Answer:
its atmospheric pressure decreases
When the temperature of an air mass increases, its atmospheric pressure drops
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A box of mass 6.0 kg is accelerated from rest
across a floor at a rate of 6.0 m/s² for 9.0 s.
Find the network done on the box
[tex]\text{Given that },\\\text{Mass, m = 6 kg}\\\\\text{Acceleration, a = 6 } \text{m} \text{s}^{-2}\\\\\text{Time, t=9 sec}\\\\\text{Displacement, }s=ut + \dfrac 12 at^2 = \dfrac 12 at^2 = \dfrac 12 \times 6 \times 9^2 = 243 ~m}\\\\\ \text{Work,} ~W = Fs = mas = 6 \times 6 \times 243 = 8748 ~ J}[/tex]
Hi there!
We know that:
[tex]W = \Delta KE = \frac{1}{2}m(\Delta v)^2[/tex]
We can begin by solving for the final velocity using the equation:
[tex]v_f = v_i + at[/tex]
The box starts from rest, so:
[tex]v_f = at\\\\v_f = 6(9) = 54 m/s[/tex]
Now, we can find the kinetic energy:
[tex]KE = \frac{1}{2}mv^2\\\\KE = \frac{1}{2}(6)(54^2) = 8748 J[/tex]
Thus:
[tex]W = \Delta KE\\\boxed{W = 8748 J}[/tex]
if you exert a force on an object, but the object remains stationary as you apply the force, then how much work have you done on the object?
Answer:
no work done
Explanation:
unless you moved the object
When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.
What is Work done?Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:
Work done= Force* Displacement
When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.
Suppose that displacement is zero then,
W=f×0
Work done is zero
Thus, the work done is zero.
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How is a controlled variable different from a responding variable? O A. A controlled variable changes due to changes in the responding variable during the experiment. B. A controlled variable stays the same throughout an experiment, but a responding variable changes, C. A controlled variable changes throughout an experiment, but a responding variable stays the same. O D. A controlled variable stays the same due to changes in the responding variable during the experient.
Answer:The controlled variable is the one that you keep constant. The responding variable or variables is what happens as a result of the experiment
Explanation:Mark me brainly please
Which of these is a unique use of beta particles?
A. CT scanners
B. Tracing chemicals in the environment C. Killing bacteria
D. Smoke detectors
Answer:
The answer is A, CT scanners.
2. Summarize how to use a spring scale to measure a pull and how to use it to apply a push with
a specific force.
If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.
According to Hook's law, the force applied to an elastic material is directly proportional to the extension of the material.
The force applied;
F = kx
where;
k is the springThe applied force can be in form of push or pull. A push force can result in compression of the spring while a pull force can result in extension of the spring.
If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.
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The total power input to the leaf blower is 750 W. The useful power outlet of the leaf blower is 360 W. Calculate the efficiency of the leaf blower.
H = Pu / P x 100% = 360/750 x 100% = 48%
P/s: Pu is the useful power outlet of the leaf blower
P is the total power input to the leaf blower
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As the skydiver's ______increases, so does the magnitude of the force due to friction.
Answer:
speed?
Explanation:
give me more information
22.13 .. Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length 5.20 mC>m. What magnitude of force does one line of charge exert o
Answer:
Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length.
Explanation:
Which statement about a HORIZONTAL projectile is false?
The horizontal velocity is constant.
The horizontal acceleration is constant.
The vertical velocity is constant.
The vertical acceleration is constant.
Answer:
the vertical velocity is constant.
Explanation:
The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; thus, the vertical velocity of a projectile changes. and the horizontal motion of a projectile is independent of its vertical motion.
[tex] \huge \mathcal{Question}[/tex]
Can someone Help me with this question ?
(I need proper Explanation if possible)
Thanks for Answering ~
Answer:
c. Force applied is 75 N
EDITED
tan 37 = a/g
a = 3g/4
a in equation
t× 3/5 = 2 × 3g/4
t = 5× 10/2
t = 25n
f = ma
f = ( mt + mb )a
F = 10 × 3× 10/4
F = 75 n
• Correct option is (C).
We know that the angle made by string is θ=
[tex]tan {}^{ - 1} ( \frac{a}{g} )[/tex]
where a is the acceleration of the frame in which the string is hanging in our case it is a trolley.
[tex]putting \: θ=37° \: or \: tan \: 37° = \frac{3}{4} [/tex]
[tex]we \: get \: a \: \frac{3g}{4} = \frac{30}{4} = 7.5 \: m/s^2[/tex]
[tex] \boxed{Force \: F=total \: mass \: of \: the \: system \: on \: which \: force \: is \: acting ×acceleration \: of \: the \: system=(8+2)×7.5=75 }[/tex]
[tex] \boxed{ so \: force \: is \: 75 \:N. }[/tex]
Use the graph of velocity versus time for an object to answer the question.
Which statement fairly compares segment 2 and segment 3?
(1 point)
O These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
These represent different periods of time, but the force acting on the object is the same during each period of time.
O These represent different periods of time, and the force during segment 2 is different than the force during segment 3.
O These represent equal periods of time, and the force acting on the object is the same during each period of time.
The statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
Since segment 2 starts at t = 60 s and ends at t = 150 s, the time interval is Δt = 150 - 60 = 90 s.
Also, segment 3 starts at t = 150 s and ends at t = 240 s, the time interval is Δt = 240 - 150 = 90 s.
So, their time periods are the equal.
We notice that segment 2 is less steep than segment 3 this implies that the acceleration in each segment is different, since the acceleration is the slope of the graph.
Since force is determined by acceleration, this implies that the force on segment 2 is different form the force acting in segment 3.
So, we have equal time periods but different forces.
So, the statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
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Answer:
Segments 2 and 3 have equal periods of time but the force during segment 2 is different than the force during segment 3 !! :)
Explanation:
Please help!
What is momentum?
Answer:
a property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity
Explanation:
Formula:
Momentum: Mass x Velocity
Hope it helps!
What would the kinetic energy of a 20kg person running at a velocity of 2.5m/s?
Answer:
62.5 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity in m/s
From the question
m = 20 kg
v = 2.5 m/s
From the question we have
[tex]k = \frac{1}{2} \times 20 \times {2.5}^{2} \\ = 10 \times 6.25 \\ = 62.5\: \: \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
62.5 JHope this helps you
a comet or asteroid impact on the earth is a frequently suggested cause for many of the mass extinctions. for which of the major mass extinctions does the most evidence exist that this was the main trigger for the event?
Answer:
Cretacious-Tertiary
Explanation:
I hope this helps!
how to add ratio numbers can someone give me an exzample
Answer:
When the denominator of both ratios is the same, adding the ratio is simple. You just add the numbers to the left of the colon (this number is called the Ratio Numerator)xplanation:
Which of the followng is Newton's Second Law?
a. An object in motion will stay in motion unless acted upon by an unbalanced outside force
b .Force = mass times acceleration
c.When one object puts a force on the another object, the second object puts a force back on the first, equal in magnitude and opposite in direction
Answer:
A
Explanation:
What is the weight, on Earth, of a book with a mass of 1. 5 kg? 1. 5 N 6. 5 N 11. 3 N 14. 7 N.
Answer:
The weight, on Earth, of a book with a mass of 1.5kg is 14.7N.
Explanation:
Hi there!
Weight of an object = mass (kg) × acceleration due to gravity (N/kg)
Plug in the given values using the g constant g = 9.8 N/kg:
W = 1.5 × 9.8 = 14.7 N
251mL=25100L
True or false and why or why not?
Answer:
False
Explanation:
To find how many liters 251mL is you would need to divide 251 by 100 which is 0.251.
The mass of the hammer is 0.454 kg. Calculate the weight of the hammer.
Explanation:
weight =0.454 × 9.8=4.4492N
Answer:
4.45 n sorry if I am wrong
a force acting on 25kg mass produces an acceleration of 4m/square what would this the same force produce on a 12kg mass
Answer:8.3m/s
Explanation:
from F=ma, f=25*4=100N. since the force is 100, 100=12a. acceleration= 8.3m/s
Copper is a type of metal.
A block of copper has a mass of 2.0kg.
The block of copper absorbs 12000J of thermal energy.
The specific heat capacity of copper is 385J /(kg°C).
What is the temperature rise of the copper?
A 15.6°C B 31.2°C C 46.8°C D 62.4°C
The temperature rise in the copper is. I think its 0.393
The temperature rise in the copper is. I think its 0.393. Copper is a chemical element with the symbol Cu (from Latin: cuprum) and atomic number 29.
What is Capacity of copper?The chemical element copper (Cu) is a reddish, incredibly ductile metal belonging to Periodic Group 11 (Ib) that has an exceptional ability to conduct heat and electricity.
In nature, copper can be found in its free metallic state. Neolithic (New Stone Age) humans originally utilised this local copper (about 8000 BCE) as a substitute for stone.
Around 4000 BCE, Mesopotamia saw the beginning of metallurgy as copper was cast into molds, reduced to metal from ores with fire and charcoal, and purposefully alloyed with tin to form bronze (c. 3500 BCE).
Therefore, The temperature rise in the copper is. I think its 0.393. Copper is a chemical element with the symbol Cu (from Latin: cuprum) and atomic number 29.
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UV light has ______ wavelengths than visible light waves, and its peak energy is at a wavelength of ______.
Explanation:
Shorter wavelength since UV light has more energy than visible light
365 nm - What is the peak energy wavelength of UV light? It allows both infrared daylight and ultraviolet night-time communications by being transparent between 320 nm and 400 nm and also the longer infrared and just-barely-visible red wavelengths. Its maximum UV transmission is at 365 nm
A large solar farm has 21 700 solar panels and generates 5.0 MW of power.
1.0 MW = 1.0 × 106 W
Calculate the average power each panel produces.
Answer:
answer is
Explanation:
average power each panel produces = 21700/ 5×10^6
4340 ×10^-6
that's mean 4340 micro Watt
The table shows the diameters of the planets in our solar system. Assume that a basketball whose diameter is 25
centimeters represents the planet Jupiter. Find the scale (ratio) between Jupiter and the basketball. Then use this ratio to
find the scaled diameter of the other planets. Enter these numbers into the table. (Saturn has been done for you.) Finally,
choose a real-world spherical or nearly spherical object that matches the scaled diameter of each planet.
Saturn is shown as an example. To find what Saturn's size would be after adjusting it to scale, follow these steps. Let the
scaled diameter of Saturn be d centimeters. If Jupiter's diameter, 142,984 kilometers, is scaled to 25 centimeters, Saturn's
diameter of 120,536 kilometers will be scaled to about 21 centimeters:
120,536
d
120,536x25
142,984
d ~ 21 cm
Use this process to complete the table.
142,984
25
Answer:
Mercury:
.85
pea
Venus:
2.1
gumball
Earth:
2.2
gumball
Mars:
1.2
marble
Uranus:
9
grapefruit
Neptune:
8.6
softball
Explanation:
I have no clue if I'm right but hopefully, I am
Please Help
A car travels on a straight road with velocity components of 20 m/s west and 70 m/s south. What is the total distance the car travels in 50 s?
What does the state of matter of an object depend on?
type of molecules
size of molecules
speed of molecules
number of molecules
please help me thank you
Answer:
Refer to the attachment
What energy is used or given off by a fire?
Answer:
Heat is given off by Fire.
Explanation:
explique ¿por que un objeto que tiene energía es capaz de realizar un trabajo?
What is a lever?....
Answer:
A lever is a simple machine in the subject "S.T.E.M"
Explanation:
Levers use the following forces in order to be used: push or pull.
examples are crow bars,shovels, brooms and ect.