314. Find the area under the graph of f(t) = t/(1+t^2) where t is
between t= 0 and t = x. where a > 0 and a does not equal 1 is
fixed, and evaluate the limit as x → .
Infinity

Answer:

45

Step-by-step explanation:

divide 3.15 by 0.07 to get 45

Answer:45

Step-by-step explanation:

divide 3.15 by 0.07 answer 45

Answer:

530.93 OR 530.9

Step-by-step explanation:

Since we know what the radius is 13 we replace R with 13 in the formula form area of a circle. area = [tex]\pi 13^{2}[/tex]

So now we multiply 13 squared or 13 x 13 which equals 169

Now we multiply pi and 169 which gives us 530.929 depending on what number you should round to give  us our answer.

530.93

530.9

Answer:

12/12

Step-by-step explanation:

6/12= 1/2

so 1/2+1/2 = One Whole and that the same thing as 12/12

Answer:

Answer is option C

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

it would be the first one!

Answer:

z ≥ -10, which is the first answer.

Step-by-step explanation:

As you can see, on the graph there is a point filled in with a line pointing to the right. That would mean the sign would be ≥, as Z is GREATER than or EQUAL TO.

Answer:

2/6

Step-by-step explanation:

you move up to spaces and over six spaces

Answer:

i: 14

ii: 140

iii: 770

(In question iii I didn't put the 10 hours overtime in it and if I put it its 910.

Step-by-step explanation:

i: 650/40=14

ii: 14x10=140

iii: 14x55=770

Answer:

6.7

Step-by-step explanation:

Answer:

6.700

Step-by-step explanation:

hope this helped

Answer:

x = 12

y = 0

Step-by-step explanation:

Sum them:

2x = 24

so x = 12

12 - y = 12

so y = 0

Answer:

no clue -0- if I knew I would tell you

[tex] \text{Given : Which ordered pair is the solution to the system of equations?} \\ \\ \begin{cases}-5x - 3y = 12 \\ y - x = 12 \end{cases} [/tex]

[tex] \text{Solution : According to the question, here let's take these variables as two} \\ \text{equations then get their value and finally get the answer.} \\ \\ \sf {1}^{st} \: equation : \\ \leadsto \frak{-5x - 3y = 12} \\ \\ \leadsto \frak{-5x = 12 + 3y} \\ \\ \leadsto \frak{x= \frac{12 + 3y}{-5}} \qquad \sf ...eq(1) \\ \\ \sf 2^{nd} \: equation : \\ \leadsto \frak{y = x - 12} \qquad \sf ...eq(2) \\ \\ \underline{ \frak{finding \: x }} : \\ \\ \dashrightarrow \frak{x= \frac{12 + 3y}{-5}} \\ \\ \dashrightarrow \frak{x= \frac{12 + 3(x - 12)}{-5}} \\ \\ \dashrightarrow \frak{x= \frac{12 + 3x - 36}{-5}} \\ \\ \dashrightarrow \frak{-5x= 12 + 3x - 36} \\ \\ \dashrightarrow \frak{-5x - 3x= - 24} \\ \\ \dashrightarrow \frak{-8x = - 24} \\ \\ \star \quad \underline{ \boxed{ \green{ \frak{x = 3}}}} \\ \\ \underline{ \frak{ getting \: y}} : \\ \\ \dashrightarrow \frak{y = 3 - 12} \\ \\ \star \quad\underline{ \boxed{\blue{ \frak{y = - 9}}}} \\ \\ [/tex]

[tex] \green{ \mathbb{HENCEFORTH, \: THE \: PAIR \: IS \: \pink{\frak{ (3,-9)}}}}[/tex]

Answer

Use your mind  

Nobody wants to help you, especially since you are no help to others.

9514 1404 393

Answer:

  (x, y) = (-6, 15) and (2, -1)

Step-by-step explanation:

You can start by subtracting the second equation from the first.

  (y) -(y) = (x^2 +2x -9) -(-2x +3)

  0 = x^2 +4x -12 . . . . . . collect terms

  0 = (x +6)(x -2) . . . . . . . factor

Solutions for x are -6 and +2. These values make the factors zero.

The corresponding solutions for y are ...

  y = -2(-6) +3 = 15

  y = -2(2) +3 = -1

Solutions to the system of equations are ...

  (x, y) = (-6, 15) and (2, -1)

Answer: C

Step-by-step explanation:

Hope it help

Answer:

4

Step-by-step explanation:

8x - 12

4(2x - 3)

Answer:

so no answer

Step-by-step explanation:

no answer

[tex]v^{2}[/tex]Answer:

4 feet long

Step-by-step explanation:

Pythagorean Theorem: [tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

In this problem, a and b are the legs of the triangle, while c is the hypotenuse

Plugging the values of [tex]\sqrt{5}[/tex] and [tex]\sqrt{11}[/tex] to the equation you get:

5 + 11 = [tex]c^{2}[/tex]

Therefore, [tex]c^{2}[/tex] = 16, and by taking the square root you find that c, or the hypotenuse, must equal 4.

Pascal's triangle up to the 7th row (starting with 0)

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

1 6 15 20 15 6 1

1 7 21 35 35 21 7 1

Then the 6th term in the expansion of (x + 5)⁷ is

7 • x¹ • 5⁶ = 109375x

I hope that the attachment helps you..

Answer:

The intersection operation is denoted by the symbol ∩. The set A ∩ B—read “A intersection B” or “the intersection of A and B”—is defined as the set composed of all elements that belong to both A and B. Thus, the intersection of the two committees in the foregoing example is the set consisting of Blanshard and Hixon.

Answer:

Not a linear function

Step-by-step explanation:

3xy = 27 is not a linear function.

A linear function is given by f(x) = mx + b (in slope-intercept form), or Ax + By = C (in standard form).   An easier way of understanding the linear function is to envision that the variables (x and y), along with the constant,(y-intercept, are along the same line.  

Isolating y from the left-hand side:

3xy = 27  

On the left-hand side of the equation: 3xy involves a multiplication operation. Thus, 3xy  is the same as expressing it as  3·x·y.  

We cannot simply add or subtract x or y to isolate either one of the variables.  The proper mathematical operation to do so is by division.

Hence, we must divide both sides by 3x to isolate y:

[tex]\displaystyle\mathsf{\frac{3xy}{3x}\:=\:\frac{27}{3x}}[/tex]

[tex]\displaystyle\mathsf{y\:=\:\frac{9}{x}}[/tex]   ⇒ This is a reciprocal function, also known as an inverse function, where it is undefined when x = 0.  The graph of an inverse function is a hyperbola.      

Attached is the graph of  [tex]\displaystyle\mathsf{y\:=\:\frac{9}{x}}[/tex]  to show why it is not considered as a linear function. A linear function will show a straight line.  

Answer:

30

Step-by-step explanation:

Hope this helps!!! :))

Answer:

b c = 5.25p this is the answer

For the first problem shown the answer is number B.

It is B because we our always going up by $5.25

For our second one it isn't a function,

it isn't a function because it follows the same rule through-out it besides at the end of it.

[tex]\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-1}x^2\stackrel{\stackrel{b}{\downarrow }}{+3}x\stackrel{\stackrel{c}{\downarrow }}{+8} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{3}{2(-1)}~~,~~8-\cfrac{3^2}{4(-1)} \right)\implies \left( \cfrac{3}{2}~~,~~ 8+\cfrac{9}{4}\right)\implies \left( \cfrac{3}{2}~~,~~ \cfrac{41}{4}\right)[/tex]

now, for the solutions, or namely the x-intercepts, we simply set y = 0 and solve for "x", now this one doesn't factor into integers nicely, so we'll need to use the quadratic formula to get them.

[tex]~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{-1}x^2\stackrel{\stackrel{b}{\downarrow }}{+3}x\stackrel{\stackrel{c}{\downarrow }}{+8} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x=\cfrac{ - 3 \pm \sqrt { 3^2 -4(-1)(8)}}{2(-1)}\implies x = \cfrac{-3\pm\sqrt{9+32}}{-2}\implies x = \cfrac{3\mp\sqrt{41}}{2}[/tex]

[tex]x = \begin{cases} \cfrac{3-\sqrt{41}}{2}\\[2em] \cfrac{3+\sqrt{41}}{2} \end{cases}\qquad \leftarrow \qquad na mely\textit{ solutions or zeros or x-intercepts}[/tex]

Answer:

-0.825

Step-by-step explanation:

Did not know the options so do not know if this is right or not.

Here is ur answer.

- BRAINLIEST answerer

Answer and explanation in the image.