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1. N2 + 3H2 → 2NH3
If you form 5.24 moles of NH3 from the above reaction, how many moles of N2 were
present at the start of the reaction?

Answer

Laws that are used by astronomers to learn about stars indirectly are as given below:-

Answer:

Approximately [tex]3.6 \times 10^{-10}\; {\rm M}[/tex], assuming that the solution is dilute and is at room temperature (such that [tex]K_\text{w} = 10^{-14}[/tex].)

Explanation:

Look up the ion product constant of water:

[tex]K_{\text{w}} \approx 10^{-14}[/tex].

In a dilute solution where water is the solvent, the product of [tex][{\rm {H_{3}O}^{+}}][/tex] and [tex][{\rm {OH}^{-}}][/tex] (concentration of [tex]\rm {H_{3}O}^{+}}[/tex] ions and [tex]{\rm {OH}^{-}}[/tex] ions) is constantly equal to [tex]K_{\text{w}}[/tex]. (The unit of both [tex][{\rm {H_{3}O}^{+}}]\![/tex] and [tex][{\rm {OH}^{-}}]\![/tex] need to be [tex]{\rm M}[/tex].) In other words:

[tex][{\rm {H_{3}O}^{+}}]\, [{\rm {OH}^{-}}] = K_{\text{w}}[/tex].

Rearrange this equation to find [tex][{\rm {OH}^{-}}][/tex] in terms of [tex]K_{\text{w}}[/tex] and [tex][{\rm {H_{3}O}^{+}}][/tex]:

[tex]\begin{aligned}[] [ {\rm OH^{-}} ] &= \frac{K_{\text{w}}}{[{\rm {H_{3}O}^{+}}]} \\ &= \frac{10^{-14}}{2.8 \times 10^{-5}} \\ &\approx 3.6 \times 10^{-10}\end{aligned}[/tex].

We need moles of Ca(OH)_2

Molar mass of Ca(OH)_2=74g/mol

Now

Option C

The mass of Ca(OH)₂ in the given solution is approximately 2.78 grams, which corresponds to option C) 2.78 g.

Given: Volume = 1500 mL, Concentration (Molarity) = 0.0250 M, and Compound = Ca(OH)₂ .

First, convert mL to L: Volume = 1500 mL × (1 L / 1000 mL) = 1.5 L.

Use the formula for calculating the number of moles: Moles = Concentration × Volume.

Moles = 0.0250 mol/L × 1.5 L = 0.0375 mol.

The molar mass of Ca(OH)₂  can be calculated:

Ca(OH)₂  molar mass = (1 * atomic mass of Ca) + (2 * atomic mass of O) + (2 * atomic mass of H)

= (1 * 40.08 g/mol) + (2 * 16.00 g/mol) + (2 * 1.01 g/mol)

= 74.09 g/mol.

Now, calculate the mass using the calculated moles and molar mass:

Mass = Moles × Molar mass

Mass = 0.0375 mol × 74.09 g/mol = 2.78 g.

Therefore, the mass of Ca(OH)₂  in the given solution is approximately 2.78 grams, which corresponds to option C) 2.78 g.

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The complete question is:

What mass of Ca(OH)₂ is contained in 1500 mL of 0.0250 M Ca(OH)₂ solution?

A) 1.85 g

B) 2.34 g

C) 2.78 g

D) 3.17 g

Answer:

your answer should be 0.57 atm

Answer:

51 579 C

Explanation:

I will assume the PRESSURE remains constant

then

V1 /T1  = V2/T2       T will be in Kelvin

                                25 C =  298.15 K

2.3 l / 298.15 K    =  400 l / T2

solve for T2 = 51852.17 K   = 51579 C

[tex]\huge\mathfrak\colorbox{white}{}[/tex]

nuclear energy, once used up it can not be used again

Filling in the gaps in the excerpt below

Molecules that do not  __Dissociate__________ (or come apart) in solution are called ___Non-electrolyte substances_________ . Most of these substances are covalently bonded __and do not conduct electricity__________ (e.g., glucose, urea, and creatinine). In contrast, a(n) ___Electrolyte_________ is any substance that dissociates in solution to form Salts

Electrolytes are substances that conduct electricity because they readily ionize when placed in a solution. while Non-electrolytes do not readily conduct electricity because they do not dissociate  into ions when placed in a solution.

Hence we can conclude that the answers to your questions are as listed above.

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K3N : Mg3N

1 : 1

X : 2,1

n(K3N) = 2,1 mol

M(K3N) = 39×3 + 32

= 149

m= nM

= 2,1 × 149

= 312,9g

Answer:

I think the answer is 0 because 0 mols of sodium react

Explanation:

Answer:

I think c is the right answer

Answer:

The substances which neutralize the acids of the stomach are called antacids. Acidity in the stomach causes the sensation of heartburn, antacids are taken to relieve this sensation. They are taken orally to suppress the effects of acidity.

Answer:

give off carbon to the air. Giving off carbon allows them to make energy storage molecules.

Explanation:

Trees use energy from the sun to create sugars through a process called photosynthesis and without these sugars as an energy source a tree cannot grow or ultimately survive. A study by Thomas Givnish found that the process of photosynthesis is directly impacted by the amount of sunlight that hits a tree's leave.

Sunlight and Tree Shape – Crandall Park Trees

Downy Woodpecker

Reading and Annotating the Question

One way to narrow the choices is to read the question first. While reading the question, annotate for important phrases. I would underline "dead branches and dying trees" and "habit would be most affected."

Reading and Annotating the Chart

Now that we have read the question, it is time to read the chart. While you read, check for words or phrases that relate to the phrases we underlined in the question. When I read the chart I noticed the phrase "decaying trees" under the Downy Woodpecker. Since the Downy Woodpecker depends on decaying trees, they would be heavily affected by the removal of dying trees.

Process of Elimination

To check our answer we can use the process of elimination.

A) We can eliminate the Baltimore Oriole because it relies on "tall trees," not dying trees.

B) The Barn Swallow is also incorrect because they nest "under roofs," which is not affected by the removal of any trees.

D) Finally, the Belted Kingfisher is wrong because they build nests in "tunnels or burrows," which is also unrelated to the removal of trees.

Taking into account the definition of Volume to Volume Percentage (% V/V), 61.3548 mL of isopropanol are in a 89.7 mL sample of the rubbing alcohol solution.

Volume to Volume Percentage (% V/V) is a measure of concentration that indicates the volume of solute per 100 volume units of solution.

In other words, the percentage %v/v indicates the volume of solute (in mL) that is dissolved in 100 mL of solution.

The %v/v of a solution is determined by the following expression, which is multiplied by 100 to express it as a percentage:

[tex]v/v=\frac{volume of solute (mL)}{volume of solution(mL)} x100[/tex]

In this case, you know:

Replacing in the definition of %v/v:

[tex]68.4=\frac{volume of solute (mL)}{89.7 mL} x100[/tex]

Solving:

volume of solute= (68.4× 89.7 mL)÷ 100

volume of solute= 61.3548 mL

Finally, 61.3548 mL of isopropanol are in a 89.7 mL sample of the rubbing alcohol solution.

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Precipitation is the fall of the condensed product to the ground. The freezing rain occurred because the air above the ground was above freezing.

Freezing rain is the form of precipitation that occurs when the rain droplets freeze upon contacting the ground surfaces. It is composed entirely of liquid water droplets.

Freezing rain occurred because there was not enough time for the water to freeze in a cloud, unlike the snow. Snow is another type of precipitation that forms when the temperature is low in the atmospheric surroundings.

Therefore, option C. the air above the ground surface was above freezing level explains the formation of freezing rain.

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Answer:

ummm a I guess if I am wrong tell me

Answer:How many moles are there of a 2 M solution with a volume of 17.95 liters = 35.9 moles !

Explanation: The formula for calculating the molarity of the solution is expressed as Molarity= mole/volume

Molarity = 2 M

Volume=17.95L

Substitute the given parameters into the formula … and you get

mole=molarity x volume

Mole=2M x 17.95L

Mole=35.9moles

moles of the solution is 35.9 moles

Hope this helps if so mark Brainalist thanks

Answer:

The α-ketoglutarate dehydrogenase enzyme is structurally and functionally homologous to the pyruvate dehydrogenase complex.

hope it helps

The minerals effervesce (produces a bubbling, fizzing reaction) in hydrochloric acid is calcite. The correct option is D, calcite.

Calcite is a mineral that is very hard, and highly reactive.

It is present in many colors, white, yellow, orange, red, green, and blue.

In Ancient Egypt, calcite was used to carve many things, such as bast, alabaster, etc.

Thus, the correct option is D, calcite.

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As the water temperature increased, the copper sulfate crystals dissolved faster but there was little change for the powdered form.

Increasing the temperature of a solvent can increase the rate at which a solid dissolves. This is because an increase in temperature causes the solvent molecules to move more rapidly, which in turn increases their kinetic energy and ability to interact with the solute particles.

As a result, the solute particles are more likely to break free from their crystal lattice and become surrounded by the solvent molecules.

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Answer:

A given quantity of solute dissolves faster when it is ground into small particles because more surface area is exposed.

Explanation:

The more surface area of a solute that is exposed, the faster the solute will dissolve. Like sugar for an example, sugar cubes take longer to dissolve as compared to regular ground up sugar.

And I took the test and got this right!

There is the change in temperature is the correct answer.

Carbonated beverages are drinks that include carbon dioxide dissolved in water.

It is given as the formation of bubbles and the odour will be concluding with the formation of the new product and thereby a chemical change. Whereas there was no chemical change if the temperature lowers down as the reason stands to be the formation of a mixture.

Hence, there is a change in temperature.

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80 molecules of [tex]NH_{3}[/tex] will be formed if 60 molecules of [tex]N_{2}H_{4}[/tex] decomposes into [tex]N_{2}[/tex] and [tex]NH_{3}[/tex]

The smallest particle of a substance has all of the physical and chemical properties of that substance. Molecules are made up of one or more atoms.

Just balance the reaction:

[tex]3N_{2}H_{4}\to N_{2}+4NH_{3}[/tex]

Now you can see that every 3 molecules of [tex]N_{2}H_{4}[/tex]4 molecules of [tex]NH_{3}[/tex].

For 60molecules of [tex]N_{2}H_{4}[/tex] we scale up these numbers by a factor of 60/3 = 20.

Therefore 4x20 = 80 molecules of  [tex]NH_{3}[/tex] are formed.

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Answer: true

Explanation:

Ocean salinity will vary with evaporation as well as with freezing and thawing. this statement is true.

Salinity, commonly known as saline water (also see soil salinity), is the degree of saltiness or the quantity of salt dispersed throughout a body of water. The standard units of measurement are grammes of salt per litre (g/L) or grammes per kilogramme (g/kg; the latter one is dimensionless therefore equal to ).

Salinity is a thermodynamic condition variable that, along with pressure and temperature, controls physical properties like the density also heat capacity of the water. Salinity plays a significant role in defining numerous facets of the chemical composition of natural waters as well as the biological processes within them. Ocean salinity will vary with evaporation as well as with freezing and thawing. this statement is true.

Therefore, ocean salinity will vary with evaporation as well as with freezing and thawing. this statement is true.

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Answer: 75.77%

Explanation:

Percent yield = (actual yield)/(theoretical yield) = 20.05 / 26.46 * 100 = 75.77%

Answer:

Equal

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Answer:

Na - 1 away from neon

Li - 1 away from helium

K - 1 away from argon

Cs - 1 away from xenon

Explanation:

We see this trend as group 1A elements are 1 away from noble gases and hence, have a valency of 1

Answer:

Explanation:

The formula for concentration is C = n/V

Where C represents concentration in mol/L.

n represents moles in mol.

V respresents volume in L.

You have 550 mL, let's convert it to L (1000 mL= 1L)

550 mL / 1000 = 0.55 L

We got V and we need n. We can find n by this formula:

n = m/M

m represents mass in g.

M represents molar mass in g/mol.

We are given grams of iron (II) chloride (FeCl2)

Find the molar mass by the periodic table: 55.85 + (2*35.45) = 126.75 g/mol.

n = (350 g) / (126.75 g/mol) = 2.76134 mol

Back to our first formula: C = n / V

C = (2.76134 mol) / (0.55 L) = 5.0206 mol/L.

to 3 significant digits it's 5.02 mol/L, and that is how you find concentration.