A toy snake was horizontally thrown from a height of 115 m. It lands 595 m away. What is the toy snake’s initial speed? (TWO decimal places!!)

The total electric flux through the cylinder is 6.46N⋅m^2/C

Given data:

• The length of the charge is l=  7m.

• The charge is q = 2μC..

• The radius the cylinder is r = 10 cm

The expression for the electric flux is given as,

ϕ=2πrLE

ϕ=2πrL(2kλ/r)

ϕ=4πkλL

Substitute the value in the above equation,

ϕ=4π(9×10^9N⋅m^2/C^2)(2×10^−6C/7m)(0.02m)

= 6.46N⋅m^2/C

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.

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The acceleration of the proton that is  projected in the positive x direction into a region of a uniform electric field is  5.76×〖10〗^13 m/s^2

The product of the field's strength and the charge's strength yields the magnitude of the electric force acting on a charge traveling in a magnetic field region.

The electric force magnitude acting on the charge is expressed in the equation below.

F=|→E|×|q|

F=|-6.00×〖10〗^5 N/C|×||+1.602×〖10〗^(-19) C|

F=9.612×〖10〗^(-14) N

Newton's second law of motion states that the magnitude of a force is equal to the product of a proton's mass and its acceleration. Where the magnitude of the acceleration of the proton is ;

a=F/m  

Where  F is the force and m is the mass;

Inserting the values into the equation,

a=(9.612×〖10〗^(-14) N)/(1.67×〖10〗^(-27) kg)

a=5.76×〖10〗^13 m/s^2

Therefore, the acceleration of proton is 5.76×〖10〗^13 m/s^2 #SPJ4

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Answer:

C. 18 s

&

B. -7 m

Explanation:

A. 12 m/s, East is a vector. It says "East" so it would be a vector. Therefore this is not our answer since it's a vector and the question is asking for which one is not a vector.

B. It says "7 m". I think that means 7 meters. That's a length. There is no direction. It's not 7 meters up, or to the east, or north. So, with no direction, it's not a vector. Therefore this is not our answer.

C. For this one it says ""18 s". I think that means "18 seconds". Since this one is not mentioned "direction" meaning it's not a vector. Since the question is asking for the ones that are not a vector this would be another answer.

D. Since this one says "miles" it means it has a direction since it has a direction it is probably a vector, since it's a vector it wouldn't be our answer. Therefore this is not our answer.

The torque acting on the loop will be zero .

The diagram is given below.

From the diagram ,  vector of the loop and therefore the force field  are parallel to every different which suggests sin 180 ° whose worth is zero.

On putting the value of sin180 in equation (1) , we get

[tex]T=NIAB\times0\\T=0[/tex]

Torque acting on the loop will be zero .

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The mass of the air in the cylinder will be 0.811 Kg.

The ideal gas law also referred to as the generic gas equation, is the equation of state for a hypothetical perfect gas. It is a good approximation of the behavior of several gases under diverse conditions, despite significant limitations.

Given that a vertical cylinder with a heavy piston contains air at 300 K . The initial pressure is 2.00 ×10⁵Pa, and the initial volume is 0.350m³. Take the molar mass of air as 28.9 g/mol.

The mass of the air in the cylinder will be calculated as below:-

P₁V₁ = nRT₁

n = ( P₁V₁  / RT₁ )

( m / M ) =  ( P₁V₁  / RT₁ )

m = ( P₁V₁ M / RT₁ )

m = ( P₁V₁ M / RT₁ ) = ( 2 x 10⁵ x 0.35 x 0.0289 ) / ( 8.314 x 300 )

m = 0.811 Kg

Therefore, the mass of the air in the cylinder will be 0.811 Kg.

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The direction of electric field at any point of z axis is always positive because of the symmetry property.

ELECTRIC FIELD - It is a force that fills the space around  every charge in space.

It is a physical quantity. It represents the vector field that is generated by a charge in the area around that charge. It is defined as the electric force per unit test charge that placed at distance from the charged that generate the electric field.

the electric field is outward from the positive charge and inward  negative point charge.

The direction of electric field at any point of z axis is always positive because of the symmetry property.

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The magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.

We have Hall Probe to measure an unknown Magnetic field.

We have to determine the Magnitude of the unknown Magnetic field.

A  Hall probe is a device that can be used to measure magnetic fields. They work on the principle of Hall effect.

According to the question, we have -

I = 120 mA = 120 x 0.001 = 0.12 Ampere.

B = 0.08 Tesla

V(H) = 0.7 [tex]\mu[/tex]V = 7 x [tex]10^{-7}[/tex]

The formula relating the above quantities is -

V(H) =  [tex]A_{H} \frac{IB}{d}[/tex]

[tex]$\frac{d}{A_{H} } =\frac{IB}{V_{H} }= \frac{0.12 \times 0.08}{7\times 10^{-7} }[/tex] = 13.71 x [tex]10^{3}[/tex]

Now -

For → V = 0.33 [tex]\mu[/tex]V =  0.33 x [tex]10^{-7}[/tex]

[tex]B=\frac{Vd}{A_{H}I }[/tex] = [tex]13.71\times 10^{3} \times\frac{0.33\times 10^{-7} }{0.12}[/tex] = 37.7 x [tex]10^{-4}[/tex] Tesla

Hence, the magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.

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75km=75000m

35min=2100 seconds

Velocity=Displacement/Time

=75000/2100

=750/21

=35.71 m/s

Several narrow tree rings in a row tell us that it was formed in the warm season.

Trees are those plants that grow very tall. We can see that ancient trees play an important role in the determination of the age of some fossils. The patterns of the rings that could be found in these trees also help us to know how old the particular tree is and especially the whether condition of the place around the time that the tree was formed.

This has been corroborated by a lot of biological evidences that show to tat effect. It can also tell us about the weather condition in a place at a particular time.

As such,  several narrow tree rings in a row tell us that it was formed in the warm season.

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A vector with magnitude 8 points in a direction 70 degrees counterclockwise from the positive x axis, the vector component form 11.53.

In Physics, greatness is characterized as the most extreme degree of size and the heading of an item. Extent is utilized as a typical calculate vector and scalar quantities. The size of a seismic tremor is characterized regarding length, expansiveness and width. It is estimated as the actual size of the tremor. A seismic tremor is considered to have a solitary extent. Greatness by and large alludes to the amount or distance. Corresponding to the development, we can associate greatness with the size and speed of the article while voyaging. The size of the article or the sum is its extent. extent for the most part alludes to distance or amount. Corresponding to development, extent alludes to the size of an article or its speed while voyaging. Speed is a scalar property in material science, and that implies that it just depicts the size, or speed, of an item, and doesn't specify the bearing that the article ventures.

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Answer:

this problem we have to draw a velocity-time graph for an object travelling initially at -3 m/s, then slowing down and turning around.

In the graph, we see that the initial velocity at time t = 0 is

v_0 = -3 m/sv

0

=−3m/s

and it is negative, so below the x-axis.

Later, the object slows down: this means that the magnitude of its velocity increases, therefore (since the velocity is negative) the curve must go upward, approaching and reaching the x-axis (which corresponds to zero velocity).

After that, the object's velocity keep increasing, but now it is positive: this means that the object is travelling in a direction opposite to the initial direction, so it has turned around.

Explanation:

I can't draw sorry

The statement that best explains why the system looses energy is; the Collison of the molecules of hydrogen with the wall of the can carries off energy to the environment.

We know that energy is defined as the rate of doing work. Now the temperature of a gas is measure of the kinetic energy of the molecules of the body. In this case, the temperature of the hydrogen in the cannister has to do with how fast the molecules of the hydrogen are moving.

The higher the temperature, the faster the molecules of the hydrogen move. The lower the temperature, the slower the molecules of the hydrogen moves.

As such, the molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.

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On doubling the Amplitude both wavelength and wave speed remains unchanged.

We have a Oscillator whose amplitude is Doubled.

We have to determine the affect of variation in amplitude on wavelength and wave speed.

According to the question, we have -

Initial Amplitude → A

Final Amplitude → 2A

On doubling the Amplitude both wavelength and wave speed remains unchanged. Wavelength is not dependent on Amplitude. It can only be changed by changing its frequency or time period. Wave speed is not dependent on Amplitude. It can only be changed by changing the properties of the string through which the wave is travelling.

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Photon move at the speed of light which is option (b)

As electrons and protons are particles of the atoms and posses mass so they do not move at the speed of light even in vaccum.

Photon is a light energy so it moves with the speed of light .

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Change in length in meters is 0.21 m

volume is given by

 [tex]V_{f} = lwh\\[/tex]

v = volume  [tex]V_{f}[/tex] = Final  volume , [tex]V_{i}[/tex] = initial volume

l = length

w = width

h = height

change in volume expansion,

[tex]V = \beta V_{i} T[/tex]

where

t = change in temperature

[tex]\beta[/tex] = coefficient of volume expansion

coefficient of volumetric expression defined as increasing volume per unit, original volume per Kelvin rising temperature.

[tex]\beta \\[/tex] = 210×10⁻⁶ C⁻¹

[tex]V_{i} = lwh_{i}[/tex]  

[tex]V_{f} - V_{i} = \beta V_{i}T[/tex]

on solving we get,

[tex]h_{f} =[/tex] 210×10⁻⁶ × 1 + 1000 = 1000.21m

Change in length=  [tex]h_{f} -h_{i}[/tex]  = 0.21 m

Change in length in meters is 0.21 m

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The maximum torque acting on the rotor is 1.2× 10⁻⁴ Nm.

To find the maximum torque, the given values are,

No .of turns of the wire = 80

Dimensions is given as, 2.50 cm by 4.00 cm

Magnetic field = 0.800 T.

current = 10 mA.

Angular speed = 3.60 ×10³ rev/min

As the torque is in the current carrying loop in the uniform magnetic field,

τ = NIAB sinθ Nm

   = 80×10×10⁻³×0.0250×0.040×0.800× Sin 90°

   = 2 × 6.4 × 10 ⁻⁴

   = 1.2 × 10⁻⁴ Nm.

Thus, the maximum torque acting on the rotor is 1.2× 10⁻⁴ Nm.

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The annual cost for electricity to power a lamppost for 7.00 h per day with a 100 W incandescent light bulb versus an energy efficient 25 W fluorescent bulb is $25.55 and $6.3875 respectively.

The Power is the amount of Energy produced per unit time.

The general formula for the annual cost can be written as:

[tex]Cost = P\cdot t\cdot d[/tex]

where. P is power, t is time in hours per day, and d is the total days.

Using the formula:

The cost of a 100 W incandescent light bulb:

[tex]Cost=(0.1)(7)(365)(0.10)=\$25.5[/tex]

Similarly,

The cost of a 25 W fluorescent light bulb:

[tex]Cost=(0.025)(7)(365)(0.10)=\$6.3875[/tex]

Hence, the annual cost is $25.55 and $6.3875 respectively.

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The distance between the cliffs is 833.4m.

A cliff is a section of rock with an overall angle defined by the vertical or nearly vertical in geography and geology. Cliffs are created by the gravitational effects of weathering, erosion, and other activities. Cliffs can be seen on rivers, escarpments, steep terrain, and coastlines. Typically, cliffs are made of weather- and erosion-resistant rock. Sandstone, limestone, chalk, and dolomite are the sedimentary materials most likely to result in cliff formation. Cliffs are frequently formed by igneous rocks like granite and basalt.

A geologic fault's movement, a landslide, or occasionally rock slides or falling rocks that alter the differential erosion of the rock layers result in the formation of an escarpment (or scarp), a type of cliff.

Explanation:

Let x1 be the distance between the cowboy and the closer canyon wall and x2 be the distance between him and the farther cliff. The first echo's sound travels a distance of 2x1. 2x2 for the following. The third is

2x1 + 2x2 , for the fourth echo  2x1 + 2x2 + 2x1

speed of sound =  343 m/s

then,

diff  of length  =  2x2 - 2x1 / 343 = 1.92 s

and 2x1 + 2x2 - 2x2 / 343 = 1.47

x1 = 0.5 * 343 * 1.47

= 252.105 m

2x2 / 343 = 1.92 + 1.47

x2 = 581.3 m

a) x1 + x2  =  581.3 + 252.105  =  833.4

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False, because in a rear tire skid when the rear wheel is in line with the front wheel, you want to release the rear brake to quickly straighten the motorcycle.

Understanding the rationale behind each correct response on the motorcycle written test is crucial for passing your motorbike permit examinations and developing into a safe rider.

When riding a motorcycle, a rear wheel skid can be a risky circumstance to encounter.

When the rear wheel locks up as a result of excessive braking, rear wheel skids happen.

You won't be able to turn around if the rear wheel locks up and starts to slide.

You must relieve the pressure on the rear brakes to stop the skidding of the rear wheels. However, the bike might quickly straighten out and knock you off in a high-side crash if the front and rear wheels are not in line when you remove the rear brake.

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the average acceleration of the bullet through the board   -55657×10⁵ m/s²

acceleration-  Rate of change of velocity with respect to time.

S = 0.10 mm = 10⁻⁵ m  ( distance)          [∵ 1mm = 10⁻³]

u =  480 m/s (initial velocity)

v = 345 m/s (final velocity)

As we know the 3rd equation of motion.  

v² = u² + 2aS

a = ? ( acceleration)

using these values in equation we get

(345)² = (480)² + 2×a× 10⁻⁵

a = (345)² -  (480)² / 2× 10⁻⁵

a =  -55657×10⁵ m/s²

The negative sign shows that the direction of acceleration is opposite of velocity thus bullet is slowing down.

the average acceleration of the bullet through the board  -55657×10⁵ m/s²

The given question is incomplete. The complete question is.

a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.

What is the average acceleration of the bullet through the board/?

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The height at which the seagull was flying is 82.45 m.

The height of motion or maximum height in projectile motion occurs when the object reaches a vertical velocity of zero magnitudes.

The height at which the seagull was flying is calculated as follows;

v² = u² - 2gh

where;

0 = u² - 2gh

2gh = u²

h =  u²/2g

h = (40.2²) / (2 x 9.8)

h = 82.45 m

Thus, the height at which the seagull was flying is 82.45 m.

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The electric force acting on a 7.80 nc charge that is located 1.69 m from a 4.54 nc point charge is: 1.115*10^-7 N

To solve this exercise the electric force formula and the procedure we will use is:

F = (k * q1 * q2)/r²

Where:

Information about the problem:

By converting the the values of the charges (q1) and (q2) from (nC) to (C) and we have that:

q1= 7.80 nC * 1 C/ 1*10^ 9 nC

q1= 7.8*10^ -9 C

q2= 4.54 nC * 1 C/ 1*10^ 9 nC

q2= 4.54 *10^ -9 C

We apply the electric force formula we have:

F = (k * q1 * q2)/r²

F = [(9 *10^9 N*m²/C² * (7.8*10^ -9 C) * (4.54 *10^ -9 C)]/ (1.69 m)²

F = 3.187*10^-7 N*m² /2.8561 m²

F = 1.115*10^-7 N

In physics the electric force is the force that attracts or repels two charges (q) separated at a distance called (r), this is expressed in the international system of units in Newton.

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According to the question: The efficiency of the speaker is 0.428%.

The quantity of energy that is transported or transformed through time is referred to as power in physics. One joule per second, or one watt, is the definition of power in the International System of Units. Power is referred to as acting in some ancient writings. A motor's output power is the result of the torque it produces and the angular velocity of its output shaft.

Explanation:

Power output, P₀ = 0.643W

Power input, P₁ = 150W

The efficiency of the speaker = P₀/P₁

                                                  = 0.643W/150W

                                                  = 0.00428 ≅ 0.428%

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The velocity of the car will be 36.8 m/s when it has traveled a distance of 70 cm.

The velocity at any moment in time during a particle's motion is given by instantaneous velocity, a continuous function of time. By calculating the derivative of the position function, which gives us the functional form of instantaneous velocity v, we may determine the instantaneous velocity at a certain time (t).

Velocity is a vector quantity.

SI unit is m/s.

According to the question, the Given values are :

Distance =40 cm

=0.4 meter

Velocity, v =2105.3 cm/s

=21.053 m/s

21.053=0.4/t

⇒t=0.4/21.053

t=0.019 seconds

Now, the distance is 70 cm

=0.70 meters

v=0.7/0.019

v=36.8 m/sec

Hence, the velocity will be 36.8 m/sec when it has traveled a distance of 70 cm.

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The Position-Time graph for the given Velocity-Time graph is drawn in the image attached.

From the Velocity-Time graph we can take the information needed.

[tex]t_{1}[/tex] = 1 s

[tex]t_{2}[/tex] = 2 s

[tex]t_{3}[/tex] = 3 s

[tex]t_{4}[/tex] = 4 s

[tex]t_{5}[/tex] = 5 s

[tex]v_{1}[/tex] = 10 m / s

[tex]v_{2}[/tex] = 20 m / s

[tex]v_{3}[/tex] = 30 m / s

[tex]v_{4}[/tex] = 40 m / s

[tex]v_{5}[/tex] = 50 m / s

v = d / t

d = v * t

[tex]d_{1}[/tex] = 10 * 1 = 10 m

[tex]d_{2}[/tex] = 20 * 2 = 40 m

[tex]d_{3}[/tex] = 30 * 3 = 90 m

[tex]d_{4}[/tex] = 40 * 4 = 160 m

[tex]d_{5}[/tex] = 50 * 5 = 250 m

Therefore, the Position-Time graph is drawn in the image attached.

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Answer:

well....to every direction the body moves towards the force exerted is conducted in the opposite direction of motion.....when it turns around force exerted is not opposite but rather non directional...

The distance covered will  be 0.301m.

firstly we will new to calculate acceleration (a).

we can do so using newtons first law of motion.

v=u + a × t

where

a is the acceleration

t is the time

from here we get

a=(v-u)/t

a=(4-0)/0.15

a=26.67m/s²

using newtons second law of motion

s=u.t+1/2at²

where s is distance travelled in t seconds.

we get,

s=0.301m

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