MULTIPLE CHOICE
What is the distance from A to B in the diagram below?

The high prevalence of human rights violations can negatively impact a community in terms of:

These are the inherent rights of all human beings, such as the right to life, work and security, for example, without distinction of class, gender or any other characteristic. They exist to protect liberty and promote equity among individuals.

Therefore, a community with human rights violations will be harmed in relation to its social and economic structure.

Find out more about human rights here:

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Answer:

A < C < B = 0.2 < 0.222 < 0.25

Step-by-step explanation:

the best way to do these least to greatest questions is to get them all in the same units so you can compare.

A = [tex]\sqrt{\frac{1}{25} }[/tex]which is [tex]\sqrt{0.04}[/tex] = 0.2

B= 1/4 = 0.25

c=0.22222222.....

now that they are in the same units we see A is the smallest, then C, and then B

Answer:26

Step-by-step explanation:

Answer:

19%

Step-by-step explanation:

Bottles manufactured in march = 4100×107% = 4387 bottles

bottles manufactured in April= 4387+500 = 4887 bottles

difference in bottles from Feb to April= 4887-4100 =787 bottles

percentage increase from Feb to April= (787/4100)×100 = 19.2%

rounded off= 19%

(0.2)x = 2.

Taking log on both sides

log (0.2)x = log 2.

x log (0.2) = 0.3010, [since log 2 = 0.3010].

x log (2/10) = 0.3010.

x [log 2 - log 10] = 0.3010.

x [log 2 - 1] = 0.3010,[since log 10=1].

x[-0.699] = 0.3010.

x= 0.3010/-0.699.

x= = -0.4306….

x= = -0.4.

(0.2)x = 2.

Taking log on both sides

log (0.2)x = log 2.

x log (0.2) = 0.3010, [since log 2 = 0.3010].

x log (2/10) = 0.3010.

x [log 2 - log 10] = 0.3010.

x [log 2 - 1] = 0.3010,[since log 10=1].

x[-0.699] = 0.3010.

x = 0.3010/-0.699

x = -0.4306

x= -0.4 (nearest tenth)

Answer:

15 miles

Step-by-step explanation:

You know that there are 8 kilometres in 5 miles, so:

120/8=15

Answer:

[tex]W_{max}=320m\\ L_{max}=160m[/tex]

Step-by-step explanation:

Since we know we only have 640 feet of fence available, we know that L + W + L = 640, [tex]\implies [/tex] 2L + W = 640. This allows us to represent the width, W, in terms of L: W = 640 – 2L

Remember, the area of a rectangle is equal to the product of its width and length, therefore,

[tex]A_{\rm pigpen}=L(640-2L)\implies 640L-2L^2[/tex]

Notice that, quadratic has been vertically reflected, since the coefficient on the squared term is negative, so the graph will open downwards, and the vertex will be a maximum value for the area.

recall,

Since our function is A(L)=640L-2L², we get

plug in the value of a and b into the first formula:

[tex]L_{max}=-(640)/2(-2)\implies 160 [/tex]

[tex]A(L)_{max}=640(160)-2(160)^2\implies 51200 [/tex]

hence,the dimensions of the pen that will maximize the area are L=160m and W=51200/160=320m

and we're done!

Answer:

width (x) = 160 m

length (y) = 320 m

(refer to the attached diagram)

Step-by-step explanation:

**see attached diagram**

Let x = width of the pig pen

Let y = length of the pig pen

(where length > width)

Given:

⇒ 2x + y = 640 m

⇒ y = 640 - 2x

Area of the pig pen = width × length

⇒ f(x) = xy

Substituting y for y = 640 - 2x:

⇒ f(x) = x(640 - 2x)

          = 640x - 2x²

Now we have a function for the area of the pig pen, to find the value of x that will maximize the area, differentiate the function:

⇒ f'(x) = 640 - 4x

Set it to zero and solve for x:

⇒ f'(x) = 0

⇒ 640 - 4x = 0

⇒ 640 = 4x

⇒ x = 160

Substitute the found value of x into y = 640 - 2x to find the length:

⇒ y = 640 - 2(160) = 320

Therefore, the dimensions of the pen that will maximize the area are:

Answer:

[tex]\displaystyle g'(s) = (s-s^4)^6[/tex]

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
[tex]\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt \right] = f(x)[/tex]

Where a is some constant.

We can let:
[tex]\displaystyle g(t) = (t-t^4)^6[/tex]

By substitution:

[tex]\displaystyle g(s) = \int_6^s g(t)\, dt[/tex]

Taking the derivative of both sides results in:
[tex]\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right][/tex]

Hence, by the Fundamental Theorem:

[tex]\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\ & = (s-s^4)^6\end{aligned}[/tex]

Answer:

25 Percent of tickets were early admission.

Step-by-step explanation:

We apply the percentage formula to solve this problem.

Total Ticket Amount * Percentage = Early tickets

We plug in our values

32 * x/100 = 8

Simplify

X=25

Answer:

25%

Step-by-step explanation:

8 out of 32 can be simplified to 1 early admission for every 4 tt (total tickets). 1/4 can be changed into a decimal which is .25, and  .25*100 is 25%

Answer:

-25

Step-by-step explanation:

f(-12) means x = -12

so you just plug it in the equation and solve for x

[tex]f(x) = 3(-12)+11\\f(x) = -36+11\\f(x) = -25[/tex]

Answer:

Step-by-step explanation:

Answer:

SSS

Step-by-step explanation:

XS=SZ

WS=SY

WX=ZY

I hope this is useful.

The congruence theorem that can be used to prove △WXS ≅ △YZS is SSS. ; option A.

Congruence theorems are theorems which are used to prove congruency in triangles.

The congruence theorems include:

In the given triangle;

Therefore, the congruence theorem that can be used to prove △WXS ≅ △YZS is SSS.

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#SPJ9

Answer:

3 I think

Step-by-step explanation:

1/3 opposite is 3/1 or 3

By identifying that it is a translation of the natural logarithm, we see that the function is:

g(x) = ln(x - 5).

We can see that the function has a logarithmic behavior. We know that the function:

f(x) = ln(x)

Has an asymptote at x = 0, and is equal to 0 for x = 1.

For our function, we can see that the asymptote is at x = 5 and the zero is at x = 6. So the graphed function seems to be the natural logarithm translated 5 units to the right.

Then the function graphed is:

g(x) = f(x - 5) = ln(x - 5)

If you want to learn more about translations, you can read:

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Answer:

m. 31.192

explanation 34.062-2.87

Answer:

[tex]\displaystyle 2\:in.[/tex]

Step-by-step explanation:

[tex]\displaystyle {\pi}r^2 = A \\ \\ \frac{{\pi}r^2}{\pi} = \frac{4\pi}{\pi} \hookrightarrow \sqrt{4} = \sqrt{r^2} \\ \\ \boxed{2 = r}[/tex]

I am joyous to assist you at any time.

Answer:

1 1/7

Step-by-step

E is on the 1 1/7 point on the number line

Answer:

[tex]1\frac{3}{20}[/tex]

Step-by-step explanation: Each space equals =.15. Count by the spaces not the lines. 15/100 simplifies to 3/20.

Answer: They intersect at [tex](2\frac{1}{6}, \frac{1}{3} )[/tex]

Step-by-step explanation:

We can solve this system of equations through elimination

Add (4x+y=9) with (2x-y=4)

[tex]4x+y=9\\+2x-y=4\\=\\6x+0=13[/tex]

Now that y is canceled out we can solve for x

[tex]6x=13\\\frac{6x}{6}=\frac{13}{6} \\x=2\frac{1}{6}[/tex]

Now sub back x into one of the original equations to find the value of y

[tex]4(2\frac{1}{6} )+y=9\\8\frac{2}{3} +y=9\\8\frac{2}{3}-8\frac{2}{3}+y=9-8\frac{2}{3}\\y=\frac{1}{3}[/tex]

Answer:

C

Step-by-step explanation:

Y=2(-1)+3

y=-2+3

y=1

true

Answer:

I think the amswer is C not 100% shere

Step-by-step explanation:

Answer:

B. 9 cubic units

Length×width×height

Answer:

125y3

Step-by-step explanation:

12x5=y

y3/2 = y26 - 5 =y

Answer:

D should be right

Step-by-step explanation:

Answer:

Clair,  since there isn't an attached picture, we don't know some info

Step-by-step explanation:

but here is how you can figure this out....

they tell use to give 6 inches on each side of the door,  so the total width of the logo can be 2 feet wide. Because the door is 3 feet wide.   Now use that to find the height.   find the height to width ratio of the logo,   so if the logo is 4 feet wide and 6 feet tall it's 6/4 or  1.5   ratio, use that and multiply by the 2 that we know the width can be on the door.    so  2*1.5 = 3.   the height of the logo would be 3 feet tall and 2 feet wide on the door.  see?

just find the ratio of the logo, and multiply that by 2  :)  to find the height on the door,  got it?

Answer:

B) Graph B

Step-by-step explanation:

[tex]x = 4 \cos(a) [/tex]

[tex] \frac{x}{4} = \cos(a) \\ [/tex]

[tex]( { \frac{x}{4} })^{2} = ({ \cos(a) })^{2} \\ [/tex]

[tex] \frac{ {x}^{2} }{16} = {cos}^{2} (a) \\ [/tex]

_____________________________________________

[tex]y = 5 \tan(a) [/tex]

[tex] \frac{y}{5} = \tan(a) \\ [/tex]

[tex]( { \frac{y}{5} })^{2} = ( { \tan(a) })^{2} \\ [/tex]

[tex] \frac{ {y}^{2} }{25} = {tan}^{2} (a) \\ [/tex]

_____________________________________________

Thus ;

[tex] \frac{ {x}^{2} }{16} - \frac{ {y}^{2} }{25} = \\ [/tex]

[tex] {cos}^{2} (a) - {tan}^{2} (a)[/tex]

[tex]x^2-6x+13=0\\\\\implies x^2-6x =-13\\\\\implies x^2 -2\cdot 3 \cdot x+3^2 -3^2 =-13\\\\\implies (x-3)^2 -9 = -13\\\\\implies (x-3)^2 = -13 +9 = -4\\\\ \implies x-3 =\pm\sqrt{-4} \\\\\implies x -3 = \pm2i\\\\\implies x = \pm 2i +3\\\\\text{Hence,}~ x = 3 + 2i, ~~ x = 3-2i[/tex]

Answer:

I dunno how do sorry mann