A sample space is shown below.


(1, 1) (2, 1) (3, 1) (4, 1) (5, 1) (6, 1)
(1, 2) (2, 2) (3, 2) (4, 2) (5, 2) (6, 2)
(1, 3) (2, 3) (3, 3) (4, 3) (5, 3) (6, 3)
(1, 4) (2, 4) (3, 4) (4, 4) (5, 4) (6, 4)
(1, 5) (2, 5) (3, 5) (4, 5) (5, 5) (6, 5)
(1, 6) (2, 6) (3, 6) (4, 6) (5, 6) (6, 6)
A compound event image occurs when any of the shaded outcomes in the sample space occurs. What is the probability of image?

A.
image

Answer:

[tex]Pr(E) = \frac{1}{9}[/tex]

Step-by-step explanation:

Given

Compound event E

replace "image" with E in the question

Required

The probability of E

From the question, 4 outcomes were shaded.

This implies that

[tex]n(E) = 4[/tex]

And we have:

[tex]n(S) = 36[/tex] --- Sample size

The probability of E is:

[tex]Pr(E) = \frac{n(E)}{n(S)}[/tex]

This gives:

[tex]Pr(E) = \frac{4}{36}[/tex]

Simplify

[tex]Pr(E) = \frac{1}{9}[/tex]

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