M

Right answer is:

D. 0.160

The density of oxygen gas at a certain temperature and pressure is 1.345 g cm-3. How many oxygen atoms are present in 2.0 L of oxygen gas at this same temperature and pressure?

Answers

The number of oxygen atoms present in 2.0L of oxygen gas at same temperature and pressure is 5.1 × 10²² atoms.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number (6.02 × 10²³).

no of atoms = no of moles × 6.02 × 10²³

According to this question, the density of oxygen gas at a certain temperature and pressure is 1.345 g cm-³. If 2.0 L of oxygen gas is given, the mass of the oxygen gas can be calculated as follows:

mass = 1.345 × 2 = 2.69grams

moles = 2.69g ÷ 32g/mol = 0.084moles

No of atoms = 0.084 mol × 6.02 × 10²³

no of atoms = 5.1 × 10²² atoms

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How many molecules of H2O are equivalent to 98.2 g of H2O

Answers

Answer:

Demo Mole Quantities

58.5g NaCl(mol/58.5g)(6.02 x 1023/mol) = 6.02 x 1023 Na

+

Cl21 pre-1982 pennies (after 1982 pennies are mostly zinc with copper coating)

63.5g Cu( mol/ 63.5g)(6.02 x 1023/mol) = 6.02 x 1023 Cu

19.0g Al (mol/27.0g)(6.02 x 1023/mol) = 4.24 x 1023 Al

Explanation:

the assembly of an RNA strand is called what

Answers

RNA strand is called ribonucleic acid

How to solve this problem in Chemistry? I am stuck

Answers

The buffer can be made using an acid or a base.

What is a buffer?

We have to know that the term buffer is the generic term that can be generally used to describe any solution that is resistant to changes in acidity and the alkalinity of the solution.

We know that we can be able to make a buffer in two ways;

1) By the use of a weak acid and its salt

2) By the use of weak base and its salt.

In each case, the pH of the solution that has been formed would not be easily changed and this is the job of the buffer.

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The table shows the chemical formulas for four substances. Substance Chemical Formula 1 C2H60 CH 2. "8" 18 ليبيا CH,CH_Br C.H.. 4. Which substances have the same number of carbon atoms? A Substances 1 and 2 B Substances 2, 3, and 4 C Substances 2 and 3 only D Substances 1 and 3​

Answers

The answer is D
Substances 1 and 3

Balance the following Equation (do not leave any empty blanks, you must enter 1 if the value is 1):
___ Na2S + ___ HCl --> ___ NaCl + ___ H2S
(Refer to image)
What type of reaction is it?
(Question one is a _______ type of reaction.)

Answers

Answer: this looks hard

Explanation:

Answer:

1 Na2S  + 2 HCl  ===>   2 NaCl  + 1 H2S

In these reactions, two compounds exchange ions to form two new compounds.

Explanation:

--- Na2S + ---- HCl ===> ---- NaCl  + ---- H2S

Na  =  2                                  Na = 1 * 2 = 2

S  = 1                                       S = 1

H = 1 * 2 = 2                             H = 2

Cl = 1 * 2 = 2                            Cl = 1 * 2 = Cl

In these reactions, two compounds exchange ions to form two new compounds.

REACTION TYPE:

DOUBLE DISPLACEMENT REACTION/DOUBLE REPLACEMENT

I hope that helps, have a wonderful day!!!!

Why atoms form compounds

Answers

Answer:

Because the atoms are trying to reach the most stable ( lowest energy ) state they can.

We learned that Energy can
exist in many forms.
Do you think energy can
converted from one form to
another?

Answers

Yea energy can convert from one form to another

If a dog has a mass of 22.9 kg, what is its mass in the following units? Use scientific notation in all of your answers. (a) What is the dog's mass in grams? × 10 g (b) What is the dog's mass in milligrams? × 10 mg (c) What is the dog's mass in micrograms? × 10 μg

Answers

Answer:

a) 2.29E4

Explanation: 1kg = 1000g. to get mass in grams multiply 22.9 kg by 1000g then divide by 1 kg to cancel the kg.

b)  2,29E5 g

c) 2.29 E10 μg

How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?

Answers

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

[tex]Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}[/tex]

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

[tex]\frac{3}{2} \times 5.3 mol\\= 7.95 mol[/tex]

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

[tex]No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g[/tex]

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Anyone know this
Please help me

Answers

Answer:

sorry I don't know

Explanation:

have a great time with your family and friends

Look at the diagram. De both lemas and humans have the traits listed at point D? Explain your reasoning​

Answers

Answer:

WHAT DIAGRAM THX FOR POINTS THO

Explanation:

The entropy change for a real, irreversible process is equal to:______.
a. the entropy change for a theoretical reversible process with the same initial and final states.
b. equal to the entropy change for the same process performed reversibly ONLY if the process can be reversed at all.
c. zero.
d. impossible to tell.

Answers

Answer:

The entropy change for a real, irreversible process is equal to zero.

The correct option is 'c'.

Explanation:

Lets look around all the given options -:

(a)  the entropy change for a theoretical reversible process with the same initial and final states , since the entropy change is equal and opposite in reversible process , thus this option in not correct.

(b) equal to the entropy change for the same process performed reversibly ONLY if the process can be reversed at all. Since , the change is same as well as opposite too . Therefore , this statement is also not true .

(c) zero. This option is true because We generate more entropy in an irreversible process. Because no heat moves into or out of the surroundings during the procedure, the entropy change of the surroundings is zero.

(d) impossible to tell. This option is invalid , thus incorrect .

Hence , the correct option is 'c' that is zero.

Answer: the entropy change for a theoretical reversible process with the same initial and final states

CaCO3 (s) + 176 KJ à CaO (s) + CO (g)

A. 176 KJ are released in an endothermic reaction.
B. 176 KJ are released in an exothermic reaction
​​​​​​C. 176 KJ are absorbed in an exothermic reaction.
D. 176 KJ are absorbed in an endothermic reaction.

Answers

Answer:

its d

Explanation:

Each of the following sets of quantum numbers is supposed to specify an orbital Choose the one set of quantum numbers that does NOT contain an error.
a) n=4, I=4, m/=1
b) n=5, I=3, m/=- 3
c) n=3, I=1, m/= -2
d) n=3, I= 2, m/=+3 ​

Answers

Answer:

C

Explanation:

The correct answer is C because the first quantum numbers containing and encompass in an orbital m contain a definite she'll of 2 and hence

I need help please in this:(

Answers

Answer:

That would be A sir or Miss

Explanation: Tell me if I am wrong, Also hope this helped you!

How many joules would be released when 256 grams of zinc at 96 c were cooled to 28 c

Answers

Answer:

–6562.816 J

Explanation:

From the question given above, the following data were obtained:

Msss (M) = 256 g

Initial temperature (T₁) = 96 °C

Final temperature (T₂) = 28 °C

Heat (Q) released =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T₁) = 96 °C

Final temperature (T₂) = 28 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 28 – 96

ΔT = –68 °C

Finally, we shall determine the heat released. This can be obtained as follow:

Msss (M) = 256 g

Change in temperature (ΔT) = –68 °C

Specific heat capacity (C) of Zn = 0.377 J/gºC

Heat (Q) released =?

Q = MCΔT

Q = 256 × 0.377 × –68

Q = –6562.816 J

Thus, –6562.816 J of heat energy is released.

10 points

Scenario: Calculate the new temperature when a 2.0 L of a gas at 220 K is compressed to 1.0 L.

Hint! You should check three boxes: one to describe particle speed, one to describe particle spacing and one to describe number of particle collisions.

Question 5 options:

The particles speed up.


The particles slow down.


The particle speed doesn't change.


The particles get squished (compressed) together.


The particles float farther apart.


The distance between particles doesn't change.


The amount of collisions among particles in the gas sample increase.


The amount of collisions among particles in the gas sample decrease.


The amount of collisions among particles in the gas sample doesn't change.

Answers

Answer:

The 2nd, 4th, and 7th options

Explanation:

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