The natural process being modeled is weathering, specifically physical weathering.
Physical weathering is the process by which rocks and minerals are broken down into smaller pieces without changing their chemical composition. Water is one of the most significant agents of physical weathering.
The scenario described in the question illustrates how water can cause physical weathering by soaking into a lump of clay, then drying out, leaving behind small pebbles and other components. The water expands as it freezes, causing the clay to crack, and as it dries, it evaporates, leaving behind the broken pieces.
Over time, this process can break down larger rocks and minerals into smaller particles, creating sediment that can be transported by wind, water, or ice, and deposited elsewhere. The result of physical weathering is often a mix of angular fragments that have the same composition as the original rock or mineral.
To know more about physical weathering, refer here:
https://brainly.com/question/29616084#
#SPJ11
Determine the ph if 50.0 ml of 0.75 m hi solution is added to 0.027 l of a 0.05 m koh solution
The pH of the resulting solution is about 0.33.
To determine the pH of the resulting solution when 50.0 mL of 0.75 M HI solution is added to 0.027 L of a 0.05 M KOH solution, we first need to find the moles of each reactant and then determine the concentration of the remaining ions.
1. Calculate moles of HI:
Volume (L) = 50.0 mL × (1 L / 1000 mL) = 0.050 L
Moles of HI = Volume (L) × Molarity = 0.050 L × 0.75 M = 0.0375 mol
2. Calculate moles of KOH:
Moles of KOH = Volume (L) × Molarity = 0.027 L × 0.05 M = 0.00135 mol
3. Determine the limiting reactant and the amount of remaining ions:
Since HI is a strong acid and KOH is a strong base, they will react completely in a 1:1 ratio. KOH is the limiting reactant, and there will be a remaining amount of HI.
Moles of remaining HI = Moles of HI - Moles of KOH = 0.0375 mol - 0.00135 mol = 0.03615 mol
4. Calculate the concentration of remaining H+ ions:
Total volume of the solution = 0.050 L (HI) + 0.027 L (KOH) = 0.077 L
Concentration of H+ ions = Moles of remaining HI / Total volume = 0.03615 mol / 0.077 L = 0.469 M
5. Determine the pH of the solution:
pH = -log10([H+]) = -log10(0.469) ≈ 0.33
The pH of the resulting solution is approximately 0.33.
To learn more about concentration, refer below:
https://brainly.com/question/10725862
#SPJ11
A gas has a pressure of 499.0 mm Hg at 50.0 °C. What is the
temperature at standard pressure (1 atm = 760 mmHg)?
The temperature of the gas at standard pressure is 219.02 °C.
What is the temperature of the gas at standard pressure (1 atm = 760 mmHg)?Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.
It is expressed as;
P₁/T₁ = P₂/T₂
We know that the pressure (P1) is 499.0 mmHg at a temperature (T1) of 50.0°C. We want to find the temperature (T2) at standard pressure (P2 = 1 atm = 760 mmHg). We also know that the volume (V1) is constant, so we can write:
P₁/T₁ = P₂/T₂
Solving for T2, we get:
T2 = (P2 × T1)/P1
T2 = (760 mmHg × 323.15 K)/499.0 mmHg
T2 = 492.172 K
Converting this temperature to °C, we get:
T2 = 492.172 K - 273.15
T2 = 219.02 °C
Therefore, the temperature is 219.02 °C.
Learn more about Gay-Lussac's law here: brainly.com/question/1358307
#SPJ1
Answer:
492.17 K (2 d.p.) = 219.02 °C (2 d.p.)
Explanation:
To find the final pressure inside the steel tank, we can use Gay-Lussac's law since the volume is constant.
Gay-Lussac's law[tex]\boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}[/tex]
where:
P₁ is the initial pressure.T₁ is the initial temperature (in kelvins).P₂ is the final pressure.T₂ is the final temperature (in kelvins).As we are solving for the final temperature, rearrange the equation to isolate T₂:
[tex]\sf T_2=\dfrac{P_2T_1}{P_1}[/tex]
Convert the initial temperature from Celsius to Kelvin by adding 273.15:
[tex]\implies \sf T_1=50+273.15=323.15\;K[/tex]
The standard pressure is 1 atm = 760 mmHg.
Therefore, the values to substitute into the equation are:
P₁ = 499.00 mmHgT₁ = 323.15 KP₂ = 760 mmHgSubstitute the values into the equation and solve for T₂:
[tex]\implies \sf T_2=\dfrac{760 \cdot 323.15}{499}[/tex]
[tex]\implies \sf T_2=\dfrac{245594}{499}[/tex]
[tex]\implies \sf T_2=492.172344689...[/tex]
[tex]\implies \sf T_2=492.17\;K\;(2\;d.p.)[/tex]
Therefore, the temperature at standard pressure for a gas with a pressure of 499.0 mmHg at 50.0 °C is 492.17 K (or 219.02 °C).
A student determined that the mass of the carbon product was less than the mass of the sulfuric acid and sugar that were combined. how would you account for this loss of mass? use evidence and scientific reasoning to support your answer.
The loss of mass could be accounted for by the release of gases such as water vapor, carbon dioxide, and sulfur dioxide during the reaction between sulfuric acid and sugar.
This is due to the fact that both sugar and sulfuric acid are organic compounds, and when heated, they undergo dehydration and decomposition reactions respectively, producing gases that escape the system. The carbon product is also likely to be less dense than the reactants, resulting in a further loss of mass.
Additionally, some of the sugar may have not fully reacted due to incomplete mixing, resulting in residual sugar that was not accounted for in the mass measurement. Overall, the loss of mass is expected in any chemical reaction, and in this case, it can be attributed to the production of gases and incomplete reaction.
To learn more about loss of mass, here
https://brainly.com/question/31417203
#SPJ4
2H2 + 1O2 --> 2H2O
Suppose you had 20. 76 moles of H2 on hand and plenty of O2, how many moles of H2O could you make?
When given 20.76 moles of H2 and plenty of O2, you can make 20.76 moles of H2O.
To determine how many moles of H2O can be produced from 20.76 moles of H2 and plenty of O2, we'll use the balanced chemical equation provided: 2H2 + 1O2 --> 2H2O.
Step 1: Identify the limiting reactant. In this case, we have plenty of O2, so H2 is the limiting reactant.
Step 2: Determine the mole ratio between the limiting reactant (H2) and the product (H2O). According to the balanced equation, the mole ratio is 2H2 to 2H2O, or 1:1.
Step 3: Calculate the moles of H2O produced. Since the mole ratio is 1:1, the number of moles of H2O produced will be the same as the number of moles of H2 available. Thus, you can produce 20.76 moles of H2O.
In summary, when given 20.76 moles of H2 and plenty of O2, you can make 20.76 moles of H2O.
To know more about moles, visit:
https://brainly.com/question/31597231#
#SPJ11
How many grams of no2 can be produced when 25.0 g of oxygen reacts?
71.875 grams of NO2 can be produced when 25.0 g of oxygen reacts in this reaction.
When 25.0 grams of oxygen reacts, the amount of NO2 produced can be determined by using stoichiometry. The balanced chemical equation for the reaction is:
2 NO + O2 → 2 NO2
From the equation, it can be seen that for every one mole of O2, two moles of NO2 are produced. Therefore, the first step is to convert the given mass of oxygen into moles. The molar mass of oxygen is 32 g/mol, so:
25.0 g O2 ÷ 32 g/mol = 0.78125 mol O2
Since the stoichiometry of the reaction shows that two moles of NO2 are produced for every one mole of O2, the next step is to calculate the number of moles of NO2 produced:
0.78125 mol O2 × 2 mol NO2/1 mol O2 = 1.5625 mol NO2
Finally, the mass of NO2 can be calculated by multiplying the number of moles of NO2 by its molar mass, which is 46 g/mol:
1.5625 mol NO2 × 46 g/mol = 71.875 g NO2
Therefore, 71.875 grams of NO2 can be produced when 25.0 g of oxygen reacts in this reaction.
To know more about oxygen, visit:
https://brainly.com/question/13370320#
#SPJ11
Calculate the moles of barium phosphate that will react with 1.60 g of aluminum hydroxide. you need to write and balance the equation, then solve it.
A total of 0.0103 moles of barium phosphate will react with 1.60 g of aluminum hydroxide.
The balanced chemical equation for the reaction between barium phosphate and aluminum hydroxide is:
Ba₃(PO₄)₂ + 2 Al(OH)₃ → 2 AlPO₄ + 3 Ba(OH)₂
To calculate the moles of barium phosphate that will react with 1.60 g of aluminum hydroxide, we need to convert the given mass of aluminum hydroxide into moles using its molar mass:
Molar mass of Al(OH)₃ = 78 g/mol
Number of moles of Al(OH)₃ = 1.60 g / 78 g/mol = 0.0205 mol
According to the balanced chemical equation, 2 moles of Al(OH)3 react with 1 mole of Ba3(PO4)2. Therefore, the number of moles of Ba₃(PO₄)₂ required can be calculated as:
Number of moles of Ba₃(PO₄)₂ = (0.0205 mol Al(OH)₃) / 2 = 0.0103 mol
To know more about balanced chemical equation click on below link:
https://brainly.com/question/28294176#
#SPJ11
Under what circumstances is an exothermic reaction non-spontaneous?.
An exothermic reaction is spontaneous if the overall Gibbs free energy change (ΔG) is negative, indicating that the reaction is energetically favorable and will proceed without an external energy input. However, an exothermic reaction can become non-spontaneous under certain circumstances.
One such circumstance is when the entropy change (ΔS) is negative. If ΔH is negative (exothermic) but ΔS is also negative (decrease in disorder), the value of ΔG could still be positive (non-spontaneous) or close to zero (at equilibrium) at temperatures where ΔH is not sufficiently large to overcome the negative ΔS.
This means that even though energy is released during the reaction, the decrease in disorder can make the reaction unfavorable.
Another circumstance is when the reactants are in a highly ordered or low-energy state, and the products are in a highly disordered or high-energy state. In such cases, the enthalpy change (ΔH) may be negative (exothermic), but the entropy change (ΔS) is also positive, and the resulting ΔG value may still be positive, making the reaction non-spontaneous.
To know more about exothermic reaction refer to-
https://brainly.com/question/10373907
#SPJ11
B) Express the answer to this multistep calculation using the appropriate number of significant figures: 87. 95 feet x 0. 277 feet +5. 02 feet - 1. 348 feet + 10. 0 feet.
The answer to the multistep calculation, expressed using the appropriate number of significant figures, is 24.3 feet.
In order to determine the appropriate number of significant figures in the answer, we need to follow the rules of significant figures for addition and subtraction.
When adding or subtracting numbers, the answer should be rounded to the same number of decimal places as the measurement with the least number of decimal places.
Here, the measurement with the least number of decimal places is 10.0 feet, which has one decimal place. Therefore, we should round the final answer to one decimal place as well.
Now, let's perform the calculation:
87.95 feet x 0.277 feet + 5.02 feet - 1.348 feet + 10.0 feet = 24.3108725 feet
Rounding to one decimal place, the final answer is:
24.3 feet
Therefore, the answer to the multistep calculation, expressed using the appropriate number of significant figures, is 24.3 feet.
To know more about significant figures refer here:
https://brainly.com/question/29153641
#SPJ11
How many liters would a 20 liter sample of gas at STP occupy if the
pressure was changed to 20 atmospheres and the temperature was changed to
38°C?
A 20-liter sample of gas at STP would occupy 5.68 liters if the pressure was changed to 20 atm and the temperature was changed to 38°C.
To solve this problem, we can use combined gas law, which relates the pressure, volume, and temperature of a gas. The formula for the combined gas law is:
[tex](P_1 * V_1) / (T_1 * n_1) = (P_2 * V_2) / (T_2 * n_2)[/tex]
where P1 and P2 are the initial and final pressures of the gas [tex]V_1[/tex] and [tex]V_2[/tex] are the initial and final volumes of the gas.
At STP, the conditions are 1 atmosphere of pressure and 0°C (273 K) of temperature.
Therefore, we can use these values as our initial conditions [tex](P_1 = 1\ atm, T_1 = 273 K)[/tex] and solve for [tex]V_2[/tex], the final volume of the gas:
[tex](P_1 * V_1) / T_1 = (P_2 * V_2) / T_2\\V_2 = (P_1 * V_1 * T_2) / (P_2 * T_1)[/tex]
Substituting the given values, we get:
[tex]V_2 = (1 atm * 20 L * 311 K) / (20 atm * 273 K) \\V_2 = 5.68 L[/tex]
To know more about STP, here
brainly.com/question/24050436
#SPJ4
the total volume of hydrogen gas needed to fill the hindenburg was l at atm and . given that for is , how much heat was evolved when the hindenburg exploded, assuming all of the hydrogen reacted to form water?
2.4453 × 10⁹ KJ energy was evolved when the total volume of hydrogen gas needed to fill the hindenburg was 2.09 × 10⁸ l at 1.00 atm and 25.1°
According to the given data,
Volume of the hydrogen gas = 2.09 × 10⁸ L
Pressure of the gas = P = 1 atm
Temperature of the gas =T = 25.1 °C =298.1 K
We know that, for an ideal gas equation
PV=nRT
1 atm ×2.09 × 10⁸ L = n × 0.0820 atmL/molK × 298.1 K
⇒n = 1 atm ×2.09 × 10⁸ L/ 0.0820 atmL/molK × 298.1 K
⇒n = 0.0855 ×10⁸ mol
ΔH for hydrogen gas is =-286 kJ/mol
For 0.0855 ×10⁸ mol energy evolved when hydrogen gas is burned =
0.0855 ×10⁸ mol × (-286 KJ/mol) = -2.4453 × 10⁹ KJ
Therefore, 2.4453 × 10⁹ KJ energy was evolved when it was burned.
To know more about energy evolved here
https://brainly.com/question/13196730
#SPJ4
The complete question is-
The total volume of hydrogen gas needed to fill the hindenburg was 2.09 × 108 l at 1.00 atm and 25.1°. how much energy was evolved when it burned?
If you needed to make 2. 5 L of a 0. 2 M fruit drink solution from the 0. 7 M drink solution, how would you do it? (Hint: Use McVc = MdVd to find the amount of concentrated solution you need, then add water to reach 2. 5 L. )
The volume of the fruit drink comes out to be 0.712 L which is calculated in the below section.
Using the dilution law,
M1 V1 = M2 V2......(1)
Here, M represents the molarity and V represents the volume.
The given parameters are as follows-
M1 = 0.2 M
V1 = 2.5 L
M2 = 0.7 M
To calculate the volume of the fruit drink after dilution, substitute the known values in equation (1) as follows-
0.2 M x 2.5 L = 0.7 M x V2
V2 = (0.2 M x 2.5 L) / 0.7 M
= 0.5 / 0.7 L
= 0.7142 L
The volume comes out to be 0.712 L.
To learn more about molarity check the link below-
https://brainly.com/question/30404105
#SPJ4
The temperature of CI 2 is changed from 836. 06 K to 625. 29 K. If its new volume is 14. 509 L, what was its original volume in liters?
The original volume of CI₂ was 19.33 L.
According to Charles' Law, the volume of a gas is directly proportional to its temperature at constant pressure. This can be expressed as V₁/T₁ = V₂/T₂, where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature.
In this problem, we are given the initial temperature (T₁ = 836.06 K), final temperature (T₂ = 625.29 K), and final volume (V₂ = 14.509 L). We are asked to find the initial volume (V₁). To do this, we can rearrange the Charles' Law equation to solve for V₁:
V₁ = (V₂/T₂) x T₁
Plugging in the values, we get:
V₁ = (14.509 L/625.29 K) x 836.06 K
V₁ = 19.35 L
As a result, the initial volume of CI₂ was 19.33 L.
To know more about the Temperature, here
https://brainly.com/question/30584358
#SPJ4
A 282. 8 g sample of copper releases 175. 1 calories of heat. The specific heat capacity of copper is 0. 092 cal/(g·°C). By how much did the temperature of this sample change, in degrees Celsius?
The temperature of this 282.8 g copper sample changed by approximately 6.78 degrees Celsius.
To find the temperature change of a 282.8 g sample of copper that releases 175.1 calories of heat with a specific heat capacity of 0.092 cal/(g·°C), we can use the following formula:
q = mcΔT
where:
q = heat released (calories)
m = mass of the sample (grams)
c = specific heat capacity (cal/(g·°C))
ΔT = temperature change (°C)
Step 1: Plug in the given values into the formula.
175.1 = (282.8)(0.092)(ΔT)
Step 2: Solve for ΔT.
ΔT = 175.1 / (282.8× 0.092)
Step 3: Calculate the value of ΔT.
ΔT ≈ 6.78 °C
So, the temperature of this 282.8 g copper sample changed by approximately 6.78 degrees Celsius.
To know more about specific heat capacity :
https://brainly.com/question/29766819
#SPJ11
Assume a gallon of gasoline contains 2370. 0 grams of octane. How many grams of carbon dioxide would be
produced by the complete combustion of the octane in this gallon of gasoline?
In 2017, people in the US used about 143 billion gallons of gasoline. How many grams of carbon dioxide
were generated by the combustion of this gasoline, assuming the value you calculated in the first question
was accurate?
The complete combustion of one gallon of gasoline containing 2370.0 grams of octane produces 6888.2 grams of carbon dioxide.
In 2017, people in the US generated approximately 9.85 x 10¹⁴ grams of carbon dioxide by burning 143 billion gallons of gasoline.
1. Write the balanced chemical equation for the combustion of octane:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
2. Determine the molecular weight of octane (C₈H₁₈) and carbon dioxide (CO₂):
C₈H₁₈: (8 x 12.01) + (18 x 1.01) = 114.23 g/mol
CO₂: (1 x 12.01) + (2 x 16.00) = 44.01 g/mol
3. Use stoichiometry to find the grams of CO₂ produced from the combustion of 2370.0 grams of octane:
(2370.0 g octane) x (16 mol CO₂/ 2 mol octane) x (44.01 g CO₂ / mol CO₂) = 6888.2 g CO₂
4. Calculate the total grams of CO₂ generated by burning 143 billion gallons of gasoline in the US in 2017:
(143 billion gallons) x (6888.2 g CO₂ / gallon) = 9.85 x 10¹⁴ grams of CO₂
To know more about balanced chemical equation click on below link:
https://brainly.com/question/28294176#
#SPJ11
Calculate the decrease in temperature when 3.00 L at 28.0 °C is compressed to 1.00 L.
Answer:
[tex]\huge\boxed{\sf T_2=100.3 \ K}[/tex]
Explanation:
Given data:Volume 1 = [tex]V_1[/tex] = 3.00 L
Volume 2 = [tex]V_2[/tex] = 1.00 L
Temperature 1 = [tex]T_1[/tex] = 28 °C + 273 = 301 K
Required:Temperature 2 = [tex]T_2[/tex] = ?
Formula:[tex]\displaystyle \frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex] (Charles Law)
Solution:Put the given data in the above formula.
[tex]\displaystyle \frac{3.00}{301} = \frac{1.00}{T_2} \\\\Cross \ Multiply\\\\3 \times T_2=301 \times 1\\\\3T_2= 301\\\\Divide \ both \ sides \ by \ 3\\\\T_2=301/3\\\\T_2=100.3 \ K\\\\\rule[225]{225}{2}[/tex]
If you have 500 ml of a 0.10 m solution of the acid, what mass of the corresponding sodium salt of the conjugate base do you need to make the buffer with a ph of 2.08 (assuming no change in volume)
The mass of the corresponding sodium salt of the conjugate base needed to make a buffer with a pH of 2.08.
To determine the mass of the corresponding sodium salt of the conjugate base needed to make a buffer with a pH of 2.08, you can follow these steps:
1. Identify the given information:
- Initial volume of acid solution: 500 mL
- Initial concentration of acid solution: 0.10 M
- Desired pH: 2.08
2. Use the Henderson-Hasselbalch equation:
pH = pKa + log ([conjugate base]/[acid])
3. Assuming the acid is a weak monoprotic acid (HA) and its conjugate base is A-, determine the pKa:
pKa = pH - log ([A-]/[HA])
4. Calculate the ratio of [A-] to [HA]:
[A-]/[HA] = 10^(pH-pKa)
5. Calculate the moles of HA in the 500 mL of 0.10 M solution:
moles of HA = (volume x concentration) = 500 mL x 0.10 mol/L = 0.050 mol
6. Calculate the moles of A- needed:
moles of A- = moles of HA x ([A-]/[HA]) ratio
7. Determine the molar mass of the sodium salt of the conjugate base (A-) using the molecular formula.
8. Calculate the mass of the sodium salt of the conjugate base:
mass = moles of A- x molar mass of A-
By following these steps, you will be able to determine the mass of the corresponding sodium salt of the conjugate base needed to make a buffer with a pH of 2.08.
To know more about conjugate base refer here: https://brainly.com/question/30086613#
#SPJ11
Use the drop-down menus to rank the boiling points of the following hydrocarbons. Use a "1" to indicate the compound with the lowest boiling point.
The boiling points of the hydrocarbons can be ranked as follows;
1. 4
2. 2
3. 3
4. 1
What controls the boiling points of the hydrocarbons?The size of the molecules and the nature of the intermolecular interactions between the molecules essentially determine the boiling points of hydrocarbons.
Because they have more electrons and a larger surface area available for intermolecular interactions like Van der Waals forces, larger hydrocarbon molecules typically have higher boiling points.
Additionally, polar hydrocarbons and those that can form hydrogen bonds have higher boiling points than non-polar hydrocarbons because of stronger intermolecular forces.
Learn more about hydrocarbons:https://brainly.com/question/31643106
#SPJ1
PLEASE HELP. Complete the following table.
[H3O+] [OH−] pOH pH Acidic or Basic
1. 0×10−8 1. 0×10−6 6. 00 8. 00 basic
_____ _____ _____ 3. 05 _____
9. 7×10−9 _____ _____ _____ _____
_____ _____ _____ 13. 79 _____
_____ 9. 6×10−11 _____ _____ _____
Part A
Complete the first column of the table.
Part B
Complete the second column of the table.
Part C
Complete the third column of the table.
Part D
Complete the fourth column of the table.
Part E
Complete the fifth column of the table
The answer to the part A, B, C, D and E are as follows-
Part A: [tex][H3O+] [OH−] pOH[/tex] pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part B:
[tex][H3O+] [OH−] pOH[/tex] pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part C:
[tex][H3O+] [OH−] pOH[/tex]pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part D:
[tex][H3O+] [OH−] pOH[/tex]pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part E:
[tex][H3O+] [OH−] pOH[/tex]pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
To know more about acidic refer to-
https://brainly.com/question/14072179
#SPJ11
Walking at a brisk pace burns off about 280 cal/h. how long would you have to walk to burn off the calories obtained from eating a cheeseburger that contained 25 g of protein, 25 g of fat, and 31 g of carbohydrates? [hint: one gram of protein or one gram of carbohydrate typically releases about 4 calg, while fat releases 9 cal/g. ] hours
You would need to walk at a brisk pace for about 1 hour and 40 minutes to burn off the calories obtained from eating the cheeseburger.
25 g of protein and 31 g of carbohydrates release 4 cal/g, which equals 240 calories. 25 g of fat release 9 cal/g, which equals 225 calories. So, the total calories in the cheeseburger are 465.
Now, to burn off 465 calories at a rate of 280 cal/h, we need to divide 465 by 280, which equals 1.66 hours or approximately 1 hour and 40 minutes.
In summary, to burn off the calories obtained from a cheeseburger containing 25 g of protein, 25 g of fat, and 31 g of carbohydrates, you would need to walk at a brisk pace for about 1 hour and 40 minutes.
To know more about carbohydrates click on below link:
https://brainly.com/question/29775112#
#SPJ11
What is the freezing point of a solution of 0. 300 mol of lithium bromide in 525 mL of water?
The freezing point of the solution is approximately 1.06306 °C
The freezing point of a solution of 0.300 mol of lithium bromide in 525 mL of water would be lower than the freezing point of pure water. The exact freezing point depression can be calculated using the formula ΔTf = Kf·m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant of water (1.86 °C/m), and m is the molality of the solution. To find the molality of the solution, we need to convert the volume of water to mass using its density (1 g/mL), which gives us 525 g of water. Then, we can calculate the molality as:
molality = moles of solute/mass of solvent in kg
= 0.300 mol / 0.525 kg
= 0.571 mol/kg
Substituting this value into the freezing point depression formula, we get:
ΔTf = 1.86 °C/m x 0.571 mol/kg
= 1.06306 °C
Therefore, the freezing point of the solution would be lowered by 1.06 °C compared to pure water.
Learn more about freezing point at https://brainly.com/question/40140
#SPJ11
6. Consider the molecule xylene; and predict its reaction behavior with
1. Bromine solution
2. KMn04
3. AlCl3 and CHCI;
1. Xylene will react with bromine solution to undergo electrophilic aromatic substitution, where bromine will replace one of the hydrogen atoms on the aromatic ring.
2. Xylene will not react with KMnO₄ under normal conditions as it is a relatively stable aromatic compound.
3. Xylene can react with AlCl₃ and CHCl₃ under Friedel-Crafts conditions to form a substituted product. AlCl₃ acts as a Lewis acid, facilitating the reaction by generating a carbocation intermediate, which is then attacked by the chloride ion from CHCl3 to form a substituted product.
In summary, xylene will undergo electrophilic aromatic substitution with bromine solution, will not react with KMnO₄, and can undergo Friedel-Crafts reaction with AlCl₃ and CHCl₃ to form a substituted product.
To know more about electrophilic aromatic substitution click on below link:
https://brainly.com/question/28286554#
#SPJ11
A decomposition of hydrogen peroxide into water and oxygen gas is an exothermic reaction. If the temperature is initially 28˚ C, what would you expect to see happen to the final temperature? Explain what is happening in terms of energy of the system and the surroundings.
If the decomposition of hydrogen peroxide into water and oxygen gas is an exothermic reaction, we would expect the final temperature to be lower than the initial temperature of 28˚C.
This is due to the fact that energy is released from the system during an exothermic reaction in the form of heat into the surroundings. In other words, the energy of the reactants is more than that of the products, and the excess energy is released into the environment.
As a result, the environment's temperature will rise, while the system's temperature will fall. This indicates that the reaction's final temperature will be lower than its 28° C starting point.
To learn more about an exothermic reaction, follow the link:
https://brainly.com/question/10373907
#SPJ1
which statement describes an experimental step(s) that is necessary to determine the molar mass using the freezing point depression method? measure the heat of fusion of the pure solvent and then measure the heat of fusion of the pure solute. measure the freezing point of the pure solvent and then measure the freezing point of the solution. determine the molar mass of the solute by looking up the elements in the periodic table. calculate the number of moles in a kilogram of solvent to determine its molality.
The experimental step necessary to determine the molar mass using the freezing point depression method is to measure the freezing point of the pure solvent and then measure the freezing point of the solution. The statement 2 is correct.
The freezing point depression method is a common technique used to determine the molar mass of a solute dissolved in a solvent. The method is based on the principle that the presence of a solute lowers the freezing point of the solvent. By measuring the change in the freezing point of the solvent caused by the solute, it is possible to calculate the molar mass of the solute. Correct answer is option 2.
To know more about freezing point, here
brainly.com/question/31357864
#SPJ4
--The complete Question is, which statement describes an experimental step(s) that is necessary to determine the molar mass using the freezing point depression method?
1. measure the heat of fusion of the pure solvent and then measure the heat of fusion of the pure solute.
2. measure the freezing point of the pure solvent and then measure the freezing point of the solution.
3. determine the molar mass of the solute by looking up the elements in the periodic table. 4. calculate the number of moles in a kilogram of solvent to determine its molality. --
If a gas is cooled from 523 K to 273 K and volume is kept constant
what final pressure would result if the original pressure was 745 mm
Hg?
Answer:
388.88 mmHg (2 d.p.)
Explanation:
To find the final pressure when the volume is kept constant, we can use Gay-Lussac's law.
Gay-Lussac's law[tex]\boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}[/tex]
where:
P₁ is the initial pressure.T₁ is the initial temperature (in kelvins).P₂ is the final pressure.T₂ is the final temperature (in kelvins).The values to substitute into the equation are:
P₁ = 745 mmHgT₁ = 523 KT₂ = 273 KSubstitute the values into the equation and solve for P₂:
[tex]\implies \sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]
[tex]\implies \sf \dfrac{745}{523 }=\dfrac{P_2}{273}[/tex]
[tex]\implies \sf P_2=\dfrac{745 \cdot 273}{523 }[/tex]
[tex]\implies \sf P_2=\dfrac{203385}{523 }[/tex]
[tex]\implies \sf P_2=388.88145315...[/tex]
[tex]\implies \sf P_2=388.88\;mmHg\;(2\;d.p.)[/tex]
Therefore, the final pressure would be 388.88 mmHg if a gas is cooled from 523 K to 273 K and the volume is kept constant, starting with an initial pressure of 745 mmHg.
Use the Beer’s law plot and best fit line to determine the concentrations for samples: M21050-1 0. 359
M21050-2 0. 356
M21050-3 0. 339
M21050-4 0. 376
M21050-5 0. 522
Beer's law establishes a connection between a substance's concentration in a solution and its absorbance at a certain wavelength.
By charting the absorbance vs concentration of each solution, a Beer's law plot is created in order to calculate concentrations of a series of copper(II) sulfate solutions with known absorbances at a set wavelength. The resulting graph should be a straight line that the least-squares approach can fit with a linear equation. The molar absorptivity is represented by slope of the best-fit line, and the absorbance at zero concentration is represented by the y-intercept. By measuring the absorbance of the unknown copper(II) sulfate solutions and solving for concentration using the equation, the concentrations of unknown solutions can be found.
To know more about Beer's law, here
brainly.com/question/30723190
#SPJ4
--The complete Question is, Use Beer's law plot and best-fit line to determine the concentrations for a series of copper(II) sulfate solutions with known absorbances at a fixed wavelength. --
Benzene at 20°C has a viscosity of 0. 000651 Pa. S. What shear stress is required to deform this fluid at a velocity gradient of 4900 s-1 ?
To calculate the shear stress required to deform benzene at a velocity gradient of 4900 s-1, we can use the equation:
Shear stress = viscosity x velocity gradient
Plugging in the given values, we get:
Shear stress = 0.000651 Pa. S x 4900 s-1
Shear stress = 3.19 Pa
Therefore, a shear stress of 3.19 Pa is required to deform benzene at a velocity gradient of 4900 s-1.
What is Shear stress?
Shear stress is a type of stress that occurs when a force is applied parallel to a surface or along a plane within a material. It is the result of the force causing the material to deform or change shape, with one part of the material sliding or shearing over another part.
Shear stress is often described in terms of the shear force per unit area, or shear strength, that is required to cause the material to shear or deform. The unit of measurement for shear stress is typically in pascals (Pa) or pounds per square inch (psi).
To know more about Shear stress:
https://brainly.com/question/12910262
#SPJ11
2.
for the reaction c + 2h2 - ch4, how many grams of hydrogen are required
to produce 0.6 moles of methane, ch4 ?
cannu help em do the whole paper
1.21 grams of hydrogen are required to produce 0.6 moles of methane (CH₄) in the given reaction.
The given reaction is:
C + 2H₂ → CH₄
We can see that 2 moles of hydrogen (H₂) are required to produce 1 mole of methane (CH₄) according to the balanced chemical equation. Therefore, to produce 0.6 moles of methane, we will need 2 times as many moles of hydrogen, which is:
number of moles of hydrogen = 2 × number of moles of methane
number of moles of hydrogen = 2 × 0.6 moles
number of moles of hydrogen = 1.2 moles
To convert the number of moles of hydrogen to grams, we need to use the molar mass of hydrogen, which is approximately 1.008 g/mol. Thus, the mass of hydrogen required can be calculated as:
mass of hydrogen = number of moles of hydrogen × molar mass of hydrogen
mass of hydrogen = 1.2 moles × 1.008 g/mol
mass of hydrogen = 1.21 g
To learn more about hydrogen follow the link:
https://brainly.com/question/31018544
#SPJ4
The complete question is:
For the reaction C+2H₂ → CH₄, how many grams of hydrogen are required to produce 0.6 moles of methane, CH₄?
What mass of dilute trioxonitrate (V) containing 10% W/W of pure acid will be required to dissolve 2. 5g chalk CaCO3
31.45 g of dilute trioxonitrate (V) acid containing 10% W/W of pure acid will be required to dissolve 2.5 g of chalk.
We need to use balanced chemical equation of the reaction between calcium carbonate and trioxonitrate (V) acid to determine the number of moles of acid required to dissolve 2.5 g of chalk.
[tex]CaCO_3 + 2HNO_3 → Ca(NO_3)_2 + CO_2 + H_2O[/tex]
From the equation, one mole of [tex]CaCO_3[/tex] reacts with two moles of [tex]HNO_3[/tex]. The molar mass of CaCO3 is 100.09 g/mol.
[tex]Number\ of\ moles\ of\ CaCO_3 = 2.5 g / 100.09 g/mol = 0.02498 mol[/tex]
[tex]Number\ of\ moles\ of HNO_3 = 2 * 0.02498 = 0.04996 mol[/tex]
Now, we can calculate the mass of dilute trioxonitrate (V) acid containing 10% W/W of pure acid required to provide 0.04996 mol of [tex]HNO_3[/tex].
Assuming the density of the dilute trioxonitrate (V) acid is 1.1 g/cm3, the mass of the acid required will be:
[tex]Mass\ of\ acid = (0.04996 mol * 63.01 g/mol) / 0.1 = 31.45 g[/tex]
To know more about calcium carbonate, here
brainly.com/question/13565765
#SPJ4
A student claimed that a sample of pyrite at 25°c with a volume of 10 cm3 would
have a mass of 2 g. using the explanation of density given in the passage, explain
how the student incorrectly calculated the mass of the sample of pyrite. then,
determine the actual mass of the 10 cm sample of pyrite.
The student incorrectly calculated the mass of the sample of pyrite by assuming the density of pyrite to be 2 g/cm³, which is actually the density of water. The actual density of pyrite is about 5 g/cm³, so the actual mass of the 10 cm³ sample would be 50 g.
The student likely confused the concept of density, which is the mass per unit volume of a substance, with the specific gravity, which is the ratio of the density of a substance to the density of water.
Pyrite has a specific gravity of about 5, meaning that its density is about 5 times greater than that of water. Therefore, the mass of a 10 cm³ sample of pyrite would be 5 times greater than the mass of a 10 cm³ sample of water, or 50 g.
To learn more about Pyrite, here
https://brainly.com/question/13435246
#SPJ4
Find the molarity of 194. 55 g of sugar (C12H22O11) in 250. ML of water
To find the molarity of a solution, we need to know the number of moles of solute (in this case, sugar) and the volume of the solution in liters. We can use the given mass of sugar and the molar mass of sugar to find the number of moles:
Mass of sugar = 194.55 g
Molar mass of sugar (C12H22O11) = 342.3 g/mol
Number of moles of sugar = Mass of sugar / Molar mass of sugar
Number of moles of sugar = 194.55 g / 342.3 g/mol
Number of moles of sugar = 0.568 mol
Now we need to convert the given volume of the solution (250 mL) to liters:
Volume of solution = 250 mL
Volume of solution = 250 mL / 1000 mL/L
Volume of solution = 0.250 L
Finally, we can use the number of moles of sugar and the volume of the solution to calculate the molarity:
Molarity = Number of moles of sugar / Volume of solution
Molarity = 0.568 mol / 0.250 L
Molarity = 2.27 M
Therefore, the molarity of the sugar solution is 2.27 M.
To know more about molarity refer here
https://brainly.com/question/31545539#
#SPJ11