After modifying a numbered list in her presentation, Su notices the numbers and the text are too close to each other. She knows she can solve this issue by using the hanging indent marker. Unfortunately, the ruler is not visible in her PowerPoint workspace.

Which tab and command group should she use to access the ruler? (View, Show or Insert, Add-ins or Home, Paragraph)
After selecting the numbered list, in which direction should she drag the hanging indent marker to increase the space between the numbers and the text? (upward or downward or to the left or to the right)

Answer:

count = 0

while True:

   people = int(input("Enter the number of people arrived/departed: "))

   count += people

   if count == 100:

       print("The bar is full")

       break

   elif count < 100:

       print("There are " + str(count) + " in the bar currently")

   else:

       print(str(people) + " people cannot enter right now")

       print("The maximum capacity is 100!")

       count -= people

       print("There are " + str(count) + " in the bar currently")

Explanation:

*The code is in Python.

Set the count as 0

Create an indefinite while loop.

Inside the loop:

Ask the user to enter the number of people arrived/departed

Add the people to the count (cumulative sum)

Check the count. If the count is 100, stop the loop. If the count is smaller than 100, print the current number of people. Otherwise, state that they cannot enter right now. The capacity is 100 at most. Subtract the people from the count and print the current number of people.

Answer:

The answer is B. I'm pretty sure It is

Explanation:

I just took the quiz and it was right  

Answer: B I took the test

Explanation:

The function that will add a name to a list of baseball players in Python is main(). The correct option is b.

Python is a popular computer programming language used to create software and websites, automate processes, and analyze data. Python is a general-purpose language, which means it may be used to make many various types of applications and isn't tailored for any particular issues.

A function is a section of code that only executes when called. You can supply parameters—data—to a function. The main() function in Python serves as the point at which any software application is executed.

Since the program only runs when it is executed directly, and not if it is imported as a module, the execution of the program can only begin when the main() function is declared in Python.

Therefore, the correct option is b, main().

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Answer:

1 - Commenting and Documentation.

2 - Consistent Indentation.

3 - Avoid Obvious Comments.

4 - Code Grouping.

5 - Consistent Naming Scheme.

6 - DRY Principle.

7 - Avoid Deep Nesting.

8 - Limit Line Length.

Explanation:

Hope this helped

Answer:

wireless technology that lets you identify and track objects  (radio frequency identification)

medical uses of RFID  (patient identification)

a low-power radio wave used for short distances  (bluetooth)

computing device used with Bluetooth hands-free microphone in car

Explanation:

sorry if late :/

Answer:

Explanation:

edg 2021

Answer:

c

Explanation:

Answer:

False

Explanation:

Being distracted isn't gonna result in better grades

Answer:

18

Explanation:

If you take the formula, and you substitute the values of the variables, it will be:

    10 * 2 - 10 / 5

Then if you remember the order of math operations, it will be:

    (10 * 2) - (10 / 5)

Which reduces to:

    20 - 2 = 18

The value of the variable result is 18

The code is represented as follows:

a = 10

b = 2

c = 5

result = a * b - a / c

Then the arithmetic operation  variable a multiplied by variable b minus  variable a divided by variable c is stored in the variable "result".

Printing the variable "result" will give you 18.

Check the picture to see the result after running the code.

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Answer:

public static void main(String[] args)

   {

       int cdCount;

       double cdCountAfterDiscount;

       DecimalFormat df = new DecimalFormat("$##.##"); // Create a Decimal Formatter for price after discount

       System.out.println("Enter the amount of CD's bought");

       Scanner cdInput = new Scanner(System.in);  // Create a Scanner object

       cdCount = Integer.parseInt(cdInput.nextLine());  // Read user input

       System.out.println("CD Count is: " + cdCount);  // Output user input

       if(cdCount <= 14 )

       {

           System.out.println("There is no discount");

           System.out.println("The final price is " + cdCount*3.5);

       }

       if(cdCount >= 15 && cdCount<=50)

       {

           System.out.println("You have a 1% discount.");

           cdCountAfterDiscount = (cdCount *3.5)-(3.5*.01);

           System.out.println("The final price is " + df.format(cdCountAfterDiscount));

       }

       if(cdCount >= 51 && cdCount<120)

       {

           System.out.println("You have a 5% discount.");

           cdCountAfterDiscount = (cdCount *3.5)-(3.5*.05);

           System.out.println("The final price is " + df.format(cdCountAfterDiscount));

       }

       if(cdCount >= 120)

       {

           System.out.println("You have a 10% discount.");

           cdCountAfterDiscount = (cdCount *3.5)-(3.5*.1);

           System.out.println("The final price is " + df.format(cdCountAfterDiscount));

       }

   }

Answer:

Here is the JAVA program:

import java.util.Scanner;  //to accept input from user

public class Main { // class name

 public static void main(String [] args) {  // start of main method

   Scanner input = new Scanner(System.in);  // creates Scanner class object to take input from user

   System.out.println("Please Enter the Cost of the Item: ");  // prompts user to enter the cost of item

   double itemCost = input.nextDouble();  //scans and reads the input value of item cost

   System.out.println("Please Enter the Amount Paid: ");  // prompts user to enter the amount paid

   double amount = input.nextDouble();  //scans and reads the value of amount from user

   int change = (int)(amount * 100 - itemCost * 100);  //compute the remaining amount i.e. change

   System.out.println("Change Owed: " + change / 100.0);  // displays the owed change

   int quarters = change / 25;  // computes the value for quarters

   change = change % 25;  // compute the quarters remaining

   int dimes = change / 10;  //  computes dimes

   change = change % 10;  //  computes dimes remaining

   int nickels = change / 5;  // computes nickels

   change = change % 5;  // compute nickels remaining

   int pennies = change;  // computes pennies

   System.out.println("Quarters: " + quarters);  // displays computed value of quarters

   System.out.println("Dimes: " + dimes);  // displays value of dimes

   System.out.println("Nickels: " + nickels);  // displays value of nickels

   System.out.println("Pennies: " + pennies);   }} //displays value of pennies

Explanation:

I will explain the program with an examples.

Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:

Change is computed as

change = (int)(amount * 100 - itemCost * 100);

This becomes;

change = (int)(5.00 * 100 - 4.57 * 100)

            = 500 - 457

change = 43

Now the change owed is computed as:

change / 100.0 = 43/100.0 = 0.43

Hence change owed = 0.43

Next quarters are computed as:

quarters = change / 25;

This becomes:

quarters = 43/25

quarters = 1

Now the remaining is computed as:

   change = change % 25;

This becomes:

   change = 43 % 25;

  change = 18

Next the dimes are computed from remaining value of change as:

dimes = change / 10;

dimes = 18 / 10

dimes = 1

Now the remaining is computed as:

   change = change % 10;

This becomes:

   change = 18 % 10

  change = 8

Next the nickels are computed from remaining value of change as:

nickels = change / 5;

nickels = 8 / 5

nickels = 1

Now the remaining is computed as:

   change = change % 5;

This becomes:

   change = 8 % 5

  change = 3

At last the pennies are computed as:

pennies = change;

pennies = 3

So the output of the entire program is:

Change Owed: 0.43                                                                                                                Quarters: 1                                                                                                                      Dimes: 1                                                                                                                         Nickels: 1                                                                                                                       Pennies: 3  

The screenshot of the output is attached.

Answer:

The answer to this question is given below in the explanation section. The forth one (FLAC and ALAC) is the correct option.

Explanation:

Common lossless compressed audio file formats include

Lossless compression formats include the common FLAC, WavPack, Monkey's Audio, ALAC (Apple Lossless).  Other options are not common lossless compressed audio formats.

Answer:d d

Explanation:

Answer: Dropdown

Choose the word that makes each sentence true.

Asking the user for four numbers is an example of__input__.

Finding the average of the four numbers is an example of__processing___.

Telling the user the average is an example of__output___.

Explanation:

Following are the discussion to the given question:

Therefore, the answer is "input, processing, and output".

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Answer:

.725

Explanation:

You are going back 2 spaces.

Answer:

0.725

Explanation:

Edge 2022

B. Online games are an influential medium.

Answer:

See Explanation

Explanation:

The lines with incorrect syntax and corrections are:

1.

Line:

usersChoice == Integer.parseInt(usersChoiceString);

Error

The error is that a relational operator (==) is used instead of an assignment operator (=)

Correction

usersChoice = Integer.parseInt(usersChoiceString);

2.

Line:

System.out.println("Fries with that?\n1 - Yes\n2 - No";

Error:

The line requires a corresponding close bracket

Correction

System.out.println("Fries with that?\n1 - Yes\n2 - No");

3.

Line:

usersChoiceString = input.next()

Error:

The line is not terminated

Correction:

usersChoiceString = input.next() ;

4.

Line

if (usersChoice = 1)

Error

A relational operator is needed

Correction:

if (usersChoice == 1)

Lastly, you need to initialize bill to a value or prompt user for input.

I've added the full source code as an attachment

Answer:

b

Explanation:

Answer:

B. Online Predators

Explanation:

Answer:

-is positioned relative to the browser window

Hope this helps!

Answer: When you set the position property for a block element to fixed, the element  remains in an exact position on the screen even if the page is scrolled down.

Answer: A parameter or a formal argument is used

1/3 ~ 100001.010101...

an exact value cannot be found; therefore, the zeros in ones in this binary representation of 1/3 alternate forever.

Answer:

1.  Insert

2. Text

3. Object

4. Create from file

Explanation:

On edg

After formatting his Excel table, Lee should navigate to the Insert tab and use the text command group.

An Excel table can be defined as a rectangular range of data in a spreadsheet document, which comprises cells that are typically arranged by using rows and columns.

In this scenario, Lee should navigate to the Insert tab and use the text command group after formatting his Excel table.

Also, an option which he click is object while clicking on the "create from file" button in the dialog box that opens.

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Answer:

D. if else inside a for loop

Explanation:

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <cstring>  //to manipulate C-strings

#include <string>  //to manipulate strings

using namespace std;  //to access objects cin cout

//function prototypes

void upper(char *);  to convert to upper case

void lower(char *);  //to convert to lower case

void reverse(char *);  //to convert to reverse case

int main() {  //start of main method

   char input[101];  //creates a char type array to hold input string

   cout << "Enter a string: ";  //prompts user to enter a string

   cin.getline(input, 101);  //reads input string from user

   upper(input);  //calls upper() method to convert the string to upper case

   lower(input);  //calls lower() method to convert the string to lower case

   reverse(input); } //calls reverse() method to convert the string to reverse case

void upper(char *cString){  //method that takes a pointer to a C-string as it's only argument and converts that string to upper case

   cout << "String in upper case: ";  //displays string in upper case

   for(int i = 0; i < strlen(cString); i++){  //iterates through the input string cString until the length of the cString is reached

       if(islower(cString[i]))  //checks if the character at i-th index of cString is in lower case

           cout << (char) toupper(cString[i]);  //converts each i-th character of cString to upper case at each iteration

       else  //if no character of cString is in lower case

           cout << cString[i];    }  //displays the cString as it is

   cout << endl;}  //prints a new line

void lower(char *cString){  //method that takes a pointer to a C-string as it's only argument and converts that string to lower case

   cout << "String in lower case: "; //displays string in lower case

   for(int i = 0; i < strlen(cString); i++){  //iterates through each character using for loop  first character to last

       if(isupper(cString[i]))  //checks if the character at i-th index of cString is in upper case

           cout << (char) tolower(cString[i]);  //converts each i-th character of cString to lower case at each iteration

       else  //if no character of cString is in upper case

           cout << cString[i];    }  //displays the cString as it is

           cout << endl; }  //prints a new line

void reverse(char *cString){  //method that takes a pointer to a C-string as it's only argument and converts that string to reverse case (upper to lower and vice versa)

   cout << "String in reverse case: ";  //displays string in reverse case

   for(int i = 0; i < strlen(cString); i++){  //iterates through each character using for loop  first character to last

       if(isupper(cString[i]))  //checks if the character at i-th index of cString is in upper case

           cout << (char) tolower(cString[i]);  //converts character at i-th position of cString to lower

       else  //if the character is in lower case

           cout << (char) toupper(cString[i]);    }  //converts character at i-th position of cString to upper

   cout << endl;}  //prints a new line

Explanation:

I will explain the program with an example.

Lets suppose user enters "hi" as input. So

Now first upper() method is called by passing this C-string to it.

It has a for loop that checks at each iteration, if a character of C-string is in lower using islower method which returns true if the character is in lower case. Since both the characters 'h' and 'i' are in lower in case so they are converted to upper case at each iteration using toupper() method. So the output of this part is:

String in upper case: HI

Now next lower() method is called by passing this C-string to it.

It has a for loop that checks at each iteration, if a character of C-string is in upper using isupper method which returns true if the character is in upper case. Since both the characters 'h' and 'i' are in lower in case so the string remains as it is. So the output of this part is:

String in lower case: hi

Now next reverse() method is called by passing this C-string to it.

It has a for loop that checks at each iteration, if a character of C-string is in upper using isupper method which returns true if the character is in upper case. Since both the characters 'h' and 'i' are in lower so else part: cout << (char) toupper(cString[i]); executes which converts these characters to upper case (reverse case). So the output of this part is:

String in reverse case: HI

The screenshot of program output with a different example is attached.

Answer:

The answer to this question is given below in the explanation section.

Explanation:

Which function key is used to update the total in cell?        

(a) F7

(b) f8

(c) f9      

The intersection of a column and row is called a

(a) Border

(b) table

(c) cell

Tables group is present on the  tab.

(a) layout

(b) insert

(c) home        

Which key combination moves the cursor to the previous cell?

(a) Tab + alt

(b) shift + tab

(c) none of these      

5. Which style affects the selected text within a paragraph?

(a) Character style

(b) paragraph style

(c) built-in style

Answer:

Written in Python

inputt = input()

if inputt == "SPATHIPHYLLUM":

     print("Yes - Spathiphyllum is the best plant ever!")

elif inputt == "spathiphyllum":

     print("No, I want a big Spathiphyllum!")

else:

     print("Spathiphyllum! Not"+ inputt+"!")

Explanation:

This line gets user input

inputt = input()

This line checks if input is uppercase SPATHIPHYLLUM and executes the corresponding print statement, if true

if inputt == "SPATHIPHYLLUM":

     print("Yes - Spathiphyllum is the best plant ever!")

This line checks if input is uppercase spathiphyllum and executes the corresponding print statement, if true

elif inputt == "spathiphyllum":

     print("No, I want a big Spathiphyllum!")

If user input is not upper or lower case of Spathiphyllum, the following if condition is considered

else:

     print("Spathiphyllum! Not"+ inputt+"!")

Answer: all answers for test are

Slide Master View

Layout and Theme

PowerPoint Template

A.

C.

Slide Master Thumbnail, Insert Tab, Header &Footer, Slide tab in the dialog box.

D.

C.

D.

Explanation:

The first thing Harry should do is select the Slide Master View, Next, he should use the command groups to edit the Layout and Theme. Finally, he should save the file as a new PowerPoint Template.

It is a presentation-based programme that employs graphics, movies, etc. to enhance the interactivity and appeal of a presentation.

A saved Powerpoint presentation has the ".ppt" file extension. PPT is another name for a PowerPoint presentation that includes slides and other elements.

This right-sided brain activity is perfectly suited to the principal function of PowerPoint presentations.

For his PowerPoint presentation, Harry wants each slide to have a consistent appearance.

Harry must first choose the Slide Master View before using the command groups to change the Layout and Theme. The file should then be saved as a fresh PowerPoint Template.

Thus, this way, Harry can create a uniform look.

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Answer: c

Explanation:

c

Answer:

#include<iostream>

using namespace std;

int main()

{

float feet, yard, inch, meter, cmeter;

cout<<"Enter number of feet: ";

cin>>feet;

yard = feet * 12/36;

inch = yard * 36;

cmeter = inch * 2.54;

meter = cmeter * 100;

cout<<feet<<" feet = "<< yard<<" yard = "<<inch<<" inches = "<<cmeter<<" cm = "<<meter<<" m";

return 0;

}

Explanation:

This line declares all necessary variables

float feet, yard, inch, meter, cmeter;

The line prompts user for number of feet

cout<<"Enter number of feet: ";

This line gets user input

cin>>feet;

The next 4 lines converts feet to yard, inches, centimeter and meter

yard = feet * 12/36;

inch = yard * 36;

cmeter = inch * 2.54;

meter = cmeter * 100;

This line prints converted units

cout<<feet<<" feet = "<< yard<<" yard = "<<inch<<" inches = "<<cmeter<<" cm = "<<meter<<" m";

Answer:

It's A. The recipient will not be able to open the contact item.

Explanation:

Correct on edg

Answer:

A on edg

Explanation:

Answer: darkened

Explanation: darkened

Answer:

While the softer B pencils are generally considered the best for shading, there's no reason to discount the harder H pencils. The HB and H are good choices for fine, light, even shading. However, they too have drawbacks. Pencil grades from HB through H, 2H to 5H get progressively harder and are easier to keep sharp.

Answer:

Yes

Explanation:

I see his damage and rpm as unfair because of the fact that he can deal over 36,000 damage in one minute.