Based on the data in the graph, which of the following solutions most likely led to the decrease in the amount of waste sent to landfills from 1990 to 2015 ?
A) Increased composting of domestic waste
B) Increased composting of e-waste
C) Increased combustion of waste
D) Increased recycling of waste

Answer:

For me it's C.

Step-by-step explanation:

the third one if you would like me to explain tell me.

The solutions to the trigonometric equations [tex]2cos(x) - \sqrt{30} = 0[/tex] in the interval [tex][0, 2\pi)[/tex] are x ≈ [tex]0.5514 + 2n\pi[/tex], where n is an integer.

Given that the equation  [tex]2cos(x) - \sqrt{30} = 0[/tex] in the interval [tex][0, 2\pi)[/tex]

To find all the solutions to the equation  [tex]2cos(x) - \sqrt{30} = 0[/tex] in the interval [tex][0, 2\pi)[/tex] ,  solve for x by isolating the cosine term and then applying the inverse cosine function.

Here are the steps to solve the equation:

Add [tex]\sqrt{30}[/tex] to both sides:

[tex]2cos(x) = \sqrt{30}[/tex]

Divide both sides by 2:

[tex]cos(x) = \sqrt{30} / 2[/tex]

Find the inverse cosine ([tex]cos^{-1}[/tex]) of both sides:

[tex]x = cos^{-1}(\sqrt{30} / 2)[/tex]

To determine the values of x in the interval [tex][0, 2\pi)[/tex] that satisfy the equation.

Evaluate [tex]cos^{-1}(\sqrt{30} / 2)[/tex] to find its approximate value.

[tex]cos^{-1}(\sqrt{30} / 2) = 0.5514[/tex] radians

Since the cosine function has a periodicity of [tex]2\pi[/tex], we can find other solutions by adding multiples of [tex]2\pi[/tex] to the initial solution.

So, the solutions in the interval  [tex][0, 2\pi)[/tex] are:

x ≈ 0.5514 radians

x ≈ [tex]0.5514 + 2\pi[/tex]

x ≈ [tex]0.5514 + 4\pi[/tex]

...

To simplify, express the solutions as:

x ≈ [tex]0.5514 + 2n\pi[/tex]

where n is an integer.

Therefore, the solutions to the trigonometric equations [tex]2cos(x) - \sqrt{30} = 0[/tex] in the interval [tex][0, 2\pi)[/tex] are x ≈ [tex]0.5514 + 2n\pi[/tex], where n is an integer.

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Therefore, the amount of heat produced when 52.40 g of methane, CH4, burns in an excess of air is -39568.2 kJ

The amount of heat produced when 52.40 g of methane, CH4, burns in an excess of air can be calculated using the following equation:

[tex]Q = mcΔT[/tex]

Where Q is the amount of heat produced (in kJ), m is the mass of the methane (in g), and ΔT is the change in temperature (in K).

Using the equation, the amount of heat produced can be calculated as follows:

Q = [tex](52.40 g)(-753.15 K) = -39568.2 kJ[/tex]
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The probability of 4 defective cell phones in a sample of 25 can be found using the binomial probability formula and is equal to 0.0263.

Probability is a branch of mathematics that deals with calculating the likelihood of a given event occurring. In probability, we calculate the number of ways an event can happen and divide it by the total number of possible outcomes.

Probability ranges from 0 to 1, with 0 indicating no chance of occurrence and 1 indicating that the event will definitely occur.

If there are only two possible outcomes in a given event, the binomial probability formula is used to calculate the probability of the event happening.

The binomial probability formula is given by: P(X = x) = (nCx)px(1 - p)n - x

Where, P(X = x) is the probability of x successes in n trials

nCx is the number of ways x successes can occur in n trials

px is the probability of a single success in a given trial(1 - p)n - x is the probability of the remaining trials being failures.

The probability of 4 defective cell phones in a sample of 25 can be calculated using the binomial probability formula.

P(X = 4) = (25C4)(0.06)4(0.94)21 = 0.0263.

Therefore, the probability of 4 defective cell phones in a sample of 25 is 0.0263.

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The sum of the circumscribed angle m∠ECD and central angle m∠EAD for five different data sets are 90°, 90°,120°,150°,180°.

A central angle is an angle in a circle that has its vertex at the center of the circle. Its arms, which are the two rays that make up the angle, both pass through points on the circumference of the circle.

m∠ECD  m∠EAD  m∠ECD + m∠EAD

45°  45°    90°

60°  30°    90°

100°  20°    120°

140°  10°    150°

180°  0°    180°

The measure of the circumscribed angle, ∠ECD, is the angle formed by the intersection of two lines, AB and CD.

The measure of the central angle, ∠EAD, is the angle formed by the intersection of the lines AB and ED.

The relationship between the circumscribed angle and the central angle can be explored by moving point B to various different locations on the coordinate plane between A and C.

By doing so, both the circumscribed angle and the central angle can be measured.

From the table above, it can be seen that the sum of the measures of the circumscribed angle and the central angle is always equal to 90°.

This is because the circumscribed angle and the central angle are supplementary angles, meaning that the sum of their measures always equal to 180°.

In this case, since the sum of the measures of the circumscribed angle and the central angle is always equal to 90°, the measures of the circumscribed angle and the central angle themselves must always add up to 90°.

Since the sum of the measures of the circumscribed angle and the central angle is always equal to 90°, the measures of the circumscribed angle and the central angle themselves must always add up to 90°.

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the correct answer is: none of these, as only binomial distribution is applicable to this scenario.

a) This scenario follows the binomial distribution, as we are drawing marbles with replacement and interested in the number of successes (getting a blue marble) in a fixed number of trials.

b) The Poisson distribution is used to model the number of events occurring in a fixed time interval, given a certain rate of occurrence. It is not applicable in this scenario.

c) The hypergeometric distribution is used to model the probability of obtaining a certain number of successes in a sample without replacement, given a finite population of items that can be classified into successes and failures. In this scenario, we are drawing with replacement, so the hypergeometric distribution is not applicable.

d) Therefore, the correct answer is: none of these, as only binomial distribution is applicable to this scenario.

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The key features of both equations are:

Equation 1 has a vertex at (1, -16) and opens upwards. Its axis of symmetry is x = 1

Equation 2 has a vertex at (2, 2) and opens upwards. Its axis of symmetry is x = 2.

To rewrite each equation in vertex form, we need to complete the square by adding and subtracting a constant from each equation.

y = x² - 2x - 15

y = (x - 1)² - 16

The vertex form of the equation is y = a(x - h)² + k, where (h, k) is the vertex. In this case, the vertex is (1, -16).

y = 2x² - 8x + 6

y = 2(x - 2)² + 2

The vertex form of the equation is y = a(x - h)² + k, where (h, k) is the vertex. In this case, the vertex is (2, 2).

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Random sampling is used to ensure that the sample is representative of the population, while random assignment is used to control for extraneous variables and increase the internal validity of the study.

Random sampling and random assignment are two distinct procedures that are often used in research studies, and it's important to understand the difference between them.

Random sampling refers to the process of selecting individuals or units from a larger population in such a way that every member of the population has an equal chance of being included in the sample. Random sampling is used to ensure that the sample is representative of the population and that the results can be generalized to the larger population.

Random assignment, on the other hand, refers to the process of assigning participants to different experimental conditions in a way that is completely random. This means that every participant has an equal chance of being assigned to any condition. Random assignment is used to control for extraneous variables that could influence the results of the study. By randomly assigning participants to conditions, researchers can be more confident that any differences observed between the groups are due to the manipulation of the independent variable, rather than pre-existing differences between the participants.

In summary, random sampling is used to ensure that the sample is representative of the population, while random assignment is used to control for extraneous variables and increase the internal validity of the study.

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Ten chairs are arranged in a circle. The number of subsets of this set of chairs that contain at least three adjacent chairs is 310.

The given that 10 chairs arranged in a circle.

            Now we have to find the number of subsets of this set of chairs that contain at least three adjacent chairs.

           To solve this, we can use the concept of permutations and combinations. The first step is to consider the number of ways in which three chairs can be selected and arranged in a subset that is adjacent to each other.

           This can be done in 10 different ways, as there are 10 chairs in total and we can select any one of them as the starting point.

           The next step is to consider the number of ways in which we can add additional chairs to this subset. For example, we can add a fourth chair to the subset in two different ways: either to the left of the first chair or to the right of the third chair.

            Similarly, we can add a fifth chair to the subset in four different ways, a sixth chair in six different ways, and so on. Using this logic, we can create the following table:

                    Length of subset number of ways to select the subset number of ways to add chairs

           Total number of subsets31 (adjacent)

                                = 10  ---43 (adjacent) 10*2

                                =20---55 (adjacent)10*4

                                =40---67 (adjacent)10*6

                                =60---79 (adjacent)10*8

                               =80---810 (adjacent)10*10

                               =100---

              As we can see from the table, the total number of subsets that contain at least three adjacent chairs is given by:

           Total number of subsets = 10 + 20 + 40 + 60 + 80 + 100

                                                     = 310

       Therefore, the number of subsets of this set of chairs that contain at least three adjacent chairs is 310.

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The value of ∠FDE is 36°

An angle is a geometric figure formed by two rays, or lines that extend infinitely in opposite directions, that share a common endpoint called the vertex. The measure of an angle is determined by the amount of rotation between the two rays.

Here given a right angle ∠CDE = 90°

So, we can say that,

∠CDF + ∠FDE = ∠CDE

(2x)° + (x+9)° = 90°

(3x + 9)° = 90°

Simplify it, x = 27°

So, the value of ∠FDE = (x+9)° = (27+9)° = 36°

Therefore, the value of ∠FDE is 36°

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The angle FDE is 36°. The required answer for the given question is option (A). 36°.

Trigonometry angles are the angles provided by the trigonometric function ratios. Trigonometry is the study of the connection between angles and triangle sides. Angle values vary from 0 to 360 degrees.

An angle is a shape in geometry made by two rays or lines that stretch indefinitely in opposite directions and have a common endpoint known as the vertex. The quantity of rotation among the two rays determines the size of an angle.

From the given figure,

∠CDF + ∠FDE = 90

Thus,

(2x)+(x+9) = 90

3x + 9 = 90

3x = 81

x = 27

Then we will have that the angle FDE is:

∠FDE = (27) + 9

∠FDE = 36

The angle of FDE is 36°

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Therefore, the correct answer is: The range is the best measure of variability, and it equals 78.

Range is a measure of variability that represents the difference between the maximum and minimum values in a dataset. It gives an indication of how spread out the data is. To find the range of a dataset, you simply subtract the minimum value from the maximum value. Range is often used as a quick and simple measure of variability, but it can be sensitive to outliers and extreme values.

Here,

1. For question 5, the appropriate measure of variability for the given data set is the range, which is the difference between the maximum value and the minimum value in the data set.

To find the maximum and minimum values from the given stem-and-leaf plot, we can look at the highest and lowest digits in each row. The highest value is 83 and the lowest value is 5, so the range is:

Range = 83 - 5 = 78

2. For question 6, the appropriate measure of center to represent the data in the given line plot is the median, because the data is skewed to the right and there are outliers present. The median is less sensitive to outliers than the mean.

Therefore, the correct answer is: The median is the best measure of center because there are outliers present.

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In the following question, among the conditions given, the cop of a Carnot refrigerator, when t(cold) is 275 k and t(hot) is 158 c. Then the COP of the Carnot refrigerator is 1.76 (written as a fraction "88/50").

The COP of a Carnot refrigerator is calculated as: COP = T(Cold) / (T(Hot) - T(Cold))The COP of a Carnot refrigerator is given by the formula:

COP = T(Cold) / (T(Hot) - T(Cold))Where T(Cold) is the temperature of the cold reservoir and T(Hot) is the temperature of the hot reservoir.

T(Cold) = 275 K and T(Hot) = 158 °C = 431 K By substituting these values into the formula: COP = 275 / (431 - 275)COP = 275 / 156COP = 1.76 The COP of the Carnot refrigerator is 1.76 (written as a fraction 88/50).

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The exponentially smoothed forecast for period 4 is 106.6.

As per given information,

Time period Actual series  Forecast series  Forecast error  1  100  100 0 2 110 3 115

Smoothing constant α=0.3

For calculating exponentially smoothed forecast for period 4,

First, we need to calculate exponentially smoothed forecast for period 2.

Smoothed forecast for period 2 = α (Actual demand for period 1) + (1-α) (Smoothed forecast for period 1)

= 0.3 (100) + (0.7) (100)= 30 + 70= 100

Next, we can calculate exponentially smoothed forecast for period 3.

Smoothed forecast for period 3 = α (Actual demand for period 2) + (1-α) (Smoothed forecast for period 2)

= 0.3 (110) + (0.7) (100)

= 33 + 70

= 103

Now, we can calculate exponentially smoothed forecast for period 4.

Smoothed forecast for period 4 = α (Actual demand for period 3) + (1-α) (Smoothed forecast for period 3)

= 0.3 (115) + (0.7) (103)= 34.5 + 72.1

= 106.6

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