The fundamental frequency will observe the change by the multiple of [tex]\sqrt{2}[/tex]
The fundamental frequency of a standing wave which has
string of length L
mass per unit meu
has the tension T
is given by f = 1/2L[tex]\sqrt{T/meu}[/tex]
Now we are required to find if the tension is doubled, with all other factors held constant, what will be the effect on the fundamental frequency
According to the formula,
the fundamental frequency f is directly proportional to the factor of square root
Hence, when the tension of the string is doubled while other factors of the system remain constant ,the formula will become
f= 1/2L[tex]\sqrt{2T/meu}[/tex]
Hence the change in the fundamental frequency will be of the factor [tex]\sqrt{2}[/tex]
Therefore, the change will be of [tex]\sqrt{2}[/tex]
Disclaimer: the question has missing part 1 and part 2 and hence part 1 has not been answered
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If a car's instantaneous velocity going down a ramp at 40cm is 2,105.3cm/s, predict the velocity of the car when it has traveled a distance of 70cm.
The velocity of the car will be 36.8 m/s when it has traveled a distance of 70 cm.
What is Instantaneous velocity?The velocity at any moment in time during a particle's motion is given by instantaneous velocity, a continuous function of time. By calculating the derivative of the position function, which gives us the functional form of instantaneous velocity v, we may determine the instantaneous velocity at a certain time (t).
Velocity is a vector quantity.
SI unit is m/s.
According to the question, the Given values are :
Distance =40 cm
=0.4 meter
Velocity, v =2105.3 cm/s
=21.053 m/s
21.053=0.4/t
⇒t=0.4/21.053
t=0.019 seconds
Now, the distance is 70 cm
=0.70 meters
v=0.7/0.019
v=36.8 m/sec
Hence, the velocity will be 36.8 m/sec when it has traveled a distance of 70 cm.
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An airplane is flying at 200 m/s at an angle of 30° north of east. How fast is the
plane flying North?
Can you please answer with clear working out .
in a rear tire skid when the rear wheel is not in line with the front wheel, you want to release the rear brake to quickly straighten the motorcycle.
False, because in a rear tire skid when the rear wheel is in line with the front wheel, you want to release the rear brake to quickly straighten the motorcycle.
What happens if the back wheel of your motorcycle locks up and starts to skid?
Understanding the rationale behind each correct response on the motorcycle written test is crucial for passing your motorbike permit examinations and developing into a safe rider.
When riding a motorcycle, a rear wheel skid can be a risky circumstance to encounter.
When the rear wheel locks up as a result of excessive braking, rear wheel skids happen.
You won't be able to turn around if the rear wheel locks up and starts to slide.
You must relieve the pressure on the rear brakes to stop the skidding of the rear wheels. However, the bike might quickly straighten out and knock you off in a high-side crash if the front and rear wheels are not in line when you remove the rear brake.
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in a certain city, electricity costs $0.10 per kw⋅h. what is the annual cost for electricity to power a lamppost for 7.00 h per day with a 100. w incandescent light bulb versus an energy efficient 25 w fluorescent bulb that produces the same amount of light? assume 1 year
The annual cost for electricity to power a lamppost for 7.00 h per day with a 100 W incandescent light bulb versus an energy efficient 25 W fluorescent bulb is $25.55 and $6.3875 respectively.
The Power is the amount of Energy produced per unit time.
The general formula for the annual cost can be written as:
[tex]Cost = P\cdot t\cdot d[/tex]
where. P is power, t is time in hours per day, and d is the total days.
Using the formula:
The cost of a 100 W incandescent light bulb:
[tex]Cost=(0.1)(7)(365)(0.10)=\$25.5[/tex]
Similarly,
The cost of a 25 W fluorescent light bulb:
[tex]Cost=(0.025)(7)(365)(0.10)=\$6.3875[/tex]
Hence, the annual cost is $25.55 and $6.3875 respectively.
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A vertical cylinder with a heavy piston contains air at 300 K . The initial pressure is 2.00 ×10⁵Pa , and the initial volume is 0.350m³ . Take the molar mass of air as 28.9 g/mol and assume CV = 5/2 R .(b) Calculate the mass of the air in the cylinder.
The mass of the air in the cylinder will be 0.811 Kg.
What is an ideal gas equation?The ideal gas law also referred to as the generic gas equation, is the equation of state for a hypothetical perfect gas. It is a good approximation of the behavior of several gases under diverse conditions, despite significant limitations.
Given that a vertical cylinder with a heavy piston contains air at 300 K . The initial pressure is 2.00 ×10⁵Pa, and the initial volume is 0.350m³. Take the molar mass of air as 28.9 g/mol.
The mass of the air in the cylinder will be calculated as below:-
P₁V₁ = nRT₁
n = ( P₁V₁ / RT₁ )
( m / M ) = ( P₁V₁ / RT₁ )
m = ( P₁V₁ M / RT₁ )
m = ( P₁V₁ M / RT₁ ) = ( 2 x 10⁵ x 0.35 x 0.0289 ) / ( 8.314 x 300 )
m = 0.811 Kg
Therefore, the mass of the air in the cylinder will be 0.811 Kg.
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please help in answering these 3 questions in science!!
(picture of questions attached)
GP Submarine A travels horizontally at 11.0 m/s through ocean water. It emits a sonar signal of frequency f = 5.27× 10³Hz in the forward direction. Submarine B is in front of submarine A and traveling at 3.00 m/s relative to the water in the same direction as submarine A. A crewman in submarine B uses his equipment to detect the sound waves ("pings") from submarine A. We wish to determine what is heard by the crewman in submarine B. (d) In Equation 17.19 , what speed of sound should be used?
The speed of sound used in water is 5408 Hz.
(d) The frequency that submarine B is able to detect is [tex]fo = fs (V -V_O/ v +V_s).[/tex]
[tex]=53.273[/tex] × [tex]10 3hz) (1533 m/s + 11 m/s / (45 m/s - 1533 m/s))[/tex]
Frequency [tex]= 5408 HZ[/tex]
Hence, the speed of sound used in water is [tex]5408Hz[/tex].
What is principle of Submarine?Submarine, any naval vessel capable of propulsion both below and above the surface of the ocean. Submarines are very distinct from surface ships in terms of appearance and design, making this a unique capacity among warships.
When Germany used them to attack surface merchant ships during World War I (1914–18), submarines initially played a significant role in naval warfare. Torpedo's, a type of self-propelled underwater missile used by submarines, were used as their main armament in such attacks. In World War II (1939–1955), submarines participated in similar operations on a bigger scale, in both the Atlantic (by Germany) and Pacific (by the United States).
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In 1962 , measurements of the magnetic field of a large tornado were made at the Geophysical Observatory in Tulsa, Oklahoma. If the magnitude of the tornado's field was B=1.50×10⁻⁸ T pointing north when the tornado was 9.00 km east of the observatory, what current was carried up or down the funnel of the tornado? Model the vortex as a long, straight wire carrying a current.
B = μ₀i/2πr
i = 2πrB/μ₀
∵ 16.50 nano Tesla = 1.65×10⁻⁸ Tesla
∵8.10Km = 8100 m
i = 2(3.14)(8100)(1.65×10⁻⁸)/4×3.14×10⁻⁷
i = 668.25 A
So the current carried up or down the funnel of the tornado is 668.25 A.
What is a tornado?A tornado is a fast spinning column of air that occasionally strikes the base of a cumulonimbus cloud as well as the Earth's surface.
A tornado is a narrow, violently rotating column of air that extends from the ground to a thunderstorm.
Tornadoes are difficult to notice since wind is invisible unless they build a condensation funnel of water droplets, dust, and debris.
Some tornadoes increase and become powerful or destructive. Strong tornadoes can last for twenty minutes or more and have winds of up to 200 miles per hour, whereas severe tornadoes can persist for more than an hour and have winds of 200 to 300 miles per hour!
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Consider (a) an electron (b) a photon, and (c) a proton, all moving in vacuum. Choose all correct answers for each question. (v) Which move at the speed of light?
Photon move at the speed of light which is option (b)
An electron is a solid negatively charged factor of an atom. Electrons exist outdoor of and surrounding the atom nucleus. Each electron includes one unit of bad charge (1.602 x 10^-19 coulomb)A proton is a subatomic particle discovered with inside the nucleus of each atom. The particle has a advantageous electric charge, identical and contrary to that of the electron. A photon is a subatomic particle, having strength and momentum however no mass or electric powered charge, this is the quantum unit of electromagnetic radiation, together with light.As electrons and protons are particles of the atoms and posses mass so they do not move at the speed of light even in vaccum.
Photon is a light energy so it moves with the speed of light .
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A pion at rest (mπ = 273 me) decays to a muon (mµ = 207 me) and an antineutrino (m-v≈0) . The reaction is written π-→ µ- + v-. Find (a) the kinetic energy of the muon
The kinetic energy of the muon is 4.08 MeV
Given that:
A pion (mπ = 273 me)
muon (mµ= 207me)
Neutrino (mv=0)
(Let’s assume that c =1, and that me= 0.511MeV)
Since the pion is at rest conversation of momentum dictates that the momenta of the muon and the neutrino be equal in magnitude,
P_μ=P_v (1)
Since the pion is at rest its energy equals its mass, E_π=m_π. Since the neutrino is massless its energy equals its momentum E_v=P_v . By conservation of energy,
E_π=E_μ+E_v, so
E_μ=m_π-P_v (2)
Substituting the right sides of (1) and (2) into the left side of the fundamental kinematic equation for the muon E_μ^2-P_μ^2=m_μ^2 yields
〖(m_π-P_v)〗^2-P_μ^2=m_μ^2
Solving for P_v gives (the magnitudes of) the momenta of the decay particles and the kinetic energy (equal to the total energy) of the massless neutrino,
P_v (〖=P〗_u=E_v )=((m_π^2-m_μ^2))/(2m_π )
P_v=(〖273〗^2-〖207〗^2)/(2× 273)=29.65 MeV
The kinetic energy of the muon equals its total energy minus its mass which, using (2), is
〖(m〗_π-P_v)-m_μ=4.08 MeV
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A Hall-effect probe operates with a 120 -mA current. When the probe is placed in a uniform magnetic field of magnitude 0.0800 T , it produces a Hall voltage of 0.700 μV .(a) When it is used to measure an unknown magnetic field, the Hall voltage is 0.330μV . What is the magnitude of the unknown field?
The magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.
We have Hall Probe to measure an unknown Magnetic field.
We have to determine the Magnitude of the unknown Magnetic field.
What is Hall Probe?A Hall probe is a device that can be used to measure magnetic fields. They work on the principle of Hall effect.
According to the question, we have -
I = 120 mA = 120 x 0.001 = 0.12 Ampere.
B = 0.08 Tesla
V(H) = 0.7 [tex]\mu[/tex]V = 7 x [tex]10^{-7}[/tex]
The formula relating the above quantities is -
V(H) = [tex]A_{H} \frac{IB}{d}[/tex]
[tex]$\frac{d}{A_{H} } =\frac{IB}{V_{H} }= \frac{0.12 \times 0.08}{7\times 10^{-7} }[/tex] = 13.71 x [tex]10^{3}[/tex]
Now -
For → V = 0.33 [tex]\mu[/tex]V = 0.33 x [tex]10^{-7}[/tex]
[tex]B=\frac{Vd}{A_{H}I }[/tex] = [tex]13.71\times 10^{3} \times\frac{0.33\times 10^{-7} }{0.12}[/tex] = 37.7 x [tex]10^{-4}[/tex] Tesla
Hence, the magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.
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A proton is projected in the positive x direction into a region of a uniform electric field →E =(-6.00 × 10⁵) i^ N/C at t=0 . The proton travels 7.00 cm as it comes to rest. Determine (a) the acceleration of the proton,
The acceleration of the proton that is projected in the positive x direction into a region of a uniform electric field is 5.76×〖10〗^13 m/s^2
The product of the field's strength and the charge's strength yields the magnitude of the electric force acting on a charge traveling in a magnetic field region.
The electric force magnitude acting on the charge is expressed in the equation below.
F=|→E|×|q|
F=|-6.00×〖10〗^5 N/C|×||+1.602×〖10〗^(-19) C|
F=9.612×〖10〗^(-14) N
Newton's second law of motion states that the magnitude of a force is equal to the product of a proton's mass and its acceleration. Where the magnitude of the acceleration of the proton is ;
a=F/m
Where F is the force and m is the mass;
Inserting the values into the equation,
a=(9.612×〖10〗^(-14) N)/(1.67×〖10〗^(-27) kg)
a=5.76×〖10〗^13 m/s^2
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what is the direction of the electric field at any point on the z axis? view available hint(s)for part a what is the direction of the electric field at any point on the z axis? parallel to the x axis parallel to the y axis parallel to the z axis in a circle parallel to the xy plane
The direction of electric field at any point of z axis is always positive because of the symmetry property.
ELECTRIC FIELD - It is a force that fills the space around every charge in space.
It is a physical quantity. It represents the vector field that is generated by a charge in the area around that charge. It is defined as the electric force per unit test charge that placed at distance from the charged that generate the electric field.
the electric field is outward from the positive charge and inward negative point charge.
The direction of electric field at any point of z axis is always positive because of the symmetry property.
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Assume a 150 -W loudspeaker broadcasts sound equally in all directions and produces sound with a level of 103dB at a distance of 1.60 m from its center.(b) Find the efficiency of the speaker, that is, the fraction of input power that is converted into useful output power.
According to the question: The efficiency of the speaker is 0.428%.
What is the power?The quantity of energy that is transported or transformed through time is referred to as power in physics. One joule per second, or one watt, is the definition of power in the International System of Units. Power is referred to as acting in some ancient writings. A motor's output power is the result of the torque it produces and the angular velocity of its output shaft.
Explanation:
Power output, P₀ = 0.643W
Power input, P₁ = 150W
The efficiency of the speaker = P₀/P₁
= 0.643W/150W
= 0.00428 ≅ 0.428%
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The rotor in a certain electric motor is a flat, rectangular coil with 80 turns of wire and dimensions 2.50 cm by 4.00 cm . The rotor rotates in a uniform magnetic field of 0.800 T . When the plane of the rotor is perpendicular to the direction of the magnetic field, the rotor carries a current of 10.0 mA . In this orientation, the magnetic moment of the rotor is directed opposite the magnetic field. The rotor then turns through one-half revolution. This process is repeated to cause the rotor to turn steadily at an angular speed of 3.60×10³ rev/min. (a) Find the maximum torque acting on the rotor.
The maximum torque acting on the rotor is 1.2× 10⁻⁴ Nm.
To find the maximum torque, the given values are,
No .of turns of the wire = 80
Dimensions is given as, 2.50 cm by 4.00 cm
Magnetic field = 0.800 T.
current = 10 mA.
Angular speed = 3.60 ×10³ rev/min
What is maximum torque?Maximum torque means the highest value of the net torque measured at full engine load.The torque can be calculated when the angle of the rotor is at 90°.When the magnet is along the magnetic field, the torque will be minimum.When the magnet is perpendicular to the magnetic field, the torque will be maximum.The maximum torque can be described with the formula,As the torque is in the current carrying loop in the uniform magnetic field,
τ = NIAB sinθ Nm
= 80×10×10⁻³×0.0250×0.040×0.800× Sin 90°
= 2 × 6.4 × 10 ⁻⁴
= 1.2 × 10⁻⁴ Nm.
Thus, the maximum torque acting on the rotor is 1.2× 10⁻⁴ Nm.
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5. Find the velocity of a train that traveled 75 km in 35 minutes. (answer
in m/s). Conversion factors: 1000 m = 1 km; 60 s = 1 min.
75km=75000m
35min=2100 seconds
Velocity=Displacement/Time
=75000/2100
=750/21
=35.71 m/s
any moment in time, the object can be stationary, moving to the right, moving to the left, or turning around. identify the motion of the object at each time provided.
Answer:
well....to every direction the body moves towards the force exerted is conducted in the opposite direction of motion.....when it turns around force exerted is not opposite but rather non directional...
A uniformly charged, straight filament 7.00m in length has a total positive charge of 2.00μC. An uncharged card-board cylinder 2.00cm in length and 10.0cm in radius surrounds the filament at its center, with the filament as the axis of the cylinder. Using reasonable approximations, find (b) the total electric flux through the cylinder.
The total electric flux through the cylinder is 6.46N⋅m^2/C
Given data:
• The length of the charge is l= 7m.
• The charge is q = 2μC..
• The radius the cylinder is r = 10 cm
The expression for the electric flux is given as,
ϕ=2πrLE
ϕ=2πrL(2kλ/r)
ϕ=4πkλL
Substitute the value in the above equation,
ϕ=4π(9×10^9N⋅m^2/C^2)(2×10^−6C/7m)(0.02m)
= 6.46N⋅m^2/C
An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.
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(a) what is the wavelength of a 2.4 ghz sine wave in inches? (b) what is the most efficient length in inches of a monopole antenna transmitting at 2.4 ghz? 2. calculate the frequency of an electromagnetic wave in free space having a wavelength of 12 cm.
The wavelength of a 2.4 ghz sine wave is 0.5 inches.
What is wavelength?In physical science, the frequency is the spatial time of an occasional wave the distance over which the wave's shape rehashes. Albeit X-beams have numerous advantageous applications, utilizing them requires alert since openness can cause visual deficiency, malignant growth and different wounds. Frequency and recurrence are conversely related so that more drawn out waves have lower frequencies, and more limited waves have higher frequencies. Frequency addresses the distance between two successive recurrence wave tops and is normally used to portray the electromagnetic range.
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A single-turn square loop of wire, 2.00 cm on each edge, carries a clockwise current of 0.200 A . The loop is inside a solenoid, with the plane of the loop perpendicular to the magnetic field of the solenoid. The solenoid has 30.0 turns/cm and carries a clockwise current of 15.0A . Find (b) the torque acting on the loop.
The torque acting on the loop will be zero .
The torque on a current-carrying loop in a uniform magnetic field 'B' .The loop carries a current ' I ', has 'N' turns, each of area 'A' , and the loop makes an angle θ with the field B is given by [tex]T=NIABsin\theta[/tex] ...(1)Torque are often outlined because the movement equivalent of a linear force. The line around that Associate in Nursing object rotates is termed the axis of rotation. In physics, force is just the tendency of a force to twist or twist.The diagram is given below.
From the diagram , vector of the loop and therefore the force field are parallel to every different which suggests sin 180 ° whose worth is zero.
On putting the value of sin180 in equation (1) , we get
[tex]T=NIAB\times0\\T=0[/tex]
Torque acting on the loop will be zero .
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Does anyone know how to draw this out?
The Position-Time graph for the given Velocity-Time graph is drawn in the image attached.
From the Velocity-Time graph we can take the information needed.
[tex]t_{1}[/tex] = 1 s
[tex]t_{2}[/tex] = 2 s
[tex]t_{3}[/tex] = 3 s
[tex]t_{4}[/tex] = 4 s
[tex]t_{5}[/tex] = 5 s
[tex]v_{1}[/tex] = 10 m / s
[tex]v_{2}[/tex] = 20 m / s
[tex]v_{3}[/tex] = 30 m / s
[tex]v_{4}[/tex] = 40 m / s
[tex]v_{5}[/tex] = 50 m / s
v = d / t
d = v * t
[tex]d_{1}[/tex] = 10 * 1 = 10 m
[tex]d_{2}[/tex] = 20 * 2 = 40 m
[tex]d_{3}[/tex] = 30 * 3 = 90 m
[tex]d_{4}[/tex] = 40 * 4 = 160 m
[tex]d_{5}[/tex] = 50 * 5 = 250 m
Therefore, the Position-Time graph is drawn in the image attached.
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suppose that you are a scientist studying tree rings in a cross-section of an ancient tree. what could several narrow tree rings in a row tell you about the climate when those rings were formed?
Several narrow tree rings in a row tell us that it was formed in the warm season.
What is a tree?Trees are those plants that grow very tall. We can see that ancient trees play an important role in the determination of the age of some fossils. The patterns of the rings that could be found in these trees also help us to know how old the particular tree is and especially the whether condition of the place around the time that the tree was formed.
This has been corroborated by a lot of biological evidences that show to tat effect. It can also tell us about the weather condition in a place at a particular time.
As such, several narrow tree rings in a row tell us that it was formed in the warm season.
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when striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.0 m/sm/s in 0.15 ss
The distance covered will be 0.301m.
firstly we will new to calculate acceleration (a).
we can do so using newtons first law of motion.
v=u + a × t
where
a is the acceleration
t is the time
from here we get
a=(v-u)/t
a=(4-0)/0.15
a=26.67m/s²
using newtons second law of motion
s=u.t+1/2at²
where s is distance travelled in t seconds.
we get,
s=0.301m
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Draw a velocity - time graph for an object originally traveling at - 3 m/s. The object then slows down and turns around.
Answer:
this problem we have to draw a velocity-time graph for an object travelling initially at -3 m/s, then slowing down and turning around.
In the graph, we see that the initial velocity at time t = 0 is
v_0 = -3 m/sv
0
=−3m/s
and it is negative, so below the x-axis.
Later, the object slows down: this means that the magnitude of its velocity increases, therefore (since the velocity is negative) the curve must go upward, approaching and reaching the x-axis (which corresponds to zero velocity).
After that, the object's velocity keep increasing, but now it is positive: this means that the object is travelling in a direction opposite to the initial direction, so it has turned around.
Explanation:
I can't draw sorry
If the amplitude of the oscillator doubles, what happens to the wavelength and wave speed?.
On doubling the Amplitude both wavelength and wave speed remains unchanged.
We have a Oscillator whose amplitude is Doubled.
We have to determine the affect of variation in amplitude on wavelength and wave speed.
Define Wavelength and Wave speed.Wavelength - It is the distance between the two adjacent crests or trough in a waveform is called Wavelength.Wave speed - It is the distance traveled by a given point on the wave in a given interval of time.According to the question, we have -
Initial Amplitude → A
Final Amplitude → 2A
On doubling the Amplitude both wavelength and wave speed remains unchanged. Wavelength is not dependent on Amplitude. It can only be changed by changing its frequency or time period. Wave speed is not dependent on Amplitude. It can only be changed by changing the properties of the string through which the wave is travelling.
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A canister and the hydrogen gas it contains are at 100°C. The canister is placed in a vacuum, and the temperature of the canister and gas begins to decrease. Which of the following statements of reasoning best explains how the canister-gas system loses energy?
High-energy hydrogen molecules collide with lower-energy molecules and the walls inside the canister, losing energy during the collisions.
High-energy hydrogen molecules collide with lower-energy molecules and the walls inside the canister, losing energy during the collisions.
The molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.
The molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.
Energy is released from the canister as infrared radiation that can travel through the vacuum, causing a decrease in the average energy of the canister and the molecules.
Energy is released from the canister as infrared radiation that can travel through the vacuum, causing a decrease in the average energy of the canister and the molecules.
Energy is released from the canister and travels through the vacuum by convection, causing a decrease in the average energy of the canister and the molecules.
The statement that best explains why the system looses energy is; the Collison of the molecules of hydrogen with the wall of the can carries off energy to the environment.
How does the cannister loose energy?We know that energy is defined as the rate of doing work. Now the temperature of a gas is measure of the kinetic energy of the molecules of the body. In this case, the temperature of the hydrogen in the cannister has to do with how fast the molecules of the hydrogen are moving.
The higher the temperature, the faster the molecules of the hydrogen move. The lower the temperature, the slower the molecules of the hydrogen moves.
As such, the molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.
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During the your European vacation, you are hanging out at the beach at the gold coast of Spain. As you are laying in your chaise lounge soaking up the warm Mediterranean sun, a large glob of seagull poop hits you in the face. You estimate the impact velocity at 40.2 m/s. Neglecting air resistance, calculate how high up the seagull was flying when it pooped. (TWO decimal places!!)
The height at which the seagull was flying is 82.45 m.
What is height of motion?
The height of motion or maximum height in projectile motion occurs when the object reaches a vertical velocity of zero magnitudes.
The height at which the seagull was flying is calculated as follows;
v² = u² - 2gh
where;
v is the final velocity at the maximum heightu is the initial velocity at the initial heightg is acceleration due to gravityh is the maximum height0 = u² - 2gh
2gh = u²
h = u²/2g
h = (40.2²) / (2 x 9.8)
h = 82.45 m
Thus, the height at which the seagull was flying is 82.45 m.
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a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.
the average acceleration of the bullet through the board -55657×10⁵ m/s²
acceleration- Rate of change of velocity with respect to time.
S = 0.10 mm = 10⁻⁵ m ( distance) [∵ 1mm = 10⁻³]
u = 480 m/s (initial velocity)
v = 345 m/s (final velocity)
As we know the 3rd equation of motion.
v² = u² + 2aS
a = ? ( acceleration)
using these values in equation we get
(345)² = (480)² + 2×a× 10⁻⁵
a = (345)² - (480)² / 2× 10⁻⁵
a = -55657×10⁵ m/s²
The negative sign shows that the direction of acceleration is opposite of velocity thus bullet is slowing down.
the average acceleration of the bullet through the board -55657×10⁵ m/s²
The given question is incomplete. The complete question is.
a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.
What is the average acceleration of the bullet through the board/?
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a vector with magnitude 8 points in a direction 70 degrees counterclockwise from the positive x axis. write the vector in component form.
A vector with magnitude 8 points in a direction 70 degrees counterclockwise from the positive x axis, the vector component form 11.53.
What is magnitude?In Physics, greatness is characterized as the most extreme degree of size and the heading of an item. Extent is utilized as a typical calculate vector and scalar quantities. The size of a seismic tremor is characterized regarding length, expansiveness and width. It is estimated as the actual size of the tremor. A seismic tremor is considered to have a solitary extent. Greatness by and large alludes to the amount or distance. Corresponding to the development, we can associate greatness with the size and speed of the article while voyaging. The size of the article or the sum is its extent. extent for the most part alludes to distance or amount. Corresponding to development, extent alludes to the size of an article or its speed while voyaging. Speed is a scalar property in material science, and that implies that it just depicts the size, or speed, of an item, and doesn't specify the bearing that the article ventures.
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