an electron in the 3rd shell of an Aluminium atom moves to the first shell in a bombardment process. Calculate the frequency of the electron the 3rd orbit and energy used in transition to the first shell.[h=6.626*10^-14J/Hz [R=3.29*10^15 Hz]

Answers

Answer 1

Following the quantic theory, the energy of a photon equals the radiation frequency multiplied by the universal constant. ν = 2.923x10¹⁵ Hz. E = 3.09x10¹⁵Hz.

What is quantum mechanic?

It is the branch of physics that studies objects and forces at a very low scale, at atoms, subatoms, and particles levels.

Quantum mechanics states that the elemental particles that constitute matter -electrons, neutrons, protons- have the properties of a wave and a particle.

It emerges from the quantic theory exposed by Max Planck (1922), in which he affirmed that light propagates in energy packages or photons.

He discovered the Universal Planck constant, h, used to calculate the energy of a photon.

He stated that the energy of a photon (E) equals the radiation frequency (ν) multiplied by the universal constant (h).

E = νh

In the exposed example, we need to calculate the energy required to change from the 3rd shell to the first shell.

To do it, we should know that the energy in a level (Eₙ) equals the energy associated to an electron in the most inferior energy level (E₁) divided by the square of the shell number (n²).

Eₙ = E₁ / n²

E₁ is a constant. We can express it in Joules or electroVolts

E₁ = -2.18x10⁻¹⁸ JE₁ = -13.6 eV

So, let us calculate the energy at level 1 and 3

Eₙ = E₁ / n²

E₁ =  -2.18x10⁻¹⁸ J / 1² =  -2.18x10⁻¹⁸ J

        E₁ =  -13.6 eV / 1² =  -13.6 eV

E₃ =  -2.18x10⁻¹⁸ J / 3² =  -2.18x10⁻¹⁸ J / 9 = - 2.42x10⁻¹⁹ J

        E₃ =  -13.6 eV / 3² =  -13.6 eV / 9 = - 1.51 eV

The change of energy can be calculated in two ways,

Option 1

ΔE = E₁ - E₃ = 2.18x10⁻¹⁸ - 2.42x10⁻¹⁹ = 1.93x10⁻¹⁸J

ΔE = E₁ - E₃ = 13.6 - 1.51 = 12.09 eV

Option 2

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE =-13.6 eV (1/nf² - 1/ni²)

Where nf is the final level and ni is the initial level. When the electron passes from its initial level to its final level it is called electronic transition.

ni = 3nf = 1

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE = -2.18x10⁻¹⁸ J (1/1² - 1/3²)

ΔE = -2.18x10⁻¹⁸ J (1 - 0.111)

ΔE = -2.18x10⁻¹⁸ J (0.888)

ΔE = - 1.937x10⁻¹⁸ J

or

ΔE = -13.6 eV  (1/nf² - 1/ni²)

ΔE = -13.6 eV  (1/1² - 1/3²)

ΔE = -13.6 eV  (1 - 0.111)

ΔE = -13.6 eV  (0.888)

ΔE = -12.08 eV

This is the energy required for the electron to go from n= 3 to n = 1. The negative sign (-) means energy (as light or photons) released or emitted.

If we want to express the result in Hz, we just need to make a conversion.

1Hz ⇔ 6.626x10⁻³⁴J ⇔ 4.136x10¹⁵ eV.

The energy required for the electron to go from n= 3 to n = 1 is 3.09x10¹⁵ Hz.

Now, we need to calculate the frequency, ν. This is, how many times the wave oscillates back and foward per second.

To do it, we will use the universal Planck constant, h, and the absolute value of the energy, E.

ν = E/h = 1.937x10⁻¹⁸ J / 6.626x10⁻³⁴ Js = 2.923x10¹⁵ 1/s =  2.923x10¹⁵ Hz.

Answer:

Frequency, ν = E/h = 2.923x10¹⁵ Hz.Energy, E = 3.09x10¹⁵ Hz.

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Related Questions

This question is in my General Chem 2 class. I will give Brainlist!


Given: 8As + 12H20 —>3H2AsO4- + 3H+ + 5AsH3 What mass of arsenic is required to produce 15.0 mL of 0.0852M H2AsO4-?

A. 0.0359 g

B. 0.255 g

C. 17.0 g

D.1134 g

Answers

Answer:

B

Explanation:

From the given chemical equation, we want to determine the mass of arsenic necessary to produce 15.0 mL of 0.0852 M H₂AsO₄⁻.

Find the amount of moles present in 15.0 mL of 0.0852 M H₂AsO₄⁻ solution. Recall that M = mol/L:

[tex]\displaystyle 15.0\text{ mL} \cdot \frac{0.0852\text{ mol H$_2$AsO$_4^-$}}{1\text{ L}} \cdot \frac{1\text{ L}}{1000\text{ mL}} = 0.00128\text{ mol H$_2$AsO$_4^-$}[/tex]

With stoichiometric ratios and molecular weights, determine the mass of arsenic necessary:

[tex]\displaystyle 0.00128 \text{ mol H$_2$AsO$_4^-$} \cdot \frac{8\text{ mol As}}{3\text{ mol H$_2$AsO$_4^-$}}\cdot \frac{74.92\text{ g As}}{1\text{ mol As}} = 0.256\text{ g As}[/tex]

In conclusion, the answer is B.

1. Nene geese in Hawaii are endangered because of
O pollution exotic species
O poaching
O habitat destruction​

Answers

Answer:

✔ habitat destruction

Explanation:

the 3 reasons are:

hunting

habitat loss

introduced predators

summed up its habitat destruction

How many Calories are contained in one tablespoon of palm oil, which has 45.3 g of fat? [Hint: One
gram of protein or one gram of carbohydrate typically releases about 4 Calg, while fat releases 9
Cal/g.] Report your answer to 1 significant figure.

Answers

Answer:

120 calories

Explanation:

Calories and nutrition for world population. One tablespoon of palm oil has 120 calories and 13.6 grams of fat. What does it tell you? Of the 13.6 grams of fat in a tablespoon of palm oil, 6.7 grams are saturated and 6.3 grams are unsaturated.

If you have 146.0 grams of HCl, how many grams of H2O can that produce?

Answers

Answer:

9 gram of H2O can be produced

how many oxygen atom in 0.25 mol ca(No3)2?

Answers

Answer:

1 molecule of Ca(NO3)2 has 6 oxygen atoms.

How do I solve this

Answers

Answer:

try doing a math problem it may help

Explanation:

b. A silver ring contains 1.1 × 1022 silver atoms. How many moles of silver are in the ring?

Answers

Answer:

1124.2

Explanation:

just easy mathamatics

Many cigarette lighters contain liquid butane, C4H10, which has a ∆H°ƒ = –147.6 kJ/mol. Using enthalpies of formation, calculate the quantity of heat produced when 1.0 g of butane is completely combusted in air. (Write the equation for the process first)

Answers

For cigarette lighters containing liquid butane, C4H10, the quantity of heat produced  is mathematically given as

q= -49.2 KJ

What is the quantity of heat produced when 1.0 g of butane is completely combusted in air?

Generally, the equation for the Chemical reaction   is mathematically given as

C₄H₁₀(l) + 6.5 O₂(g)---->4 CO₂(g) + 5 H₂O(l)

Therefore

dH°r = .(-393.5 ) + 5.(-285.5] - [1.(-147.6 )+6.5.

dH°r = -2853.9 kJ/mol

In conclusion, No.of mole

Nm = 1g/58g/mol

Nm= 0.01724mol

Hence, Heat of combustion

q = dH°r x moles

q = -2853.9 ×0.01724

q= -49.2 KJ

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Which of the following mixtures cannot be separated by using both particle size and color as observable properties?
(A) Nickels and pennies
(B)Sand and rocks
(C) Stick and stones
(D)Salt and beans

Answers

Answer:

(A) Nickels and pennies

19. Which reaction will form a salt and water?
Aa precipitation reaction
Ba displacement reaction
Can acid-base neutralization
Dan ionic dissociation reaction

Answers

Answer:

acid-base neutralization

Explanation: When a base and acid react, it neutralizes the substance making it a neutral substance, which is water and a salt

What family kept the kings of Nepal under guard and would not let them have any power.

Answers

Answer:

Gyanendra of Nepal

Which pictures shows the proper structure of the water molecule? Click the picture to see each choice.

Answers

The third picture is the answer

Explanation:

there are 2 hydrogen atom 1 oxygen

An element has 25 protons and 30 neutrons. What is the correct nuclear notation for the element? Please use the Periodic Table to find the correct symbol

Answers

Answer:

It is:

55

Mn

25

What is the pH of a 0.050 M LiOH solution?

Answers

Answer:

a. <1.0

b. 1.30

c. 3.00

d. 11.00

e. 12.70

How many moles of CO2 will be produced in the following reaction if the initial amount of reactants was 0.50 moles?

2NaHCO3 —> Na2CO3 + CO2 + H2O

Answers

Answer:

In the following reaction, how many moles of

CO2

can be made by reacting 0.50 moles of

CH4

with excess oxygen?

CH4+O2>CO2+H2O

Explanation:

What pressure is exerted by 901.3 g of CH4 in a 0.690 L steel container at 185.7 K

Answers

Ideal gas law:  PV = nRT

Write down what you know and what you want to fine:

P = pressure = ?

V = volume in liters = 0.950 L

n = moles = 727.2 g x 1 mol CH4 / 16 g = 45.45 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 221.9K

Solve for P:

P = nRT/V = (45.45)(0.0821)(221.9) / 0.950

P = 872 atm (3 sig. figs. based on 0.950 L having 3 s.f.)

HELP ME OUT PLS!!!!!!!

Our earth is situated in the Milky Way galaxy. The Milky Way galaxy is which type of galaxy?

elliptical

irregular

spiral

oval​

Answers

Answer:

the spiral type of galaxy

Our earth is situated in the Milky Way galaxy. The Milky Way galaxy is a spiral galaxy. Therefore, the correct option is option C.

What is milky way galaxy?

The Milky Way constellation is indeed a huge spiral formation containing hundreds of trillions of stars, along with the Sun. the irregularly formed belt of stars and gas clouds visible from Earth that spans the sky. despite the reality that Earth is positioned within the Milky Way constellation, astronomers do not completely understand its nature, despite its proximity with other external star systems.

A dense layer of interstellar dust obscures the majority of the Galaxy from optical observatories, and astronomers can only understand its massive building with the assistance of radio and infrared telescopes, which can detect the forms of light that may travel through the obscuring material. Our earth is situated in the Milky Way galaxy. The Milky Way galaxy is a spiral galaxy.

Therefore, the correct option is option C.

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#SPJ6

what is joule ?
a. time
b. mass
c. volume
d. length
e. none ​

Answers

Explanation:

It is the unit of work or energy

Define, giving examples of
Binary ionic Compound:​

Answers

Answer:

A binary ionic compound contains an ion that is a metal (cation) and an ion that is a nonmetal (anion).

Explanation:

Tell me if its wrong

3.Calculate the pH of a 0.250 M solution of potassium phenolate, KC6H5O. Ka for phenol (C6H5OH) is 1.0 x 10-10.

Answers

From the statement and the information available in the question, the pH of the solution is 12.2.

What is Ka?

The term Ka refers to the acid dissociation constant of a substance, we can obtain this by setting up the ICE table as shown;

       C6H5O^-  +   H2O ⇄  C6H5OH + OH^-

I         0.250                           0                0

C         -X                                +X             +X

E      0.250 -x                         x                x

Now;

Kb = 1 * 10^-14/ 1.0 x 10-10

Kb = 1 * 10^-4

Kb = [C6H5OH] [OH^-]/[C6H5O^-]

1 * 10^-4 = x^2/ 0.250 -x

1 * 10^-4 (0.250 -x) = x^2

2.5 * 10^-4 - 1 * 10^-4 x = x^2

x^2 + 1 * 10^-4 x  - 2.5 * 10^-4 = 0

x=0.016 M

Given that; [C6H5OH] = [OH^-] =x

pOH = -log(0.016 M) = 1.8

pH = 14 - 1.8 = 12.2

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PLEASE HELP 50 POINTS NO ROBOTS OR I WILL REPORT Which functional group does the molecule below contain?
H
H-C-C
H
H
O A. Ether
O B. Amino
O C. Hydroxyl
• D. Carbonyl

Answers

Answer:

D. carbonyl

Explanation:

A C=O group is present, otherwise known as a carbonyl group

How do you think life on Earth would be different without the evolution of angiosperms? Provide two examples, each with an explanation.
PLSSS HURRRYYY!!!!!! WILL GIVE BRAINLIEST!!!

Answers

Answer:

Without angiosperms, average annual rainfall in the area declined by 300 millimeters. In the eastern Amazon basin, the length of the wet season decreased by nearly 3 months. The extent of the wettest rainforests, which receive more than 100 millimeters of rain per month, shrank by 80%.

A sample of water goes through a temperature change of -74.14 °C while releasing 578.7 joules of heat. The specific heat capacity of water is 4.184 J/(g·°C). What is the mass of this sample? grams (Report your answer using 4 significant figures).

Answers

Answer:

[tex] \boxed{ \sf \: m = 1.866 \: grams}[/tex]

Explanation:

Given:

Change in temperature ∆T= -74.14°C

Heat(Energy) released Q= 578.7 joules

Specific heat capacity s = 4.184 J/(g·°C)

To find:

Mass of the sample (m)=?

Solution:

[tex] \sf s= \frac{Q}{m \cdot \Delta T} \\ \sf \: Substituting \: the \: given \: parameters \\ \sf 4.184 = \frac{578.7}{m \times ( - 74.14)} \\ \sf m = \frac{578.7}{4.184 \times ( - 74.14)} \\ \sf m = \frac{578.7}{310.20176} \\ { \sf m = 1.8655 \approx1.866 \: grams}[/tex]

Since, we need the answer in 4 significant figures,

[tex] \boxed{ \sf \: m = 1.866 \: grams}[/tex]

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How many oxygen atom in 0.25 mol ca(No3)2

Answers

Answer: I believe its 1 but i'm not sure

Explanation:

Which of the following is not an example of an inexhaustible resource?
1.) Wind power
2.) Wave and tidal power
3.) Solar energy
4.) Biomass

Answers

Solar energy because solar take more resources then all the options that are on the question Answer is 3

Answer:

I would say 4.) Biomass

Explanation:

This looks like the best possible answer because it is plant based. Worst case scenario we could run out of plants. In comparison, wind will pretty much always be around along with wave/tidal power and solar.

How many electrons are in the n = 2 shell of a magnesium atom?

Answers

Answer:

eight

Explanation:

That means there are 12 electrons in a magnesium atom

hope this helps

If you have 2m of hydrochloric acid and also 2m of vinegar which one is weak and strong and why?​

Answers

strong because it’s strong and all that it gives with it

How many grams of a gas with a molar mass 36.02 g/mol would be required to occupy a 3979 mL flask at 1.07 atm and 81.7 degrees Celcius? Record your answer in scientific notation to 2 decimal spaces.

Answers

A 3979 mL flask is occupied by 5.26 g of a gas with a molar mass of 36.02 g/mol at 1.07 atm and 81.7 °C.

What is an ideal gas?

An ideal gas is that whose behavior can be explained using the ideal gas laws.

Step 1. Convert 81.7 °C to Kelvin.

We will use the following expression.

K = °C + 273.15 = 81.7 + 273.15 = 354.9 K

Step 2. Calculate the moles of the gas.

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.07 atm × 3.979 L / (0.08206 atm.L/mol.K) × 354.9 K = 0.146 mol

Step 3. Calculate the mass of the gas.

The molar mass of the gas is 36.02 g/mol.

0.146 mol × 36.02 g/mol = 5.26 g

A 3979 mL flask is occupied by 5.26 g of a gas with a molar mass of 36.02 g/mol at 1.07 atm and 81.7 °C.

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Which subshells (s, p, d, f, or g) can have electrons with the indicated magnetic quantum number (ml)?

Answers

Answer:

=3 means is 3 or greater so that would be f and g subshells

=0 means is 0 or greater so that would be s, p, d, f and g subshells

=1 means is 1 or greater so that would be p, d, f, and g subshells

=4 means is 4 or greater so that would be g only

Insoluble sulfide compounds are generally black in color. Which of the following combinations could yield a black precipitate? a) Na2S(aq) + KCl(aq) b) Li2S(aq) + Pb(N03)2(aq) c) Pb(C103)2(aq) + NaNO3(aq) d) AgNo3(aq) + KCl(aq) e) K2S(aq) + Sn(N03)4(aq)

Answers

Answer:

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

Explanation:

they are the only two of the options that contain a sulfide ion (S) therefore they are the only ones that could be considered in the question.

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

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