Brenya Estate produces a high quality tea branded Super by blending three types of tea coded A, B and C in the ration 1½ : 5 : 1. Originally Type A tea costs GHS 1,600 type B costs GHS 800 and type C costs GHS 1,700 per Kg to produce. Brenya Tea Estate packs Super tea in packets of 825g each. Blending and packing costs are 40 per Kg. Determine the production cost for a packet of Super tea.

Answers

Answer 1

Therefore, the production cost for a packet of Super tea is $923.91.

Cost calculation

Since Brenya Estate produces a high quality tea branded Super by blending three types of tea coded A, B and C in the ration 1½ : 5 : 1, and originally Type A tea costs GHS 1,600 type B costs GHS 800 and type C costs GHS 1,700 per Kg to produce, and Brenya Tea Estate packs Super tea in packets of 825g each. Blending and packing costs are 40 per Kg, to determine the production cost for a packet of Super tea, the following calculation must be made:

Blending ad packing costs = 40 x 0.825 = 331.5 + 5 + 1 = 7.57.5 = 1001.5 = X1.5 x 100 / 7.5 = 207.5 = 1005 = X5 x 100 / 7.5 = 66.66100 - 66.66 - 20 = 13.3333 + (1600 x 0.2 x 0.825) + (800 x 0.6666 x 0.825) + (1700 x 0.1333 x 0.825) = X33 + 264 + 439.96 + 186.95 = X923.91 = X

Therefore, the production cost for a packet of Super tea is $923.91.

Learn more about cost calculation in https://brainly.com/question/27344683


Related Questions

PLEASE HELP!!!!!!!!! ​

Answers

Answer:

With Graph and Without Graph.

Step-by-step explanation:

Without graphing calculator, you plug in your x-values into the equation

y = 16 -x^2 to solve for y-values.

f(x) = 16 - x^2

f(-4) = 16 - (-4)^2 = 16 - 16 =0

...

f(4) = 16 - (4)^2 = 16 - 16 =0


With Graphing Calculator.

4x - 5y = 6
- 8x +10y = -12
gausse elimination

Answers

Step-by-step explanation:

4x−5y=6

−8x+10y=−12

Isolate x for 4x –5y = 6: x=6-5y/4

Substitute x= 6+5y/4

[-8 (6-5y/4) +10y=-12]

Simplify

[-12= -12 ]

The solutions to the system of equations are:

x=6+5y/4

7. A sector of a circle has are length 2cm and central angle 0.4 radians. Find its
radius and and area?

Answers

12 is the factor n the bro 92 n minus 8

What solution value does not satisfy the compound inequality X - 7 < 17 or -6x >
36?
O A) x = -1
OB) x=0
O C) x= - 10
C
O D) x=25
Dx = 25

Answers

Inequalities are expressions not separated by an equal sign. The solution of the compound inequality will be -6 < x < 24

Compound inequality

Inequalities are expressions not separated by an equal sign.

Given the compound inequalities

X - 7 < 17 or -6x >36

For the inequality

x - 7 < 17

x < 17 + 7

x < 24

Similarly for -6x >36

x < -36/6
x < -6

The solution of the compound inequality will be -6 < x < 24

Learn more on inequality here: https://brainly.com/question/11613554

5. Convert the rectangular equation x² + y² - 6y = 0 into a polar equation.
A. r = 6 sin theta
B. r = 6 cos theta
C. r = √6 sin theta
D. r = √6 cos thea​

Answers

Answer:

A. r = 6 sin theta

Step-by-step explanation:

Given equation is: [tex]x^2+y^2-6y=0[/tex]....(1)

Using the formulae that link Cartesian to Polar coordinates.

[tex]x=r\cos\theta \: and \: y = r\sin\theta[/tex]

Plugging the values of x and y in equation (1), we find:

[tex](r\cos\theta)^2+(r\sin\theta)^2-6(r\sin\theta)=0[/tex]

[tex]\implies r^2\cos^2\theta+r^2\sin^2\theta-6r\sin\theta=0[/tex]

[tex]\implies r^2(\cos^2\theta+\sin^2\theta)=6r\sin\theta[/tex]

[tex]\implies r^2(1)=6r\sin\theta[/tex]

[tex](\because \cos^2\theta+\sin^2\theta=1)[/tex]

[tex]\implies\frac{ r^2}{r}=6\sin\theta[/tex]

[tex]\implies\huge{\purple{ {r}=6\sin\theta}}[/tex]

Answernone

none

none

Step-by-step explanation:

Will the product of 2 2/5 x 1/6 be larger or smaller than 2 2/5

Answers

Answer:

Smaller

Step-by-step explanation:

2 2/5 * 1/6 = 2/

5

= 0.4

Conversion a mixed number 2 2/

5

to a improper fraction: 2 2/5 = 2 2/

5

= 2 · 5 + 2/

5

= 10 + 2/

5

= 12/

5

To find a new numerator:

a) Multiply the whole number 2 by the denominator 5. Whole number 2 equally 2 * 5/

5

= 10/

5

b) Add the answer from previous step 10 to the numerator 2. New numerator is 10 + 2 = 12

c) Write a previous answer (new numerator 12) over the denominator 5.

Two and two fifths is twelve fifths

Multiple: 12/

5

* 1/

6

= 12 · 1/

5 · 6

= 12/

30

= 2 · 6/

5 · 6

= 2/

5

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(12, 30) = 6. In the following intermediate step, cancel by a common factor of 6 gives 2/

5

.

In other words - twelve fifths multiplied by one sixth = two fifths.


Maitri and Aabhas do a work in 12 hours.

Aabhas and Kavya do the work in 15 hours.

Kavya and Maitri do
work in 20 hours.

In how many hours will they finish it together and separately?

Pls help me

Answers

Answer:

See below ~

Step-by-step explanation:

Given

Maitri and Aabhas do a work in 12 hoursAabhas and Kavya do the work in 15 hoursKavya and Maitri do the work in 20 hours

Solving

Take Maitri, Aabhas, and Kavya to be x, y, z respectivelyx + y = 12 (1)y + z = 15 (2)x + z = 20 (3)

Take Equation 1 and rewrite it so that it is equal to x.

x = 12 - y

Take Equation 2 and rewrite it so that it is equal to z.

z = 15 - y

Now, substitute these values in Equation 3.

x + z = 2012 - y + 15 - y = 20-2y + 27 = 202y = 7y = 7/2 = 3.5 hours [Aabhas]

Substitute the value of y in Equation 1.

x + 3.5 = 12x = 8.5 hours [Maitri]

Substitute the value of y in Equation 2.

3.5 + z = 15z = 11.5 hours [Kavya]

Add the values of x, y, and z together.

x + y + z8.5 + 3.5 + 11.512 + 11.523.5 hours [together]

Calc I optimization problem, Please see attachment!

Answers

Answer:  14 feet

=======================================================

Explanation:

Let C be the corner point.

x = distance from P to C

That makes segment AP to be 70-x feet long

Focus on the right triangle PBC. Use the pythagorean theorem to find the hypotenuse PB.

[tex]a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\PB = \sqrt{(PC)^2 + (CB)^2}\\\\PB = \sqrt{x^2 + 90^2}\\\\PB = \sqrt{x^2 + 8100}\\\\[/tex]

If we knew what x was, then we could find a numeric value for PB.

---------------------

It costs $28 per foot to run cable along the ground. This is the portion from A to P. So it costs 28(70-x) dollars to run that portion of cable above ground. Simply multiply the cost per foot by the number of feet.

Similarly, the cost from P to B is [tex]53\sqrt{x^2+8100}[/tex] since it costs $53 per foot to have it run underground.

The total cost is therefore [tex]28(70-x) + 53\sqrt{x^2 + 8100}[/tex]

The derivative of this will help determine when the cost is minimized.

Type that function into GeoGebra and have it compute the derivative.

You should find that the x intercept of the derivative curve is exactly x = 56

If x = 56, then 70-x = 70-56 = 14

This means AP = 14 feet is the amount of cable to run along main street.

This also leads to [tex]PB = \sqrt{x^2 + 8100} = \sqrt{56^2 + 8100} = 106[/tex]

The total length of the wire is 14+106 = 120 feet

It costs $28 per foot along the 14 ft section, so 28*14 = 392 dollars is the cost for this section.

It costs $53 per foot along the 106 ft section, so 53*106 = 5618 dollars is the cost for this other section.

The total min cost is 392+5618 = 6010 dollars

------------------

Side note: You could do all this without a calculator to compute the derivative and use algebra to end up with x = 56. However, I think the use of technology is beneficial because it's fast/efficient. In real world settings, you won't be likely to pull out pencil/paper to get things done. The modern world relies on computers. It's refreshing to see that your teacher encourages the use of technology.

Let me know if you need me to go over the algebraic steps and I'll update my answer.

solve 1 + cos theta = 2 cos^2 theta

Answers

[tex]~~~~1+ \cos \theta = 2 \cos^2 \theta \\\\\implies 2\cos^2 \theta -\cos \theta -1 = 0\\\\\implies 2 \cos^2 \theta -2\cos \theta + \cos \theta -1 = 0\\\\\implies 2 \cos \theta( \cos \theta -1) +(\cos \theta -1)=0\\\\\implies (\cos \theta -1)(2 \cos \theta +1)=0\\\\\implies \cos \theta = 1, ~~\cos \theta = -\dfrac 12\\\\\implies \theta = 2n\pi,~~~ \theta = 2n\pi \pm \dfrac{2\pi}3[/tex]

Hello can u guys help me please

Answers

Answer:

[tex]\displaystyle \frac{1}{4}[/tex]

Step-by-step explanation:

Given:

[tex]\displaystyle\frac{4^{6} }{4^{7}}[/tex]

Expand:

[tex]\displaystyle\frac{4*4*4*4*4*4 }{4*4*4*4*4*4*4}[/tex]

Simplify ones, in this case [tex]\frac{4}{4}[/tex]:

[tex]\displaystyle \frac{1}{4}[/tex]

     If you raise 4 to the power of 6, to the power of 7, and then simplify the fraction, you will get the same result. This method is much quicker when you have numbers with the same bases (here the base is 4) so I used this way.

The graph shows the function f(x) = 3* What is the value of f-1(x) at x = 3?

Answers

Answer:

1

I've attached a screenshot from my graphing calculator of [tex]f(x)[/tex] in blue and [tex]f^{-1}(x)[/tex] in red. Notice how the red line (inverse function) has (3, 1)

Step-by-step explanation:

[tex]f(x) = 3^x\\f^{-1}(x) =\ ?\\[/tex]

We must first figure out the inverse function of [tex]f(x)[/tex] which is  [tex]f^{-1}(x)[/tex]

[tex]y = f(x) = 3^x\\y = 3^x\\log\ y = log\ 3^x\\log\ y = x \times log\ 3\\x = \frac{log\ y}{log\ 3}\\[/tex]

We say y = f(x) to begin with, but after find x = ...

we must 'swap' x and y

[tex]x = \frac{log\ y}{log\ 3}\\y = \frac{log\ x}{log\ 3}\\[/tex]

[tex]f^{-1}(x) = \frac{log\ x}{log\ 3}[/tex]

[tex]f^{-1}(3) = \frac{log\ 3}{log\ 3} = 1[/tex]

Given x^2+y^2=r^2 and the figure of the right triangle with legs x and y and hypotenuse r, prove cos^2θ+sin^2θ=1.

I need assistance filling out the blanks on the attached document.

Answers

By definition of cosine and sine,

cos(θ) = x/r

sin(θ) = y/r

so that

cos²(θ) + sin²(θ) = (x/r)² + (y/r)²

… = x²/r² + y²/r²

… = (x² + y²)/r²

… = r²/r²

… = 1

To that end, I would say

• [blank1] = "Division property of equality"

That is, we divide both sides of an equation by the same number and equality still holds since r ≠ 0

• [blank2] = "Definition of cos"

• [blank3] = "cos²(θ) = x²/r²"

• [blank4] = "Defintion of sin"

• [blank5] = "sin²(θ) = y²/r²"

• [blank6] = "Simplify"

More specifically, x² + y² = r² is given, so

x²/r² + y²/r² = (x² + y²)/r² = r²/r² = 1

1 box of blue counters from which 25 counters have been removed and then the remaining number has been doubled

Answers

If 1 box is removed from 25
25-1
24
So remaining there are 24 boxes
And then if the remaining is doubled then
24*2
48 boxes is the answer

please help me thanks

Answers

Answer:

y = 3x

Step-by-step explanation:

i cant see any equations

but the equaiton would be..

Solve for an angle in right triangles. Round to the nearest hundredths

Answers

Answer:

Use   SOH  CAH TOA  to rember how the trig function fit on the triangle

Step-by-step explanation:

we are given  the Hypotenuse and the Opposite  or   H and O   look for the trig function with each of those,  SOH is good

Sin Ф =  Opp /  Hyp,    or   SOH

now plug in what you are given

Sin Ф = 5 / 8

use inverse trig fuction to find the angle

arcSin ( Sin Ф) = arcSin ( 5/8)

trig functions cancel out

Ф = arcSin(5/8)

I'm using my calculator to find the arcSin(5/8)

Ф=38.6821...°

also make sure you know if your calculator is in degrees or radians.  

Ф=38.68°   to the nearest hundredth  :)

Answer:

∠A = 38.68°

Step-by-step explanation:

The side opposing ∠A and the hypotenuse are given.

Therefore, take the inverse sin function of ∠A.

sin∠A = 5/8∠A = sin⁻¹ (0.625)∠A = 38.6821875∠A = 38.68° (nearest hundredth)

What is the difference between a regular and irregular quadrilateral?

Answers

Answer:

ir

Step-by-step explanation:

irregular

regular

what do you notice different?

the both have r, e, g, u, l, a, r, but one has ir at the beginning.

Expand 96•06 using powers​

Answers

Answer:

Step-by-step explanation:

Use long multiplication to evaluate.

576

A rectangular field is 30 yards in length and 81 feet in width.

What is the area of the field in square feet?

Answers

Answer:

7290in ^2

Step-by-step explanation:

covert 30yd to feet which equals too 90ft.

Then multiple 90 x 81 = 7290

For each of the following prisms,find (I) its volume (ii) its total surface area

Answers

it has to be answer8

The base of S is the region enclosed by the parabola y = 8 − 8x2 and the x-axis. Cross-sections perpendicular to the x-axis are isosceles triangles with height equal to the base.

Answers

The base of a solid is the region in the first quadrant bounded by the y-axis, the x-axis, the graph of y=ex, and the vertical line x=1. For this solid, each cross section perpendicular to the x-axis is a square. What is the volume of the solid?

Step-by-step explanation:

Answer: Sometimes I dont want to be happy.

can someone please help? :((
if you want another 50 points or more you could maybe help with one of the previous unanswered questions on my profile

Answers

Just find the vertex and then compare with graph

#a

y=2x²-8y=2(x-0)²-8

Parabola opening upwards

Vertex at (0,-8)

Graph 3

#2

y=(x+3)²+0

Vertex at (-3,0)

Graph IV

#3

y=-2(x-4)²+8

Parabola opening downwards as a is -ve

Graph I

#4

One graph is left

Graph Ii

Answer:

a)  graph iii)

b)  graph iv)

c)  graph i)

d)  graph ii)

Step-by-step explanation:

Vertex form of a quadratic equation:  [tex]y = a(x - h)^2 + k[/tex]

where [tex](h, k)[/tex] is the vertex (turning point)

First, determine the vertices of the parabolas by inspection of the graphs:

Graph i) → vertex = (4, 8)Graph ii) → vertex = (3, -8)Graph iii) → vertex = (0, -8)Graph iv) → vertex = (-3, 0)

Next, write each given equation in vertex form and compare to the vertices above.

[tex]\textsf{a)}\quad y=2x^2-8[/tex]

[tex]\textsf{Vertex form}: \quad y=2(x-0)^2-8[/tex]

⇒ Vertex = (0, -8)

Therefore, graph iii)

[tex]\textsf{b)} \quad y=(x+3)^2[/tex]

[tex]\textsf{Vertex form}: \quad y=(x+3)^2+0[/tex]

⇒ Vertex = (-3, 0)

Therefore, graph iv)

[tex]\textsf{c)} \quad y=-2|x-4|^2+8[/tex]

[tex]\textsf{Vertex form}: \quad y=-2|x-4|^2+8[/tex]

⇒ Vertex = (4, 8)

Therefore, graph i)

[tex]\textsf{d)} \quad y=(x-3)^2-8[/tex]

[tex]\textsf{Vertex form}: \quad y=(x-3)^2-8[/tex]

⇒ Vertex = (3, -8)

Therefore, graph ii)

Solve the inequality įx - 2 Ž. Which number line represents the graph of the solution?
7 8 9 10 11 12 13 14 15
th
-5-4-3-2-1 0 1 2 3 4 5
-1
3
4
niwa
1
4
0
H
8
-
7
9
0
-1
1
9
-
No
2 5 4 1 2
3 9939

Answers

Answer:

2 ND option

solve and write

bianca's dad was taking everyone out to eat for her birthday. he spent $8 total on the adults and $9 total on the kids. how much did it cost for everyone?

Answers

How many people in total where their

Find the area of the shaded region

Answers

Not getting in to too much details but basically
Area of half circle - area of triangle
3.14r^2-1/2bh
r=6 b=12 h=6

Answer:

20.52 cm²

Area of shaded region:

area of semi-circle - area of triangle

[tex]\dashrightarrow \sf \dfrac{1}{2} \ \pi (radius)^2 \ - \ \sf \dfrac{1}{2} *base*height[/tex]

[tex]\rightarrow \sf \dfrac{1}{2} (3.14)(6)^2 - \dfrac{1}{2} *12*6[/tex]

[tex]\hookrightarrow \sf 56.52 \ - \ 36[/tex]

[tex]\hookrightarrow \sf 20.52 \ cm^2[/tex]

image coordinate plane with points plotted at ordered pairs Q (-4, 4) R (2, 4) S (5,-3) T(2,-3) and U (-4, -3) first persin to get it in 30 min get brainlest​

Answers

Answer:

I have graphed them on desmos and given you three options to choose from:

Step-by-step explanation:

1. with lines (complete shape)

2. with lines (incomplete shape)

3. without lines

Hope this helps!

Answer:

here

Step-by-step explanation:

What key features do the functions f(x) = 12x and g of x equals the square root of x minus 12 end root have in common?

Both f(x) and g(x) include domain values of [-12, ∞) and range values of (-∞, ∞), and both functions have an x-intercept in common.
Both f(x) and g(x) include domain values of [12, ∞) and range values of [0, ∞), and both functions have a y-intercept in common.
Both f(x) and g(x) include domain values of [-12, ∞) and range values of (-∞, ∞), and both functions increase over the interval (-6, 0).
Both f(x) and g(x) include domain values of [12, ∞), and both functions increase over the interval (12, ∞).

Answers

Both f(x) and g(x) include domain values of [12, ∞), and both functions increase over the interval (12, ∞). Then the correct option is D.

What are domain and range?

The domain means all the possible values of the x and the range means all the possible values of the y.

The functions are given below.

[tex]\rm f(x) = 12x \\\\g(x) = \sqrt{x - 12}[/tex]

Then the domain of f(x) is (-∞, ∞) and the domain of g(x) is (12, ∞). And both the functions increases in the interval of (12, ∞).

More about the domain and range link is given below.

https://brainly.com/question/12208715

#SPJ1

. What is the vertical asymptote(s) for y=x-5/x^2-4x-12​

Answers

Answer:

x = -2 and 6

Step-by-step explanation:

To find vertical asymptote, set the denominator equal to 0 and solve for x. See the guidelines below for determining VA

[tex]y=\frac{x-5}{x^{2} -4x-12}[/tex]

[tex]x^{2} -4x-12=0[/tex]

[tex]x^{2} -6x+2x-12=0[/tex]

[tex]x(x-6)+2(x-6)=0[/tex]

[tex](x+2)(x-6)=0[/tex]

[tex]x=-2,6[/tex]

Hope this helps and God bless!

cosx(tanx+cotx)=

Pls Help

Answers

Step-by-step explanation:

Tangent is equal to sine over cosine. Cotangent is equal to cosine over sine. Therefore:

[tex]cos(x)( \frac{sin(x)}{cos(x)} + \frac{cos(x)}{sin(x)} )[/tex]

Distribute the cos(x) into the sum to get:

[tex]sin(x) + \frac{ {cos(x)}^{2} }{sin(x)} [/tex]

Get a common denominator by multiplying the first term by sine over sine to get:

[tex] \frac{ {sin(x)}^{2} }{sin(x)} + \frac{ {cos(x)}^{2} }{sin(x)} [/tex]

The numerator adds to equal 1 due to a common trigonometric identity. Therefore the only remaining term is:

[tex] \frac{1}{sin(x)} [/tex]

final answer to the expression is csc(x)

At a local school,940 students each wrote 40 letters to students in another country.How many letters were written in all?

Answers

Answer:

37,600

Step-by-step explanation:

940 X 40 = 37,600.

simple multiplication

Answer:

, 37,000

Step-by-step explanation:

940 x 40= 37,000

A
Select the correct answer from each drop-down menu.
The front, back left and right sides of the second floor of the house will be painted. The roof will not be painted. The total surface area to be
painted is 728 square feet. The windows shown each measure 3 feet by 2 feet. There are no other windows on the second floor.
Ich 4) to
hft
2017
25 ft
What is the value of 2
The front and back of the top section of the
The bottom section of the second floor can be modeled by a
second floor can be modeled by the bases of a
The value of hin feet is
Reset
Next

Answers

Answer: rectangular prism, triangular prism, 6

Step-by-step explanation:

The bottom section of second floor can be modeled by a rectangular prism.The front and back of top section of second floor can be modeled by bases of a triangular prism.The value of height is 6 feet.

How to calculate the area of the base of a triangular prism?

The area of base of the triangular prism can be calculated by the half of the product of the height of the triangular base of prism and base of prism.

How to calculate the area of the base of a rectangular prism?

The area of base of the rectangular prism can be calculated by the product of the length of the rectangular base of prism and the breadth of prism.

The area of the bottom section of the second floor = 2( area of the front part of the wall + area of the side of the wall)

= 2( 20*h + 25*h)

=90h

The front and back of top section of second floor = 2* area of the front wall=2*(1/2*20*(h+4))=20h+80

Total area of the second floor=total area of the window+total area to be painted

⇒Total area of the second floor= 728 + (2* area of the window)

⇒Total area of the second floor= 728 + (2*3*2)

area of front and back of top section of second floor + The area of the bottom section of second floor = 728+12

area of front and back of top section of second floor + The area of the bottom section of second floor = 740

⇒(20h+80)+90h=740

⇒110h+80=740

⇒110h=740-80

⇒110h=660

⇒h=660/110

⇒h=6 feet

Therefore the value of h is 6 feet.

Learn more about area of triangular Prism

here: https://brainly.com/question/17111476

#SPJ2

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A student observes a cell under a microscope. The cell contains chromosomes that show up inside of a nucleus surrounded by an envelope. Based on the information here, the student was able to determine whether the cell was prokaryotic or eukaryotic. After making the distinction, the student could assume the cell came from certain cell types. From which potential organism was this cell-derived? Which is a difference that arises as a result of the different ways in which the speech and the poster convey their intended messages? the posters images feature the male factory workers more prominently and almost hides the female worker in the background, while the speech specifically acknowledges both male and female workers equally. the posters images merely suggest that factory work is a thankless job, whereas the speech specifically acknowledges that it is. the posters images portray a variety of different industries, whereas the speech acknowledges only those who work in factories. the posters images clearly illustrate that factory work is a vital job, whereas the speech barely acknowledges its significance. Gold is not a compound.O A. TrueO B. False As of 2022, what is the total population of the planet?. 1: 542 mg =____g2: 39 cm = ____m3: 0.75 m =____cm4: 6,367 mm= ___m5: 6.5 g =___ mg6:736 m = ___ km7:12 g =____ kg8:22 cm =___m A student rolls a 3-kilogram ball down the same ramp used in Setup 2. The speed of the ball after 2 seconds was 4 meters per second. The student concludes that the kinetic energy of the 3-kilogram ball is identical to the 1-kilogram ball after it has rolled down the ramp for 2 seconds.Explain whether the students conclusion is correct or incorrect. Use evidence from the investigation to support your answer. what i learned about life and career skills? what causes the villagers roofs to collapse If there were no lynx controlling the snowshoe hare population, what would eventually happen to the population of the snowshoe hares and the grasses that the snowshoe hares eat? Which factor is important for any process for adapting the aerobic energy system to exercise?the ability of cardiovascular system to pump oxygenated blood to musclesthe frequency for the body to rely on the lactic acid systemthe efficiency of muscles to remove phosphate from the bloodthe requirement for blood to transform ADP to ATP An individual receives a knife wound to the axillary region. The nerve plexus most likely to be damaged is the. Area of the parallelogram? 308 meters squared312 meters squared316 meters squared320 meters squared What is the product of 17 and 41 suppose the government imposed a new tax on an item for which demand is typically inelastic who would probably end up bearing the incidence of the tax?why? During the beginning of the AmericanIndustrial Revolution, governmentusually did which of the following?A. Favored big businessB. Ignored big businessC. Stopped big businessD. Tolerated big business Why is it beneficial to plants that soil particles have negatively-charged surfaces?. Choose the function whose graph is given below. William Byrd's influence on music in his homeland has earned him the title of _____.A: "Composer of the year 1620" for western Europe.B: "Composer of the year 1600" for all of Europe.C: "Father of British music." How is the nurse behaving that is frustrating to juliet?. What expression represents the volume of the cone, in cubic units? two-thirdsx3 four-thirdsx2 2x3 4x3