A tuna jumps out of the water with an initial velocity of 44 feet per second (assume its starting height is 0 feet). Use the vertical motion model, h 16t²+uts where is the initial velocity in feet per second and is is the height in feet, to calculate the amount of time the tuna is in the air before it hits the ground again. Round your answer to the nearest tenth if necessary. ​

Based in the frame rate and the distance travelled by the ball, the speed of the ball is 398.6 cm/s.

The speed of an object or a moving body is the ratio of the distance covered by the moving body or object and the time taken to cover that distance.

Mathematically:

The speed of the ball in the diagram is determined as follows:

Total distance covered by the ball will the product of the distance between the points and the number of point covered by the ball after the original point.

Distance between points = 19 cm

number of points = 6

Total distance covered by the ball = 6 *19 cm

Total distance covered by the ball = 114 cm

Time taken = 1/frame rate * number of points

Time taken = 1/22 * 6

Time taken = 0.286 s

Speed = 114 cm/0.286 s

Speed = 398.6 cm/s

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Answer: All that seems to be needed to be done, is for you to subtract 57m from 70m and that equals: 13m displacement! hope this is helpful! good luck!

Answer:

2.9 Hrs

Explanation:

Time = Distance/velocity

6265  / 2150 ≈ 2.9 hrs

If the thermal coefficient of resistivity for nichrome is 4.5 x 10-4 1/co, the   temperature of the coil of the coil is 0.56 a.

Resistivity is a central property of a material, and it shows how unequivocally the material opposes or transmits electric flow. A low resistivity is an obvious sign of a material which promptly permits electric flow. The resistivity increments implies that the conductivity of the material abatements. For metals or transmitters, it is said that they have a positive temperature co effective. The worth α is positive. Electrical resistivity is a property interesting to each material, which is fundamental to comprehend prior to making and planning electrical and electronic frameworks.

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0.03185A current is required in the windings for that to occur.

It is given that 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T .

Putting above values in equation (1) , we get

[tex]1.00\times10^{-4}=\frac{4\pi \times10^{-7}\times1000I}{0.400} \\\\I=\frac{1.00\times10^{-4} \times0.400}{4\pi \times1000} \\\\I=0.03185A[/tex]

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Answer:

It's all in the Explanation.

Explanation:

You round the number of the IP address and boom. You have your answer.

The wavelength of the final note is 0.389m

The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction. The distance a wave travels between its crests or troughs is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The wave's crest is its highest point, while its dip is its lowest. Because a wavelength represents a distance or length, it is expressed in length units like meters, centimeters, millimeters, nanometers, etc. Light's wavelength changes with color, or it differs for each hue. While violet has the shortest wavelength, red has the longest.

wavelength = v/f

wavelength = 343/800 m = 0.389m

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Electron, photon and proton carry momentum .

Equation (1) can be written as   [tex]\lambda=\frac{h}{p}[/tex]   where λ  is known as de Broglie wavelength and p is momentum , h = Plank’s constant

For photon , the momentum is given by   [tex]p=\frac{E}{c}[/tex]   ...(2)  where c is the speed is the speed of light .

From equation (1) and (2) we can conclude that electron, photon and proton carry momentum .

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The magnitude of the electric field for 40 cm is 1.46 × 10^6 N/C

We choose a Gaussian sphere of radius r = R. Apply Gauss’s law from  Equation (1):

[tex]\Phi_{\text{E}}=\oint \overrightarrow{\mathbf{E}}\cdot d\overrightarrow{\mathbf{A}}=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]

[tex]\oint EdA=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]

[tex]E\oint dA=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]

[tex]EA=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]

Where A is the area of the solid sphere found from Equation (2) and [tex]q_{\text{in}}[/tex] is the charge enclosed by the Gaussian surface  which is the total charge of the sphere found from Equation (3):

[tex]E(4\pi r^2)=\dfrac{\rho V}{\epsilon_0}[/tex]

[tex]E(4\pi r^2)=\dfrac{(Q/\bcancel{V})\bcancel{V}}{\epsilon_0}[/tex]

Solve for E:

[tex]E=\dfrac{Q}{4\pi\epsilon_0 r^2}\tag{6}[/tex]

Substitute numerical values:

[tex]E&=\dfrac{26\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.4)^2}\\ &={1.46\times 10^{6}\;\mathrm{N/C}\;\text{directed radially outward}}}[/tex]

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The phrase which best describes the structure of an atom from the answer choices given above is a nucleus surrounded by an electron cloud.

The correct answer choice is option b

This means that an atom consist of a centrally placed nucleus in which electrons revolves around it. The nucleus of any given atom consist of protons and neutrons. Electrons revolve round the nucleus of any atoi

An atom is a smallest particle of an element that takes part in chemical reaction.

Atom is divided into three basic parts:

So therefore, the phrase which best describes the structure of an atom from the answer choices given above is a nucleus surrounded by an electron cloud.

The correct answer choice is option b

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(a) No, it is not possible if one attract other two then it means rest of two have some sign of charge which repel to each other.

(b)Yes, similarly & it is not possible

(c) Yes, Two current carrying having same direction current, it

attract, If one attract others two it means all have same direction. Hence it is true

(d) (Not possible) Because of one repel other two it means other two have same direction which attract to each other.

Gravity is an invisible force that pulls things toward Earth. Actually, there are other places with gravity than our planet. Every thing in the universe possesses gravity, including you and the stars, planets, and moons. All objects are attracted to one another by gravity.

Every thing on Earth experiences weight, or a gravitational pull produced by the mass of the planet that is proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience.

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283 Hz is the frequency closest to 300 Hz to which the oscillator may be adjusted such that the observer hears a minimal sound.

Δr = 1/2λ

   = v/2f        

f = v / 2Δr

  = 343 / 2(√13 - 3.00)

   = 283 Hz.

Frequency is a vital parameter used in technological know-how and engineering to specify the temporal fee of exchange located in oscillatory and periodic phenomena, including mechanical vibrations, audio signals (sound), radio waves, and light.

The wide variety of intervals or cycles consistent with 2d is referred to as frequency. The SI unit for frequency is the hertz (Hz). One hertz is the same as one cycle in keeping with 2nd.

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The ion rocket engine give an acceleration to the space probe of: 0.001 m/s²

To solve this exercise, the formula and procedure to be applied is:

F = m * a

Where:

Information about the problem:

Applying the force formula and isolating the acceleration, we get:

F = m * a

a = F/m

a = 1 N /1000kg

a =  1 kg * m/s² / 1000kg

a = 0.001 m/s²

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

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Answer:

Ask a question.

Explanation:

Your question is the basis of any theory.

The length of the rod as a function is  379.57 Δt

(b) The speed of a wave in metal=3560 m/s

Let L be the length of the rod.

[tex]-\frac{l}{3560}+\frac{l}{343}=\Delta t \\&l=\Delta t\left(\frac{1}{-\frac{1}{3560}+\frac{1}{343}}\right)[/tex]

[tex]\\&l=379.571 \Delta t \\&\text[/tex]

As a result, the rod's length as a function is 379.57 Δt.

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The primary distinction between a system's ground state and excited state is that a system's ground state is any state in which its electrons are at their lowest potential energy levels, whereas an excited state is any state in which they are at an energy higher than the system's ground state.

Any quantum state of a system that has higher energy than the ground state is considered to be in an excited state in quantum mechanics. An increase in energy level over a predetermined starting point, typically the ground state, but occasionally an already excited state, is referred to as excitation.

A ground-state atom is one in which moving one or more electrons to different orbitals will not reduce the overall energy of the electrons in the atom. In other words, all of the electrons in a ground-state atom are at their lowest conceivable energy levels.

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Answer:

.587 s

Explanation:

d = 1/2 a t^2

1.69 m  = 1/2 ( 9.81 m/s^2) (t^2)

  t = .587 s

The outer gaseous giants are characterized by abundant gases like hydrogen, helium, methane, etc while the inner terrestrial planets are characterized by abundant solid elements like iron, nickel, silicon, etc.

Our solar system consists of the Sun and eight planets orbiting around it that are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

Out of the eight, the four planets closest to the sun i.e Mercury, Venus, Earth, and Mars are terrestrial, which means that their surfaces are rock solid and are composed of elements like iron, nickel, aluminum, silicon, etc.

They also have no moons or a few moons.

On the other hand, the remaining four planets i.e Jupiter, Saturn, Uranus, and Neptune are composed mainly of gases like hydrogen, helium, and methane. They are devoid of solid surfaces.

Also, they all have a large number of moons orbiting them.

Therefore, the outer gaseous giants are characterized by abundant gases like hydrogen, helium, methane, etc while the inner terrestrial planets are characterized by abundant solid elements like iron, nickel, silicon, etc.

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H= 2gu 2sin 2 is the expression for the total range of a projectile launched at an angle that reaches ground that is the same height at the launch position.

Let's imagine that a projectile is moving at a velocity of u at an angle of to the horizontal. After time t, the velocity will be v=v x i+v y j+v=ucos i+(usingt) j (because v y = usingt).

The projectile's only horizontal component at maximum height is vx =ucosv y 2u y2 =2ayv y =0(atm ax heightH)u y =usin ay=gH.

To put these values into context,

0=(usin) 2 2gH

H= 2gu 2sin 2

Projectile angular momentum is equal to mu cos h, where h stands for height. In the case of angular projection, the angle between the velocity and acceleration ranges from 0 to 180 degrees.

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The sound intensity of a jet engine radiating an acoustic power of 2.11×105 w sound at a distance of 50.3 m from the engine is approximately 6.64 [tex]W/m^2[/tex].

The intensity means the amount of loudness in it. The actual definition of intensity is the amount of power a sound has per unit area.

Mathematically, the intensity can be written as:

[tex]I=\frac{Power}{Area}[/tex]

The given data:

Power, P = [tex]2.11\times 10^5 W[/tex]

Area, A = [tex]4\pi d^2=4\pi (50.3)^2 m^2[/tex]

So using the formula, we have:

[tex]I=\frac{2.11\times 10^5}{4\pi (50.3)^2} \approx 6.64 W/m^2[/tex]

Hence, the intensity of a jet engine is approximately 6.64 [tex]W/m^2[/tex].

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pavement is defined as the surface of Road or sidewalk.

for example, the surface of Expressway.

There are two types of pavement.

rigid pavement which consists of one layer.

flexible pavement which consist of multiple layers.

While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the pedal, then apply brake lightly until we are moving at a low speed.

if you run off the pavement, you should: turn the steering wheel quickly toward the road steer straight and slow down before attempting to return to the pavement steer straight ahead and speed up apply the brakes hard

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The speed of electron exceeds that of the proton by 0.917c given that the rest energy of an electron is 0.511MeV and the rest energy of a proton is 938MeV, with both particles having kinetic energies of 2.00MeV.

From,

v=√1-1/γ^2 ×c     (1)

 Where γ=4.91 for electrons and γ=1.002 for protons

The speed of proton is 0.063c and the speed of the electron is 0.98c

∆V  is the change in velocity or speed

V_e  is the velocity of the electron

V_p  is the velocity of the proton

Change in velocity between the electron and proton ∆V=V_e-V_p

∆V=0.98c-0.063c

∆V=0.917c

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The total energy of the proton is 2882.31 MeV.

We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by

Eo = m₀ . c²

where Eo is rest energy, m₀ is rest mass and c is speed of light (3 x 10⁸ m/s).

The total energy of object can be described as

E = Eo / √(1 - v²/c²)

where E is total energy, v is the object speed.

From the question above, we know that :

m₀ = 1.6 x 10¯²⁷ kg

c = 3 x 10⁸ m/s

v = 0.95c

Find the rest energy

Eo = m₀ . c²

Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²

Eo = 1.44 x 10¯¹⁰ joule

Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV

Eo = 900 x 10⁶ eV

Eo = 900 MeV

Determine the total energy

E = Eo / √(1 - v²/c²)

E = 900 / √(1 - (0.95c)²/c²)

E = 900 / 0.31

E = 2882.31 MeV

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The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 125 m * (2 * 9.8 m/s²))

v₀ = √( 125 m * 19.6 m/s²)

v₀ = √2450 m²/s²

v₀ = 49.497 m/s

Applying the maximum time formula we get:

t max= v₀ / g

t max= 49.497 m/s / 9.8 m/s²

t max = 5.050 s

Applying  the time of flight formula, we get:

t(of) =2 * t max

t(of) =2 * 5.050 s

t(of) = 10.1 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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The time spent in the air by the ball is 10.01 seconds.

The total time spent in the air by the ball is the sum of the time it spends moving up and the time it spends falling down.

The time spent by the ball moving up - time spent by the ball travelling down.

Time spent by the ball traveling down a distance of 125 meters is calculated using the formula given as follows:

t = √2h/g

Total time spent = 2 * √2h/g

where:

h = 125 m

g = 9.81 m/s²

T = 2 * √(2 * 125/9.81)

T = 10.01 s

Therefore, the time spent in the air by the ball is the sum of the time spent moving up and the time it spends falling down which are both equal.

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K-wires or pins are smooth, sharpened, and sterilized pins made of stainless steel. The wires are now frequently utilized in orthopedic surgery as well as other forms of human and animal surgery.

Sometimes it's necessary to mend a fracture with Kirschner wires (K-wires), which are firm, straight wires (broken bone). K-wires are frequently referred to as "pins." K-wires may be required if your child has a fracture that requires surgery in order to keep the bones in place while they mend.

Surgery is used in open reduction and internal fixation (ORIF) to put shattered bone fragments back together. The shattered bone is held together with screws, plates, sutures, or rods. When a shattered bone is in multiple parts, an ORIF is frequently performed as an emergency operation. The goal is to facilitate joint bone healing.

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The result will be E1=E2>E4>E3

When the plane of the armature of an a.c. dynamo is parallel to the lines of force of the magnetic field, the amplitude of the induced e.m.f. is at its greatest. Additionally, the rate of change of the magnetic flux associated with the armature is at its greatest. As a result, in this orientation, the e.m.f. induced in the armature is greatest.

The EMF's amplitude is equal to Nr2B. N is the number of turns, and r is the square's half-side.

In example 3, the axis is perpendicular to the magnetic field, hence the flux is zero and the amplitude is zero as a result.

Case 4 has an axis that falls between types 1, 2, and 3.

Here, we must consider the angular velocity's x and y components.

Component in the x direction will be zero.

Additionally, the new angular velocity will be 2w because it is exactly halfway between x and y.

So now put these numbers in actual formula. The result will be E1=E2>E4>E3

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The resultant velocity of the boat with respect to the North is 17 m/s North-West.

Resultant velocity is the single velocity obtained when two or more velocities are are combined.

To calculate the resultant velocity of the boat, we use the formula below.

Formula:

From the question,

Given:

Substitute these values into equation 1

Hence, the resultant velocity of the boat with respect to the North is 17 m/s North-West.

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Yes, electromagnetic can travel without medium.

Mechanical waves and electromagnetic waves are two important ways that energy is transported in the world around us.

Waves in water and sound waves in air are two examples of mechanical waves.

Mechanical waves are caused by a disturbance or vibration in matter, whether solid, gas, liquid, or plasma.

Matter that waves are traveling through is called a medium.

These mechanical waves travel through a medium by causing the molecules to bump into each other, like falling dominoes transferring energy from one to the next.

Sound waves cannot travel in the vacuum of space because there is no medium to transmit these mechanical waves.

On the other hand electromagnetic waves don't require medium for its propagation.

An easy example would be light which is an EM wave reaches earth even though space has no medium.

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The Energy flux from Star B is 16 times of the energy flux from Star A.

We have Two stars - A and B with 4900 k and 9900 k surface temperatures.

We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.

Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-

[tex]$\frac{Energy}{Area} = \sigma\times T^{4}[/tex]

Now -

Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -

[tex]$E= \sigma\times T^{4}[/tex]

Now -

For Star A →

[tex]T_{A}[/tex] = 4900 K

For Star B →

[tex]T_{B}[/tex] = 9900 K

Therefore -

[tex]$\frac{T_{B} }{T_{A} } =\frac{9900}{4900}[/tex]

[tex]\frac{T_{B} }{T_{A} }=[/tex] 2.02 = 2 (Approx.)

Now -

Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -

[tex]$\frac{E(B)}{E(A)} = \frac{\sigma\times T(B)^{4} }{\sigma \times T(A)^{2} }[/tex]

E(B) = E(A) x [tex](\frac{T(B)}{T(A)} )^{4}[/tex]

E(B) = E(A) x [tex]2^{4}[/tex]

E(B) = 16 E(A)

Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.

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