Answer:
0.67 ms
Explanation:
The total time it takes the sound to enter and leave the water is t and
t = t' + t" where t' = total time of sound in air = d'/v' where d' = total distance sound travels in water = 2D (since the sound waves passes through the water twice )where D = distance travelled from water to surface of copper block = 0.45 m and v' = speed of sound in water = 1500 m/s and t" = total time of sound in copper = d"/v" where d" = total distance sound travels in copper block = 2D' (since the sound waves passes through the copper block twice )where D' = thickness of copper block = 0.15 m and v" = speed of sound in water = 4600 m/s
So, t = t' + t"
t = d'/v' + d"/v"
t = 2D/v' + 2D'/v"
Substituting the values of the variables into the equation, we have
t = 2 × 0.45 m/1500 m/s + 2 × 0.15 m/4600 m/s
t = 0.90 m/1500 m/s + 0.30 m/4600 m/s
t = 0.0006 s + 0.000065 s
t = 0.000665 s
t = 0.665 ms
t ≅ 0.67 ms
Note that the sound wave passes through the water and copper block without refracting since it enters perpendicularly. Also, the sound wave passes twice through each of the copper block and water hence the total distance in each material is twice the initial distance or thickness.
Answer:
t = 6.63 10⁻⁴ s
Explanation:
The speed of sound is constant in a given material medium, so to calculate time we can use the uniform motion relationships
v = d / t
t = d / v
the speeds of sound in the three media are
air v = 343 m / s
water v₁ = 1493 m / s
copper v₂ = 5010 m / s
the distance traveled in the water on the round trip is
d = 2 x
d₁ = 2 0.45 0.90m
the time to travel this distance is
t₁ = d₁ / v₁
t₁ = 0.9 / 1493
t₁ = 6.028 10⁻⁴ s
the distance in the copper
d₂ = 2 0.15 m
d₂ = 0.30 m
the time to travel this distance in copper is
t₂ = d₂/ v₂
t₂ = 0.30 / 5010
t₂ = 5.988 10⁻⁵-5 s
the total travel time is
t = t₁ + t₂
t = 6.028 10⁻⁴ + 0.5988 10⁻⁴
t = 6.6268 10⁻⁴ s
t = 6.63 10⁻⁴ s
the potential energy of a stone on the earth surface is zero why
Answer:
because potential energy is the kinetic energy something COULD have. Like when a rollercoaster is about to go over a bump, before it goes down it has potential energy, then when it goes it accelerates and creates kinetic energy. That rock be zero cause it has no potential
Explanation:
In a computer, the __________________________ chips are magnetic.
Kenny and Chris are walking down the road. They walk a distance of 250meters in
50 seconds. What was their average speed? (remember to choose the correct units!)
Explanation:
Distance is 250m
Time is 50sec
Formular
Speed= distance/time
Speed=250/50
Speed is 5m/s
If correct mark as brainliest
Answer:
[tex]\boxed {\boxed {\sf 5 \ m/s}}[/tex]
Explanation:
Speed is the rate an object moves. It is found by dividing the distance by the time.
[tex]s=\frac{d}{t}[/tex]
Kenny and Chris walked a distance of 250 meters in 50 seconds. So:
d= 250 m t= 50 sSubstitute the values into the formula.
[tex]s=\frac{250 \ m}{ 50 \ s}[/tex]
Divide.
[tex]s= 5 \ m/s[/tex]
Kenny and Chris had an average speed of 5 meters per second.
Two spherical objects have masses of 8,000 kg and 5.0 kg. Their centers are separated by a distance of 1.5 m. Find the gravitational attraction between them.
The gravitational force of attraction between them is 3.56 * 10⁻⁴ N
What is Gravitational attraction?F = G*M1M2/d²,
where G = 6.67 * 10⁻¹¹ Nm²Kg⁻²,
M1 = 8000Kg and M2 = 1500 Kg,
F = 6.67 * 10⁻¹¹ * 8000 * 1500 / (1.5)² F = 3.56 * 10⁻⁴ N
The gravitational force of attraction between them is 3.56 * 10⁻⁴ N.
The universal gravitational law of Newton. According to this law, every body in the universe is attracted to every other body with a force that is inversely proportional to the square of the distance between them and proportional to the product of their masses.
Therefore, The gravitational force of attraction between them is 3.56 * 10⁻⁴ N.
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An air puck of mass 0.304 kg is tied to a string and allowed to revolve in a circle of radius 0.44 m on a horizontal, frictionless table. The other end of the string passes through a hole in the center of the table and a mass of 1.15 kg is tied to it. The suspended mass remains in equilibrium while the puck revolves. 0.44 m v 1.15 kg 0.304 kg What is the tension in the string
The tension in the string can be found by using the equation for centripetal force. which is equal to 150.
This equation states that the centripetal force (Fc) is equal to the mass of the object (m) multiplied by the square of the velocity (v) and divided by the radius (r). Therefore,
Fc = m x v²/r.
In this case, the centripetal force is equal to the tension in the string, so the tension in the string (T) can be found by rearranging the centripetal force equation to
T = m x v²/r.
Substituting in the given values for mass (m) and radius (r) gives
T = 0.304 kg x (2.83 m/s)²/0.44 m
T= 150N
Therefore the tension of the string is 150N
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Marc’ favorite ride at Busch Gardens is the Flying Umbrella, which is lifted by a hydraulic jack. The operator activates the ride by applying a force of 72N to a 30cm2 cylindrical piston, which holds the 20,000N ride off the ground. What is the area of the piston that holds the ride?
The area of the piston that holds the ride is 8333,33 [tex]cm^{2}[/tex]
For hydraulic press system pressure in = pressure out
P = Pressure
F = Force
A = Area
The formula P = [tex]\frac{F}{A}[/tex]
We know F1 = 72 N, A1 = 30 [tex]cm^{2}[/tex]
F2 = 20000 N
The area of the piston that holds the ride = A2
P 1 = P2
[tex]\frac{F1}{A1}[/tex] = [tex]\frac{F2}{A2}[/tex]
[tex]\frac{72 N}{30 cm^{2} }[/tex] = [tex]\frac{20000 N}{A2}[/tex]
A2 = 20000 N : ( [tex]\frac{72 N}{30 cm^{2} }[/tex] )
A2 = ( 20000 N x 30 cm2 ) : 72 N
= 8333,33 cm2
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The motion of a particle is described by x= 10 sin2t + 8cos2t. Determine the period, amplitude and phase angle
Answer:
Explanation:
period is 2pi / B which is 2pi/8 which is 1/4 pi
amplitude is a which is 10
Item 3 A 5kg object is released from rest near the surface of a planet such that its gravitational field is considered to be constant. The mass of the planet is unknown. After 2s, the object has fallen 30m. Air resistance is considered to be negligible. What is the gravitational force exerted on the 5kg object near the pl
So because acceleration of freely falling objects is constant, if a 5 kilogram object starts free falling at rest, its acceleration at 3 seconds is g=9.8 m/s2 or 32.2 ft/s2.
What happens to an object's weight as it travels through space away from a planet?As the gravitational pull of an object changes as it is moved further away from Earth or placed on another planet, so does the object's weight. Regardless of whether an object is on Planet, in deep space, or on the Moon, its mass will always be the same.
How can gravitational potential energy be used to determine weight?For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters. Notice that gravitational potential energy has the same units as kinetic energy, kg m2 / s2.
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On a wheel and axle, if the large wheel has a radius of 20 cm and the small wheel has a radius of 4 cm, what is the ideal mechanical advantage
The ideal mechanical advantage is 5.
Here, we have value larger radius , R = 20 cm and smaller radius = 4 cm
So, as per the problem, mechanical advantage will be 20/4 = 5.
A wheel and axle must be permanently joined in order to be considered a simple machine, and the wheel must by definition have a bigger radius than the axle. A point on the wheel moves a distance of 2 R whereas a point on the axle moves a distance of 2 r when you turn the wheel through a full revolution, which likewise causes the axle to turn through a full revolution.
The force you apply F R times the distance the point moves equals the effort W required to move a point on the wheel through one full revolution. Work is energy, and since energy must be conserved, a point on the axle must be subjected to a larger force F r because it moves a shorter distance.
The mathematical relationship is:
W = Fr (subscript) ×2πr/θ =F r(subscript) ×2πR/θ
Where θ is the angle that the wheel is turned.
And therefore:
Fr(r in subscript) / FR(R in subscript) = R/r
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State the Boyle's Law. If the graph for Boyle's law is straight line through the origin then state the quantity taken along: a) X-axis , b)Y-axis.(NOTE: Please clearly mention the quantities appropriately by mentioning the axes)
Answer:
(a) X- axis represent (1/P) inverse of pressure
(b) Y-axis represent (V) volume
Explanation:
Boyle's Law States that at constant temperature, the volume of a fixed mass of gas is inversly proportional to its pressure. It can be expressed mathematically as
V α 1/P
VPα1
removing the proportionality sign and introducing a constant
VP = k
V₁P₁ = V₂P₂
Where V₁ and V₂ are initial and final volume respectively, P₁ and P₂ are initial and final pressure respectively.
If the graph for Boyle's law is straight line through the origin,
(a) X-axis represent (1/P) inverse of pressure
(b) Y- axis represent (V) volume.
The polarization of light is a phenomena that is best explained by
Answer:
एकच
Explanation:
डॉ बाळगू गमच दाखल सकाळी एकदिवसीय
Explanation:
the wave model of electromagnet
Assume that g is 10 N/kg and that air resistance and other
frictional forces are negligible.
1 )An object has a mass of 6 kg What is its gravitational potential energy
a( 4 m above the ground
b) 6 m above the ground?
2) An object of mass 6 kg has a speed of 5 m/s.
a What is its kinetic energy?
b What is its kinetic energy if its speed is doubled?
3 A ball of mass 0.5 kg has 100 J of kinetic energy. What
is the speed of the ball?
help with this its very important plss
Answer:
1) Given acceleration due to gravity as 10N/kg
N/kg is the same as m/s². From W=mg
making g subject ... you have g = W/m
where m is in kg and W is in N
hence we have N/kg
So g=10ms-²
Gravitational Potential Energy=mgh
At height 4m
PE=6 x 10 x 4
=240J.
At height 6m
PE=6 x 10 x 6
=360J.
2) KE=1/2mv²
=1/2 x 6 x 5² =75J
When the speed is doubled... it becomes 2x
so V = 2x5=10ms-¹
KE=1/2 x 6 x 10² =300J.
3) KE=1/2mv²
KE is given as 100J
mass=0.5kg
Making V the subject
you have v² =2KE/m
v²=2 x 100/0.5
v²=400
taking square root
v=20ms-¹.
Have a great day✌
An object with mass of 50kg moves with
velocity of 11. 2m/s and an event occur
whereby it transfers 1539 of energy to
another objects as work.
What is the new
velocity of the object after the event??
The new velocity of the object after the event is 7.99m/s.
We are given that,
Mass = m = 50kg
Initial velocity = v = 11.2m/s
Energy = E = 1539j
The kinetic energy of object can be calculated as,
K= (1/2)mv²
K = (50×125.44)/2
K = 3136J
Consequently, since both the initial kinetic energy and the total amount of energy transferred are known. The article's resulting energy is easily discernible.
Final energy = initial kinetic energy - the ending energy
Final energy = 3136-1539= 1597 joules
Therefore, using the equation for kinetic energy derivation, the speed of the object can now be determined.
K.E = 1/2MV²
1597 = 50/2V²
3194 = 50V²
V = 7.99m/s
Therefore , the new velocity of the object after the event would be 7.99m/s.
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A particular power source creates electricity through the use of giant magnets that are rotated to create a flow of electrons. This electricity is then directed:
This electricity is then directed from the electric generator to electric outlets in homes
A power source that creates electricity through the use of giant magnets that are rotated to create a flow of electrons is called a generator. Generators use the principle of electromagnetic induction to convert mechanical energy (rotational energy of the magnets) into electrical energy.The electricity generated by the generator is then directed through electrical transmission lines to a substation, where it is transformed to a higher voltage level for long-distance transmission. Then it is distributed to homes and businesses through power lines and transformers.
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_____ is the term that refers to making something magnetic.
[tex] \huge{ \texttt{ANSWERS}}[/tex]
MAGNETIZATION
In most materials, magnetization occurs when a magnetic field is applied to a body. a material is the density of magnetic bipolar moments that are magnetized by the metal, a separation process that takes place when one of its components is ferromagnetic,Anxiety disorders can become a pathological disorder when feelings of apprehension and fear __________.
a. are recurrent for less than six months
b. are inherited due to genetics
c. become excessive, uncontrollable, and affect daily life
d. are controllable but excessive
please select the best answer from the choices provided a b c d
When feelings of anxiety and worry become excessive, out of control, and interfere with daily life, they can develop into pathological diseases called anxiety disorders. So the correct option is (c).
Anxiety disorders are characterized by feelings of apprehension and fear, which are normal human emotions. However, when these feelings become excessive, uncontrollable, and affect daily life, they can be considered a pathological disorder. Anxiety disorders can affect a person's ability to perform daily activities, such as work or school, and can also cause physical symptoms such as insomnia, muscle tension, and fatigue. These disorders can be recurrent, but they need to be excessive, uncontrollable, and affect daily life in order to be considered pathological.
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in an experiment to determine the refractive index of water a black line is cleaned it on the bottom of a tall glass container, which then partially filled with water. On looking vertically down into the water the black line appears to be closer that it really is
It is true that on looking vertically down into the water the black line appears to be closer that it really is.
What is refractive index?A material's refractive index, which is quantified, indicates how much a light path is bent or refracted when it penetrates that material.
The critical angle for total internal reflection and the amount of light that is reflected when it reaches the contact are both determined by the index of refraction.
Due to the refraction of light rays as they pass through water and into the air, an item seen in the water typically appears to be deeper than it actually is.
Since the angle subtended by the object is greater, it "appears" larger because the light's refraction away from the normal changes the angle at which the light appears at the eye.
Thus, the given scenario is true.
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Where the ungrounded conductors for a 225-ampere feeder are increased in size from 250 kcmil copper to 800 kcmil copper due to length, what is the minimum-size copper equipment grounding conductor required for the circuit?
The minimum-size copper equipment grounding conductor required for the circuit is 1/0 kcmil.
The NEC (National Electric Code) provides guidelines for the minimum size of equipment grounding conductors.The minimum size of the equipment grounding conductor is based on the ampacity of the feeder circuit.In this case, the ampacity of the feeder circuit is 225 amperes.The conductors for the feeder circuit have been increased in size from 250 kcmil to 800 kcmil due to the length of the circuit.According to the NEC (National Electric Code), the minimum size copper equipment grounding conductor required for a 225-ampere feeder circuit where the conductors have been increased in size from 250 kcmil to 800 kcmil due to length would be 1/0 kcmil.Learn more about conductors here:
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A worker uses a pulley (Links to an external site.) system to raise a 225 N carton 16.5 m. A force of 129 N is exerted and the rope is pulled 33.0 m. What is the IMA of the system
Answer: 1.74
Explanation: “How do you calculate the mechanical advantage of a block and tackle pulley?To calculate the mechanical advantage, we can either divide the weight of the object being lifted by the force required to lift it or we can divide the amount of rope we have to pull by the distance the object moves."If we use the rope method the mech advantage is 33.0/16.5 = 2 now if we use the forces MA = 225/129 =1.74 <==== this is not equal to '2' as we first found due to energy being lost to friction/deformation of rope etc. SO I would say the truemechanical advantage = 1.74 Efficiency = 1.74/2 = 87%
In 1935, a french destroyer , La Terrible , started from rest and accelerates to attain a speed of 93 km/h. Suppose it took 2 minutes for the ship to speed up. Find the ships average acceleration.
According to the given statement The ships average acceleration is 2790 km/hr².
What is an explain acceleration?Rate of change in both speed and direction of motion over time. A point or object going straight forward is accelerated when it accelerates or decelerates. Even though the speed is constant, motion on a circle accelerates because of direction is always shifting
Calculation:We know that from newton's equation,
v² + u² = 2as
S = ut + 0.5 at²
Where, v = final speed
u = initial speed
a = acceleration
S = distance covered
t = time taken
Given, u = 0
So the equations becomes:
v² = 2as
S = 0.5 at²
Using these equations we get:
v² = 2a(0.5)at²
v² = a²t²
v = at
v/t = a
Given, v = 93 km/hr
t = 2 min = 2/60 hr
Putting these values in above equation we get, a = 2790 km/hr²
So, the ships average acceleration is 2790 km/hr²
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Contrast the force of gravity between these
pairs of objects: a 1-kg mass and a 2-kg
mass that are 1 m apart; a 1-kg mass and a
2-kg mass that are 2 m apart; and two 2-kg
masses that are 1 m apart.
The force of gravity between these pairs of objects: a 1-kg mass and a 2-kg mass that are 1 m apart is 13.[tex]10^{-11}[/tex]34N.
For 2 m apart 6.67[tex]10^{-11}[/tex]N.
For 2-kg mass that are 2 m apart; and two 2-kg masses that are 1 m apart is 26.68N.
How many gravitational forces are there?The resultant (vector sum) of two forces is the force of gravity on Earth: (a) the gravitational pull according to Newton's universal law of gravitation; and (b) the centrifugal force, which is the outcome of choosing an earthbound, rotating frame of reference.
Force between two object is calculated f=Gmm/r^2.
G=6,67*10^-7
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Can anyone answer this question its a science question NO LINKS !!!!
Answer:
I think the correct answer is the skier at the top.
Explanation:
cause potential energy is equal to mgh.
here mass and gravitational acceleration is same for all 3, but the top fellow has more height
A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0. 20 km. What is the magnitude of the friction force required to keep the car from sliding?
The friction force required to keep the car from sliding is 9000N.
Calculation-mass of car, m = 1000 kg
speed , v = 30 m/s
diameter , d = 0.2 km
r = 100 m
for the car to keep from sliding frictional force is required, ff = m*v^2/r
ff = 1000 * 30^2 /100
ff = 9000 N
the friction force required is 9000 N
What kind of force does an automobile exert on a straightaway?Simply put, an unbanked curve (or turn) is a curve that is flat on the ground (parallel to the horizontal). A force of friction applies to the car as it drives along one of these curves, keeping it rotating in a circular course.
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What is the difference between the weight of an object and the mass of an object?
A body's mass is the total amount of its material. Gravitational pull on a body is represented by weight.
What is the difference between mass and weight?The relationship between mass and weight Mass is a measure of inertia, whereas weight is a measure of force.
Both of these names are frequently used in the same sentence. Calculating how much matter a body contains requires knowing its mass.
Weight is a unit of measurement for the force that gravity's acceleration has on a mass.
Weight is a measurement of how the force of gravity works upon a mass, whereas mass is a measure of the amount of matter in a material.
In order to determine how much matter a body contains, we need to use its mass.
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Press the hotspot that indicates the location that a string will experience the least tension during vertical circular motion. Assume that the speed of the ball remains constant.
which one will experience the least tension t3 t2 t1 or t4
The least tension will be experienced by T3
The weight of a moving object causes tension, which is the force applied along the length of a string, rope, or cable. The force that maintains an object moving in a circular direction when it is in a vertical circular motion is called tension. Perpendicular to the circle's radius, the tension in the string is pointed in the direction of the circle's centre.
Due to the centripetal force required to maintain the object moving in a circular motion, the tension in the string varies as the object moves in a vertical circle, with the highest tension occurring at the top of the circle and the least tension occurring at the bottom. In the given case, T3 will experience the least tension during vertical circular motion, assuming that the speed of the ball remains constant. This is because T3 is the point on the string that is closest to the circle's centre, and thus is subject to the least amount of tension as the ball moves in a vertical circle.
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How did the Japanese Tsunami (2011) happen and explain why it did happen?
just ask safari
Explanation:
Two friends A and B started at different times and covered 30km as shown in the graph.
Identify the correct statement from the following.
option 1 - A and B move with the same speed
option 2 - B moves with non-uniform speed
option 3 - A completes his journey early
option 4 - B overtakes A at 11:10 a.m.
Answer:
Explanation:
option 1 - A and B move with the same speed INCORRECT because the lines have different slopes
option 2 - B moves with non-uniform speed INCORRECT because the line for B is straight
option 3 - A completes his journey early INCORRECT because A ends his journey at about 11:45 after going about 42 km. B finishes his journey at about 11:35.
option 4 - B overtakes A at 11:10 a.m. CORRECT. They meet at the 30 km mark at 11:10, which is where the lines intersect.
If A and B are non-zero vectors, is it possible for A×B and A·B both to be zero?
It is important to note that the dot product and cross product of any two non-zero vectors cannot both be zero therefore A×B and A·B cannot both be zero.
What are non-zero vectors?In vector space, a non-zero vector. V is a vector that differs from the zero vector in V. If u is a non-zero vector in V and an is a scalar, i.e. an element of the field over which V is defined, then au=0 is only possible if a=0.
The product of any two non-zero vectors is non-zero in this vector context. It is referred to as Hamilton's Quaternions. Over the real numbers, quaternions form a four-dimensional vector space, and their multiplication is a combination of dot product and cross product.
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A 26 kg crate initially at rest on a horizontal floor requires a 70 N horizontal force to set it in motion. Find the coefficient of static friction between the crate and the floor.
The coefficient of static friction between the crate and the floor is calculated to be 0.275.
The frictional force when an object moves on the horizontal surface is given as,
Ff = μ N
where, N is the normal force
μ is the coefficient of static or kinematic friction
If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal force are equal in magnitude.
N = W = m g
Given that,
Mass of the crate = 26 kg
Frictional force Ff = 70 N
Weight of the crate = 26 × 9.8 = 254.8 N
The normal force is 254.8 N.
The coefficient of static friction μ = Ff /N = 70/254.8 = 0.275
Thus, the coefficient of static friction between the crate and the floor is 0.275.
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What is the relationship between torque and force lever arm length?
Torque is produced by multiplying the length of a lever arm by the force acting perpendicular to the lever arm. There are two conceivable orientations for the scalar quantity torque: clockwise and anticlockwise.
What is the result of the force times the lever arm?A torque is created when a force is applied perpendicular to a lever arm. The lever arm or moment arm is the length that extends perpendicularly from the pivot point, or the centre of rotation, to the point at which the force is applied. A torque is always defined with reference to a pivot point.
How can torque be multiplied?A torque multiplier multiplies the torque applied to the bolt with each gearing level. For instance, a 5:1 torque multiplier will result in an output.For example, a torque multiplier with a 5:1 ratio will result in an output at the shaft that is five times the torque, but the speed will only be one fifth of the original since no energy can be created.
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