Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?
Answers
The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]
the momentum is defined by the product of the mass and the velocity of the body.
p = mv
The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.
If the system is isolated, the forces during the collision are internal and the it is conserved. Let's find the momentum is two instants.
Initial instant. Before crash.
p₀ = m₁ u₀ + 0
Final moment. After crash.
[tex]p_f = m_1 u_f + m_2 v_f[/tex]
The momentum is preserved.
p₀ = [tex]p_f[/tex]
[tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]
Since the collision is elastic, the kinetic energy is conserved.
K₀ = [tex]K_f[/tex]
½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex] + ½ m₂ [tex]v_f^2[/tex]
Let's write our system of equations.
[tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]
Let's solve
[tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]
[tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]
[tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
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Both choices are correct.
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Answer:
Wheel and axleForce multipliersLeverInclined planePulleyScrewWedgeExplanation:
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Some machines decrease mechanical advantage and are utilized to multiply distance to decrease speed.
What is the mechanical advantage?Mechanical advantage can be described as a measure of the ratio of output force to input force in a system. Mechanical advantage is used to analyze the forces in simple machines such as levers and pulleys.
Mechanical Advantage= output force (load) /input force(effort)
The mechanical advantage will increase as the slope of the inclined plane decreases but the load has to move with more distance. Under the mechanical advantage, the distance the load will move will be a fraction of the distance through applied force.
Thus, the mechanical advantage is decreased by some simple Machines decrease and are used to multiply distance to decrease speed.
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Answers
The kinetic energy of the toy before hitting the ground is 294.3 J
From the question given above, the following data were obtained:
Mass (m) = 3 Kg
Height (h) = 10 m
Acceleration due to gravity (g) = 9.81 m/s²
Kinetic energy (KE) =?Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.
KE = PE = mgh
KE = 3 × 9.81 × 10
KE = 294.3 JTherefore, the kinetic energy of the toy is 294.3 J
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A camper stands in a valley between two parallel cliff walls. He claps his hands and notices that the echo from the nearby wall returns 0.9 s later while the echo from the farther wall returns 1.10 s later. If the air temperature is -10 C, how wide is the valley?
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Answer:
675 KM
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hAVE A NICE DAY
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Explanation:
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Answer:
the answer is solid.
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The energy of characteristic x rays tend to increase for heavier elements
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X rays energy is also usually more in heavier elements than when
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Answer:
Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
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Một oto đang chuyển động thẳng đều với vận tốc 36km/h thì hãm phanh sau 20s thì ô tô dừng lại quãng đường oto đi được là
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Answers
Answer:
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What is change in internal energy?Internal energy is all the energy contained in an object.
To calculate the change in internal energy of the system, we use the formula below.
Formula:
ΔU = Q-W............. Equation 1Where:
ΔU = Change in internal energy of the system,W = work done by the systemQ = Heat released by the system.From the question,
Given:
Q = - 622 kJ ( released of heat)W = 105 kJ.Substitute these values into equation 1
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PLS ANSWER FAST CORRECT ANSWER WILL BE BRAINLIEST
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Answer:
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Answer:
ETotal=38505J
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Known values:
m=150kg
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Answers
Answer:
2 m/s2
Explanation:
|acceleration| = (change in speed) divided by (time for the change)
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Initial speed of walking = 1 m/s
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Change of speed in walking = (3 - 1) m/s
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Time in which the change of speed occurred = 1 sec
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What is acceleration?Acceleration can be defined as the rate of change of velocity.
The acceleration can be calculated using the formula below.
Formula:
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Given:
v = 3 m/su = 1 m/st = 1 secondsSubstitute these values into equation 1
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