A tennis player can serve a tennis ball at approximately 2.0 m/s.
If the other player is 4.0 meters away from the server, how long
does it take the ball to reach the second player? Please show
your work in order to earn credit for this question.
Kinematic Equation which may help with this problem.

Answers

Answer 1
Distance, Velocity and Time

Formula: [tex]d=vt[/tex]

d = distancev = velocityt = time

Solving the Question

We're given:

v = 2.0 m/sd = 4.0 mSolve for t

[tex]d=vt\\\\t=\dfrac{d}{v}[/tex]

⇒ Plug in the given values:

[tex]t=\dfrac{4.0}{2.0}\\\\t=2.0[/tex]

Answer

Therefore, it took 2.0 seconds for the ball to reach the second player.


Related Questions

Three liquids are at temperatures of 2°C, 21°C, and 34°C, respectively. Equal masses of the first two liquids are mixed, and the equilibrium temperature is 5 C. Equal masses of the second and third are then mixed, and the equilibrium temperature is 30.1°C.
Find the equilibrium temperature when equal masses of the first and
third are mixed.
Answer In units of 'C.

Answers

Answer:

m - mass of each liquids (all masses are equal )

C_1C 1 - specific heat of the first third C_2C 2 - specific heat of the second  liquid

C_3C 3- specific heat of the third liquid

Temperature of liquids: T_1=7 ◦C,T_2=20◦C, T_3=34◦CT

1 =7◦C,T 2 =20◦C,T 3=34◦C

Temperature of 1+2 liquids mix: T_{12}=11^oCT

12 =11 oC

Temperature of 2+3 liquids mix: T_{23}=22.6^oCT

23=22.6 oC

Temperature of 1+3 liquids mix: T_{13} - ?T 13 −?

When the first two are mixed:

m C₁ (T₁ − T_{12}) + m C₂ (T₂ − T_{12}) = 0 \\ C₁ (7− 11) + C₂ (20 − 11) = 0\\ 4C_1=9C_2\\ C_1=2.25C_2mC₁(T₁−T 12)+mC₂(T₂−T 12 )=0C₁(7−11)+C₂(20−11)=04C \1=9C 2C 1 =2.25C 2

​When the second and therd are mixed:

m C_2 (T_2 − T_{23}) + m C_3 (T_3 − T_{23}) = 0 \\ C_2 (20−22.6) + C₂ (34 −22.6) = 0\\ 2.6C_2=11.4C_3\\ C_2=4.38C_3mC 2 (T 2 −T 23 )+mC 3 (T 3 −T 23 )=0C 2(20−22.6)+C₂(34−22.6)=02.6C 2 =11.4C 3C2 =4.38C 3

​When the first and therd are mixed:

m C_1 (T_1 − T_{13}) + m C_3 (T_3 − T_{13}) = 0 \\ C_1 (7−T_{13}) + C_3 (34 −T_{13}) = 0\\ C_1=2.25C_2=2.25(4.38C_3)=9.86C_3\\ 9.86C_3 (7−T_{13})=-C_3(34 −T_{13})\\ 9.86 (7−T_{13})=-(34 −T_{13})\\ T_{13}=9.5^oCmC 1(T1 −T13)+mC 3(T3−T13 )=0C1 (7−T13 )+C 3(34−T 13 )=0C1 =2.25C2=2.25(4.38C3 )=9.86C39.86C3 (7−T13 )=−C3(34−T13 )9.86(7−T13)=−(34−T13 )T13 =9.5 oCT_{13}=9.5^oCT 13 =9.5 o C:

How long will it take a car to accelerate from 20m/s to 26m/s at a rate of 1.4m/s2?

• 2.2 s
• 4.6 s
• 2.7 s
• 4.3 s​

Answers

Answer:

4.3s

Explanation:

a=v-u/t

t=v-u/a

t=26-20/1.4=4.28

=4.3

A red, 400Kg bumper car is moving to the right at 2m/s. The red bumper car collides head on with a blue bumper car with a combined driver/car mass of 600kg and a velocity of 1m/s. The collision was elastic. If the blue car bounced backwards at a velocity of 0.25m/s, what was the final velocity of the red car?

Answers

Based on the principle of the conservation of linear mometum, the recoil velocity of the bliue car is 3.1 m/s.

Principle of conservation of linear momentum

The principle of conservation of linear momentum states that; the total mometum before collsion is equal to the total momentum after collision.

Now;

m1u1 + m2u2 = m2v2 + m2v2

(400Kg * 2m/s) + (600kg *  1m/s) = (600kg * 0.25m/s) + (400Kg * v)

800 + 600 = 150 + 400v

800 + 600 - 150 =  400v

v = 800 + 600 - 150/400

v = 3.1 m/s

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Carbon -14 is used to date a palm fossil that originally contained 0.24 grams of carbon -14. The half life is 5700 years. If the fossil is found to be 17,100 years old, how much carbon -14 does it contain now?

Please make sure to show all of your work/process so I can learn how to do it on my own!! thank you ​

Answers

Answer:

Exactly 0.03042 carbon-14 is remaining.

Roughly 0.03 Carbon-14 is remaining. (When/If Multiple Choice)

Explanation:

Not a physics question, this is chemistry, but I'll answer.

First, divide 17,000/5700 to find the t, or time.

t = 2.98245614 or 2.98.

If it originally contained .24 grams, and a half life means x/2,

you would use the formula x/2^p, with p being the number of half lives

(these variables are made up, you can use any you would like)

In 17,000 years, the palm fossil experienced 2.98 half lives.

Thus meaning, using our equation, we would find (.24)/2^2.98

This equals 0.030418784 carbon-14 remaining to be exact.

(For Multiple Choice, it may be required to round to For Multiple Choice, it may be required to round to 3, so .24/2/2/2 or .24/2=.12 then .06 then it equals :  .03 Carbon-14)

Carbon -14 is used to date a palm fossil that originally contained 0.24 grams of carbon -14. The half life is 5700 years. If the fossil is found to be 17,100 years old then 0.0303 g of carbon -14 does it contain now.

What is radioactive decay ?

The process by which an unstable atomic nucleus loses energy through radiation is known as radioactive decay (also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration). A radioactive substance is one that contains unstable nuclei. Alpha decay, beta decay (-decay), and gamma decay (-decay) are three of the most prevalent forms of decay, all of which entail the emission of one or more particles. The mechanism responsible for beta decay is the weak force, while the other two are regulated by electromagnetism and nuclear force. Electron capture is a fourth form of common decay in which an unstable nucleus grabs an inner electron from one of the electron shells.

According to decay formula,

N(t) = N₀ e^(-λt)

Given,

N₀ = 0.24g

t = 17100 years

λ = 0.693/T

Where T is half life.

λ = 0.693/5700 = 1.21 × 10⁻⁴

Putting all the values in the equation,

N(t) = 0.24g e^(-1.21 × 10⁻⁴ ×17,100)

N(t) = 0.0303 g

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A force of 900 N is applied to a 9kg object. How fast will it accelerate?

Answers

Given :

Force = 900 N

Mass = 9kg

[tex] \\ [/tex]

To find :

Acceleration = ?

[tex] \\ [/tex]

We know :

[tex] \boxed{ \rm Force=Mass\times Acceleration}[/tex]

By using this formula we can find acceleration.

[tex] \dashrightarrow \sf Force=Mass\times Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf900=9\times Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf900 \times \dfrac{1}{9} =Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf \cancel9 \times 100 \times \dfrac{1}{ \cancel9} =Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf \dfrac{100}{1} =Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf Acceleration = \dfrac{100}{1} \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \bf Acceleration = 100\: ms^{-2}[/tex]

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Related Concept :

Define Acceleration:

Acceleration is the rate by which velocity changes with respect to time

Main formula :-

a = (Vf - Vi)/t

where :-

Vf is final velocityVi is initial velocityt is time

Define Force :

Force is a push or pull that changes or may tends to change an object from rest to motion or from motion to rest.

Main formula:

f = m × a

where :-

m is massa is accelerationf is force

Define Mass :

The amount of matter present in body

Main formula:

m = v × d

where:-

m is massv is volumed is density

The uncertainty principle applies not only to momentum and position, but also to energy and time.
a. True
b. False

Answers

Answer:

(a)    that is a true statement

A force of 4,500 N acts on a car. The
acceleration of the car is 3 m/s/s. What
is the mass of the car? Show your work
below.

Answers

Answer:

1500 kg is mass of car

Explanation:

F = ma

F/a = m

4500n / 3 m/s^2 = 1500 kg

A spring with a spring constant of 5.25N/m applies a force of 8.50N when it is stretched. How much was the spring compressed?

Answers

Answer:

1.62

Explanation:

F = kx

8.5 = 5.25 * x

8.5/5.25 = 1.62

Which statement about natural selection on early earth is correct?.

Answers

Answer:

wheres the statements

Explanation:

where its incomplete

Natural selection could act on a population of proto-cells on early Earth, selecting for those that were stable and had self-replicating, catalytic RNA that allowed them to grow and divide to produce similar daughter proto-cells. The correct option is option (B).

Natural selection could act on a population of proto-cells on early Earth. Proto-cells were early, simpler forms of cells that lacked DNA but had self-replicating, catalytic RNA. Through natural selection, those proto-cells that were more stable and had RNA molecules capable of self-replication and catalytic functions would have had a reproductive advantage.

These traits would allow them to grow, divide, and produce similar daughter proto-cells. Over time, this selection process could have led to the development of more complex and stable cellular structures, eventually leading to the emergence of cells that utilize DNA as their genetic material.

Therefore the correct option is option B.

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The complete question is:

Which statement about natural selection on early Earth is correct?

A. Natural selection could only act on populations of living organisms that had DNA as their genetic material.

B. Natural selection could act on a population of proto-cells on early Earth, selecting for those that were stable and had self-replicating, catalytic RNA that allowed them to grow and divide to produce similar daughter proto-cells.

C. Natural selection acted on populations of proto-cells on early Earth in order to make them more like modern living cells that have DNA as their genetic material.

which of the following is an example of wernickes aphasia?

Answers

An example of wernickes aphasia is someone making a speech which does not make sense.

It majorly caused by loss of flow of blood to the brain. Other causes include

Head injuryBrain inflammationBrain infectionStroke. e.t.c

What is wernickes aphasia?

Wernickes aphasia can simply be defined as a language disorder that makes it very difficult for an individual to understand words and communicate with other people.

So therefore; an exam of wernickes aphasia is someone making a speech which does not make sense.

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I WILL MARK BRAINLIEST

EXPERIMENT: MIXTURES
OBJECTIVES
Utilize a filter to separate a mixture of sand and water.
Summarize your findings.

Many tasks in chemistry involve separating mixtures. For example, crude oil by itself has very few uses, but many important substances are separated from crude oil. In this investigation we will attempt to separate sand from salt water, and salt from water. If you do not have access to sand, you can use small pebbles or BBs.

Before you begin the experiment, hypothesize whether or not you can separate sand from salt water using filter paper. After the experiment summarize your findings in a scientific report. Upload your report below in question 1.

These supplies are needed:

salt
water
sand
a measuring cup
a balance
filter paper
funnel
plastic spoon
two beakers or glasses
Measure 5 grams of salt and 10 grams of sand using the balance.
Mix together the salt and sand in a beaker or glass.
Add one half-cup of water to the salt-sand mixture.
Stir the mixture with the plastic spoon until all the salt is completely dissolved.
To filter the mixture fold the filter in half to form a semi-circle. Fold it again which creates the shape of a triangle. Place the filter paper in the funnel and open one layer of the filter paper and spread it out onto one side of the funnel, and the other three layers onto the other side of the funnel. You may want to wet the filter paper with water so that the filter paper lays flat against the sides of the funnel. Carefully pour the salt water -sand mixture into the funnel and drain the liquid into a beaker or glass.
Remove the filter paper from the funnel and lay it out flat to allow the sand to dry.

Answers

Answer:

I found out that you could separate the sand because the filterstion and all the materials uses their elements to filter it out

Findings say that one could separate the sand using the filtration and all the materials uses their elements to filter it out.

What is filtration?

Filtration is the technique of segregating the components from a mixture.

In the given experiment, the filter is used to separate a mixture of sand and water.

This experiment can be successfully completed through the filtration process.

Thus, one could separate the sand using the filtration and all the materials uses their elements to filter it out.

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The greatest variation in size, mass, and luminosity occurs in:.

Answers

The greatest variation in size, mass, and luminosity occurs in elliptical galaxies.

What is Variation?

This is defined as the difference from the norm which is exhibited by objects.

In the solar system, variation in features such as size, mass, and luminosity occurs mostly in elliptical galaxies due to presence of array of stars thereby making it the most appropriate choice.

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HELP ME PLEASE!!!!

Do some research on digital vs. analog recording, and decide which you think gives the most accurate and best quality sound. State the advantages and disadvantages of each in a paragraph. Be sure to back up your opinions with facts, and state your sources.

Answers

Answer:

The question of analog vs. digital audio is one of the more hotly debated questions in the world of music, film, and media today. Does digital sound better? Does analog sound better? Is there even a noticeable difference?

It’s impossible to understand the difference completely without understanding what distinguishes analog audio from digital audio. A full discussion of these terms is best left to your curriculum and discussions with your mentor in the studio. For now, though, here’s a brief explanation of what these two words mean, and the differences between them.

Explanation:

The ____________ is a phenomenon that occurs when electrons are ejected from a piece of metal after light has been shined onto the metal surface.

Answers

Answer:

Photoelectric Effect

Explanation:

Photoelectric Effect is a phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation.

Who ran faster? The turtle or the rabbit?
(A) The rabbit
(B) The turtle

Answers

Answer:

the turtle was finished faster but the rabbit was faster

Explanation:

Each of the ____________ is specially positioned to detect angular acceleration in one of the three planes.

Answers

Each of the semicircular canals is especially positioned to detect angular acceleration in one of the three planes.

What is angular acceleration?

Angular acceleration is defined as the pace of change of angular velocity concerning time.

Each of the semicircular canals is especially positioned to detect angular acceleration in one of the three planes.

The semicircular canals are biomechanical sensors that detect and encode angular motion of the head in three dimensions.

Hence semicircular canals are the correct answer for the blank.

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Which statement describes a chemical property related to the particles that make up a material

Answers

Answer:

Salt crystals are hard and brittle because they are made up of atoms that combine by ionic bonding.

Explanation:

Do you know it is scientifically impossible for bees to fly. yet bees fly.

Answers

Answer:

yes

Explanation:

but no i dont know anyways what is the question

Scientifically, that one "observation" right there proves that they can and they do.

find the resistance of the lamp if an electrical bulb is rated 60W,240v.​

Answers

Answer:

[tex]R= 960 \: Ohm[/tex]

Explanation:

P = 60 W

V = 240 V

[tex]P= VI[/tex]

[tex]\implies I= \frac{P}{V}[/tex]

[tex]\implies I= \frac{60}{240}[/tex]

[tex]\implies I= 0.25 A[/tex]

Now, by Ohms law

[tex]R= \frac{V}{I}[/tex]

[tex]\implies R= \frac{240}{0.25}[/tex]

[tex]\implies R= 960 \: Ohm[/tex]

Answer:

960 Ω

Explanation:

Like diomedes and patroclus before him, achilles fights against a god during his aristeia in iliad books 20-22. Which god?.

Answers

The god that Achilles fought in the Illiad was the god Hector and he ended up killing him.

Who is achilles?

He was a warrior that fought in the Trojan war. After the death of Patroclus. Achilles had to fighty the Trojan Army singlehandedly.

It was the war that saw the end of Hector and also he joined the war for the avenging of the death of Petroclus.

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Please Help! 20 BRAIN POINTS
An astronaut (m = 95 kg) and her tool box (m = 21 kg) is drifting through deep space at a speed of 0.4 m/s [FWD]. In order to change the direction of travel, the astronaut throws her tool box forward. What is the minimum speed of the thrown tool box necessary, so that the astronaut changes direction?

Answers

Answer:

The Speed of the throw that is required to create enough impulse, to change the direction of the momentum is: -1.81m/s

Explanation:

m1=95kg

m2=21kg

V1=.4m/s

V2=?

V'=<0 or -.01 at lowest.

for the Impulse formula, I found: m1 x V1 + m2 x V2 = <0

so,

(95) x (.4) + (21) x (V2)=<0

38kgm/s+(21kg x V2)=<0 or -0.01m/s

I found that V2 was equivalent to -1.81, and when you plugin the value, you get the equation

(95) x (.4) + (21) x (-1.81) = -0.01m/s

Because sound waves vibrate longitudinally, what can result?

A Disruptions of fixed waves

B. Changes in the density of air

C. Pressure differences where compressions are rarefied

D Regions of high pressure and low pressure


HELp!!!!!!!!​

Answers

Answer:

I think its D.

Explanation:

I think this because sound waves move up and down im pretty sure but i might have that mixed with radio waves

Guys i need help rn

Needs a nice ans, thanks​

Answers

Answer:

51.92 m

Explanation:

Given

angle at which it is launched (α) = 30°initial velocity (v₀) = 31.9 m/s

Formula

Range (R) = [tex]\frac{v_{0}^{2} sin2\alpha }{g}[/tex]

Solving for R

R = (31.9)² x sin2(30°) / 9.8R = 1017.61 x sin60° / 9.8R = 1017.61 / 19.6 [sin 60° = 1/2]R = 51.92 m

If a spring has a spring constant of 0. 5 N/m and it is stretched 0. 5 m, what is the force

of the spring?

Answers

Answer:

0.25N

Explanation:

k=0.5N/m

e=0.5m

f=?

were k=spring constant

e=extension

F=force

According to hooks law,

f=ke

f=0.5x0.5 =0.25 N

please help me I’ll make u brainliest please


A 1 liter jar contains 0.5 moles of gas at a pressure of 2 atm. What is the temperature of the gas?


What is the volume of a
container of 4 moles of gas at 200 K with a pressure of 3 atm?


Your scientist friend is trying to figure out how many molecules of gas are in a container. They know that the container has a volume of 5 liters, and they measured the pressure and temperature to be 3.5 atm and 275 K. From this information, what do you tell them the mole measurement should be?


Answers

Answer:

See below  ( Ideal gas law)

Explanation:

A)   PV = n RT       P = 2 * 760 = 1520 mm  

    1520 ( 1)  =  .5 (8.314)(T)       T is in Kelvin

     T = 365.64 K

B) PV = nRT

   3 ( 760) V = 4 ( 8.314)(200)

           V = 2.92 Liters

C) PV = nRT

    3.5 (760) (5) = n (8.314)(275)    n = 5.8 moles

help me PLEASE, it's physical science D:

Answers

Answer:

90

Explanation:

The bottom number on the element is the number of protons and the top number is the total of the protons + neutrons

Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant

Answers

Speed of particle B is 2v₀/3 m/s to the left. Particle A and particle B will always have equal speed since they experience equal forces.

Conservation of energy

The speed and direction of the particle B is determined by applying the principle of conservation of energy as follows;

K.E₁ + P.E₁ = K.E₂ + P.E₂

[tex]\frac{1}{2} Mv^2_A + \frac{G}{r^2} = \frac{1}{2} Mv^2_B + \frac{G}{r^2} \\\\ \frac{1}{2} Mv^2_A = \frac{1}{2} Mv^2_B\\\\v^2_A = v^2_B\\\\v_A = v_B[/tex]

[tex]v_B = \frac{2v_0}{3} \ m/s \ to \ the \ left[/tex]

At any given position, the speed of particle A and particle B will be equal, since they experience equal force and they have equal masses.

The complete question is below:

Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant. At time t=T1 particle A is observed to be traveling with speed 2vo/3 to the left. The speed and direction of motion of particle B is ?

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Answer:

Explanation:

the linear momentum is conserved MiVi=MaVa+MbVb

MV0=2V0M/3+MVb

Vb=V0/3

A 42.0-cm-diameter wheel, consisting of a rim and six spokes, is constructed from a thin, rigid plastic material having a linear mass density of 25.0 g/cm. this wheel is released from rest at the top of a hill 69.0 m high.

Answers

For a 42.0-cm-diameter wheel, consisting of a rim and six spokes,the angular speed is mathematically given as

w=118.6 rad/s

What is the angular speed?

Generally, the equation for the  Conservation of energy  is mathematically given as

K1+U1=K2+U2

Therefore

Mgh+0=0+(1/2)MV2+(1/2)Iω2

Where

M=m+6m

M=2rλ(π+3)

Therefore

[tex]2r \lambda (\pi+3)gh=0.52r \lambda (\pi+3)(rw)2+(1/2)[(2 \pi \lambda r)r2+6( \lambda r)r2/3]w2[/tex]

[tex]w=\sqrt{[(\pi+3)*9.8*53/(0.42/2)2*(\pi+2)[/tex]

w=118.6 rad/s

In conclusion, The angular speed is

w=118.6 rad/s

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Below is a nuclear equation. What number should go in the place marked (i)?

Answers

Step by step explanation: you have not provided the nuclear equation!

A ball of play-doh with a mass of 1 kg is thrown at 5 m/s against a wall. The wall causes the play-doh to smash and come to a stop in 0.13 s. What force does the wall apply to the play-doh to make it stop?"

Provide the magnitude of the force applied by the wall (number only).

Answers

The magnitude of the force applied by the wall on the ball while smashed is 38.462 newtons.

How to determine the required impact force to stop a ball of Play-Doh(TM)

After a quick reading of the statement we conclude that the impact theorem shall be useful to determine the dynamic force required to stop the ball when smashed. The impulse theorem results from the combination of the Newton's laws of motion, principle of energy conservation and work-energy theorem:

[tex]m \cdot v_{o} = F\cdot \Delta t[/tex]     (1)

Where:

m - Mass of the ball, in kilograms.[tex]v_{o}[/tex] - Initial speed of the ball, in meters per second.Δt - Impact time, in seconds. F - Impact force, in newtons.

If we know that m = 1 kg, [tex]v_{o} = 5\,\frac{m}{s}[/tex] and Δt = 0.13 s, then the impact force is:

F = (1 kg) · (5 m/s)/(0.13 s)

F = 38.462 N

The magnitude of the force applied by the wall on the ball while smashed is 38.462 newtons. [tex]\blacksquare[/tex]

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