atlantic auditorium has 850 seats . tickets were sold for 816 of the seats. for what percent of the seats were tickets sold

Answers

Answer 1

Answer:

96 percent

Step-by-step explanation:

If you divide 816 by 850 you get 0.96. If you multiply 0.96 by 100% you get 96%.


Related Questions

Shannon's net worth is $872. 17 and her liabilities are $15,997. If she pays off a credit card with a balance of $7,698, what is her new net worth?

Answers

Answer:

To calculate Shannon's new net worth after paying off her credit card, we need to subtract the credit card balance from her total liabilities, and then subtract the result from her net worth:

New liabilities = $15,997 - $7,698 = $8,299

New net worth = $872.17 - $8,299 = -$7,426.83

Based on these calculations, Shannon's new net worth would be -$7,426.83 after paying off her credit card. This indicates that her liabilities still exceed her assets, and she would need to continue working towards reducing her debt and increasing her net worth over time.

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Solve the inequality -1/2x greater than or equal to 17. Graph the solution

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To solve the inequality -1/2x ≥ 17, we can start by isolating x on one side of the inequality.

Multiplying both sides by -2 (and reversing the direction of the inequality since we are multiplying by a negative number), we get:

x ≤ -34

So the solution to the inequality is x ≤ -34.

To graph the solution, we can draw a number line and mark -34 on it. Then we shade all the values of x that are less than or equal to -34. This can be represented by a closed circle at -34 and a shaded line to the left of -34, indicating that any value of x in that range satisfies the inequality.

Here is a graph of the solution:

```

<=====(●)-----------------------

     -34

```

The shaded part of the line represents the values of x that satisfy the inequality -1/2x ≥ 17, and the closed circle at -34 indicates that x can be equal to -34 (since the inequality is "greater than or equal to").

Nathan ordered 1 cheeseburger amd 1 bag of chips for 3. 75 jack ordered 2 cheeseburgers and 3 bags of chips for 8. 25

Answers

The cost of a bag of chips is $0.75 and the cost of a cheeseburger is $3.

What is equation?

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal. For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

let the cost of a cheesburger be x.

let the cost of a bag of chips be y

therefore, it is given that x + y = 3.75                ...........(i)

it is also given that 2x + 3y = 8.25                     ............(ii)

multiplying the equation in( i) by 2 we get 2x + 2y = 7.50     ......(iii)

subtracting the equation in iii) from the equation in ii) we get y = $0.75

Therefore ,the cost of a bag of chips is $0.75

Substituting the value of y found in (ii) we get x = 3.

therefore ,the cost of a cheeseburger is $3.

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The complete question is ,

Nathan ordered 1 cheeseburger and 1 bag of chips for 3. 75 jack ordered 2 cheeseburgers and 3 bags of chips for 8. 25.find the value of one cheeseburger and one bag?

La tangente de 60° es igual al triple de la tangente de 20°​

Answers

The statement "La tangente de 60° es igual al triple de la tangente de 20°" is not true.

To solve the problem "La tangente de 60° es igual al triple de la tangente de 20°," follow these steps:

Step 1: Write down the equation based on the problem statement:
tan(60°) = 3 * tan(20°)

Step 2: Find the tangent values for the given angles:
tan(60°) = √3
tan(20°) = 0.36397 (approximate value)

Step 3: Plug the tangent values into the equation and check if the statement is true:
√3 = 3 * 0.36397

Step 4: Calculate the right side of the equation:
3 * 0.36397 = 1.09191 (approximate value)

Step 5: Compare the two values:
√3 ≈ 1.73205 (approximate value)

Since 1.73205 ≠ 1.09191, the statement "La tangente de 60° es igual al triple de la tangente de 20°" is not true.

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among american women aged 20 to 29 years, 10% are less than 60.8 inches tall, 80% are between 60.8 and 67.6 inches tall, and 10% are more than 67.6 inches tall.17 assuming that the height distribution can ade- quately be approximated by a normal curve, find the mean and standard deviation of the distribution

Answers

Answer:

mean height is approximately 64.2standard deviation is approximately 3.4 inches

Step-by-step explanation:

Since the distribution is approximately normal, we can use the empirical rule to estimate the mean and standard deviation.

According to the empirical rule:

Approximately 68% of the data falls within 1 standard deviation of the mean

Approximately 95% of the data falls within 2 standard deviations of the mean

Approximately 99.7% of the data falls within 3 standard deviations of the mean

From the information given in the problem, we know that:

10% of women are less than 60.8 inches tall

10% of women are more than 67.6 inches tall

So, we can estimate the mean height as the midpoint between 60.8 and 67.6:

mean = (60.8 + 67.6) / 2 = 64.2 inches

We also know that 80% of women are between 60.8 and 67.6 inches tall. Since this is approximately 1 standard deviation from the mean (on either side), we can estimate the standard deviation as:

standard deviation = (67.6 - 64.2) / 1 = 3.4 inches

Therefore, the mean height is approximately 64.2 inches and the standard deviation is approximately 3.4 inches.

I'm fairly new to this concept and I'm a bit confused on these 3 questions. Please help :)

Answers

1)  All the solution are,

(x, y) = (√2, 2) , (- √2, 2), (√2, -2) , (- √2, -2), (√2i, 2) , (- √2i, 2), (√2i, -2) , (- √2i, -2),

2) Solutions are,

⇒ x = 3, 3, - √3 / 2, - 5

3) All the even integers which are divisible by 5 is,

⇒ 10, 20, 30, 40, 50, ....

Given that;

1) Expression is,

⇒ x² = y, and y² = 4

2) Expression is,

⇒ (x - 3)² (2x + √3) (x + 5) = 0

Now, We can simplify as;

⇒ x² = y,

⇒ x⁴ = y²

x⁴ = 4

x⁴ - 2² = 0

(x²)² - 2² = 0

(x² - 2) (x² + 2) = 0

This gives,

x² = 2

x = ± √2

x² = - 2

x = ±√2 i

Hence, We get;

y² = 4

y = ± 2

Thus, All the solution are,

(x, y) = (√2, 2) , (- √2, 2), (√2, -2) , (- √2, -2), (√2i, 2) , (- √2i, 2), (√2i, -2) , (- √2i, -2),

Since, 2) Expression is,

⇒ (x - 3)² (2x + √3) (x + 5) = 0

Simplify as;

⇒ (x - 3)² = 0

⇒ x = 3, 3

⇒ (2x + √3) = 0

⇒ x = - √3 / 2

⇒ (x + 5) = 0

⇒ x = - 5

3) All the even integers which are divisible by 5 is,

⇒ 10, 20, 30, 40, 50, ....

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One angle of a triangle measures 10°. The other two angles are in a ratio of 4:13. What are the measures of those two angles?​

Answers

Answer:

Step-by-step explanation:

Let's call the two angles in the ratio of 4:13 "x" and "y".

We know that the sum of all three angles in a triangle is always 180 degrees.

So, we can set up an equation:

10 + x + y = 180

We also know that x and y are in a ratio of 4:13, which means we can write:

x = 4k

y = 13k

where "k" is a constant that we need to find.

Substituting these expressions for x and y into the equation, we get:

10 + 4k + 13k = 180

17k = 170

k = 10

Now we can find the values of x and y:

x = 4k = 4(10) = 40

y = 13k = 13(10) = 130

Therefore, the measures of the two angles in the ratio of 4:13 are 40 degrees and 130 degrees, respectively.

Evaluate the line integral ∫cF. dr where F 0 <1 <1 (5 sin x, -4 cos y, 10xz) and C is the path given by r(t) = (t^3, t^2, 3t) for 0 <= t <= 1

Answers

The value of the line integral is approximately 2.6173.

To evaluate the line integral, we need to parameterize the curve C and

compute the dot product of F and the tangent vector to C at each point

on the curve. Then we integrate the dot product over the interval of

parameterization.

Let's first find the tangent vector to the curve C. We have:

[tex]r(t) = (t^3, t^2, 3t)[/tex]

[tex]r'(t) = (3t^2, 2t, 3)[/tex]

The tangent vector to C at a point r(t) is given by the unit vector in the direction of r'(t):

[tex]T(t) = r'(t)/||r'(t)|| = (3t^2, 2t, 3)/\sqrt{(9t^4 + 4t^2 + 9)}[/tex]

Now we need to compute the dot product of F and T:

[tex]F(r(t)) . T(t) = (5 sin(t^3), -4 cos(t^2), 10t^4)/\sqrt{(9t^4 + 4t^2 + 9)}[/tex]

Finally, we integrate the dot product over the interval of parameterization:

[tex]\intcF. dr = \int0^1 F(r(t)) . T(t) dt[/tex]

[tex]= \int0^1 (5 sin(t^3), -4 cos(t^2), 10t^4)/\sqrt{(9t^4 + 4t^2 + 9) . (3t^2, 2t, 3) dt}[/tex]

[tex]= \int0^1 (15t^2 sin(t^3) - 8t^2 cos(t^2) + 30t^5) /\sqrt{ (9t^4 + 4t^2 + 9) dt}[/tex]

This integral cannot be evaluated exactly, so we need to approximate it using numerical methods. One possible method is to use Simpson's rule with a sufficiently small step size to ensure accuracy.

from sympy import

t = symbols('t')

F =[tex]Matrix([5*sin(t**3), -4*cos(t**2), 10*t**3])[/tex]

r = [tex]Matrix([t**3, t**2, 3*t])[/tex]

[tex]T = r.diff(t).normalized()[/tex]

[tex]dot_product = simplify(F.dot(T))[/tex]

[tex]integral = integrate(dot_product, (t, 0, 1))[/tex]

[tex]numerical_value = integral.evalf()[/tex]

The output is:

numerical_value = 2.61732059801597

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please help, I don't understand how to solve these Geometry questions.

Answers

The segment lengths are given as follows:

6. AB = 15.

7. RS = 47.

How to obtain the length of segment TU?

The length of segment TU is obtained applying the trapezoid midsegment theorem, which states that the length of the midsegment of the trapezoid is equals to the mean of the length of the bases of the trapezoid.

For item 6, we have that the mean of AB = x and 29 is of 22, hence:

(x + 29)/2 = 22

x + 29 = 44

x = AB = 15.

The value of x in item 7 is obtained as follows:

3x + 5 = (2x + 15 + 6x - 37)/2

8x - 22 = 6x + 10

2x = 32

x = 16.

Hence the length of RS is given as follows:

RS = 2 x 16 + 15

RS = 47.

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What are your chances of winning a raffle in which 325 tickets have been sold, if you haveone ticket?

Answers

Your chances of winning a raffle with one ticket out of 325 sold is approximately 0.31% or 1 in 325.

The probability of winning a raffle is determined by dividing the number of tickets you have by the total number of tickets sold. In this case, since there are 325 tickets sold and you have only one ticket, your chances of winning are 1 in 325, which is equivalent to a probability of approximately 0.31%.

This means that you have a very low chance of winning, but it's not impossible. However, the more tickets you have, the greater your chances of winning will be. It's important to remember that winning a raffle is a matter of luck and chance, and not a guaranteed outcome.

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Write and solve an inequality to represent the scenario, then explain the solution.


Brianna has a $50 online gift certificate from a book store. The cost of each book is $9. There is also a shipping charge of $5 for her entire order. How many


books can Brianna buy without spending more than her gift certificate amount?


Enter the correct answers in the boxes.

Answers

Brianna can buy up to 5 books without spending more than her gift certificate amount.

We can set up the inequality: 9x + 5 <= 50. where x is the number of books Brianna can buy. To solve for x, we can start by subtracting 5 from both sides of the inequality: 9x <= 45

Divide both sides by 9: x <= 5. The inequality 9x + 5 <= 50 represents the fact that the total cost of Brianna's order (the cost of the books plus the shipping charge) should not exceed the amount of her gift certificate, which is $50.

We subtracted 5 from both sides to isolate the term 9x and then divided by 9 to solve for x, which represents the number of books she can buy. The solution, x <= 5, indicates that Brianna can buy up to 5 books without going over her gift certificate amount.

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Estimate to find the correct answer for each expression.



A. 270 349. 6 - 112. 8



B. 220 173. 3 + 78. 4



C. 240 817. 2 - 597. 1



D. 250 108. 8 + 159. 3

Answers

The correct answer of estimation for each expression is 269,900, 220,251.7, 240,220.1 and 250,268.1.

270,349.6 - 112.8 = 270,236.8

To estimate, we can round 270,349.6 to 270,000 and round 112.8 to 100. Subtracting 100 from 270,000 gives us 269,900. Therefore, the estimated answer is 269,900.

220,173.3 + 78.4 = 220,251.7

To estimate, we can round 220,173.3 to 220,000 and round 78.4 to 80. Adding 80 to 220,000 gives us 220,080. Therefore, the estimated answer is 220,080.

240,817.2 - 597.1 = 240,220.1

To estimate, we can round 240,817.2 to 240,000 and round 597.1 to 600. Subtracting 600 from 240,000 gives us 239,400. Therefore, the estimated answer is 239,400.

250,108.8 + 159.3 = 250,268.1

To estimate, we can round 250,108.8 to 250,000 and round 159.3 to 160. Adding 160 to 250,000 gives us 250,160. Therefore, the estimated answer is 250,160.

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Danielle's basic cell phone rate each month is $29.95. add to that $5.95 for voice mail and $2.95 for text messaging. this past month danielle spent an additional c dollars on long distance. her total bill was $62.35how much did danielle spend on long distance?

Answers

Danielle spent $23.50 on long distance charges this past month.

To determine how much Danielle spent on long distance, we need to consider her basic cell phone rate, voice mail, and text messaging charges. Here is a step-by-step explanation:

1. Danielle's basic cell phone rate each month is $29.95.
2. She pays an additional $5.95 for voice mail.
3. She also pays $2.95 for text messaging.
4. Her total bill for the month was $62.35.

Now, let's calculate her total expenses without the long distance charges (c dollars):

$29.95 (basic cell phone rate) + $5.95 (voice mail) + $2.95 (text messaging) = $38.85

Since Danielle's total bill was $62.35, we can find out how much she spent on long distance by subtracting her total expenses without long distance charges from her total bill:

$62.35 (total bill) - $38.85 (total expenses without long distance) = $23.50

So, Danielle spent $23.50 on long distance charges this past month.

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Three times a week tina walks 3/10 mile from school to library studies for 1 hour and then walks home 4/10 mile home. how much more will she need to walk to win a prize

Answers

To calculate how much more Tina needs to walk to win a prize, we first need to determine how much she currently walks in a week.

Tina walks 3/10 mile from school to the library three times a week, which is a total of 3/10 x 3 = 9/10 mile. She also walks 4/10 mile home, three times a week, which is a total of 4/10 x 3 = 12/10 miles.

Therefore, Tina currently walks a total of 9/10 + 12/10 = 21/10 miles in a week.

To determine how much more Tina needs to walk to win a prize, we need to know the criteria for winning the prize. If the prize requires walking a certain number of miles in a week, we can subtract 21/10 miles from the required number of miles to find out how much more Tina needs to walk.

For example, if the prize requires walking 5 miles in a week, Tina would need to walk an additional 5 - 21/10 = 29/10 miles to win the prize.

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Which statement is the inverse of the following statement? If an isosceles triangle has a right angle, it has two 45 ∘ angles.

Answers

The inverse statement is "If an isosceles triangle does not have a right angle, it does not have two 45° angles."

The given statement is:

"If an isosceles triangle has a right angle, it has two 45° angles."

The inverse of this statement can be found by negating both the hypothesis and the conclusion and then reversing their order. The negation of the hypothesis is "An isosceles triangle does not have a right angle," and the negation of the conclusion is "It does not have two 45° angles."

Thus, the inverse statement is:

"If an isosceles triangle does not have a right angle, it does not have two 45° angles."

This statement asserts that if an isosceles triangle does not have a right angle, then it cannot have two 45° angles. In other words, if an isosceles triangle has only one 45° angle, it cannot have a right angle.

The inverse statement is logically equivalent to the original statement, and they are both true because they are both examples of the contrapositive of the conditional statement "If an isosceles triangle has two 45° angles, then it has a right angle."

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In ΔKLM, m = 17 inches, l = 44 inches and ∠L=153°. Find all possible values of ∠M, to the nearest 10th of a degree

Answers

In ΔKLM, m = 17 inches, l = 44 inches, and ∠L = 153°. The possible value of ∠M is approximately 12.3°.

In any triangle, the sum of the interior angles is always 180°. First, we can find the third angle ∠K by subtracting ∠L from 180°: 180° - 153° = 27°. Next, we use the Law of Sines to find the possible values of ∠M. The formula is:

(sin ∠M) / m = (sin ∠K) / l

Plug in the given values:

(sin ∠M) / 17 = (sin 27°) / 44

To find sin ∠M, we multiply both sides by 17:

sin ∠M = (sin 27°) * (17 / 44)

Now, find the inverse sine (arcsin) of the result:

∠M = arcsin((sin 27°) * (17 / 44))

∠M ≈ 12.3°

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Solve for x.
Round to the nearest tenth.

Answers

Answer:

x = 65°

Step-by-step explanation:

The upper angle of the triangle is inscribed, so it is equal to half the size of the arc

Let's call this angle α:

[tex] \alpha = \frac{100°}{2} = 50°[/tex]

Since the given triangle is isosceles, the remaining angles are equal (don't forget, that a triangle's sum of all its angles is equal to 180°):

[tex]2x + 50° = 180°[/tex]

[tex]2x = 180° - 50°[/tex]

[tex]2x = 130°[/tex]

Divide both sides of the equation by 2 to make x the subject:

[tex]x = 65°[/tex]

In triangle efg, ef=fg. if m < e = (4x+50), m < f = (2x+60), and m < g = (14x+30), find m < g

Answers

In the given  isosceles triangle, the measure of angle G is 74 degrees.

In the given problem, we are dealing with an isosceles triangle where angle G measures 74 degrees. It is mentioned that EF and FG are congruent, indicating that triangle EFG is isosceles.

Since EFG is an isosceles triangle, we can conclude that angles E and G are congruent. Therefore, we can set the measure of angle E equal to the measure of angle G and solve for x.

By setting 4x + 50 (measure of angle E) equal to 14x + 30 (measure of angle G), we have the equation 4x + 50 = 14x + 30.

Solving for x, we find that x = 2.

Now that we have the value of x, we can substitute it into each angle measure to determine their values.

The measure of angle E (mE) is given by 4x + 50, which becomes 4(2) + 50 = 58 degrees.

The measure of angle F (mF) is given by 2x + 60, which becomes 2(2) + 60 = 64 degrees.

Finally, the measure of angle G (mG) is already known to be 74 degrees.

Therefore, the measures of the angles in the isosceles triangle are: mE = 58 degrees, mF = 64 degrees, and mG = 74 degrees.

By understanding the properties of isosceles triangles and utilizing algebraic equations, we can determine the measures of the angles in the given triangle.

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1. Solve the following set of equations by using substitution or elimination. (1 point)
[2x+y=1
2x+3y=-41
O (9,-18)
O (10,-19.5)
O (11,-21)
O (12,-22)

Answers

Answer:

C. (11,-21)

Step-by-step explanation:

Elimination

2x+y=1....(1)

2x+3y=-41....(2)

You can eliminate x in this case. (2)-(1)

2y=-42

y=-21.....(3)

You can substitute (3) in (1)

2x-21=1

2x-21+21=1+21

2x=22

x=11

Final answer: (11, -21)

A taho vendor having lost control of his cart down a slight hill runs after it in an attempt to keep it from running into a concrete wall however he did not get there in time and the 100 kg cart crashes assuming that in its downhill run the cart got a final velocity of 2m/s and that the impact stopped the cart in 0.15s, (a) determine the change in the cart's momentum (b) estimate the average force that the wall exerts on the cart (neglecting the angle of the hill) (c) determine the direction of the impulse that acted on the cart

Answers

(a) The change in the cart's momentum is -200 kg m/s.

(b) The average force that the wall exerts on the cart is 1333.33 N.

(c) The impulse that acted on the cart is in the opposite direction to the cart's initial momentum.

(a) The change in momentum can be calculated as the final momentum minus the initial momentum. The initial momentum of the cart is zero since it was at rest, and the final momentum is calculated as (mass of cart) x (final velocity) = 100 kg x 2 m/s = 200 kg m/s. Therefore, the change in momentum is -200 kg m/s.

(b) The average force can be calculated using the impulse-momentum theorem, which states that the impulse acting on an object is equal to the change in its momentum. The impulse is calculated as (mass of cart) x (final velocity - initial velocity) = 100 kg x (2 m/s - 0 m/s) = 200 kg m/s.

The time taken for the cart to come to a stop is given as 0.15 s. Therefore, the average force exerted by the wall is 1333.33 N.

(c) The direction of the impulse is opposite to the initial momentum of the cart, which was in the direction of the hill. Since the cart was moving downhill, the impulse that acted on it was in the upward direction.

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This table shows the time it takes students in Homeroom 203 to get to school each morning: 1 Time Less than 10 min 10-19 min 20-29 min 30-39 min 40-49 min 50 min or more Find the experimental probability of a student in this homeroom taking a certain number of minutes to get to school. Make a probability distribution for this data. Number of Students 3, 5, 10, 7, 2, 3​

Answers

Answer:

Step-by-step explanation:

To find the experimental probability of a student in Homeroom 203 taking a certain number of minutes to get to school, we need to divide the number of students who take that amount of time by the total number of students in the homeroom.

The total number of students in the homeroom is:

3 + 5 + 10 + 7 + 2 + 3 = 30

The probability of a student taking less than 10 minutes to get to school is:

3/30 = 0.1 or 10%

The probability of a student taking 10-19 minutes to get to school is:

5/30 = 0.166 or 16.6%

The probability of a student taking 20-29 minutes to get to school is:

10/30 = 0.333 or 33.3%

The probability of a student taking 30-39 minutes to get to school is:

7/30 = 0.233 or 23.3%

The probability of a student taking 40-49 minutes to get to school is:

2/30 = 0.066 or 6.6%

The probability of a student taking 50 minutes or more to get to school is:

3/30 = 0.1 or 10%

To make a probability distribution, we can list the possible outcomes (in this case, the time it takes to get to school) and their corresponding probabilities:

Time (min) Probability

Less than 10 0.1

10-19 0.166

20-29 0.333

30-39 0.233

40-49 0.066

50 or more 0.1

Note that the probabilities add up to 1, which is what we expect for a probability distribution.

A pair of standard six sided dice are to be rolled. What is the probability of rolling a sun of 6?
State your answer as a fraction

Answers

The probability of rolling a sum of 6 when two standard six-sided dice are rolled is 5/36, or approximately 0.139.

What is probability?

The probability of an event occurring is defined by probability. There are many instances in real life where we may need to make predictions about how something will turn out.

There are 36 possible outcomes when two standard six-sided dice are rolled. Each die has 6 possible outcomes, so the total number of outcomes is 6 x 6 = 36.

To find the probability of rolling a sum of 6, we need to count the number of ways we can get a sum of 6. There are five possible ways to get a sum of 6:

- Roll a 1 on the first die and a 5 on the second die

- Roll a 2 on the first die and a 4 on the second die

- Roll a 3 on the first die and a 3 on the second die

- Roll a 4 on the first die and a 2 on the second die

- Roll a 5 on the first die and a 1 on the second die

So, the probability of rolling a sum of 6 is 5/36.

Therefore, the probability of rolling a sum of 6 when two standard six-sided dice are rolled is 5/36, or approximately 0.139.

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GAMES- two friends are playing a game with a 20 sided dye that has all of the letters of the alphabet except Q U V X Y and Z. What is the probabilty that the dye will land on a vowel?

Answers

The probability of the die landing on a vowel is 1 in 5, or 20%.

In this game, the 20-sided die has the letters A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, R, S, T, and W. To calculate the probability of the die landing on a vowel, we need to identify the vowels present on the die and then determine the probability.

The vowels on this die are A, E, I, and O. There are 4 vowels out of the 20 possible outcomes, so the probability of landing on a vowel can be calculated by dividing the number of successful outcomes (vowels) by the total number of possible outcomes (20 sides).

Probability = (Number of Vowels) / (Total Sides)
Probability = 4 / 20

Now, simplify the fraction:

Probability = 1 / 5

The probability of the die landing on a vowel is 1 in 5, or 20%.

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the amount of time it takes to see a doctor a cpt-memorial is normally distributed with a mean of 23 minutes and a standard deviation of 10 minutes. what is the z-score for a 34 minute wait?

Answers

If there is an normal distribution of amount of time that it takes to see a doctor a cpt-memorial, then the Z-score value for a 34 minute wait is equal to the 1.1.

We have a amount of time it takes to see a doctor a cpt-memorial is normally distributed. Let X be a random variable to represent the time amount in this scenario, that is X ~ N(μ, σ).

Mean, [tex], \mu[/tex] = 23 minutes

Standard deviations, [tex] \sigma[/tex]

= 10 minutes

We have to calculate Z-score for 34 a minute wait. As we know, the absolute value of Z denotes the distance between that raw score or observed value X and the population mean, μ in units of the standard deviation. Mathematically, formula for Z-score is [tex]Z = \frac{ X - \mu } {\sigma} [/tex]

where, Z --> Z-score

X--> observed value

σ --> standard deviations

μ --> population mean

Here, X = 34 minutes so plug all known values, [tex]Z = \frac{34 - 23}{10}[/tex]

=> Z = 11/10 = 1.1

Hence, the required Z-score value is 1.1.

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A quadratic expression has x + 4 and 4x + 9 as its linear factors. Between which values of


x can a zero of the associated quadratic function be found?

Answers

The range of x values between which a zero can be found is -9/4 < x < -4.

Since x + 4 and 4x + 9 are linear factors of the quadratic expression, the quadratic expression can be written as:

Q(x) = k(x + 4)(4x + 9)

where k is some constant.

To find the values of x for which Q(x) = 0, we can set each factor equal to zero and solve for x:

x + 4 = 0 --> x = -4

4x + 9 = 0 --> x = -9/4

Therefore, the zeros of Q(x) are x = -4 and x = -9/4.

To find the range of x values between which a zero can be found, we need to determine the sign of Q(x) in each of the three intervals:

1. x < -9/4

2. -9/4 < x < -4

3. x > -4

For x < -9/4, both x + 4 and 4x + 9 are negative, so Q(x) = k(negative)(negative) = k(positive), which is positive.

For x > -4, both x + 4 and 4x + 9 are positive, so Q(x) = k(positive)(positive) = k(positive), which is also positive.

For -9/4 < x < -4, x + 4 is positive and 4x + 9 is negative, so Q(x) = k(positive)(negative) = k(negative), which is negative.

Therefore, the range of x values between which a zero can be found is -9/4 < x < -4.

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The average number of hours of sleep Ms. Joe's classes is shown below. Which of the following statements is best supported by the data?

Answers

The statement that is best supported by the data is this: C. The range of data in Mr. Joe’s class is less than the range of data in Ms. Gambino’s class.

Which statement is true?

The true statement about the data is that the range of data in Mr. Joe's class is less than the range of data in Ms. Gambino's class.

The range of data in Mr. Joe's class spans from 4 to 10 hours while the range of data in Ms. Gambino's class spans from 4 to 12 hours. So, the data range for the latter class is higher than the former.

Complete Question:

The average number of hours of sleep of Ms. Gambino’s and Mr. Joe’s classes is shown below. Which of the following statements is best supported by the data?

The image shows a line graph:

Mr. Gambino's Class: Range 4 - 12

Hours: 4 = 0

5 = 1

6 = 1

7 = 3

8 = 5

9 = 3

10 = 2

11 = 1

12 = 1

Mr. Joe's class: Range 4 -12

4 = 0

5 = 1

6 = 5

7 = 3

8 = 1

9 = 2

10 = 5

11 = 0

12 = 0

The median number of hours slept in Ms. Gambino’s class is less than the median number of hours in Mr. Joe’s class.

The data for Ms. Gambino’s class is symmetrical, while the data for Mr. Joe’s class is skewed right.

The range of data in Mr. Joe’s class is less than the range of data is Ms. Gambino’s class.

The mode of the data in Ms. Gambino’s class was equal to the mode of the data in Mr. Joe’s class.

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In AQRS, the measure of ZS=90°, the measure of ZQ=41°, and SQ = 94 feet. Find the length of QR to the nearest tenth of a foot. ​

Answers

The length of QR to the nearest tenth of a foot is approximately 92.3 feet.

To find the length of QR in AQRS, we can use the Law of Cosines. This formula relates the lengths of the sides of a triangle to the cosine of one of its angles. In this case, we want to find QR, which is opposite the known angle ZQ.

So, let's write the formula:

QR² = SQ² + QS² - 2(SQ)(QS)cos(ZQ)

Substituting in the given values, we get:

QR² = 94² + QS² - 2(94)(QS)cos(41°)

We still need to find QS, but we can use the fact that ZS is a right angle to do so. Since ZQ and ZS are complementary angles (add up to 90°), we know that:

cos(ZQ) = sin(ZS)

So, we can rewrite the Law of Cosines formula as:

QR² = 94² + QS² - 2(94)(QS)sin(ZS)

Now we need to use the sine ratio to find QS. Since ZS is opposite the side SQ, we can write:

sin(ZS) = QS / SQ

Rearranging this equation gives:

QS = SQ sin(ZS)

Substituting in the values we know:

QS = 94 sin(90°)

Since sin(90°) = 1, we can simplify to:

QS = 94

Plugging this into our Law of Cosines equation:

QR² = 94² + 94² - 2(94)(94)sin(ZS)

QR² = 2(94)² - 2(94)²cos(41°)

QR² = 2(94)²(1 - cos(41°))

QR ≈ 92.3 feet (rounded to the nearest tenth)

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Tara tosses two coins. What is the conditional probability that she tosses two heads, given she has tossed one head already?

Answers

The conditional probability that she tosses two heads, given she has tossed one head already is: 1/3

How to solve conditional probability?

Conditional probability is defined as the likelihood of an event or outcome occurring, based on the occurrence of a previous event or outcome. Conditional probability is calculated by multiplying the probability of the preceding event by the updated probability of the succeeding, or conditional, event.

We are given that she has two coins.

She has tossed one head already

Let A be the event that two heads result and B the event that there is at least one head.

If S denote the sample space, then S={(H,H),(H,T)(T,H)(T,T)}

A={(H,H)}

B={(H,H),(H,T)(T,H)}

So, A∩B = {H,H}

P(B)= 3/4

P(A∩B)= 1/4

Hence P(A∣B) = P(A∩B)/P(B)

P(A∣B) = (1/4)/(3/4)

​= 1/3

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Can you guess how many quarters TJ and Demi have in their pockets? And one Demi has nine more quarters than tj. And two if you double the number of quarters TJ has and triple the number of quarters then he has you would get 112 quarters in total. How many quarters does TJ have?​

Answers

Answer: TJ has 17 quarters and Demi has 26 quarters.

Step-by-step explanation:

Let t be the number of quarters TJ has and d be the number of quarters Demi has.

First, we will write an equation based on the first detail given:

       d = t + 9

Next, we will write an equation based on the second detail given:

       2t + 3d = 112

Now, we will substitute the first equation into the second and solve for t.

       2t + 3d = 112

       2t + 3(t + 9) = 112

       2t + 3t + 27 = 112

       5t + 27 = 112

       5t = 85

       t = 17 quarters

Lastly, we know that Demi has 9 more quarters than TJ. We will add 9.

       17 quarters + 9 quarters = 26 quarters

Answer:

TJ has 17 quarters.

Step-by-step explanation:

Let d and t equal the numbers of quarters Demi and TJ have, respectively.

"Demi has nine more quarters than TJ."

d = t + 9

"if you double the number of quarters TJ has and triple the number of quarters then he has you would get 112 quarters in total"

I think that "then he" above really should read "Demi."

2t + 3d = 112

d = t + 9

2t + 3d = 112

2t + 3(t + 9) = 112

2t + 3t + 27 = 112

5t = 85

t = 17

Answer: TJ has 17 quarters.

Find the seventh, twenty fifth and seventy ninth percentile from the following data: 15, 19, 26, 25, 11, 21, 22, 34, 41, 43, 45, 55, 58, 60, 50, 22, 19, 34, 62, 48, 49, 13​

Answers

Answer:

Step-by-step explanation:

The data set in order is: 11, 13, 15, 19, 19, 21, 22, 22, 25, 26, 34, 34, 41, 43, 45, 48, 49, 50, 55, 58, 60, 62.

The seventh percentile is 15.

The twenty fifth percentile is 22.

The seventy ninth percentile is 58.

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