Answer:
(9/10 mile)/(5/3 hour) = 27/50 miles/hour
Step-by-step explanation:
If you are looking for the speed, then speed = distance/time
speed = (9/10 mile)/(5/3 hour)
speed = 9/10 ÷ 5/3 miles/hour
speed = 9/10 × 3/5 miles/hour
speed = 27/50 miles/hour
Answer:
1. 9/10/3/5
2. 3/2
Step-by-step explanation:
Got it correct on iReady.
A study found that 85% of sports business executives surveyed believed that sponsor development of ________ in new venues will be a benefit of top-tier sponsorships in coming years.
100 Points
Emily wants to buy turquoise stones on her trip to New Mexico to give to at least 4 of her friends. The gift shop sells small stones for $4 and large stones for $6, and Emily has no more than $30 to spend.
Write and graph a system of Linear Equations and write two possible solutions.
Answer:
Step-by-step explanation:
what is she going to buy? Small stones or big stones? if its small stones then she can buy 7 small stones. If its big stones then she can buy 5 big stones.
What is the period of the trigonometric function f(t) = 3sin()?
A) 2 pi
B) 3 pi
C) 4 pi
D) pi / 2
plz help asap plzz plllzzzzz
Write the equation of a sine or cosine function to describe the graph.
Answer:
Step-by-step explanation:
Average = (Ymax + Ymin)/2 = (4 + (- 2))/ 2 = 1
Amplitude = (Ymax - Ymin)/2 = (4 - (- 2))/ 2 = 3
y is at a maximum when x = 0, so cosine function is easy.
one cycle (2π radians) is completed in 2π/3
therefore
y = 1 + 3cos(2π(x /(2π/3))
y = 1 + 3cos(3x)
Answer(s):
[tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1 \\ y = 3cos\:3x + 1[/tex]
Step-by-step explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{6}} \hookrightarrow \frac{-\frac{\pi}{2}}{3} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\:3x + 1,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{6}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{6}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{6}} = \frac{-\frac{\pi}{2}}{3}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\frac{2}{9}\pi, -\frac{1}{2}],[/tex]from there to [tex]\displaystyle [\frac{4}{9}\pi, -\frac{1}{2}],[/tex]they are obviously [tex]\displaystyle \frac{2}{3}\pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{2}{3}\pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
You buy a $266,000 home.with. a.down payment of 21%. Find the amount of the down payment and the mortgage amount.
down payment mortgage amount
[tex]5/12 + 11d/12 - 3 = 3d + 7 - 4d.[/tex]
PLEASE HELP!!
The values of x and y which satisfy the equations
x + 2 y = 27 and 2x - y = 19 are respectively
(A) 15 and 10
(B) 10 and 15
(C) 7 and 13
(D) 13 and 7
A line that passes through (3, 1) and (0, -3)
1
Write the equation
for this line in
slope-intercept form.
y = -2x + [?]
4-3-4-1
34
op
A 4
B. 2
C -2
D. -12
Answer:
A, -4 is the answer
Step-by-step explanation:
it intersects there
you have to estimate
Answer:
75,388
Step-by-step explanation:
Long Multiplication form
[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]
[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]
[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]
[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex] [tex]=75,388[/tex]
See Image for the addition:
plz help its so confusing
Answer:
20, 4
Step-by-step explanation:
Let's assume total number of students registered is n
Last week n/4 people are absent
so people present are n - n/4 = 3n/4
Today after return of Jen 1/5 n are absent
so people present are n - n/5 = 4n/5
which is also equal to last week present people + 1 (Jen)
= 3n/4 + 1
= (3n + 4) / 4
so (3n + 4) / 4 = 4n/5
=> 3n + 4 = 4n/5 * 4
=> (3n + 4) * 5 = 16n
=> 15n + 20 = 16n
=> 20 = n
=> n = 20
So total students registered for class is 20
today no of people absent = n/5 = 20/5 = 4
solve: |2(x-5)|+11=17
Answer:
x = 8, x = 2
Step-by-step explanation:
|2(x-5)|+11=17
|2(x-5)| = 6
|(x-5)| = 3
x = 8 AND x = 2 because of the absolute value.
Brainliest, please :)
The solution of the given equation will be x = 2 and 8.
What is an expression?
Expression in math is defined as the collection of the numbers, variables and functions by using signs like addition, subtraction, multiplication, and division.
Given that;
The expression is;
| 2 (x - 5) | + 11 = 17
Now, Solve the expression is;
| 2 (x - 5) | + 11 = 17
Subtract 11 both side,
| 2 (x - 5) | + 11 - 11 = 17 - 11
| 2 (x - 5) | = 6
Reduce modulus we get;
2 (x - 5) = ±6
Take positive sign,
2 (x - 5) = 6
x - 5 = 6/2
x - 5 = 3
x = 3 + 5
x = 8
And, Take negative sign,
2 (x - 5) = -6
x - 5 = -6/2
x - 5 = -3
x = 5 - 3
x = 2
Thus, The solution of the given equation will be x = 2 and 8.
Learn more about the modulus function visit:
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Crafts Unlimited sells ribbon by the foot. Serena needs ribbon
for an art project. The cost of the ribbon is 5 feet for $3.00.
Feet of Ribbon 1 5 10 15
Cost (in dollars) $3.00
a. Complete this ratio chart based on the information provided.
b. How many feet of ribbon can Serena buy for $12.00?
c. If Serena needs 17 feet of ribbon, how much will she pay?
How do you know?
The completed ratio chart is provided below:
Feet of Ribbon 1 5 10 15
Cost $0.60 $3 $6 $9
The amount Serena would get if she has $12 is 20 yards.
The amount Serena would pay if she wants 17 feet of the ribbon is $10.20.
The first step is to determine the unit cost of a ribbon.
Unit cost of a ribbon = $3 / 5 = $0.60
The cost of 10 feet of the ribbon = $0.60 x 10 = $6
The cost of 15 feet of the ribbon = $0.60 x 15 = $9
The feet of ribbon Serena can buy if she has $12 = $12 / $0.60 = 20 yards.
The cost of 17 feet of the ribbon = $0.60 x 17 = $10.20
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Use the drop-down menus to complete each statement to show why 5sqrt(7) is between 10 and 15.
Answer:
First drop down: √4 and √9
Second drop down: 2 and 3
Third drop down: 10 and 15
Step-by-step explanation:
the root of four is 2
the root of nine is 3
thus √ 7 is between 2 and 3
5√7 is between 10 and 15 because 2x5 is 10 and 3x5 is 15.
Evaluate.
12⋅(1/4+1/3)power 2 +23 help ASAP
Answer:
325/12
Step-by-step explanation:
12(1/4 + 1/3)² + 23
12(7/12)² + 23
12(49/144) + 23
49/12 + 23
325/12 = 27 1/12 = 27.08333333
Please Help, This is Due in 4 Hours.
At the deli counter, Dalton bought 0.38 of a pound of roast beef and 0.7 of a pound of ham. Compare the amounts of roast beef and ham that Dalton bought.
Record the comparison using the <, >, or = symbol and explain how you know.
Answer:
0.38 < 0.70
Step-by-step explanation:
what is the equation of this line in slope-intercept form
Answer:
y=3/5x+3 i think
Step-by-step explanation:
3 is the y intercept, and to find the slope its rise over run so 3 up and 5 to the side, i hope this helps!!
Find the complementary Angle of 24 / 1/5
Incredibly, Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of total tickets.
What is the minimum number of games that Enzo could have played?
Answer:
Enzo must have played 11 games.
Step-by-step explanation:
Since Enzo earns 5 tickets from every game and Beatriz wins 11 tickets from each game, we have to find the LCM (Least Common Multiple) since they earned the same amount of tickets when they stopped.
The LCM of 11 and 5 is 55.
To see how many games they both played we have to divide the amount of tickets they earn each time from the LCM (55).
Since Enzo earns 5 tickets from each game and both Enzo and Beatrice earned 55, Enzo must've played 11 games.
(If that makes sense lol)
An investor has an account with stock from two different companies. Last year, his
stock in Company A was worth $2000 and his stock in Company B was worth $4240.
The stock in Company A has increased 1% since last year and the stock in Company B
has increased 5%. What was the total percentage increase in the investor's stock
account? Round your answer to the nearest tenth (if necessary).
Answer:
Submit Answer
acer
Answer:
Total percent: 3.7%
Step-by-step explanation:
(2000 x 0.01) + (4240 x 0.05) = $232
X/100 = 232/6240
= 23200/6240 = 3.7%
Question: • What is the slope?
• What is the y-intercept?
Which set of ordered pairs lies along the same vertical line?
Answer:
All ordered pairs with the same x value
Step-by-step explanation:
A vertical line can be represented by the equation x=k for some value k. So any pair with x value equal to k satisfies the equation and is thus in the set
A furniture store receive
order for 456 chairs. They
can fit 9 chairs in a large
shipping box. How many
shipping boxes will they
need to ship all of the
chairs?
Math is hard help me please
Answer:
the third answer
Step-by-step explanation:
because If two positive numbers are multiplied together or divided, the answer is positive. If two negative numbers are multiplied together or divided, the answer is positive. If a positive and a negative number are multiplied or divided, the answer is negative.
Problem 1
Each scholar in fifth grade participates in one of the three extracurricular activities: sports,
chess, or art.
2/5 of the fifth grade scholars participate in sports
1/4 of the fifth grade scholars participate in chess
What fraction of the fifth grade scholars participate in art?
Answer:
7/20 participate in art.
Answer:
7/20 hcjauwauhfehhfieafuewaueiwavibiurbviubwibvebaiubj
What is the value of w?
Answer:
w= -2. Solve for w: (w-5) (w+2) = w^2-4. Expand out terms of the left hand side: w^2-3 w-10 = w^2-4. Subtract w^2-4 from both sides
Step-by-step explanation:
If 3 bananas cost of 50 cents, how many bananas can be bought for 20 dollars?
Answer:
120 bananas
Step-by-step explanation:
$20 = 2000 cents
Create a proportion:
Cross multiply, then divide: 3 × 2000 = 6000, 6000 ÷ 50 = 120
So, you can buy 120 bananas for $20
hope this helps
A satellite orbits the Earth with an elliptical orbit modeled by x squared over 47 million three hundred thirty four thousand four hundred plus y squared over forty three million nine hundred fifty six thousand nine hundred equals 1 comma where the distances are measured in km. The Earth shares the same center as the orbit. If the radius of the Earth is 6,370 km, what is the maximum distance between the satellite and the Earth?
6,880 km
6,630 km
510 km
260 km
An elliptical of the satellite in the field of astrodynamics is known as a
Kepler orbit.
The distance between the satellite and the Earth is; 510 km.
Reasons:
The function that represents the elliptical orbit of the satellite is presented
as follows;
[tex]\dfrac{x^2}{47,334,400} + \dfrac{y^2}{43,956,900} = 1[/tex]
The radius of the Earth, R = 6,370 km.
The equation of an ellipse is presented as follows;
[tex]\mathbf{\dfrac{(x - h)^2}{a^2} + \dfrac{(y - k)^2}{b^2}} = 1[/tex]
Where, in a horizontal ellipse;
a = The major axis (the longer axis), which gives the maximum distance
between the satellite and Earth.
b = The minor axis (the shorter axis)
By comparison, we get;
a² = 47,334,400 km²
Therefore;
a = √(47,334,400 km²) = 6,880 km.
The distance between the satellite and the surface of the Earth, d, is given
as follows;
d = a - R
Which gives;
d = 6,880 km - 6,370 km = 510 km
Distance between the satellite and the surface of the Earth, d = 510 km.
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Answer:510 KM
Step-by-step explanation:
1
4
3
Time (h)
2
.
3
Cars
Washed
6
9
12
a. Proportional?
b. Equation:
C. Number of hours:
3. Cars washed:
Step-by-step explanation:
Proportional = time/cars washed
= 1/3
no. of hours= 90hours
cars washed = 30 cars washed