An online video streaming service offers two plans for unlimited streaming. Plan A has a one-time $25 membership fee and is $8 per month. Plan B has a $5 membership fee and is $12 per month. how many months till they cost the same amount?​

Answer:

D. turns

Step-by-step explanation:

Rotation is the process of turning around a center or an axis.

(Sorry if it's wrong. I hope I helped somewhat.)

Answer:

Answer is either 1 or 2

Step-by-step explanation:

Answer:

This is an acute angle since it measures less than 90 degrees.

Answer:

6

Step-by-step explanation:

Find the interquartile range (h-spread).

:)

Answer:

29 candy bars

Step-by-step explanation:

13 movie pases= $9.50x13= $123.50

3 gift cards= $25×3 =$75

amount of money she has left over to buy candy bars = $250- $75- $123.5 = $51.50

Amount of candy bars she can buy = $51.50÷$1.75 = 29.43 candy bars, but u can only buy full candy bars and there for 29 candy bars is the final answer

Answer:

2nd one

Step-by-step explanation:

if you were to look on a grid the slope would point up

Answer:

115: a) -4

120: a) 11

Step-by-step explanation:

115: Use the formula  

[tex]m = \frac{rise}{run} = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

= (-5)-(3) / (6) - (4)

= -8 / 2

= -4

120: Count the units between point B and point F

Answer:

13.72 cm²

Step-by-step explanation:

The formula to find the area of a shaded region: Area of the bigger shape - area of the smaller shape.

The formula to find the area of a square: [tex]a^{2}[/tex], where [tex]a[/tex] is the side.

The formula to find the area of a circle: [tex]\pi r^{2}[/tex], where [tex]\pi[/tex] is 3.14 or [tex]\frac{22}{7}[/tex] or 3.142 or similar, [tex]r[/tex] is the radius (diameter ÷ 2).

1) Find the area of the circle using the formula. The radius is 4 because the diameter is 8 (8 ÷ 2 = 4).

= [tex]\frac{22}{7}*4^{2}[/tex]

= [tex]\frac{22}{7}*16[/tex]

= 50.285

2) Find the area of the square using the formula.

= [tex]8^{2}[/tex]

= 64

3) Apply: area of the bigger shape - area of the smaller shape.

= 64 - 50.285

= 13.715

4) Round it off to the nearest hundredth.

= 13.72

Answer:

the number = -23 because there are different ways to do this don't bother

Answer:

Volume = 92.15

Step-by-step explanation:

V=πr2h/3=π·42·5.5/3≈92.15

Answer:

g= 60°

i= 70°

h= 50°

Step-by-step explanation:

g=180-120 = 60°

i= 180-110 = 70°

h=180-60-70 = 50°

hope this helps =)

Kindly rate and mark brainliest. Thank you.

Answer:

283

Step-by-step explanation:

[tex]15 \times 18 + 12 \div 3 + 9 \\ 270 + 4 + 9 \\ 283[/tex]

By using BODMAS rule

Before adding the 12 u have to divide 12 by 3 =4 then u will add 4

Answer:

Your wrong the correct answer is 283

Step-by-step explanation:

[tex]15 \times 18 + 12 \div 3 + 9 \\ = 270 + 4 + 9 \\ = 283 \\ [/tex]

{ The algorithm, multiplication and division comes first, then addition}

Answer:

10 rs

Step-by-step explanation:

Answer:

x = 24

Step-by-step explanation:

let x be the number we want to determine its value

The statement  x increased by ¼ of itself is equal to 30

is equivalent to :

[tex]x + \frac{x}{4}=30\\\\then[/tex]

[tex]\frac{4x+x}{4} = 30\\\\then[/tex]

[tex]\frac{5x}{4} = 30\\\\then[/tex]

5x = 4× 30

then

5x = 120

then

x = 120/5

then

x = 24

Answer:

Option B

Step-by-step explanation:

Given:

To determine the percentage of the production was out of spec, we need to use the percentage formula (x/y × 100).

[tex]\implies \dfrac{x}{y} \times 100[/tex]

The value of "x" is the the number of pieces that were out of spec and the value of "y" is the total pieces in the production results.

[tex]\implies \dfrac{130}{3500} \times 100[/tex]

Simplify the expression to determine the percentage of the pieces that were out of spec.

[tex]\implies \dfrac{13000}{3500}[/tex]

[tex]\implies \dfrac{130}{35} = \dfrac{130 \div 5}{35 \div 5} = \dfrac{26}{7} = 3.714... \%[/tex]

When the percentage is estimated to nearest hundredth, we get 3.71%

(Option B)

Answer:

B)  3.71%

Step-by-step explanation:

[tex]\textsf{130 out of 3500}\sf =\dfrac{130}{3500}[/tex]

To convert to a percentage, multiply by 100:

[tex]\implies \sf \dfrac{130}{3500} \times 100\%=0.03714.. \times 100\%=3.71\%[/tex]

Answer: 32

Step-by-step explanation:

We know that the original number of paper snowflakes was 36, plus 28 given by her brother. The new total would be 64 paper snowflakes and she only uses half of the paper snowflakes. The answer would be 32.

Answer:

Step-by-step explanation:

LCD (15,20) = 60

[tex]\frac{2}{15}[/tex] + [tex]\frac{1}{20}[/tex] = [tex]\frac{8}{60}[/tex] + [tex]\frac{3}{60}[/tex] = [tex]\frac{11}{60}[/tex]

Answer:

2/15 + 1/20 = 11/60

Step-by-step explanation:

1. Find the least common denominator or LCM of the two denominators:

15 and 20.

Steps to find LCM:

1. Find the prime factorization of 15

15 = 3 × 5

2. Find the prime factorization of 20

20 = 2 × 2 × 5

3. Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM:

LCM = 2 × 2 × 3 × 5

LCM = 60

2. Next, find the equivalent fraction of both fractional numbers with denominator 60.

For the 1st fraction, since 15 × 4 = 60,

2/15 = 2 * 4 / 15 * 4 = 8/60

Likewise, for the 2nd fraction, since 20 × 3 = 60,

1/20 = 1 * 3 / 20 × 3 = 3/60

Add the two like fractions:

8/60 + 3/60 = 8 + 3/60 = 11/60

Answer:

te paso mi canal subcribete y la respueta

Step-by-step explanation:

2.2315

mi canal es navegando con incognito subcribete

Answer: 5

Step-by-step explanation:

lower quartile: 4

upper quartile: 9

9-4=5

IQR=5

If u = ⟨-4, 8⟩ and v = ⟨5, -18⟩, then we have

2u - 4v = ⟨-8, 16⟩ + ⟨-20, 72⟩ = ⟨-28, 88⟩

To this vector, we want to add another vector w = ⟨a, b⟩ such that

2u - 4v + w = ⟨0, 1⟩

Solve for w :

w = ⟨0, 1⟩ - ⟨-28, 88⟩ = ⟨28, -87⟩ … … … [C]

Answer:

1. The use of a domain for a function that is smaller than the function's domain of definition. Note: Restricted domains are commonly used to specify a one-to-one section of a function.

2. Domain restrictions can be calculated by finding singularities, which are the x -values for which the denominator Q(x) is zero.

Answer:

by setting the denominator equal to zero and solving. The x -values at which the denominator equals zero are called singularities and are not in the domain of the function.

Step-by-step explanation:

Answer:

okay so the circumference is 40.82m

[tex]circumference = 2\pi \: \times r \\ = 2 \times 3.14 \times 6.5 \\ = 40.82m[/tex]

the diameter will be divided by 2 to give 6.5

Answer:

6pi miles

Step-by-step explanation:

Answer: 6pi

formula for perimeter: pi*diameter

diameter=radius*2

diameter=3*2=6

6*pi=6pi

Answer:

x= -5

Step-by-step explanation:

not right its -5

The statement that correctly descrives the likelilhood of an event based on the given numbered cube is: Option A: It is likely that a number less than 6 is occured.

Suppose that for a considered sample space, we consider an event E

Then, E is likely to occur if:

[tex]P(E) \geq P(E')[/tex]

where [tex]E_i '[/tex] is complementary event of E (ie, E'  occurs whenever E doesn't occur and vice versa)

If so, then we say that E is likely to occur as the outcome of the considered random experiment, else unlikely.

Since we have:

[tex]P(E) = 1- P(E')[/tex] due to E and E' being complement of each other, therefore, we get:

[tex]P(E) \geq 1 - P(E)\\P(E) \geq 0.5[/tex]

Thus, event E is said to be likely if its probability is greater or equal to 0.5, else not.

It is given that the cube is 6 faced (assuming all equally likely), numbered from 1 to 6.

Evaluating likelihood of each event:

P(Getting a number < 6 on that cube) = [tex]\dfrac{5}{6}[/tex] (since a number out of 6 numbers can occur in 6 ways, but it being < 6 can be done in 5 ways).

Thus, we have:

P(Getting a number < 6 on that cube) =5/6 > 0.5

So it is likely to get a number < 6 on the considered cube. So this statement correctly describes the likelihood of its considered event.

Ways to get a number on the considered cube = 6

Ways to get a number < 4 on the considered cube = 3

Thus, we get:

P(Getting a number < 4 on that cube) = 3/6 = 0.5

Thus, it is likely to get a number < 4 on that cube, so this option is wrong.

Yes it is certain, but we're considering only those options which correctly describe likelihood instead of certainity.

So, this option is not considerable.

Ways to get a number on the considered cube = 6

Ways to get a number > 1 on the considered cube = 5

Thus, we get:

P(Getting a number > 1 on that cube) = 5/6 > 0.5

Thus, it is likely to get a number > 1 on that cube, so this option is wrong.

Thus, the statement that correctly descrives the likelilhood of an event based on the given numbered cube is: Option A: It is likely that a number less than 6 is occured.

Learn more about likelihood of events here:

https://brainly.com/question/14954386

#SPJ1

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

[tex]\qquad \tt \dashrightarrow \:\dfrac{d}{dx} \left[ \sin^{-1}(\cos e^x)-\cos^{-1}(\sin e^x) \right][/tex]

[tex]\qquad \tt \dashrightarrow \:\dfrac{d}{dx} \sin^{-1}(\cos e^x) - \dfrac{d}{dx}\cos^{-1}(\sin e^x) [/tex]

[tex]\qquad \tt \dashrightarrow \: \bigg(\dfrac{1}{ \sqrt{1 - ( \cos( {e}^{x} ) ) {}^{2} } } \times - \sin( {e}^{x} ) \times {e}^{x} \bigg) - \bigg( - \dfrac{1}{ \sqrt{1 - ( \sin( {e}^{x} )) {}^{2} } } \times \cos( {e}^{x} ) \times {e}^{x} \bigg)[/tex]

[tex]\qquad \tt \dashrightarrow \: \bigg(\dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{1 - ( \cos( {e}^{x} ) ) {}^{2} } } \bigg) - \bigg( - \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{1 - ( \sin( {e}^{x} )) {}^{2} } } \bigg)[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{1 - \cos {}^{2} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{1 - \sin {}^{2} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{ { \sin}^{2} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{ \cos {}^{2} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ { { \sin}^{} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ { \cos {}^{} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: - {e}^{x} + {e}^{x} [/tex]

[tex]\qquad \tt \dashrightarrow \:0[/tex]

I hope this helps, if you find any problem with steps or got a mistake in my explanation then feel free to ask me ~